5. What is the amplitude of the sinusoidal function? Please help

Answer:

-9.4, -0.5, 0.75, 1.25, 7/4

Step-by-step explanation:

These are the values of all the numbers in order.

Have a good day!!!

To plot the given numbers -0.5, 7/4, 1.25, 0.75, -9/4 on a number line, convert them into decimal form and mark these points on a line between appropriate integers. Hence, the points are -2.25 (between -2 and -3), -0.5 (between 0 and -1), 0.75 (between 0 and 1), and 1.25 and 1.75 (between 1 and 2).

To plot the given numbers -0.5, 7/4, 1.25, 0.75, -9/4 on a number line, we first need to convert them all into the same form. Converting everything into decimals, we have -0.5, 1.75 (which is 7/4), 1.25, 0.75, and -2.25 (which is -9/4).

Start by drawing a straight horizontal line and mark the points for integers. For example, if the numbers range from -3 to +2, mark these integers on your line. Next, find the points that correspond to the decimal numbers. Suppose you've marked the numbers from -3 to 2, your plot would look like the following:

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Answer:

x = 1 is not part of the domain

Step-by-step explanation:

The denominator of g(x) cannot be zero as this would make g(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve

x - 1 = 0 ⇒ x = 1 ← restricted value

The number x = 1 is not part of the domain of the function g(x) = (x+2)/(x-1) because setting x to 1 would result in division by zero, which is undefined. Thus, x = 1 is an asymptotic value and is excluded from the domain.

The number that is not part of the domain of the function g(x) = \frac{x+2}{x-1} is x = 1. Knowing that the domain of a function includes all the values that x can take on for which the function is defined, we can identify values that are not in the domain by looking for any values that would cause the function to be undefined. In the case of g(x), since it involves a division by x-1, we need to make sure that the denominator does not equal zero since division by zero is undefined in mathematics.

To find out when the denominator is zero, we set x-1 = 0 and solve for x. The solution is x = 1, which means that x cannot be 1, since it would make the function undefined. Therefore, x = 1 is not part of the domain of g(x).

As described in FIGURE 4.4 from OpenStax under a CC BY 4.0 license, functions like y = \frac{1}{x} have asymptotes or limits that indicate values that are not part of the domain. g(x) has a similar characteristic, where x = 1 is an asymptote.

Answer: 37%

Step-by-step explanation:

Initial Population                                        = 100,000

 Population after 5 years                            = 137,000

Population increase                                    = 137,000 - 100,000

                                                                     = 37,000

Therefore % increase                                  = 37,000/100,000 x 100

                                                                     = 37%

Final answer:

The final line of Mariana's work would show identical sides after simplification, resulting in an equation like 0 = 0 or x = x, indicating an infinite number of solutions.

Explanation:

If Mariana solved a linear equation and found that it had an infinite number of solutions, the final line of her work would show that both sides of the equation are identical after simplification. For instance, if the original equation was 2x + 3 = x + x + 3, upon simplifying both sides, she would end up with x + x = x + x, which is an identity (indicating that any value for x would satisfy the equation). Therefore, the final line could have been a simplified equation that resulted in a statement like 0 = 0 or x = x after all terms cancel out.

Answer:

t=3

Step-by-step explanation:

6t= 36+7-25

t=18/6

Answer:

Step-by-step explanation:

Exponential functions have the form

f(x) = bx, where b > 0 and b ≠ 1. Just as in any exponential expression, b is called the base and x is called the exponent.

Answer:

Exponential functions have the form

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

80% of the test = 32 questions

100% of the test = x questions

Cross multiply

80*x = 100 * 32   Combine the right

80x = 3200         Divide by 80

x = 3200/80

x = 40

There are 40 questions on the test.

Answer:

$206.4

Step-by-step explanation:

8.6*24=206.4

Answer:

$896.70

Step-by-step explanation:

Amount( A) Devi earned can be calculated from the formula below

[tex]A =P ({ 1 + \frac{r}{m} })^{mt}[/tex]

Where,

P= principal=$750

r=rate=6%=0.06

m=compounding frequency=4

t=time=3yrs

[tex]A =750 ({ 1 + \frac{0.06}{4} })^{(4 \times 3)}[/tex]

[tex]A =750 ({ 1 + 0.015)}^{12}[/tex]

[tex]A =750 \times ({ 1.015)}^{12}[/tex]

[tex]A =750 \times 1.1956[/tex]

[tex]A = 896.70[/tex]

Answer:

135

885-750 is 135 on financial literacy

A. side AB = 38/3 units B.m∠VYX =77°

Step-by-step explanation:

A.A rhombus has its four sides equal. This means side AB=side CD

Given that AB=5x+1 and CD=2x+8  equate the two sides to find value of x as;

5x+1=2x+8

collect like terms

5x-2x=8-1

3x=7

x=7/3

side AB = 5x+1

AB= 5*7/3 +1

AB=35/3 +1

AB=35/3 +3/3 = 38/3

B.

