13x + 3y = 15 and y = 5 - 4x.
A. x = 0, y = 5
B. x = 5, y = 0
C. x = 9, y = -31

Pleaseee explain with words and number pleasee thank you so much

The equation that represents the line passing through the points (-1, 2) and (3, 1) is  [tex]\[ x + 4y = 7 \][/tex]

The correct option is (B).

To find the equation of the line that passes through the points (-1, 2) and (3, 1), we need to determine the slope of the line and use the point-slope form of the equation of a line, which is [tex]\( y - y_1 = m(x - x_1) \)[/tex], where [tex]\( m \)[/tex] is the slope and [tex]\( (x_1, y_1) \)[/tex] is a point on the line.

First, let's calculate the slope [tex]\( m \)[/tex] using the two given points [tex]\( (x_1, y_1)[/tex]= [tex](-1, 2) \) and \( (x_2, y_2) = (3, 1) \)[/tex]:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Let's compute the slope.

The slope \( m \) of the line that passes through the points (-1, 2) and (3, 1) is [tex]\( -0.25 \)[/tex].

Next, we'll use one of the points and the slope to write the equation of the line in point-slope form and then convert it to slope-intercept form[tex]\( y = mx + b \)[/tex]. Let's use the point (-1, 2) to find the equation of the line.

The equation of the line in slope-intercept form is [tex]\( y = -0.25x + 1.75 \)[/tex].

Now let's convert this to the standard form of the line equation, [tex]\( Ax + By = C \),[/tex] and compare it with the given options.

To get the standard form, we will multiply through by 4 to eliminate the decimals and then rearrange the terms:

[tex]\[ y = -0.25x + 1.75 \][/tex]

[tex]\[ 4y = -x + 7 \][/tex]

[tex]\[ x - 4y = -7 \][/tex]

This standard form equation needs to be matched with one of the given options by comparing coefficients. Let's do this by checking which of the given options has the same ratio of coefficients for[tex]\( x \) and \( y \)[/tex] as the equation we found.

The equation that represents the line passing through the points (-1, 2) and (3, 1) is given by option B, which is:

[tex]\[ x + 4y = 7 \][/tex]

Choose the equation that represents a line that passes through points (-1,2) and (3,1)

A. 4x-y=6

B.x+4y=7

C. x-4y =-9

D.4x+y=2​

Answer:

111

Step-by-step explanation:

a1 = -12

a27 = 66

Now using the formula  an = a1+(n-1)d we will find the value of d

here n = 27

a1 = -12

a27 = 66

Now substitute the values in the formula:

a27 = -12+(27-1)d

66= -12+(26)d

66 = -12+26 * d

66+12 = 26d

78 = 26d

now divide both the sides by 26

78/26= 26d/26

3 = d

Now put all the values in the formula to find the 42 term

an = a1+(n-1)d

a42 = -12 +(42-1)*3

a42 = -12+41 *3

a42 = -12+123

a42 = 111

Therefore 42 term is 111....

Answer:

Assuming it is arithmetic, the 42nd term is 111.

Assuming it is geometric, the conclusion says it isn't geometric.

Step-by-step explanation:

Let's assume arithmetic first.

Arithmetic sequences are linear. They go up or down by the same number over and over.  This is called the common difference.

We are giving two points on our line (1,-12) and (27,66).

Let's find the point-slope form of this line.

To do this I will need the slope.  The slope is the change of y over the change of x.

So I'm going to line up the points and subtract vertically, then put 2nd difference over 1st difference.

(1  , -12)

-(27,66)

------------

-26   -78

The slope is -78/-26=78/26=3.  The slope is also the common difference.

I'm going to use point [tex](x_1,y_1)=(1,-12)[/tex] and [tex]m=3[/tex] in the point-slope form of a line:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-(-12)=3(x-1)[/tex]

Distribute:

[tex]y+12=3x-3[/tex]

Subtract 12 on both sides:

[tex]y=3x-3-12[/tex]

[tex]y=3x-15[/tex]

So we want to know what y is when x=42.

