Answer:
44 mL of Na2SO4
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)
Step 2:
Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:
Molarity of Ba(NO3)2 = 0.5 M
Volume of solution = 20 mL = 20/1000 = 0.02 L
Mole of solute (Ba(NO3)2) =?
Molarity = mole /Volume
0.5 = Mole of Ba(NO3)2 / 0.02
Cross multiply to express in linear form
Mole of Ba(NO3)2 = 0.5 x 0.02
Mole of Ba(NO3)2 = 0.01 mole
Step 3:
Determination of the number of mole of Na2SO4 that reacted.
Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)
From the balanced equation above,
1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.
Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.
Step 4:
Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:
Mole of Na2SO4 = 0.01 mole
Molarity of Na2SO4 = 0.225M
Volume =?
Molarity = mole /Volume
0.225 = 0.01 / volume
Cross multiply to express in linear form
0.225 x Volume = 0.01
Divide both side by 0.225
Volume = 0.01/0.225
Volume of Na2SO4 = 0.044 L
Converting 0.044 L to mL, we have
Volume of Na2SO4 = 0.044 x 1000
Volume of Na2SO4 = 44 mL
Therefore, 44 mL of Na2SO4 is needed for the reaction
Answer:
She has to add 44.44 mL of Na2SO4
Explanation:
Step 1: Data given
Volume of barium nitrate = 20.00 mL = 0.020 L
Molarity of barium nitrate = 0.500 M
Molarity of sodium sulfate = 0.225 M
Step 2: The balanced equation
Ba(NO3)2 (aq) + Na2SO4 (aq) → BaSO4 (s) + 2 NaNO3 (aq)
Step 3: Calculate volume of the sodium sulfate solution needed
For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol basO4 and 2 moles NaNO3
C1*V1 = C2*V2
⇒with C1 = the molarity of Ba(NO3)2 = 0.500 M
⇒with V1 = the volume of Ba(NO3)2 = 0.020 L
⇒with C2 = the molarity of Na2SO4 =0.225 M
⇒with V2 = the volume of Na2SO4 = TO BE DETERMINED
0.500 M * 0.020 L = 0.225 M * V2
V2 = (0.500 M * 0.020 L) / 0.225 M
V2 = 0.04444 L = 44.44 mL
She has to add 44.44 mL of Na2SO4
- Describe how the amount of air changes as you travel up through Earth's atmosphere
Answer:
The air in our atmosphere is composed of molecules of different gases. ... While the composition doesn't change much as you travel up through the lower layers of the atmosphere, what does change is the number of molecules. As you travel higher, the air molecules become less plentiful.
Explanation:
-. Is Electricity naturally produced in our environment.
Marcie is hiking in the mountains and she discovers an interesting shiny rock.As she picks it up she wonders whether it could be a mineral or whether it's just a rock. She notes that it is solid and naturally occurring with a definite chemical composition, but that it has no definite crystal structure
Given its lack of a definite crystal structure, Marcie's shiny rock is likely a rock, not a mineral. Rocks are comprised of various minerals and other materials, which results in a less distinct structure compared to minerals.
Explanation:Marcie's shiny rock is likely a rock, given its description. Rocks and minerals, while sharing some characteristics, have key differences. Both rocks and minerals are solid, naturally occurring substances. However, minerals, besides having a definite chemical composition, also possess a specific crystal structure. By confirming that Marcie's shiny rock does not have a definite crystal structure, it's safer to categorize it as a rock. Rocks are comprised of different minerals as well as other elements, making them less uniform than minerals. Rocks range from three basic types: igneous (from molten rock or lava), sedimentary (from the deposition and sedimentation of organic or inorganic particles), and metamorphic rock (undergone chemical alteration under high temperature and pressure).
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Marcie's rock is likely a rock, not a mineral, due to its lack of a definite crystalline structure. Although certain rocks with metallic content can be extraterrestrial, no indication is given to suggest this. The rock could be classified as metamorphic, sedimentary, or igneous, depending on its formation process.
