100 points, please help? explanations are appreciated (: ill give brainliest too

The points A , B and R are coplanar  with point C and E , Option B is the correct answer.

Two points are called co planar when they lie on the same surface , for example all the points in a circle are co planar.

In the given figure The points A , B and R are co planar  with point C and E , C and E are not co planar with each other .

Therefore Option B is the correct answer.

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Answer:

  43.6°, 46.4°

Step-by-step explanation:

Let x represent the smaller angle. Then the complementary angle is (90°-x). The problem statement tells us the relation is ...

  x = (90°-x) -2.8°

  2x = 87.2° . . . . . add x, collect terms

  x = 43.6° . . . . . . divide by 2

Then the complementary angle is ...

  90°-x = 46.4°

The measures of the angles are 43.6° and 46.4°.

the answer is,

-2, 4, -8, 16, -32, 64

Answer,

Prime[1] = 2, Prime[2] = 3, Prime[3] = 5

Hope this helps :-)

ANSWER

The lines are two intersecting lines. They intersect` at the point [tex](\frac{1}{4}, \frac{9}{2})[/tex]

EXPLANATION

To determine which type of lines, we look for the slopes of the two lines and compare them to see whether they are parallel or perpendicular.

The first line is [tex]y=2x+4--(1)[/tex].

This line is already in the form;

[tex]y=mx+c[/tex], which is referred to as the slope intercept form, where [tex]m=2[/tex] is the slope.

The second line is

[tex]2y=-4x+10[/tex]

Dividing through by 2 gives;

[tex]y=-2x+5--(2)[/tex]

This implies that, this line also has a slope of [tex]-2[/tex].

Since the two slopes are not the same,the lines are not parallel.

Also the the product of the two slopes, [tex]-2\times 2 \ne -1[/tex], hence the two lines are  not perpendicular.

Adding equation (1) and (2) gives;

[tex]2y=9[/tex]

[tex]\Rightarrow y=4.5[/tex]

Putting [tex]y=4.5[/tex] in  equation (1) gives

[tex]4.5=2x+4[/tex]

[tex]\Rightarrow 0.5=2x[/tex]

[tex]\Rightarrow x=\frac{1}{4}[/tex].

Hence the two lines intersect` at the point [tex](\frac{1}{4}, \frac{9}{2})[/tex]

The answer would be translitive because if a=b and b=c then a

Is equal to c

That’s why the answer is translitive

Have you learned about translitive

If yo haven’t then the other answer would be the zero product

A [tex]x^{7}[/tex]

add the exponents when multiplying

[tex]x^{5}[/tex]× [tex]x^{2}[/tex] = [tex]x^{5+2}[/tex] = [tex]x^{7}[/tex]

To multiply x5 by x2, you add the exponents, resulting in x7 (option A). This operation follows the laws of exponents in algebra.

When asked to multiply x5 by x2, you are performing an operation in algebra known as exponentiation. According to the laws of exponents, when you multiply two exponential terms with the same base, you add the exponents. Therefore, x5 multiplied by x2 is x7 because 5 + 2 equals 7. The correct answer is A. x7.

Answer:

There are two discontinuities, one in the point (-2,2) and another on (-1,3).

Step-by-step explanation:

The discontinuity in (-2,2) is referred to as a removable discontinuity because this point is defined elsewhere.

The discontinuity in (-1,3) is called a jump discontinuity because it seems to "jump" from one point and continue at another.

Answer:

4.2*10^7

Step-by-step explanation:

Khan Academy

The human heart beats approximately 4.2 ⋅ 10^7 times in one year.

To calculate the number of times the human heart beats in one year, we need to multiply the average number of beats per day by the number of days in a year. The average human heart beats 1.15 ⋅ 105 times per day, and there are 3.65 ⋅ 102 days in one year. So, the number of times the heart beats in one year is:

1.15 ⋅ 105 times/day ⋅ 3.65 ⋅ 102 days/year = 4.1975 ⋅ 107 times/year

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[tex](0,\ 2);\ \left(\dfrac{\pi}{2},\ 0\right);\ (\pi,\ -2);\ \left(\dfrac{3\pi}{2},\ 0\right);\ (2\pi,\ 2);\ \left(\dfrac{5\pi}{2},\ 0\right);\ (3\pi,\ -2)\\\\\text{Look at the picture}\\\\Answer:\ \boxed{y=2\cos(x)}[/tex]

The two dollar bills are not similar because the ratios of their corresponding dimensions are not the same.

