128,96,72,54,...find the common ratio

Answers

Answer 1
Final answer:

To find the common ratio of the given sequence, divide each term by the previous term. The common ratio is 0.75.

Explanation:

The given sequence is: 128, 96, 72, 54, ...

To find the common ratio, we need to determine the ratio between consecutive terms. We can do this by dividing each term by the previous term.

Ratio between the 2nd and 1st terms: 96/128 = 0.75

Ratio between the 3rd and 2nd terms: 72/96 = 0.75

Ratio between the 4th and 3rd terms: 54/72 = 0.75

Since the ratio is the same for all consecutive terms, we can conclude that the common ratio of this geometric sequence is 0.75.

Answer 2

The correct common ratio for the given sequence is [tex]\(\frac{3}{4}\) or 0.75.[/tex]

To find the common ratio of the sequence, we divide each term by the previous term and look for a consistent value:

1. For the second term, \(96\), divided by the first term, [tex]\(128\)[/tex], we get:

[tex]\[ \frac{96}{128} = \frac{3}{4} = 0.75 \][/tex]

2. For the third term, [tex]\(72\),[/tex] divided by the second term, [tex]\(96\),[/tex] we get:

[tex]\[ \frac{72}{96} = \frac{3}{4} = 0.75 \][/tex]

3. For the fourth term, [tex]\(54\),[/tex] divided by the third term, [tex]\(72\)[/tex], we get:

[tex]\[ \frac{54}{72} = \frac{3}{4} = 0.75 \][/tex]


Related Questions

A soccer ball has a radius of 6 inches, what is the approximate volume of the ball? Pi =3.14 *

Answers

4/3 * 3.14 * 6^3
4/3 * 3.14 * 216
4/3 * 678.24
904.32
Answer is 904.32

Gina sells 216 cakes in the ratio small :medium:large 5:7:12. The profit for one medium cake is twice the profit for one small cake. The profit for one large cake is three times the profit for one small cake. Her total profit id £648.45. Work out the profit for one small cake.

Answers

Answer:

£1.31

Step-by-step explanation:

5+7+12=24

216÷24=9

Small=9x5=45

Medium=9x7=63

Large=9x12=108

2x= Medium, Large= 3x, Small=x

Small=45x, Medium= 63x2=126x, Large=108x3=324x

45x+126x+324x=495x

£648.45=495x

£648.45÷495=x

£1.31=x

The profit for one small cake will be £ 1.31. The profit of the one small cake is the amount of benifit obtained to sell one cake.

What is profit?

When money generated from a commercial activity exceeds the expenses, costs, and taxes involved in maintaining the activity in question, profit is earned.

The ratio of the small :medium: large cake is 5:7:12.

Let the cake is considered to be x;

The sum of alll the cakes is;

5x+7x+12x=24 x

The total no of cake is 216

Each no of cake is found as;

[tex]\rm 24 x = 216 \\\\ x = 9[/tex]

The number of the small cake;

N(s) = 9 ×5 =45

N(m)=9×7=63

N(l)=9×12=108

Let the small cake is x

The profit for one medium cake is twice the profit for one small cake;

P(m)=2x

P(l)=3x

P(s)=x

The small medium and the large cake according to the new condition will be 45 x,126x,324x respectively.

The sum of all the cakes according to the new condition is found as;

[tex]4s x +126 x+324 c \\\\ 495 x=648.45 \\\\ x=\£ \ 1.31[/tex]

Hence the profit for one small cake will be £ 1.31.

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The vertex of a quadratic function is located at (1, 4), and the y-intercept of the function is (0, 1). What is the value of a if the function is written in the form y = a(x – h)2 + k?

a=____

Answers

Using the values of h and k from the vertex in equation of parabola, we get:

[tex]y=a(x-1)^{2} +4[/tex]

The y-intercept of the parabola is (0,1). Which means for x=0, y=1 for the given parabola. Using these values of x and y in above equation, we can find the value of a for the parabola.

[tex]1=a (0-1)^{2} +4 \\ \\ 1-4=a \\ \\ a=-3[/tex]

The equation of parabola thus becomes:

[tex]y=-3 (x-1)^{2} +4[/tex]


Answer:

-3

Step-by-step explanation:

right on edge

Solve the system of equations using the linear combination method.

