To calculate future population growth, we use a formula incorporating the initial population, annual growth rate, and number of years. For growth, we add one to the growth rate and raise it to the power of elapsed years, then multiply by the initial population. For decline, we subtract the rate from one and then do similar exponentiation and multiplication.
Calculating Future Population Growth
To calculate the future population of deer given a starting population and a constant annual growth rate, we use the formula y = a(1+b)^x, where 'a' is the starting amount, 'b' is the growth rate, and 'x' is the number of years elapsed. For the deer population, from 2000 to 2020, there are 20 years of growth at 3.5% annually. Using a=3500, b=0.035, and x=20, the calculation is as follows:
Convert the percentage to a decimal: 3.5% becomes 0.035.
Add 1 to the growth rate: 1 + 0.035 = 1.035.
Raise this sum to the power of 20: (1.035)^20.
Multiply the result by the initial population: 3500 * (1.035)^20.
For the New Haven population, which is decreasing at 2.9% annually from 2004 to 2015 (11 years), the steps are similar. However, we subtract the percentage decline from 1 instead since the population is decreasing.
Convert the percentage to a decimal: 2.9% becomes 0.029.
Subtract this from 1: 1 - 0.029 = 0.971.
Raise this to the power of 11: (0.971)^11.
Multiply the result by the initial population of New Haven: 148220 * (0.971)^11.
After performing these calculations, we will get the estimated populations for both the deer and New Haven in the specified years.
The family room floor in Zacks home has a rectangular area rug that measures 6.5 feet by 9 feet the floor is rectangular and measures 10 feet by 12 feet What area of the floor is not covered by the rug
Final answer:
To find the area of the floor not covered by the rug, calculate the total floor area (120 square feet), subtract the rug's area (58.5 square feet), resulting in 61.5 square feet of uncovered floor.
Explanation:
To find the area of the floor that is not covered by the area rug, we first need to calculate the area of the entire floor and then subtract the area of the rug.
The area of the floor is calculated by multiplying its length and width. So for a floor that measures 10 feet by 12 feet, the area is 10 feet × 12 feet = 120 square feet.
The area rug measures 6.5 feet by 9 feet, which means its area is 6.5 feet × 9 feet = 58.5 square feet.
Now, subtract the area of the rug from the area of the entire floor to find the part of the floor not covered by the rug:
120 square feet - 58.5 square feet = 61.5 square feet.
Therefore, the area of the floor not covered by the rug is 61.5 square feet.
A tortoise travels 11 feet in one hour. In each subsequent hour, the tortoise travels one-third the distance it traveled in the previous hour. How far does this tortoise travel in 6 hours?
The distance that a tortoise will cover in 6 hours is:
16.47735 feet.
Step-by-step explanation:It is given that :
A tortoise travels 11 feet in one hour.
In each subsequent hour, the tortoise travels one-third the distance it traveled in the previous hour.
This means that in 2 hours it travels a total of:[tex]11+\dfrac{1}{3}\times 11\ feet[/tex]
which is equal to:
[tex]11\times \dfrac{4}{3}\ feet=\dfrac{44}{3}\ feet[/tex]
in the 3 hours it will travel a total of:[tex]=11+\dfrac{1}{3}\times 11+\dfrac{1}{3^2}\times 11\ feet[/tex]
In 4 hours it will travel a total of:[tex]=11+\dfrac{1}{3}\times 11+\dfrac{1}{3^2}\times 11+\dfrac{1}{3^3}\times 11\ feet[/tex]
In 5 hours it will travel a total of:[tex]=11+\dfrac{1}{3}\times 11+\dfrac{1}{3^2}\times 11+\dfrac{1}{3^3}\times 11+\dfrac{1}{3^4}\times 11\ feet[/tex]
In 6 hours it will travel a total of:[tex]=11+\dfrac{1}{3}\times 11+\dfrac{1}{3^2}\times 11+\dfrac{1}{3^3}\times 11+\dfrac{1}{3^4}\times 11+\dfrac{1}{3^5}\times 11\ feet=16.47735\ feet[/tex]
Hence, the answer is:
16.47735 feet
A quadratic equation is shown below: 10x2 − 3x − 1 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points) Part B: Solve 16x2 − 2x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (5 points)
A) Consider the equation [tex]10x^2-3x-1=0[/tex]
We have to describe the solutions to this equation.
We will determine the radicand = [tex]b^2-4ac[/tex]
= [tex](-3)^2 - 4(10)(-1) = 9+ 40 = 49[/tex] which is greater than zero,
Therefore, the given equation ha real roots.
B) Consider the equation [tex]16x^2-2x-5=0[/tex]
We will use middle splitting term method to solve this equation.
[tex]16x^2+8x-10x-5 =0[/tex]
[tex]8x(2x+1) -5(2x+1)=0[/tex]
[tex](2x+1)(8x-5)=0[/tex]
So, [tex]2x+1=0[/tex]
[tex]x = \frac{-1}{2}[/tex] and [tex]x = \frac{5}{8}[/tex]
I chose this method, because this is more easier and takes less time.
