4. When referring to the element phosphorus on the periodic table
osphorus on the periodic table, the number 15 represents
A. energy level.
B. atomic weight.
C. atomic number.
D number of atoms.

Answer: C. Mass divided by volume

Explanation:

The slope of a line is equal to the rise over run meaning y over x. Mass is the y value and volume is the x value.

Answer:44m/s

Explanation:

The final speed of the car will be 150 m/s. The correct option is B.

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.

Given that a race car travelling at 10. meters per second accelerates at the rate of 1.5 meters per second while travelling a distance of 7,467m.

The final speed of the car will be calculated as,

V² = u² + 2aS

V² = (10)² + ( 2 x 1.5 x 7467 )

V² = 100 + 22401

V = √22501

V = 150 m/s

Therefore, the final speed of the car will be 150 m/s. The correct option is B.

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Answer:

Respiratory system takes Oxygen in and carbon dioxide out. Taken Oxygen by respiratory system is delivered to all the cells in our body by the help of vessels and blood in circulatory system.

Explanation:

Final answer:

The circulatory and respiratory systems synergistically facilitate gas exchange; the respiratory system provides oxygen and expels carbon dioxide, while the circulatory system transports these gases. The structures of both systems, such as the alveoli and capillary networks, are adapted for this efficient exchange. Homeostasis is maintained through the respiratory and cardiovascular collaboration.

Explanation:

The circulatory and respiratory systems are structured to work collaboratively in the exchange of gases to sustain life. The main function of the respiratory system is to supply the body with oxygen and remove carbon dioxide, which involves structures such as the nasal cavity, pharynx, larynx, trachea, bronchi, bronchioles, and alveoli. Air first enters through the nasal cavity and progresses through these structures. The terminal part of the respiratory system, the alveoli, is where the gas exchange takes place; they are tiny sacs with thin walls that allow oxygen and carbon dioxide to move between the lungs and bloodstream.

The cardiovascular system or circulatory system includes the heart and a vast network of blood vessels. The heart pumps oxygenated blood from the lungs to the body and deoxygenated blood from the body to the lungs. This essential collaboration allows oxygen to be delivered to the cells for aerobic respiration and carbon dioxide to be expelled. Remarkably, the homeostasis of gases is maintained through this constant exchange, facilitated by the complementing structures of both systems.

The organ that is part of both the respiratory and digestive systems is the pharynx, illustrating how organs can serve multiple body systems. Moreover, the extensive capillary network surrounding the alveoli highlights the intimate contact necessary for efficient gas exchange.

Answer:

(a) Kinetic energy of the cart is 648.32 J.

(b) Speed of the cart is 11.44 m/s.

Explanation:

From the attached below figure we came to know that,

Mass of the crate is 10 kg (m)

Initial speed of the crate is 1.2 m/s (v)

Coefficient of friction on a rough plane is 0.286 (µ)

Force on the cart is 150 N (F)

The distance which crate is moved (d) is 8.05 m.

[tex]\text { Angle at which cart is moved is } 27^{\circ}(\theta)[/tex]

[tex]\text { "g" acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]

Calculation of kinetic energy:

Acceleration of the cart:

We know that,

F = F – m × g × sinθ - µ × m × g × cosθ (F = ma)

m × a =  F – m × g × sinθ - µ × m × g × cosθ

10 × a = 150 – (10 × 9.8 × sin 27) – (0.286 × 10 × 9.8 × cos 27)

10 × a = 150 – 44.49 – 24.97

10 × a = 80.54

[tex]\mathrm{a}=\frac{80.54}{10}[/tex]

[tex]\mathrm{a}=8.054 \mathrm{m} / \mathrm{s}^{2}[/tex]

Change in kinetic energy = m × a × d

Change in kinetic energy = 10 × 8.054 × 8.05

Change in kinetic energy = 648.32 J

Calculation of speed:

[tex]\text { Speed of the crate is }\left(v_{f}^{2}\right)=v^{2}+2 a d[/tex]

