(2^n)^1/2=64 find value of n

One of these doesn't seem to be required information for a feasibility region. Are you sure that these are the correct equations?

obviously $48.60 would save more.

Answer,

48.60

Hope this helps - Laura

:-)

Answer:

The density of the object is [tex]0.1067[/tex] grams per cubic centimeter. (Rounded off to 4th decimal)

Step-by-step explanation:

Density = [Mass/Volume]

Here we have been given the dimensions of the object.

Volume = Height * Width * Length

Volume = [tex]3.0cm*15.0cm*5.0cm[/tex]

             =[tex]225cm^{3}[/tex]

Now we can substitute the Mass and the Volume to the density equation.

Density = [Mass/Volume]

             =[tex]\frac{24grams}{225cm^{3} }[/tex]

             =[tex]0.1067[/tex] grams per cubic centimeter. (Rounded off to 4th decimal)

so lets say base = x

Then 1*x=2.5

Therefore the base equals 2.5

Hope this helps!

g(θ) = 20θ − 5 tan θ

To find out critical points we take first derivative and set it =0

g(θ) = 20θ − 5 tan θ

g'(θ) = 20 − 5 sec^2(θ)

Now we set derivative =0

20 − 5 sec^2(θ)=0

Subtract 20 from both sides

− 5 sec^2(θ)=0 -20

Divide both sides by 5

sec^2(θ)= 4

Take square root on both sides

sec(θ)= -2  and sec(θ)= +2

sec can be written as 1/cos

so sec(θ)= -2  can be written as cos(θ)= -1/2

Using unit circle the value of θ is [tex]\frac{2\pi}{3} and\frac{4\pi}{3}[/tex]

sec(θ)= 2  can be written as cos(θ)=1/2

Using unit circle the value of θ is [tex]\frac{\pi}{3}and\frac{5\pi}{3}[/tex]

For general solution we add 2npi

So critical points are

[tex]\frac{2\pi}{3} + 2n\pi,\frac{4\pi}{3} + 2n\pi , \frac{\pi}{3} + 2n\pi, \frac{5\pi}{3} + 2n\pi[/tex]

The critical points of a function are where its derivative is zero or undefined. The critical points for the function g(θ) = 20θ − 5 tan θ can be found by taking its derivative, setting it to zero, and solving for θ. Additional critical points may occur when the derivative does not exist.

In mathematics, the critical points of a function are those where its derivative is zero or undefined. We can find the critical points for the function g(θ) = 20θ − 5 tan θ by taking its derivative and setting it equal to zero.

To find these points, we differentiate the function g(θ) to obtain g'(θ) = 20 - 5/(cos^2 θ). Setting this equal to zero and solving for θ will provide the critical points. In this case, the function is undefined whenever cos θ=0 , providing additional potential critical points. Thus, with trigonometric functions like the tangent function in this question, the critical points occur when the derivative is zero or the derivative does not exist.

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(5,1)

x=5

y=1

m=1/2

Use this formula

y-y1=m(x-x1)

y-1=1/2(x-5)

y-1=x/2-5/2

Isolate for y

y=x/2-3/2

Hope this helps.

Answer:x-2y=3

Step-by-step explanation:

Given

Lines passes  through (5,1) and slope of 0.5

i.e. [tex] tan\theta =0.5[/tex]

where [tex]\theta [/tex]is the angle made by line with horizontal

equation of line can be given by

[tex]\frac{y-1}{x-5}=tan\theta [/tex]

2y-2=x-5

x-2y=3 is the required line

Answer:

[tex]\large\boxed{x=\dfrac{6b}{\pi n^2}}[/tex]

Step-by-step explanation:

[tex]b=\dfrac{1}{6}\pi n^2x\qquad\text{multiply both sides by 6}\\\\6b=\pi n^2x\qquad\text{divide both sides by}\ \pi n^2\neq0\\\\\dfrac{6b}{\pi n^2}=b[/tex]

  Well we know that our function is -3, so we can plug this into the equation. \

f(x) = 2x + 1 + 5

f(-3) = 2(-3) + 1 + 5, now from here we simplify (:

-6 + 1 + 5 then finally we combine our like terms

-6 + 1 equals -5, then -5 + 5 equals 0

our final answer is zero if our function is f(-3) ((((((((((((((((((((((((((((((:

so 50 pages and 2 stamps in one page

To begin, Arnold should sort on whether or not it is a screw, nut, bolt.

