2 times the difference between 49.6 and 37.5

The system of linear inequalities that are graphed are {y≥3x−2  and x+2y≤4

In order to get the required system of inequalities, we need to get the equations of both lines.

For the line with having the coordinate points (0, 2) and (4, 0)

The standard form of the expression will be y = mx+b

m = 0-2/4-0

m = -2/4

m = -1/2

The y-intercept "b" is 2 (the point where the line cuts the y-axis)

The equation of the line will be y = -1/2x + 2

2y = -x + 4

x + 2y = 4

Since the line is a solid line and shaded towards the negative side of the graph, the given inequality expression will be x+2y ≤ 4

For the line with having the coordinate points (0, -2) and (2, 4)

The standard form of the expression will be y = mx+b

m = 4+2/2-0

m = 6/2

m = 3

The y-intercept "b" is -2 (the point where the line cuts the y-axis)

The equation of the line will be y = 3x-2

Since the line is a solid line and shaded towards the positive side of the graph, the given inequality expression will be y≥3x−2

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Answer:

It's false, only if the situation gets worse.

Step-by-step explanation:

On the off chance that a debate over a contract emerges and casual endeavors at determination fall flat, the foremost common next step may be a claim. On the off chance that the sum at issue is underneath a certain dollar figure (ordinarily $3,000 to $7,500 depending on the state), the parties may be able to resolve the issue in small claims court.

Please correct any mistakes in my answer :) Glad to help ya!

Answer:

A) x²/25 + y²/9 = 1

Step-by-step explanation:

The major axis length is the sum of distances to the foci from the ellipse, 10. So the semi-major axis has length 10/2 = 5. The foci are on the x-axis, so the ellipse is oriented horizontally.

The semi-minor axis is the other leg of the right triangle having the focus and center as one leg, and the semi-major axis as the hypotenuse. This is obviously a 3-4-5 triangle, so the semi-minor axis length is 3.

When the ellipse is horizontal, the formula for it is ...

... (x/(semi-major axis))² + (y/(semi-minor axis))² = 1

... (x/5)² + (y/3)² = 1

... x²/25 + y²/9 = 1

0.4 feet per second is the answer.

the first few bars are the people who walked fewer than 4,000, so add up the numbers on the side (2 and 5) and you get 7, so a

7 people have averaged fewer than 4,000 steps.

Option A is the correct answer.

Given,

The bar graph of the number of steps on the horizontal line and the number of people on the vertical line.

We need to find how many people averaged fewer than 4,000 steps each day.

Read the bar graph.

Steps - 0 - 1,999

= 2 people

Steps - 2,000 - 3,999

= 5 people

Steps - 4,000 - 5,999

= 12 people

Steps - 6,000 - 7,999

= 7 people

Steps - 8,000 - 9,999

= 3 people

Find the number of people who have fewer than 4,000 steps.

We have,

Steps - 0 - 1,999

= 2 people

Steps - 2,000 - 3,999

= 5 people

So,

2 + 5 = 7

= 7 people

Thus 7 people have averaged fewer than 4,000 steps.

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Answer: Two consecutive square numbers be 16 and 9.

Step-by-step explanation:

Let first consecutive square number be x²

Let second consecutive square number be (x+1)²

According to question,

[tex]x^2\times (x+1)^2=144[/tex]

Now we'll do this by factorisation,

[tex]144=2\times2\times2\times2\times3\times3\\\\144=16\times 9[/tex]

So, two consecutive square numbers are 16 and 9

Consecutive numbers are numbers that follow one another.

The consecutive squares are: 9 and 16

Let the bigger square be x^2

So, we have:

[tex]\mathbf{(x - 1)^2 \times x^2 = 144}[/tex]

Express 144 as 12^2

[tex]\mathbf{(x - 1)^2 \times x^2 = 12^2}[/tex]

Take square roots of both sides

[tex]\mathbf{(x - 1)\times x = 12}[/tex]

Expand

[tex]\mathbf{x^2 - x = 12}[/tex]

Rewrite as:

[tex]\mathbf{x^2 - x - 12 = 0}[/tex]

Expand

[tex]\mathbf{x^2 - 4x +3x- 12 = 0}[/tex]

Factorize

[tex]\mathbf{x(x - 4) +3(x- 4) = 0}[/tex]

Factor out x - 4

[tex]\mathbf{(x +3) (x- 4) = 0}[/tex]

Solve for x

x= -3 or x = 4

x cannot be negative.