[tex]\text { Speed of the crate is }\left(v_{\mathrm{r}}^{2}\right)=1.2^{2}+2 \times 8.054 \times 8.05[/tex]

[tex]\text { Speed of the crate is }\left(v_{f}^{2}\right)=1.44+129.66[/tex]

[tex]\text { Speed of the crate is }\left(v_{f}^{2}\right)=131.1[/tex]

[tex]\text { Speed of the crate is }\left(\mathrm{v}_{\mathrm{f}}\right)=\sqrt{131.1}[/tex]

[tex]\text { Speed of the crate is }\left(v_{f}\right)=11.44 \mathrm{m} / \mathrm{s}[/tex]

The change in kinetic energy of the crate is 1207.5 J. The final speed can't be accurately determined without knowing the initial speed and the mass of the crate.

The subject of this question is physics specifically, it relates to the concepts of force, kinetic energy, and speed.

a) The change in kinetic energy can be calculated using the concept of work done by the force. Since the force is acting in the direction of motion, Work done by the force = Force x displacement = 150 N * 8.05 m = 1207.5 J. This work done by the force results in the change in kinetic energy of the crate, so the change in kinetic energy is 1207.5 J.

b) Without knowing the initial speed and the mass of the crate, it's impossible to accurately calculate the final speed of the crate, since acceleration caused by the force (which relies on mass) and initial speed are factors in determining final speed.

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Answer:

A windmill. Windmills are used to harness the wind through the motion of the windmills wheels spinning. Usually, windmills are used to grind grain or pump water but now with a more modern version called the wind turbine, we can use the wind to generate energy.

Explanation:

this is one example you could use remember to change it up! :)

Three examples of machines that humans have designed are the lever, pulley, and wheel and axle. They all take advantage of mechanical advantage to reduce the input force needed by spreading the force over a greater distance.

The first machine we can consider is the lever. A lever is a simple machine that provides a mechanical advantage by increasing the distance over which an input force is applied, hence, reducing the input force needed to accomplish the same amount of work. Consider a seesaw; when one side is pushed down with a certain force, the other side goes up.

Another machine is the pulley. It reduces the effort required to lift an object by spreading the work over a longer length of rope. For example, a pulley system used in construction cranes makes it easier to lift heavy loads.

The third machine is the wheel and axle. It gives a mechanical advantage by allowing the user to exert force over a greater distance. An example of this is the use of wheel and axles in bicycles; pedaling covers a long distance but requires less force.

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The magnitude of the air drag is 784 N

Explanation:

When the airman is falling down, there are two forces acting on him:

- The force of gravity, downward, of magnitude

[tex]F=mg[/tex]

where

m = 80 kg is the mass of the airman

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

- The air drag, upward, of magnitude [tex]F_D[/tex], whose value is proportional to the speed of the airman

At the beginning of the fall, the speed is zero, so the air drag is also zero and therefore the airman starts accelerating due to the presence of the force of gravity, which is unbalanced. However, as the airman falls down, he gains speed, so the magnitude of the air drag increases up to a point where it becomes equal to the magnitude of the force of gravity. When this occurs, the airman no longer accelerates and continues its motion at constant velocity, which is called terminal velocity.

Therefore, at terminal velocity, the air drag is equal to the force of gravity on the airman (the weight), so we can write:

[tex]F_D = mg = (80)(9.8)=784 N[/tex]

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Voltage differences create an electric field that pushes free charges through a conductor, resulting in an electric current. This occurrence is explained by Ohm's Law, which states that current is directly proportional to the voltage applied to a conductor. Conventional current flows from the positive to the negative terminal although electrons, the actual charge carriers in metals, move in the opposite direction.