The diagonals of a rhombus intersect to form 90°

Hence

(3n²-0.75)°=90°

3n²=90°+ 0.75°

3n² =90.75° -----dividing by 3 both sides

n² =90.75°/3 =30.25°

n²=30.25°

n=√30.25°

n=5.5°

so angle Z =90°

and angle ZVW =(9n+2)°

∠ZVW = (9*5.5 +2 )° =51.5°

In a rhombus all four sides are equal, thus side VY = YX.This means triangle VYX is an isosceles triangle.

Hence angle ∠YVZ=∠WVZ =51.5°, and because VYX is an isosceles triangle then ∠YXV =51.5° so

∠VYX= 180°-(51.5°+51.5°)

          =180°-103°=77°

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Answer:

Part a) The equation for the volume of the film canister is

[tex]32\pi=\pi r^{2}(8)[/tex]

Part b) The radius of the film canister is [tex]2\ cm[/tex]

Step-by-step explanation:

The complete question is

A film canister in the shape of a cylinder has a height of  8 centimeters and a volume of 32π cubic centimeters.

a. Write an equation for the volume of the film canister.

b. What is the radius of the film canister?

Part a) Write an equation for the volume of the film canister

we know that

The volume of a cylinder is equal to

[tex]V=\pi r^{2} h[/tex]

where

r is the radius of the circular base

h is the height of the cylinder

we have

[tex]V=32\pi\ cm^3[/tex]

[tex]h=8\ cm[/tex]

substitute

[tex]32\pi=\pi r^{2}(8)[/tex] ----> equation for the volume of the film canister

Part b) What is the radius of the film canister?

we have

[tex]32\pi=\pi r^{2}(8)[/tex]

[tex]32\pi=8\pi r^{2}[/tex]

Simplify

Divide by 8π both sides

[tex]4=r^{2}[/tex]

square root both sides

[tex]r=2\ cm[/tex]

The equation for the volume of the film canister is V = 3.142 × r² × 8.

Use the formula V = πr²h, where V represents the volume, r is the radius, and h is the height.

Substitute the given values into the formula to calculate the volume.

For a given height of 8 centimetres, the volume formula becomes V = 3.142 × r² × 8.

Answer:

3x² - 12x - 36

= 3(x - 6)(x + 2)

Step-by-step explanation:

3x² - 12x - 36      Find any common factor. All terms are divisible by 3.

= 3(x² - 4x - 12)    Find two numbers that sum to -4 and whose product is -12. Replace -4 with these two numbers.

= 3(x² - 6x + 2x - 12)   Group the terms splitting from the middle

= 3( (x² - 6x) + (2x - 12) )   Find the common factor in each group.

= 3( x(x - 6) + 2(x - 6) )      The groups have a common factor (x - 6).

= 3( (x - 6)(x + 2) )           Remove the extra brackets

= 3(x - 6)(x + 2)             Fully factored

100 children tickets and 200 adult tickets were sold.

Step-by-step explanation:

Given,

Cost of one student ticket = $4

Cost of one adult ticket = $6

Total sales = $1600

Number of tickets sold = 300

Let,

x represent the number of children tickets sold.

y represent the number of adult tickets sold.

According to given statement;

x+y=300      Eqn 1

4x+6y=1600   Eqn 2

Multiplying Eqn 1 by 4

[tex]4(x+y=300)\\4x+4y=1200\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](4x+6y)-(4x+4y)=1600-1200\\4x+6y-4x-4y=400\\2y=400[/tex]

Dividing both sides by 2

[tex]\frac{2y}{2}=\frac{400}{2}\\y=200[/tex]

Putting y=200 in Eqn 1

[tex]x+200=300\\x=300-200\\x=100[/tex]

100 children tickets and 200 adult tickets were sold.

Keywords: linear equation, elimination method

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Answer:

[tex](x^3-11x^2+ 22x + 40)\div (x-5)=(x^2-6x-8)[/tex]

Step-by-step explanation:

When dividing [tex](x^3-11x^2+ 22x + 40)[/tex] by [tex](x-5),[/tex]

1. Multiply [tex](x-5)[/tex] by [tex]x^2[/tex] and subtract the result from [tex](x^3-11x^2+ 22x + 40)[/tex] to eliminate [tex]x^3:[/tex]

[tex](x^3-11x^2+ 22x + 40)-x^2(x-5)\\ \\=x^3-11x^2+22x+40-x^2+5x^2\\ \\=-6x^2+22x+40[/tex]

