Answer: I am pretty sure the answer is B
Explanation: If not sorry bro.
(oof already know the answer but at less yall answer so i can add a brainliest) Is this true or false? Think about the differences between climate and weather and complete the following sentence:The short-term, constantly changing state of the air in an area is known as weather, while the conditions of an area over a long period of time is known as climate.
Answer:
True, the statement is correct
Answer:
True
Explanation:
Weather: It is the atmospheric condition for a small area over a short span of time. For example: cloudy weather. If one place is witnessing this condition it may or may not be same for all the places.
Climate: It refers to the atmospheric condition of an area over a long period of time for say a decade or a century. For example: the climate of the polar region is changing drastically and resulting in the reduction of glacial ice.
Kepler's third law relates the period of a planet
to its orbital radius r, the constant G in Newton's law of gravi-
tation (F = Gm1m2/r^2), and the mass of the sun M.. What com-
bination of these factors gives the correct dimensions for the
period of a planet?
Answer:
√(r³ / (MG))
Explanation:
The dimensions of each variable are:
r = [m]
G = [m³/kg/s²]
M = [kg]
Multiplying M and G eliminates kilograms:
MG = [m³/s²]
The radius cubed divided by MG eliminates meters:
r³ / (MG) = [s²]
The square root gives us seconds:
√(r³ / (MG)) = [s]
Kepler's third law relates the time period of a planet to its orbital radius r, the gravitational constant G and the mass of the sun M, the combination of these factors gives the correct dimensions for the period of a planet would be √( 4πr³/GM)
What are Kepler's laws of planetary motion?There are three laws of Kepler as follows
The orbit of the planet is elliptical and the sun is present at one of the two focuses of the elliptical path followed by the revolving planet.
A line segment joining a planet and the Sun covers equal areas during equal intervals of the time period.
The square of a planet's orbital period is proportional to the cube of the length of the semi-major axis of its elliptical orbit.
Think about a small mass M traveling in a circle around a large mass M. The centripetal force for mass m comes from gravity. Taking circular motion as an example and applying Newton's second law,
gravitational force balances the centripetal force
GMm/r² = mv²/r
GM/r = v²/r
Let us take a Time period of the orbital is P
v = 2πr/P
GM/r = 4πr²/P²
P² = 4πr³/GM
P = √( 4πr³/GM)
Thus the correct dimension for the time period in terms of the orbital radius (r), gravitational constant (G ), and the mass of the sun (M) would be √( 4πr³/GM).
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Time for some gravity! Except if have no idea what’s going on, could someone help? :)
Answer: number 2 I think is d all of the above
Explanation: the teacher explained it to the class that.
1). C
2). D
3). B
4). A
5). D
6). B
7). C
8). A
9). B
10). B
In your own words, explain red shift and blue shift. Use at least two complete sentences to write your answer.
Answer:
Redshift and blueshift show how light shifts to shorter or longer wavelengths as objects in space move closer of farther away from us. People looking at an object that is moving away from them see light that has a longer wavelength than it had when it was produced (a redshift), while people looking at an source coming closer see light that is shifted to shorter wavelength (a blueshift).
Give the general name for the type of quantity that has magnitude and acts in a particular direction.
Answer:
Vector quantity
Explanation:
physical quantity that has both magnitude and direction is called vector quantity.
Answer:
Vector
Explanation:
A vector is a quantity that is composed of a magnitude and a direction.
Some examples of vectors are forces. A force has a magnitude that indicates how large or small it is, and also has a direction that indicates where this force is being exerted.
Another popular example of a vector is velocity.
How are light and sound waves affected by the different media they travel though?
Final answer:
Sound waves, as mechanical waves, need a medium to travel and are affected by its properties, while light waves, which are electromagnetic, can travel through a vacuum. When light travels through media of different densities, it experiences changes in speed, leading to refraction and reflection, changing brightness and color perception.
Explanation:
Light and sound waves are fundamentally different in how they interact with various media they travel through. Sound waves are mechanical waves meaning they require a medium like air, liquid, or solid to travel. The density and elasticity of these media affect the speed and quality of sound, with denser media generally allowing faster sound transmission. Also, movements in the medium, such as wind, can also influence the speed and direction of sound waves.