[tex]y=3(42)-15[/tex]

[tex]y=126-15[/tex]

[tex]y=111[/tex]

So [tex]a_{42}=111[/tex] since the explicit form for this arithmetic sequence is

[tex]a_n=3n-15[/tex]

-----------------------------------------------------------------------------------------

Let's assume not the sequence is geometric. That means you can keep multiplying by the same number over and over to generate the terms given a term to start with.  That is called the common ratio.

The explicit form of a geometric sequence is [tex]a_n=a_1 \cdot r^{n-1}[/tex].

We are given [tex]a_1=-12[/tex]

so this means we have

[tex]a_n=-12 \cdot r^{n-1}[/tex].

We just need to find r, the common ratio.

If we divide 27th term by 1st term we get:

[tex]\frac{a_{27}}{a_1}=\frac{-12r^{27-1}}{-12r^{1-1}}=\frac{-12r^{26}}{-12}=r^{26}[/tex]

We are also given this ration should be equal to 66/-12.

So we have

[tex]r^{26}=\frac{66}{-12}[/tex].

[tex]r^{26}=-5.5[/tex]

So the given sequence is not geometric because we have an even powered r equaling a negative number.

Answer: 2:45

Step-by-step explanation:

1 hour and 15 minutes plus 30 minutes equal an hour and 45 minutes. We subtract 1 hour and 45 minutes from 4:30 and get 2:45.

So she started shopping at 2:45.

Answer:

Step-by-step explanation:

Yes it’s parallel because the lines do not meet

Using the rule that any non-zero number raised to the power of zero equals one, the equation 3 • 4^0 / a^0 simplifies to 3.

The problem seems to be a little bit confusing, so let's format it more clearly. I believe that you're looking to simplify: 3 • 4^0 / a^0.

There's a rule in mathematics stating that any number raised to the zeroth power equals one. In other words, if x is a non-zero number, then x^0 = 1. In this case, 4^0 = 1 and a^0 = 1.

Apply that rule to your problem and it becomes 3 • 1 / 1, or simply 3.

So, according to the rules of exponents, the simplified form of 3 • 4^0 / a^0 is 3.

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Answer:

[tex]\large\boxed{x^\frac{4}{5}}[/tex]

Step-by-step explanation:

[tex]\sqrt[n]{a}=a^\frac{1}{n}\Rightarrow\sqrt[5]{x}=x^\frac{1}{5}\\\\\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}=x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}=x^\frac{4}{5}[/tex]

Answer:

[tex]x^{\frac{4}{5}}[/tex]

Step-by-step explanation:

fifth root of x can be written in exponential for as:

[tex]x^\frac{1}{5}[/tex]

[tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex]

WE apply exponential property to multiply it

a^m times a^n= a^{m+n}

[tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex] times  [tex]x^\frac{1}{5}[/tex]

[tex]x^{\frac{1}{5} +\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}[/tex]

The denominator of the fractions are same so we add the numerators

[tex]x^{\frac{4}{5}}[/tex]

Answer: Choice A

Step-by-step explanation:

-

Answer:

A

Step-by-step explanation:

Given :

2x + 4y = 14  ---------- eq 1

4x + y = 20 ---------- eq 2

if you multiply eq 2 by -4 on both sides, you get

-4 (4x + y = 20) = -4 (20)

-16x -4y = -80 --------- eq3

we can see that eq. 1 and eq 2 together forms the system of equations presented in option A, Hence A is equvalent to the orginal system of equations given in the question.

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}2x+4y=14&(1)\\4x+y=20&(2)\end{array}\right\\\\\left\{\begin{array}{ccc}2x+4y=14&(1)\\4x+y=20&\text{multiply both sides by (-4)}\end{array}\right\\\left\{\begin{array}{ccc}2x+4y=14&(1)\\-16x-4y=-80&(2)\end{array}\right\to \boxed{A.}[/tex]

B.