So: x = 4

Square both sides

[tex]\mathbf{x^2 = 4^2}[/tex]

[tex]\mathbf{x^2 = 16}[/tex]

Calculate the smaller square

[tex]\mathbf{(x - 1)^2 = (4-1)^2}[/tex]

[tex]\mathbf{(x - 1)^2 = 9}[/tex]

Hence, the consecutive squares are: 9 and 16

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3(3x - 8) + 4x = -2(12 - 7x) - x

9x - 24 + 4x = -24 + 14x - x    distributed 3 on the left and -2 on the right

   - 24 + 13x = -24 + 13x        added like terms on the left and the right

            -13x            -13x

   -24          =   -24

           TRUE

A true statement means infinitely many solutions (aka All Real Numbers)

Answer: C

$0.07. use the formula provided and just substitute.

Cost per gallon= Price per gallon/miles per gallon.

cost=$2.56/35

That led to 0.0731428571 and the nearest cent would be $0.07

Let's have time in minutes as x.

Now we will make the next equation

3x+126 = 2x+151  First we will add number (-126) to the both sides and get

3x+126-126=2x+151-126 => 3x= 2x + 25

3x=2x+25 Now we will add monom (-2x) to the both sides and get

3x-2x=2x-2x+25 => x=25 minutes

They spent the same time 25 minutes and earned the same amount of money

Wilson earned  3*25+126= 75+126= $201

Jonathan earned 2*25+151=50+151= $201

Good luck!!!

-58.82% is the percent increase

Answer:

200 CD's.

Step-by-step explanation:

Jake recorded a special album in honor of mother's day. His mom was so excited that she purchased 40% of the copies in the store.

we have tell the total number of CD's in the store.

Let total number of CD's available in the store was = A

Then 40% of the total numbers of CD's = A×40% = 0.04 A

Since 0.04A = 80

A = 80/0.04 = 200

Therefore there were 200 CD's in the store for the sale.

the value of x for which L is parallel to M :28 done

Answer:

B.y=−3x−1

Step-by-step explanation:

given that the line is parallel to y = -3x+4

Hence required line will be of the form

y =-3x+k for some k.

(Reason: slopes will be equal for parallel lines)

Since the line passes through (-2,5)

Substitute x =-2 and y =5 in the equation.

5=-3(-2)+k

Simplify

5 = 6+k

Subtract 6

Or k =-1

Hence required line has equation y =-3x-1

Answer: the first choice, |x − 18.25| > 0.36; x < 17.89 or x > 18.61

Explanation:

1. Target weight: 18.25 oz

2. Variability accepted: 0.36 oz

3. Range of accepted masses: 18.25 oz - 0.36 oz ≤ x ≤ 18.25 oz + 0.36 oz

4. Addition property of the inequalities (subtract 18.25 oz to the three parts of the inequality):

- 0.36 oz ≤ x - 18.25 oz ≤ 0.36 oz

5. Definition of absolute value inequality: | x - a | ≤ c equals - c ≤ x - a ≤ c

   ∴ - 0.36 ≤ x - 18.25 ≤ 0.36  equals | x - 18.25 | ≤ 0.36, which is the range of accepted masses.