{5p−3q=−39
{−2p−3q=3

Enter your answers in the boxes.

Answers

       5p - 3q = -39
-     (-2p - 3q = 3)
==> 7p = -42 ==> p = -6

==> p = -6
      -2(-6) - 3q = 3 ==> 12 - 3q = 3 

==>p = -6
     -3q = 3 - 12 ==> -3q = -9

==> p = -6
       q = 3
      

By solving the equations through linear combination method we are going to get the values of p and q are -6 and three.

What is linear combination method?

It is a bit like elimination method of solving equations within which one variable is eliminated so we'll get the worth of another variable.

How to solve an equation?

We are having two equations:

5p-3q=-39-------------1

-2p-3q=3---------------2

equation1 * 2 and equation 2 *5

10p-6q=-78

-10p-15q=15

Now add both equations

10p-6q-10p-15q=-78+15

-21q=-63

q=3

Put the worth of q in 1

5p-3(-3)=-39

5p+9=-39

5p=-30

p=-6

Hence the system of equations have the worth of p=-6 and q=3.

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A square banner has an area of (4x^2-12x+9) square inches. Write an expression for the perimeter of the banner.

Answers

The equation can be written as (2x-3)^2
Ans since it is square, then we can take the root of the equation to find on side of the square, which is (2x-3) and by multiplying it by4, we can find the perimeter.

Select the statements that are true for the graph of y=(x−1)^2(−6)




The vertex is (1, −6) .

The vertex is ​ (−1, −6) ​.

The graph has a minimum.

The graph has a maximum.

Answers

The first and third statement are true

Hope this helps<3

From the graph of given function, we have vertex (1, -6). Therefore, option A is the correct answer.

What is the function?

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The given function is y=(x-1)²-6.

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: (1, -6)

Focus: (1, -23/4)

Axis of symmetry: x=1

Directrix: y=-25/4

The coordinate points to plot are (-1, -2), (0, -5), (1, -6), (2, -5) and (3, -2).

Therefore, option A is the correct answer.

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Which diagram shows parallel lines cut by a transversal?

Answers

the third one shows parallel lines cut by a transversal

Answer:

The third diagram.

Step-by-step explanation:

When we have two parallel lines cut by a transversal, vertical angles are congruent; alternate interior angles are congruent; alternate exterior angles are congruent; corresponding angles are congruent; and same-side interior angles are supplementary.

In the first diagram, we have two angles on the same side of their respective parallel lines and the same side of the transversal.  These are by definition corresponding angles.  Since they are not congruent, these lines are not truly parallel.

In the second diagram, we have two angles on opposite sides of the transversal and outside the block of parallel lines.  These are by definition alternate exterior angles.  Since they are not congruent, these lines are not truly parallel.

In the third diagram, we have two angles inside the block of parallel lines and on the same side of the transversal.  These are by definition same-side interior angles.  Since they are congruent, these are parallel lines.

Find the supplement to the angle whose measure is 70 degrees. Show all your work

Answers

Supplementary angles add up to 180 degrees. Suppose the supplement of 70 degrees is x.
therefore the sum of our angles will be:
x+70=180
solving for x we get:
x=180-70
x=80°
hence the value of the supplement of 70° is 80°

HELP!!!!!!!!!Which geometric series converges?

Answers

The first series does not converge.  As the sequence continues, the numbers will continue to get larger and larger, going above 1 whole.  Adding numbers like this together does not approach a numeric limit, but instead approaches infinity.
The second series does converge.  As the sequence continues, the numerator will stay 1 and the denominator will continue to increase.  This means the overall fraction gets smaller and smaller, approaching 0.  Thus the sum will approach a finite number.
The third series does not converge.  As the exponents get larger and larger, the answers will swing to larger positives and larger negatives each time.  As the sum goes on, the absolute value of it will get larger and the sign will switch.
The fourth series does not converge.  As 2 gets raised to a higher and higher exponent, the product of it and 1/5 will be a larger and larger number.  It will approach infinity, not a finite number.

Answer:

its b

Step-by-step explanation:

For model 5, the tip of the blade travels 0.18 mile per revolution. What is the approximate speed, in revolutions per minute,for model 5?

Answers

need the answer tooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo


The approximate speed of model 5's 148-foot blade travels at 0.18 miles per revolution converted to feet is approximately 385.8 revolutions per hour.

