The force exerted on her is 1700 N
Explanation:
First of all, we start by calculating the acceleration of the car. Since its motion is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2 = 2as[/tex]
where
v = 0 is the final velocity of the car (which comes to a stop)
u = 14.0 m/s is the initial velocity
a is the acceleration
s = 3.0 m is the distance covered by the car during the collision
Solving for a,
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-14^2}{2(3)}=-32.7 m/s^2[/tex]
And the negative sign means it is a deceleration.
Now we can find the force exerted on the passenger during the collision, using Newton's second law:
[tex]F=ma[/tex]
where
F is the force
m = 52.0 kg is the mass of the passenger
[tex]a=32.7 m/s^2[/tex] is the acceleration (we ignore the sign since we are only interested in the magnitude of the force)
Substituting,
[tex]F=(52.0)(32.7)=1700 N[/tex]
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Determine the acceleration of a raptor that reaches 25 m/s from rest in 6.5 s.
Answer:
3.8 m/s²
Explanation:
Average acceleration is the change in velocity over change in time.
a = Δv / Δt
a = (25 m/s − 0 m/s) / 6.5 s
a ≈ 3.8 m/s²
Final answer:
The raptor's acceleration is found using the formula a = Δv / t. By substituting the final velocity (25 m/s), initial velocity (0 m/s), and time (6.5 s), we determine the acceleration to be approximately 3.85 m/s².
Explanation:
The question asks us to determine the acceleration of a raptor that changes its velocity from rest to 25 m/s in 6.5 seconds.
To find the acceleration, we can use the formula:
a = Δv / t
Where:
a is the acceleration,Δv is the change in velocity, andt is the time.Since the raptor starts from rest, its initial velocity is 0 m/s, and its final velocity is given as 25 m/s. The time taken is 6.5 seconds. Substituting the values into the formula gives:
a = (25 m/s - 0 m/s) / 6.5 s = 25 m/s / 6.5 s = approximately 3.85 m/s²
Therefore, the raptor's acceleration is approximately 3.85 m/s².
A 110-kg tackler moving at a speed of 3.5 m/s
meets head-on (and holds on to an 85-kg halfback
moving at a speed of 5.0 m/s.
Part A
What will be their mutual speed immediately after the collision?
Express your answer to two significant figures and include the appropriate units.
Units
Objects 1 and 2 attract each other with a gravitational force of 36.0 units. If the mass of Object 2 is tripled, then the new gravitational force will be _____ units.
Answer:
108N
Explanation:
According to law of gravitation which states that "the force
of attraction between two masses in a gravitational field is directly proportional to the product of their masses and inversely proportional to the square of their distance between them.
Mathematically, F = Gm1m2/r²
Where;
m1 and m2 are the masses of the object
G is the gravitational constant
r is the distance between the masses
If Objects 1 and 2 attract each other with a gravitational force of 36.0 units, we will have;
36 = Gm1m2/r²... (1)
If the mass of Object 2 is tripled, the gravitational force becomes
F = Gm1(3m2)/r²
F = 3Gm1m2/r²... (2)
Dividing equation 1 by 2, we will have;
36/F = {Gm1m2/r²}/3Gm1m2/r²
36/F = Gm1m2/r²×r²/3Gm1m2
36/F = 1/3
Cross multiplying we have
F = 36×3
F = 216N
Therefore, the gravitational force when the second object is tripled is 108N
Final answer:
The new gravitational force, when the mass of Object 2 is tripled and the distance between the objects remains the same, would be 108.0 units.
Explanation:
If the mass of Object 2 is tripled, according to the law of universal gravitation, the gravitational force between two objects is directly proportional to the product of their masses. The gravitational force can be described by the formula:
F = G \( \frac{m1 \cdot m2}{d²} \)
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between the centers of the two objects.
In the student's question, if the mass of Object 2 is tripled, and the distance remains unchanged, the new gravitational force would be:
Original force: 36.0 units
New force: 36.0 units \( \times 3\)
New force: 108.0 units
This is because tripling the mass of Object 2 causes the force to triple, as the force is directly proportional to the product of the two masses.
An airplane weighing 11,000 N climbs to a
height of 1.6 km in 9.8 min. Calculate the
accomplished power in horsepower.