6. The range of rejected masses is the complement, so it is:

          |x - 18.25 | > 0.36

7. Solve the inequality to find the range of rejected masses:

    a) x - 18.25 > 0.36 ⇒ x > 18.25 + 0.36 ⇒ x > 18.61

    b) x - 18.25 < 0.36 ⇒ x < 18.25 - 0.36 ⇒ x < 17.89

The function represented by the graph is (b) the reciprocal, y = 1/x

From the question, we have the following parameters that can be used in our computation:

The graph

From the graph, we can see that

The function has horizontal and vertical asymptotes

Only rational functions have this property

This means that the function represented by the graph is (b) the reciprocal, y = 1/x

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[tex]ax^2+bx+c=0\\\\\text{From quadratic formula the roots are equal:}\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\ \text{and}\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\text{We have}\ 2x^2+7x-15=0\\\\a=2,\ b=7,\ c=-15\\\\\text{and}\ r,\ s\ \text{are two solution}\\\\\sqrt{b^2-4ac}=\sqrt{7^2-4(2)(-15)}=\sqrt{49+120}=\sqrt{169}=13\\\\x_1=\dfrac{-7-13}{2(2)}=\dfrac{-20}{4}=-5\\\\x_2=\dfrac{-7+13}{2(2)}=\dfrac{6}{4}=\dfrac{3}{2}\\\\\dfrac{3}{2}>-5\ \text{therefore}\ r=\dfrac{3}{2}\ \text{and}\ s=-5.[/tex]

[tex]r-s=\dfrac{3}{2}-(-5)}=\dfrac{3}{2}+5=\dfrac{3}{2}+\dfrac{10}{2}=\dfrac{13}{2}\\\\Answer:\ \boxed{B)\ \dfrac{13}{2}}[/tex]

Josh would be 15 years old

He would be 12 years old on 1 September, 2015.

The requried simplified value of the given function at x = 1/2 is 5/8.

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

here,
Given function f(x) = -3/4x + 1
For f(1/2), put x = 1/2 in the above expression,

f(1/2) = -3/4(1/2) + 1
f(1/2) = -3/8 + 1
f(1/2) = [-3 + 1×8]/8
f(1/2) = [5]/8
f(1/2) = 5/8

Thus, the requried simplified value of the given function at x = 1/2 is 5/8.

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Final answer:

We solved the algebraic equation to find that the solution is x = -10. Each step involved distributing, combining like terms, and isolating the variable.

Explanation:

Let's solve the algebraic equation step-by-step:

The solution to the equation is x = -10, which you can verify by plugging it back into the original equation.

Answer:

A) 30 cubes.

B) 30 units³.

Step-by-step explanation:

A) 1. Calculate the volume of the rectangular prism, as following:

[tex]Vr=(lenght)(width)(height)[/tex]

2. You have that:

- The length is: [tex]1^{\frac{1}{2}}ft=1.5ft[/tex]

- The width is: [tex]1ft[/tex]

- The heigth is: [tex]2^{\frac{1}{2}}ft=2.5ft[/tex]

3. Substitute these values into the formula:

[tex]Vr=(1.5ft)(1ft)(2.5ft)=3.75ft^{3}[/tex]

4. The volume of one cube is:

[tex]Vc=side^{3}[/tex]

5. The length of one side is: [tex]\frac{1}{2}ft=0.5ft[/tex]

6. Substitute this value into the formula:

[tex]Vc=(0.5ft)^{3}=0.125ft^{3}[/tex]

7. The number of small cubes that can be packed in the rectangular prism is:

[tex]cubes=\frac{Vr}{Vc}\\cubes=\frac{3.75ft^{3}}{0.125ft^{3}}\\cubes=30[/tex]

B) 1. The length, the width and the height of the rectangular prism in term of units cubes is:

[tex]Length=\frac{1.5ft}{0.5ft}=3units[/tex]

[tex]Width=\frac{1ft}{0.5ft}=2units[/tex]

[tex]Heigth=\frac{2.5ft}{0.5ft}=5units[/tex]

2. Therefore, the volume of the rectagular prism in terms of the small cube and a unit cube is:

[tex]Vr=(3units)(2units)(5units)=30units^{3}[/tex]

Answer:

30 cubes.

