5 kilograms of coffee are going going to be shared equally among 4 people.

How many kilograms of coffee does each person get?

Choose 1 Answer:

5 Kilograms Of Coffee Are Going Going To Be Shared Equally Among 4 People.How Many Kilograms Of Coffee

Answers

Answer 1

Answer:

B: between 1 and 2

Step-by-step explanation:

Since you share 5 kg amongst 4 you need to divide it by 4.

5 / 4 = 1.25 kg

This is between 1 and 2 kg

Answer 2

Answer: B. Between 1 and 2 kilograms.

Step-by-step explanation: Divide the amount of coffee by the number of people.

5/4=1.25.

Each person will get 1.25 kilograms of coffee, which is between 1 and 2 kilograms.


Related Questions

What is the sum of the geometric series?
4
E (-2)(-3)^n-1
n=1

A. –122
B. –2
C. 40
D. 54

Answers

[tex]

\Sigma_{n=1}^{4}-2\cdot(-3)^{n-1} \\

(-2)(-3)^{1-1}+(-2)(-3)^{2-1}+(-2)(-3)^{3-1}+(-2)(-3)^{4-1} \\

-2+6-18+54 \\

\boxed{40}

[/tex]

So the answer is C,

[tex]\Sigma_{n=1}^{4}-2\cdot(-3)^{n-1}=40[/tex]

Hope this helps.

r3t40

The sum of the finite geometric series (-2)(-3)ⁿ⁻¹ for n=1 to n=4 is 40, calculated using the geometric series sum formula.So,option C is correct.

The sum of a finite geometric series with a general term given as (-2)(-3)ⁿ⁻¹ where 'n' ranges from 1 to 4. To find the sum of a geometric series, we need to identify the first term (a) and the common ratio (r), and then use the formula Sₙ = a(1 - rⁿ) / (1 - r), where n is the number of terms.

The first term of the series can be found by substituting n = 1 into the general expression, yielding a = (-2)(-3)¹⁻¹ = -2. The second term, with n = 2, is (-2)(-3)²⁻¹ = -6(-3) = 18, indicating a common ratio of -3.

Thus, the sum of the series for the first four terms can be calculated as:

S₄ = (-2)(1 - (-3)⁴) / (1 - (-3))

S₄= (-2)(1 - 81) / (1 + 3)

S₄= (-2)(-80) / 4

S₄ = 160 / 4

S₄ = 40

Therefore, the sum of the given geometric series is 40.

HELP!!
Type the correct answer in each box. Round the vector’s magnitude to the nearest tenth.
Vector u has its initial point at (14, -6) and its terminal point at (-4, 7). Write the component form of u and find its magnitude.

Answers

Answer:

Component form of u is (-18,13)

The magnitude of u is 22.2

Step-by-step explanation:

The component form of a vector is an ordered pair that describe the change is x and y values

This is mathematically expressed as (Δx,Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

Terminal point of the vector as (-4,7)

Here x₁=14,x₂=-4, y₁=-6 ,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding Magnitude of the vector

║u=√(x₂-x₁)²+(y₂-y₁)²

║u=√-18²+13²

║u=√324+169

║u=√493

║u=22.2

You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circles to be less than or equal to 5\pi. If r+R=10, what is the maximum difference in the lengths of the radii?

Answers

The maximum difference in the lengths of the radii is 1/2.

To solve this problem, let's denote the radius of the smaller circle as ( r ) and the radius of the larger circle as ( R ). We're given that [tex]\( r + R = 10 \)[/tex].

The area of a circle is given by the formula [tex]\( A = \pi r^2 \)[/tex], where ( r ) is the radius.