Explanation:Marcie's shiny rock, being solid, naturally occurring, and possessing a definite chemical composition, meets most criteria to be termed a mineral. However, a key aspect of a mineral is that it exhibits a definite crystalline structure, which her rock does not. Hence, it would better be described as a rock. Rocks can be an amalgamation of different minerals and do not require a specific crystalline structure to classify.
The identified characteristics of the rock, however, do not necessarily mean it is extraterrestrial in origin, as the provided references might suggest. While it is true that the irons and stony-irons with metallic content can be extraterrestrial, there is no indication given that Marcie's rock is metallic or contains iron. Therefore, it is unlikely a meteorite. It may require a laboratory analysis to confirm this.
It may be a metamorphic, sedimentary, or igneous rock, which are categories based on their geologic formation processes. Metamorphic rocks undergo physical and chemical alteration under high temperature and pressure, sedimentary rocks are formed from the sedimentation of particles, and igneous rocks originate from the solidification of magma or lava.
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Draw Bohr model of atom with atomic number 16 and name the element. What is the valency of the atom? What type of ion does it form and what will be the value of the charge on the ion produced? Justify the answer.
Answer:
Sulphur is the element having atomic number 16. Its valency is 6 and forms anion.
Explanation:
Sulphur is the element having atomic number 16 and mass number 32 which means sulphur has 16 proton, 16 electron and 16 neutron. 2 electrons are present in the first shell, 8 electrons are present in the second shell and 6 electrons are present in the outermost shell. Sulphur requires 2 electrons to become stable so that's why sulphur take 2 electrons and become anion. its valency is 6 which means 6 electrons are present in the outermost shell of sulphur atom.
A 0.2475−g sample of solid magnesium is burned in a constant-volume bomb calorimeter that has a heat capacity of 3024 J/°C. The temperature increases by 2.027°C. (a) Calculate the heat associated with the burning Mg in kJ/g. kJ/g (b) Calculate the heat associated with the burning of Mg in kJ/mol.
Answer:
ΔH = -601.9 kJ/ mol Mg
Explanation:
Step 1: Data given
Mass of the solid magnesium sample = 0.2475 grams
The heat capacity of calorimeter = 3024 J/°C
The temperature increases by 2.027 °C
Step 2: Calculate the heat transfer
q = Ccal * ΔT
⇒with q = the heat transfer
⇒with Ccal = the heat capacity of calorimete 3024 J/°C
⇒ΔT = The temperature increases by 2.027 °C
q = 3024 J/°C * 2.027 °C
q = 6129.6 J
Since this is an exothermic reaction, ΔH will be negative
Step 3:Calculate the heat associated with the burning of Mg
Heat = -6129.6 J / 0.2475 grams Mg
Heat = 24766 J/grams = -24.77 kJ /grams Mg
Heat = -24.77 kJ/ grams * 24.3 g/mol
ΔH = -601.9 kJ/ mol Mg
What’s the connection between population and limiting factors?
Answer:
Limiting factors are resources or other factors in the environment that can lower the population growth rate. Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration.
Explanation:
How do balanced chemical equations show the conservation of mass
Answer: Matter cannot be created or destroyed
Explanation: Balanced equations are set equations we cannot change one element or compound in the equation without changing the entire equation. So balanced equation show the conservation of mass because while other substances may be formed from the synthesis or decomposition of compounds new elements are never introduced and are not created out of thin air :)
Answer:
Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.
The temperature at 300 seconds (5 minutes) is the
final temperature of both the metal and the water.
Record it to the nearest 0.1°C in the data table.