Step-by-step explanation:

The ball hits the ground at unknown time (t) when the height (h) = 0

h(t) = -16t² + vt + h    ⇒ v = 64, h = 0, h(t) = 0, find t

 0  = -16t² + 64t

 0  = -16t(t - 4)

0 = -16t       or    0 = t - 4

  t = 0         or        t = 4

It starts at t = 0 seconds and ends at t = 4 seconds

Answer: B

Final answer:

Using the kinematic equation for vertical motion, we find that the golf ball will hit the ground after 4 seconds. We factor the kinematic equation to solve for the time given initial velocity and gravity's acceleration, ignoring the 0 time solution. TΔherefore, the correct option is b.

Explanation:

The question asks after how many seconds a golf ball hit from ground level with an initial vertical velocity of 64 ft/s will hit the ground. This problem involves kinematic equations of motion under the influence of gravity. We can use the equation for vertical motion: distance = initial velocity × time + 0.5 × acceleration × time². Since the ball returns to ground level, the distance covered is 0. Taking downward as positive, gravity's acceleration is +32 ft/s² (the usual acceleration due to gravity in units of ft/s²). We can rearrange the equation to solve for time (t): 0 = 64t + 0.5 × 32t². Factoring out t gives us t(64 + 16t) = 0, and solving for t gives us t = 0 or t = -64/16 = -4 seconds. Since time cannot be negative in this context, the positive solution reflects the time after launch, thus the answer is 4 seconds, which is option b.

we are given two system of equations

First equation is

[tex]y=2x-1[/tex]

we can write as

[tex]-2x+y=-1[/tex]

Second equation is

[tex]6x-y=13[/tex]

now, we can find augmented matrix

[tex]A=\begin{pmatrix}-2&1&-1\\ 6&-1&13\end{pmatrix}[/tex]

now, we can change it into reduced row echelon form

step-1: multiply the 1st row by -1/2

[tex]A=\begin{pmatrix}-1&-1/2&1/2\\ 6&-1&13\end{pmatrix}[/tex]

step-2: add -6 times the 1st row to the 2nd row

[tex]A=\begin{pmatrix}-1&-1/2&1/2\\ 0&2&10\end{pmatrix}[/tex]

step-3:multiply the 2nd row by 1/2

[tex]A=\begin{pmatrix}-1&-1/2&1/2\\ 0&1&5\end{pmatrix}[/tex]

step-4:add 1/2 times the 2nd row to the 1st row

[tex]A=\begin{pmatrix}1&0&3\\ 0&1&5\end{pmatrix}[/tex]

so, we will get

[tex]x=3,y=5[/tex]

Answer is (3,5)

Replace x and Y in the answers and see which one works:

A) 4(4) -3 = 16-3 = 13, not -3 FALSE.

B) 1/2(4) - 5 = 2-5 = -3 TRUE

The correct answer is B

Answer:

When P and Q are equal there is no solution exist.

For example - (0,0) , (1,1)  

Step-by-step explanation:

Given : Equation [tex]Px+40=Qx+20[/tex]

To find : Which values of P and Q result in an equation with no solutions?

Solution :

In the given equation [tex]Px+40=Qx+20[/tex]        

P, Q, x are variable.

We have to find the values at which the equation has no solutions.  

[tex]Px+40=Qx+20[/tex]

[tex]Px+20=Qx[/tex]

[tex]20=Qx-Px[/tex]

[tex]20=x(Q-P)[/tex]

If Q=P then (Q-P)x = 0 for all x

Thus the original equation has no solutions.

For example,

Put x=1 and Q=1

[tex]x+40=x+20[/tex]

[tex]40\neq 20[/tex]

There is no solution.

Answer: red = 10, orange = 20

Step-by-step explanation:

Let R represent the # of red skittles and G represent the # of orange skittles

there are 10 less red skittles than orange skittles: R = G - 10

orange skittles are twice the red skittles: G = 2R

Use substitution to solve the system:

 R = (2R) - 10

-R   -R        

0  = R - 10

+10     +10

10 = R

G = 2R   = 2(10)   = 20

Answer:30

Step-by-step explanation:

20+10=30