To find the number of revolutions per minute for Model 5 with a blade length of 148 feet and a tip speed of 0.18 miles per revolution,

use the following calculation:

First, convert the tip speed from miles to feet:

0.18 miles × 5280 feet per mile = 950.4 feet per revolution

Now, divide this by the length of the blade in feet:

950.4 feet per revolution / 148 feet = 6.43 revolutions per minute

Finally, multiply this by 60 minutes per hour to get the number of revolutions per hour:

6.43 revolutions per minute × 60 minutes per hour = 385.8 revolutions per hour

Therefore, the required speed of model 5 has a blade that makes approximately 385.8 revolutions per hour.

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Write an equation of the line that passes through the points (-2,-2) and (0,5)

Answers

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ &&(~ -2 &,& -2~) &&(~ 0 &,& 5~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-2)}{0-(-2)}\implies \cfrac{5+2}{0+2}\implies \cfrac{7}{2} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=\cfrac{7}{2}[x-(-2)] \\\\\\ y+2=\cfrac{7}{2}(x+2)\implies y+2=\cfrac{7}{2}x+7\implies y=\cfrac{7}{2}x+5[/tex]

can you please help me with this I will crown you brainly

Answers

c. ΔKPT ≈ ΔKRT

It's identical on both sides. 

Mr Daniels is organizing a class field trip on a budget of $900.The bus rental costs $600. Mr.daniels will also buy tickets that will cost $9.50 per student. Write an inequality to represent the number students,y, that he can bring on the trip.

Answers

600 + 9.5x (less than or equal to) 900

600 fixed amount
9.5 is the variable changing amount and differs among number of students taken

Answer:

y ≤ 31 students

Step-by-step explanation:

The rental cost is a fixed cost that will be incurred irrespective of the number of students embarking on the class field trip. This cost added to the total ticket cost must be less than or equal to the budget.

the total ticket cost for y number of students

= 9.5y

Hence the total cost = 9.5y + 600 ( measured in $)

In inequality form,

9.5y + 600 ≤ 900 (all in $)

9.5y ≤ 900 - 600

9.5y ≤ 300

y ≤ 300/9.5

y ≤ 31 students

PLEASE HELP ASAP!!! 42 POINTS

Answers

[tex]k:\ y=m_1x+b\\\\l:\ y=m_2x+c\\\\l\ ||\ k\iff m_1=m_2\\\\k:\ y=\dfrac{2}{3}x-17\to m_1=\dfrac{2}{3}\\\\l:\ 4x-6y=-6\ \ \ |-4x\\\\-6y=-4x-6\ \ \ |:(-6)\\\\y=\dfrac{-4}{-6}x-\dfrac{6}{-6}\\\\y=\dfrac{2}{3}+1\to m_2=\dfrac{2}{3}\\\\m_1=m_2[/tex]

Answer:Yes, since the slopes are the same and the y-intercepts are different.

Jason is buying hamburgers and hot dogs for a barbecue. One package of hamburgers costs $10. One package of hotdogs costs $5. He has $60 to spend, and must buy AT LEAST 3 packages of hot dogs.
What 2 inequalities can be used?

Answers

let hotdogs be d and hamburgers be b

he needs AT LEAST 3 packages of hotdogs
so
[tex]d \geqslant 3[/tex]
each packet costs $5 so he must spend $15 in total on hotdogs
so he can spend NO MORE than $45 on hamburgers so can buy no more than 4 packs of hamburgers
so
[tex]b \leqslant 4[/tex]

Answer:

10x + 5y ≤ 60 & y ≥ 3

Step-by-step explanation:

Let x = the number of hamburgers

Let y = the number of hotdogs

Let us first represent the amount of food:

10x + 5y ≤ 60

This means x packages of $10 hamburgers plus y packages of $5 hotdogs is greater than or equal to $60.

However, we have also been given another important piece of information and that is that he must buy at least three packages of hotdogs.

y ≥ 3

this means that the packages of hotdogs must be no less than 3.

Hence or two inequalities are 10x + 5y ≤ 60 & y ≥ 3.

This also means that the least he can spend on hotdogs is $15. The most he can spend on hamburgers is $45, meaning the most packages of hamburgers he can get is 4

PLEASE MARK BRAINLIEST

Nancy randomly scattered one handful of seeds in her garden. The garden is circular and has a radius of 5 feet. Somewhere in the garden is a 2 feet by 2 feet square patch that has especially good soil for the seeds. If it is equally likely for a seed to land anywhere in the garden, what is the probability that a seed will land in the 2 feet by 2 feet square?