The power in horsepower is 40.1 hp
Explanation:
We start by calculating the work done by the airplane during the climb, which is equal to its change in gravitational potential energy:
[tex]W=(mg)\Delta h[/tex]
where
mg = 11,000 N is the weight of the airplane
[tex]\Delta h = 1.6 km = 1600 m[/tex] is the change in height
Substituting,
[tex]W=(11,000)(1600)=17.6\cdot 10^6 J[/tex]
Now we can calculate the power delivered, which is given by
[tex]P=\frac{W}{t}[/tex]
where
[tex]W=17.6\cdot 10^6 J[/tex] is the work done
[tex]t=9.8 min \cdot 60 = 588 s[/tex] is the time taken
Substituting,
[tex]P=\frac{17.6\cdot 10^6 J}{588}=2.99\cdot 10^4 W[/tex]
Finally, we can convert the power into horsepower (hp), keeping in mind that
[tex]1 hp = 746 W[/tex]
Therefore,
[tex]P=\frac{2.99\cdot 10^4}{746}=40.1 hp[/tex]
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Final answer:
The power accomplished by an airplane weighing 11,000 N climbing to a height of 1.6 km in 9.8 min is calculated by determining the change in gravitational potential energy and then converting that work into power over the time taken. The result is approximately 40.13 horsepower.
Explanation:
To calculate the power accomplished, we can use the work-energy principle where the work done by the airplane engines to climb to the height is equal to the change in gravitational potential energy. The gravitational potential energy (GPE) change is calculated as the weight of the airplane times the height it reaches. The formula for GPE is:
GPE = weight × height
For the airplane problem, we have:
GPE = 11,000 N × 1.6 km = 11,000 N × 1600 m = 17,600,000 J (joules)
Next, we convert 9.8 minutes to seconds to find the power in watts. Power is work (or GPE here) divided by time:
Time = 9.8 minutes × 60 seconds/minute = 588 seconds
Power in watts = GPE / Time
Power in watts = 17,600,000 J / 588 s ≈ 29,932 W (watts)
To convert power to horsepower, we use the conversion factor 1 horsepower ≈ 746 watts:
Power in horsepower = Power in watts / 746
Power in horsepower ≈ 29,932 W / 746 ≈ 40.13 hp
Therefore, the accomplished power in horsepower while the airplane climbs to a height of 1.6 km in 9.8 min is approximately 40.13 hp.
A lock clicks 88 times in 22 seconds. Calculate the frequency and period of the clock
1) The frequency of the clock is 4 Hz
2) The period of the clock is 0.25 s
Explanation:
1)
In a periodic motion, the frequency of the motion is equal to the number of complete cycles per second.
Mathematically:
[tex]f=\frac{N}{t}[/tex]
f is the frequency
N is the number of cycles completed in a time t
For the clock in this problem, we have
N = 88 (number of cycles)
t = 22 s (time interval)
Substituting,
[tex]f=\frac{88}{22}=4 Hz[/tex]
2)
The period of a periodic motion is the time taken for one complete oscillation to occur.
Mathematically, the period is equivalent to the reciprocal of the frequency:
[tex]T=\frac{1}{f}[/tex]
where
T is the period
f is the frequency
Here we have found
f = 4 Hz
So, the period of the clock is
[tex]T=\frac{1}{4}=0.25 s[/tex]
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The frequency and period of the clock is 4Hz and 0.25s respectively.
Given the data in the question;
Number of cycles; [tex]N = 88[/tex]
Time interval; [tex]t = 22s[/tex]
Frequency; [tex]f = \ ?[/tex]
Period; [tex]T = \ ?[/tex]
Frequency is the number of complete cycles occurring per period of time.
Frequency; [tex]f = \frac{N}{t}[/tex]
We substitute in our given values
[tex]f = \frac{88}{22s} \\\\f = 4s^{-1}\\\\f = 4Hz[/tex]
Therefore, the frequency of the clock is 4Hz
Frequency [tex]f[/tex] is also the reciprocal of the period [tex]T[/tex]:
Hence, [tex]T = \frac{1}{f}[/tex]
We substitute in our values
[tex]T = \frac{1}{4s^{-1}} \\\\T = 0.25s[/tex]
Therefore, the period of the clock is 0.25s
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Jordan drove from his home to his new college. He drove 150 miles in 2.5 hours. What was his average speed, in miles per hour
Answer:
60 m/h
Explanation:
[tex]v = x \div t[/tex]
so v = 150 / 2.5 = 60 m/h
Most of the sun's energy reaches Earth by
conduction
radiation
convection
thermal expansion
Radiation is the process by which energy is transferred in the form of electromagnetic waves, including visible light, infrared radiation, and ultraviolet radiation. Most of the Sun's energy reaches Earth by b) radiation.
