4 salt samples were each dissolved into 200 cm3 of water to determine their solubility. The amount of each salt that dissolved is recorded below: Magnesium chloride: 110 grams Sodium chloride: 76 grams Copper chloride: 139 grams Zinc chloride: 400 grams Order the salts from least soluble to most soluble
A. Copper chloride, sodium chloride, zinc chloride, magnesium chloride
B. Magnesium chloride, zinc chloride, sodium chloride, copper chloride
C. Sodium chloride, magnesium chloride, copper chloride, zinc chloride
D. Magnesium chloride, zinc chloride, copper chloride, sodium chloride

Answer:

The answer to your question is: less than

Explanation:

Some properties of matter depend on the amount of matter in a sample others do not.

Extensive properties: are properties that depend on the amount of matter in a sample. Ex. size, volume

Intensive properties: are properties that do not depend on the amount of matter in a sample. Ex. color, temperature, density, solubility, boiling point.

Then in your question boiling point does not depend on the amount of matter, then the boiling points will be the same as in number 1.

The boiling point of a substance is the temperature at which the substance changes to vapour. The value of M in the scenario given will be less than N

Given equal mass ;

Hence, 100°C < 300°C ; M < N

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Answer:

ΔG° = –7.4 kcal/mole

Explanation:

When there are coupled reactions taking place, we can say that their free energy variations are additive. Meaning that if there is a reaction A → B followed by B → C, each reaction will have its own free energy variation, ΔG°₁ and ΔG°₂. As both reactions are secuential, there is a global reaction taking place, which is A → C. This global reaction also has its own free energy variation, ΔG°total, which represents the sum of the individual free energy variations of the coupled reactions, ΔG°₁ +  ΔG°₂ = ΔG°total.

For this case we have, in the first reaction of glycolysis, there are two coupled reactions that take place:

(1) glucose + Pi → glucose 6-phosphate + H₂O

(2) ATP + H₂O → ADP + Pi

We know that the total variation of free energy for that reaction is:

ΔG°total =  –4.06 kcal/mole

But the individual variations of free energy, ΔG°₁ and ΔG°₂, are unknown, so we can propose the next equation:

ΔG°₁ + ΔG°₂ = –4.06 kcal/mole

Then we have another value given to us, the variation of free energy of the reversed first reaction (1), which would be:

(3) glucose 6-phosphate → glucose + Pi

ΔG°₃ = –3.34 kcal/mole

As this reaction is the reversed reaction of the first one (1), we can assume the next:

ΔG°₁  = (–1) * (ΔG°₃) = (–1) * (–3.34 kcal/mole) = 3.34 kcal/mole

So now that we have the value of ΔG°₁ we can substitute it in the proposed equation to find out the value of ΔG°₂ :

ΔG°₁ + ΔG°₂ = –4.06 kcal/mole

ΔG°₂ = –4.06 kcal/mole – ΔG°₁

ΔG°₂ = –4.06 kcal/mole – 3.34 kcal/mol

ΔG°₂ = –7.4 kcal/mole

So there it is, that is the value of the variation of free energy of the second reaction (2), which is the hydrolisis of ATP.

Final answer:

The ΔG° for hydrolysis of ATP to ADP and Pi, considering the ΔG° values given for the phosphorylation and dephosphorylation of glucose, is -7.40 kcal/mole.

Explanation:

The student asked for the ΔG° for the hydrolysis of ATP. In enzymatic reactions, the ΔG° of the reverse reaction is the negative of the ΔG° of the forward reaction. Given that hexokinase catalyzes the phosphorylation of glucose to glucose 6-phosphate with a ΔG° of -4.06 kcal/mole and the reverse reaction, catalyzed by glucose 6-phosphatase, has a ΔG° of -3.34 kcal/mole, we can find the ΔG° for hydrolysis of ATP by adding these two values (because to find the overall ΔG° for a coupled reaction, you sum the ΔG° values of the individual steps). The sum of -4.06 kcal/mole and -3.34 kcal/mole is -7.40 kcal/mole, which is the ΔG° for the hydrolysis of ATP to ADP and Pi.

