5. Oscar needs to fill a sphere-shaped balloon with
helium. If the balloon has a diameter of 8 inches, what is
the total amount of helium that the balloon will hold to
the nearest tenth?
A. 2,143.6 in.3
B. 714.5 in.
C. 268.1 in.3
D. 150.7 in.

Answer:

Would ypu plz show us the number line so at least i could answer the question

Answer: 9 and -4

Step-by-step explanation:

9 and 4 are both factors of 36, however we want to multiply to -36 so one of them must be a negative.

The two must also add up to 5, so that means -9 and 4 would not work as those would add to -5, leaving 9 and -4 left as the answer.

The value of two numbers multiply by -36 and added to 5 would be - 36 and 5.

Used the concept of the equation that states,

Mathematical expression is defined as the collection of numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that,

The multiplication of two numbers = - 36

The addition of two numbers = 5

Let us assume that the two numbers are x and y.

Hence the equations become,

x + y = 5   .. (i)

And, xy = - 36  .. (ii)

From (i);

x = 5 - y

Substitute the above value in (ii);

(5 - y)y = - 36

5y - y² = - 36

y² - 5y - 36 = 0

y² - (9 - 4)y - 36 = 0

y² - 9y + 4y - 36 = 0

y (y - 9) + 4 (y - 9) = 0

(y + 4) (y - 9) = 0

This gives,

y = - 4

y = 9

Substitute both the values in (i);

Put x = - 4

x - 4 = 5

x = 9

Put x = 9;

x + 9 = 5

x = - 4

Therefore, the two numbers are 9 and - 4.

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The number of sides of a polygon can be determined from the total interior angle or each exterior angle. The interior angle measures of a regular polygon can be used to find unknown quantities. The sum of the interior angles in an 11-gon is 1620° regardless of whether it is regular or irregular.

a. The sum of the interior angles of a polygon is given by the formula (n-2) * 180°, where n is the number of sides. To find the number of sides, you rearrange the formula to n = (sum of angles/180) + 2. For 1980°, n = (1980/180) + 2 = 13. For 900°, n = (900/180) + 2 = 7.

b. The sum of the exterior angles of any polygon is always 360°. If each exterior angle is 90°, divide 360 by 90 to get 4. This polygon has 4 sides, so it's a square.

c. In a regular pentagon, each interior angle is 108°. So, if 2x + 4 = 108°, solve for x to find x = 52°.

d. The sum of the exterior angles of a polygon is also 360°. If four of them are 57, 74, 56, and 66, add these up and subtract from 360 to find the remaining angle. It's 107°.

e. The sum of the interior angles of an 11-gon (n = 11) is (11-2) * 180 = 1620°. This is the same whether the polygon is regular or not.

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This problem can be solved by Conducting a Chi-square test for independence to explore the relationship between helmet usage and head injuries. We state our null and alternative hypotheses, then we carry out our plan by calculating the observed and expected counts, the test statistic, and the p-value. The conclusion is drawn based on the computed p-value.

The purpose of this analysis is to see if there is a relationship between the use of helmets and head injuries in skiers and snowboarders. In this case, we are dealing with two categorical variables: injury status (injured or not injured) and helmet use (helmet used or not). This falls under the field of statistics in math, specifically, Chi-square test for independence is appropriate here.

Step 1 - STATE: We're comparing the proportion of helmet users among skiers and snowboarders who have head injuries (p1) with the proportion of helmet users among uninjured skiers and snowboarders (p2). The null hypothesis is that the two proportions are equal, i.e., p1 = p2, while the alternative is that they are not equal, i.e., p1 ≠ p2.

Step 2 - PLAN: We are to use a Chi-square test for independence to investigate if helmet use is independent of injury status.

Step 3 - SOLVE: Calculate the observed and expected counts, the test statistic, and the p-value. The observed counts are given in the problem: 96 out of 578 injured subjects used helmets and 656 out of 2992 uninjured subjects used helmets. Expected counts and the test statistic would require a detailed calculation that isn’t shown here.

