Answer:
I think b if not then c hopefully this helps
Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium? oxygen + lithium oxide Right arrow. Lithium lithium + oxygen Right arrow. Lithium oxide oxygen + lithium Right arrow. Lithium + oxide lithium oxide Right arrow. Lithium + oxygen
Answer: lithium + oxygen Right arrow. lithium oxide
lithium + oxygen proper arrow. lithium oxide This equation indicates lithium oxide is formed from the reaction between oxygen and lithium.
what is lithium oxide used for?
Lithium oxide is used as a flux in ceramic glazes and creates blues with copper and pinks with cobalt. Lithium oxide reacts with water and steam, forming lithium hydroxide, and needs to be isolated from them.
wherein is Lithium Oxide found?Lithium Oxide is an extraordinarily insoluble thermally stable Lithium source suitable for glass, optic, and ceramic programs. Lithium oxide is a white stable also referred to as lithia, it is produced whilst lithium metallic burns inside the presence of oxygen.
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The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224 g of this metal by 71°C.
Answer:
Preceding accumulative aggregate of energy indispensable is disseminated as 5455 J.
Explanation:
Allotted the contiguous information:
Q: Not identified.
M: 224 g
S: 0.343 J/g°C
Final thermodynamics: 71°C
Initial thermodynamics: 0°C
ΔT = 71°C
We can equate as imminent:
Q = 224 g · 0.343 J/g°C · 71°C
Q ⇒ 5455 J
Hence, the pertaining preeminent albeit paramount indispensable consignment or quantity of energy obligated, concerning an augmentation in thermodynamics subject to the undisclosed metal by 71°C is 5,455 J.
The energy required to raise the temperature of the metal is 5365.256 J.
Explanation:To calculate the energy required to raise the temperature of a substance, we use the formula:
q = m * c * ΔT
The energy required to raise the temperature of a substance can be calculated using the formula: q = mcΔT where q is the energy in joules, m is the mass in grams, c is specific heat capacity in J/(g•°C), and ΔT is the change in temperature in °C.
Given that the mass (m) of the metal is 224 g, the specific heat capacity (c) is 0.343 J/(g•°C), and the temperature change (ΔT) is 71°C, you can substitute these values into the formula:
Plugging in the values given:
q = (224 g) * (0.343 J/(g•°C)) * (71°C)
Simplifying the equation gives:
q = 5365.256 J
Therefore, the energy required to raise the temperature of 224 g of this metal by 71°C is 5365.256 J.
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What is the molarity of a 2.0L solution that was made up with 4.0 moles of NaCl?
Answer:
[NaCl]: 2M
Explanation:
This solution is made of NaCl therefore:
Our solute is NaCl
Moles of solute: 4
Our solution's volume is 2L
Molarity are the moles of solute contained in 1L of solution (mol/L)
[NaCl]: 4 mol /2L = 2M
We can also make a rule of three:
In 2 L we have 4 moles of solute
So, In 1 L we must have (1 . 4) /2 = 2 M
The molarity of the solution is 2.0 M (moles per liter).
To determine the molarity of a solution, one must use the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute (n)}}{\text{Volume of solution (V)}} \][/tex]
Given that the solution contains 4.0 moles of NaCl (solute) and has a total volume of 2.0 liters, we can plug these values into the formula:
[tex]\[ \text{Molarity (M)} = \frac{4.0 \text{ moles}}{2.0 \text{ L}} \] \[ \text{Molarity (M)} = 2.0 \text{ M} \][/tex]
Therefore, the molarity of the solution is 2.0 moles per liter. This means that there are 2.0 moles of NaCl dissolved in every liter of the solution.
Liquid A has a vapor pressure of 7.37 kPa at 40C. Liquid B has a vapor pressure of 18.04kPa at 40C. Which liquid would evaporate faster at 40C? Explain your answer.
Answer:
Liquid B because of its higher vapor pressure due to the fact that evaporation rate is directly proportional to vapor pressure
Explanation:
The vapor pressure of liquid at equilibrium is a function to the liquid's rate of evaporation. The evaporation rate and hence the vapor pressure is a measure of the propensity of the particles of the liquid to leave the surface of the liquid and exist as vapor directly above the liquid. As high evaporation rate leads to high vapor pressure, a liquid with a higher vapor pressure will evaporate faster than one with a lower vapor pressure at the same temperature and pressure.