Answer:

45.3 °C was the initial temperature

Explanation:

Step 1: explain the problem

We have to find the initial temperature, when a certain amount of heat raises this sample of water to its boiling point ( 100 °C)  

⇒this amount of heat = 5.61 x 10^5 J

We will use the formule : Q = mcΔT

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with ΔT = change in temperature ( in °C or K)

The  specific heat of water is 4.186 J/g °C

Step 2 : Calculate the initial temperature

To find the initial temperature, we have to rearrange the formule:

ΔT = Q / mc

In this case we have :

ΔT = 5.61 * 10^5 J / 2450 g * 4.186 J/g °C = 54.70

⇒ The final temperature of the water is the boiling point (100 °C). The change of temperature is 54.70  This means that the boiling point is 54.70°C higher than the initial temperature.

This means : ΔT = Tboiling point - Tinitial

ΔT = 54.70 °C = 100 °C - Tinitial

Tinitial = 100 °C - 54.70 °C = 45.3 °C

The initial temperature of the water is 45.3 °C

Answer:

B.  1.7 g/cm^3.

Explanation:

Density = mass / volume

= 520 / 300

=  1.733.

The density of a substance is calculated by dividing mass by the volume of the object. A substance weighing 520 grams has a density of 1.7 g/cm³. Thus, option B is correct.

Density has been constituted of mass in grams per cubic centimeter of substance. The volume inversely affects the density possessed by the substance. It gives the estimation of buoyancy and whether the object will float or sink.

It is calculated with the help of mass and volume and its formula is given as,

Density (D) = Mass (m) ÷ Volume (V)

Given,

Volume (V) = 300 cubic centimeter

Mass (m) = 520 grams

Density is calculated as,

Density (ρ) = Mass (M) ÷ Volume (V)

ρ = 520 ÷ 300

ρ =  1.733 grams per cubic centimeter

Therefore, option B. 1.7 grams per cubic centimeter is the density of the substance.

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Answer:

Double replacement reaction

Explanation:

Now, let us first write the reaction equation properly:

     H₂SO₄ + 2KOH ⇒ K₂SO₄ + 2H₂O

The above reaction is a neutralization reaction between an acid and a base whose product gives salt and water only at most instances.

From here, we can observe that the species displaces on another in their ionic state. Hydrogen replaces potassium and water is produced. Potassium combines chemically with sulfate ions to give the salt of potassium.

Answer:

The answer to your question is Endothermic reaction

Explanation:

Endothermic reactions are reactions that absorbe energy from the environment.

All the reactions that needs heat to proceed are endothermic, example: photosynthesis, reactions in the laboratory that are heated, heat our meals.

This is an endothermic reaction because the enthalpy of the products is higher than the enthalpy of the reactants,

A reaction diagram illustrates the changes in enthalpy and the reaction progression, with the 'hill' or 'saddle' shapes indicating the activation energy barriers in one-step or two-step reactions, respectively.

A reaction diagram illustrates the changes in enthalpy and the progression of a chemical reaction over time. The diagram you're describing, with either a 'hill' shape or a 'saddle' shape, represents the energy changes that occur during a chemical reaction. The vertical axis measures the enthalpy of the system, while the horizontal axis represents the reaction coordinate, showing the progress from reactants to products.

In a one-step reaction, the diagram shows one energy barrier to be overcome, which is represented by the 'hill' on the curve. This barrier is known as the activation energy, which is the energy required to initiate the reaction. In a two-step reaction, two such barriers exist, and the 'saddle' shape of the reaction curve reflects this. The highest points on these curves represent the transition states, which are unstable species that exist at the peak of the activation energy.

The type of reaction can often be determined by the relative energies of the reactants and products. If the products have lower energy than the reactants, the reaction is exothermic. Conversely, if the products have higher energy, the reaction is endothermic. The difference in enthalpy between the reactants and products indicates the overall energy change of the reaction.

Answer:

b. H3O c. H2SO4 d. HNO3

Explanation:

The hydrogen bonds can be form with molecules that have free electron pairs  and hydrogen atoms. In the case of NH4 molecule, the "free" electron pair in the nitrogen is not free because there is an hydrogen occuping them, and, in fact, this molecule has a positive charge. The other acids have free electron pairs in the oxigen, nitrogen or sulfur.

The molecules that have the ability to form hydrogen bonds with themselves

are H₃0, H₂SO₄, and HNO₃

The above element removes the high number of the electron density in the covalent bond with hydrogen, leaving the H atom lack or lower number of electron

An hydrogen bond is also defined as the electromagnetic attraction that is formed between a partially positively charged hydrogen atom fused to a highly electronegative atom and another close electronegative atom.

Conclusively, we can therefore say that option b, c, and d explain what the statement means.

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Answer:

47 g/mol

Explanation:

0.70 (50 amu) + 0.25 (35 amu) + 0.05 (70 amu) = 47 amu = 47 g/mol

Explanation:

The atomic weight of element X is calculated by taking the weighted average of the atomic masses of its isotopes. Considering the individual contribution of each isotope, which is determined by multiplying each isotope's atomic mass by its relative abundance, the atomic weight of element X is 47.25 amu.

The atomic weight of an element is calculated by taking the weighted average of the atomic masses of its naturally occurring isotopes. An isotope's contribution to the overall atomic weight is proportional to its abundance. In this case, Element X is composed of three isotopes A, B, and C.

Following are the contributions from each isotope:

So, by adding all these contributions, the atomic weight of element X would be 35 + 8.75 + 3.5 = 47.25 amu.

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Answer : The enthalpy change of reaction is -23.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

[tex]Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)[/tex]    [tex]\Delta H=?[/tex]

The intermediate balanced chemical reaction will be,

(1) [tex]2Fe(s)+\frac{3}{2}O_2(g)\rightarrow Fe_2O_3(s)[/tex]    [tex]\Delta H^o_1=-824.2kJ[/tex]

(2) [tex]CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)[/tex]    [tex]\Delta H^o_2=-282.7kJ[/tex]

First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :

(1) [tex]Fe_2O_3(s)\rightarrow 2Fe(s)+\frac{3}{2}O_2(g)[/tex]    [tex]\Delta H^o_1=+824.2kJ[/tex]

(2) [tex]3CO(g)+\frac{3}{2}O_2(g)\rightarrow 3CO_2(g)[/tex]    [tex]\Delta H^o_2=3\times (-282.7kJ)=-848.1kJ[/tex]

The expression for final enthalpy is,

[tex]\Delta H=\Delta H^o_1+\Delta H^o_2[/tex]

[tex]\Delta H=(+824.2kJ)+(-848.1kJ)[/tex]

[tex]\Delta H=-23.9kJ[/tex]

Therefore, the enthalpy change of reaction is -23.9 kJ

Answer:

Protein B with 58400 [tex]M_{r}[/tex]

Explanation:

[tex]M_{r}[/tex] is an abreviation of relative molecular mass and is a measure of weight in macromolecules such as proteins,.

If you compare and order the macromolecules [tex]M_{r}[/tex] you obtain:

[tex]58400 M_{r} >27000M_{r} >15600M_{r} >11300M_{r}[/tex]

Remember that the largest protein will emerge first of the gel filtration column, and so on, until the smalest protein have been emerged. The above due to the smallest protein moves a longer distance than the largest protein.

In view of the above the largest protein is protein B with 58400 [tex]M_{r}[/tex]

Answer:

The correct answer is "protein B, with ????r=58400Mr=58400".

Explanation:

A gel filtration column separates different molecules in a mixture according to their molar masses. The gel particles that comprise a gel filtration column are made of Sephadex, a porous material that retains low-molar-mass molecules. Therefore, the proteins that have the higher molecular masses will be the first to elute since they do not interact with the column. In this case, protein B with a molar mass of 58400 will be the first to elute

Answer:

The answer to your question is: 0.1 M

Explanation:

data

Volume of AgNO3 = 20.00 ml

                   1000 ml --------------  1 l

                       20 ml --------------- x              

          x = 20x 1 /1000 = 0.02

AgCl = 0.2867 g

MW of AgCl = 35.45 + 107.9 = 143.35 g

                       143.35 g -------------- 1 mol

                       0.2867 g -------------  x

  x = 0.2867 x 1 / 143.35 = 0.002 moles of AgCl

   From the balance reaction we see that the proportion of AgNO3 to AgCl is 1:1, then

           1 mol of AgNO3 -------------------- 1 mol of AgCL

                 x                   ---------------------  0.002 moles of AgCl

 x = 0.002 moles of AgNO3

   This moles of AgNO3 are in 20 ml or 0.02 liters

So, Molarity = # moles/liter

      Molarity = 0.002 moles/ 0.02 = 0.1 M

Acidity.  As you go down it’s more of an acid as you go up it becomes more of a base

Final answer:

A decrease in pH from 9 to 8 indicates an increase in the concentration of [OH-] tenfold (10X).

Explanation:

The pH of a solution is a measure of how acidic or basic it is. A pH of 9 indicates a basic solution, while a pH of 8 indicates a slightly less basic solution. As the pH decreases from 9 to 8, the concentration of [OH-] increases tenfold (10X) compared to what it was at pH 9.

Answer: The correct answer is Option 5.

Explanation:

[tex]M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of the NaOH.

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the [tex]Ca(OH)_2[/tex]

We are given:

[tex]n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL[/tex]  

Putting all the values in above equation, we get:

[tex]M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M[/tex]

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base.

We are given:

[tex]n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL[/tex]

Putting values in above equation, we get:

[tex]1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M[/tex]

Hence, the correct answer is Option 5.

The molarity of the HCl solution used to neutralize a basic solution of NaOH and Ca(OH)2 is 0.060 M. The correct answer is option 5.

The question asks about the molarity of the HCl solution used to neutralize a basic solution of NaOH and Ca(OH)2. The first step is to determine the moles of OH- ions contributed by both NaOH and Ca(OH)2. Next, the moles of HCl need to be found because in a neutralization reaction, the moles of H+ ions (from HCl) will equal the moles of OH- ions (from NaOH and Ca(OH)2). The molarity of the HCl is then calculated by dividing the moles of HCl by the volume of the HCl solution which is given in mL but needs to be converted to L for this calculation.

First, calculate the number of moles from each OH- source: NaOH (0.10 M x 0.050 L = 0.005 moles) and Ca(OH)2 (2 x (0.10 M x 0.050 L) = 0.01 moles) because each formula unit of Ca(OH)2 supplies 2 OH- ions. So, total moles of OH- = 0.005 moles + 0.010 moles = 0.015 moles.

Since the moles of H+ ions (from HCl) equals the moles of OH- ions (from NaOH and Ca(OH)2), the moles of HCl also equals 0.015 moles. Finally, calculate the molarity of the HCl solution: Molarity = Moles / Volume = 0.015 moles / 0.250 L = 0.060 M.

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Generally, the solubility of solids in water increases with increasing temperature. Nevertheless, there are exceptions with some solids and gases. Temperature can be used to create supersaturated solutions, where more solute is dissolved than the equilibrium solubility.

In terms of the solubility of solids in water, generally the solubility increases with increasing temperature. This can be verified by the general trend observed in the solubility curves of various substances, as represented in Figure 11.16. However, there are exceptions to this typical behavior, such as the ionic compound cerium sulfate, which is less soluble at higher temperatures.

The temperature dependence of solubility can be applied in creating supersaturated solutions, where a higher concentration of solute is retained in the solution than what is achievable at equilibrium. This is done by dissolving the solute at a higher temperature and then cooling the solution without allowing the excess solute to precipitate. In some instances, the solubility of gases in water decreases with increasing temperatures.

The dissolution process is influenced by several factors, including temperature, pressure, and the nature of the solute and solvent. Practically speaking, while some solids are entirely insoluble in water, many others exhibit significant solubility.

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The correct answer is: increases with increasing temperature.

The solubility of the majority of solid substances tends to increase as the temperature increases. This trend can be visualized using solubility curves, which graphically represent the relationship between solubility and temperature.

However, it is essential to note that there are exceptions, as certain compounds may show little change or even a decrease in solubility with rising temperature, such as cerium sulfate.

Examples:

Understanding the general trend and exceptions can help predict the behavior of different substances when dissolved in water at various temperatures.

Answer:

The names or formulas are below, just look for the the names or symbols in the tables, write them and cross the powers without the signs.

Explanation:

Ammonium sulfide         (NH₄)₂S

Iron III chloride                FeCl₃

Aluminum Nitrate

Barium acetate               Ba(C₂H₃O₂)₂

Calcium bromide

Sodium nitrate

Lithium oxide               Li₂O

Copper II bromide       CuBr₂

Calcium hydroxide

Ammonium phosphate

Magnesium nitrate

Strontium nitrate          Sr(NO₃)₂

Silver sulfide                 Ag₂S

Cobalt III hydroxide      Co(OH)₃

Copper II chloride

Potassium sulfide

Iron III sulfate

Mg₃(PO₄)₂

Sn(NO₃)₄

Sodium phosphate

To determine the limiting reactant, compare the moles of N2 and H2. The excess reactant can be determined by subtracting the moles of the limiting reactant used from the moles of the excess reactant initially present. The amount of NH3 formed can be calculated using the stoichiometry of the balanced equation.

To determine the limiting reactant in this reaction, we need to compare the moles of N2 and H2. The balanced equation tells us that it takes 1 mole of N2 to react with 3 moles of H2 to produce 2 moles of NH3. Therefore, if we have 2.00 moles of N2 and 4.00 moles of H2, the limiting reactant is the one that runs out first. Since 1 mole of N2 reacts with 3 moles of H2, we need 6.00 moles of H2 to react completely with 2.00 moles of N2. The excess reactant can be determined by subtracting the moles of the limiting reactant used from the moles of the excess reactant initially present. In this case, the excess reactant is H2, and the amount of excess H2 remaining can be calculated. Lastly, to determine the amount of NH3 formed, we use the stoichiometry of the balanced equation. Since the balanced equation tells us that 1 mole of N2 produces 2 moles of NH3, we can calculate the moles of NH3 formed from the moles of N2 used.

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Answer:

[tex][OH^-]^2=2.0\times 10^{6}[/tex]

Explanation:

The ionization constant of the water = [tex]4.0\times 10^{12}[/tex] at a temperature of [tex]112\ ^0C[/tex] and pressure of 20 MPa

Water dissociates as;

[tex]H_2O\rightleftharpoons H^++OH^-[/tex]

The expression for the ionization constant is :

[tex]K_w=[H^+][OH^-][/tex]

For pure water,

[tex][H^+]=[OH^-][/tex]

So,

[tex]K_w=[OH^-]^2[/tex]

[tex][OH^-]^2=4.0\times 10^{12}[/tex]

The concentration of the hydroxide ions, [tex][OH^-]^2=2.0\times 10^{6}[/tex].

Answer:

c. temperature and water vapor content.

Explanation:

The density of any substance is dependent of temperature, and in gases, the variations is greater than in any other substance, therefore, temperature is very important to calculate air density. Also, the concentration of water vapor in the air can vary depending  where is located, and that concentration will affect the density because it affects the average mass of air.

Answer:

c. temperature and water vapor content is the correct answer.

Explanation:

temperature and water vapor content are the two most important in determining the density of air.

When the temperature gets increase it results in the increase of volume and density gets decreases.

Temperature is an important factor to determine the air density.

The concentration of water vapor in the air change depending on where it is placed and so when water vapor is added it will change the density of air because it changes the average mass of air and density gets decrease.

Answer:

The answer to your question is: c) Water reacts with group 1 metals

Explanation:

A chemical property is a property that shows a change in the original molecule.

a) Water is a polar molecule  This is a physical property of water, it doesn't change the original composition of water. This option is incorrect.

b) Water is the universal solvent.  This is also a physical property of water, when water dissolves something it continues being water, then this answer is incorrect.

c) Water reacts with group 1 metals  Most of the reactions are chemical properties in this example when water reacts with a metal there is a change. This is the right option.

d) Water has a high specific heat capacity. This option is not correct, heat capacity is not a chemical property is a physical one.

Answer:

it is C!

Explanation:

i did the quiz on usatestprep

Answer:

189.91g

Explanation:

Given parameters:

Mass of beaker with oil = 200.6g

Mass of beaker = 10.69g

Unknown:

Mass of corn oil = ?

Solution:

To find the mass of corn oil, we know that:

 Mass of beaker with oil = Mass of beaker + mass of corn oil

Therefore:

           Mass of corn oil = Mass of beaker with oil - Mass of beaker

    Mass of corn oil = (200.60 - 10.69)g

    Mass of corn oil = 189.91g

An example of a solution is D. A mixture of rock granules .

- A solution is a homogeneous mixture composed of a solute dissolved in a solvent.
- In this example, sugar acts as the solute and tea acts as the solvent.
- When sugar is added to tea and stirred, it dissolves and becomes evenly distributed throughout the tea.
- The resulting mixture is a solution, where the sugar particles are dispersed at the molecular level in the tea.
- This is different from a mixture like sand, where the components (rock granules and bits of shell) are physically mixed but not dissolved in each other.

In summary, sugar dissolved in tea is an example of a solution because it involves a solute (sugar) being dissolved in a solvent (tea) to form a homogeneous mixture.

Hence Option D is correct.

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Final answer:

Sugar dissolved in tea is the example of a solution because it is a homogeneous mixture with a uniform composition, whereas the other options are either pure elements or heterogeneous mixtures.

Explanation:

The example of a solution in the choices provided is C. Sugar dissolved in tea. A solution is defined as a homogeneous mixture where the composition is uniform throughout. In sugar dissolved in tea, the sugar particles are completely dispersed in the water, and everywhere in the solution the composition is consistent, making it a homogeneous mixture (solution).

Other options provided such as B. Mercury is a pure element, not a solution. D. A mixture of rock granules and bits of shell known as sand is a heterogeneous mixture because its components can be physically distinguished, and its composition is not uniform throughout.

Aldehydes can be oxidized to form organic acids, specifically carboxylic acids, not ketones. Primary alcohols can also be oxidized to aldehydes and then further to carboxylic acids.

When discussing the oxidation of aldehydes, it's important to understand that they can be further oxidized to form organic acids, specifically carboxylic acids. This is in contrast to primary alcohols, which can be initially oxidized to aldehydes and then further to carboxylic acids if the oxidation conditions are strong enough. Therefore, aldehydes do not oxidize to form ketones, but rather to organic acids.

It's noteworthy that primary alcohols like RCH₂OH can be selectively oxidized to aldehydes using milder oxidizing agents such as PCC or DMP. In comparison, secondary alcohols are oxidized to form ketones, and tertiary alcohols do not oxidize readily. However, the oxidation of aldehydes takes them one step further, from the aldehyde stage to the carboxylic acid stage.

Explanation:

The given precipitation reaction will be as follows.

        [tex]AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)[/tex]

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = [tex]\frac{\text{no. of moles}}{\text{volume in liter}}[/tex]

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

                    Molarity = [tex]\frac{\text{no. of moles}}{\text{volume in liter}}[/tex]

                     0.269 M = [tex]\frac{\text{no. of moles}}{1.14 L}[/tex]

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                   0.307 mol = [tex]\frac{mass}{143.32 g/mol}[/tex]

                           mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

Answer:

C7H5N3O6

Explanation:

C = 12 g/mol

O = 16 g/mol

H = 1 g/mol

N = 14 g/mol

CO2 = 44 g/mol

H2O = 18 g/mol

NH3 = 17 g/mol

* 44 g CO2 is produced from 12 g C

0.213 g CO2 is produced from = (12)(0.213) / 44 = 0.0581 g C present in 0.157 g compound.

* 18 g H2O is produced from 2 g H

0.0310 g H2O is produced from = (2)(0.0310) / 18 = 0.0034 g H present in 0.157 g compound.

* 17 g NH3 is produced from 14 g N

0.0230 g NH3 is produced from = (14)(0.0230) / 17 = 0.0189 g N present in 0.103 g compound.(this is different)

If in 0.103 g compound there is 0.0189 g N

in 0.157 g compound there is ;

(0.157)(0.0189) / 0.103 = 0.0288 g N

* Mass of C, H and N = 0.0581 + 0.0034 + 0.0288 = 0.0903 g

The rest is mass of O = 0.157 - 0.0903 = 0.0667 g

Moles of elements in the compound sample:

C = 0.0581 g / 12 g/mol = 0.00484 mol

H = 0.0034 g / 1 g/mol = 0.0034 mol

N = 0.0288 g / 14 g/mol = 0.00205 mol

O = 0.0667 g / 16 g/mol = 0.00417 mol

Smallest mole ratio:

N = 0.00205 / 0.00205 = 1.00

C = 0.00484 / 0.00205 = 2.36

H = 0.0034 / 0.00205 = 1.66

O = 0.00417 / 0.00205 = 2.00

Multiplying by 3 we get;

N = 3

C = 7

H = 5

O = 6

Simplest formula:

C7H5O6N3

This is probanly TNT (trinitrotoluen)

Final answer:

The empirical formula of the compound is determined by converting the masses of CO2, H2O, and NH3 to moles of C, H, and N, respectively, and then finding the simplest whole number ratio of these elements.

Explanation:

To determine the empirical formula of the compound, we must first find the number of moles of carbon, hydrogen, and nitrogen in the given samples.