We want the absolute difference in the areas of the two circles to be less than or equal to [tex]\( 5\pi \)[/tex]. So, we can set up the following inequality:

[tex]\[ |(\pi R^2) - (\pi r^2)| \leq 5\pi \][/tex]

[tex]\[ |(\pi (10-r)^2) - (\pi r^2)| \leq 5\pi \][/tex]

Expanding and simplifying:

[tex]\[ |(100\pi - 20\pi r + \pi r^2) - (\pi r^2)| \leq 5\pi \][/tex]

[tex]\[ |100\pi - 20\pi r| \leq 5\pi \][/tex]

[tex]\[ 100 - 20r \leq 5 \][/tex]

[tex]\[ 100 - 5 \leq 20r \][/tex]

[tex]\[ 95 \leq 20r \][/tex]

[tex]\[ \frac{95}{20} \leq r \][/tex]

[tex]\[ r \geq \frac{19}{4} \][/tex]

So, the maximum difference in the lengths of the radii is when [tex]\( r = \frac{19}{4} \)[/tex] and [tex]\( R = 10 - r = 10 - \frac{19}{4} = \frac{21}{4} \)[/tex].

The maximum difference in the lengths of the radii is [tex]\( \frac{21}{4} - \frac{19}{4} = \frac{2}{4} = \frac{1}{2} \)[/tex].

PLEASE HELP ME WITH THIS MATH QUESTION

Answers

Answer:

  C'(4, 4)

Step-by-step explanation:

We assume dilation is about the origin, so all coordinates are multiplied by the scale factor:

  C' = 2C = 2(2, 2) = (4, 4)

In the system below, use equation (1) with equation (2) to eliminate x. Then use equation (1) with equation (3) to eliminate x. x-y-2z=4 (1) -x+3y-z=8 (2) -2x-y-4z=-1 (3) What is the new 2 × 2 system?

Answers

Answer:

2y -3z = 12-3y -8z = 7

Step-by-step explanation:

(1) +(2) ⇒ (x -y -2z) +(-x +3y -z) = (4) +(8)

  2y -3z = 12

__

2(1) +(3) ⇒ 2(x -y -2z) +(-2x -y -4z) = 2(4) +(-1)

  -3y -8z = 7

___

The reduced system of equations is ...

2y -3z = 12-3y -8z = 7

Answer:

2y - 3z = 12.

-3y - 8z = 7.

Step-by-step explanation:

x - y - 2z = 4     (1)

-x + 3y - z = 8    (2)

-2x - y - 4z = -1   (3)

Adding (1) + (2):

2y - 3z = 12.

2 * (1) + (3) gives:

-3y - 8z = 7.

10 cards are numbered from 1 to 10 and placed in a box. One card is
selected at random and is not replaced. Another card is then randomly
selected. What is the probability of selecting two numbers that are less than
62​

Answers

Answer:

0.889

Step-by-step explanation:

I think it is multiplied.

10 *9 = 90

which is the total number of ways you can draw 2 cards without replacement.

I think it is easier to figure out how many possibilities there are over 62 and go from there.

10*9

10*8

10*7

===========

9*8

9*7

So there are 5 combinations that are over 62. There are 5 more possibilities because you could draw them in the reverse order

9 * 10

8 * 10

7 * 10  

8* 9

7 * 9

In all there are 10 ways of drawing numbers that are over 62

So what is the probability of drawing 2 cards above 62?

10/90 = 1/9 = 0.111

Therefore, there must be a probability of 1 - 0.111 for under 62 = 0.889

What is the slope of the line passing through the points (2,-5) and(4,1)

Answers

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-5)}{4-2}\implies \cfrac{1+5}{2}\implies \cfrac{6}{2}\implies 3[/tex]

To travel 80 miles, it takes Sue, riding a moped, 2 hours less time than it takes Doreen to travel 60 miles riding a bicycle. Sue travels 10 miles per hour faster than Doreen. Find the times and rates of both girls.

Answers

Answer:

Time taken by Doreen is 6 hours and speed is 10 miles per hour.

Time taken by Sue is 4 hours and speed is 20 miles per hour.

