(a) entry fee cost
(b) the number of ride tickets James can buy (after he pays the entry fee)
(c) an equation for total cost y for purchase of x tickets
Solution(a) We know the total cost is the cost of entry fee and ride tickets. For Jennifer, this is ...
... 30.75 = (entry fee) + 15×1.25
... 30.75 -18.75 = (entry fee)
entry fee = 12.00 . . . dollars
(b) If James spends his entire budget on entry fee and x rides, the number of ride tickets he can buy is given by ...
... 22 = 12 + 1.25x
... 10 = 1.25x
... 10/1.25 = x = 8
James can buy 8 ride tickets.
(c) The equation for total cost that we have been using is ...
... total cost = entry fee + (cost per ticket)×(number of tickets)
... y = 12 + 1.25x
1. Which property is illustrated by the statement 2(-6/7)=(-6/7)2
A. Associative property of addition
B. Inverse propert. Of multiplication
C. Communtative property of multiplication
D. Communtative property of addition
2. Which property is illustrated by the statement? 5.4 + 3 = 3 + 5.4
A. Associative property of addition
B. Inverse propert. Of multiplication
C. Communtative property of multiplication
D. Communtative property of addition
(1) it is (C) the commutative property of multiplication: a*b = b*a, so 2*(-6/7) = (-6/7)*2
(2) it is (D) the commutative property of addition: a+b=b+a, so 5*4+3=3+5*4
commutate = "swap around"
if P(a)=0.60 and P(b)=0.30, then a and b are independent events if
Answer: [tex]\text{P(A or B)}=0.90[/tex]
[tex]\text{P(A and B)}=0.18[/tex]
Step-by-step explanation:
Given : P(A)=0.60 and P(B)=0.30
We will say A and B are independent events if :
[tex]\text{P(A or B)=P(A)+P(B)}\\\\=0.60+0.30=0.90[/tex]
[tex]\text{P(A and B)=P(A) x P(B)}\\\\=0.60\times0.30=0.18[/tex]
Thus , A and B are independent events if :
[tex]\text{P(A or B)}=0.90[/tex]
[tex]\text{P(A and B)}=0.18[/tex]
Answer: P( A and B)= 0.18
Please I need your help desperately what is the area of this triangle? See attached image thank you so much
To find the area of the given traingle we have to draw perpendicular from point 'J' which meets the x axis at point (2,0) and let us named it 'P'.
As we know that area of triangle is
[tex] = \frac{1}{2}\times b \times h [\tex]
Here base 'b' will be LK and height 'h' will be JP
Here,
LK= 4 units JP=4 units
Area ={1}{2} *(4)*(4)
On solving the equation we get,
Area=8 Sq units
In triangle ΔABC, ∠C is a right angle and CD is the height to AB . Find the angles in ΔCBD and ΔCAD if: Chapter Reference a m∠A = 20° Answer: m∠CDB = m∠CBD = m∠BCD = m∠CDA = m∠ CAD= m∠ACD =
In triangle ABC, when ∠A = 20°, then ∠B = 70°, ∠C = 90°. In triangle CAD, when ∠CAD = 20° and ∠CDA = 90°, ∠ACD = 70°. In triangle CBD, with ∠CBD = 90° and ∠BCD = 70°, ∠CDB = 20°.
Explanation:In triangle ΔABC, ∠C is a right angle and CD is the height to AB. Considering ∠A = 20°, by the angles sum property of a triangle, ∠B = 180° - ∠A - ∠C = 180° - 20° - 90° = 70°.
Moving on to triangle ΔCAD, this is a right triangle with ∠CDA=90°. ∠CAD is given as 20° (the same as ∠A of triangle ΔABC). Therefore, ∠ACD = 180° - ∠CAD - ∠CDA= 180° - 20° - 90° = 70°.
For triangle ΔCBD, ∠CBD is 90°, and ∠BCD corresponds to ∠B of triangle ΔABC, which we've determined as 70°. Hence, ∠CDB = 180° - ∠CBD - ∠BCD = 180° - 90° - 70° = 20°.