On the other hand, light waves, being electromagnetic waves, do not require a medium and can travel through a vacuum. However, when they pass through different media, their speed can vary. In denser media, light waves slow down which can lead to phenomena such as refraction (bending of the light) or reflection. The changes in speed and direction make light interact with objects differently, often affecting the brightness and color as perceived by the observer.
Classify the waves as being mechanical or electromagnetic. microwave ocean wave seismic wave radio wave
Answer:
Micro waves and radio waves are electromagnetic waves while ocean wave and seismic wave are mechanical waves.
Explanation:
Electromagnetic waves do not require a medium for propagation. They can travel along vacuum just like they travel through matter.
Further examples of electromagnetic waves are x rays, infrared waves etc.
Spectrum of electromagnetic waves in the increasing order of frequency is radio waves, microwaves, infrared waves, visible light, ultraviolet, x ray, gamma ray.
Mechanical waves require a medium for propagation. Thus they cannot travel through a vacuum.
Sound wave is an example of mechanical wave.
Final answer:
Microwaves and radio waves are electromagnetic waves that do not require a medium to travel, whereas ocean waves and seismic waves are mechanical waves that require a medium for their propagation.
Explanation:
Waves can be broadly classified into two categories: mechanical waves and electromagnetic waves. This classification is based on whether the waves require a medium to travel through or not.
Microwave and radio wave are types of electromagnetic waves. These waves do not require a medium to travel and can move through the vacuum of space. Examples of electromagnetic waves include light, radio waves, and X-rays.Ocean wave and seismic wave are categorized as mechanical waves. They require a medium (such as water, air, or the Earth's interior) to travel. Ocean waves move through water, while seismic waves travel through the Earth's crust.To summarize, microwaves and radio waves are electromagnetic in nature, capable of traveling through a vacuum, whereas ocean waves and seismic waves are mechanical, needing a medium to propagate.
List two things you should not do when giving a presentation
Answer:
running or skipping
Explanation:
feelin yourself and talking to quiet
just stay still and talk with a decent voice but no too loud
a granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass of the monument to the nearest tenth.
The mass of the granite monument is
g.
Answer:
The mass of the monument (to the nearest tenth) where volume of the granite monuments is [tex]25,365.4 \mathrm{cm}^{3}[/tex] and density of the granite is [tex]2.7 g / \mathrm{cm}^{3}[/tex] is 68,486.6 g
Explanation:
Given:
Volume of the granite monument, p[tex]=25,365.4 \mathrm{cm}^{3}[/tex]
density of granite, [tex]V=2.7 \mathrm{g} / \mathrm{cm} 3[/tex]
To find:
The mass of the monument to the nearest tenth= ?
Solution:
Step 1:
mass of the monument ,[tex]m=p V \text { grams }[/tex]
step 2:
[tex]m=p V[/tex]
substituting the values,
m[tex]=(25,365.4)(2.7)[/tex]
m[tex] =68,486.58 g[/tex]
m [tex]= 68,486.6 g[/tex] (rounding off to nearest tenth)
Result :
The mass of the monument (to the nearest tenth) where volume of the granite monuments is [tex]25,365.4 \mathrm{cm}^{3}[/tex] and density of the granite is [tex]2.7 \mathrm{g} / \mathrm{cm}^{3}[/tex] is 68,486.6 g.
The mass of the granite monument is 68,486.58 g which has a volume of [tex]25364.4 cm^{3}[/tex] and density of [tex]2.7 gcm^{-3}[/tex].
Given data:
To calculate the mass of the granite monument, we can use the formula:
mass = density * volume
Given that the density of granite is [tex]2.7g cm^{-3}[/tex] and the volume of the monument is [tex]25364.4 cm^{3}[/tex]
we can substitute these values into the formula:
mass = 2.7 * 25,365.4
Calculating the mass:
mass = 68,486.58 g
To express the mass in kilograms, we can divide by 1000 (since there are 1000 grams in a kilogram):
mass = 68,486.58 g / 1000 kg
Calculating the mass in kilograms:
mass = 68.48 kg
Hence, the mass of the granite monument is approximately 68.57 kg, rounded to the nearest tenth.