The conclusion depends on the computed p-value. If the p-value is less than the significance level (usually 0.05), we reject the null hypothesis and conclude that helmet use is less common among skiers and snowboarders who have head injuries. However, bear in mind that correlation does not imply causation, and this is an observational study, not an experiment.

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The probability that a person will take longer than 21 days to pass it is 0.12

Explanation:

Given:

Mean time, μ = 14 days

Standard deviation, ρ = 6 days

Let x be the time to pass the kidney stones.

Probability that a person will take longer than 21 days to pass it.

We need to find z score first

Z score = [tex]\frac{x - u}{p}[/tex]

Z score = [tex]\frac{21-14}{6}[/tex]

            = 1.166

Probability that a person will take longer than 21 days to pass it = P(x > Z)

                                                                                                          = P(x > 1.16)

                                                                                                          = 0.12

Therefore, the probability that a person will take longer than 21 days to pass it is 0.12

Answer:

1500%

Step-by-step explanation:

From March 2004 - March 2006, this is 2 years. The number of "6-month" period there are in 2 years is:

2* 12 = 24 months

24/6 = 4  "6 month periods"

So, it doubles "4" times in that time frame.

Let Initial population be 100 (In March 2004).

1 times double = 100 * 2 = 200

2 times double = 200 * 2 = 400

3 times double = 400 * 2 = 800

4 times double = 800 * 2 = 1600

So, population goes from 100 to 1600. How much percentage increase is that?

To get percentage increase, we find the increase and divide by original (initial amount). Then multiply by 100 to get percentage. So,

1600 - 100 = 1500 increase

1500/100 = 15

15 * 100 = 1500%

        Percentage increase in the number of blogs from March'04 to March'06 will be 1500%.

          [tex]P(t)=P_0(1+r)^t[/tex]

          Here, [tex]P(t)=[/tex] Final value

          [tex]P_0=[/tex] Initial value

          [tex]r=[/tex] Growth rate

          [tex]t=[/tex] Period of 6 months

Given in the question,

"Number of blogs are doubled in every six months"

[tex]P(t)=2P_0[/tex]

[tex]2P_0=P_0(1+r)^1[/tex]

2 = (1 + r)

r = 1 Or 100%

Therefore exponential function will be,

[tex]P(t)=P_0(2)^t[/tex]

To find the increase in blogs from March 2004 to March 2006,

Number of six monthly periods in 2 years = 4

[tex]P(4)=P_0(2)^4[/tex]

P(4) = 16(P₀)

Percentage increase in blogs = [tex]\frac{P(4)-P_0}{P_0}\times 100[/tex]

                                                  [tex]=\frac{16P_0-P_0}{P_0}\times 100[/tex]

                                                  = 1500%

     Therefore, percentage increase in the number of blogs will be 1500%.

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Answer:

V = 3 * (70 + 230) / 2

V = 450 m^3

Step-by-step explanation:

Based on the two measured rates, and assuming that the rate of increase was uniform, the volume would be the average, hourly volumetric flow rate, multiplied by number of hours, or

Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

A value X is significantly high is:

[tex]X > E(X) + 2\sqrt{V(X)}[/tex]

In this problem:

[tex]p = 0.149, n = 5000[/tex]

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

[tex]E(X) = np = 5000*0.149 = 745[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18[/tex]

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

[tex]E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36[/tex]

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

Answer:

D

Step-by-step explanation:

65% × 78 =

(65 ÷ 100) × 78 =

(65 × 78) ÷ 100 =

5,070 ÷ 100 =

50.7;

Answer:

A 120

Step-by-step explanation:

you divide 120 by 0.65 to find 78

Answer:

6.5 bottles

Step-by-step explanation:

convert liters to ml 1 bottle= 1000ml

divide how much she drank by 1000ml

6500÷1000=6.5

Answer:

For  values

Hence the Dr.Clifford Jones claim is wrong about the bats mean weight

Step-by-step explanation:

Given:

Mean=1.659 grams

Standard deviation: 0.264

No of samples=200

To find :

Confidence intervals at

1)99.9% 2)99%  3)95% 4)80% and

Whether the Dr. Clifford with 1.7 mean weight is less or not?