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In triangle ΔCBD, the angles are: m∠CDB = m∠CBD = 90° and m∠BCD = 90°. In triangle ΔCAD, the angles are: m∠CDA = 70° and m∠CAD = 70°. Finally, m∠ACD = 40°.
Explanation:In triangle ΔCBD, since ∠C is a right angle, ∠CBD = 90° and ∠BCD = 90°.
In triangle ΔCAD, using the fact that the sum of angles in a triangle is 180°, we can find that ∠CDA = 90° - ∠CBD = 90° - 20° = 70°.
Similarly, ∠CAD = 90° - ∠BCD = 90° - 20° = 70°.
Finally, since ∠CDA = ∠CAD, ∠ACD = 180° - ∠CDA - ∠CAD
= 180° - 70° - 70°
= 40°.
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- 2/3 + (3/4 + 5/3)
The commutative property of addition lets you rearrange this to
(3/4 +5/3) - 2/3
The associative property of addition lets you regroup this to
3/4 + (5/3 -2/3)
= 3/4 + 3/3
= 1 3/4 . . . . take your pick of the final form
= 7/4
= 1.75
plz help for brainlest
2. A model rocket is launched from the ground with an initial velocity of 288 ft/sec.
c. How long will it take the rocket to reach its maximum height? Show all work in the space provided.
d. Assume the model rocket’s parachute failed to deploy and the rocket fell back to the ground. How long would it take the rocket to return to Earth from the time it was launched? Show all work in the space provided.
2c. We assume that the equations for ballistic motion in a vacuum apply, and the rate of downward acceleration is 32 ft/s². Then it will take ...
... (288 ft/s)/(32 ft/s²) = 9 s
for the rocket to reach its maximum height (its vertical velocity to decrease to zero).
2d. The trip down takes the same amount of time as the trip up, so the round trip time is ...
... (9 s)×2 = 18
_____
More ExplanationThe acceleration due to gravity decreases the vertical velocity by the same amount (32 ft/s) each second. An equation for that might be ...
... v = 288 -32t
When the vertical velocity is zero, the rocket is no longer going up. It has reached its maximum height. Then the equation for that looks like ...
... 0 = 288 -32t
... 32t = 288
... t = 288/32 = 9 . . . . . compare to the solution above
After 9 seconds, the rocket reaches its maximum height.
___
Simplifying the description of free-fall is a little harder. In physics terms, the potential energy the rocket has at its maximum height all gets converted to kinetic energy on the way down. At impact with the ground, the kinetic energy is the same as it was when the rocket was launched. That is, its velocity is 288 ft/s earthward at impact. The above equation for velocity still applies, but now we're solving for v = -288.
... -288 = 288 -32t
... -576 = -32t
... 576/32 = t = 18 . . . . . twice the time it took to reach maximum height.
The round trip takes 18 seconds.
(x-7)^2=0 does this have a real solution?
Yes. You can solve in the usual way.
Take the square root:
... x-7 = ±√0 = 0
Add 7:
... x = 7
_____
There is one distinct real solution (with multiplicity 2).
a moving truck charges $250 to rent a truck and $0.40 for each mile driven. mr.lee paid a total of $314. which equation can be used to find m, the number of miles he drove the moving truck?
The price of 1 share of stock fell $4 every day for 3 straight days. How did the price of the stock change over these 3 days.
Answer:
The price over three days fell linearly
Step-by-step explanation:
s = stock
s = -4x
s = -4(3)
s = -12
The stock decreased by 12 dollars over 3 days.
Answer: -12
Step-by-step explanation:Hello!I hope you are having a good day or evening and I hope this helps :) !!
Avi's pet hamster Chubby loves to run in his hamster wheel. During one "race", Avi counts 100100100 rotations of the wheel. She wants to know how far Chubby ran, so she measures the diameter of the wheel and finds that it is 20 \text{ cm}20 cm20, space, c, m. How far did Chubby run? Round your answer to the nearest \text{cm}cmc, m.
Answer: 6280 cm
Step-by-step explanation:
Given: The diameter of hamster wheel = 20 cm
The circumference of hamster wheel is given by :-
[tex]C=\pi d[/tex], where d is the diameter of the hamster wheel.