Therefore, liquid B with a vapor pressure of 18.04 kPa at 40° C will evaporate faster than liquid A with a lower vapor pressure of 7.37 kPa at the same 40°C.
Liquid B with a higher vapor pressure of 18.04 kPa at 40°C would evaporate faster than liquid A with 7.37 kPa, as higher vapor pressure indicates that the liquid is more volatile and its molecules can more easily escape into the gas phase.
Explanation:At 40°C, between liquid A with a vapor pressure of 7.37 kPa and liquid B with a vapor pressure of 18.04 kPa, liquid B would evaporate faster. This is because vapor pressure is a measure of the tendency of molecules to escape from a liquid and enter the gas phase. A higher vapor pressure indicates that molecules can break away from the surface of the liquid more easily, which is indicative of a more volatile liquid. Therefore, liquid B, with its higher vapor pressure at the same temperature, is the more volatile and will evaporate more rapidly than liquid A.
Vapor pressure of a liquid is directly related to its intermolecular forces; liquids with weaker intermolecular forces have higher vapor pressures, and hence they evaporate faster. Conversely, greater intermolecular forces result in a lower vapor pressure and slower evaporation rate. For volatile liquids in a mixture, adding their partial pressures yields the total vapor pressure of the mixture
which solution contains phenolphthalein pink?
Consider the reaction below.
HCIO3 + NH3 → NH4+ + CIO3-
Which is a base-conjugate acid pair?
NH3 and CIO3-
NH3 and NH4+
HCIO3 and NH3
HCIO3 and NH4+
Answer:
NH3 and NH4+
Explanation:
NH4+ is the conjugate acid of the base NH3.
The example of base-conjugate acid pair is B. NH3 and NH4+.
What is a base-conjugate acid pair?A base-conjugate acid pair simply means a pair that consist of two substances that only differ by the presence of a proton (H+).
In this case, the example of base-conjugate acid pair is NH3 and NH4+ because bNH4+ is the conjugate acid of the base NH3.
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HgO + Cl2 → HgCl + O2
A. Double Replacement
B. Single Replacement
C. Combustion
D. Decomposition
E. Synthesis
Answer:
B. Single Replacement
Explanation:
Single replacement:
It is the reaction in which one elements replace the other element in compound.
AB + C → AC + B
Chemical equation:
2HgO + Cl₂ → HgCl + O₂
This is the single replacement reaction. In this reaction chlorine replace the oxygen from mercury oxide and form mercury chloride.
Other options are incorrect because,
Decomposition reaction:
It is the reaction in which one reactant is break down into two or more product.
AB → A + B
Synthesis reaction:
It is the reaction in which two or more simple substance react to give one or more complex product.
A + B → AB
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AC +BD
The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?
Answer:
Explanation:
q = (mass) (temp change) (specific heat)
q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ
154 kJ / 2220 kJ/mol = 0.069369369 mol
0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)
answer choice 4
The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.
3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.
What is meant by heat of combustion?The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions. In most cases, a hydrocarbon reacts with oxygen to produce carbon dioxide, water, and heat.The heat of combustion of a substance is the amount of energy released when a specific amount (e.g., 1 mol, 1g, 1 L) of the substance completely burns in oxygen. The heat of combustion is typically measured at 298K (25 C) and 101.3kPa.The energy released when a substance X completely burns with an excess of oxygen under standard conditions (25°C and 1 bar). It is the inverse of the enthalpy change for the combustion reaction in thermodynamic terms.q=m*c*(change of T)
q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)
q=154000J
154000J*(1 mol/2220 KJ)=69.36936 x [tex]10 ^-3[/tex] mol
here's where I'm stuck
0.069369 mol
and i know that for every 1 mol there is 44.11g of C3H8.
0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.
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The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hours. Calculate the concentration of SOCl2 after 17.0 hours have passed in an experiment where the initial concentration of sulfonyl chloride was .0837M.