Voltage differences are what drive an electric current in a conductor. When a voltage source such as a battery or a generator is connected to a conductor, it applies a potential difference that creates an electric field. This electric field exerts a force on free charges, causing them to move and create an electric current. In a material like a metal wire, the current is carried by the movement of electrons, which are negative charges moving from the negative terminal to the positive terminal. When discussing current flow, we often refer to the term "conventional current," which flows from the positive terminal to the negative terminal, even though the actual charge carriers (electrons) move in the opposite direction. This stems from historical convention initiated by Benjamin Franklin.

According to Ohm's Law, the current that flows through a substance is directly proportional to the voltage applied to it, which means that a higher voltage will generally result in a larger current, assuming the resistance of the material does not change. If charges accumulate at certain points, reducing the voltage there, the electric field will adjust to push the current toward areas with higher voltage. In static conditions, excess charges collect along the surface of a conductor until static equilibrium is reached.

The angular acceleration is [tex]6.25 rad/s^2[/tex]

Explanation:

To solve this problem we can use the equivalent of Newton's second law for rotational motions:

[tex]\tau = I \alpha[/tex] (1)

where

[tex]\tau[/tex] is the torque acting on the body

I is the moment of inertia of the body

[tex]\alpha[/tex] is the angular acceleration

In this problem we have:

[tex]\tau = 450 Nm[/tex] is the torque

The moment of inertia of a solid cylinder about its axis is

[tex]I=\frac{1}{2}MR^2[/tex]

where

M = 100 kg is the mass

R = 1.2 m is the radius

Substituting,

[tex]I=\frac{1}{2}(100)(1.2)^2=72 kg m^2[/tex]

And solving eq.(1) for [tex]\alpha[/tex], we find the angular acceleration:

[tex]\alpha = \frac{\tau}{I}=\frac{450}{72}=6.25 rad/s^2[/tex]

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Answer:

wind

Explanation:

A steeper incline plane will require more force to move an object up. This is because the component of the gravitational force acting parallel to the incline increases with the steepness, necessitating a greater force to oppose it. The force required to move objects up an incline plane, therefore, increases with the steepness of the incline.

When analyzing an object at rest on an inclined plane, the force of gravity acting on the object is divided into two crucial components - a force acting perpendicular to the plane and a force acting parallel to the plane. The perpendicular force of weight is typically equal in magnitude, but opposite in direction to the normal force. However, the force that impacts the effort needed to move an object up an incline directly is the component of force acting parallel to the plane.

As the slope of an incline plane gets steeper, this parallel component of the gravitational force increases, and it requires more force to oppose this component and move the object up the incline. Therefore, a steeper incline plane will require more force to move an object up.

In simpler terms, think of it as pushing a cart up a steep hill versus a gentle slope - the steeper hill requires more effort, or force, to push the cart up.

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Since Amaya ran around a 1 mile track 3 times we can multiply this to find the total distance she traveled (displacement).

3 x 1 = 3 miles traveled.

-----------

Formula: [tex]V_a_v_g~=~\frac{displacement}{change~in~time}[/tex]

-----------

In this question the variables are classified as:

Displacement = 3 miles

Change in Time = 45 minutes

-----------

Now, fill in the expression to solve.

[tex]V_a_v_g~=~\frac{45}{3}\\V_a_v_g~=~15~[/tex]

-----------

Amayas average velocity is 15 minutes per mile.

______

Best Regards,

Wolfyy :)

Average Velocity = (displacement) / (time)

Displacement = distance and direction between the start-point and end-point, no matter what happens in between.

Amaya ran around the track, so she ended in the same place she started. The distance between her start-point and end-point was zero.  So . . .

Average Velocity = zero.

= = = = = = = = = =

Average Speed = (distance covered) / (time to cover the distance)

Amaya's distance = (1 mile/track) x (3 tracks) = 3 miles

Time to cover the distance = (3/4 hour)

Average speed = (3 miles) / (3/4 hour)

Average speed = (3 ÷ 3/4) mi/hr

Average speed = (3 x 4/3) mi/hr

Average speed = 4 miles per hour

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

Answer:

B

Explanation:

Answer: B Potential

Explanation:

Because the object can, when interacted, become kinetic (falling down the tree). Kinetic energy is energy in motion, while potential energy means it can become kinetic at any time.