Solution:

We know  interval estimation is given by ,

E=mean±Z value*{standard deviation/Sqrt(N)}

Now For Z value 99.9% =3.291

E=1.659±3.291{0.264/Sqrt(200)}

=1.659±0.0614

i.e.C.I.[1.6 to 1.72]

Now for Z value 99 % =2.576

E=1.659±2.576{0.264/Sqrt(200)}

=1.659±0.0481

i.e. C.I[1.61,1.71]

Now for Z value at 95% =1.96

E=1.659±1.96*(0.264/sqrt(200))

=1.659±0.0366

i.e. C.I.[1.62,1.7]

Now ofr Z value at 80% =1.28

E=1.659±1.28*(0.264/sqrt(20))

=1.659±0.0239

i.e. C.I.[1.64,1.68]

Using t distribution as ,

value for mean =1.7

raw i.p=1.659

Degree of freedom =N-1=200-1=199

Hence

t-score is similar to zscore

T-score =(Raw input -mean)/(standard deviation/Sqrt(n))

=(-1.7+1.659)/(0.264/Sqrt(200))

=-2.19721

Consider 1 tailed ,

p value =P(Z≤-2.19721)

=0.0143

i.e  P value is 0.0143

Hence The result is not significant at p<0.01

To find the confidence interval for the mean weight of all bumblebee bats, use the formula: Confidence Interval = Xbar ± (Z-Value) * (Standard Deviation / sqrt(n)). To test whether bumblebee bats weigh less on average than Dr. Clifford Jones claims, use the t-distribution technique.

To find the confidence interval for the mean weight of all bumblebee bats, we will use the formula:

Confidence Interval = Xbar ± (Z-Value) * (Standard Deviation / sqrt(n))

where Xbar is the sample mean, Z-Value is the critical value from the standard normal distribution table, Standard Deviation is the population standard deviation, and n is the sample size.

(a) For a 99.9% confidence interval, the Z-value corresponding to a 99.9% confidence level is 3.291. Using the given values, the confidence interval can be calculated as follows:

Confidence Interval = 1.659 ± (3.291) * (0.264 / sqrt(200)) = 1.659 ± 0.1153

So the 99.9% confidence interval for the mean weight of all bumblebee bats is (1.543, 1.774).

(b) For a 99% confidence interval, the Z-value corresponding to a 99% confidence level is 2.576. Using the given values, the confidence interval can be calculated as follows:

Confidence Interval = 1.659 ± (2.576) * (0.264 / sqrt(200)) = 1.659 ± 0.0942

So the 99% confidence interval for the mean weight of all bumblebee bats is (1.565, 1.753).

(c) For a 95% confidence interval, the Z-value corresponding to a 95% confidence level is 1.96. Using the given values, the confidence interval can be calculated as follows:

Confidence Interval = 1.659 ± (1.96) * (0.264 / sqrt(200)) = 1.659 ± 0.0734

So the 95% confidence interval for the mean weight of all bumblebee bats is (1.586, 1.732).

(d) For an 80% confidence interval, the Z-value corresponding to an 80% confidence level is 1.282. Using the given values, the confidence interval can be calculated as follows:

Confidence Interval = 1.659 ± (1.282) * (0.264 / sqrt(200)) = 1.659 ± 0.0547

So the 80% confidence interval for the mean weight of all bumblebee bats is (1.604, 1.714).

2) To test whether bumblebee bats weigh less on average than Dr. Clifford Jones claims, we will use the t-distribution technique. We will set up the following hypotheses:

Null hypothesis (H0): The mean weight of bumblebee bats is equal to 1.7 grams.

Alternative hypothesis (Ha): The mean weight of bumblebee bats is less than 1.7 grams.

We will use a one-tailed test since we are only interested in whether the bats weigh less on average. Calculate the test statistic t using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(n))

where the sample mean is 1.659 grams, the hypothesized mean is 1.7 grams, the sample standard deviation is 0.264 grams, and the sample size is 200. Using these values, the test statistic can be calculated as follows:

t = (1.659 - 1.7) / (0.264 / sqrt(200)) = -2.524

Using a t-table or calculator, we can find the critical value for a one-tailed test with a significance level of 0.05 and 199 degrees of freedom to be approximately -1.652.