Answer:
[tex][SOCl_2]=0.0218M[/tex]
Explanation:
The equations for a first order reaction are:
[tex]\dfrac{d[A]}{dt}=-k[A][/tex]
[tex][A]=[A_0]e^{-kt}[/tex]
[tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]
1. Calculate the constant of reaction, k:
Use the equation
[tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]
[tex]8.75h=\dfrac{\ln 2}{k}[/tex]
[tex]k=\dfrac{\ln 2}{8.75h}[/tex]
[tex]k\approx 0.0792168h^{-1}[/tex]
2. Calculate the concentration after 17.0 hours
Use the equation
[tex][A]=[A_0]e^{-kt}[/tex]
[tex][SOCl_2]=0.0837M\cdot e^{-0.0792168h^{-1}\times 17.0h}[/tex]
[tex][SOCl_2]=0.0218M[/tex]
Balance each of the chemical equations below. (Some equations may already be
in balance.) In the space to the right, classify the reaction as a synthesis, decomposition,
single replacement, or double replacement reaction.
A. ___ AgNO3 + ___ KCl⇒ ___ AgCl + ___ KNO3 _______________________
B. ___ H2O + ___ SO3 ⇒ ___ H2SO4 _______________________
C. ___ KI + ___ Cl2 ⇒ ___ KCl + ___ I2 _______________________
D. ___ NaHCO3 ⇒___ Na2CO3 + ___ H2O + ___ CO2 _______________________
E. ___ Zn + ___ HCl ⇒ ___ ZnCl2 + ___ H2 _______________________
F. ___ BaCl2 + ___ Na2SO4 ⇒ ___ BaSO4 + ___ NaCl _______________________
G. ___ C3H8 + ___ O2 ⇒ ___ CO2 + ___ H2O _______________________
H. ___ Al + ___ CuCl2 ⇒ ___ AlCl3 + ___ Cu _______________________
i will give 80 points and brainliest answer to the first one that answers
Answer:
A. 1 AgNO3 + 1 KCl ⇒ 1 AgCl + 1 KNO3 double replacement
B. 1 H2O + 1 SO3 ⇒ 1 H2SO4 synthesis
C. 2 KI + 1 Cl2 ⇒ 2 KCl + 1 I2 single replacement
D. 2 NaHCO3 ⇒ 1 Na2CO3 + 1 H2O + 1 CO2 decomposition
E. 1 Zn + 2 HCl ⇒ 1 ZnCl2 + 1 H2 single replacement
F. 1 BaCl2 + 1 Na2SO4 ⇒ 1 BaSO4 + 2 NaCl double displacement
G. 1 C3H8 + 5 O2 ⇒ 3 CO2 + 4 H2O combustion
H. 2 Al + 3 CuCl2 ⇒ 2 AlCl3 + 3 Cu single displacement
Explanation:
Use algebra to make sure you have the same amount of each element on each side (Reactants and Products) and only change the coefficients of the compounds and elements!
double displacement: AB + CD ⇒ AD + CB
single replacement: AB + C ⇒ A + CB
decomposition: A ⇒ B + C
synthesis: A + B ⇒ C
combustion: any reaction that involve oxygen and don't follow any of the previous reactions
To balance a chemical reaction equation, the number of atoms of each element on both sides of the reaction equation must be the same.
A chemical reaction equation has a right hand side (reactants side) and a left hand side (products side). The reactants combine to give the products. The number of atoms of each element on the reactants side must be exactly the same as the number of atoms of the same element on the products side.
The balanced chemical reaction equation for each of the reactions is shown below;
AgNO3 + KCl ------>AgCl + KNO3 double replacement reactionH2O + SO3 -------> H2SO4 synthesis reaction2KI + Cl2 ------> 2 KCl + I2 single replacement reaction 2NaHCO3 ----> Na2CO3 + CO2 + H2O decomposition reactionZn + 2HCl -----> ZnCl2 + H2 single replacement reaction BaCl2 + Na2SO4 ------> 2NaCl + BaSO4 double replacement reactionC3H8 + 5O2 ------> 3CO2 + 4H2O Combustion reaction2Al + 3CuCl2 -----> 2AlCl3 + 3Cu single replacement reactionIf there is no molar coefficient written in front of any of the species then the molar is 1.