To determine if the two dollar bills are similar, we need to check if the ratios of the corresponding dimensions are the same.

The dimensions of the current dollar bill are 6.125 inches by 3.375 inches. The dimensions of the older dollar bill are 7.3125 inches by 3.125 inches.

Since the ratios (1.8148 and 2.3400) are not equal, the two dollar bills are not similar.

Circumference varies directly with radius means:

[tex]\frac{C}{r} = k[/tex]

[tex]\frac{9.42}{1.5} = k[/tex]

6.28 = k

So, the new equation is:

[tex]\frac{C}{r} = 6.28[/tex]

[tex]\frac{C}{9} = 6.28[/tex]

[tex](9)\frac{C}{9} = (9)6.28[/tex]

C = 56.52

****************************************

paycheck varies directly with hours means:

[tex]\frac{P}{h} = k[/tex]

[tex]\frac{52.50}{6} = k[/tex]

8.75 = k

So, the new equation is:

[tex]\frac{P}{h} = 8.75[/tex]

[tex]\frac{P}{11} = 8.75[/tex]

[tex](11)\frac{P}{11} = (11)8.75[/tex]

P = $96.25

Answer:

The answer is (1,6) so its either A or C since they both have (1,6)

Step-by-step explanation:

I think the answer is both A and C since there the same so the answer is 1,6

Answer:  The correct option is

(A) No, because one x-value correspond to two different y-values.

Step-by-step explanation:  We are given to check whether the table represent a function or not.

From the table, we note that

the corresponding values of x and y in form of ordered pairs are

(x, y) = (2, 1), (2, 4), (3, 4), (4, 2) and (5, 5).

We know that a set of ordered pairs (x, y) represents a function of no value of x correspond to more than one one value of y.

But, in the given table, when the value of x is 2, then we are getting two different values of y, 1 and 4.

That is, one value of x correspond to two different values of y.

Thus, the given table DOES NOT represent a function, because one x-value correspond to two different y-values.

Option (A) is CORRECT.

Marcy jogged 1.7 miles total. Hope I could help!!

This is all i could come up with

The strongest classification for quadrilateral ABCD is that it is a parallelogram because its opposite sides are parallel.

To determine the classification of quadrilateral ABCD, we need to examine its properties and compare them to the defining traits of different types of quadrilaterals. One of the most effective ways to do this is by calculating the slopes of its sides and the lengths of its sides and diagonals.

Slopes of Sides:

We first find the slopes of each side of the quadrilateral using the coordinates of its vertices.

Slope of AB: (5 - 2) / (3 - 1) = 3/2

Slope of BC: (3 - 5) / (5 - 3) = -1

Slope of CD: (1 - 3) / (2 - 5) = 2/3

Slope of DA: (2 - 1) / (1 - 2) = -1

Lengths of Sides and Diagonals:

Next, we compute the lengths of the sides and diagonals using the distance formula.

Length of AB: √((3 - 1)² + (5 - 2)²) = √(2² + 3²) = √13

Length of BC: √((5 - 3)² + (3 - 5)²) = √(2² + 2²) = 2√2

Length of CD: √((2 - 5)² + (1 - 3)²) = √((-3)² + (-2)²) = √13

Length of DA: √((1 - 1)² + (2 - 1)²) = √(0² + 1²) = 1

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i just took the assignment and the was correct

have a good day

The answer you are looking for is e= -2

The equation 9e - 7 = 7e - 11 simplifies to e = -2.

To solve the equation 9e - 7 = 7e - 11, follow these steps:

Thus, the value of e is -2.

ANSWER

[tex]-\frac{2}{3}(2x-\frac{1}{2})\le \frac{1}{5}x-1[/tex]

Multiply through by LCM of 15

[tex](15) \times -\frac{2}{3}(2x-\frac{1}{2})\le 15(\frac{1}{5}x-1)[/tex]

[tex] -10(2x-\frac{1}{2})\le 3x-15[/tex]

Expand brackets to obtain,

[tex] -20x+5\le 3x-15[/tex]

Group like terms

[tex] 15+5\le 20x+3x[/tex]

[tex] 20\le 23x[/tex]

[tex] \frac{20}{23}\le x[/tex]

[tex]x\ge \frac{20}{23}[/tex]

In interval form it is written as

[tex] [\frac{20}{23}, \infty)[/tex]

The correct solution to the inequality is x ≥ 20/23, written in interval notation as: [20/23, +Infinity).