From the combustion data of carbon to CO₂, we use the mass of CO₂ to find the moles of carbon. The molar mass of CO₂ is 44.01 g/mol, so:

0.213 g CO₂ × (1 mol CO₂ / 44.01 g CO₂) = 0.00484 mol CO₂

Each mole of CO₂ contains 1 mole of carbon, so:

0.00484 mol CO₂ × (1 mol C / 1 mol CO₂) = 0.00484 mol C

Similarly, from the mass of H₂O, we find the moles of hydrogen. The molar mass of H₂O is 18.02 g/mol, so:

0.0310 g H₂O × (1 mol H₂O / 18.02 g H₂O) = 0.00172 mol H₂O

Each mole of H₂O contains 2 moles of hydrogen, hence:

0.00172 mol H₂O × (2 mol H / 1 mol H₂O) = 0.00344 mol H

For nitrogen, the molar mass of NH₃ is 17.03 g/mol, which means:

0.0230 g NH₃ × (1 mol NH₃ / 17.03 g NH₃) = 0.00135 mol NH₃

Each mole of NH₃ contains 1 mole of nitrogen, thus:

0.00135 mol NH₃ × (1 mol N / 1 mol NH₃) = 0.00135 mol N

Finally, to find the ratio of atoms in the empirical formula, divide the moles of each element by the smallest number of moles obtained:

The empirical formula is C₄H₃N. The oxygen content is assumed to make up the remainder of the compound's mass. However, since the combustion analysis provides information for C, H, and N only, we'll stop at determining their ratios.

Answer:

The average is 63.6

Explanation:

Step 1: Calculate the total points of all tests together

The total of the 4 tests is : 83.2 points + 44.6 points + 74.4 points + 52.3 points = 254.5 points

Step 2: Calculate the average points

We have 4 tests so we divide the total number by 4

254.5 points  / 4 = 63,625 points

Step 3: take significant digits into account

Sum or difference : Add or subtract in the normal way, then round the answer to the LEAST number of places to the decimal point of any number in the problem

⇒ in this case : 83.2 + 44.6 + 74.4 + 52.3 = 254.5

Multiplication and division: the answer is reported in such a way that it reflects the reliability of the least precise operation. Your answer cannot be MORE precise than the least precise measurement.

254.5 / 4 = 63.6

Answer:

From hypotonic to hypertonic

Explanation:

Water diffusion is a phenomenon that occurs when a solute (eg. a salt) is present in different concentrations in different areas. Because the concentration is inversely proportional to volume (meaning that the higher the volume, the lower the concentration), water will move from areas with lower concentration (hypotonic) to areas with higher concentration (hypertonic), so as to match the concentrations.

Answer:

Water will move from hypotonic to hypertonic solutions

Explanation:

When a hypotonic solution is separated by a permeable membrane from another solution with more solute (hypertonic), water will move across the membrane until both solutions have the same concentration: when water comes into the compartment with hypertonic solution, this solute dissolves.

Water will not move from hypertonic to hypotonic without energy addition.

Answer:

The answer to your question is: water, polar solvent.

Explanation:

Data

sample of CaCl2

Solid copper this option is incorrect because in order to dissolve something the solvent must be liquid and this is a solid solvent.

water, I think this option is right, because CaCl2 is ionic and water is a polar solvent, CaCl2 will dissolve in water.

a polar solvent, CaCl2 will dissolve is a polar solvent like water, this option is correct.

hexane, CaCl2 will not dissolve in hexane because hexane is a non polar solvent and CaCl2 is ionic. This option is wrong

a nonpolar solvent This option is not right, CaCl2 will only dissolve in polar solvents.

liquid mercury, This option is wrong, mercury is not a solvent.

Matthias can dissolve the calcium chloride, an ionic compound, in water, a polar solvent. Solid copper, hexane, and liquid mercury won't effectively dissolve it.

Matthias can dissolve the sample of calcium chloride, an ionic compound, in water. Water is a polar solvent and is known for its ability to dissolve a variety of compounds, especially ionic compounds. The process of dissolution occurs because water molecules can attract and surround the ions in the calcium chloride, leading to its dissolution. On the other hand, solid copper, hexane (a nonpolar solvent), and liquid mercury will not effectively dissolve the calcium chloride.

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Answer:

The answer to your question is: 53.46 % pure

Explanation:

data

Fe = 1.92 ✕ 103 kg   produced    = 1920 kg

Fe2O3 = 5.13 ✕ 103 kg    sample   = 5130 kg

MW Fe2O3 = (56x2)+(16x3) = 160 kg

% of purity = ?