The Sun emits a vast amount of energy through nuclear fusion processes occurring in its core. This energy travels through space in the form of electromagnetic waves and reaches Earth as sunlight. Unlike conduction and convection, which require a medium or material substance to transfer heat, radiation can occur in a vacuum and does not require a physical medium.
The energy from the Sun's radiation is essential for sustaining life on Earth and driving various Earthly processes such as weather, climate, and photosynthesis.
Most of the Sun's energy reaches Earth by b) radiation.
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Arthur reads an article describing an experiment to test the effects of caffeine on the reaction time of humans—how long it took them to respond to a particular signal. In the experiment, the subjects' reaction times were measured, then they were divided into three groups. One group was given a high dose of caffeine. The second group was given a medium dose of caffeine. The third group was given a sugar pill that had no caffeine. After waiting 45 min for the caffeine to take effect, the reaction times were measured again.
In the experiment Arthur read about, what was the dependent variable?
A.
the amount of caffeine given to each person
B.
the type of signal each person responded to
C.
the amount of time the caffeine was given to take effect
D.
the change in reaction times for each person
Answer:
the change in reaction times for each person
Explanation:
The dependent variable in Arthur's article on the effects of caffeine on human reaction time is the change in reaction times for each person after consuming caffeine or a placebo.
Explanation:In the described experiment, the dependent variable is the change in the subjects' reaction times after they have been administered varying amounts of caffeine or a placebo. This is because the dependent variable is the factor that the researchers are measuring to see if it changes in response to the manipulation of the independent variable (in this case, the amount of caffeine given to each person). The different doses of caffeine or the placebo (sugar pill) represents the independent variables, because they are what the researchers are manipulating to see if there is an effect on the dependent variable.
Therefore, the correct answer to the question 'In the experiment Arthur read about, what was the dependent variable?' is D. the change in reaction times for each person.
A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to the nearest tenth.
Ax = miles
Answer:
The west axis component of walk is, A = 5 miles
The east axis component of walk is, B = 8 miles
Explanation:
Given data,
The displacement of hiker south of west, R = 9.4 miles
The angle formed south of west, Ф = 60°
The vector components along,
the west axis is
A = R cosФ
A = 9.4 x cos 60
A = 4.7 miles
A = 5 miles
The west axis component of walk is, A = 5 miles
the south axis is
B = R sinФ
B = 9.4 sin 60
B = 8.14 miles
B = 8 miles
The east axis component of walk is, B = 8 miles
Answer:
Ax= -4.7
Ay= -8.1
Explanation:
If a crane worker lifts a crate with a mass of 200 kg from the ground to a
shipping container that is 45 meters off the ground, by how much has the
worker increased the gravitational potential energy of the crate? (Recall that g
= 9.8 m/s2)
A. 88,200 J
B. 31,900 J
C. 63,500 u
D. 48,100 J
Answer:
A. 88,200 J
Explanation:
Given data,
The mass of the crate, m = 200 kg
The height of the shipping container, h = 45 m
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
P.E = 200 x 9.8 x 45
= 88,200 J
Hence, the gravitational potential energy of the crate is, P.E = 88,200 J
A ball rolls 50 meters in
10 seconds *
A. 2 meters per second
B. 5 meters per second
C. 10 meters per second
D. 25 meters per second
The speed of the ball is B. 5 meters per second
Explanation:
For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation
[tex]v=\frac{d}{t}[/tex]
where
v is the speed
d is the distance covered
t is the time taken
For the ball in this problem:
d = 50 m is the distance covered
t = 10 s is the time taken
Substituting, we find the speed:
[tex]v=\frac{50}{10}=5 m/s[/tex]
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WILL MARK BRAINLYYY Which organ is part of the respiratory system of tigers?
skin
lungs
gills
tracheae
Answer:
lungs
Explanation:
Similar to other mammal species that live on land and breath air (oxygen), the pair of lungs is the most important part of the respiratory system, which keeps living organisms alive.