Initial temperature of metal =
Initial temperature of water = 0
Final temperature of both =
'c
RETRY
250 ml
Continue (60s more)
05:00
Answer:
initial temperature of metal : 100
initial temperature of water : 22.4
final temp of both 27.1
Explanation: that one is for aluminum so i don’t know which metal you needed if for though
Answer:
Initial metal= 100
Initial water= 22.7
Final Both= 24.6
Explanation: THESE ARE FOR COPPER
Warm-Up
A 206-gram bar of iron has sunlight shining on it. Initially, its temperature is 24.7°C. As it gains 1,070.79 joules of energy, its
temperature rises to 36.2°C. Calculate the specific heat capacity of the iron bar using the formula Q = mCAT.
Answer:
0.425
Explanation:
Answer:
0.452
Explanation:
Enzymes use several types of catalytic mechanisms. Differentiate between acid-base catalysis
Answer:
Explanation:
Covalent catalysis is when a transient covalent bond is formed between substrate and residues such that so the enzyme nucleophilic group on an electrophilic moiety of the substrate is bound at the active site. Metal ion catalysis involves activating bound water through forming nucleophilic hydroxide ion.
Protonation or proton abstraction may be accomplished through the use of amino acids such as aspartate or Lysine in acid-base catalysis.
What is catalysis ?The term Catalysis is defined as the process of adding a catalyst to facilitate a reaction. During a chemical reaction, the bonds between the atoms in molecules are broken, rearranged, and rebuilt, recombining the atoms into new molecules.
Catalysis by covalent bonds the two-part catalytic process forms a covalent bond between enzyme and substrate (for example, chymotrypsin mechanism uses a nucleophilic functional group).
By changing the oxidation state, metal ion catalysis catalysts can participate in oxidation-reduction reactions.
Through ionic interactions, a Zn2+ cofactor may properly orient the substrate in the active site. May be involved in Fe2+ interactions.
All lowers activation energy or stabilizes the transition state or intermediate catalyst after the reaction occurs.
Thus, a proton is transferred between enzyme and substrate may use amino acids such as aspartate or Lysine for protonation or proton abstraction is called as acid-base catalysis.
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Your question is incomplete, most probably your question was
Enzymes use several types of catalytic mechanisms. Differentiate between acid-base catalysis, covalent catalysis, and metal ion catalysis.
The characteristic odor of pineapple is due to ethyl butyrate, an organic compound which contains only carbon, hydrogen and oxygen. If a sample of ethyl butyrate is known to contain 0.62069 g of carbon, 0.103448 g of hydrogen and 0.275862 g of oxygen, what is the empirical formula for ethyl butyrate?
Answer:
C3H6O
Explanation:
Data obtained from the question. This includes:
Carbon (C) = 0.62069 g
Hydrogen (H) = 0.103448 g
Oxygen (O) = 0.275862 g
The empirical formula can be obtained as follow:
Step 1:
Divide by their molar mass.
C = 0.62069 / 12 = 0.0517
H = 0.103448 / 1 = 0.103448
O = 0.275862 / 16 = 0.0172
Step 2:
Divide by the smallest number.
C = 0.0517 / 0.0172 = 3
H = 0.103448 / 0.0172 = 6
O = 0.0172 / 0.0172 = 1
Step 3:
Writing the empirical formula.
The empirical formula is C3H6O
Answer:
The empirical formula is C3H6O
Explanation:
Step 1: Data given
A sample of ethyl butyrate contains:
0.62069 g of carbon
0.103448 g of hydrogen
0.275862 g of oxygen
Atomic mass of carbon = 12.01 g/mol
Atomic mass of hydrogen = 1.01 g/mol
Atomic mass of oxygen = 16.0 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles carbon = 0.62069 grams / 12.01 g/mol
Moles carbon = 0.0517 moles
Moles hydrogen = 0.103448 grams / 1.01 g/mol
Moles hydrogen = 0.1024 moles
Moles oxygen = 0.275862 grams / 16.0 g/mol
Moles oxygen = 0.0172 moles
Step 3: Calculate the mol ratio
We divide by the smalllest amount of moles
C: 0.0517 moles / 0.0172 moles = 3
H: 0.1024 moles / 0.0172 moles = 6
O: 0.0172 moles / 0.0172 moles = 1
The empirical formula is C3H6O
Okay, so i got a question about phenotype, and geneotype, and i dont know how to do it. The question is: Some trolls have one eye (EE, Ee) while others have two (ee). Two heterozygous one eyed trolls are crossed. What is the expected genotype ratio of the two eyed offspring?