This might only be # 1 and 3 but you should be able to put together a number line with the information I provided. Some of the #s may look different but that is because I used the Least Common Denominator. Hope this helps!

Screws: Least to greatest (top = least)

4 Screws 4/64” x 3” long

12 Screws 5/64” x 3” long

3 Screws 6/64” x 4” long

6 Screws 11/64” x 4” long

16 Screws 24/64” x 2” long

1 Screw 28/64” x 3” long

1 Screw 32/64” x 3” long  

1 Screw 48/64” x 2” long

Hex Bolts: Least to greatest by diameter (top = least)

4 Hex bolts 1.5” x 4” long

4 Hex bolts 1.875” x 4” long

1 Hex bolt 2.25” x 2” long

6 Hex bolts 3.375” x 3” long

4 Hex bolts 3.75” x 3” long

i think you add 232 and 184 then divide by 13.

Hope this helps!

It would go under Utilities Expense (right column, second from the bottom) as a Debit

The answer is false due to the object is changes shape not size

Answer:

-5.76x=-27.33

-6x=-27

Step-by-step explanation:

you would bring the 3.98 over to the other side, so it would be -3.98+6.58=2.6-8.39=-5.76

The answer is 8.608 because you would just divide 860800 by 100k to get this answer

1) 4/5

2) -62/13

3) 1/9

4) 527/42

I only answered these four questions.

Hope this helps. By the way they are all in the exact form.

To solve the multiplication problem and simplify the fractions, follow these steps:

Multiply 32/5 × 513/1:

(32/5) × (513/1) = (32 × 513) / (5 × 1) = 16416 / 5

Now, let's find how many novels Jeffrey owns. He owns 230 books, and of them are novels:

Number of novels = (Number of novels) / Total books

Number of novels = (3/9) × 230

Number of novels = (1/3) × 230

Number of novels = 230 / 3

Number of novels = 76⅔ (mixed number)

To simplify the mixed number 76⅔, remember that ⅔ is equivalent to 2/3.

76⅔ = 76 + ⅔ = 76 + 2/3 = (76 × 3 + 2) / 3 = 230 / 3

So, Jeffrey owns 76⅔ novels.

For the standardized test practice, we have two fractions:

Fraction of students wearing school colors = 1/4

Fraction of students wearing school colors in the 6th grade = 3/20

To find the fraction of students wearing school colors in the 6th grade, we can multiply these fractions:

Fraction = (1/4) × (3/20) = 3/80

So, the fraction of students at the school dance who wore the school colors and were in the 6th grade is 3/80.

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when you are buying toothbrushes and s is boxes of toothbrushes, and there are 100 tooth brushes per box, 974 > 878

Answers:

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1)   (3 inches)(5 inches) = (3 in)(5 in) = 3 * 5 * in * in = 15 * in * in   =  "  15 in² " .

___________________________________________________________

2)  (5 feet)(2 feet) = (5 ft)(2ft) = 5 * 2 * ft * ft = 10 * ft * ft   =  " 10 ft²  " .

___________________________________________________________

Final answer:

Exponents are used for repeated multiplication of the same number, hence, (3 inches)(5 inches) and (5 feet)(2 feet) cannot be simplified using exponents since they involve different numbers. Exponents and conversion factors are distinct mathematical tools, with the latter used for converting units of measure.

Explanation:

The question addresses using exponents to express products of the same units in a simpler form. The product of (3 inches)(5 inches) suggests multiplying these two measurements, however, when writing this product using exponents, we should consider that both are units of length, and thus their product will result in a unit of area, which is square inches (in2). We cannot simplify this expression further using exponents as they are not repeated multiplication of the same number.

On the other hand, for the product (5 feet)(2 feet), we again get an area, but this time in square feet (ft2). Still, there's no need for using exponents in this expression because we are not dealing with repeated multiplication of the same number.