Since the test statistic t is less than the critical value, we reject the null hypothesis. Therefore, there is evidence to suggest that bumblebee bats weigh less on average than Dr. Clifford Jones claims at a significance level of 0.05.

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Answer:

a

Step-by-step explanation:

Answer:

The mean number of points she scored per game was 8.

Step-by-step explanation:

The mean number of points scored per game is the sum of total points scored divided by the number of games played:

Her point total for each game were 8,14,4,7,6,14,4 and 7.

This means that there were 8 total games.

She scored 8+14+4+7+6+14+4+7 = 64 total points

64/8 = 8

The mean number of points she scored per game was 8.

Look at the attached picture ⤴

Hope it will help u...

Answer:

0.5

Step-by-step explanation:

you have to combine like terms

Answer:

a=-2

Step-by-step explanation:

Let me know if you need the steps tho.

Answer: A.13

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

An object can never act on itself. Forces related to Newton's third law apply to different bodies, therefore they cannot cancel each other out. For example, the reaction to Earth's gravitational pull on the Moon is the Moon's pull on Earth.

Answer:

Step-by-step explanation:

8000x0.04=

$320

Answer:

$320.

Step-by-step explanation:

.04 x 8000 = 320

Feel free to let me know if you need more help! :)

Answer:

C 32

Step-by-step explanation:

[tex]f(x) = 8 \sqrt{143 - x} \\ f(127) = 8 \sqrt{143 - 127} \\ f(127) = 8 \sqrt{16} \\ f(127) = 8 \times 4 \\ \huge \red{ \boxed{ f(127) = 32}}[/tex]

Answer: the interest owed is $21

Step-by-step explanation:

The question is incomplete. The complete question is:

Sari Tagore obtains a $1000 loan to purchase a laser printer. Her interest rate is 7% ordinary interest for 108 days. What is the interest owed?

Solution:

When calculating ordinary interest, we assume that a year has 360 days. We would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

I represents interest paid on the loan

P represents principal or amount borrowed.

R represents interest rate

T represents duration in years

From the information given,

P = 1000

R = 7%

T = 108 days. Converting to years, it becomes 108/360

Therefore

I = (1000 × 7 × 108/360)/100

I = $21

The number of 2-point shots and the number of 3-point shots if, The basketball team scored a total of 79 points last game, They made 35 shots, including 2-point shots and 3-point shots, are 26 and 9 respectively.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Given:

The basketball team scored a total of 79 points last game,

They made 35 shots, including 2-point shots and 3-point shots,

Write the equation as shown below,

x + y = 35

2x + 3y = 79

Here, x  is the number of 2-point shots and y is the number of 3-point shots,

Solve the equation by elimination method,

y = 9, x = 35 - 9 = 26

Thus, the number of 2-point shots is 26  and the number of 3-point shots is 9.

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Answer:

The optimal capital structure of a firm is the best mix of debt and equity financing that maximizes a company’s market value while minimizing its cost of capital. In theory, debt financing offers the lowest cost of capital due to its tax deductibility. However, too much debt increases the financial risk to shareholders and the return on equity that they require. Thus, companies have to find the optimal point at which the marginal benefit of debt equals the marginal cost.

Step-by-step explanation:

Answer:

[tex](C)\dfrac{9+\sqrt{14} }{9+\sqrt{14} }[/tex]

Step-by-step explanation:

To rationalize the expression:

[tex]\dfrac{5-\sqrt{7} }{9-\sqrt{14} }[/tex]

In order to rationalize any Surdic expression, what is needed is to multiply both the numerator and the denominator of the rational function by the conjugate of the denominator.