Step-by-step explanation:

Let the speed of Doreen be x

According to the question  speed of Sue   is = x+10

time  taken By Sue to cover 80 miles = [tex]\frac{80}{x+10}[/tex]

time taken by Doreen to travel 60 miles = [tex]\frac{60}{x}[/tex]

According to question Sue take two hours less than Doreen takes

therefore

[tex]\frac{60}{x}[/tex] - [tex]\frac{80}{x+10}[/tex] =2

[tex]\frac{60(x+10)-80x}{x(x+10)}[/tex] =2

60(x+10) -80x = 2(x(x+10)

60x+600-80x = [tex]2x^2+20x\\[/tex]

simplifying it ,we get

[tex]2x^2+40x-600=0\\[/tex]

Dividing both sides by 2 ,we get

[tex]x^2+20x-300=0\\[/tex]

solving it for x ,we get

(x+30)(x-10) =0

x =-30 which is not possible

x =10 miles per hour

Speed of Doreen = 10 miles per hour

Speed of Sue = 10+10 = 20 miles per hour

Time taken by Doreen = 60 divided by 10 = 6 hours

Time taken  by Sue = 80 divided by 20 = 4 hours

Final answer:

In conclusion, Doreen travels at a speed of 30 mph, taking her 4 hours to travel 60 miles. Sue, on the other hand, travels at a speed of 40 mph, taking her 2 hours to travel 80 miles.

Explanation:

This problem is a classic example of distance, rate, and time relations in mathematics. Let's start by denoting Sue's speed as x mph, the Doreen's speed would then be x-10 mph. We know that time is equal to distance divided by speed. So, the time it takes Sue to travel 80 miles would be 80/x hours and the time it takes Doreen to travel 60 miles would be 60/(x-10) hours. The question states that Sue's travel time is 2 hours less than Doreen's. Therefore, we can form the equation: 60/(x-10) = 80/x + 2. Solving this equation, we find that x equals 40 mph, which is Sue's speed and Doreen's speed is 30 mph. Consequently, the time it takes Sue to travel 80 miles is 2 hours and for Doreen to travel 60 miles is 4 hours.

Learn more about Distance, Rate, Time Relations here:

https://brainly.com/question/4480564

#SPJ11

PLEASE HELP ME!! D:

Use the graph of the line to answer the questions.

What is an equation of the line in point-slope form?

How can the point-slope form be written in function notation?

Answers

Answer:

Point-slope form:

[tex]y-0=\frac{1}{3} (x-1)\\f(x)-0=\frac{1}{3}(x-1)[/tex]

Slope-intercept form:

[tex]y=\frac{1}{3}x-\frac{1}{3} \\f(x)=\frac{1}{3} x-\frac{1}{3}[/tex]

Step-by-step explanation:

You have points on that line at (-2, -1) and (1, 0). To find your slope using those points, use the slope formula.

[tex]\frac{y2-y1}{x2-x1} \\\\\frac{0-(-1)}{1-(-2)} \\\\\frac{0+1}{1+2} \\\\\frac{1}{3}[/tex]

Now that we have your slope, you can use your slope and one of your points to write an equation in point-slope form.

[tex]y-y1=m(x-x1)\\y-0=\frac{1}{3} (x-1)\\y=\frac{1}{3} x-\frac{1}{3}[/tex]

To put it in function notation, substitute y for f(x).

[tex]f(x)-0=\frac{1}{3} (x-1)\\f(x)=\frac{1}{3} x-\frac{1}{3}[/tex]

First answer is y+1=(1/3) (x+2)

Second answer is f(x) =(1/3) x-(1/3)

Consider the function f(x) = 2X and the function g(x).
How will the graph of g(x) differ from the graph of f(x)?

Answers

Answer:

(A)

Step-by-step explanation:

Answer:

Option A is correct.

Step-by-step explanation:

Given  : [tex]f(x) =2^{x}[/tex] and [tex]g(x) =2^{x+4}[/tex].

To find : How will the graph of g(x) differ from the graph of f(x).

Solution : We have given that  

[tex]f(x) =2^{x}[/tex] and g(x)   [tex]g(x) =2^{x+4}[/tex]

By the transformation Rule : If f(x) →→ f(x +h) if mean graph of function shifted to left by h units .

Then  graph of [tex]g(x) =2^{x+4}[/tex] is the graph of [tex]f(x) =2^{x}[/tex] is shifted by 4 unt left.

Therefore, Option A is correct.