Answer:
= 25 %
Explanation:
Given that :
the genotype attributed to trolls having one eye = (EE, Ee); that is homzygous dominant or heterozygote dominant for eye number
Likewise those that posses two eyes have (ee) ; that is homzygous recessive
Now; two heterozygous one eyed trolls are crossed ; we have :
Ee × Ee
The punnet square for this cross looks like what we have below:
E e
E EE Ee
e Ee ee
From the above cross; we have:
1 EE ---- (homozygous dominant ) indicating troll having one eye
2 Ee ---- ( heterozygote dominant ) indicating troll having one eye
1 ee ----- ( homozygous recessive ) indicating troll having two eyes
The genotypic ratio is 1:2:1
Thus; the expected genotype ratio of the two eyed offspring = [tex]\frac{1}{4}*100[/tex]
= 25 %
Answer:
25% is the expected genotype ratio of the two-eyed offspring.
Explanation:
First, we analyze the information that we have:EE or Ee are trolls with one eye.ee are trolls with two eyes.E is dominant and is the gene responsible for one eye.e is recessive and is the gen responsible for two eyes.If two heterozygous trolls are crossed that means that both trolls are Ee, they have different copies of the same gene. After looking at the information, we draw a Punnett Square, and we can see that there is a 25% that their offspring is a two-eyed troll (ee).║ E ║ e ║
E║ EE ║ Ee ║
e ║ eE ║ ee ║
Identify each substance as an acid or a base.
liquid drain cleaner, pH 13.5
milk, pH 6.6
DONE
Intro
Answer:
Liquid drain cleaner: Base
Milk: Acid
Explanation:
Would make sense to see this on the pH scale where anything above 7 is basic and below 7 is acidic.
The identification of each substance treated as an acid or substance should be Liquid drain cleaner: Base and Milk: Acid
What are acid and base?Acid should be treated as the hydrogen that contained the substance where the proton should be donated to the other substance. While on the other hand, the base represent the molecule for accepting the hydrogen ion from an acid. Also if the pH scale should be above 7 so it should be treated base while below should be treated as the acid.
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1. During her soccer game, Erica accidentally kicks the ball (3.6L) into a trash can! The temperature on
the field is 10°C, but in the trash can it is 25°C. Cindy, standing nearby, wonders "hmmm hat is new
volume of the soccer ball if atmospheric pressure did not change?"
The new volume of the soccer ball is 9 litres when temperature inside the can was 25°C and pressure remained constant.
Explanation:
Data given:
initial volume of the ball, V1 = 3.6 litres
temperature of the field, initial temperature, T1 = 10°C
temperature in the trash can, final temperature, T2 = 25 °C
pressure =constant throughout
volume of the ball when in trash can, final volume V2 =?
From the data given:
Charles' Law will be applied to know the volume of the ball in the can:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
putting the values in the equation after rearranging it:
V2 = [tex]\frac{V1T2}{T1}[/tex]
V2 = [tex]\frac{3.6 X 25}{10}[/tex]
V2 = 9 litres
The volume will be increased to 9 litres when ball will go inside the trash can.
How many moles of potassium chloride (KCI) are in 252 mL of 0.33 mil/L KCI
Answer:
0.083 moles KCl
Explanation:
We have 252 mL of 0.33 M KCl. "M" is molarity, and it's measured in mol/L. Since we know the molarity is 0.33 mol/L, in order to find how many moles 252 mL is, we need to multiply our given volume by the molarity.