[tex]\Rightarrow C=(3.14)(20)=62.8\text{ cm}[/tex]
During one race, the number of rotations of the wheel = 100
Therefore, the distance run by chubby is given by :-
[tex]D=100\times C\\\\\Rightarrow D=100\times62.8\\\\\Rightarrow D=6280\text{ cm}[/tex]
Answer:
6283 cm.
Step-by-step explanation:
We have been given that Avi's pet hamster Chubby completed 100 rotations of the wheel. The diameter of the hamster wheel is 20 cm.
Since wheel is a circle, so the distance covered by Chubby in one rotation will be equal to the circumference of wheel.
[tex]\text{Circumference of circle}=2\pi r=\pi D[/tex], where,
r = Radius of circle,
D = Diameter of circle.
Now we will find the circumference of wheel by substituting [tex]D=20[/tex] in above formula.
[tex]\text{Circumference of wheel}=\pi*20[/tex]
[tex]\text{Circumference of wheel}=62.83185307[/tex]
Since Chubby covers a distance of 62.83185307 cm in one rotation, so in 100 rotations distance covered by Chubby would be:
[tex]\text{Distance covered in 100 rotations}=100\times 62.83185307[/tex]
[tex]\text{Distance covered in 100 rotations}=6283.185307\approx 6283[/tex]
Therefore, Chubby ran a distance of 6283 centimeters.
A student bought a juice pouch for $2.50 and three bags of chips the total cost was $5.05 right and solve an equation to determine the cost of a bag of chips, c
The total amount of the purchase was ...
... $2.50 + 3c = $5.05
This equation can be solved by subtracting 2.50 and dividing by 3. Both these operations are done to both sides of the equation in accordance with the rules of equality.
... 3c = $2.55
... c = $0.85
The cost of a bag of chips was $0.85.
The cost of a bag of chips can be found by subtracting the juice price from the total cost and then dividing by the number of chip bags. This gives us an answer of $0.85 per bag.
Explanation:To solve this problem, we need to subtract the cost of the juice from the total cost, then divide that answer by the total number of chip bags bought to find the cost of one bag. First, we subtract the juice price ($2.50) from the total spent ($5.05), which gives us $2.55. This is the total cost of the chips. Then, we divide that $2.55 by the number of chip bags bought (which is three) to find the cost of one bag. This can be represented by the equation: c = (total cost - juice price) / number of chip bags, or c = ($5.05 - $2.50) / 3. Calculating this, we find that c equals $0.85, so a bag of chips costs $0.85.
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What is another way to name ∠QRS ? Select each correct answer. ∠R ∠S ∠Q ∠QSR ∠SRQ ∠RSQ
<SRQ Because if you go any other way other than its opppsite you would get a different angle.
Another way to name ∠QRS is ∠SRQ as R is the vertex of the angle.
What is a vertex?A vertex is a common endpoint between two rays that forms an angle.
We know when an angle is represented by three letters the vertex of the angle is the middle letter.
∴ Another name ∠for QRS is ∠SRQ because here R is the vertex of the angle and we can not place R in the first or the third place as it would completely change the vertex of the angle which are not the same angles, of Ofcourse their measure can be same but they are different.
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Valerie wants to take out a discount loan of $569. The rate is 4.5% for 250 days. How much interest will she pay? (Be sure to round the time to the nearest hundredth.
The interest is computed from
... I = Prt
where P is the principal amount ($569), r is the rate (0.045) and t is the time in years (250/360).
... I = $569×0.045×250/360 ≈ $17.78
Please note that time is not rounded. Rather, the exact value (25/36) is used in the calculation. The only rounding of any number is done at the end, where the amount is rounded to the nearest cent. (Your text authors should know this.)
_____
If you follow the problem instructions (which Valerie's lender will not do), the interest is calculated as ...
... t = 250/360 = 0.6944444... ≈ 0.69 . . . . years
... I = $569×0.045×0.69 ≈ $17.67
_____
Note the rounding of intermediate numbers (time) introduces an error of about $0.11 in the answer.