Answers

we know that
the garden is circular--------------> r=5 ft
Area1=pi*r²=pi*5²=78.50 ft²

 path 2 feet by 2 feet square (good soil for the seeds)
Area2=2*2=4 ft²

the probability that a seed will land in the 2 feet by 2 feet square=Area2/Area1
P=4/78.5=0.051 (5.1%)

the answer is 0.051 (5.1%)

The radius of the bulls-eye of the dartboard is 8 inches. The radius of each concentric circle (there are 4 labeled A, B, C, D from the inside out) is 14 inches more than the radius of the circle inside it. If a dart lands at random on the dartboard, the probability that the dart will hit in area C is what percent?

Answers

The formula for the area of a circle is A = πr².  The area for A, the innermost circle, is A=3.14(8²)=200.96 in². 
The area for B (including the area of A) is A=3.14(8+14)²=1519.76 in².
The area for C (including the areas of A and B) is A=3.14(8+14+14)²=4069.44.
The area for D (including the areas of A, B and C) is A=3.14(8+14+14+14)²=7850 in².
We now need to know how much the ring for circle C takes up.  We take the entire area for C and subtract the total area for B (since it includes A):
4069.44-1519.76=2549.68 in².
To find the percent, we divide this amount by the total area of the board, 7850:
2549.68/7850=0.3248
The probability of hitting circle C would be 32.48%.

help with these two please....

Answers

1) Find the real and complex solutions of x^3 - 216 = 0

Answer: fourth choice 6, - 3+3√3 i, and -3 - 3√3 i

Solution:

1) Factor x^3 - 216 as a difference of cubes:

(x)^3 - (6)^3 = (x - 6) (x^2 + 6x + 6^2) = (x - 6) (x^2 + 6x + 36) = 0

3) first factor = 0 => x - 6 = 0 => x = 6

4) second factor = 0 => x^2 + 6x + 36 = 0

Using the quadratic formula:

x = [ - 6 +/- √(6^2 - 4*1*36) ] / (2)

=> x = [ - 6 +/- √ (-108) ] / 2 = -3 +/- 3√3 i

=> x = - 3 + 3√3 and x = - 3 - 3√3 i

Answer: 3, - 3+3√3 i, and -3 - 3√3 i

2) Which is equivalent to (2p^2 + 5pq - q^2) + (p^2 + 3pq - 2q^2) ?

Answer: first option 3p^2 + 8pq - 3q^2

Solution:

1) eliminate parenthesis:

2p^2 + 5pq - q^2 + p^2 + 3pq - 2q^2

2) combine like terms:

2p^2 + p^2 = 3p^2

5pq + 3pq = 8pq

-q^2 - 2q^2 = - 3q^2

3) The result is 3p^2 + 8pq - 3q^2, which is the first option.



Suppose that a car rental agency charges a fixed amount per day plus an amount per mile for renting a car. heidi rented a car one day and paid $58 for 190 miles. on another day she rented a car from the same agency and paid $86 for 330 miles. find the linear function f(x) (where x is in miles and f(x) is in dollars) that the agency could use to determine its daily rental charges.

Answers

The linear function f (x) hat the agency could use to determine its daily rental charges will be;

⇒ f (x) = 0.2x + 20

Where, f (x) is in dollars and x is in miles.

What is linear expression?

A linear expression is an algebraic statement where each term is either a constant or a variable raised to the first power.

Given that;

Heidi rented a car for one day and paid $58 for 190 miles.

And, On another day she paid $86 for 330 miles.

Now,

We find the linear function for f (x), where f (x) is in dollars and x is in miles as;

Here the two situations are given for miles and dollars as;

(190, 58) and (330, 86)

Thus, The linear function with two points (190, 58) and (330, 86) is defined as;

⇒ y - y₁ = (y₂ - y₁)/(x₂ - x₁) (x - x₁)

⇒ y - 58 = (86 - 58) / (330 - 190) (x - 190)

⇒ y - 58 = 28 / 140 (x - 190)

⇒ y - 58 = 1/5 (x - 190)

⇒ y - 58 = 0.2 (x - 190)

⇒ y - 58 = 0.2x - 38

⇒ y = 0.2x - 38 + 58

⇒ y = 0.2x + 20

⇒ f (x) = 0.2x + 20

Thus, The linear function f (x) hat the agency could use to determine its daily rental charges will be;

⇒ f (x) = 0.2x + 20

Where, f (x) is in dollars and x is in miles.

