200.0 mL OF A 5.10 M solution are diluted to 500.0 mL. What is the concentration of the resulting solution? *

Answer:

Carbonates, Carbides, Carbon oxides

Explanation: Its the answer I promise!!

Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Answer:

the wet bulb will get warmer because their will be a smaller difference between the the dry/wet bulb temps.

Explanation:

At any given ambient temperature, less relative humidity results in a greater difference between the dry-bulb and wet-bulb temperatures; the wet-bulb is colder.

For your problem, this is opposite, therefore it will get warmer.

Answer: N/A

Explanation: You have to write down the equation otherwise we are unable to help you.

Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles[/tex]

The balanced chemical reaction will be,

[tex]C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2[/tex]

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce =  [tex]\frac{2}{1}\times 0.54=1.08[/tex] mole of ethanol

Now we have to calculate the mass of ethanol produced

[tex]\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}[/tex]

[tex]\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g[/tex]

Now we have to calculate the percent yield of ethanol

[tex]\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%[/tex]

Therefore, the percent yield is 47.0 %

Final answer:

The theoretical yield of ethanol from the fermentation of 97.5 g of glucose is 49.3 g. The percent yield is 47.4% if the actual yield of ethanol is 23.4 g.

Explanation:

To determine the theoretical yield of ethanol, we need to calculate the molar ratio between glucose and ethanol. According to the balanced equation, for every mole of glucose, two moles of ethanol are produced. Therefore, we can set up a proportion and solve for the theoretical yield:

(97.5 g glucose / 180.15 g/mol) x (2 mol ethanol / 1 mol glucose) x (46.08 g/mol) = 49.3 g ethanol

For the percent yield, we can divide the actual yield (23.4 g) by the theoretical yield (49.3 g) and multiply by 100:

(23.4 g / 49.3 g) x 100 = 47.4%

Answer:

Budding- A new organism growing from the body of the parent

Fragmentation- The parent breaks into parts that may regenerate into offspring

Binary Fission- The parent cell divides to produce a genetically identical cell

Answer: A new organism growing from the body of the parent

Fragmentation- The parent breaks into parts that may regenerate into offspring

Binary Fission- The parent cell divides to produce a genetically identical cell

Answer:

D) 0.001 M AlCl3

Explanation:

The solution with the lowest freezing point would be 0.001 M AlCl3 because it produces the most particles when fully ionized in water, therefore lowering the freezing point the most.

Theoretically, the aqueous solution that will have the lowest freezing point is D) 0.001 M AlCl3. This is based on the principle of colligative properties, which states that the freezing point of a solution is lowered when solutes are added. The extent of this lowering depends on the number of solute particles present. In this case, AlCl3, when fully ionized in water, produces 4 particles (1 Al3+ and 3 Cl-), contributing to the greatest decrease in freezing point.

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Answer:

3.4g of Al

Explanation:

you would need to start with 3.4 g of Al

Answer:

Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.

Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.

In thermodynamics, heat is defined as the form of energy crossing the boundary of a thermodynamic system by virtue of a temperature difference across the boundary.[1] A thermodynamic system does not contain heat. Nevertheless, the term is also often used to refer to the thermal energy contained in a system as a component of its internal energy and that is reflected in the temperature of the system. For both uses of the term, heat is a form of energy.

Another example of informal usage is the term heat content, used despite the fact that physics defines heat as energy transfer. More accurately, it is thermal energy that is contained in the system or body, as it is stored in the microscopic degrees of freedom of the modes of vibration.

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Final answer:

Ling's scientific prediction was most likely that a person's heart rate slows down to normal in three minutes after exercise, as this directly pertains to the expected outcome of her science project. Option C is correct.

Explanation:

The scientific prediction that Ling likely made about her project is related to the time it will take for a person's heart rate to return to normal after exercise. Based on the options provided, the most relevant prediction is C. A person's heart rate slows down in three minutes. This is because it refers directly to the expected outcome of the experiment regarding heart rate recovery time, while the other options are either base rate information or observations that don't predict the outcome of the experiment.

Answer:

1.16x10^–3 mole

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.

Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,

Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e

Xmol of MgBr2 = 6.99x10^20/6.02x10^23

Xmol of MgBr2 = 1.16x10^–3 mole

Answer : [tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.

Explanation :

As we know that when strontium hydroxide, [tex]Sn(OH)_2[/tex] dissociates then it gives strontium ion, [tex]Sr^{2+}[/tex] and hydroxide ion, [tex]OH^-[/tex].

The dissociation reaction will be:

[tex]Sr(OH)_2\rightarrow Sr^{2+}+2OH^-[/tex]

[tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.

Strontium hydroxide, Sr(OH)2, dissociates into one Sr2+ ion and two OH- ions when it dissolves in water.

When Sr(OH)2 (strontium hydroxide) dissociates in water, it separates into ions with specific charges. The chemical equation representing this dissociation is:

Sr(OH)₂ → Sr²⁺ (aq) + 2OH⁻(aq)

This means that one molecule of strontium hydroxide will produce one Sr²⁺ ion and two OH⁻ ions. The Sr²⁺ ion has a plus two charge and each of the OH⁻ ions has a negative one charge.

Answer:

It is given that number of electrons is 11.

It is known that when an atom is neutral then the number of protons equals number of electrons. Also, atomic number means number of protons an atom holds.

Whereas mass number equals number of protons + number of neutrons. Thus, mass number of given atom is 11 + 13 = 24.

The symbol for this element will be as follows 24/11x  . This atom sodium has atomic number 11 and mass number 24.

Therefore, symbol of this radioactive nuclide is as follows . A)Superscript 24 subscript 11 upper N a.

Answer:

Answer Is A

Explanation:

24/11 NA: This answer was correct

Answer:

C

Explanation:

A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.

Density is the degree of how closely the mass of matter is compacted. The more compacted the mass is in relation to the amount of volume the matter occupies, the higher its density will be. Conversely, matter that has a low density, has a smaller ratio of mass per amount of volume the matter occupies.

To determine the density of a solid that has regular side lengths, it is first needed to calculate the volume of the solid using the equation volume = length x width x height.

The density of a material depends on the molecular packing.

Therefore, A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.

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Final answer:

Untreated sewage dumped into a river causes significant harm to aquatic life, leading to sickness and fatalities among animals, degradation of water quality, and the creation of dead zones. These pollutants also pose a risk to human health as they can travel up the food chain.

Explanation:

The effect of untreated sewage being dumped into a river on the animals living therein is typically devastating. The correct answer to the question, 'What effect has the raw sewage had on the animals that live in the river?' is C) Many animals have become sick or have been found dead.

Water pollution from untreated sewage includes harmful bacteria and chemicals that can cause disease and death in river ecosystems. Pollutants like nitrogen and phosphorus can lead to eutrophication, which depletes the oxygen in the water, creating dead zones where fish and other aquatic life cannot survive. Additionally, contaminated water can carry diseases and toxins up the food chain, posing health risks to animals and humans alike.

Industrial waste and agricultural runoff also contribute to the degradation of water quality, affecting not only the immediate area but also environments downstream. This contamination has a cascading effect on ecosystems, harming countless plants, animals, and humans who depend on these water sources.

Answer:

H2SO4 ( sulfuric acid )

Explanation:

An acid is a substance that releases hydrogen ions in solution. Strong acids like hydrochloric acid ionize completely and are highly likely to participate in chemical reactions, whereas weak acids, like acetic acid, do not ionize completely. Acids are also classified based on their ability to donate protons, which also indicates their strength.

An acid is a substance that releases hydrogen ions (H*) in solution. Strong acids, like hydrochloric acid (HCl), ionize completely; releasing all of their H* and are, therefore, more likely to participate in chemical reactions. On the other hand, weak acids, such as acetic acid (vinegar), don't ionize completely meaning some of their hydrogen ions remain bonded within a compound in solution.

Here are examples of acids:

The strength of an acid is determined by how readily it donates its H*. For instance, Hydrochloric acid (HCl) is a strong acid as it completely dissociates into hydrogen and chloride ions, being highly acidic.

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Final answer:

Potassium nitrate is the most likely to be soluble among the options given because all nitrates are known to be soluble in water, while Iron carbonate and Copper oxide are typically insoluble.