Answer:$17.41 (A+)
Step-by-step explanation:
An airplane has a maximum capacity of 118 passengers. The flight attendant has loaded 40 passengers. Which inequality represents the solution set that shows the number of passengers, p, that can still load the plane
A) p ≥ 68
B) p ≤ 68
C) p ≤ 78
D) p ≥ 78
C) p ≤ 78
I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.
Answer:
C) p ≤ 78
Step-by-step explanation:
so we know the plane has a maximum capacity of 118
and 40 have already been loaded.
118-40= 78
we know it cannot have greater than 78 but it can equal 78
there fore passengers are less than or equal to 78
also shown like this p ≤ 78 or option C
If i have a pay rate of $21.00 and marked up 78.7% and made a 10% profit. how did i get $41.28?
Answer:By multiplying with (1+0.01x) where x is the percentage of increase, monthly pay rate of 21$ after marked up 78.7% and 10% profit will be $41.28.
Step-by-step explanation:
Given that pay rate is 21$ and it is marked up by 78.7% and made a 10% profit.
If any value marked up or made a profit of x% then we have to multiply with (1+0.01x) to find the new value.
New pay after 78.7% marked up using above formula is [tex]21X(1+0.01X78.7)=21X1.787=37.527[/tex]
Now we have to use above formula again for 10% profit.
Hence new value [tex]=37.527(1+0.01X10)=37.527X1.1=41.2797[/tex]≈$41.28
Which of the following graphs represents a function that has a positive leading coefficient? Check all that apply.
Alright, so i'm looking at the graphs and i'm seeing B as an answer, Probably not A. C and D are confusing,
In the end, i'd say B and D.
If i'm wrong, please tell me.
The correct answers are (B), (C), and (D).
(C) is pretty straight forward. The graph resembles the graph of a quadratic function that us concave upwards. A quadratic function, and functions with an even degree like [tex]x^4, x^6[/tex] will be concave upwards if the leading term is positive.
For function with an odd degree such as [tex]x^3, x^5[/tex] will be mostly negative on the side of the negative x axis and positive on the side of the positive x-axis if the leading coefficient is positive. A cubic function with a positive leading term will be negative on the side of the negative x-axis for large negative numbers and positive on the side of the positive x-axis for large positive numbers. From this explaination we can gather that (B) and (D) are also correct .
The correct options are (B),(C) and (D).
HELP ASAP 30 POINTS
Who kills the Duke of Buckingham?
a.
the Comte de Wardes
c.
D'Artagnan
b.
Queen Anne
d.
Felton
D. John Felton kills the Duke of Beckingham
Here is some proof: https://en.wikipedia.org/wiki/John_Felton_(assassin)
Answer:
d
Step-by-step explanation:
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.
Tutorial Exercise Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 900 cm3, the pressure is 150 kPa, and the pressure is increasing at a rate of 40 kPa/min. At what rate is the volume decreasing at this instant?
Differentiating both sides of PV = C with respect to t gives us
Differentiating both sides of PV = C with respect to t gives us ...
... P'V +PV' = 0
Filling in the given numbers gives us ...
... (40 kPa/min)(900 cm³) + V'(150 kPa) = 0
Solving for V' gives ...
... V' = -(40 kPa/min)(900 cm³)/(150 kPa)
.. V' = -240 cm³/min
The volume is decreasing at the rate of 240 cm³/min.
Final answer:
In Physics, Boyle's Law relates the pressure and volume of a gas at constant temperature. To find the rate at which volume is decreasing as pressure increases, we differentiate the equation PV = C with respect to time and solve for [tex]\frac{dV}{dt}[/tex] , given the pressure, volume, and rate of change of pressure which comes out to be 240 cm³/min.
Explanation:
The subject of this question is Physics, specifically relating to Boyle's Law, which is part of gas laws studied in chemistry and physics. The level of this question is appropriate for High School students. We know from Boyle's Law that for a given amount of gas at constant temperature, the pressure P is inversely proportional to the volume V, meaning that PV = C or k, where C is a constant.