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Radium has a half-life of 1,660 years. Calculate the number of years until only 1/16th of a sample remains.
years
Radium has a half-life of 1,660 years.The number of years until only 1/16th of a sample remains is 6641 years.
Answer: 6641 years
Explanation:
Given that the half-life of Radium is 1660 years. The number of years to be calculated when the sample of radium could just be remained of 1/16th of its part, which can be calculated by the following means,
Half life, [tex]T_{1 / 2}=1660 \text { years }[/tex]
[tex]\frac{N}{N_{0}}=\frac{1}{16}[/tex]
t is the taken time, then,
[tex]\frac{N}{N_{0}}=e^{-\lambda t}[/tex]
[tex]\frac{N}{N_{0}}=e^{\lambda t}[/tex]
Taking ln on both sides, we get,
[tex]\lambda t=\ln \left(\frac{N}{N_{0}}\right)[/tex]
[tex]t=\frac{1}{\lambda} \ln \left(\frac{N_{0}}{N}\right)[/tex]
[tex]=\frac{T_{1 / 2}}{0.693}\left(\ln \left(\frac{N_{0}}{N}\right)\right)[/tex]
By substituting the given values,
[tex]t = \frac{1660}{0.693}(\ln 16)[/tex]
Therefore, t = 6641 years
What is the weight of a text book whose mass is 2.4 kg measured on the moon? The gravitational acceleration on the moon is approximately 1/6 that on the earth.
Answer:
2.4 kg
1 kg = 10N
2.4 kg = ?
2.4 kg = 24N
On the moon 1/6th
1/6 * 24 = 4N
therefore weight of the textbook on the moon would be 4N
A vehicle moving with a uniform acceleration of 2 m/s2 has
a velocity of 4 m/s at a certain time. What will its velocity be
a 1s later,
b 5s later?
Answer:
a) 6 m/s
b) 14 m/s
Explanation:
Acceleration is change in velocity over change in time.
a) a = Δv / Δt
2 m/s² = (v − 4 m/s) / 1 s
v = 6 m/s
b) a = Δv / Δt
2 m/s² = (v − 4 m/s) / 5 s
v = 14 m/s
(please help ;-;) Which of the following statements about the water cycle is true?
Organisms in the biosphere do not influence the water cycle.
The water cycle only continues during daylight hours.
Plants play a vital role in the water cycle.
Precipitation that falls to the ground ends up only as groundwater.
Answer:
I guess that the answer is plants play a vital role In the water cycle.
Answer:
Plants play a vital role in the water cycle.
Explanation:
Vegetation plays an important role in the water cycle by preventing soil erosion and increasing groundwater levels. In areas with thick vegetation cover, the foliage cover breaks the force of precipitation falling on the ground, which may otherwise cause erosion.
ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give your answer n seconds
Answer:
About 8.3 minutes
Explanation:
Use the formula for velocity as the distance covered by the light divided the time it takes: [tex][tex]velocity=\frac{distance}{time}[/tex][/tex]
Use the information about the speed of light in vacuum: [tex]300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}[/tex]
and the information you are given regarding the distance between Sun and Earth: [tex]1.5 * 10^{11} m[/tex]
to solve the first velocity equation for the unknown time "t":
[tex]velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s[/tex]
we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes
Can someone please tell me how to solve these question below.
16. A man stands on top of a 25 m tall cliff. The man throws a rock upwards at a 25 degree angle above the horizontal with an initial velocity of 7.2 m/s. What will be the vertical position of the rock at t = 2 seconds? What will be the horizontal position of the rock at that time?