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How many grams of sodium bromide must be dissolved in 400.0 g of water to produce a 0.500 molal solution?
Answer:
The answer is 20.6 grams.
Explanation:
Molality describes the concentration of a solution. It can be defined as the number of moles of a solute dissolved in 1 kilogram of solvent. Then it is equal to the moles of solute (the substance that dissolves) divided by the kilograms of solvent (the substance used to dissolve):
[tex]Molality=\frac{number of moles of solute}{kilogram of solvent}[/tex]
The molality is expressed in units ([tex]\frac{moles}{kg}[/tex]).
So, you can apply the following rule of three with the solution being 0.5 molal: if in 1 kg of solution there are 0.5 moles of solute, in 0.4 kg (400 g, being 1kg = 1000g) how many moles of solute are there?
[tex]moles=\frac{0.4 kg*0.5 moles}{1 kg}[/tex]
moles=0.2 moles
Now, you know:
Na: 23 g/moleBr: 80 g/moleThen, The molar mass of sodium bromide NaBr is
NaBr= 23 g/mole + 80 g/mole= 103 g/mole
Now a new rule of three applies, if in 1 mole of sodium bromide there are 103 grams, in 0.2 mole how much mass is there?
[tex]mass=\frac{0.2 moles*103 grams}{1 mole}[/tex]
mass= 20.6 grams
The answer is 20.6 grams.
How many dots should be shown in the Lewis dot diagram of carbon?
1
2
3
4
Answer:
Im 90% sure its 3.
Explanation:
Answer:
4
Explanation:
How many moles are there in 24.00 g of NaCl
Answer:
The answer to your question is 0.41 moles
Explanation:
Data
moles of NaCl = ?
mass of NaCl = 24 g
Process
To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.
1.- Calculate the molar mass
NaCl = 23 + 35.5 = 58.5 g
2.- Use proportions and cross multiplication
58.5 g of NaCl ------------------- 1 mol
24.0 g ------------------- x
x = (24 x 1) / 58.5
x = 0.41 moles
What is the volume of 2.3 mol of helium at 17 C and 0.89 atm? Assume helium behaves as an ideal gas.
Answer:
39.446L
Explanation:
since helium is ideal gas, we can use PV = nRT
P = pressure
V = volume
n = moles
R = gas constant
T = temperature in Kelvin
we are solving for V
V = [tex]\frac{nRT}{P}[/tex]
C to K temp transfer: K = C + 273, so K = 290 since C = 17
our gas constant is 0.08206 atm L/mol K, this gas constant r will change depending on what unit of pressure you are using (mmHg, atm, etc).
plug and chug
V = [tex]\frac{(2.3mol)(290K)(\frac{0.08206 atmL}{molK}) }{1 atm}[/tex]
canceling out units
V = [tex]\frac{2.3 * 209 * 0.08206L}{1}[/tex] = 39.446
Consider the equation ; N₂ + 3 H₂ → 2 NH₃ What is the mole ratio of hydrogen to ammonia (NH₃)?
1. 1:1
2. 1:2
3. 3:2
4 5:4
Answer:
3. 3:2
Explanation:
in the reactants, 3 is the coefficient for the hydrogen atoms.
In the products, 2 is the coefficient for the ammonia atoms.
Ozone reacts completely with NO, producing NO2 and O2. A 13.0 L vessel is filled with 1.30 mol of NO and 1.30 mol of O3 at 401.0 K. Find the partial pressure of each product and the total pressure in the flask at the end of the reaction.
Answer:
6.58 atm total
3.29 atm NO2
3.29 atm O2
Explanation:
Balanced equation:
O3 + NO → NO2 + O2
There are equal numbers of moles of both reactants, so neither is in excess and either could be considered the limiting reactant.