What is the following quotient? 5/√11-√3
ANSWER
[tex]\frac{5( \sqrt{11} + \sqrt{3} )} {8} [/tex]
EXPLANATION
The given rational function is
[tex] \frac{5}{ \sqrt{11} - \sqrt{3}} [/tex]
We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of
[tex] \sqrt{11} - \sqrt{3} [/tex]
which is
[tex]\sqrt{11} + \sqrt{3} [/tex]
When we rationalize we obtain:
[tex] \frac{5( \sqrt{11} + \sqrt{3} )}{(\sqrt{11} - \sqrt{3} )( \sqrt{11} + \sqrt{3} )} [/tex]
The denominator is now a difference of two squares:
[tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex]
We apply this property to get
[tex]\frac{5( \sqrt{11} + \sqrt{3} )}{( \sqrt{11}) ^{2} - ( \sqrt{3}) ^{2} )} [/tex]
[tex]\frac{5( \sqrt{11} + \sqrt{3} )}{11 - 3} [/tex]
This simplifies to
[tex]\frac{5( \sqrt{11} + \sqrt{3} )} {8} [/tex]
Or
[tex]\frac{5 } {8}\sqrt{11} + \frac{5 } {8}\sqrt{3} [/tex]
Answer:
B
Step-by-step explanation:
What is the overlap of Data Set 1 and Data Set 2?
A. High
B. Moderate
C. Low
D. None
Please help as so as possible
Polygon ABCD is the result of a translation of polygon EFGH . AB¯¯¯¯¯ is parallel to DC¯¯¯¯¯ in the pre-image. Drag the answers to the boxes to correctly complete the statement about this image. The corresponding segments and in the image are
Answer: The corresponding segments in the in the figure and the image are :
AB and EF,
AD and EH,
CD and HG,
BC and FG,
Step-by-step explanation:
Given: Polygon ABCD is the result of a translation of polygon EFGH .
AB is parallel to DC in the pre-image.
We know that a translation is a rigid transformation which produces congruent images such that the corresponding segments have equal lengths.
So from the given statements the corresponding segments in the figure and the image are :
AB and EF,
AD and EH,
CD and HG,
BC and FG,
In the diagram ∠BAD ≅ ∠CAD. If m∠BAD = 12x + 8 and m∠CAD = 16x, find m∠BAC. A) 22 degrees
B) 32 degrees
C) 48 degrees
D) 64 degrees
enter the missing value into the box to complete the ratio comparing 500 meters to 3 kilometers
Is the equation A = 21000 ( 1 − .12 )^t a model of exponential growth or exponential decay, and what is the rate (percent) of change per time period?
Answer is Exponential Decay.
Exponential Growth and Decay:
Exponential decay is a process that decreases quantity over time.
Exponential growth is a process that increases quantity over time.
(Given),
[tex]A = 21000(1-0.12)^{t}[/tex]
Let's take,
[tex]B = (1 - 0.12)^{t}[/tex]
As the t increases the B value decreases exponentially. So, the A = 21000*B also decreases exponentially as t increases.
And the rate of change per time period is (0.12 x 100)% = 12%.
So, It is exponential decay.
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Which data set is represented by the modified box plot?
•85, 70, 80, 108, 46, 66, 68, 82, 70, 68
•85, 78, 80, 108, 46, 66, 68, 80, 72, 68
•85, 78, 80, 108, 46, 66, 68, 82, 72, 80
•85, 78, 80, 108, 46, 66, 68, 82, 72, 68
Hey guys I need help with this THANKS!
Answer: c
Step-by-step explanation: hope this helps
Morgan bought a pair of shoes at a sale of 25%. If the amount she paid was $1000, find the marked price.
The marked price of the shoes that Morgan bought at a 25% discount for $1000 is $1333.33. The calculation was done by dividing the discounted price by (1 minus the discount percentage in decimal form).
The question involves finding the marked price of an item given the discounted price and the discount percentage. Morgan paid $1000 for a pair of shoes after getting a 25% discount. To find the original marked price, we can use the formula:
Discounted Price = Marked Price × (1 - Discount Percentage)
Here, the Discounted Price is $1000, and the Discount Percentage is 25%, which is equivalent to 0.25 in decimal form.
By rearranging the formula to solve for the Marked Price, we get:
Marked Price = Discounted Price ÷ (1 - Discount Percentage)
Now we can calculate:
Marked Price = $1000 ÷ (1 - 0.25) = $1000 ÷ 0.75 = $1333.33
Therefore, the marked price of the shoes was $1333.33.
180 miles in 3 hours in fraction form and in word form
60 miles per hour
Or
60/1
can you discuss the differences between circumference and area of a circle ?
the temperature last night was 10 degrees below 0. The next morning by 9 a.m. the temperature had risen 12 degrees. what was the temperature at 9 a.m.?
i need help
Fundraising your school raised 125% of its fundraising goal the school raised $6750.what was the goal
There are 453.592 grams in one pound . A semi - slick , Kevlar tire weighs about 520 grams . What is the tires weighs in pounds ?