Answer:
lungs are part of the respiratory system of tigers
the displacement of the body in 5 seconds from the beginning of the motion is
Answer:
The displacement of the object is, d = 5V m
Explanation:
Given data,
The time period of displacement, t = 5 s
Let the average velocity of the object be, V = v m/s
If the object has an initial velocity, V and final velocity v, then the average velocity of the object is,
V = (u + v) / 2
The formula for velocity, displacement and time is,
V = d / t
∴ d = V x t
On substitution,
d = V x 5 s
= 5V m
Substituting the value of V gives the value of displacement,
Thus, the displacement of the object is, d = 5V m
5V m is the displacement of the object.
What is Displacement?Displacement is defined as the change in position of an object. It is represented as an arrow that points from the initial position to the final position.
According to the question,
Time period , t = 5 s
Let, average velocity of the object is V = v m/s
Assume the initial velocity, V and final velocity v,
So, the average velocity of the object is,
[tex]V = \frac{(u + v)}{2}[/tex]
The relationship between velocity, displacement and time is,
[tex]V = \frac{d}{t}[/tex]
[tex]d = V * t[/tex]
Put t =5s
[tex]d = V * 5 s[/tex]
[tex]d = 5V m[/tex]
Therefore,
The displacement of the object is, d = 5V m
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determine the quantity of work done when a crane lifts a 100-N block from 2 m above the ground to 6 m above the ground.
A. 600 J
B. 400 J
C. 100 J
D. 200 J
I will mark the first RIGHT answer brainliest!
The work done on the block is B) 400 J
Explanation:
The work done when lifting an object is equal to the change in gravitational potential energy of the object:
[tex]W=mg \Delta h[/tex]
where
m is the mass of the object
g is the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the object
In this problem we have:
(mg) = 100 N is the weight of the block (product of mass and acceleration of gravity)
[tex]\Delta h = 6 m - 2 m = 4 m[/tex] is the change in heigth of the object
Substituting, we find the work done:
[tex]W=(100)(4)=400 J[/tex]
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Answer:
400j
Explanation:
took test and 100 times 4 equals 400
Which type of stress is a uniform stress that doesn't lead to earthquakes?
A. Shear stress
B. Compression
C. Lithostatic pressure
D. Tension
Answer:
C) Lithostatic pressure
Explanation:
An earthquake is what happens when two blocks of the earth suddenly slip past one another. The surface where they slip is called the fault or fault plane.
In the Earth the pressure due to the weight of overlying rocks is a uniform stress and is referred to as confiningstress. If stress is not equal from all directions then the stress is a differential stress. Three kinds of differential stress occur. Shear stress, which result in slippage and translation.
Answer:
Lithostatic pressure
Explanation: when you search up what lithostatic means you will see.
i need help with question 8 and 9
8) The height of the shelf is 2.04 m
9) The gravitational potential energy is 100 J
Explanation:
8)
The gravitational potential energy of an object is given by:
[tex]PE=mgh[/tex]
where
m is the mass of the object
g is the acceleration of gravity
h is the heigth of the object, relative to the ground
For the object in this problem, we have
m = 10 kg
[tex]g=9.8 m/s^2[/tex]
And we know that
PE = 200 J
Therefore we can re-arrange the formula to solve for h, the heigth of the object:
[tex]h=\frac{PE}{mg}=\frac{200}{(10)(9.8)}=2.04 m[/tex]
9)
As before, the gravitational potential energy of the object is given by:
[tex]PE=mgh[/tex]
where in this case, we have:
m = 10 kg is the mass of the object
h = 2.04 m is the height of the object from the ground
While in this case, the acceleration of gravity on this planet is
[tex]g=4.9 m/s^2[/tex]
Substituting,
[tex]PE=(10)(4.9)(2.04)=100 J[/tex]
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A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
a. Draw a free body diagram for the textbook.
b. What is the motion in the vertical?
c. What is the net horizontal force acting on the book?
d. What is the net force acting on the book?
e. What is the acceleration of the book?
Answer:
a. See attached diagram
b. There is no vertical motion
c. Net horizontal force: 35 N
d. Total net force: 35 N
e. Acceleration of the book: 8.75 m/s^2
Explanation:
Please see attached diagram for all the forces acting on the book:
Forces acting vertically:
1) The book's weight (force exerted by gravity) is pictured in purple pointing down and labeled "w".
2) The normal force the table exerts on the book as reaction, is pictured in blue pointing up, and labeled "n". It cancels with the force of gravity, so there is no vertical movement since gravitational force and the normal are the only forces acting in the vertical direction.
Forces acting horizontally:
1) the pushing 50 N force is pictured in green and pointing to the right, parallel to the surface of the table.