( 1.30 mol NO) x (1 mol NO2 / 1 mol NO) = 1.30 mol NO2
( 1.30 mol NO) x (1 mol O2 / 1 mol NO) = 1.30 mol O2
Total pressure by using the formula;
P = nRT / V
= ( 1.30 mol + 1.30 mol) x (0.08205746 L atm/K mol) x (401.0 K) / (13.0 L)
= 6.58 atm
Partial pressure for NO2;
(6.58 atm) x (1.30 mol NO2) / (1.30 mol + 1.30 mol)
= 3.29 atm NO2
Partial pressure for O2
6.58 atm total - 3.29 atm NO2
= 3.29 atm O2
1. The partial pressure of nitrogen dioxide ([tex]NO_2[/tex]) is equal to 3.29 atm.
2. The partial pressure of oxygen gas ([tex]O_2[/tex]) is equal to 3.29 atm.
3. The total pressure in the flask at the end of the chemical reaction is 6.58 atm.
Given the following data:
Volume of flask = 13.0 LitersNumber of moles of NO = 1.30 moles.Number of moles of [tex]O_3[/tex] = 1.30 moles.Temperature = 401.0 K.Scientific data:
Ideal gas constant, R = 0.0821L⋅atm/mol⋅KTo determine the partial pressure of each product and the total pressure in the flask at the end of the chemical reaction:
First of all, we would write a balanced chemical equation for the chemical reaction as follows:
[tex]O_3 + NO \rightarrow NO_2+O_2[/tex]
Since the numbers of moles of reactants are equal, the total number of moles of products is:
[tex]n=1.3+1.3[/tex]
n = 2.6 moles
Now, we can find the total pressure in the flask at the end of the chemical reaction by using the ideal gas law equation;
[tex]PV=n RT[/tex]
Where;
P is the pressure.V is the volume.n is the numbers of moles of gas.R is the ideal gas constant.T is the temperature.Making P the subject of formula, we have;
[tex]P=\frac{nRT}{V}[/tex]
Substituting the parameters into the formula, we have;
[tex]P=\frac{2.6 \times 0.0821 \times 401}{13}\\\\P=\frac{85.597}{13}[/tex]
Total pressure, P = 6.58 atm.
Next, we would determine the partial pressure of each product:
[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}[/tex]
[tex]Molefraction \;of \;a \;substance =\frac{1.3}{2.6} \\\\Molefraction \;of \;a \;substance =0.5[/tex]
For [tex]NO_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]NO_2[/tex] = 3.29 atm.
For [tex]O_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]O_2[/tex] = 3.29 atm.
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What is the molar mass of Na(C2 H3 O2)?
Answer:
The answer to your question is 82g
Explanation:
Data
Molecule: Sodium acetate Na(C₂H₃O₂)
Molar mass = ?
Process
Look for the atomic mass of each element, multiply this number by the subscript and add the results.
Sodium = 23 g
Carbon = 2 x 12 = 24 g
Hydrogen = 1 x 3 = 3 g
Oxygen = 2 x 16 = 32 g
Sum up the result
Molar mass = 23 + 24 + 3 + 32
= 82 g
75.0 g of sodium completely reacts with iron III Carbonate. How many grams of sodium carbonate are formed?
Answer:
mass = 172.78 grams Na₂CO₃(s) formed
Explanation:
6Na°(s) + Fe₂(CO₃)₃ => 3Na₂CO₃(s) + 2Fe°(s)
moles Na°(s) = 15g/23g/mol = 3.26 mole Na°(s)
From stoichiometry of reaction equation, 3.26 mole Na°(s) => 3/6(3.26) mole Na₂CO₃(s) = 1.63 mole Na₂CO₃(s) x 106 g/mole = 172.78 grams Na₂CO₃(s)
Juanita sticks a nail to the end of a bar magnet. She then sticks a second nail to the first, then another to that one, and so on. When she gets to the seventh nail, it falls off the sixth nail.
Which statement best describes the forces acting on the seventh nail?
