Mr. Smith earns 6% commission on every house he sells. If he earns 9,000, what was the price of the house?
Can anyone help ME? PLEASE HELP IF I DONT TURN THIS IN BY TOMMOROW I DONT GET TO GO TO NEW YORK AND THAT IS MY DREAM
Consider a large population with a mean of 150 and standard deviation of 27. a random sample of size 25 is taken from the population. calculate the standard error of the sampling distribution of this sample mean and round your answer to the hundredths place.
Answer:
Standard error = 5.4
Step-by-step explanation:
We are given that Population Mean, [tex]\mu[/tex] = 150 and Population Standard deviation, [tex]\sigma[/tex] = 27 and sample size, n = 25
Standard error formula for the sampling distribution of this sample mean is given by;
Standard error = [tex]\frac{\sigma}{\sqrt{n} }[/tex] = [tex]\frac{27}{\sqrt{25} }[/tex] = 5.4
in a city of 88,000 people, there are 33,000 people under 25 years of age. What percent of the population is under 25 years of age?
PLEASE HELP ME!!!!!!!! ASAP
an aquarium weighs 22.5 lb when empty the aquarium is 30 in long 14 in wide and is filled with water to a depth of 18 in. Water weighs 0.036 pounds per cubic inch. How much does the aquarium weigh when it's full of water
The weight of the aquarium when it's full of water is 294.66 pounds.
To get the weight of the aquarium we first calculate the volume of the aquarium.
[tex]Volume=(length\times width\times height)[/tex]
[tex]V=30\times 14\times18[/tex]
[tex]V=7560 \ in^3[/tex]
But weight of water is such that for every cubic inches, the weight is [tex]0.036\ lb[/tex]
thus the weight of water will be:
[tex]0.036×7560=272.16 lb[/tex]
Thus the total weight of the aquarium is:
[tex]272.16+22.5[/tex]
[tex]=294.66 \l b[/tex]
The weight of the aquarium when it's full of water is 294.66 pounds.
7 times as much as the sum of 1_3 and 1_4
What is the difference between 2386 and 7000?
The amount after 8years will be what
Domingo works 40 hours per week as a tire store manager. If he made $29,640 last year, how much was he paid per hour? A. $14.25 B. $16.50 C. $12.25 D. $11.00
By dividing Domingo's annual salary of $29,640 by the total number of hours worked in a year (2080 hours), we find that his hourly rate is $14.25.
To determine how much Domingo was paid per hour, we need to follow these steps:
Find the total number of hours Domingo worked in the year. He works 40 hours per week for 52 weeks, so the total is 40 hours/week × 52 weeks/year = 2080 hours/year.Calculate the hourly wage by dividing his total annual salary by the total number of hours worked. He made $29,640 last year, so we do the following calculation: $29,640 / 2080 hours = $14.25/hour.Therefore, Domingo was paid $14.25 per hour.
Answer: A. $14.25evaluate the following algebraic expression if a equals 3 and b equals 4 2a^+5b
Q9 Q13.) Find the products AB and BA to determine whether B is the multiplicative inverse of A.
The polygon circumscribes a circle find the perimeter of the polygon
Polygons that encircle a circle contain tangents of similar length, as such the perimeter of the polygon that circumscribes the circle is 76 cm.
The act of circumscribing a circle inside a polygon involves the process of drawing a circle that perfectly fits in the polygon by bisecting two arcs on each side of the polygon and then drawing a circle where all the sides meet in the middle of the polygon.
Polygons that encircle a circle contain tangents of similar length that originate at the same vertex, which explains the computation of the dimensions.
Taking a look at the figure attached, we have:
Two tangents with a length of 19 cmTwo tangents with a length of 9 cmTwo tangents with a length of 4 cmTwo tangents with with a length of 6 cmThus, the perimeter of the polygon can be calculated as:
= (19 + 19 + 6 + 6 + 4 + 4 + 9 + 9) cm
= 76 cm
Learn more about the perimeter of a polygon here:
https://brainly.com/question/15387363
1. WHAT DOES IT MEAN TO SOLVE A RIGHT TRIANGLE?
2. HOW CAN YOU SOLVE RIGHT TRIANGLES USING SIMILARITY? THE PYTHAGOREAN THEOREM?
3. WHAT IS THE RELATIONSHIP BETWEEN THE SIDES AND ANGLES MEASURES OF RIGHT TRIANGLES THAT
DESCRIBE TRIGONOMETRIC FUNCTIONS?