Latitude measures the distance ( in degrees-north or south ) above the equator. The equator has a latitude of 0° . Your friend lives in a town 10 degrees north of Cleveland. Cleveland has a latitude of 40° N. If you reflect the town's location over the equator, what would be its new latitude?
a. 30° S
b. 40° N
c. 50° S
d. 50° N
The friend lives in a town that is 10° farther north than 40° N. The latitude of that town is 40° +10° = 50° N. When that latitude is reflected across the equator, N changes to S. The new latitude would be c. 50° S.
Draw three rectangles.Then draw to show halves,thirds,and fourths. Write about each whole that you have drawn
The height of a triangle is twice the length of its base. The area of the triangle is 50m^2. Find the height and base to the nearest tenth of a meter
Which of the following is not equivalent to the other
The third fraction [tex]\frac{10}{80}[/tex] is not equivalent to the other options. The other options, 0.8, 80% and [tex]\frac{24}{30}[/tex] are all equivalent.
In mathematics, a fraction is a composition that represents a part of a whole. Fractions can be written in a few different ways, but the most frequent way is to utilize a numerator and a denominator. The numerator is the number of parts we have, and the denominator is the total number of parts. For illustration, the fraction 1/2 represents one part out of two.
Option 1 is 0.8.
Option 2 is 80% which is in fact equal to [tex]\frac{80}{100}[/tex] .
[tex]\frac{80}{100}[/tex] = [tex]\frac{8}{10}[/tex] = 0.8.
Option 3 is [tex]\frac{24}{30}[/tex] .
[tex]\frac{24}{30}[/tex] = [tex]\frac{8}{10}[/tex] = 0.8.
So, only the third option is not equivalent to the others.
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What is 0.24 ̅ (4 is repeating) expressed as a fraction in simplest form?
Show your work please
Here, we need to find express 0.2444... as a fraction in simplest form.
Let the fraction be expressed as x
Now,
x = 0.2444....
Since, x is recurring in 1 decimal places, we multiply it by 10.
10x = 2.4444....
From left hand-side, x is subtracted and from 0.24444... from right hand side
10x - x = 2.4444.... - 0.24444....
So now,
9x = 2.2
x = [tex] \frac{2.2}{9} [/tex]
x = [tex] \frac{22}{90} [/tex]
x = [tex] \frac{11}{45} [/tex]
Thus, fraction as simplest form = [tex] \frac{11}{45} [/tex]
If jeremy gives his horse 12 gallons of water each day. How many one quart pails of water is that
Maria’s math test had 25 questions. She got 84% correct. How many problems did she get wrong
The surface area of a triangular prism is 60 square centimeters. What is the surface area of a similar prism that is smaller by a scale factor of 1 5th
The smaller triangular prism's surface area is calculated by squaring the scale factor of 1/5 (which is 1/25) and then multiplying it by the surface area of the larger prism. The result is 2.4 square centimeters.
The question asks about the surface area of a similar but smaller triangular prism given that the larger prism has a surface area of 60 square centimeters and the scale factor of the smaller prism is 1/5. When the size of an object changes by a scale factor, the surface area changes by the square of that scale factor. For the smaller triangular prism, the surface area will be the square of 1/5, which is 1/25, times the surface area of the larger prism.
To calculate it:
Take the surface area of the larger prism, which is 60 square centimeters.Multiply this area by the square of the scale factor, (1/5)², which is 1/25.The result will give us the surface area of the smaller prism: 60 cm2 * 1/25 = 2.4 cm².Therefore, the surface area of the similar smaller triangular prism by the given scale factor is 2.4 square centimeters.
The product of two consecutive odd integers is fifteen. Find all such integers.
the two consecutive odd integers that have a product of fifteen are 3 and 5.
The question asks for the two consecutive odd integers whose product is fifteen. To solve this, we can use algebraic methods or observe that the square root of 15 is less than 4, and since 15 is an odd number, we look for odd numbers around 4 that multiply to 15.
Let's define the smaller integer as n. Since the integers are consecutive and odd, the next odd integer after n is n+2. The equation to represent their product is n*(n+2) = 15. Solving for n gives us the integers 3 and 5, since 3*5 = 15.
Therefore, the two consecutive odd integers that have a product of fifteen are 3 and 5.
Cassie bakes cookies and brownies for the school bake sale. Each cookie will sell for $0.50 and each brownie will sell for $0.75. Write an expression for the amount of money Cassie will raise for the school with the cookies and brownies she baked.
Sara got 88, 90, 75, 78, 100, 54, 90, 100, 45, and 60 on her English tests. Lee got 77, 67, 99, 79, 100, 65, 79, 89, 58, and 67 on his English tests. What is the mean of Sara's English tests? What is the mean of Lee's English tests? please answer both questions
Simplify the expression
(5jk)^4