A wholesaler requires a minimum of 4 items in each order from its retail customers. The manager of one retail store is considering ordering a certain number of sofas, x, and a certain number of pillows that come in pairs, y. Which graph represents the possible combinations of sofa and pillow orders the manager can have?

Answers

Answer:

Option D

Step-by-step explanation:

We have the following variable definitions:

sofas: x

pillows: y

Pillows come in pairs so we have 2y pillows

The total order for all the possible combinations is:

[tex]x+2y[/tex]

The wholesaler requires a minimum of 4 items in each order from its retail customers. This means the retailers can order 4 or more.

Therefore the inequality is:

[tex]x+2y\ge4[/tex]

To graph this inequality, we graph the corresponding linear equation, [tex]x+2y=4[/tex]  with a solid line and shade above.

The correct choice is D

See attachment

Answer:The last graph is the right one

AB id a diameter of a circle centered at o. C is a point on the circle such that angle BOC is 60 degrees.If the diameter of the circle is 5 inches the length of the chord ac expressed in inches is

Answers

Answer:

[tex]AC=4.3\ in[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The triangle AOC is an isosceles triangle

OA=OC=5/2=2.5 in -----> the radius of the circle

∠AOC=180°-60°=120°

∠CAO=∠ACO=120°/2=60°

Applying the law of cosines find the length of the chord AC

[tex]AC^{2}=OA^{2}+OC^{2}-2(OA)(OC)cos(120\°)[/tex]

substitute

[tex]AC^{2}=2.5^{2}+2.5^{2}-2(2.5)(2.5)cos(120\°)[/tex]

[tex]AC^{2}=18.75[/tex]

[tex]AC=4.3\ in[/tex]

Find the value of Y [Inscribed Angle]

Answers

Check the picture below.

Answer:

x = 60°

Step-by-step explanation:

From ΔOPQ,

∠OPQ = 120°   [ angle at the center inscribed by arc PQ ]

PQ ≅ OQ

so opposite angles to PQ and OQ will be equal

∠OPQ  ≅ ∠OQP

∠OPQ + ∠OQP + ∠POQ = 180°

∠OPQ + ∠OPQ + 120 = 180°

2∠OPQ = 180 - 120 = 60°

∠OPQ = 30°

Since radius OP is perpendicular to tangent.

so ∠OPQ + Y = 90°

y + 30° = 90°

y = 90 - 30 = 60°

Answer x = 60°

Select the correct answers in the table.

Answers

Answer:

  see below

Step-by-step explanation:

To find miles per hour, divide miles by hours:

  (5 2/3 mi)/(2 2/3 h) = (17/3 mi)/(8/3 h) = (17/8) mi/h = 2 1/8 mi/h

Hours per mile is the reciprocal of that:

  1/(17/8 mi/h) = 8/17 h/mi

Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was 35 the size of the brand name. If the generic television set is 16 inches by 40 inches, what are the dimensions of the brand name television?

List the dimensions of the brand name television.

Show your work.

Answers

Answer:

The dimensions of the brand name television are [tex]26\frac{2}{3}\ in[/tex] by  [tex]66\frac{2}{3}\ in[/tex]

Step-by-step explanation:

we know that

The generic version was based on the brand name and was 3/5 the size of the brand name

Let

x----> the length of the size of the brand name

y----> the width of the size of the brand name

Find the length of the size of the brand name

we know that

[tex]40=\frac{3}{5}x[/tex] -----> equation A

Solve for x

Multiply by 5 both sides

[tex]5*40=3x[/tex]

Rewrite and divide by 3 both sides

[tex]x=200/3\ in[/tex]

Convert to mixed number

[tex]200/3=(198/3)+(2/3)=66\frac{2}{3}\ in[/tex]

Find the width of the size of the brand name

we know that

[tex]16=\frac{3}{5}y[/tex] -----> equation B

Solve for y

Multiply by 5 both sides

[tex]5*16=3y[/tex]

Rewrite and divide by 3 both sides

[tex]x=80/3\ in[/tex]

Convert to mixed number

[tex]80/3=(78/3)+(2/3)=26\frac{2}{3}\ in[/tex]

A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per pound and cashews cost $6.50 per pound, how many pounds of each should he use?