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To determine the daily rental charges at a car rental agency based on fixed and per mile fees, the linear function f(x) is found to be $40 + $0.15 per mile.

Linear function f(x):

Define variables: Let d = daily rental charge, m = per mile charge.Form equations based on given data: $58 = d + 190m and $86 = d + 330m.Solve the system of equations to find f(x): d = $40 and m = $0.15. Therefore, f(x) = 40 + 0.15x.

There are 454 grams in a pound. There are 16 ounces in a pound. How many grams are in an ounce?

Answers

Answer: There are 28.375 grams in an ounce.


Step-by-step explanation:

Given: Total grams in a pound =454 grams

Total ounces in a pound = 16 ounces

Therefore, 16 ounces = 454 grams

To find grams in an ounce, we need to divide 454 grams by 16, we get

The total grams in an ounce=[tex]\frac{454}{16}=28.375\ grams[/tex]

∴The total grams in an ounce= 28.375 grams

Hence, there are 28.375 grams in an ounce.

28.375 grams in an ounce.

To calculate how many grams are in an ounce, divide 454 (grams in a pound) by 16 (ounces in a pound) to get 28.375 grams in an ounce.

To find out how many grams are in an ounce:

Given: 1 pound = 454 grams and 1 pound = 16 ounces.Since 1 pound = 454 grams and 1 pound = 16 ounces, divide 454 by 16 to find out how many grams are in an ounce.454 grams ÷ 16 = 28.375 grams in an ounce.

Write an expression to show the sum of fourteen and triple eight.

Answers

14 + 3 x 8 = 14 + 24 = 38

Which sets of the real number system does − 2 belong to?

Answers

it belongs to intergers
intergers......................

Really need help! Been trying to solve for a while.

1. Solve the system by using a table. 3y=4x+7 , -4x-4y=28. These are the possible solutions:(–4, –3),(–3, –4), (4, 3),(3, 4).

2.Solve by graphing. -3x-y=-10, 4x-4y=8. possible solutions:(-1,3), (3-1), (1,3), (3,1)

Answers

3y=4x+7 ; 4x - 3y = -7 .... equn 1 
-4x - 4y = 28
  =========
  -7y = 21 ; y = 21/-7 = -3 
 Substituting value of y in equn 1
 4x - 3(-3) = -7
 4x +9 = -7
 4x = -7 -9
 4x = -16
 x = -4 
 Solution : (-4, -3) 
 ------------------------------------- 
 -3x - y = -10 .... equn 1
 4x - 4y = 8 .... equn 2
 =========
 x - 5y = -2 ; x = 5y - 2 
 Substituting value of x in equn 1
 -3(5y - 2) -y = -10
 -15y + 6 -y = -10
 -16y = -10 - 6
 -16y = -16
 y = 1 
 Substituting value of y in equn 1
 -3x - 1 = -10
 -3x = -9
 x = 3 
 Solution : (3,1)

Charlie used these steps to solve the equation 6x+5=1+2(3x+2)6x+5=1+23x+2. Which choice describes the meaning of his result, 5=5

Answers

we have that
[6x+5]=1+2*(3x+2)
[6x+5]=1+2*3x+2 --------> is not correct ------->1+ 2*(3x+2)=1+2*3x+2*2 

then 
[6x+5]=1+6x+4---------------> [6x+5]=[6x+5] 

this equation is an identity, all real numbers are solutions.

Answer:

All values of x make the equation true. It is an infinite solution.

A Rectangle launch tray has a length of X centimeters and a width of 15 cm the trays length is at least 20% greater than it's width. right an inequality to represent this situation. suppose X is a whole number find the least possible permitted and the least possible area of the lunch tray

Answers

we know that
x-------------> length rectangle launch tray 
w------------< width rectangle launch tray------> 15 cm

length is at least 20% greater than it's width
x>=1.2w---------> x>=1.2*15

the answer part a) is
x>=18  ---------------> ( inequality to represent this situation)

part b) suppose X is a whole number find the least possible permitted and the least possible area of the lunch tray

the least possible permitted length is 18 cm 
the least possible area of the lunch tray is 18*15=270 cm²

A sphere has a radius of 26 inches. a horizontal plane passes through the center of the sphere describe the cross section formed by the plane and the sphere.