To solve the problem stated, we differentiate both sides of PV = C with respect to time t. This will give us P[tex]\frac{dV}{dt}[/tex] + V[tex]\frac{dP}{dt}[/tex] = 0. With the known values of P, V, and[tex]\frac{dP}{dt}[/tex] , we can solve for [tex]\frac{dV}{dt}[/tex], which will give us the rate at which the volume is decreasing as the pressure increases.
By substituting the given values into the differentiated equation: 150 kPa x [tex]\frac{dV}{dt}[/tex]+ 900 cm³ x 40 kPa/min = 0, we solve for [tex]\frac{dV}{dt}[/tex] to find the rate at which the volume is changing.
[tex]\frac{dV}{dt}[/tex] = - [tex]\frac{900}{150}[/tex] x 40
[tex]\frac{dV}{dt}[/tex] = -6 x 40
[tex]\frac{dV}{dt}[/tex] = -240 cm³/min
Following this method, we find that the volume is decreasing at a rate of 240 cm³/min.
What is the product of 4-5i and 2+3i
Multiply these as you would any binomial expressions, then replace i² with -1.
(4 -5i)·(2 +3i) = 4·2 +4·3i -5i·2 -5i·3i
... = 8 +12i -10i -15i²
... = 8+15 +2i
... = 23 +2i
_____
Your calculator may be able to do this problem for you.
Need help, thanks. :)
Answer:
f(2) = 0
Step-by-step explanation:
Plug x = 2 into the formula for f(x):-
f(2) = 2(2) - 4
= 4 - 4
= 0
f(2) = 0
substitute x = 2 into f(x)
f(2) = (2 × 2 ) - 4 = 4 - 4 = 0
the box part of the box plot contains all the values between which numbers?
between 27 and 36 and between 37 and 40
between 32 and 36
between 32 and 37
between 27 and 32 and between 37 and 40
The left end of the box is at 32; the right end is at 37. The box part of the plot contains all the values ...
... between 32 and 37.
Answer:
The correct option is 3.
Step-by-step explanation:
From the given box plot it is clear that
1. The left end point of the line is 27. So, the minimum value of the data is 27.
2. The left end of the box is 32. It means the first quartile of the data is 32.
3. The line inside the box represents the median. So the median of the data is 36.
4. The right end of the box is 37. It means the third quartile of the data is 37.
5. The right end point of the line is 40. So, the maximum value of the data is 40.
It means the box part of the box plot contains all the values between 32 and 37.
Therefore the correct option is 3.
what is 24 percent of 25
6
24% = [tex]\frac{24}{100}[/tex]
multiply 25 by this fraction
25 × [tex]\frac{24}{100}[/tex] = [tex]\frac{25(24)}{100}[/tex] = 6
A grocery store bought milk for $2.80 $2.80 per half gallon and stored it in two refrigerators. During the night, one refrigerator malfunctioned and ruined 13 13 half gallons. If the remaining milk is sold for $4.06 $4.06 per half gallon, how many half gallons did the store buy if they made a profit of $63.14 $63.14 ?
Let x represent the number of half-gallons purchased by the store. Then x-13 is the number sold, and 2.80x is the store's cost. The revenue is 4.06(x-13) and the difference between that and cost is the profit.
... 4.06(x -13) -2.80x = 63.14
... 1.26x - 52.78 = 63.14 . . . . eliminate parentheses, collect terms
... 1.26x = 115.92 . . . . . . . . . . add 52.78
... x = 115.92/1.26 = 92 . . . . . divide by the coefficient of x
The store purchased 92 half-gallons of milk.
Trish plans to sell off 40% of her fast food restraunt business. If the business has been appraised for 350,000 dollars how much money does she expect to raise
40% of $350, 000
40% = [tex]\frac{40}{100}[/tex] = 0.4, hence
expected amount = 0.4 × $350, 000 = $140, 000
How do I get the revised bill rate ?
The initial pay rate is $16.00. It is also mentioned that the price is marked up by 78.7%. It means that the prices are increased by 78.7%. Also, there is a profit of 10% too. So, the pay rates after mark up will be
$16.00 + (78.7% of 16.00)
= $16.00 + $12.592
=$28.592
And the pay rates after estimated profit is
$28.592 + (10% of $28.592)
= $28.592 + $2.8592
= $31.4512
Hence, the revised bill rate, rounded to the nearest cent is $31.45.
