2. An engine's _______ contains the cylinder head, the valves, the valve train components, the manifolds, and the engine covers. A. lower end B. upper end C. bottom end D. back end

Answer:

709 kg/m³

Explanation:

Applying the expression obtained from Archimedes Principle as:

[tex]\% of\ the\ fraction\ submerged=\frac {\rho_{object}}{\rho_{liquid}}\times 100[/tex]

Given :

Percentage of the log above water = 29.1%

Percentage of the log of the water submerged = 100-29.1 % = 70.9%

Density of water = 1000 kg/m³

So,

[tex]70.9 \% =\frac {\rho_{object}}{1000}\times 100[/tex]

The average density of the log = 709 kg/m³

Answer:

kinetic energy is the energy an object contains due to motion while potential energy is stored energy that an object contains due to its position or shape.

hope this helps! (:

Answer:

Kinetic energy- is energy of an object which contains becuase of motion. Potential energy- is stored energy that an object contains because of its position or shape.

Answer:

[tex]v = 0.478 m/s[/tex]

Explanation:

As we know that bullet strike the block and fix in it

so here if bullet and box is taken as a system then there is no external force on it

so here the initial momentum of bullet and block must be equal to final momentum of bullet and block

so here we have

[tex]m_1v_{1i} + m_2v_{2i} = m_1v + m_2v[/tex]

now we have

[tex]m_1 = 8 g[/tex]

[tex]v_1 = 120 m/s[/tex]

[tex]m_2 = 2kg[/tex]

[tex]v_{2i} = 0[/tex]

now from above equation we have

[tex](0.008)(120) + 2(0) = (0.008)v + 2v[/tex]

[tex]v = 0.478 m/s[/tex]

The speed of the wooden block after the collision with the bullet can be calculated by applying the principle of conservation of momentum. The initial velocity of the block is zero as it was stationary before the collision. By applying the formula for momentum conservation, we get the final speed of the block.

The subject of the question deals with a principle in Physics known as conservation of momentum. In an isolated system (in this case, the bullet and the wood block), the total momentum before the collision is equal to the total momentum after the collision. The bullet has a mass of 0.008 kg (converted from 8.0 g to kg) and a velocity of 120 m/s before the collision while the block of wood has a mass of 2.0 kg and is stationary (velocity of 0 m/s).

To apply the conservation of momentum principle, we use the formula: m1v1 + m2v2 = (m1 + m2)v where m1 and v1 are the mass and velocity of the bullet and m2 and v2 are the mass and velocity of the wooden block (initially v2 is 0 because the block is stationary). After substituting the given data, we can solve for variable v; the resultant speed of the block after the collision.

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Explanation:

There are three ways in which the thermal transfer (heat) occurs:

1. By Conduction, when the transmission is by the direct contact.  

2. By Convection, heat transfer in fluids (like water or the air, for example).  

3. By Radiation, by the electromagnetic waves (they can travel through any medium and in vacumm or empty space)

Since outter space is vacuum (sometimes called "empty"), energy cannot be transmitted by convection, nor conduction. It must be transmitted by electromagnetic waves that are able to travel with or without a medium.

Answer:

The angular momentum and angular velocity are 1.134 kg.m²/s and 174.5 rad/s.

Explanation:

Given that,

Moment of inertia [tex]I= 6.5\times10^{-3}\ kg.m^2[/tex]

Torque = 21 N.m

Time dt = 54 ms

(a). We need to calculate the angular momentum

Using formula of torque

[tex]\tau=\dfrac{dL}{dt}[/tex]

[tex]dL =\tau\times t[/tex]

Where, dL = angular momentum

t = time

[tex]\tau[/tex] = torque

Put the value into the formula

[tex]dL=21\times0.054[/tex]

[tex]dL=1.134\ kg.m^2/s[/tex]

(b). We need to calculate the angular velocity of the disk

Using formula of angular velocity

[tex]dL=I\omega[/tex]

[tex]\omega=\dfrac{dL}{I}[/tex]

[tex]\omega=\dfrac{1.134}{6.5\times10^{-3}}[/tex]

[tex]\omega=174.5\ rad/s[/tex]

Hence, The angular momentum and angular velocity are 1.134 kg.m²/s and 174.5 rad/s.

Answer:

A) Magma emplacement

Explanation:

Sedimentary structures forms during deposition of sediments. It can also form after sediments have been deposited. Sedimentary structures can only be found in sedimentary rocks. Some examples include mud cracks, ripple marks, cross stratification, potholes, etc

Magma emplacement is an igneous process which describes the different mechanisms by which magma can be emplaced. It is only typical of igneous rocks.