Explanation:

Among the given options of salts—Potassium nitrate, Iron carbonate, and Copper oxide—the one most likely to be soluble is Potassium nitrate. This is due to the general solubility rule that all nitrates are soluble in water. Salts containing the large, singly charged NO₃⁻ ion, such as Potassium nitrate, tend to form highly soluble compounds, while carbonates (like Iron carbonate) and oxides (like Copper oxide) are often less soluble or insoluble except in the presence of certain cations like potassium, sodium, and ammonium.

Iron carbonate and Copper oxide are generally insoluble in water. For instance, iron(II) carbonate is not soluble except when combined with cations like potassium, sodium, or ammonium. Similarly, Copper oxide's solubility is very low in water. On the contrary, even though Copper sulfate is not provided as an option, it is worth mentioning that many sulfates, unlike carbonates and oxides, are generally soluble, with few exceptions.

Answer:

A. Chlorine (Cl2) is the limiting reactant.

B. 6.77g of AlCl3

Explanation:

The balanced equation for the reaction. This is given below:

2Al + 3Cl2 —> 2AlCl3

Next, we shall determine the masses of Al and Cl2 that reacted and the mass of AlCl3 produced from the balanced equation. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al from the balanced equation = 2 x 27 = 54g

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 from the balanced equation = 3 x 71 = 213g

Molar Mass of AlCl3 = 27 + (3x35.5) = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g

Thus, from the balanced equation above,

54g of Al reacted with 213g of Cl2 to produced 267g of AlCl3.

A. Determination of the limiting reactant. This is illustrated below:

From the balanced equation above,

54g of Al reacted with 213g of Cl2.

Therefore, 3.2g of Al will react will react with = (3.2 x 213)/54 = 12.52g of Cl2.

We can see that it will take a higher mass of Cl2 ( i.e 12.52g) than what was given ( i.e 5.4g) to react with 3.2g of Al.

Therefore, Cl2 is the limiting reactant.

B. Determination of the mass of AlCl3 produced from the amount of the limiting reactant available.

This is illustrated below:

The limiting reactant is Cl2 with a mass of 5.4g

From the balanced equation above, 213g of Cl2 reacted to produced 267g of AlCl3.

Therefore, 5.4g of Cl2 will react to produce = (5.4 x 267)/213 = 6.77g of AlCl3.

Therefore, 6.77g of AlCl3 is produced from the amount of the limiting reactant available.

The correct answer is that chloride is the limiting reactant and 13.25 grams of aluminium chloride can be produced from the amount of limiting reactant available.

To determine the limiting reactant and the amount of aluminium chloride that can be produced, we need to use stoichiometry. The balanced chemical equation for the reaction between aluminium (Al) and chloride (Cl) to form aluminium chloride (AlCl3) is:

[tex]\[ 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3 \][/tex]

First, we need to calculate the moles of Al and Cl2 available:

- For aluminium (Al):

[tex]\[ \text{Moles of Al} = \frac{\text{Mass of Al}}{\text{Molar mass of Al}} = \frac{3.2 \text{ g}}{26.98 \text{ g/mol}} \approx 0.12 \text{ mol} \][/tex]

- For chloride (Cl2):

[tex]\[ \text{Moles of Cl}_2 = \frac{\text{Mass of Cl}_2}{\text{Molar mass of Cl}_2} = \frac{5.4 \text{ g}}{35.45 \text{ g/mol}} \approx 0.15 \text{ mol} \][/tex]

Next, we use the stoichiometry of the balanced equation to determine which reactant is limiting:

- The ratio of the moles of Cl2 to Al required by the balanced equation is 3:2.

- For the given moles of Al (0.12 mol), the required moles of Cl2 would be:

[tex]\[ \text{Required moles of Cl}_2 = \frac{3}{2} \times 0.12 \text{ mol} = 0.18 \text{ mol} \][/tex]

Since we only have 0.15 mol of Cl2, chloride is the limiting reactant.

Now, we calculate the amount of AlCl3 that can be produced from the limiting reactant (Cl2):

- From the balanced equation, 3 moles of Cl2 produce 2 moles of AlCl3.