It is important to note that exponents are used to represent repeated multiplication of the same number. For example, if we had (5 inches)(5 inches), we could write this as 5 inches squared (5 in)2, because it's 5 inches multiplied by itself. On the contrary, when multiplying different numbers, exponents don't apply.

When converting between different units of measure, as in converting feet to inches, we use conversion factors. For instance, 1 foot equals 12 inches, so by multiplying feet by 12, we can convert it to inches. Similarly, inches can be converted to feet by dividing by 12.

16 + 36 = 52 so the answer would be A) 4(4 + 9) because that equals 52 as well.

Answer:

Step-by-step explanation:

Let's first find out how many workstations there would be.

It says in the problem that there are two classrooms and that they both have the same number of workstations.

There are seven workstations in each of the two classrooms.

√70 = 8.37

It would be between 8 and 9.

The result of the division of x³-7 by x+2 will be (x²−2x+4)−15/(x+2).

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Division = divide any two numbers or variables called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

Division of (x³-7) ÷ (x+2)

Keep quotient x² → (x³-7) - (x³+2x²) ⇒ remainder = -7-2x²

Next quotient -2x → (x³-7) - (-2x²-4x) ⇒ remainder = -7+4x

Next quotient 4 →  (x³-7) - (8+4x) ⇒ reminder = -15

Therefore,

(x³-7) ÷ (x+2) = (x²−2x+4)−15/(x+2).

Hence "The result of the division of x³-7 by x+2 will be (x²−2x+4)−15/(x+2)".

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[tex]10x^2+27x-28=10x^2+35x-8x-28=5x(2x+7)-4(2x+7)\\\\=(2x+7)(5x-4)\\\\Answer:\ D.\ 2x+7[/tex]

Divide total miles driven by the total amount of gas used to find the number of miles per gallon.

Then multiply that by the number of gallons you want to find out:

268 miles / 12 gallons = 22.333 miles per gallon.

22.333 miles per gallon x 9 gallons = 201 total miles.

-2(6-x) is the remainder.

The perimeter of a rectangle is the sum of all four sides of the rectangle.

(Perimeter = 2width + 2length)

Let's assume the width of the rectangle to be x.

For length, the statement says that is equals to 3 times the width (= 3x) and 5cm more meaning 5cm would be added to 3 times the width.

Width = x

Length = 3x + 5

Perimeter = 2x + 2(3x+5)

74 = 2x + (6x+10)

74 = 8x + 10

solve for x

8x = 74 - 10

x = 64/8, x=8

Width = 8

length = 3(8)+5 = 29

The area of the stretched triangle is four times the area of the original triangle

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

if a² + b² = c² , it is a right triangle

if a² + b² < c² , it is an obtuse triangle

if a² + b² > c² , it is an acute triangle

Given data ,

Let's assume that the original triangle has sides of length a, b, and c, and that its area is A. Without loss of generality, we can assume that side a is the shortest side.

After the rubber is stretched, each side of the enlarged triangle will be twice the length of its original length. Thus, the lengths of the sides of the stretched triangle will be 2a, 2b, and 2c.

Since the rubber is stretched equally from all sides, we know that each angle of the original triangle will be doubled. Therefore, the stretched triangle will be similar to the original triangle.

The area of a triangle is given by the formula:

A = (1/2) x base x height

where the base and height are the lengths of any two sides of the triangle that are perpendicular to each other.

Since the stretched triangle is similar to the original triangle, we can use the ratios of corresponding sides to find the lengths of the corresponding altitudes. Specifically, we have:

(altitude of stretched triangle corresponding to side 2a) = 2 x (altitude of original triangle corresponding to side a)

(altitude of stretched triangle corresponding to side 2b) = 2 x (altitude of original triangle corresponding to side b)

(altitude of stretched triangle corresponding to side 2c) = 2 x (altitude of original triangle corresponding to side c)

Therefore, the area of the stretched triangle is given by:

A' = (1/2) x (2a) x (2b) x (2/2) + (1/2) x (2b) x (2c) x (2/2) + (1/2) x (2c) x (2a) x (2/2)

Simplifying this expression gives:

A' = 4A

Hence , the area of the stretched triangle is four times the area of the original triangle.

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