Answers

When a horizontal plane passes through the center of a sphere with a radius of 26 inches, the cross-section formed is a circle with a radius of 26 inches.

let's break down the problem into two parts:

Describe the cross-section: We'll describe the shape formed when a horizontal plane passes through the center of the sphere.

Calculate the dimensions of the cross-section: We'll calculate the dimensions of the cross-section, such as its radius or diameter.

1. Describe the cross-section:

When a horizontal plane passes through the center of a sphere, it divides the sphere into two equal halves. The cross-section formed by this plane and the sphere will be a circle. Since the plane passes through the center of the sphere, the circle will be perfectly centered.

2. Calculate the dimensions of the cross-section:

Since the radius of the sphere is given as 26 inches, the radius of the cross-section (which is also the radius of the circle formed) will also be 26 inches.

So, the cross-section formed by the plane and the sphere is a circle with a radius of 26 inches.

Look at the rational expression below. x^2-4/2-x Which value of x makes the expression undefined?

Answers

the answer would 2, since you cannot divide anything by 0 as it would be undefined. 2 is the only number that gives you this option 

Answer:

given rational function is undefined for x = 2

Step-by-step explanation:

The given rational function is

[tex]\frac{x^2-4}{2-x}[/tex]

The rational function is undefined if the denominator is zero.

Hence, the given rational function is undefined if

[tex]2-x=0[/tex]

Solve the equation for x

[tex]x=2[/tex]

Therefore, the given rational function is undefined for x = 2

The sum of two consecutive integers is 37. Write an equation that models this situation and find the values of the two integers.

Answers

n + (n+1) = 37

n+n + 1 = 37
2n + 1 = 37
2n = 36
n = 18
n+1 = 19

18 and 19

Hope this helps ^_^

Your school raise 125% of its fundraising goal. The goal raised $6,750. What was the goal?

Answers

I take it you mean the original goal.
100/x = 125 / 6750
100% is to x and 125 is 6750
100/x = 125/6750 Cross multiply.
100 * 6750 = 125x Divide by 125
100 * 6750 / 125 = x
x = 5400 was the initial goal.


Larry wants to inscribe an equilateral triangle in a circle using only a compass and straightedge. He will first construct a circle and locate its center. He will then perform the following steps.

Step 1: Set the width of the compass to the diameter of the circle.
Step 2: Plot a point on the circle. Place the compass on this point and draw two arcs to cut the circle. These two points of intersection between the arcs and the circle represent two of the vertices.
Step 3: Draw a segment between the two vertices. Adjust the width of the compass to the length of the segment. Place the compass on one vertex and draw an arc to construct the third vertex.
Step 4: Draw a line from one vertex to the next to form an equilateral triangle.

What is the error in Larry's construction?

A. He did not draw a pair of perpendicular bisectors to construct two diameters of the circle.
B. He drew only two arcs.
C. He set the width of the compass to the diameter of the circle.
D. He did not ensure that the length of the sides of the triangle was the same as the diameter of the triangle.

Answers

Answer: The error in Larry's construction is Option C.

He set the width of the compass to the diameter of the circle. The step 1 should be: Set the width of the compass to the radius of the circle.
Answer:

The error in Larry's construction is:

C.  He set the width of the compass to the diameter of the circle.

Step-by-step explanation:

The steps for the construction of an inscribed equilateral triangle is as follows:

Step 1:  Draw a circle on a piece of paper.Take a point anywhere on the circumference of the circle and take that point as a starting point.Step 2: Now without changing the span of the circle we have draw two arcs to cut the circle.These two points of intersection between the arcs and the circle represent two of the vertices. Step 3:  Draw a segment between the two vertices. Adjust the width of the compass to the length of the segment. Place the compass on one vertex and draw an arc to construct the third vertex. Step 4:  Draw a line from one vertex to the next to form an equilateral triangle.

Hence, the error he that he set the width of compass  equal to the diameter of circle.

Instead he should have set the width of the compass equal to the radius of the circle.

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