4. WHAT ARE THE INVERSE TRIGONOMETRIC FUNCTIONS? HOW ARE THE INVERSE FUNCTIONS USED WHEN
SOLVING RIGHT TRIANGLES?
5. WHAT IS THE RELATIONSHIP BETWEEN THE ANGLE OF ELEVATION AND THE ANGLE OF DEPRESSION?
GIVE AN EXAMPLE OF AN APPLICATION USING THE ANGLE OF ELEVATION OR THE ANGLE OF DEPRESSION.
0.04 × 0.61 =
Tell me how to work this out
Without doing any computation, decide which has a higher probability, assuming each sample is from a population that is normally distributed with mu equals100 and sigma equals 15. explain your reasoning. (a) p(90less than or equals x overbarless than or equals110) for a random sample of size nequals 10 (b) p(90less than or equals x overbarless than or equals110) for a random sample of size nequals 20
A Japanese garden has a circular koi pond in the middle that has a radius of 3 feet. What is the area of the Japanese garden around the koi pond? Use 3.14 for pi. 195.74 ft2 224.00 ft2 252.26 ft2 337.04 ft2
Answer: [tex]195.74\ ft^2[/tex]
Step-by-step explanation:
From the given picture, the length of the garden = 16 ft
The width of the garden = 14 ft
Now, the area of the whole garden is given by :-
[tex]\text{Area of whole garden}=length\times width\\\\\Rightarrow\text{Area of whole garden}=16\times14=224\ ft^2[/tex]
Also, the radius of the circular pond (r)= 3 ft
The area of the circular pond is given by :-
[tex]\text{Area of pond}=\pi r^2\\\\\Rightarrow\text{Area of pond}=(3.14)(3)^2\\\\\Rightarrow\text{Area of pond}=28.26\ ft^2[/tex]
Now, the area of the Japanese garden around the koi pond
= Area of the whole garden - Area of the Koi pond
=[tex]224-28.26=195.74\ ft^2[/tex]
Hence, the area of the Japanese garden around the koi pond is [tex]195.74\ ft^2[/tex]
If the radius and height of a cylinder are multiplied by 3, the lateral area of the cylinder is multiplied by
1. Draw a right triangle with sides 2,2√3, and 4 units. Label all angle measures and sides. Using the side relationships from the figure, show that the following trigonometric identities hold true for either one of the non-right angles:
a. tan 0=sin 0/cos O
b.) sin^2(0)+cos^2(0)=1
where 0 represents whichever angle you choose
FYI...all of the 0 have a line through them
THank you because I don't understand this at all.
Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29)
Answer:
x=-4,1,2+5i,2-5i
Step-by-step explanation:
Given is an algebraic expression g(x) as product of two functions.
Hence solutions will be the combined solutions of two quadratic products
[tex]g(x) = (x^2 + 3x - 4)(x^2 - 4x + 29)\\[/tex]
I expression can be factorised as
[tex](x+4)(x-1)[/tex]
Hence one set of solutions are
x=-4,1
Next quadratic we cannot factorize
and hence use formulae
[tex]x=\frac{4+/-\sqrt{16-116} }{2} =2+5i, 2-5i[/tex]
Answer:
The answer above is correct:
B. 1
C. 4
E. 2+5i
F. 2-5i
Step-by-step explanation:
I got this right on Edg. 2021
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
6-inch apothem
A = sq. in
Answer: 12√3 square inches
Step-by-step explanation:
By the property of equilateral triangle,
Apothem = √3/2 × Side
⇒ Side = 2/√3 × Apothem
Here, apothem = 6 inches
Thus, the side of the given equilateral triangle = [tex]\frac{2}{\sqrt{3}}\times 6[/tex]
= [tex] \frac{12}{\sqrt{3}}[/tex]
= [tex]4\sqrt{3}[/tex] unit
Since, For an equilateral triangle,
[tex]\text{ Area} = \frac{\sqrt{3}}{4}\times (\text{ side})^2[/tex]
⇒ The area of the given equilateral triangle = [tex] \frac{\sqrt{3}}{4}\times (4\sqrt{3})^2[/tex]
[tex]=\frac{\sqrt{3}}{4}\times 48[/tex]
[tex]=12\sqrt{3}[/tex] square inches
An analogy makes a comparison between objects based on their similar qualities. Cassidy wanted to create an analogy for the motion of atoms in solids, liquids, and gases, so she compared them to marbles in a tray. Which best compares the phases of matter to marbles in a tray? A solid is like the tray being shaken and the marbles moving around it, and a liquid is like the tray being shaken slowly and all the marbles moving in their positions. A solid is like the tray being shaken slowly and all the marbles moving in their positions, a liquid is like the tray being shaken and the marbles moving around it, and a gas is like the tray being shaken hard and the marbles moving vigorously around it. A gas is like the tray being shaken slowly and all the marbles moving in their positions, and a solid is like the tray being shaken hard and the marbles moving vigorously around it. A liquid is like the tray being shaken hard and the marbles moving vigorously around it, and a gas is like the tray being shaken slowly and all the marbles moving in their positions.