2) the 15 N force of friction is pictured in red, and acting in opposite direction to the pushing force. It is represented by a shorter vector than the pushing force due to the fact that its magnitude is smaller.
In this horizontal direction there is a net force that is propelling the object in horizontal motion. This net force is the difference between the 50 N force and the 15 N force, resulting in a 35 N force pointing in the same direction as the pushing force.
The net horizontal force is 35 N in magnitude.
The addition of all forces acting is dominated by the horizontal components, since the vertical acting forces cancel each other. Therefore, the total net force acting on the book is the 35 N resulting horizontal force.
The acceleration of the book can be calculated via Newton's second law of motion:
[tex]F_{net}=m\,*\,a\\35 N = 4\,kg\,*a\\a=\frac{35}{4} \,\frac{m}{s^2} \\a=8.75\, \frac{m}{s^2}[/tex]
A safe is hurled down from the top of a 1.3 x 102 m
building at a speed of 11.0 m/s. What is its velocity as
it hits the ground?
The final velocity is 49.7 m/s downward
Explanation:
The motion of the object is a free fall motion (affected only by the force of gravity), so the object accelerates downward with a constant acceleration of [tex]g=9.8 m/s^2[/tex] (acceleration of gravity). Therefore, we can use the following suvat equation:
[tex]v^2 -u^2 = 2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
Taking downward as positive direction, we have
u = 11.0 m/s
[tex]a=g=9.8 m/s^2[/tex]
[tex]s=1.3\cdot 10^2 m = 130 m[/tex] (height of the building)
Solving for v, we find the final velocity as the object hits the ground:
[tex]v=\sqrt{u^2+2as}=\sqrt{11.0^2+2(9.8)(120)}=49.7 m/s[/tex]
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If all of the forces acting on an object are balanced, then:
Check all that apply.
I
A. the direction the object is moving in will not change.
B. the acceleration of the object will be 0 m/s2
I
c. the object will not be in motion.
D. the velocity of the object will be 0 m/s.
A. the direction the object is moving in will not change.
B. the acceleration of the object will be 0 m/s2
Explanation:
We can answer this problem by using Newton's second law of motion:
[tex]\sum F = ma[/tex]
where
[tex]\sum F[/tex] is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, all the forces acting on the object are balanced, therefore the net force is zero:
[tex]\sum F=0[/tex]
which means that also the acceleration is zero:
[tex]a=0[/tex]
Acceleration is equal to the rate of change of velocity: therefore, zero acceleration means that the velocity of the object does not change. We can now analyze the given statements:
A. the direction the object is moving in will not change. --> TRUE, because the velocity is not changing.
B. the acceleration of the object will be 0 m/s2 --> TRUE, as we stated above
c. the object will not be in motion. --> FALSE: we just know that its velocity is constant, but it can be different from zero
D. the velocity of the object will be 0 m/s. --> FALSE, for the same reason stated in C
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Final answer:
When all of the forces on an object are balanced, the object will not change its direction of motion, its acceleration will be 0 m/s^2, and its velocity will be 0 m/s.
Explanation:
When all of the forces acting on an object are balanced, several things occur:
The direction the object is moving in will not change. This is because there is no net force acting on the object to change its motion.The acceleration of the object will be 0 m/s². This is because acceleration is directly proportional to the net force acting on an object, and if the forces are balanced, there is no net force and therefore no acceleration.The velocity of the object will be 0 m/s. Velocity is the rate at which an object changes its position, and if the forces are balanced, there is no change in position and therefore the velocity is 0 m/s.Help me with this Weather Station Model by answering 5 questions. It is due tomorrow.
1. What is the wind speed at this location?
A. 15 knots
B. 25 knots
C. 15 miles per hour
D. 25 miles per hour
2. What is the atmospheric pressure at this location?
A. 21 millibars
B. 82 millibars
C. 1002.1 millibars
D. 1021 millibars
3. What is the approximate relative humidity at this location?
A. 95%
B. 83%
C. 50%
D. 21%
4. Over the past few hours the air pressure has been
A. Decreasing
B. Increasing
C. Remaining constant
5. Which of the following instruments was NOT used to gather this weather data?
A. A sling psychrometer
B. An anemometer
C. A Seismometer
D. A Barometer
A cat walks 15 m north and then 12 m south. What distance did the cat walk?
O
A. 27 m north
O
B. 3 m
O
c. 27 m
O
D. 3 m north
Answer:
it's 27 meters - answer B
When a loaded cannon is fired, which physical variables are affected?