2. Multiply [tex](x-5)[/tex] by [tex]-6x[/tex] and subtract the result from [tex]-6x^2+22x+40[/tex] to eliminate [tex]-6x^2:[/tex]

[tex]-6x^2+22x+40-(-6x)(x-5)\\ \\=-6x^2+22x+40+6x^2-30x\\ \\=-8x+40[/tex]

3. Multiply [tex](x-5)[/tex] by [tex]-8[/tex] and subtract the result from [tex]-8x+40[/tex] to eliminate [tex]-8x:[/tex]

[tex]-8x+40-(-8)(x-5)\\ \\=-8x+40+8x-40\\ \\=0[/tex]

So,

[tex](x^3-11x^2+ 22x + 40)\div (x-5)=(x^2-6x-8)[/tex]

Answer:

[tex]\large\boxed{x=\dfrac{1}{2}}[/tex]

Step-by-step explanation:

[tex]|a|=\left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a<0\end{array}\right\\\\|x-4|=\left\{\begin{array}{ccc}x-4&for&x-4\geq0\to x\geq4\\-(x-4)&for&x<4\end{array}\right[/tex]

[tex](1)\ x<4\\\\-(x-4)-5=3(x-1)\qquad\text{use the distributivep property}\\\\-x-(-4)-5=3x+(3)(-1)\\\\-x+4-5=3x-3\qquad\text{combine like terms}\\\\-x+(4-5)=3x-3\\\\-x-1=3x-3\qquad\text{add 1 to both sides}\\\\-x-1+1=3x-3+1\\\\-x=3x-2\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\-x-3x=3x-3x-2\\\\-4x=-2\qquad\text{divide both sides by (-4)}\\\\\dfrac{-4x}{-4}=\dfrac{-2}{-4}\\\\x=\dfrac{1}{2}\in(1)[/tex]

[tex](2)\ x\geq4\\\\x-4-5=3(x-1)\\\\x+(-4-5)=3x-3\\\\x-9=3x-3\qquad\text{add 9 to both sides}\\\\x-9+9=3x-3+9\\\\x=3x+6\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\x-3x=3x-3x+6\\\\-2x=6\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2x}{-2}=\dfrac{6}{-2}\\\\x=-3\notin(2)[/tex]

The equation of a line parallel to y = 5x + 4 that passes through (-1 , 2) is y = 5x + 7

Step-by-step explanation:

The parallel lines have:

The form of the linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept

∵ The equation of the given line is y = 5x + 4

∴ m = 5 and b = 4

∵ The two lines are parallel

∴ Their slopes are equal

∴ The slope of the parallel line = 5

- Substitute the value of the slope in the form of the equation

∴ y = 5x + b

- To find b substitute x and y in the equation by the coordinates

   of any point on the line

∵ The parallel line passes through point (-1 , 2)

∴ x = -1 and y = 2

∵ 2 = 5(-1) + b

∴ 2 = -5 + b

- Add 5 to both sides

∴ 7 = b

- Substitute the value of b in the equation

∴ y = 5x + 7

The equation of a line parallel to y = 5x + 4 that passes through (-1 , 2) is y = 5x + 7

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Answer:

-2

Step-by-step explanation:

The equation is -12/c=6

by solving for c you get,

-12/c=6

Then multiply both sides by the LCM c to get, -12=6c

Divide both sides by 6 to get,

-12/6=6c/6

-2=c

Verification:

-12/-2=6 since when a negative number divides a negative number the answer is a positive value

Answer:

(-∞,∞) or {y|y∈R}

Step-by-step explanation:

The team moved the ball -3 yards per play.

Step-by-step explanation:

Given,

Total yards lost = 12 yards

Total plays = 4 plays

As the yards are lost, therefore, we will use negative sign.

Yards per play = [tex]\frac{Number\ of\ yards}{Number\ of\ plays}[/tex]

Yards per play = [tex]\frac{-12}{4}[/tex]

Yards per play = -3

The team moved the ball -3 yards per play.

Keywords: division, unit rate

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Answer:

2 years are the 18.2% of 11 years.

Step-by-step explanation:

For calculating what percentage of 11 years is 2 years, we have to do the following calculations:

Fraction used to represent the question = 2/11

Now, we divide 2 by 11, where 2 is the dividend and 11 the divisor:

2/11 = 0.1818....

Converting 0.1818 to percentage:

0.1818 * 100 = 18.2% (Rounding to the nearest tenth)

2 years are the 18.2% of 11 years.