A. The force of magnetism is equal to the force of gravity.
B. The force of gravity is stronger than the force of magnetism.
C. The force of magnetism is stronger than the force of gravity.
Explanation:
answer is b
The reduction potential (E0′) of a substance reflects its tendency to donate or accept electrons. The larger the difference (ΔE0′) between the reduction potentials of the electron donor and the electron acceptor, __________.A) the greater the change in free energy (ΔG0′), and the less energy is releasedB) the closer the substances are on the electron towerC) the more enzymes will be required to catalyze the reaction(s)D) the greater the change in free energy (ΔG0′), and the greater the energy released
Answer:
The greater the change in free energy (ΔG0′), and the greater the energy released
Explanation:
Recall that the change in free energy is given by:
∆G°'= nFE°'
But E° is given by E°acceptor - E°donor
Hence the greater the difference between E°acceptor and E°donor, the greater the value of E° and consequently the greater the value of ∆G° and the energy released.
Note: E°acceptor and E°donor refer to reduction potentials of donor and acceptor
Given the equation I = Q/t, solve for t.
Answer: [tex]t=\frac{Q}{I}[/tex]
Explanation:
[tex]I=\frac{Q}{t}[/tex]
Multiply by t on both sides.
[tex]t*I=\frac{Q}{t}*t[/tex]
[tex]tI=Q[/tex]
Now divide by I to isolate t.
[tex]\frac{tI}{I}=\frac{Q}{I}[/tex]
[tex]t=\frac{Q}{I}[/tex]
Final answer:
To solve for time t in the equation I = Q/t, multiply both sides by t to get t × I = Q, and then divide both sides by I to obtain[tex]t=\frac{Q}{I}[/tex].
Explanation:
To solve the equation, [tex]I= \frac{Q}{t}[/tex] for the variable t, you need to isolate t on one side of the equation. This can be done by rearranging the equation algebraically. Here's how it is done step-by-step:
Multiply both sides of the equation by t to get t × I = Q.
Next, divide both sides of the equation by I to solve for t, so we have [tex]t=\frac{Q}{I}[/tex].
Through these steps, we've successfully isolated t and found that the time (t) is equal to the charge (Q) divided by the current (I).
A 48.4-g sample of glucose (a nondissociated, nonvolatile solute with the formula c6h12o6) is dissolved in 151.2 g of water. what is the vapor pressure of this solution at 100°c?
Answer:
Vapor pressure of solution is 736mmHg
Explanation:
Vapor pressure of an ideal solution follows Raoult's law:
[tex]P_{solution} = X_{solvent}P_{solvent}[/tex]
Where P is vapor pressure and X is mole fraction
Moles of glucose are:
48.4g × (1mol / 180.156g) = 0.2687mol glucose
Moles of water:
151.2g × (1mol / 18.1g) = 8.354 mol water
Thus, mole fraction of water (Solvent) is:
8.354 mol / (8.354 mol + 0.2687mol) = 0.9688
Vapor pressure of a solvent at boiling point is equal to atmospheric pressure (760mmHg). Replacing in Raoult's law:
[tex]P_{solution} = 0.9688*760mmHg[/tex]
Vapor pressure of solution is 736mmHg
The vapor pressure of the solution will be "736 mmHg".
Vapor pressureAccording to the question,
Sample of glucose = 48.4 g
Mass of water = 151.2 g
Temperature = 100°C
Now,
Moles of glucose will be:
= 48.4 × ([tex]\frac{1 \ mol}{180.156}[/tex])
= 0.2687 mol
Moles of water will be:
= 151.2 × ([tex]\frac{1 \ mol}{18.1}[/tex])
= 8.354 mol
Water's moles fraction will be:
= [tex]\frac{Moles \ of \ water}{Moles \ of \ water +Glucose}[/tex]
By substituting the values,
= [tex]\frac{8.354}{8.354+0.2687}[/tex]
= 0.9688
hence,
By using Raoult's Law,
→ [tex]P_{solution}[/tex] = [tex]X_{solvent} P_{solvent}[/tex]
By substituting the values,
= 0.9688 × 760
= 736 mmHg
Thus the above solution is correct.55
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You purchase several rolls of fiberglass insulation and pay extra for installation. Have you purchased a product or a service?
You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.
What is fiberglass insulation?The majority of homes include fibreglass, an insulation substance made of incredibly thin glass fibres. It is frequently used in two forms of insulation: loose-fill and batts and rolls. Additionally, rigid boards or duct insulation are both options.