[tex]\left\{\begin{array}{ccc}2x+4y=14&(1)\\4x+y=20&\text{change the signs}\end{array}\right\\\\\left\{\begin{array}{ccc}2x+4y=14&(1)\\-4x-y=-20&\text{it's different to (2)}\end{array}\right[/tex]

C.

[tex]\left\{\begin{array}{ccc}2x+4y=14&\text{multiply both sides by 2}\\4x+y=20&(2)\end{array}\right\\\left\{\begin{array}{ccc}4x+8y=28&\text{different to (1)}\\4x+y=20&(2)\end{array}\right[/tex]

D.

[tex]\left\{\begin{array}{ccc}2x+4y=14&\text{change the signs}\\4x+y=20&(2)\end{array}\right\\\left\{\begin{array}{ccc}-2x-4y=-14&\text{different to (1)}\\4x+y=20&(2)\end{array}\right\\\\A.[/tex]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (2, - 4), thus

y = a(x - 2)² - 4

To find a substitute (- 3, - 3) into the equation

- 3 = a(- 3 - 2)² - 4

- 3 = 25a - 4 ( add 4 to both sides )

1 = 25a ( divide both sides by 25 ), hence

a = [tex]\frac{1}{25}[/tex]

y = [tex]\frac{1}{25}[/tex] (x - 2)² - 4 ← in vertex form

  = [tex]\frac{1}{25}[/tex] (x² - 4x + 4) - 4 ← in expanded form

Hence the coefficient of the x² term is [tex]\frac{1}{25}[/tex]

Answer:-5

Step-by-step explanation:

Answer:

C. y=x^2-6x+8

Step-by-step explanation:

We have to check each functions in options with the given point

So,

The point is (3,-1)

For A:

[tex]y = x^2+6x+8\\Putting\ the\ point\\-1 = (3)^2+6(3)+8\\ -1=9+18+8\\-1 \neq 35[/tex]

For B:

[tex]y=x^2-2x-8\\-1 = (3)^2-2(3)-8\\-1=9-6-8\\-1\neq -5[/tex]

For C:

[tex]y = x^2 - 6x+8\\-1 =(3)^2-6(3)+8\\-1= 9-18+8\\-1=-1[/tex]

The given point satisfies the third function. Therefore, Option C is the correct answer ..

Answer:

(D) 6 & 7

Step-by-step explanation:

You are plugging in numbers into the question marks to make the equation true. In this case, plug in the numbers, 6 & 7 or (D)

Plug in 6 in the first ? mark and 7 in the second:

?1 - 2? = 34 = (61) - (27) = 34

61 - 27 = 34

34 = 34 (True) ∴ 6 & 7 is your answer.

~

Answer:

The points C(1,2) and E(2,2) make both inequalities true

Step-by-step explanation:

we have

[tex]y < 5x+2[/tex] -----> inequality A

The solution of the inequality A is the shaded area below the dashed line

[tex]y\geq \frac{1}{2}x+1[/tex] ------> inequality B

The solution of the inequality B is the shaded area above the solid line

The solution of the system of inequalities is the shaded area between the dashed line and the solid line

see the attached figure

Remember that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities and the point lie on the shaded area of the solution

Plot the points and verify if lie on the shaded area

Let

[tex]A(-1,3),B(0,2),C(1,2),D(2,-1),E(2,2)[/tex]

see the attached figure

The points C(1,2) and E(2,2) lie on the shaded area

Note

The points A(-1,3) and B(0,2) satisfy inequality B but don't satisfy inequality A

The point D(2,-1) satisfy inequality A but don't satisfy inequality B

therefore

The points C(1,2) and E(2,2) make both inequalities true

Answer:

c and e

Step-by-step explanation:

Answer:

-4x-1

Step-by-step explanation:

-1(2x + 3) -2 (x - 1)

Distribute the -1 and the -2

-2x - 3 -2 x  +2

Combine like terms

-4x-1

[tex]\huge \boxed{-4x-1}[/tex], you can use the distributive property of [tex]\displaystyle a(b+c)=ab+ac[/tex].  