Answers

Answer:

3lbs of Cashews

Step-by-step explanation:

lbs of Cashews, and 7 lbs of Peanuts

$4.00P + 6.50C = ($4.75/lbs)(10lbs)

$4.00(7) + $6.50(3) = $47.50

$28.00 + $19.50 = $47.50

$47.50 = $47.50

Therefore it's 3lbs of Cashews

Answer:

3lbs of Cashews

hope it helps! x

Find the values of x in this equation: x – 15 / x = 2.


A) -7, 3

B) -5, 2

C) -7, 5

D) -2, 5

E) -3, 5

Answers

Answer:

E) -3, 5

Step-by-step explanation:

x – 15 / x = 2

x^2 - 15 = 2x

x^2 - 2x - 15 = 0

(x - 5)(x + 3) = 0

x - 5 = 0; x = 5

x + 3 = 0; x = -3

Solutions: -3, 5

For this case we must solve the following equation:

[tex]x- \frac {15} {x} = 2[/tex]

We manipulate the equation algebraically:

[tex]\frac {x ^ 2-15} {x} = 2\\x ^ 2-15 = 2x\\x ^ 2-2x-15 = 0[/tex]

To solve, we factor the equation. We must find two numbers that when multiplied by -15 and when summed by -2. These numbers are:

+3 and -5.

[tex](x + 3) (x-5) = 0[/tex]

So, the roots are:

[tex]x_ {1} = - 3\\x_ {2} = 5[/tex]

Answer:

Option E

brainliest plus 10 points! simplify
6y^2-6/8y^2+8y÷3y-3/4y^2+4

Answers

Answer:

  (y² +1)/y

Step-by-step explanation:

Invert the denominator fraction and multiply. Factor the difference of squares.

[tex]\displaystyle\frac{\left(\frac{6y^2-6}{8y^2+8y}\right)}{\left(\frac{3y-3}{4y^2+4}\right)}=\frac{6(y^2-1)}{8y(y+1)}\cdot\frac{4(y^2+1)}{3(y-1)}\\\\=\frac{24(y+1)(y-1)(y^2+1)}{24y(y+1)(y-1)}=\frac{y^2+1}{y}[/tex]

I would like some help with this question plz

Answers

Answer:

Step-by-step explanation:

As the value of a increases, the radical function sweeps out higher, increasing the range of the function.  The k value moves it up or down.  A "+k" moves up (for example, +3 moves the function up 3 from the origin).  The h value moves it side to side.  A positive h value moves to the right and a negative h value moves to the left.  For example, √x-3 moves 3 to the right and √x+3 moves 3 to the left.

In summary, a and k affect the range of the function, k being the "starting point" and a being the "ending point"; h affects the domain of the function.

which function is a linear function a. 1-3x^2 b. y+7=5x c. x^3 + 4 = y d. 9(x^2-y) = 3 e.y-x^3=8

Answers

Answer:

b. y+7=5x

Step-by-step explanation:

a. 1-3x^2     is a quadratic

b. y+7=5x    is a linear function:  y = 5x - 7

c. x^3 + 4 = y   is a cubic function

d. 9(x^2-y) = 3    is a quadratic function

e.y-x^3=8   is a cubic function

Marya wants to factor the polynomial 36x3 – 22x2 – 144x. which term can she add to the polynomial that would not change its greatest common factor? check all that apply. a. 11 b. 50xy c. 40x2 d. 24 e. 10y

Answers

Answer:

[tex]50xy[/tex] and [tex]40x^2[/tex].

Step-by-step explanation:

The given polynomial is [tex]36x^3-22x^2-144x[/tex].

The prime factorization of each term are;

[tex]36x^2=2^2\times 3^2\times x^3[/tex]

[tex]-22x^2=-2\times 11\times x^2[/tex]

[tex]-144x=-2^4\times 3^2\times x[/tex]

The greatest common factor of these three terms is [tex]2x[/tex].