Answer: 1) 24.76 kJ/g

2)  597.4 kJ/mol

Explanation:

Let the heat released during reaction be q.

[tex]q=m\times c\times \Delta T[/tex]

q = Heat gained by water

m = Mass of water= 300 g

c = Heat capacity of water = 4.184 J/g°C

Change in temperature = ΔT = 1.126 °C

[tex]q=300\times 4.184\times 1.126=1413.3J[/tex]

Heat gained by bomb calorimeter = [tex]q_{cal}[/tex]

Heat capacity of bomb calorimeter , C = 1769J/g°C

Change in temperature = ΔT'= 1.126 °C

[tex]q_{cal}=m_{cal}\times c_{cal}\times \Delta T=C_{bomb}\times \Delta T=1769\times 1.126=1991.9J[/tex]

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

[tex]q_{combustion}=-(q_{water}+q_{cal}[/tex]

[tex]q_{combustion}=-(1413.3+1991.9)J[/tex]

[tex]q=3405J=-3.405kJ[/tex]

Thus 0.1375 g of magnesium releases 3.405 kJ of heat

1 g of magnesium releases =[tex]\frac{3.405}{0.1375}\times 1=24.76kJ[/tex] of heat

Thus heat given off by the burning magnesium, in kJ/g is 24.76.

Moles of magnesium =[tex]\frac{0.1375g}{24g/mol}=5.7\times 10^{-3}mol[/tex]

[tex]5.7\times 10^{-3}[/tex]  moles of magnesium releases 3.405 kJ of heat

1 mole of magnesium releases =[tex]\frac{3.405}{5.7\times 10^{-3}}\times 1=597.4 kJ[/tex] of heat

Thus heat given off by the burning magnesium, in kJ/mol is 597.4.

The heat given off by the burning magnesium is 0.27297 kJ. The heat given off per gram of magnesium is 1.984 kJ/g. The heat given off per mole of magnesium is 48.15 kJ/mol.

To calculate the heat given off by the burning magnesium, we need to use the equation q = mCΔT, where q is the heat, m is the mass, C is the heat capacity, and ΔT is the temperature change. In this case, the mass is 0.1375 g, the heat capacity is 1769 J/°C, and the temperature change is 1.126 °C.

Plugging in these values, we get q = (0.1375 g)(1769 J/°C)(1.126 °C) = 272.97 J.

To convert this to kJ, use the conversion factor 1 kJ = 1000 J. Therefore, the heat given off by the burning magnesium is 0.27297 kJ.

To find the heat given off per gram of magnesium, divide the heat by the mass of the magnesium: 0.27297 kJ / 0.1375 g = 1.984 kJ/g.

To find the heat given off per mole of magnesium, we need to convert the mass of the magnesium to moles using the molar mass of magnesium. The molar mass of magnesium is 24.31 g/mol.

Therefore, moles of magnesium = (0.1375 g) / (24.31 g/mol) = 0.00566 mol.

Divide the heat by the moles of magnesium to get the heat given off per mole: 0.27297 kJ / 0.00566 mol = 48.15 kJ/mol.

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Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

Answer: The magnitude of the force on the space vehicle is 0 N

Explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

[tex]F=m\times a[/tex]

where,

F = force exerted on the space vehicle

m = mass of the space vehicle = 160 kg

a = acceleration of the space vehicle = [tex]0m/s^2[/tex]    (Speed is constant)

Putting values in above equation, we get:

[tex]F=160kg\times 0m/s^2\\\\F=0N[/tex]

Hence, the magnitude of the force on the space vehicle is 0 N

Answer: This law allows us to know how the illuminance  of the star varies with the square of the distance.

Explanation:

The Law of the Inverse of the Square for light, allows us to determine, in the case of a star, and considering it as a point source, how its illuminance  

[tex]E[/tex]  (power per unit area) varies with the square of the distance   [tex]r[/tex] that separates us from it when measuring its apparent brightness.

This law is expressed as follows:

[tex]E=\frac{I}{r^{2}}[/tex]

Where [tex]I[/tex] is the pointance (The flux power per unit solid angle, which is somehow analog with the intensity).

As we can see, as the distance from the light source increases, the illuminance decreases.

The inverse square law of light enables us to calculate the distance to a star by using its apparent brightness and known intrinsic brightness, especially through the use of standard candles in astronomy.