Answer:
Vertical position of the rock after 2 seconds = 11.46 m
Horizontal position of the rock after 2 seconds = 13.06 m
Explanation:
Initial height = 25 m
Angle of throw = 25 degrees
Velocity of throw = 7.2 m/s
Horizontal velocity of throw = 7.2 cos 25 = 6.53 m/s
Vertical velocity of throw = 7.2 sin 25 = 3.04 m/s
Acceleration in horizontal direction = 0 m/s²
Acceleration in vertical direction = -9.8 m/s²
Vertical position of the rock at t = 2 seconds
We have equation of motion s = ut + 0.5at²
s = 3.04 x 2 - 0.5 x 9.81 x 2²
s = -13.54 m
Vertical position = 25 - 13.54 = 11.46 m
Horizontal position of the rock at t = 2 seconds
We have equation of motion s = ut + 0.5at²
s = 6.53 x 2 + 0.5 x 0 x 2²
s = 13.06 m
Horizontal position = 13.06 m
Vertical position of the rock after 2 seconds = 11.46 m
Horizontal position of the rock after 2 seconds = 13.06 m
Select the correct answer. A meteor is approaching Earth. Which statement about its motion is true? A. The meteor travels upward relative to Earth. B. The meteor accelerates. C. The meteor is out of Earth’s gravitational force field. D. The meteor falls with a constant velocity.
The meteor accelerates is the true statement about motion when it is approaching Earth.
Answer: Option B
Explanation:
Meteor is referred as the rock or a body made of metal wandering in space. The earth has gravitational pull and when any object or anything comes by, it gets accelerated.
Similarly when a meteor approached the earth, it gets pulled by gravitational force acting upon the earth and it gets accelerated and is forced to move into the earth's field.
Answer:
the meteor accelerates
An engineer in a locomotive sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 270 m from the crossing
and its speed is 12 m/s.
If the engineer’s reaction time is 0.79 s,
what should be the magnitude of the minimum deceleration to avoid an accident?
Answer in units of m/s
2
.
Answer:
a=0.27637 m/s²
Explanation:
Hello,
You should remember that ;
Stopping distance=reaction distance + braking distance
First find the reaction distance which is that distance traveled from point of detecting danger to start of breaking process.
Formula: d=(s*r) where s is speed in m/s and r is reaction time in seconds
Given: s=12m/s and r=0.79 s
d= 12*0.79=9.48 m
Remaining distance to cover and stop
Where distance from locomotive to railroad crossing is 260, then remaining distance will be;
270m-9.48m=260.52 m
To get magnitude of minimum deceleration to avoid an accident you apply the formula:
v²=u²-2as
where
v= final speed = 0 m/s
u=speed of locomotive = 12 m/s
a=acceleration in m/s²
s=remaining distance to cover
v²=u²-2as
0²=12²-2*a*260.52
0=144-521.04 a
144/521.04= 521.04/521.04a
a=0.27637 m/s²
Hope this Helps!
you have a 200 kg bag being lifted with a block and tackle. If you pull with 100 newtons what is the MA of the system?
Answer:
The mechanical advantage of the system is equal to 19.62
Explanation:
The ratio of the force produced by a machine to the force applied to it is called mechanical advantage. In other words it is the ratio of output force to the input force.
In this problem mass=200kg
applied force=100N
input force=100N
output force=[tex]mg=200 \times 9.8=196N.[/tex]
mechanical advantage [tex]MA= \frac{1960}{100}=19.6[/tex]
It gives an idea about the efficiency of a mechanical device. It is indeed a measure of force amplification. In block and tackle system an assembly of ropes and pulleys is used to lift loads. When the moving block is supported by a greater number of rope sections the force amplification will be more.
Answer:
19.6
Explanation:
MA=Ouput/Input
To get output value multiply; 200 (which is the mass) * 9.8 (which is gravity)
So, 200*9.8=1960N
Input is 100 because that is the force you are putting into the bag
Back to our formula MA=Output/Input, enter in our values...
MA=1960/100
Now divide 1960/100=19.6
MA=19.6
(no units; they cancel out).
If the mass of a person is 600kg on Earth what is the persons mass on the moon
Answer:
The mass of the person would remain 600kg.
Explanation:
mass refers to the amount of matter in a particular object. therefore even though the moon has less gravitational force than the Earths, it still would have the same mass since the person is made up of the same amount of matter on Earth and in the moon.
when asked about weight, it would be 1000N. but in mass , same 600kg.
When you are running, there is friction between your feet and the ground and
air resistance between your body and the air. Where does the extra energy
that keeps you moving come from?
OA) kinetic energy
OB) chemical potential energy
OC) potential energy of springs
OD) gravitational potential energy
Answer:
B) chemical potential energy
Explanation:
Your body uses chemical energy from the food you eat to power your motion.