Solve the literal equation |ax+b|=c for x.
Try this solution; note, this way is not the shortest one.
The solutions for the modular equation are:
[tex]x = \frac{c - b}{a}[/tex] or [tex]x = -\frac{c + b}{a}[/tex]
-----------------------
A modular equation |f(x)| = a means that:
[tex]f(x) = a[/tex] or [tex]f(x) = -a[/tex]
-----------------------
The equation given is:
[tex]|ax + b| = c[/tex]
Which means that:
[tex]ax + b = c[/tex]
[tex]ax = c - b[/tex]
[tex]x = \frac{c - b}{a}[/tex]
Or
[tex]ax + b = -c[/tex]
[tex]ax = -c - b[/tex]
[tex]ax = -(c+b)[/tex]
[tex]x = -\frac{c + b}{a}[/tex]
The solutions are [tex]x = \frac{c - b}{a}[/tex] or [tex]x = -\frac{c + b}{a}[/tex]
A similar problem is given at https://brainly.com/question/5123313
50 Points
Find the specified vector or scalar. Show your work.
u = -4i + 1j and v = 4i + 1j; Find |u+v|.
| u + v | = 2
u + v = - 4i + 1j + 4i + 1j = 2j
the magnitude of a vector ai + bj is
| ai + bj | = √(a² + b² )
for u + v = 0 + 2j
| u + v | = √(0² + 2² ) = √4 = 2
Use the information about the graph of a polynomial function to determine the function. Assume the leading coefficient is 1 or −1. There may be more than one correct answer.
The y-intercept is
(0, 9).
The x-intercepts are
(−3, 0), (3, 0).
Degree is 2.
End behavior: as
x → −∞,
f(x) → −∞,
as
x → ∞,
f(x) → −∞.
y = -x² + 9
the x-intercepts are x = - 3 and x = 3 hence the factors are
(x + 3 ) and (x - 3 )
polynomial is the product of its factors
y = a(x - 3 )(x + 3) ← ( a is a multiplier )
from the end behaviour the parabola opens down and is a maximum and so the value of a is negative
y = -(x - 3)(x+3) = - (x² - 9 ) = - x² + 9
The polynomial function with the given features is f(x) = -(x + 3)(x - 3), which is a quadratic function with the required y-intercept, x-intercepts, and end behavior.
Explanation:The question involves finding a polynomial function given certain characteristics: a y-intercept of (0, 9), x-intercepts at (-3, 0) and (3, 0), a degree of 2, and specific end behavior.
Since the degree is 2, we are dealing with a quadratic function.
The x-intercepts tell us that the factors of the polynomial are (x + 3) and (x - 3).
The y-intercept indicates that when x is 0, the function equals 9.
The end behavior suggests that the leading coefficient is -1 because as x goes to infinity or negative infinity, f(x) goes to negative infinity.
Considering all the information, the function can be expressed as:
f(x) = -(x + 3)(x - 3)
To verify, expanding the factors gives:
f(x) = -(x^2 - 9)
f(x) = -x^2 + 9
This function has the required y-intercept of 9, x-intercepts of -3 and 3, and the correct end behavior.
I need help with number 2 please !!
The sales volume for an online bookstore was 432 books in the first week. Then due to the new policy of tax for on-line shopping, the sales volume dropped to 297 books at the second week. By what percent did the sales volume go down?
The volume drop is 432-297= 135
135 books is a fraction 135/432 of the original volume 432. That is (x100): 31.25%
So the sales went down by 31.25%
31.25 percent of sales go down in second week as compared to first week.
What is percentage?Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".
Given that, the sales volume for an online bookstore was 432 books in the first week.
Then due to the new policy of tax for on-line shopping, the sales volume dropped to 297 books at the second week.
Percentage dropped= 297/432 ×100
= 0.6875×100
= 68.75%
Now, 100-68.75=31.25%
Therefore, 31.25 percent of sales go down in second week as compared to first week.
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