Multiply from left to right.

[tex]\displaystyle 1\times(2x+3)=2x+3[/tex]

[tex]\displaystyle -(2x+3)-2(x-1)[/tex]

[tex]\displaystyle -(2x+3)=-2x-3[/tex]

[tex]-2(x-1)=-2x+2=-2x-3-2x+2[/tex]

[tex]\Large\textnormal{Solve to find the answer.}[/tex]

[tex]\displaystyle-2x-3-2x+2=-4x-1[/tex]

[tex]\large \boxed{-4x-1}[/tex], which is our answer.

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, -4) and (x₂, y₂ ) = (3, - 1)

d = [tex]\sqrt{(3-0)^2+(-1+4)^2}[/tex]

  = [tex]\sqrt{3^2+ 3^2}[/tex]

  = [tex]\sqrt{9+9}[/tex]

  = [tex]\sqrt{18}[/tex] = 3[tex]\sqrt{2}[/tex] ≈ 4.24 ( to 2 dec. places )

Answer:

Area =  16 units²

Step-by-step explanation:

Points to remember

Distance formula

The distance between two points (x1, y1) and (x2, y2) is given by

Distance = √[(x2 - x1)² + (y2 - y1)²]

To find the length and breadth of rectangle

Let the points be  (1, 7) , (5, 3)

Distance = √[(x2 - x1)² + (y2 - y1)²]

 = √[(5 - 1)² + (3 - 7)²]

 =  √[(4)² + (-4)²]

 = √32 = 4√2

If the points be  (5, 3) , (3, 1)

Distance = √[(x2 - x1)² + (y2 - y1)²]

 = √[(3 - 5)² + (1 - 3)²]

 =  √[(-2)² + (-2)²]

 = √8 = 2√2

Length = 4√2 and breadth = 2√2

To find the area of rectangle

Area = Length * Breadth

 = 4√2 * 2√2

 = 16 units²

Answer:

16 units

Step-by-step explanation:

i have answered ur question

ANSWER

The exact solution are:

[tex]y = \frac{ - 6 - 2 \sqrt{6} }{5} \: \: or \: \: y = \frac{ - 6 + 2 \sqrt{6} }{5} [/tex]

EXPLANATION

The given quadratic equation is

[tex] {(5y + 6)}^{2} = 24[/tex]

We use the square root method to solve for y.

We take square root of both sides to get:

[tex] \sqrt{{(5y + 6)}^{2}} = \pm\sqrt{24} [/tex]

This gives us:

[tex]5y + 6 = \pm 2 \sqrt{6} [/tex]

Add -6 to both sides to get:

[tex]5y = - 6 \pm 2 \sqrt{6} [/tex]

Divide through by 5:

[tex]y = \frac{ - 6 \pm2 \sqrt{6} }{5} [/tex]

[tex]y = \frac{ - 6 - 2 \sqrt{6} }{5} \: \: or \: \: y = \frac{ - 6 + 2 \sqrt{6} }{5} [/tex]

Answer:

8 x^6 + x + 14

Step-by-step explanation:

Simplify the following:

7 x^6 + x^6 + x + 5 + 9

Grouping like terms, 7 x^6 + x^6 + x + 5 + 9 = (x^6 + 7 x^6) + x + (9 + 5):

(x^6 + 7 x^6) + x + (9 + 5)

x^6 + 7 x^6 = 8 x^6:

8 x^6 + x + (9 + 5)

9 + 5 = 14:

Answer: 8 x^6 + x + 14

For this case we must find the sum of the following polynomials:

[tex]x ^ 6 + x + 9\ and\ 7x ^ 6 + 5[/tex]

We have:

[tex](x ^ 6 + x + 9) + (7x ^ 6 + 5) =[/tex]

We eliminate parentheses:

[tex]x ^ 6 + x + 9 + 7x ^ 6 + 5 =[/tex]

We add similar terms:

[tex]x ^ 6 + 7x ^ 6 + x + 9 + 5 =\\8x ^ 6 + x + 14[/tex]

Finally we have that the sum of the polynomials is:[tex]8x ^ 6 + x + 14[/tex]

Answer:

[tex]8x ^ 6 + x + 14[/tex]

Answer:

$8,000 to the nearest hundred.

Step-by-step explanation:

A depreciation of 15% means that after each year the car is worth 0.85 of it's value the previous year.

So after 7 years the values of the car is 25,000(0.85)^7

= 8,014

The value of a car that depreciates at a rate of 15% per year after 7 years is $10,400, after rounding to the nearest hundred.

The question is asking for the value of the car after 7 years when it depreciates at a rate of 15% per year. To find the car's value after each year, we can multiply the current value at the end of each year by 85% (which is 100% - 15%), because the car is losing 15% of its value. The formula to calculate the depreciation is P(1 - r)^t, where P is the initial principal (the initial value of the car), r is the depreciation rate, and t is the time in years.

Using this formula, the car's value after 7 years would be: $25,000 x (1 - 0.15)^7. Calculating this gives a value of $25,000 x 0.417709 = $10,442.73.

After rounding to the nearest hundred, the value is approximately $10,400.

Answer:

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

Step-by-step explanation:

Ok to decide if a point is on a line you plug it in.  If you get the same thing on both sides, then that point is on that line.  If you don't get the same thing on both sides, then that point is not on that line.

Test (6,6) for -5x+6y=-23.

(x,y)=(6,6) gives us

-5x+6y=-23

-5(6)+6(6)=-23

-30+36=-23

6=-23

So (6,6) is not on -5x+6y=-23.

Test (6,6) for y=-4x+30

(x,y)=(6,6) give us

y=-4x+30

6=-4(6)+30

6=-24+30

6=6

So (6,6) is on y=-4x+30.

Test (3,4) for -5x+6y=-23.

(x,y)=(3,4) gives us

-5x+6y=-23

-5(3)+6(4)=-23

-15+24=-23

9=-23

So (3,4) is not on -5x+6y=-23.

Test (3,4) for y=-4x+30.

(x,y)=(3,4) gives us

y=-4x+30

4=-4(3)+30

4=-12+30

4=18

So (3,4) is not on y=-4x+30.

Test (7,2) for -5x+6y=-23.

(x,y)=(7,2) gives us

-5x+6y=-23

-5(7)+6(2)=-23

-35+12=-23

-23=-23

So (7,2) is on -5x+6u=-23.

Test (7,2) for y=-4x+30.

(x,y)=(7,2) gives us

y=-4x+30

2=-4(7)+30

2=-28+30

2=2

So (7,2) is on y=-4x+30

(x,y)  Line 1    Line 2     Both     Neither

(6,6)                  *

(3,4)                                                   *

(7,2)                                  *

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

Answer:

Step-by-step explanation:

[tex]a_n-\text{geometric sequence}\\\\a_1,\ a_2,\ a_3,\ ...,\ a_n-\text{terms of a geometric sequence}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=\hdots=\dfrac{a_n}{a_{n-1}}-\text{common ratio}\\\\\text{We have:}\ a_1=2,\ a_2=4,\ a_3=8,\ a_4=16,\ ...\\\\\text{The common ratio:}\\\\r=\dfrac{4}{2}=\dfrac{8}{4}=\dfrac{16}{8}=2[/tex]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

[tex]f\left(x\right)=\left|x+3\right|-5[/tex]