- Therefore, 0.15 moles of Cl2 will produce:

[tex]\[ \text{Moles of AlCl}_3 = \frac{2}{3} \times 0.15 \text{ mol} = 0.1 \text{ mol} \][/tex]

- The molar mass of AlCl3 is:

[tex]\[ \text{Molar mass of AlCl}_3 = 26.98 \text{ g/mol (Al)} + 3 \times 35.45 \text{ g/mol (Cl)} \approx 133.23 \text{ g/mol} \][/tex]

- Finally, the mass of AlCl3 produced is:

[tex]\[ \text{Mass of AlCl}_3 = \text{Moles of AlCl}_3 \times \text{Molar mass of AlCl}_3 \][/tex]

[tex]\[ \text{Mass of AlCl}_3 = 0.1 \text{ mol} \times 133.23 \text{ g/mol} \approx 13.323 \text{ g} \][/tex]

Rounding to the appropriate number of significant figures, we get approximately 13.25 grams of aluminium chloride.

Answer:

where in the book is it

Explanation:

Answer:

The correct answer is 8,026 x 10³ kPa

Explanation:

We have gaseous CO₂ at the following conditions:

mass = 94.60 g

T= 57.00ºC = 330 K

V= 0.7500 L

We can use the ideal gas equation to calculate the pressure (P):

P x V = n x R x T

⇒ P = (n x R x T)/V

We need n, which is the number of moles of the gas. In order to calculate this, we have to calculate first the molecular weight (MM) of CO₂ as follows:

MM(CO₂)= Molar mass C + (2 x Molar mass O) = 12 g/mol + (2 x 16 g/mol) = 44 g/mol

Now, we can calculate the number of moles (n) of CO₂ from the mass and the molecular weight as follows:

n = Mass/MM = 96.60 g/44 g/mol = 2.19 moles

Now we have all the data. So, we introduce the data in the previos equation and calculate the pressure P:

P = (n x R x T)/V = (2.19 mol x 0.082 L.atm/K.mol x 330 K)/0.7500 L = 79.0152 atm

Finally, we have to convert the pressure from atm to kPa. For this, we know that 1 atm = 1,01325 x 10⁵ Pa and 1 kPa= 1000 Pa.

79.0152 atm x 1,01325 x 10⁵ Pa/atm x 1 kPa/1000 Pa = 8,026 x 10³ kPa

Answer:

7859.98 KPa

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of CO2 = 94.60g

Temperature (T) = 57℃

Volume (V) = 0.75 L

Pressure (P) =?

Step 2:

Determination of the number of mole of CO2.

Mass of CO2 = 94.60g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 94.60/44

Number of mole of CO2 = 2.15 moles

Step 3:

Conversion of celsius temperature to Kelvin temperature.

Temperature (Kelvin) = temperature (celsius) + 273

Temperature = 57℃ + 273 = 330K

Step 4:

Determination of the pressure. This is illustrated below:

The pressure can be obtained by using the ideal gas equation as shown below:

PV = nRT

Temperature (T) = 330K

Volume (V) = 0.75 L

Number of mole (n) = 2.15 moles

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =?

PV = nRT

0.75 x P = 2.15 x 0.082 x 330

Divide both side by 0.75

P = (2.15 x 0.082 x 330)/0.75

P = 77.572 atm

Step 5:

Conversion of the pressure in atm to KPa. This is illustrated below:

1 atm = 101.325 KPa

Therefore, 77.572 atm = 77.572x101.325 = 7859.98 KPa

Answer:

The gas will occupy a volume of 4000L

Explanation:

V1 = 2000L

T1 = 100K

P1 = 100kPa = 100*10³Pa

T2 = 400k

P2 = 200kPa = 200*10³kPa

V2 = ?