Answer:

It's 6 units

Step-by-step explanation:

i took the test

Answer:

Step-by-step explanation:

Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12   (answer)

HOPE THIS HELPED ;3

Answer:

Step-by-step explanation:

4 1/2 minutes = 4.5 minutes

2 / 4.5 = 0.44 laps per minute

OR

4.5 / 2 = 2.25 minutes per lap

not sure which one ur looking for...but both are unit rates

The unit rate of Jordan's swimming speed is approximately 0.44 laps per minute. This is calculated by dividing the number of laps (2) by the total time (4.5 minutes).

To identify the unit rate in this scenario, we first need to understand what we are finding. The unit rate means how much of something is done in one unit of time, in this case, how many laps Jordan can swim in one minute. Since Jordan can swim two laps in 4 1/2 minutes, we want to find out how many laps he can swim in one minute. We divide the total laps (2) by the total time (4.5). This will compute to approximately 0.44. Hence, Jordan can swim around 0.44 laps in one minute.

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Hey!

I'm also getting 11.4, do you think you're wrong or is it saying so? I have also calculated the answer 11.4.

I believe you aren't wrong, but we will make sure.

12 Divided by 100 times 95, you get 11.4, I believe you're correct!

Please give me any updates and let me know if you need any extra help.

Balancing of equations as shown in the attached document requires that the number of atoms, of an element, on the left of the equation is equivalent to the number of the atoms of the same element on the right of the equation. This is in observation of the conservation of mass rule of thermodynamics. Mass and energy cannot be destroyed nor created, it can only be transformed from one form to another. In this case, mass remains the same in the system since this is a chemical reaction- only the bonds between atoms are being rearranged.

Answer:

Explanation:

1. Using the minimun number of sheets  of paper in the interval [300, 400]

a) Cost: $ 2.00 / 100 sheets

b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day

c) Approimately 20 school days per month:

2. Using the maximum number of sheets of paper in the interval [300, 400]

a) Cost: $ 2.00 / 100 sheets

b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day

c) Approimately 20 school days per month:

3. Middle value:

Calculate the middle value between $160.00 and $120.00

Thus, the answer is the option A.

Answer:

The fence is 18.9 ft long.

Step-by-step explanation:

If you were to create a diagonal line from corner to corner with a square that is 10x16ft, you would have a triangle with 2 known sides and an unknown value. In this case, because you are making a 90° triangle, you can use Pythagorean Theorem:

a^{2} + b^{2} = c^{2}

10^{2} + 16^{2} = c^{2}

100 + 256 = c^{2}

356 = c^{2}

√356 = c

18.9 = c

The length of the fence that Justin needs to split the garden diagonally is approximately 18.9 feet (rounded to the tenth of a foot).

To split the rectangular garden diagonally using a fence, you would be creating two right triangles with the fence as the hypotenuse. You can use the Pythagorean Theorem to find the length of the fence.

The Pythagorean Theorem states: [tex]\(c^2 = a^2 + b^2\)[/tex], where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

In this case, the rectangular garden has dimensions of 10 feet and 16 feet, so a = 10 and b = 16. Let c be the length of the fence.

Now, use the Pythagorean Theorem to find c:

[tex]\[c^2 = 10^2 + 16^2\][/tex]

[tex]\[c^2 = 100 + 256\][/tex]

[tex]\[c^2 = 356\][/tex]

Now, take the square root of both sides to find c:

[tex]\[c = \sqrt{356} \approx 18.9\text{ feet}\][/tex]

So, the length of the fence that Justin needs to split the garden diagonally is approximately 18.9 feet (rounded to the tenth of a foot).

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65 student tickets were sold

Solution:

Given that movie theater sells student tickets for $ 6 and adults for $ 8

Let "s" be the number of student tickets sold

Let "a" be the number of adult tickets sold

Cost of 1 student ticket = $ 6

Cost of 1 adult ticket = $ 8

Given that theater sold 140 tickets

Number of student tickets sold + number of adult tickets sold = 140

s + a = 140 ------ eqn 1

The theater generated $ 990

number of student tickets sold x Cost of 1 student ticket + number of adult tickets sold x Cost of 1 adult ticket = 990

[tex]s \times 6 + a \times 8 = 990[/tex]

6s + 8a = 990 ------ eqn 2

Let us solve eqn 1 and eqn 2 to find values of "s" and "a"

From eqn 1,

s = 140 - a ----- eqn 3

Substitute eqn 3 in eqn 2

6(140 - a) + 8a = 990

840 - 6a + 8a = 990

2a = 150

a = 75

Substitute a = 75 in eqn 3

s = 140 - 75

s = 65

Therefore 65 student tickets were sold

Answer:

53q+10

Step-by-step explanation:

(-3q+3)+7(8q+1)

-3q+3+56q+7

53q+3+7

53q+10

Answer:

[tex] - 3q + 3 + 56q + 7 \\ 53q + 10[/tex]

Good luck!

Intelligent Muslim,

From Uzbekistan.