                   Fe2O3 + 3 CO → 2 Fe + 3 CO2

Convert mass to moles

Fe

      56 kg  --------------------- 1 mol

  1920 kg ---------------------   x moles       x = 34.28 moles

From the reaction

   1 mol of Fe2O3 ---------------------  2 moles of Fe

      x moles of Fe2O3 --------------- 34.28 moles

  x = 34.28/2 = 17.14 moles of Fe2O3

       160 kg of FE2O3 ----------------  1 mol

             x kg of Fe2O3---------------  17.14 moles

x = 17.14 x 160/1 = 2742,4 kg of Fe2O3  It's supposed to be the amount of Fe if it was 100% pure.

                             2742.4 kg of Fe2O3 ----------------  100%

                              5130 kg of Fe2O3 -------------------   x

x = (2742.4x100)/5130 = 53.46 pure

Answer:

The respective figure with label and targets is missing but yet the definitions and stability considerations can help you, so I explain them below.

Explanation:

Remember these definitions:

Hence,

The neutrons provide stability to the nucleus of the atom by compensating the electrostatic repulsion force that arise from the fact that positive charges are forced to be so close in the nucleus.

Since the more protons are added to the nucleus the stronger the repulsive force inside the nucleus are, as the atomic number increase the neutron number must increase too.

For the ligther elements (lower atomic and mass numbers) the ratio of neutrons to protons is very close to 1.

For heavier elements (greater atomic and mass numbers) the ratio of neutrons to protons increase: proportionally more neutrons are needed to provide stability to the nucleus.

Final answer:

The atomic number is defined by the number of protons, and an element's mass number is the total of its protons and neutrons. Isotopes have different numbers of neutrons, thus changing the mass number, while the atomic number remains constant. The atomic mass is an average of the mass numbers of an element's isotopes.

Explanation:

The atomic number and mass number of an element are essential concepts in chemistry. The atomic number of an element is defined by the number of protons in its nucleus and is used to distinguish one element from another. The mass number, on the other hand, is the sum of the number of protons and neutrons within the nucleus. It is important to note that electrons contribute negligibly to an element's mass and are, therefore, often disregarded when calculating the mass number.

Isotopes are different forms of the same element that vary only in their number of neutrons. This variability can change the mass number, and thus, isotopes of the same element will have slightly different mass numbers. Since the atomic number remains unchanged (protons do not change), the number of neutrons can be calculated by subtracting the atomic number from the mass number. The atomic mass of an element is a weighted average that reflects the mass numbers of all its naturally occurring isotopes, and is often a decimal number as a result.

Answer : The molar mass of unknown compound is 152.38 g/mole

Explanation :

Depression in freezing point = [tex]1.9^oC[/tex]

Mass of unknown compound = 16.5 g

Mass of water = 106.0 g

Formula used :  

[tex]\Delta T_f=i\times K_f\times m\\\\\Delta T_f=i\times K_f\times\frac{\text{Mass of unknown compound}}{\text{Molar mass of unknown compound}\times \text{Mass of water in Kg}}[/tex]

where,

[tex]\Delta T_f[/tex] = depression in freezing point

i = Van't Hoff factor = 1 (for non-electrolyte)

[tex]K_f[/tex] = freezing point constant for water = [tex]1.86^oC/m[/tex]

m = molality

Now put all the given values in this formula, we get

[tex]1.9^oC=1\times (1.86^oC/m)\times \frac{16.5g\times 1000}{\text{Molar mass of unknown compound}\times 106.0g}[/tex]

[tex]\text{Molar mass of unknown compound}=152.38g/mole[/tex]

Therefore, the molar mass of unknown compound is 152.38 g/mole

Answer: The molar mass of the unknown compound is 152 g/mol.

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f-^0T_f=(0-(-1.9)^0C=1.9^0C[/tex] = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

[tex]K_f[/tex] = freezing point constant = [tex]1.86^0C/m[/tex]

m= molality

[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]

Weight of solvent (water)= 106.0 g = 0.106 kg

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 16.5 g

[tex]1.9=1\times 1.86\times \frac{16.5g}{M g/mol\times 0.106kg}[/tex]

[tex]M=152g/mol[/tex]

Thus the molar mass of the unknown compound is 152 g/mol.