However, our given volume is in mL, so let's convert to L first by dividing 252 by 1000 (because there are 1000 mL in 1 L):
252/1000 = 0.252 L
Now, we can multiply 0.252 L by 0.33 mol/L to get moles since the L units will cancel out:
0.252 L * 0.33 mol/L = 0.08316
We have two significant figures here, so round 0.08316 to 0.083.
The answer is 0.083 moles.
Hope this helps!
Which of the following are not at equilibrium? Check all that apply. Check all that apply. The concentrations of reactants and the products are not constant. The rate of the forward reaction does not change. The rates of the forward and reverse reactions are equal.
The concentrations of reactants and the products are not constant and the rates of the forward and reverse reactions are equal. and these reactions are not at equilibrium.
Explanation:
The conditions to attain equilibrium is that,
Conversion of reactant to product and vice versa occurs at the same rate.The system is a closed system.The temperature remains constant.Concentration of every substance remains constant.Rate of forward and reverse reactions will be different.So the answer is The concentrations of reactants and the products are not constant and the rates of the forward and reverse reactions are equal.
A system is at equilibrium when the rates of forward and reverse reactions are equal and the concentrations of reactants and products are constant. Thus, any changes in concentrations or reaction rates indicate that the system is not at equilibrium.
Explanation:Based on Chemical Equilibrium principles, a system is at equilibrium when the rates of the forward and reverse reactions are equal, and the concentrations of reactants and products are constant. Therefore, if the concentrations of the reactants and the products are not constant, the system is not at equilibrium. Similarly, if there is a condition where the rate of the forward or reverse reaction does not change, the system is also not at equilibrium.
This means that even if the forward and reverse reaction rates are equal, but the concentrations are still fluctuating, the system hasn't reached equilibrium yet. So changes in the concentrations of the reactants or products indicate that the system is not in equilibrium. These principles form the basis of the Le Châtelier's principle.
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which two conditions must exist in population for natural selection to take place ?
Final answer:
Natural selection requires genetic variation within a population and environmental pressures that select for certain traits, leading to changes in the population's genetic makeup over generations.
Explanation:
For natural selection to take place in a population, two essential conditions must exist: genetic variation among individuals and environmental pressures that favor certain traits over others. Genetic variation ensures that there are differences in traits among individuals, which may be advantageous or not depending on the environmental context. These traits must have a genetic basis so that they can be inherited by the next generation.
Environmental pressures, such as climate change, predation, availability of resources, and competition, then determine which of these traits are beneficial, leading to the greater reproductive success of individuals with those traits, thus altering the genetic makeup of the population over time.
85.0 grams of NaN3 decompose at 75 degrees Cesius and at 2.3atm. Of pressure. What volume of N2 will be made according to the equation: 2NaN3(g) -------> 2Na(g) + 3N2(g)
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore the volume of N[tex]_2[/tex] will be made according to the equation is 2.64l.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature. Ideal gas is a hypothetical gas. Vanderwaal gas can behave as ideal gas at low pressure and high temperature.
Mathematically,
PV=nRT
where,
P = pressure= 2.3atm
V= volume=?
n =number of moles=85.0/65.01
=1.30moles
T =temperature=348K
R = Gas constant = 0.0821 L.atm/K.mol
Substituting all the given values in the above equation, we get
2.3 × V=1.30× 0.0821 L.atm/K.mol × 348 K
V=1.76l
volume of nitrogen = 3/2× 1.76l=2.64l
Therefore the volume of N[tex]_2[/tex] will be made according to the equation is 2.64l.
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To calculate the volume of nitrogen gas produced from the decomposition of NaN3 at a given temperature and pressure, we must apply the stoichiometry from the balanced chemical equation and use the ideal gas law formula.