Answer:
it can explode lol
Explanation:
Historically, massive stone or metal balls were fired from cannons, which are big, powerful guns that are typically mounted on two or four wheels.
What are the physical variables?Because they result from the existence of quantitative characteristics of physical systems, physical variables provide the basis of the mathematical formulation of physics. It is convenient to begin with a thorough investigation of the physical variables in a physical theory before analyzing its mathematical structure.
When a loaded cannon is fired, some of the physical variables get affected
the cannon's temperaturethe potential energy of chemicalsthe ball's temperaturethe canon's momentumBall's velocity and so on.These are few physical variables which get affected when loaded cannon is fired.
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Which of the following is the best thermal insulator?
A.) Air
B.) Water
C.) Metal
D.) Stone
Please help I’m torn between A and B. I’ve asked many and people say A, but I asked my science teacher and she said B. And also I’ve researched and on answers.com also says Water is the better insulator..but idk I’m conflicted! APEX
Answer:
you're right it is b....
Answer:
A.) Air
Explanation:
Ap-ex
Consider this situation: A child is holding onto a tree rope and swinging through the air.
Of the forces listed, identify which act upon the child.
a. Normal Force
b. Gravity Force
c. Applied Force
d. Friction Force
e. Tension Force
f. Air Resistance Force
Final answer:
In the scenario of a child swinging on a rope, the acting forces are the gravity force, tension force, and air resistance force. Normal force and applied force are not directly acting on the child in the swing, and friction force is not a significant factor in this context.
Explanation:
When a child is swinging through the air while holding onto a tree rope, the child is subject to several forces. Among the forces listed, the following forces act upon the child:
Gravity Force: This is also known as weight, represented by W in the free-body diagram. It pulls the child directly downwards towards the center of the Earth.
Tension Force: Represented by T in the free-body diagram, this force is exerted by the rope on the child, pulling upwards and often inclined depending on the motion of the swing.
Air Resistance Force: As the child swings, they encounter air resistance that opposes their motion through the air.
The normal force does not act upon the child while they are swinging because there is no perpendicular contact with a solid surface like the ground or a table. Applied force would be present if someone or something else is pushing the child to start the swinging motion or to keep it going. However, for the child simply swinging, we do not consider an ongoing applied force. Friction force is usually associated with contact between two surfaces, such as the wheels of a wagon rolling on the ground. Therefore, friction is not a significant factor when considering a child swinging on a rope.
Using this understanding, we can create a free-body diagram that includes only external forces such as gravity force, tension force, and air resistance force to analyze the child's motion.
What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of temperature against energy to show this process.
Answer:
The amount of energy required is 31.1692 kJ .
Explanation:
The transitions of water are as follows,
(243K ice to 273K ice to 273K water to 373k water to 373K steam to 393K steam)
The following required data is,
specific heat capacity of ice= 2.1 kJ/kg
specific heat capacity of water= 4.2 kJ/kg
specific heat capacity of ice= 1.996 kJ/kg
specific latent heat of fusion=334 kJ/kg
specific latent heat of vapourisation = 2260 kJ/kg
FORMULAS:-
temperature change=mc(T2-T1)
phase transistion = mL,
where, m=mass , c=specific heat capacity ,L = latent heat of fusion or vapourisation ,(T2-T1)= temparature change
Thus the total amount of heat is,
=mc(T4-T3) + mL + mc(T3-T2) + mL + mc(T2-T1)
=[tex]10(10^{-3} )(2.1)(30)+10(10^{-3} )(334)+10(10^{-3} )(100)(4.2)+10(10^{-3} )(2260) +10(10^{-3} )(20)(1.996)[/tex]
=(0.3)(2.1) + (3.34) + (4.2) + (22.6) + (0.2)(1.996)
=31.1692 kJ.
A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?
The distance covered by the feather is 65.5 m
Explanation:
The motion of the feather is a free-fall motion (affected only by the force of gravity), therefore it is a motion at constant acceleration, and so we can use the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the displacement
u is the initial velocity
t is the time
a is the acceleration
In this problem, we have
u = 0 is the initial velocity of the feather
t = 9.00 s is the time interval
[tex]a=g=1.62 m/s^2[/tex] is the acceleration of gravity on the Moon
And solving for s, we find the distance covered by the feather in its fall:
[tex]s=0+\frac{1}{2}(1.62)(9.00)^2=65.6 m[/tex]
Learn more about free fall:
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#LearnwithBrainly
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As a sound wave travels from liquid water into ice, its wavelength would
Stretch.
Hope this helps.
FASTTTTTTTTTTTTTTT PLEASEEEEEEEEEEEEE ITS 2O POINTS
The graph below shows a velocity vs. time graph. A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line runs from 0 seconds 10 meters per second to 5 seconds 2 meters per second. Which graph would match the same type of movement that the graph shows? A graph with horizontal axis time (seconds) and vertical axis position (meters). A straight line runs from 0 seconds 0 meters upward. A graph with horizontal axis time (seconds) and vertical axis position (meters). A concave line runs from 0 seconds 0 meters upward. A graph with horizontal axis time (seconds) and vertical axis position (meters). A straight line runs from 0 seconds some positive number meters upward downward to some positive number of seconds 0 meters. A graph with horizontal axis time (seconds) and vertical axis position (meters). A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters.
Answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
Explanation:
The figure shows Velocity vs Time Graph.
At t1=0, u=10m/s
At t2=5, v=2m/s
Let's calculated the acceleration
[tex]a=\frac{v-u}{t2-t1}[/tex]
[tex]a=\frac{2-10}{5-0}[/tex]
[tex]a=\frac{-8}{5}[/tex]
The equation of distance is given by
[tex]d=ut+\frac{a}{2} t^{2}[/tex]
[tex]d=(10)t+\frac{\frac{-8}{5}}{2} t^{2}[/tex]
[tex]d=10t+\frac{-8}{10} t^{2}[/tex]
[tex]d=10t+\frac{-4}{5} t^{2}[/tex]
[tex]5d=50t-4t^{2}[/tex]
From here, You can plot the graph of above equation by taking several points.
When t=0,
[tex]5d=50(0)-4(0)^{2} = 0m[/tex]
When t=5,
[tex]5d=50(5)-4(5)^{2}[/tex]
[tex]5d=250-100[/tex]
[tex]5d=150[/tex]
[tex]d=30m[/tex]
Similarly,
When t= 3s d=22.8m
When t=4s d=27.2m
Figure shown is graph of Distance vs Time.
Thus, answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
Answer:
Your answer is D) A graph with horizontal axis time (seconds) and vertical axis position (meters). A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters.
Explanation:
10) If the mass 2m, the left mass
is m/2 and the distance is
r What is the gravitation
force ?
Answer:
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex].
Explanation:
Gravitational force between two objects of masses [tex]m_{1}, m_{2}[/tex] kept at a distance r is given by the formula
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex]
Here ,[tex]m_{1}[/tex] = 2m
[tex]m_{2}[/tex] = [tex]\frac{m}{2}[/tex]
Thus , F = [tex]\frac{-G.2m.\frac{m}{2} }{r^{2} }[/tex]
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex].
A group of students were testing different insulators. They used three metal cans, one wrapped with bubble wrap, a second with a paper towel, and third unwrapped. Equal amounts of hot water were poured into each can and the temperature was noted at definite time intervals. The data is shown in the table.
From the data, they concluded that bubble wrap was the best insulating material. What is the weakness in the conclusion?
A) It is the better of two insulators only; it is not the best insulator.
B) The experiment should have been continued till the temperatures of the cans reached 0°C.
C) The experiment must be repeated at least three times before this conclusion can be drawn.
D) The data on the can without insulator is irrelevant and distracts from the main idea of the experiment.
Answer:
A)
Explanation:
The insulator is a material that creates a barrier for the heat transferred, maintaining the temperature of the system almost unaltered. To know what is the best insulator, the experiment needs to be done with an unwrapped can, so that is possible to know how much heat the can be lost, thus letter "d" is incorrect.
The temperature of the water would not achieve 0°C, but the ambient temperature, being in thermal equilibrium, so the letter "b" is also incorrect.
By the data given is already notice the insulator power, because the temperature decreases faster with the paper towel, thus it's not necessary to repeat the experiment only to know which one is better, so the letter "c" is incorrect.
But, it's not possible to affirm that the bubble wrap is the best insulating material, because exists a lot off insulating material that wasn't tested. Besides, the insulation depends on the thickness of the material.
Answer:
A
Explanation:
The term “best” means that there is nothing better. The student cannot conclude that bubble wrap is the best insulator after having tested only two insulating materials. It is the better of two insulators only; it is not the best insulator.