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

[tex]\sum F_x = ma_x[/tex]

where

m is the mass of the block

[tex]a_x[/tex] is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

[tex]a_x = 0[/tex]

So the equation becomes

[tex]\sum F_x = 0[/tex] (1)

The net force here is given by

[tex]\sum F_x = F cos \theta - F_f[/tex] (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

[tex]F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N[/tex]

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Answer:

A

Explanation:

because u are subtracting if this is from flvs that is what i did and it was right

Answer:

A 0.89m

Explanation:

V= fλ

λ= V/f

λ=346/358

λ=0.89m

In order to have a verified or reliable answer to this question, they should take the watch apart and test the mechanism to see what causes failure.

Answer: Option D

Explanation:

For dropping a similar watch to record results, we need to buy another one. So, it becomes expensive. And, calling the manufacturer will give accurate results, but no knowledge. It is like getting multiple choices by luck.

Consulting senior faculty won’t result in any progress, because they may not have conducted these. So, one should rip off the watch, and study the mechanism, and its limitations.  The testing of mechanism gives the actual results.

Answer: B) Drop a similar watch multiple times and record the results.

Explanation:

In order to have a verified or reliable answer to this question, investigators must drop a similar watch multiple times and record the results. By doing this and repeatedly getting the same result(s), they are able to determine that their answer is in fact true.

*** I would also like to note that I got this question right on a test. Cheers!

Answer:

first option

Explanation:

we know the total amount of charges should be constant so

3 + (-3) + 5 + (-3) = 2

1 + 1 = 2 true

6 + 8 = 14 false

2 + (-2) = 0 false

5 + 3 = 8 false

Object A: +1 Object B: +1 indicates a possible net charge for each object.

The problem can be solved by following steps.

Let us , calculate the total charge

3+(-3)+5-3

=2

Hence, the net charge of Object A will be +1 and the net charge of Object B will be +1

Object A: +8 Object B: +6 is incorrect because the net charge is 8+6 =14

Object A: –2 Object B: +2 is incorrect because the net charge is -2+2=0

Object A: +5 Object B: +3  is incorrect because the net charge is 5+3=8

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Answer:

[tex]\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

Explanation:

Mass of the kid 23.7 kg.

[tex]\text { The kid is accelerating down at an angle is } 47.2^{\circ} .[/tex]

[tex]^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

[tex]23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}[/tex]

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

[tex]a=\frac{170.24}{23.7}[/tex]

[tex]a=7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

[tex]\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

1) The distance is 12 km

2) The speed is 4 km/h

3) The displacement is 8.6 km at [tex]35.5^{\circ}[/tex] north of west

4) The velocity is 2.87 km/h at [tex]35.5^{\circ}[/tex] north of west

Explanation:

1)

The distance covered by an object is the total length of the path covered by the object during its motion, regardless of its direction. Distance is a scalar quantity.

In this problem, the person walks:

5 km North

and then

7 km west

So, the distance covered is:

d = 5 km + 7 km = 12 km

And being a scalar, distance has no direction.

2)

Speed is a scalar quantity that tells "how fast" an object is moving. It is defined as:

[tex]speed=\frac{d}{t}[/tex]

where

d is the distance covered

t is the time taken

In this problem, we have

d = 12 km is the distance

t = 3 h is the time taken

Substituting,

[tex]speed = \frac{12 km}{3h}=4 km/h[/tex]

And being a scalar, speed has no direction.

3)

Displacement is a vector quantity; it is a vector connecting the initial position to the final position of motion. Therefore, its magnitude must be found by using the rules of vectors.

In this problem, the person walks:

5 km North

and then

7 km West

The two motions are at right angle, so they form the sides of a right triangle, of which the hypothenuse corresponds to the displacement. Therefore, we can find it by using Pythagorean's theorem:

[tex]d=\sqrt{7^2+5^2}=8.6 km[/tex]

Being a vector, displacement has also a direction, given by:

[tex]\theta=tan^{-1}(\frac{5}{7})=35.5^{\circ}[/tex] north of west.