Now observe that:

The GCF of [tex]2x[/tex] and 11 is 1

The GCF of [tex]2x[/tex] and 50xy is 2x

The GCF of [tex]2x[/tex] and [tex]40x^2[/tex] is 2x

The GCF of [tex]2x[/tex] and 24 is 2

The GCF of [tex]2x[/tex] and 10y is 2

The correct options are [tex]50xy[/tex] and [tex]40x^2[/tex].

A circular jogging track forms the edge of a circular lake that has a diameter of 2 miles. Johanna walked once around the track at the average rate of 3 miles per hour. If t represents the number of hours it took Johanna to walk completely around the lake, which of the following is a correct statement?
A. 0.5
B. 1.75
C. 2.0
D. 2.5
E. 3

Answers

Answer:

Given:

Diameter of lake = 2 miles

∴ [tex]Radius = \frac{Diameter}{2}[/tex] = 1 miles  

The circumference of the lake can be computed as :

Circumference = 2πr

Circumference = 2×3.14×1 = 6.28 miles

This circumference is the total distance traveled by Johanna.

We are give the speed at which Johanna jogs, i.e. Speed = 3 miles/hour

∴ Time taken by Johanna to jog around the lake is given as :

[tex]Time = \frac{Distance}{Speed}[/tex]

Time = 2.093 hours

∴ The correct option is (c.)

An employee who earned $550 a week working 35 hours had her pay increased by 5 percent. Later, her hours were reduced to 30 per week, but the new hourly rate of pay was retained. What was her new amount of weekly pay?

Answers

Answer:

  $495

Step-by-step explanation:

After the 5% raise, her weekly pay was ...

  $550 × 1.05 = $577.50

If she works 35 hours for that pay, her hourly rate is

  $577.50/35 = $16.50

Then, working 30 hours, her weekly pay will be ...

  30 × $16.50 = $495.00

Final answer:

To find the new amount of weekly pay, multiply the increase in pay by the new number of hours. The new amount is $577.50.

Explanation:

To find the new amount of weekly pay, we need to calculate the increase in pay and then multiply it by the new number of hours.

The employee's pay increased by 5 percent. This means the pay increased by 5% of $550, which is equal to 0.05  imes 550 = $27.50.

Her new hourly rate of pay is the same, so it remains at $550 + $27.50 = $577.50.

Finally, we need to calculate the new amount of weekly pay, taking into account the reduced number of hours. The new pay per hour is $577.50 / 30 = $19.25. Multiply this by the new number of hours to get the new amount of weekly pay: $19.25  imes 30 = $577.50.

y=2x^2 y^2=x^2+6x+9 What is a possible solution for x in the system of equations above?

Answers

Answer:

So we have the two real points (3/2 , 9/2)  and (-1,2).

(Question: are you wanting to use the possible rational zero theorem? Please let me know if I didn't answer your question.)

Step-by-step explanation:

y=2x^2

y^2=x^2+6x+9

is the given system.

So my plain here is to look at y=2x^2 and just plug it into the other equation where y is.

(2x^2)^2=x^2+6x+9

(2x^2)(2x^2)=x^2+6x+9

4x^4=x^2+6x+9

I'm going to put everything on one side.

Subtract (x^2+6x+9) on both sides.

4x^4-x^2-6x-9=0

Let's see if some possible rational zeros will work.

Let' try x=-1.

4-1+6-9=3+(-3)=0.

x=-1 works.

To find the other factor of 4x^4-x^2-6x-9 given x+1 is a factor, I'm going to use synthetic division.

-1   |  4     0     -1     -6    -9

    |         -4     4     -3      9

    |________________ I put that 0 in there because we are missing x^3

        4    -4     3     -9      0

The the other factor is 4x^3-4x^2+3x-9.

1 is obviously not going to make that 0.

Plug in -3 it gives you 4(-3)^3-4(-3)^2+3(-3)-9=-162 (not 0)

Plug in 3 gives you 4(-3)^3-4(-3)^2+3(-3)-9=72 (not 0)

Plug in 3/2 gives you 4(3/2)^2-4(3/2)^2+3(3/2)-9=0 so x=3/2 works as a solution.