Answer:
B
Step-by-step explanation:
5 to 2 = __ to 4 and also 14 to 21 = __ to 15
Which functions represent the arithmetic sequence 8, 1.5, –5, –11.5 . . . ? Check all that apply.
f(n) = –6.5n + 14.5
f(n) = –1.5n + 9.5
f(n) = 6.5n + 1.5
f(1) = 8, f(n + 1) = f(n) – 6.5
f(1) = 8, f(n + 1) = f(n) – 1.5
f(1) = 8, f(n + 1) = f(n) + 6.5
Answer:
f(n) = –6.5n + 14.5
f(1) = 8, f(n + 1) = f(n) – 6.5
Step-by-step explanation:
The nth term of an arithmetic sequence is given as
Tn = a + (n-1)d
where a is the first term and d is the common difference between two consecutive terms
From the given sequence,
a = 8, d = 1.5 - 8
d = -6.5
As such, Tn = f(n) = 8 + (n-1)-6.5
= 8 - 6.5n + 6.5
= 14.5 - 6.5n
f(1) = 8
f(n + 1) - f(n) = – 6.5
f(n + 1) = f(n) – 6.5
A hotel has $504 to buy new pillows. If the cost of each pillow is $6, how many pillows will the hotel be able to buy? A) 78 B) 84 C) 88 D) 96
In the diagram, what is the measure of angle 1?
A. 135°
B. 125°
C. 15°
D. 45°
The height of a free falling object at time t can be found using the function, h(t) = - 12t2 + 36t. Where h(t) is the height in feet and t is the in seconds. Find the time when the object hits the ground
Answer:
3 seconds is the time when the object hits the ground.
Step-by-step explanation:
Given the height of a free falling object at time t can be found using the function is given by:
[tex]h(t)=-12t^2+36t[/tex] ....[1]
where,
h(t) is the height in feet
t is the in seconds.
We have to find the time when the object hits the ground.
⇒h(t) = 0
Substitute this in [1] we have;
[tex]-12t^2+36t =0[/tex]
⇒[tex]12t^2-36t = 0[/tex]
⇒[tex]12t(t-3) = 0[/tex]
⇒t = 0 and t = 3
Since, time cannot be 0.
⇒t = 3 seconds
Therefore, the time when the object hits the ground is, 3 seconds
what is 30% of 250 =
Compute with percents
a monument stands at level ground. The angle of elevation to the top of the monument taken at a point 405 feet away is 32°. Find the height of the monument.
The height of the monument is approximately 253.2 feet.
To find the height of the monument, we can use trigonometry, specifically the tangent function, which relates the angle of elevation to the height and distance from the observation point.
Step-by-Step Solution:
Identify the given values:
Distance from the point: 405 feetAngle of elevation: 32°Use the tangent function:
tan(θ) = opposite / adjacent
Where θ is the angle of elevation, the opposite side represents the height of the monument (h), and the adjacent side represents the distance from the point (405 feet).
Set up the equation and solve for h:
tan(32°) = h / 405 feet
Using a calculator, find tan(32°):
tan(32°) ≈ 0.6249
So the equation is:
0.6249 = h / 405
Multiply both sides by 405 to solve for h:
h ≈ 0.6249 * 405
h ≈ 253.2 feet
Thus, the height of the monument is approximately 253.2 feet.
at a shopping mall,4/9 of the shoppers were children and 5/7 of the adults were woman.They were 1/2 as many boys as men.They were 90 more girls than boys. (a) what fraction of the shoppers in the shopping mall were men ? (b) How many shoppers were in the shopping mall ?