4)

Velocity is a vector quantity, given by:

[tex]velocity = \frac{d}{t}[/tex]

where

d is the displacement

t is the time taken

In this problem, we have

d = 8.6 km (displacement)

t = 3 h (time taken)

Therefore, the velocity is

[tex]v=\frac{8.6 km}{3 h}=2.87 km/h[/tex]

And being a vector, velocity has also a direction, which is the same of the displacement: so, [tex]35.5^{\circ}[/tex] north of west.

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Answer:True

Explanation:

Answer:true

Explanation:because the glass material is template and the wood is natural for SAE convention and normalitation have in chard that glass is more resistive than the wood

Answer:

The distance of the student from the center of the merry-go-round is, r = 1.74 m

Explanation:

Given,

The acceleration of the student in merry go round, a = 3.6 m/s²

The tangential velocity of the student is, v = 2.5 m/s

The acceleration of the merry go round is given by the formula,

                                a = v² / r

Therefore,

                                 r = v² / a

                                    = 2.5² / 3.6      

                                    = 1.74 m

Hence, the distance of the student from the center of the merry-go-round is, r = 1.74 m

Answer:

The coefficient of dynamic friction is 0.025.

Explanation:

Given:

Initial speed after the push is 'v' as seen in the graph.

Final speed of the stone is 0 m/s as it comes to rest.

Total distance traveled is, [tex]D=29.8\ m[/tex]

Total time taken is, [tex]t_{total}=17.5\ s[/tex]

Time interval for deceleration is 3.5 to 17.5 s which is for 14 s.

Now, average speed of the stone is given as:

[tex]v_{avg}=\frac{D}{t_{total}}=\frac{29.8}{17.5}=1.703\ m/s[/tex]

Now, we know that, average speed can also be expressed as:

[tex]v_{avg}=\frac{v_i+v_f}{2}\\1.703=\frac{v+0}{2}\\v=2\times 1.703=3.41\ m/s[/tex]

Now, from the graph, the vertical height of the triangles is, [tex]v=3.41\ m/s[/tex]

The deceleration is given as the slope of the line from time 3.5 s to 17.5 s.

Therefore, deceleration is:

[tex]a=\frac{\textrm{Vertical height}}{\textrm{Time interval}}\\a=\frac{v-0}{17.5-3.5}\\a=\frac{3.41}{14}=0.244\ m/s^2[/tex]

Frictional force is the net force acting on the stone. Frictional force is given as:

[tex]f=\mu_dN\\Where, \mu_d\rightarrow \textrm{coefficient of dynamic friction}\\N\rightarrow \textrm{Normal force}\\N=mg\\\therefore f=\mu_dmg[/tex]

Now, from Newton's second law, net force is equal to the product of mass and acceleration.

Therefore,

[tex]\mu_dmg=ma\\\mu_d=\frac{a}{g}[/tex]

Plug in 0.244 for 'a' and 9.8 for 'g'. This gives,

[tex]\mu_d=\frac{a}{g}=\frac{0.244}{9.8}=0.025[/tex]

Therefore, the coefficient of dynamic friction is 0.025.

Answer:

D

Explanation:

The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.

Answer:

The velocity of the astronaut is, v = - 0.36 m/s

Explanation:

Given data,

The mass of the astronaut, M = 84 kg

The mass of the gas expelled by the thruster, m = 35 g

                                                                                 = 0.035 g

The velocity of the gas expelled, v = 875 m/s

According to the conservation of momentum,

             MV + mv = 0

                       V = - mv / M           

Substituting the values,

                        V = - 0.035 x 875 / 84

                           = - 0.36 m/s

The negative sign in the velocity indicates the astronaut moves opposite to the direction of velocity of gas.