Assuming we can measure the apparent brightness of a star, the inverse square law of light allows us to calculate the distance to the star when we know its intrinsic brightness. This law states that the observed flux of an object decreases as the inverse of the square of its distance from the observer. When utilizing this principle in astronomy, the standardized luminosity of certain astronomical objects, commonly known as standard candles, is needed to determine their distance. For example, if we identify a main sequence star with a known spectral type, we can assume it has a similar luminosity to other stars with the same spectral type and thus calculate its distance by observing its flux and applying the inverse square law.

(a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

(a)

The total resistance of the circuit is found as;

R=R₁+R₂

R=8 -ohm +6-ohm

R=14.0-ohm

(b)

The current in the 6.0-ohm resistor is;

The potential difference across the 6.0-ohm resistor= 12-V.

From Ohm's law;

V=IR

I=V/R

I=12-V/8-ohm

I=1.5-A

c)The potential difference across the battery is;

[tex]\rm I=I_1 \\\\ \frac{V}{R} =\frac{V_1}{R_1} \\\\\frac{V}{14} =\frac{12}{6} \\\\ V=28 \ volt[/tex]

Hence, a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

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The total resistance of the circuit is 14.0 ohms. The current in the 6.0-ohm resistor is 2 A. The potential difference across the battery is 28 V.

Let's analyze the series circuit step by step:

Answer:

Part (a): The goods must be dropped 422.812 meters advance of the recipients.

Part (b): The supplies must be given with ascendent vertical velocity of V=0.147 m/s to make they arrive precisely at the climbers position.

Explanation:

h= 235m

g= 9.8 m/s²

V= 61.1 m/s

Part a:

fall time of supplies:

[tex]t=\sqrt{\frac{2.h}{g} }[/tex]

t= 6.92 sec

d= V*t

d= 61.1 m/s * 6.92 s

d= 422.812 m

Part b:

d= 425m

d=V*t

t=d/V

t= 6.95 sec

Δt= 6.95 sec - 6.92 sec

Δt=0.03 sec

The supplies must be given ascendent vertical velocity to compensate that difference of time Δt. the half of the difference must be used to the ascendent part and the other half will be used to descendent part of the supplies.

To calculate the vertical velocity:

Vo= g * Δt/2

Vo= 9.8 m/s² * (0.03 sec/2)

Vo= 0.147 m/sec

Part (a) The horizontal distance in advance the goods should be dropped is approximately 422.812 meters

Part (b) The velocity to be given to the supplies is approximately 0.394 m/s up

The reason the above values are correct is as follows:

The known parameters are;

The vertical distance of the climbers below the airplane, h = 235 m

The horizontal velocity of the airplane, v = 61.1 m/s

Acceleration due to gravity, g ≈ 9.81 m/s²

Part (a) Required:

The distance in advance of the recipients the goods must be dropped

Solution:

The time, t, it will take the goods to drop is given by the following formula for free fall;

[tex]t =\mathbf{ \sqrt \dfrac{2 \times h }{g }}[/tex]

[tex]t =\ \sqrt {\dfrac{2 \times 235 }{9.81 } } \mathbf{\approx 6.92}[/tex]

The time it will take the goods to drop, t ≈ 6.92 seconds

The distance in advance the goods should be dropped, d, is given as follows;

Distance , d = Velocity, v × Time, t

∴ d = Velocity of the airplane, v × The time it will take the goods to drop, t

Which gives;

d ≈ 61.1 m/s × 6.92 s = 422.812 meters

The horizontal distance in advance the goods should be dropped, d ≈ 422.812 meters

Part (b) Given:

The horizontal distance in advance the airplane releases the supplies, d = 425 meters

Required:

The vertical velocity (up or down) to be given the to supplies so they arrive at the climbers position

Solution:

The time the  supplies spend in the air, t, is given as follows;

t = d/v

Where;

v = The horizontal velocity of the airplane  = 61.1 m/s

∴ t = 425 m/(61.1 m/s) =  6.95581015 s ≈ 6.96 s

The vertical distance of travel, s, is given by the following kinematic equation of motion

s = u·t + (1/2)·g·t²

Where;

u = The vertical velocity downwards

s = The distance = 235 meters (below)

g = +9.81 m/s² (downward motion)

Plugging in the values gives;

235 = u·6.96 + (1/2)×9.81×6.96² = 6.96·u + (1/2)×9.81×6.96 = 237.606048

u·6.96 = 237.606048- 240.345 = -2.738952

u = -2.738952/6.96 ≈ -0.394

The velocity to be given to the supplies, u ≈ -0.394 m/s down ≈ 0.394 m/s up (wards)

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Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, [tex]A \rightarrow B + C + Heat[/tex]

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction [tex]A \rightarrow B + C + heat[/tex], the potential energy of the products is less than that of the reactant.

The correct answer is: the potential energy of the products is less than that of the reactant.