To solve this question, we need to use combined gas equation

[(P₁ * V₁) / T₁] = [(P₂ * V₂) / T₂]

V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)

V₂ = (100*10³ * 2000 * 400) / (200*10³ * 100)

V₂ = 8.0*10¹⁰ / 2.0*10⁷

V₂ = 4000L

The new volume of the gas is 4000L

Answer:

The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa is 4000. L

Explanation:

Here we are required to utilize the combined gas equation as follows;

[tex]\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}[/tex]

Where:

P₁ = Initial pressure of the gas = 100.0 kPa

V₁ =  Initial volume of the gas = 2000. L

T₁ =  Initial temperature of the gas = 100.0 K

P₂ = Final pressure of the gas = 200.0 kPa

V₂ =  Final volume of the gas = Required

T₂ =  Final temperature of the gas = 400.0 K

Making V₂ the formula subject of the combined gas equation, we have;

[tex]V_{2}}{} = \frac{P_{1}\times V_{1}\times T_{2} }{T_{1}\times P_{2}}[/tex]

Therefore, by plugging the values, we have;

[tex]V_{2}}{} = \frac{100.0\times 2000\times 400.0 }{100.0 \times 200.0 } = 4000. \, L[/tex]

The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa = 4000. L.

The step which best describes asexual rather than sexual reproduction is that "in some organisms, a piece of the parent may bud off to produce offspring." Thus, the correct option for this question is C.

Asexual reproduction may be defined as a mode of reproduction in which a new offspring is significantly produced or constructed by a single parent itself. This mode of reproduction does not involve the fusion of gametes or a change in the number of chromosomes.

The new individuals produced through asexual reproduction are genetically and physically identical to each other along with their parents, i.e., they are the clones of their parents. This type of reproduction is mediated via mitosis.

Therefore, the correct option for this question is C.

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Answer:

.875

Explanation:

Use Boyle's Law and rearrange formula.

- Hope this helps! Please let me know if you need further explanation.

When it comes to nanoparticles, their size is what gives them their special properties. For example, silver nanoparticles have longer-lasting antibacterial properties than bigger particles of silver. Nanoparticles can be made of many different substances.

The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.

Colloidal silver is also called normal silver which is a suspension of silver particles in liquid. The size of colloidal silver particle is higher than 100 nm. Colloidal silver is used in dietary supplements, medication etc.

Silver nanoparticles are the nanoparticles of silver the size of these nanoparticles lies between 1nm and 100 nm. Silver nanoparticles are used in medial field, industrial purpose , health care due to their unique physical properties and unique chemical properties.

Thus from the above conclusion we can say that The size of silver nanoparticles different from normal sized silver as silver nanoparticles size lies between 1 nm and 100 nm and size of colloidal silver has higher than 100 nm.

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Answer:

A

Explanation:

N2(g) + 3H2(g) -> 2NH3(g)

According to Le Chatelier's principle, and since H2(g) is on the left side and a reactant, if it's concentration is increased, the equilibrium shifts to the right and the forward reaction is favoured, leading to the production of more NH3(g). The rate of the forward reaction increases.

As the concentration of H2(g) is increased, the concentration of the other reactant, N2(g) decreases as more of it is used up to react with the excess H2(g)

The forward reaction would increase to start reducing the concentration of N2.

Explanation:

Answer:

The symbol is 111/49 or D

Explanation:

Answer:

The Correct answer here Is D

Explanation:

The answer was 111/49 and i got It right.

Answer:

killer whale

Explanation:

Answer:

c

Explanation:

im taking the test right now

Answer:

the concentration of the Zn²⁺ (aq) ion at the cathode is 0.255 M

Explanation:

The voltage generated by the zinc electric cell that is discribed by the following relation;

[tex]Zn(s)\mid 0.1MZn^{2+(aq)}\parallel 0.2 Zn^{2+}(aq)\mid Zn(s)[/tex]

The Nernst equation is given as follows;

[tex]E = E^0 - \frac{RT}{nF} ln(\frac{a^b_B}{a^a_A} )[/tex]

[tex]E_{anode} = E^0 - \frac{0.0591}{2} logZn^{2+}[/tex]

[tex]E_{anode}-E_{cathode} =-\frac{0.0591}{2} log\frac{[Z^{2+}]}{[x]}[/tex]

[tex]0.012 =-\frac{0.0591}{2} log\frac{0.1}{[x]}[/tex]

x = 0.255 M.  

Therefore the concentration of the Zn²⁺ (aq) ion at the cathode = 0.255 M.