In accordance with the U.S. Department of Energy, manufacturers already make medium- and high-density fibreglass batt insulation materials with a little better R-Value than regular batts. Unfinished floors, ceilings, and walls can all be filled with fibreglass. It is set in place between beams, joists, and studs. You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.
Therefore, fiberglass insulation is a service.
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If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?
Answer:
I got .146 g of water
Explanation:
Refer to this equation:
Q= mcΔt
Q= .545 J
c= 4.186 J/g
Δt= .892
plug in values:
.545 J = m(4.186 J/g)(.892°C)
simplify:
.545 J = m(3.734 J/g°C)
.146 g
How many miles of C5H12 are there in 362.8 grams of the compound?
Answer:
5.03 moles
Explanation:
Find the molar mass of C5H12 and you will get 72.17 g/mol
Next to find the number of moles, you divide 362.8 by the molar mass and you get
(362.8 g)/(72.17 g/mol)= 5.03 moles
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B) type of bonds in the reactants C) effect of a stress on the system D) polarity of the product molecules
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".
Option: C
Explanation:
Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.
Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.
For a reaction system at equilibrium, the Le principle can be used to predict the effect of a stress on the system.
The Le principle is an observation about chemical equilibria of reactions. Le principle can be used to predict the effect of a stress like changing concentration of a substance has on a reaction system at equilibrium.
If the concentration of a reaction species is increased at constant Temperature and Volume, the equilibrium system will shift in the direction that reduces the concentration of that substance so we can conclude that the Le principle can be used to predict the effect of a stress on the system.
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Some farmers leave a strip of land around the edge of each field which they do
not spray with chemicals.
Suggest two reasons why this will lead to an increase in the number of partridges
on these farms.
Answer:
There are no caterpillars on the oak tree in winter. ... Some farmers spray their crops with chemicals to kill insects and weeds. ... Some farmers leave a strip of land around the edge of each field which they do not spray with chemicals.
Explanation:
Hope this help ;)
Farmers leaving unsprayed strips of land can increase partridge numbers due to safer habitats free from pesticides and better provision of food and nesting areas.
Explanation:Leaving a strip of land around the edge of each field unsprayed with chemicals will likely increase the number of partridges on these farms for two main reasons.
Pesticide avoidance provides a safe habitat for partridges and other wildlife, reducing mortality rates from chemical exposure. Habitat provision enhances the availability of food sources and nesting areas, encouraging the proliferation of partridge populations.Crop rotation is also a practice that allows farmers to improve soil fertility, diversify their crops, and reduce pesticide costs by breaking the cycle of weeds, insects, and diseases naturally.
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What volume of water should be used to dissolve 19.6 g of LiF to create a 0.320 M solution?
Answer:
2.4 L
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
A sample of gas occupies 280 mL when the pressure is 560.00 mm Hg . If the temperature remains constant , what is the new pressure if the volume changes to 560.0 mL?
Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 560.00 mmHg
[tex]P_2[/tex] = final pressure = ?
[tex]V_1[/tex] = initial volume = 280 mL
[tex]V_2[/tex] = final volume = 560.0 mL
Now put all the given values in the above formula, we get:
[tex]560.00mmHg\times 280 mL=P_2\times 560.0 mL[/tex]
[tex]P_2=280mmHg[/tex]
Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg
How many liters of 1.5 M potassium permanganate could be made if 152 g of the solute are available?
Answer:
0.64 L
Explanation:
Recall that
n= CV where n=m/M
Hence:
m/M= CV
m= given mass of solute =152g
M= molar mass of solute
C= concentration of solute in molL-1 = 1.5M
V= volume of solute =????
Molar mass of potassium permanganate= 158.034 g/mol
Thus;
152 g/158.034 gmol-1= 1.5M × V
V= 0.96/1.5
V= 0.64 L
Answer:
The volume of KMnO4 produced is = 16,013.7 Litres
Explanation:
Concentration = mass (in moles) ÷ volume (in litres)
1g = 158.03 moles
152g = 24,020.56 moles of KMnO4
1.5 M = mass (in moles) ÷ vol
⇒ Volume = [tex]\frac{24,020.56} {1.5}[/tex]
= 16,013.7 Litres