Hence, the velocity of the astronaut is, v = - 0.36 m/s

Answer:

-0.364m/s

Explanation:

Mass of Astronaut (M₁) = 84kg

mass of gas(m₂) = 35g = 0.035kg

velocity of gas (v₂) = 875m/s

velocity of astronaut (v₁) =

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(84 * 0) + (0.035 * 0) = (84 * v₁) + (0.035 * 875)

0 = 84v₁ + 30.625

84v₁ = -30.625

v₁ = -0.364m/s

The period of oscillation of the system is 12.56 s

Explanation:

The period of oscillation of a spring-mass system is given by

[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]

where

m is the mass attached to the spring

k is the spring constant

For the system in this problem, we have

m = 40 kg

k = 10 N/m

Substituting into the equation, we find

[tex]T=2\pi \sqrt{\frac{40}{10}}=12.56 s[/tex]

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The final momentum is 120 kg m/s

Explanation:

According to the impuls theorem, the impulse exerted on an object (the product of force applied and time interval) is equal to its change in momentum. Mathematically:

[tex]F \Delta t = \Delta p = p_f - p_i[/tex]

where

F is the average force on the object

[tex]\Delta t[/tex]  is the time interval during which the force is applied

[tex]p_f[/tex] is the final momentum

[tex]p_i[/tex] is the initial momentum

In this problem:

F = 30 N is the force applied

[tex]\Delta t = 4 s[/tex] is the time interval

[tex]p_i = 0[/tex] is the initial momentum, since the object starts from rest

Solving for [tex]p_f[/tex], we find the final momentum:

[tex]p_f = F\Delta t=(30)(4)=120 kg m/s[/tex]

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The average force on the ball is 287.3 N.

Explanation:

The impulse exerted on an object, which is equal to the product between the force exerted and the duration of the collision, is equal to the change in momentum of the object.

If we apply this to the ball, we can write:

[tex]F \Delta t = m(v-u)[/tex]

where

F is the force exerted on the ball

[tex]\Delta t = 0.045 s[/tex] is the duration of the collision

m = 513 g = 0.513 kg is the mass of the ball

u = 12.1 m/s is the initial velocity of the ball

v = -13.1 m/s is the final velocity (negative since the ball rebounds in the opposite direction)

And solving for F, we find:

[tex]F=\frac{m(v-u)}{\Delta t}=\frac{(0.513)(-13.1-12.1)}{0.045}=-287.3 N[/tex]

So, the magnitude of the average force is 287.3 N.

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Answer: The distance between the objects.

Explanation: The equation for the gravitational force is written as:

F = G*m1*m2/r^2

Where r is the distance between the objects, m1 and m2 are the masses and G is the gravitational constant.

This cuantity is in the denominator because, as larger is the distance, smaller is the strenght of the field.

And is squared because is a force that spreads in a solid angle (as the change of area in a growing sphere )

Answer:

The positively charged ions are called cations and negatively charged ions are called anions.

Explanation:

Question:

The two methods used for determining mass are: measuring directly on a scale measuring directly on a balance measuring directly by displacement of water calculated by measurements of w and g

Answer:

The two methods used for determining mass are measuring directly on a balance and measuring directly by displacement of water.

Explanation:

Mass is the actual content of the body, and when it is under some gravity, it becomes weight. But, mass cannot be calculated using any scale. It can be determined by using balance, as well as by a weight machine.

But, what is true here is that the mass of a body cannot be measured directly. It should be directly measured using water displacement. Because the displaced amount of water is equal to the volume of the objects.

Answer: 2352 J

Explanation:

A body's gravitational potential energy [tex]U[/tex] depends on its position and is mathematically expressed as follows:

[tex]U=mgh[/tex]

Where:

[tex]m=60 kg[/tex] is the mass of the skater

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]h=4 m[/tex] is the skater's current height

Solving:

[tex]U=(60 kg)(9.8 m/s^{2})(4 m)[/tex]

[tex]U=2352 J[/tex]