Now let's find another factor

3/2  |     4       -4           3        -9

      |                6           3          9

      |________________________

            4          2           6        0

So we have 4x^2+2x+6=0.

The discriminant is b^2-4ac which in this case is (2)^2-4(4)(6). Simplifying this gives us (2)^2-4(4)(6)=4-16(6)=4-96=-92.  This is negative number which means the other 2 solutions are complex (not real).

So the other real solutions that satisfy the system is for x=3/2 or x=-1.

Since y=2x^2 then for x=3/2 we have y=2(3/2)^2=2(9/4)=9/2 and for x=-1 we have y=2(1)^2=2.

So we have the two real points (3/2 , 9/2)  and (-1,2)

What is the product?

Answers

Answer:

=20s³+50s²+32s+6

Step-by-step explanation:

We multiply each of the term in the initial expression by the the second expression as follows:

4s(5s²+10s+3)+2(5s²+10s+3)

=20s³+40s²+12s+10s²+20s+6

Collect like terms together.

=20s³+50s²+32s+6

a jet fighter accelerates at 17.7 m/s^2 increasing its velocity from 119 m/s to 233 m/s how much time does that take

Answers

If its acceleration is constant, then it is equal to the jet's average velocity, given by

[tex]a=a_{\rm ave}=\dfrac{\Delta v}{\Delta t}[/tex]

Then it takes

[tex]17.7\dfrac{\rm m}{\mathrm s^2}=\dfrac{233\frac{\rm m}{\rm s}-119\frac{\rm m}{\rm s}}{\Delta t}\implies\Delta t=\boxed{6.44\,\mathrm s}[/tex]

Answer:

The time taken by the jet is 6.44 seconds.

Step-by-step explanation:

It is given that,

Acceleration of the jet, [tex]a=17.7\ m/s^2[/tex]

Initial velocity of the jet, u = 119 m/s

Final velocity of the jet, v = 233 m/s

Acceleration of an object is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]t=\dfrac{v-u}{a}[/tex]

[tex]t=\dfrac{233-119}{17.7}[/tex]

t = 6.44 seconds

So, the time taken by the jet is 6.44 seconds. Hence, this is the required solution.

PLEASE HELP ME FIND THE LENGTH

Answers

Answer:

Length of arc AB is,

= 2πr (angle between AB) /360

=2×3.14×90/360

=1.57 cm

For this case we have that by definition, the arc length of a circle is given by:

[tex]AL = \frac {x * 2 \pi * r} {360}[/tex]

Where:

x: Represents the angle between AB. According to the figure we have that x = 90 degrees.

[tex]r = 7.9 \ cm[/tex]

So:

[tex]AL = \frac {90 * 2 \pi * 7.9} {360}\\AL = \frac {90 * 2 * 3.14 * 7.9} {360}\\AL = \frac {4465,08} {360}\\AL = 12.403[/tex]

Answer:

[tex]12.4\ cm[/tex]

PLEASE HELLLPPP!!!! WILL GET BRAINIEST!!
Solve the equation for 0 ≤ x < 360.


tan(x) + 1 = -1

45 degrees
63 degrees
Both A and B
Does not exist.

Answers

Answer:

  x = 117°, 297°

Step-by-step explanation:

Subtract 1 from both sides of the equation and you have ...

  tan(x) = -2

Then the arctangent function tells you ...

  x = arctan(-2) ≈ 116.5651°, 296.5651°

  x ≈ 117° or 297°

Find the volume of the sphere.

Answers

Answer:

[tex]\frac{\pi }{6}[/tex]

Step-by-step explanation:

The volume of a sphere is [tex]\frac{4}{3} \pi r^{3}[/tex]

Just plug in 1/2 for r

[tex]\frac{4}{3} \pi (\frac{1}{2}) ^{3}[/tex]

The answer is [tex]\frac{\pi }{6}[/tex]

In the figure below, if angle T measures 130 degrees, what is the measure of angle Q?