In this mathematical inequality problem, your steps are correct until you get to -2/3(2x - 1/2) ≤ 1/5x - 1. Thereafter, however, your proceedings seem to be erroneous. Let's correct the steps:

So the solution to the inequality is x ≥ 20/23, which in interval notation would be written as: [20/23, +Infinity).

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Answer:

Perimeter of triangle = 71.72 unit.

Area of triangle = 149.44 unit²

Explanation:

 Distance between (a,b) and (c,d) = [tex]\sqrt{(c-a)^2+(d-b)^2}[/tex].

 So we have  SB = [tex]\sqrt{(-2-15)^2+(21-(-8))^2}=\sqrt{1130} =33.62[/tex]unit

                       BA = [tex]\sqrt{(0-(-2))^2+(0-21^2)}=\sqrt{445} =21.10[/tex]unit

                       AS = [tex]\sqrt{(15-0)^2+(-8-0)}=\sqrt{289} =17[/tex]unit

 So perimeter of triangle = 33.62 + 21.10 + 17 = 71.72 unit.

  We have SB = Base = 33.62 unit and Perpendicular height = 8.89 units.

  Area = 0.5 x Base x Perpendicular height.

           = 0.5 x 33.62 x 8.89 = 149.44 unit²

The perimeter of the triangle SBA is approximately 66.91 units and the area is approximately 131.06 square units.

To find the perimeter of triangle SBA, we need to find the lengths of the three sides first. We can use the distance formula to calculate the length of each side. Using the coordinates of S(15,-8), B(-2,21), and A(0,0), we find that SB ≈ 29.47 units, BA ≈ 18.19 units, and AS ≈ 19.25 units. The perimeter is the sum of these three lengths, which is approximately 66.91 units.

To find the area of triangle SBA, we can use the formula: area = 1/2 * base * height. The base is the length of SB, which is approximately 29.47 units, and the height is given as 8.89 units. Plugging these values into the formula, we get the area ≈ 131.06 square units.

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You can make 20 quarter pounders based on the information provided. You can show your work by dividing 5 by .25. You need to make both of these a fraction by doing 5/1 x 1/4. This leading you to get 20 making this your answer.

the answer should be {-2+4i,-2-4i}

Answer:

{-1-2i, -1-2i}

Step-by-step explanation:

1. Consider right triangle ABK. The hypotenuse AB is 6 un. and the leg AK is 3 un. Since the leg is half of the hypotenuse, then the opposite to the leg angle is 30°. This means that m∠ABK=30°. Then m∠BAK=90°-30°=60°.

2. By the Pythagorean theorem,

[tex]AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9,\\\\BK^2=27,\\\\BK=3\sqrt{3}\ un.[/tex]

3. Consider right triangle ABD. In this triangle AD is hypotenuse and m∠ADB=90°-m∠BAD=90°-60°=30°. Then the leg AB opposite to the angle 30° is half of the hypotenuse and AD=12 un.

4. The area of parallelogram is

[tex]A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.[/tex]

Answer:

I would say D

Answer:

4

Step-by-step explanation:

A certain arithmetic sequence has this explicit formula for the nth term:

[tex]a_n = 11 + (n- 1)(4)[/tex]

Substitute n = 1

[tex]a_1 = 11 + (1- 1)(4)[/tex]

[tex]a_1 = 11 [/tex]

Substitute n =2

[tex]a_2 = 11 + (2- 1)(4)[/tex]

[tex]a_2 = 15[/tex]

[tex]d= a_2-a_1=15-11=4[/tex]

So,[tex]a_2=a_1+d=11+4=15[/tex] --1

Substitute n = 3

[tex]a_3 = 11 + (3- 1)(4)[/tex]

[tex]a_3 = 19[/tex]

[tex]a_3=a_2+d=15+4=19[/tex] ---2

So, with 1 and 2

Recursive formula : [tex]a_n=a_{n-1}+d[/tex]

Since d is 4

So, the number belongs in the blank space in the recursive formula is 4.

You would use PEMDAS to solve this:

0.8 x 1.5 = 1.2

4 + 1.2 - 3

5.2 - 3

2.2 is your answer

Answer:

the answer is 2.2