Explanation:The student's question involves determining the volume of nitrogen gas (N2) produced from the decomposition of sodium azide (NaN3) under specified conditions of temperature (75 degrees Celsius) and pressure (2.3 atm). To solve this, one must use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. The first step is to calculate the moles of N2 that can be produced from 85.0 grams of NaN3 using the stoichiometry of the given balanced equation.
Firstly, one needs to find the molar mass of NaN3 to convert grams to moles. Then, apply the stoichiometry from the balanced equation (2 mol NaN3 produces 3 mol N2). Finally, using the calculated number of moles of N2, apply the ideal gas law to find the volume of nitrogen gas at the given temperature and pressure.
Whenever quantities of two or more reactants are given in a stoichiometric problem, you must identify the __________. This is the reagent that is completely up in the reaction.
The amount of limiting reagent determines the amount of __________ that is formed. When an equation is used to calculate the amount of product that will form during a reaction, the value obtained is the __________. This is the amount of product that could be formed from a given amount of__________. The amount of product that forms when the reaction is carried out in the laboratory is called the __________.
Answer:
1. Limiting reactant.
2. Product.
3. Theoretical yield.
4. Reactants.
5. Actual yield
Explanation:
1. The limiting reactant. The limiting reactant is the reagent that is completely up in the reaction.
2. Product. Product is the result obtained From a reaction and the amount of product formed is determined by the limiting reactant
3. Theoretical yield. This is the result obtained from the stoichiometry calculations.
4. Reactant. Reactant are the starting material for a chemical reaction. The amount of the reactants determines the theoretical yield (products)
5. Actual yield. This is the result obtained from the experiment carried out in the laboratory.
"You measure 48.9 mL of a solution of sulfuric acid with an unknown concentration, and carefully titrate this solution using a 1.500 M solution of KOH. You find that 34.7 mL of the KOH solution is required to fully neutralize the acid. What is the concentration of the original sulfuric acid solution
Answer:
C= 0.532M
Explanation:
The equation of reaction is
H2SO4 + 2KOH = K2SO4+ H2O
nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml
Applying
CAVA/CBVB = nA/nB
(CA× 48.9)/(1.5×34.7)= 1/2
Simplify
CA= 0.532M
Sarah lives beside the ocean in Eureka, California. Her penpal, Ruby, lives in Redding, California, which is located inland. As a school project one year, Sarah and Ruby decide to collect local climate data and compare the average monthly high and low temperatures from their cities. The data they collect are shown below. Month Eureka Average High Eureka Average Low Redding Average High Redding Average Low January 54°F 41°F 55°F 35°F February 55°F 43°F 58°F 38°F March 55°F 43°F 70°F 41°F April 56°F 45°F 71°F 45°F May 58°F 48°F 80°F 52°F June 60°F 51°F 89°F 60°F July 61°F 52°F 98°F 64°F August 62°F 53°F 97°F 61°F September 63°F 51°F 89°F 56°F October 61°F 49°F 69°F 45°F November 58°F 45°F 60°F 40°F December 55°F 42°F 55°F 34°F Based on the climate data that Sarah and Ruby collect, they can conclude that
Answer:
Temperature variance at Redding > > Temperature variance beside at Eureka
Monthly temperatures at Redding are generally higher than the monthly temperatures beside the ocean at Eureka
Explanation:
Month January
Eureka Eureka Redding Redding
Average Average Average Average
High Low High Low
54°F 41°F 55°F 35°F
February
55°F 43°F 58°F 38°F
March
55°F 43°F 70°F 41°F
April
56°F 45°F 71°F 45°F
May
58°F 48°F 80°F 52°F
June
60°F 51°F 89°F 60°F
July
61°F 52°F 98°F 64°F
August
62°F 53°F 97°F 61°F
September
63°F 51°F 89°F 56°F
October
61°F 49°F 69°F 45°F
November
58°F 45°F 60°F 40°F
December
55°F 42°F 55°F 34°F
58 46.92 74.25 47.58 Mean
3.16 4.25 15.99 10.63 Standard Dev
9.97 14.08 255.84 112.992 Variance
63 53 98 64 Max
54 41 55 34 Min
Based on the climate data that Sarah and Ruby collect, they can conclude that
From the data we have
From the data it is observed that the temperatures beside the ocean in Eureka are lesser than and more stable (vary less) than the temperatures in Redding, also the temperatures in Redding are much higher than the temperatures beside the ocean in Eureka.
Elements in group 7A in the periodic table are called the halogens: elements in group 6A are called the chalcogens (a)
What is the most common oxidation state of the chalcogens compared to the halogens? (b) For each of the following
periodic properties. state whether the halogens or the chalcogens have larger values: atomic radii, ionic radii of the most
common oxidation state, first ionization energy. second ionization energy.
Answer:
Most common oxidation state of the chalcogens is -2, most common oxidation state of the halogens is -1.
Explanation:
For atomic radii, the chalcogens have a larger atomic radii than the halogens
This is because atomic radii decreases across the period due to increase in nuclear charge.
For ionic radii the chalcogens also have larger ionic radii than the halogens. This is because the chalcogens always carry a -2 charge compared to halogens that carry a -1 charge. Since -2 is the most common oxidation state for chalcogens and -1 is the most common oxidation state for the halogens.
In terms of oxidation states, the halogens show a higher value of common oxidation state -1 while for chalcogens is -2 even though +2, +4 and +6 oxidation states are also well known.
First ionization energy of halogens is greater than that of the chalcogens due to greater effective nuclear charge.
The second ionization energy of chalcogens is greater than that of the halogens.
Chalcogens have −2, +2, +4, and +6 whereas halogens have −1, +1, +3, +5, and +7 oxidation state.
The most common oxidation states of the elements of chalcogens are −2, +2, +4, and +6 while on the other hand, the oxidation states of halogens such as fluorine, chlorine, bromine, and iodine are −1, +1, +3, +5, and +7. The chalcogens have larger atomic as well as ionic radii as compared to halogens because of the presence of less number of electrons in the outermost shell.
We know that when we moves from left to right in the periodic table, atomic radius decreases due to addition of extra electrons in the outermost shell. The attraction of nucleus on the additional electron increases which leads to movement of outermost shell nearer to nucleus.
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A 4.0 g sample of iron was heated from 0°C to 20.°C. It absorbed 35.2 J of energy as heat. What is the specific heat of this piece of iron?
Answer:
Explanation:i joule is equal to 0.238902957619 calories so 1251 joules is equal to 298.87 calories divided by 25.0 degrees centigrade is equal to 11.95 calories divided by the 35.2 gram sample weight to get the calories per gram per degree centigrade would come to 0.3396 calories/gram degree centigrade. Presumably this, if correct, could be used to obtain the metal in question by consulting a chart or table with specific heats of various metals because they should always be the same specific heat for each metal.
Please consider the following gas phase reaction and its experimentally determined rate law expression. If the concentration of A is tripled and the concentration of B is doubled, the reaction rate would be increased by a factor of:_________.
A + B → C rate = k[A]^2 [B]
A) 6
B) 9
C) 12
D) 18
E) 36
Answer:
D) 18
Explanation:
Hello,
In this case, by considering the given rate law:
[tex]r=k[A]^2[B][/tex]
We also take into account that the concentration of A is tripled and the concentration of B is doubled, therefore, we have:
[tex]r=k[3*A]^2[2*B][/tex]
Which results in an increasing factor of:
[tex]3^2*2=9*2=18[/tex]
By considering only the tripling and the doubling, thus, the answer is D) 18.
Regards.
threats faced by the Everglades and the Louisiana wetlands.
Answer:
Invasive species, runoff pollution, and climate change.
Explanation:
Invasive species, such as Burmese pythons, threaten the Florida Everglades because they are not native to the natural habitat. Pythons eat the native animals, but they don't have any predators.