Answers

Circle theorem:

The angle at the centre (T) is double the angle at the circumference (Q)

---> That also means that:

The angle at the circumference (Q) is half the angle at the centre (T)

Since T = 130 degrees;

Q = 130 divided by 2

   = 65°

___________________________________

Answer:

∠Q = 65°

Answer:

m<Q = 65°

Step-by-step explanation:

It is given that <T = 130°

To find the <Q

From the figure we can see that <T is the central angle made by the arc RS

And <Q is the angle made by the arc RS on minor arc.

We know that m<Q = (1/2)m<T

We have m<T = 130°

Therefore m<Q = 130/2 = 65°

Other Questions
Dynamothermal (regional) metamorphism occurs when ________. a. the upper surface of a body of rock develops a thick soil profile b. a pluton causes metamorphism in a small surrounding region c. regression of the sea leads to erosion of sedimentary cover on a body of rock d. rock becomes deeply buried during continental collision and mountain building A cashier has 54 bills, all of which are $10 or $20 bills. The total value of the money is $910. How many of each type of billdoes the cashier have? Which statement best applies to the slope of the line below?A the slope is negativeB. the slope is zeroC.the slope is positiveD. the line has no slope What is the optimal solution for the following problem?MinimizeP = 3x + 15ysubject to2x + 4y ? 125x + 2y ? 10andx ? 0, y ? 0.(x, y) = (2, 0)(x, y) = (0, 3)(x, y) = (0, 0)(x, y) = (1, 2.5)(x, y) = (6, 0) The correct conversion from metric system to household system isA. 5 ml equals 1 tablespoonB. 15 ml equals 1 teaspoonC. 30 ml equals 1 fluid ounceD. 500 ml equals 1 measuring cup Find the height of the given pyramid. How did the soviets win at stalingrad help advance the allies europe first strategy? The most prevalent category of observation study is _____ observation. A. linguisticB. extralinguisticC. spatialD. nonverbalE. digital The vapor pressure of water is 23.76 mm Hg at 25 C. A nonvolatile, nonelectrolyte that dissolves in water is sucrose. Calculate the vapor pressure of the solution at 25 C when 12.25 grams of sucrose, C12H22O11 (342.3 g/mol), are dissolved in 176.3 grams of water. water = H2O = 18.02 g/mol. When discussing cholesterol levels with a patient, which of the following is desirable?High cholesterol, low HDLHigh LDL, low cholesterolHigh cholesterol, high LDLHigh HDL, low LDLHigh HDL, High LDL A researcher wants to make a 99% confidence interval for the population proportion. The most conservative estimate of the sample size that would limit the maximum error of estimate to within .05 of the population proportion is at least: (A) 1274 (B) 666 (C) 26 (D) 1128 To fill out a function's ___ ___, you will need to use test numbers before and after each of the function's ___ and asymtopesA). Sign chart; ValuesB). rational equation; valuesC). sign chart; zeroesD). rational equation; zeroes Research conducted by Edward Prescott of Arizona State University, and Edward Glaeser of Harvard University along with Bruce Sacerdote of Dartmouth College indicate that the effects of supply-side policies A. are, as of now, unclear and require more careful study. B. have little or no effect at all. C. are clearly defined and small. D. are clearly defined and substantial. Whos the best villain of all time and why? A group of entomologists has determined that the population of ladybugs at a local park can be modeled by the equation y = 1.437 x + 197.686 , where x represents the number of years since 2010 and y represents the number of ladybugs, in thousands. a) Predict the ladybug population at the park in 2024. b) Predict the ladybug population at the park in 2060. What is the value of "c" in the quadratic equation 3x 2 + 5x + 7 = 0? A given line has the equation .2X - 12Y = -1What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?A. Y = -6X + 9B. Y = - 1/6X + 9C. Y = 1/6X +9D. 6X+ 9 Which power raised to a power expression are equivalent to 8 to the power of 12? Check all that apply Write the equation of the line shown in the graph. Please help. How many kilograms are in44 pounds? 1 kg = 2.2 lbs44 lbs = [?] kg