Obtain the function g(x)

[tex]g(x)=-\frac{1}{5} f(x)[/tex]

substitute

[tex]g(x)=-\frac{1}{5} [\left|x+3\right|-5][/tex]

[tex]g(x)=-\frac{1}{5}\left|x+3\right|+1[/tex]

using a graphing tool

The graph in the attached figure

The vertex is the point (-3,1)

The x-intercepts are the points (-8,0) and (2,0)

The y-intercept is the point (0,0.4)

Answer:

n

Step-by-step explanation:

Answer:

1.25 mi

Step-by-step explanation:

Think of this in terms of a graph in the x-y axis

Bill starts out at point (0,0)

He walks 1/2 mile south (i.e 0.5 miles in the -y direction) and ends up at (0,-0.5)

Next he walks 3/4 mile (0.75 miles) in the +x direction and ends up at (0.75, -0.5)

Then he continues to walk 1/2 mile (0.5 miles) in south in the -y direction and ends up at (0.75, -1).

His final distance from the starting point (0,0) from his end point (0.75,-1) is simply the distance between the 2 coordinates (see picture for formula).

hence,

D = √ (0.75 -0)² + (-1 - 0)²

D = √ (0.75)² + (-1)²

D = 1.25

Answer:

1.25 M

Step-by-step explanation:

Answer:

82%

Because O.34 + O. 48 = .82 and .82 • 1OO=82

So 82% Can swim

i got it right on Aoex

The percentage of people cannot swim is 18%.

Relative frequency can be defined as the number of times an event occurs divided by the total number of events occurring in a given scenario.

Given that, in a survey, 250 adults and children were asked whether they know how to swim.

From table cannot swim = 0.06+0.12

= 0.18

In percentage = 0.18×100

= 18%

Therefore, the percentage of people cannot swim is 18%.

To learn more about the relative frequency visit:

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Answer:

B.

Step-by-step explanation:

So [tex]2x^2+5x+3[/tex] will have two factors if one factor in the form [tex](ax+b)[/tex] is given.

The other factor will also be in the form of [tex](cx+d)[/tex].

So we have

[tex](x+1)(cx+d)[/tex]:

Let's use foil.

First:  x(cx)=cx^2

Outer: x(d)=dx

Inner: 1(cx)=cx

Last: 1(d)=d

---------------------Adding like terms:

cx^2+(d+c)x+d

We are comparing this to:

2x^2+     5x+3

So we see that c=2 and d=3 where the other factor is cx+d=2x+3.

Also this works since c+d=5 (we know this because 2+3=5).

Answer:

B

Step-by-step explanation:

The radius of the circle is 11, so the area is

[tex]A=\pi r^2 = 121\pi[/tex]

The central angles of the shaded and non-shaded regions sum up to 360 degrees, so the central angle of the shaded region is

[tex]360-217=143[/tex]

The area of the shaded region is in proportion with the area of the whole circle: if the whole area is given by a sector of 360°, the area of a 143° sector will be given by

[tex]A_{360}\div A_{143} = 360\div 143[/tex]

Since we know that the whole area is [tex]121\pi[/tex], we can solve for the area of the 143° sector:

[tex]121\pi\div A_{143} = 360\div 143 \iff A_{143}=\dfrac{121\pi\cdot 143}{360} \approx 151[/tex]

Answer:

121

143

151

Step-by-step explanation:

[tex]\huge{\boxed{\text{2000 pounds}}}[/tex]

One ton is equal to [tex]\boxed{\text{2000 pounds}}[/tex].

For example, two tons is equal to [tex]4000[/tex] pounds, because [tex]2000*2=4000[/tex].

Answer is provided in the image attached.

Answer:

18

Step-by-step explanation:

A rectangular prism has four parallel edges along its length, four parallel edges along its width, and four parallel edges along its height.