In the example above:

The denominator is: [tex]9-\sqrt{14}[/tex]

Its conjugate therefore is: [tex]9+\sqrt{14}[/tex]

Therefore, we multiply the fraction by the expression:

[tex]\dfrac{9+\sqrt{14} }{9+\sqrt{14} }[/tex]

Answer:

c

Step-by-step explanation:

Answer:

From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

The mean is given by:

[tex] \bar X = 13.6[/tex]

And the deviation is given by:

[tex]\sigma_{\bar X} =\frac{3}{\sqrt{100}}= 0.3[/tex]

Step-by-step explanation:

For this case we define the random variable X as "number of years of education of self-employed individuals in the U.S." and we know the following properties:

[tex] E(X) = 13.6 , Sd(X) = 3[/tex]

And we select a sample of n = 100

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

Solution to the problem

From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

The mean is given by:

[tex] \bar X = 13.6[/tex]

And the deviation is given by:

[tex]\sigma_{\bar X} =\frac{3}{\sqrt{100}}= 0.3[/tex]

Answer:

a) Mean of the sampling distribution = 13.6 years

b) Standard deviation of the sampling distribution = 0.3

[tex]\bar {x} = N(13.6, 0.3)[/tex]

Step-by-step explanation:

Population mean, [tex]\mu = 13.6 years[/tex]

Population standard deviation, [tex]\sigma = 3.0 years[/tex]

Sample size, n = 100

a) Mean of the sampling distribution = mean of the normal distribution

[tex]\mu_{s} = \mu\\\mu_{s} = 13.6 years[/tex]

b) Standard deviation of the sampling distribution, [tex]\sigma_{s} = \frac{\sigma}{\sqrt{n} }[/tex]

[tex]\sigma_{s} = \frac{3}{\sqrt{100} } \\\sigma_{s} = \frac{3}{10} \\\sigma_{s} = 0.3[/tex]

Answer:

  1/343

Step-by-step explanation:

  [tex]\dfrac{7^{-1}}{7^2}=7^{-1-2}=7^{-3}=\dfrac{1}{7^3}=\boxed{\dfrac{1}{343}}[/tex]

__

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

Answer:

exactly I need help with this one to

Answer:

Step-by-step explanation:

Hello!

The variable of the study is

X: taxi fare from Logan Airport to downtown Boston.

This variable has a normal distribution

Suppose a sample of 7 taxi fares was taken and a 95%CI for the population mean was calculated obtaining:

$[20.51; 24.21]

The confidence level is a way of estimating the value of a population parameter of interest just like the point estimation. The difference is that instead of obtaining one value that may or may not be close to the true value of the parameter you obtain the range of values the parameter may take with a certain level of confidence.

The confidence level of an interval is the probability under which it is built. This probability indicates that if they build 100 confidence intervals, we expect 95 to contain the value of the parameter of interest we are trying to estimate.

As mentioned before in this case the parameter of interest is:

μ: population mean of taxi fares from Logan Airport to downtown Boston

And the 95% CI can be interpreted as:

We are 95% confident that the average taxi fare between Logan Airport and downtown Boston will fall between $20.51 and $24.21.

I hope this helps!

Answer:

The hawk drops the prey from a height of 4 meters.

The prey reaches the ground 4 seconds after.

Step-by-step explanation:

Notice that the equation gives you information about the height of the prey at any time counting from the moment the hawk drops it. Therefore, if we want to find the height at which the hawk drops the prey, we just need to evaluate the expression for time = zero (the starting time). SUch gives as the answer to the first question:

[tex]h=4+11t-3t^2\\h=4+11\,(0)-3\,(0)^2\\h=4\, \,meters[/tex]

Now, in order to find the time at which the prey reaches the ground, we want "h" to be zero (height zero), and solve for "t".

Notice that this gives a quadratic equation that can be solved using the quadratic formula:

[tex]h=4+11t-3t^2\\0=4+11t-3t^2\\-3t^2+11t+4=0\\t=\frac{-11+-\sqrt{11^2-4\,(-3)(4)} }{2\,(-3)} \\t=\frac{-11+-\sqrt{121+48} }{-6} \\t=\frac{-11+-13 }{-6} \\t= 4\,\,and \,\, t=-\frac{1}{3}[/tex]

Since negative times will not make sense, we select the positive 4 (4 seconds)