Pollution from nearby farms and roads enters the water and damages the ecosystem of the Everglades and Louisiana wetlands. Toxic chemicals lead to detrimental effects for both humans and wildlife.
Humans have drained swampy areas to allow for development. However, this has led to the Everglades drying up and even burning in recent years.
why can a magnet separate iron and sulphur in a mixture but not a compound?
Answer:
A compound is different from elements in that it is made from the chemical union of two or more elements. ... Mixtures are different from compounds in that they are easily separated. A magnet could be used to separate the iron from the sulfur, because iron is attracted to magnets, while sulfur is not.
Explanation:
The equation represents the combustion of sucrose. C12H22O11 + 12O2 Right arrow. 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? 0.029 mol 0.250 mol 0.351 mol 3.00 mol
Answer: 0.029 mol
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
The balanced chemical equation is:
[tex]C_{12}H_{22}O_{11}+12O_2\rightarrow 12CO_2+11H_2O[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{10.0g}{342g/mol}}=0.029moles[/tex]
Thus there are 0.029 moles of sucrose
Answer:
A
Explanation:
4. What are the properties of the elements in the Boron group?
Answer:
they are characterized as a group by having 3 electrons in the outermost parts of their atomic structure. boron the lighter of these elements
5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(PO4)2 + 6 H2O
Answer:
Mass of Mg(OH)₂ required for the reaction = 863.13 g
Explanation:
3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O
(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.
According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.
This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.
1 mole = (6.022 × 10²³) molecules.
x mole = (5.943 x 10²⁴) molecules
x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)
x = 9.87 moles
From the stoichiometric balance of the reaction,
2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂
9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂
y = (3×9.87)/2 = 14.80 moles
So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass
Mass = (number of moles) × Molar mass
Molar mass of Mg(OH)₂ = 58.3197 g/mol
Mass of Mg(OH)₂ required for the reaction
= 14.8 × 58.3197 = 863.13 g
Hope this Helps!!!
Answer:
5.943 × 10²⁴ molecules of H₃PO₄ will react with 789.29 grams of Mg(OH)₂
Explanation:
Here we have
5.943 × 10²⁴ molecules of H₃PO₄ in a reaction with Mg(OH)₂
as follows
3Mg(OH)₂ + 2H₃PO₄ → Mg₃(PO₄)₂ + 6H₂O
Therefore 3 moles of Mg(OH)₂ react with 2 moles of H₃PO₄ to form 1 mole of Mg₃(PO₄)₂ and 6 moles of H₂O
5.943 × 10²⁴ molecules of H₃PO₄ which is equivalent to [tex]\frac{5.943 \times 10^{24}}{6.02 \times 10^{23}} moles = 9.869 \, moles \, of \, H_3PO_4[/tex]
Will react with 3/2×9.869 moles or 14.8 moles of Mg(OH)₂
One mole of Mg(OH)₂ weighs 58.3197 g/mol
Therefore, 5.943 × 10²⁴ molecules of H₃PO₄ will react with 14.8×58.3197 g or 789.29 grams of Mg(OH)₂.
"Acetylcholinesterase follows Michaelis-Menten kinetics. A 1.3 micromolar solution of acetylcholinesterase catalyzes the formation of 6.5 mmoles choline s-1 when saturated with acetylcholine. What is acetylcholinesterase's kcat?"
Answer:5000 s^-1
Explanation: Solution=
Using the formulae----> Kcat=Vmax/Et
where
Vmax is the maximum rate of the reaction when all the enzymes are saturated.
Vmax= 6.5 mmoles/s
Et=1.3 uM
1 mmole= 1000 umole
Changing to micromoles/sec, gives=
Vmax= 6.5 mmoles/s \times 1000= 6500 micromoles/s
Bringng back the equation,
----->Kcat= Vmax/Et
= 6500/1.3
= 5000 /s
Therefore, our answer is 5000 s^-1