Which of the following is an example of the conclusion phase of the scientific method?
a scientists creates graphs and performs calculations
a scientist decides on a question to explore
a scientist collects data
a scientist examines the results and answers the lab question
Answer:
A scientist examines the results and answers the lab question.
Also in the conclusion write down what you learned from the experiment.
Answer:
the dude above me is right
Explanation:
he right
How are the input and output forces of the parts of a compound machine related?
Answer:
Within a compound machine, the output force of one simple machine becomes the input force of another simple machine.
A hockey puck slides across the ice with an initial velocity of 7.2 m/s. It has a deceleration of 1.1 m/s2 and is traveling toward the goal 5.0 m away. How much time does the goalie have to stop the puck
Answer:
0.74 s
Explanation:
We can solve the problem by using the following SUVAT equation:
[tex]d = ut + \frac{1}{2}at^2[/tex]
where
d = 5.0 m is the displacement
u = 7.2 m/s is the initial velocity
a = -1.1 m/s^2 is the acceleration (which is negative since it is a deceleration)
t is the time
Substituting numbers into the equation, we find:
[tex]5.0 = 7.2 t -0.55t^2\\0.55t^2 -7.2t + 5.0 = 0[/tex]
This is a second-order equation, whose solutions are given by:
[tex]t=\frac{-(-7.2) \pm \sqrt{(-7.2)^2-4(0.55)(5.0)}}{2(0.55)}[/tex]
And the solutions are
t = 0.74 s
t = 12.36 s
The solution we are looking for is the first one, because it corresponds to the first time at which the hockey puck has travelled the distance of 5.0 m, reaching the goal.
The goalie has approximately 6.55 seconds to stop the hockey puck. This is calculated using the motion equation v = u + at, taking into account that the puck is decelerating.
Explanation:This is a question of physics, specifically dealing with the concept of motion and deceleration. We use the equation of motion that relates final velocity (v), initial velocity (u), acceleration (a), and time (t): v = u + at. However, since the puck is decelerating, we are actually dealing with a negative acceleration.
Therefore, the equation becomes final velocity (0 m/s because it will eventually stop sliding) = initial velocity (7.2 m/s given) + acceleration (-1.1 m/s²) * time.
By rearranging this equation we can solve for time (t): t = (final velocity - initial velocity) / acceleration. So it then becomes t = (0 - 7.2) / -1.1. Solving this yields a time of approximately 6.55 seconds for the puck to stop.
Note: The distance to the goal does not play a role in the time it takes for the puck to stop sliding because the puck's motion is determined by its initial velocity and deceleration, not its destination.
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A 4.5 kg bowling ball rolls down a 500m hill. How much potential energy does it lose?
Answer:
22050 J
Explanation:
Given Mass of the ball, m = 4.5 Kg
Height, h =500 m
Acceleration due to gravity, [tex]g= 9.8m/s^{2}[/tex]
To calculate the potential energy we use formula,
[tex]PE = mgh[/tex]
Substituting the given values, we get
PE = 4.5× 9.8×500
=22050 J
The potential energy loss for a 4.5 kg bowling ball rolling down a 500m hill would be approximately 221325 Joules in an idealized scenario.
Explanation:The potential energy loss of an object rolling down a hill can be calculated using the formula for gravitational potential energy, PE = mgh, where m is the mass of the object, g is the gravitational acceleration (9.81 m/s² on Earth), and h is the height of the hill. So, for a 4.5 kg bowling ball rolling down a 500m hill, the potential energy loss would be PE = (4.5 kg) * (9.81 m/s²) * (500 m), which equals 221325 Joules. However, it's important to note that this is an idealized calculation and in real scenarios some of this energy would be transferred into other forms such as kinetic energy as the ball speeds up, and thermal energy due to friction.
Relevant concepts: Potential Energy, Kinetic Energy, and Gravitational Potential Energy.
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PLEASE HELP BRAINLIEST + POINTS'
How much work is done by a 100W engine in 120s? P = W/t
Question 15 options:
120 J
12,000 J
1200 J
.833 J
For this case we have that by definition, physical power refers to the amount of work done for a unit of time.