We want to know how many different pairs of parallel edges there are.  Starting with the length, the number of unique pairs is:

₄C₂ = 6

The same is true for the width and height.  So the total number of different pairs of parallel edges is:

3 × 6 = 18

Answer:

C. [tex] \frac{3}{2} [/tex]

Step-by-step explanation:

To find the value f b, we need to compare the exponents.

The given exponential equation is:

[tex]( {x}^{2} {y}^{3} )^{3} = ( {x} {y}^{a} )^{b}[/tex]

Recall and apply the following rule of exponents.

[tex] ( {x}^{m} )^{n} = {x}^{mn}[/tex]

We apply this rule on both sides to get:

[tex]{x}^{2 \times 3} {y}^{3 \times 3} = {x}^{b} {y}^{ab}[/tex]

Simplify the exponents on the left.

[tex]{x}^{6} {y}^{9} = {x}^{b} {y}^{ab}[/tex]

Comparing exponents of the same variables on both sides,

[tex]b = 6 \: and \:\: ab = 9[/tex]

[tex] \implies \: 6b = 9[/tex]

Divide both sides by 6.

[tex]b = \frac{9}{6} [/tex]

[tex]b = \frac{3}{2} [/tex]

Answer:

A 18%

Step-by-step explanation:

I believe it should be A because there is no specific type a marble specified therefore if you do

12/33--> 0.36 times 100= 36 % which isn't an option

15/33->0.45 times 100= 45 % which also isn't an option

6/33= 0.18 times 100= 18% this is the only option given

Answer:

B. 82%

Step-by-step explanation:

From the question; A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear).

To find p(not clear), we use this formula;

P(not clear) = 1 -  p(clear)

To proceed we first have to find p(clear) and the minus it from 1

But,

probability =  Required outcome/ all possible outcome

In the question, since what we are looking for now is probability of clear, so our 'required outcome' is the number of marble which is 6,

all possible outcome is the number of all the marbles; 15 + 12 + 6 = 33

We can now proceed to find the probability of clear marble, hence;

probability =  Required outcome/ all possible outcome

p(clear marble) = 6/33

Now, we go ahead to find the probability of 'not clear marble'

P(not clear) = 1 -  p(clear)

                   =   1 - 6/33

                    = 1 -   0.181818

                     =0.818182

P(not clear) = 0.818182

But the question says we should round our answer to the nearest percent, so we will multiply our answer by 100%

p(not clear)  = 0.818182 ×  100%

p(not clear) = 82% to the  nearest percent

Answer:

3x² - 2x + 5 ; will be a polynomial ⇒ answer A

Step-by-step explanation:

* Lets explain what is the polynomial

- A polynomial is an expression containing two or more algebraic terms.

- Polynomial is often the sum of some terms containing different powers

 of variables.  

- If you add or subtract polynomials, you get another polynomial.

- If you multiply polynomials, you get another polynomial.

* Lets solve the problem

∵ 5x² + 3x + 4 is polynomial

∵ 2x² + 5x - 1 is polynomial

- When we subtract them the answer will be polynomial

∵ (5x² + 3x + 4) - (2x² + 5x - 1)

- Open the second bracket by multiplying the negative sign by

  each term in the bracket

∵ -(2x²) = -2x²

∵ -(5x) = -5x

∵ -(-1) = 1

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 5x² + 3x + 4 - 2x² - 5x + 1

- Add the like terms

∴ (5x² - 2x²) = 3x²

∴ (3x - 5x) = -2x

∵ (4 + 1) = 5

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 3x² - 2x + 5

∴ 3x² - 2x + 5 is a polynomial

∴ (5x² + 3x + 4) - (2x² + 5x - 1) = 3x² - 2x + 5 ; will be a polynomial

* The answer is A

Answer:

A. 3[tex]x^{2}[/tex] − 2x + 5; will be a polynomial

Step-by-step explanation:

Give The Dood Above Brainliest