Here's why:

The reaction notation A B + C + heat indicates an exothermic reaction. This means the reaction releases heat to the surroundings.

In exothermic reactions, the total potential energy of the products is less than the total potential energy of the reactants. The released heat signifies a decrease in the overall potential energy of the system.

Let's analyze the other options:

Net input of energy: This is the opposite of what's happening in an exothermic reaction. The reaction releases energy, not absorbs it.

Potential energy of products is the same: In some reactions, the potential energy might remain the same. However, the "heat" term in the notation signifies a release of energy, making this unlikely.

Entropy has decreased: Entropy, a measure of randomness, usually increases in most natural processes, including chemical reactions.

(a) -83.6 Hz

Due to the Doppler effect, the frequency of the sound of the train horn appears shifted to the observer at rest, according to the formula:

[tex]f' = (\frac{v}{v\pm v_s})f[/tex]

where

f' is the apparent frequency

v = 343 m/s is the speed of sound

[tex]v_s[/tex] is the velocity of the source of the sound (positive if the source is moving away from the observer, negative if it is moving towards the observer)

f is the original frequency of the sound

Here we have

f = 350 Hz

When the train is approaching, we have

[tex]v_s = -40.4 m/s[/tex]

So the frequency heard by the observer on the platform is

[tex]f' = (\frac{343 m/s}{343 m/s - 40.4 m/s})(350 Hz)=396.7 Hz[/tex]

When the train has passed the platform, we have

[tex]v_s = +40.4 m/s[/tex]

So the frequency heard by the observer on the platform is

[tex]f' = (\frac{343 m/s}{343 m/s + 40.4 m/s})(350 Hz)=313.1 Hz[/tex]

Therefore the overall shift in frequency is

[tex]\Delta f = 313.1 Hz - 396.7 Hz = -83.6 Hz[/tex]

And the negative sign means the frequency has decreased.

(b) 0.865 m

The wavelength and the frequency of a wave are related by the equation

[tex]v=\lambda f[/tex]

where

v is the speed of the wave

[tex]\lambda[/tex] is the wavelength

f is the frequency

When the train is approaching the platform, we have

v = 343 m/s (speed of sound)

f = f' = 396.7 Hz (apparent frequency)

Therefore the wavelength detected by a person on the platform is

[tex]\lambda' = \frac{v}{f'}=\frac{343 m/s}{396.7 Hz}=0.865m[/tex]

To solve these problems, use the Doppler Shift formula to calculate the change in frequency as the train moves from approaching to receding. Then, use the relationship between speed, frequency, and wavelength to find the wavelength of the sound as the train approaches.

To solve part (a) of the question regarding the overall change in frequency, we need to apply the formula for the Doppler Shift. Since the train passes the observer with a velocity of 40.4 m/s, and the speed of sound in air is about 343 m/s we can utilize these values. Add in the frequency of the horn, 350 Hz, once when the train is approaching (+ velocity) and again while receding (- velocity). This will give us the observed frequency in both scenarios. Subtract the frequency of the horn when it is receding from the frequency when it is approaching to get the overall change in frequency.

For part (b), we already know that the speed of sound v is 343 m/s and the frequency f (Doppler Shift) is 350 Hz from the given. We just need to apply these values into the equation relating speed, frequency, and wavelength (v = fλ). Solving for λ (wavelength) will give us the wavelength of the sound as it reaches the person on the platform.

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Answer: the answer is c (apex)

Explanation: ya welcome....

Answer:

D) Synthesizers have always had a well-established presence in standard ensembles

Explanation:

Identify the false statement: Select one:

A) Synthesis refers to creating sounds electronically from electronically generated waveforms.

B) The synthesizer generates sounds electronically.

C) On the synthesizer, timbre and volume depend on the waveform.

D) Synthesizers have always had a well-established presence in standard ensembles.

A synthesizer is an electronic musical instrument that generates audio signals. Synthesizers generate audio through the following means: subtractive synthesis, additive synthesis, and frequency modulation synthesis. .

,they generate sounds electronically by the virtue of the oscillator

c. on the synthesizer , timbre and volume depend on the waveform , which is true

D is absolutely not correct

The false statement is that synthesizers have always had a well-established presence in standard ensembles. This is not true because synthesizers became more common in ensembles during the mid-20th century, revolutionizing music with their electronic sound generation and waveform manipulation capabilities. So the correct option is D.

The false statement among the options provided is:

D) Synthesizers have always had a well-established presence in standard ensembles.

This statement is false because synthesizers were not part of standard ensembles until the mid-20th century when electronic instruments became more prevalent in various music genres. Prior to that, ensembles typically consisted of acoustic instruments. Synthesizers, which generate sounds electronically and allow for the manipulation of timbre and volume depending on the waveform, brought a new dimension to music that was not always present or well-established in traditional ensembles.

Sound from an electronic speaker is produced when the cone of the speaker vibrates, creating small changes in the pressure of the air, not the temperature or volume. Timbre is not the pitch or wavelength of the sound but refers to the quality of a sound that distinguishes one source or musical instrument from another.

Answer:

1.2/4.5=4/15=2.666 m/s^2

Explanation:

f=ma

The bird's acceleration is approximately 0.2667 m/s² in the direction opposite to its motion (westward).

To calculate the bird's acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

Mathematically, Newton's second law can be expressed as:

Net Force = mass x acceleration

Given:

Mass of the pelican (m) = 4.5 kg

Net force (F) = 1.2 N (acting to the west)

We want to find the acceleration (a).

Now, let's rearrange the formula to solve for acceleration:

acceleration = Net Force / mass

Substitute the given values:

acceleration = 1.2 N / 4.5 kg

Now, calculate the acceleration:

acceleration = 0.2667 m/s² (rounded to four decimal places)

So, the bird's acceleration is approximately 0.2667 m/s² in the direction opposite to its motion (westward).

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Answer:

a)  1.301 kg/s

b) 0.001301 m³/s

c) V₁ = 6.505 m/s, V₂ = 1.626 m/s

d) 118.93 kPa

Explanation:

Given:

The number of cans  = 220

The volume of can, V = 0.355 L = 0.355 × 10⁻³ m³

time = 1 minute = 60 seconds

gauge pressure at point 2, P₂ = 152 kPa

b) Thus, the volume flow rate, Q = Volume/ time

Q = (220 × 0.355 × 10⁻³)/60 = 0.001301 m³/s

a) mass flow rate = Volume flow rate × density

since it is mostly water, thus density of the drink = 1000 kg/m³

thus,

mass flow rate = 0.001301 m³/s × 1000 kg/m³ = 1.301 kg/s

c) Given:

Cross section at point 1 = 2.0 cm² = 2 × 10 ⁻⁴ m²

Cross section at point 2 = 8.0 cm² = 8 × 10 ⁻⁴ m²

also,

Q = Area × Velocity

thus, for point 1

0.001301 m³/s = 2 × 10 ⁻⁴ m² × velocity at point 1 (V₁)

or

V₁ = 6.505 m/s

for point 2

0.001301 m³/s = 8 × 10 ⁻⁴ m² × velocity at point 1 (V₂)

or

V₂ = 1.626 m/s

d) Applying the Bernoulli's theorem between the points 1 and 2 we have

[tex]P_1+\rho gV_1 + \frac{\rho V_1^2}{2}=P_2+\rho gV_2 + \frac{\rho V_2^2}{2}[/tex]

or

[tex]P_1=P_2+\rho\timesg(y_2-y_1)+\frac{\rho}{2}(V_2^2-V_1^2))[/tex]

on substituting the values in the above equation, we get

[tex]P_1=152+1000\times 9.8(1.35)+\frac{1000}{2}(1.626^2-6.505^2))[/tex]

it is given that point 1 is above point 2 thus, y₂ -y₁ is negative

or

[tex]P_1=118.93\ kPa[/tex]

thus, gauge pressure at point 1 is 118.93 kPa

Answer:

6.7 kg

Explanation:

V = 5000 L = 5000 x 10^-3 m^3 = 5 m^3

T = 0.2 degree C = 273.2 K

P = 1.04 atm = 1.04 x 1.01 x 10^5 Pa = 1.0504 x 10^5 Pa

R = 8.314 in SI system of units

Use the ideal gas equation. Let n be the moles of air occupied in the lungs of whale.

P V = n R T

n = P V / R T

n = (1.0504 x 10^5 x 5) / (8.314 x 273.2) = 231.22

the mass of one mole of air is 28.98 g

So, the mass of 231.22 moles of air = 231.22 x 28.98 = 6700 .88 g = 6.7 kg

Calculate the mass of air in an adult blue whale's lungs using the ideal gas law with provided values for lung capacity, temperature, pressure, and molar mass.

The mass of air contained in an adult blue whale’s lungs can be calculated using the ideal gas law:

Given:
Lung capacity (V) = 5.0 x 10^3 L
Temperature (T) = 0.2°C = 273.2 K
Pressure (P) = 1.04 atm
Molar mass (m) = 28.98 g/mol

Using the ideal gas law equation: PV = nRT, you can find the number of moles of air, and then calculate the mass of air using the molar mass.

Example Calculation:
n = PV / RT
n = (1.04 atm x 5.0 x 10^3 L) / (0.0821 L.atm/mol.K x 273.2 K)

Answer:

294.11 N

Explanation:

F1 = 200 N

Let the other force is F2 = F = ?

Resolve the components of F1 and F2.

As the object is in equilibrium in y direction, it means the net force in y direction is zero.

So, F1 Sin 30 = F2 Sin 20

200 x 0.5 = F x 0.34

F = 294.11 N

The magnitude of force is 294.11 N

Answer: Alex traveled a distance of 27.0 km in 2.25 hours.  

Further Explanation:

Speed is how fast an object moves or how far an object travels per unit time. If the distance traveled and the total time of travel are known, the speed can be calculated using the formula:

[tex]speed \ = \frac{distance}{time}[/tex]

In the problem, we are given:

speed = 12.0 km/hr

time = 2.25 hr

We are looking for the distance traveled by Alex which can be represented by the variable d.

We can solve for d by manipulating the speed formula to get the equation:

distance, d \ = \ (speed)(time)[/tex]

Plugging in our values for speed and time, we get the equation:

[tex]distance \ = \ (12.0 \ \frac{km}{hr})(2.25 \ hr)\\ \boxed {distance,d\ = \ 27.0 \ km}[/tex]

Since the number of significant figures of the given is 3, the answer must be expressed with 3 significant figures, too.

Thus, the distance Alex traveled for 2.25 hours at a speed of 12.0 km/hr is 27.0 km.

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Keywords: speed, distance, kinematics

Answer:

D.very slowly (centuries to a million years) when it forms a deep pluton.

Explanation:

Magma is a molten rock that forms within the earth crust. It is sometimes called melt. When it reaches the earth surface, it is called lava.

Only D is correct. Magma would cool slowly in a very deep pluton. In such an enviroment, access to circulating ground water is cut off and the temperature would be close to that by which the melt forms.

When magma cools and solidifies, it forms a wide variety of igneous rocks.

In the presence of circulating ground water, magma would cool and crystallize very rapidly. The ground water would provide more fluid phase for the movement of ions within the very thick and viscous melt thereby facilitating crystallization of minerals in the melt. Due to the temperature of the water, it serves as a coolant for the melt. The ground water takes heat away and returns with a more cold water.

Magma cools faster if the surface area of the intrusion is very large. A larger surface area would help more heat to dissipate and leave the body of the melt.

Magma cooling and crystallization form solid igneous rocks, with the rate of cooling influencing crystal size. Slowly cooling magma forms large crystals in intrusive igneous rocks like granite, while rapidly cooling magma forms fine-grained rocks. Deep plutons may take centuries to a million years to cool, resulting in coarse-grained textures.

Magma may cool and crystallize to form solid igneous rock. This process can occur at variable rates depending on several factors. When magma cools slowly, typically deep within the Earth, the resulting crystals are larger, forming coarse-grained intrusive or plutonic igneous rocks such as granite. Conversely, magma that cools quickly, often at or near the Earth's surface, forms rocks with much smaller crystals, known as fine-grained igneous rocks.

Cooling and forming crystals happen when the molten magma begins to cool. The slower the cooling process, the larger the crystals that can grow, since ions have more time to arrange into a crystal lattice. For example, a deep pluton, which is a large body of intrusive igneous rock that crystallized from magma cooling beneath the Earth's surface, can take from centuries to a million years to cool.

To achieve an interference pattern, we must have two coherent wave sources. For coherence, the waves must have the same frequency and either have no phase difference or a constant phase difference.

For two waves traveling in the same medium, having the same frequency implies having the same wavelength by v = fλ where v = velocity, f = frequency, and λ = wavelength.

An interference pattern requires all of the above conditions except for having the same amplitude.

Choice C

Answer:

e.) They all travel through space at the same speed.

All electromagnetic waves travel through space at the same speed. therefore the correct answer is option E

The oscillation of an electric field and a magnetic field produces electromagnetic waves, which are waves. In other words, electromagnetic waves (EM waves) are made up of vibrating magnetic and electric fields that are orthogonal to one another. Transverse waves are another name for electromagnetic waves since they move in a transverse direction.

These waves are used to transfer light & heat as a form of electromagnetic radiation, these electromagnetic waves are of various kinds such as radio waves, visible light, ultraviolet waves, x-rays, infrared waves, microwaves, gamma rays, etc.

All different kinds of electromagnetic waves have different wavelengths and frequencies but they all travel through space at the same speed of light.

Thus, All electromagnetic waves travel through space at the same speed. therefore the correct answer is option E

Learn more about Electromagnetic waves from here

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Answer:

The way to produce things in an assembly line

Explanation:

He created assembly line production, which was quite popular in the Industrial Revolution

Answer:

a) [tex]v_0=640[/tex] ft/s

b) [tex]y=H+1600[/tex] ft where[tex]H[/tex]  represents the height as the projectile was launched.

c)[tex]x=11085.13[/tex] ft

Explanation:

First, recognize the values that are given in the problem:

[tex]\alpha =30 ^o[/tex]

[tex]t_f=20[/tex]

[tex]y_f=H[/tex]

a) With those three use this formula: [tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2[/tex]

to find the initial velocity [tex]v_0[/tex].

[tex]\\y_f= H+v_0sin(\alpha)t_f-\frac{1}{2}gt_f^2 \\H= H+v_0sin(30)(20)-\frac{1}{2}(32)(20)^2 \\ -v_0sin(30)(20)=-\frac{1}{2}(32)(20)^2\\ v_0=\frac{\frac{1}{2}(32)(20)^2}{sin(30)(20)} \\ v_0=\frac{6400}{10} =640[/tex]

b) In order to find the maximum altitude, the time is needed to apply the formula. The maximum altitude is when the velocity in the y-axis is equal to zero, so use the formula for the velocity in the y-axis is to find the time, the formula is:

[tex]v_y=v_{0y}-gt\\v_y=v_0sin(\alpha)-gt\\0=(640)sin(30)-32t\\32t=(640)sin(30)\\t=\frac{(640)sin(30)}{32}=\frac{320}{32}=10[/tex]

With [tex]s=10[/tex]s use this formula for the altitude: [tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2[/tex]

[tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2\\y=H+(640)sin(30)(10)-\frac{1}{2}(32)(10)^2\\y=H+3200-1600\\y=H+1600[/tex]

Finally, the range is the maximum displacement in the x-axis, the formula of the  displacement is:

[tex]x=v_{0x}t=v_0cos(\alpha )t[/tex]

And the maximum occurs when[tex]t=20[/tex]s

[tex]x=v_0cos(\alpha)t\\x=640cos(30)(20)\\x=11085.13[/tex]

Polarized light vibrates in one plane while unpolarized light vibrates in multiple, random directions. Unpolarized light can become polarized by passing through polarizing materials or by reflecting off surfaces, predominantly leaving horizontally polarized light.

The difference between polarized and unpolarized light lies in the orientation of the light waves' vibrations. Unpolarized light, such as sunlight or light from an ordinary bulb, consists of waves that vibrate in multiple directions perpendicular to the direction of the light's travel. This means the electric field vectors are randomly oriented. When we pass this unpolarized light through a polarizing material like Polaroid sheets, the light is filtered so that it vibrates in only one plane; it becomes polarized.

Furthermore, the process of reflecting light off a surface can also lead to polarization. When unpolarized light reflects, there is a selective filtering effect whereby the vertically polarized light components tend to be absorbed or refracted, and the horizontally polarized components are more likely to be reflected. This is similar to the way arrows that hit a surface on their side tend to bounce off, whereas those hitting tip-first are more likely to stick.

The intensity of polarized light can be calculated with the equation I = Io cos² θ, where I is the intensity of the polarized light, Io is the incident intensity, and θ is the angle between the polarization direction and the axis of the filter.

Answer:

No, the net force on the skydiver is zero

Explanation:

According to Newton's Second Law, the net force on an object is equal to the product between the mass of the object and its acceleration:

[tex]F=ma[/tex]

where

F is the net force

m is the mass of the object

a is the acceleration

In this problem, the acceleration of the skydiver is zero:

a = 0

This implies that also the net force on the skydiver is zero, according to the previous equation:

F = 0

So, the net force on the skydiver is zero. This occurs because the air resistance, which points upward, exactly balances the force of gravity on the skydiver, acting downwards.

Answer:3.884

2.136

2.563

Explanation:

Given

[tex]Length\ of\ simple\ pendulum\left ( L\right )=0.65m[/tex]

[tex]mass\ of\ the\ bob\left ( m\right )=0.34 kg[/tex]

angle of deflection =[tex]9.4^{\circ}[/tex]

[tex]\left ( a\right )[/tex]

[tex]Angular frequency\left ( \omega \right )[/tex]

[tex]\omega =\sqrt{\frac{g}{L}}=3.884 rad/s[/tex]

[tex]\left ( b\right )[/tex]

[tex]Total\ mechanical\ energy\ of\ the\ bob =mgh\left ( at highest point\right )[/tex]

[tex]M.E.=mgL\left ( 1-cos\theta \right )=0.34\times 9.8\times \0.65\left ( 1-cos\left ( 9.4\right )\right )[/tex]

M.E.=2.136 J

[tex]\left ( c\right )[/tex]

Bob's velocity at lowest point

Equating top most point energy =Bottom point energy

[tex]mgh=\frac{1}{2}mv^2[/tex]

[tex]v^2=2.563 m/s[/tex]

The angular frequency of the pendulum's motion is approximately 3.87 rad/sec. The total mechanical energy of the pendulum is approximately 0.034 J. The speed of the pendulum bob at the lowest point of its swing is approximately 0.83 m/s.

The subject in question pertains to the physics of simple harmonic motion as exhibited by a simple pendulum. Given the length of the pendulum (L = 0.65 m), the mass of the pendulum bob (m = 0.34 kg), and the initial displacement angle (9.4°), we are to find: (a) the angular frequency, (b) the total mechanical energy, and (c) the speed at the lowest point of the swing.

(a) The angular frequency (ω) of the pendulum's motion can be calculated using the formula ω = sqrt(g/L), where g is the acceleration due to gravity (9.8 m/s²). Substituting the given values, we get ω ≈ 3.87 rad/sec.

(b) The total mechanical energy (E) of the pendulum is given by E = mgh, where h = L(1 - cosθ). Substituting the given values, we get E ≈ 0.034 J.

(c) The speed (v) of the pendulum bob at the lowest point of the swing can be calculated using the concept of energy conservation. As the pendulum is initially released from rest and assuming no dissipation, the total mechanical energy at any point is the same. Thus, the bob's speed at the lowest point is given by v = sqrt(2*g*h), yielding v ≈ 0.83 m/s.

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Faraday's Law states that the magnitude of the emf induced in a coil is directly proportional to the rate of change of magnetic flux through it. Hence, a large magnetic flux change would induce a greater emf compared to a small flux change. This process of induction is foundational to many operational principles of electrical and electronic devices.

The concept asked in the question revolves around Faraday’s Law in Physics. According to Faraday’s Law, an electromotive force (emf) is induced in a coil when there is a change in magnetic flux through the coil. The magnitude of the induced emf is directly proportional to the rate of change of magnetic flux. Therefore, a large change in magnetic flux through a coil would induce a greater emf as compared to a small flux change.

So, if you were to suddenly increase the magnetic field strength (B) passing through a coil, this would represent a large change in magnetic flux (Ø), which as per Faraday's law, would induce a greater emf. Conversely, a slower or smaller change in magnetic field strength would lead to a smaller emf.

The process whereby a change in magnetic flux induces an emf is called electromagnetic induction. Remember, not only the magnitude of the magnetic field but also the orientation of the magnetic field (angle θ referenced in BA cos θ) with respect to the coil can affect the emf. Magnetic flux, Ø is given by BA cos θ, where B is the magnetic field strength, A is the area through which field passes and θ is the angle between B and A.

In application, a tangible example of this is the working of electric generators where a coil is rotated in a static magnetic field. The rotation changes the magnetic flux through the coil, hence inducing an emf according to Faraday’s Law. Induced emf is the fundamental principle behind the workings of many electrical and electronic devices we use in daily life.

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Explanation:

To start a fire it is more optimal to use a concave mirror than a plane mirror. This is because the concave mirror allows concentrating sunlight at a point (the focal point) on an object that acts as fuel and ignite the fire there.

For this it is necessary the object to be  positioned between the center of curvature of the mirror and the mirror (its focus). Thus the rays of the Sun, when converging on the focus, will heat the object and make it burn.

Hence, the correct option is B.

A concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature, is optimal for starting a fire using sunlight. This is due to the mirror's ability to concentrate parallel sunlight at a specific point.

The most accurate statement for starting a fire using sunlight and a mirror would be B) It would be best to use a concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature. This is due to the properties of concave mirrors in focusing parallel beams of light, such as sunlight, to a single point. These mirrors can concentrate light at a specific point, effectively increasing the light's intensity and, hence, its heat. This is similar to how a magnifying glass can focus sunlight enough to ignite paper.

The statement C) is incorrect because positioning an object at the center of curvature would spread the light across the object, rather than concentrating it at a point. Convex mirrors (D), on the other hand, would focus light away from the object, making them unsuitable. The statement E) is untrue, as mirrors certainly can form real images and concentrate light to the point of starting a fire. The primary consideration here is the shape of the mirror and the positioning of the object to be ignited relative to the mirror's focal point.

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