So:
[tex]P = \frac {W} {t}[/tex]
Where:
W: It's the work
t: It's time
The power units are in [tex]\frac {Joules} {s} = Watts[/tex]
So, according to the problem data we have:
[tex]P = 100W\\t = 120s[/tex]
Clearing the work of the formula:
[tex]W = P * t\\W = 100 * 120 = 1200[/tex]
Thus, the work is 1200 joules.
Answer:
Option C
A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a total of 2 minutes for the bicycle to return to point A. What is the average speed and average velocity of the bicycle?
Answer:
2.5 m/s
0 m/s
Explanation:
Average speed is distance over time.
Average velocity is displacement over time.
The bicycle travels 150 meters from A to B, then 150 meters from B to A. So the distance is 300 meters and the displacement is 0 m.
s = 300 m / 120 s = 2.5 m/s
v = 0 m / 120 s = 0 m/s
3. Order the following lengths from shortest to longest.
a. 400 millimeters
b. 22 kilometers
c. 170 meters
d. 3.3 centimeters
Answer: [tex]d < a < c < b[/tex]
[tex]3.3 cm < 400 mm < 170 m < 22 km[/tex]
Explanation:
Firstly, let's convert these length to meters [tex]m[/tex], in order to work with the same units:
a. 400 millimeters
[tex]400 mm \frac{1m}{1000 mm}=0.4 m[/tex]
b. 22 kilometers
[tex]22 km \frac{1000m}{1 km}=22000 m[/tex]
c. 170 meters
Here the lenght is already in meters
d. 3.3 centimeters
[tex]3.3 cm \frac{1m}{100 cm}=0.033 m[/tex]
Now that we have all the lengths in meters, we can order them from shortest to longest:
[tex]0.033 m < 0.4 m < 170 m < 22000 m[/tex]
or
[tex]d < a < c < b[/tex]
Need help asap pls!!!
Select all that apply.
The moon _____.
orbits the sun
has no atmosphere
rotates and revolves in the same amount of time
controls the Earth's ocean tides
has less gravity than Earth
Answer:
a,d,e
Explanation:
all of those are true for it orbits the earth witch orbits the sun
the moon has no atmosphere for if it did then there would be a higher chance for water and plants on the moon
the moon is less deans than the earth and its gravitational pole is 1.62 m/s^2
and in your text book it says Tides are the daily rise and fall of sea level at any given place. The pull of the Moon’s gravity on Earth is the primary cause of tides and the pull of the Sun’s gravity on Earth is the secondary cause. The Moon has a greater effect because, although it is much smaller than the Sun, it is much closer. The Moon’s pull is about twice that of the Sun’s
Answer:
A. B. D. E.
Explanation:
all of those are true for it orbits the earth witch orbits the sun
the moon has no atmosphere for if it did then there would be a higher chance for water and plants on the moon
the moon is less deans than the earth and its gravitational pole is 1.62 m/s^2
and in your text book it says Tides are the daily rise and fall of sea level at any given place. The pull of the Moon’s gravity on Earth is the primary cause of tides and the pull of the Sun’s gravity on Earth is the secondary cause. The Moon has a greater effect because, although it is much smaller than the Sun, it is much closer. The Moon’s pull is about twice that of the Sun’s.
define average velocity and instantaneous velocity when are they same
Answer:
Look to the explanation
Explanation:
Average velocity: is the average rate of change of displacement with
respect to time
Average velocity is a measure for distance traveled in a given time
We can calculate the average velocity by the rule [tex]v=\frac{s}{t}[/tex]
where s is the displacement and t is the time
Instantaneous velocity: is the velocity of an object in motion at a
specific point (x , t)
instantaneous velocity is the limit of velocity as the change in time
approaches zero
We can calculate the instantaneous velocity by the rule [tex]v=\frac{ds}{dt}[/tex]
Average velocity is equal to the instantaneous velocity when
acceleration is zero
Jesseca’s material In what areas of the country should this material be marketed?
Answer: Somewhere with high temperatures.
Explanation:
Answer:
Because the material is meant to coat roofing shingles to keep houses cooler, the material should be marketed in areas that have high temperatures.
Explanation: