7. What is the acceleration of the box?
a. 2.5 m/s2
b. 4 m/s2
c. 6 m/s2
d. 10 m/s2

7.What Is The Acceleration Of The Box?a.2.5 M/s2b.4 M/s2c.6 M/s2d.10 M/s2

Answers

Answer 1
This is your answer
b) 4m/s2
Here’s my work
7.What Is The Acceleration Of The Box?a.2.5 M/s2b.4 M/s2c.6 M/s2d.10 M/s2

Related Questions

How does atmospheric pressure affect the boiling point of a liquid

Answers

Answer:

The atmospheric pressure and boiling point are directly proportional

Increasing atmospheric pressure increases the boiling point also

Explanation:

The atmosphere contain molecules that are in constant motion. They exert a downward force on a liquid’s surface. The higher the air pressure, the harder it is for the liquid to evaporate. Therefore, the boiling point of a solvent or liquid is affected by the atmospheric pressure and boiling point is raised.

A liquid in a high pressure environment boils at a higher temperature.

When placed in a lower pressure environment it boils at a lower temperature.

The starting conditions of an oscillator are characterized by the

Answers

Answer:

The phase constant

Explanation:

The phase constant tells how much a signal is shifted along the x-axis. A phase constant of ϕ means that each value of the signal happens ϕ amount of time earlier. If the signal has a beginning, then a phase constant of ϕ means the signal occurs that much sooner.

The starting conditions of an oscillator are characterized by the phase constant. Option B is correct.

Phase Constant:

This represents the number of oscillation per cycle of wave. It is denoted by [tex]\bold {\phi}[/tex]. It is also known as Propagation constant. The phase constant can be calculated using the formula.

[tex]\bold {\phi = \dfrac {2\pi }{\lambda}}[/tex]

Where, lambda is wavelength.

Frequency is the number of waves passing from a point per unit time.Amplitude is the height of the wave from its mid point.

Therefore, option B is correct. The starting conditions of an oscillator are characterized by the phase constant.

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El vector a tiene componented ax= 2.70 cm, ay=2.25 cm; y el vector b tiene componentes bx= 0.30 cm, by= 1.75 cm. Calcular las componentes de la resultante a+b

Answers

Answer:

Explanation:

Given that,

A vector A has x component to be 2.7cm and y component to be 2.25cm

Then,

A = 2.7•i + 2.25•j

A vector B has x component of 0.30cm and y component of 1.75cm

B = 0.3•i + 1.75•j

So, we want to find A+B

Addition of vectors

Generally

(a•i + b•j) + (c•i + d•j) = (a+c)•i +(b+d)•j

Vectors are added component wise.

So,

A + B = (2.7•i + 2.25•j) + (0.3•i + 1.75•j)

A + B = (2.7 + 0.3)•i + (2.25 + 1.75)•j

A + B = 3•i + 4•j

We can also find it magnitude and direction

Generally,

A = a•i + b•j

|A| = √(a²+b²)

<A = arctan(b/a)

So,

|A+B| = √(3²+4²) = √9+16 = √25

|A+B| = 5

And it's direction

< = arctan(y/x)

< = arctan(4/3)

< = 53.13°

What is the equivalent resistance in this circuit?


Ω




What is the current in this circuit?


A

Answers

Answer:

6.0?

Explanation:

What is the current in this circuit?

A

Hold on, our servers are swamped. Wait for your answer to fully load.

Answer:

The first one is 15.

The second one is 3.0.

Explanation:

You add up all the sides accept the voltage. 2+3+4+6= 15

For the second one you divide the voltage by all the resisters. 45/15=3

During a redox reaction the molecule that gains an electron is

Answers

Since the molecule gains an electron through this redox reaction, it is oxidising the compound which is making the overall charge rising towards positive.

Hence, they are called Oxidants as they oxidise.
Final answer:

In a redox (reduction-oxidation) reaction, the molecule that gains an electron is reduced. Reduction and oxidation always occur together in such reactions. Reduced molecules often act as energy carriers in metabolic pathways.

Explanation:

During a redox (reduction-oxidation) reaction, the molecule that gains an electron is referred to as being reduced. This process is accompanied by an energy transfer. When a molecule loses an electron (a process termed as oxidation), energy is released; this energy and the electron are then transferred to another molecule, resulting in reduction of that molecule. These two processes, oxidation and reduction, always occur together in a redox reaction.

For example, considering a metabolic pathway involving Nicotinamide adenine dinucleotide (NAD+), when it accepts a hydride ion (H-) from a hydrogen atom, it gets reduced to form NADH. Here, NAD+ is the molecule that gets reduced in this redox reaction.

In summary, in redox reactions, the molecule that gains an electron and is reduced can act as an energy carrier, an important function in metabolism, facilitating the controlled transfer of energy within the cell. The concepts of oxidation and reduction are integral to understanding energy extraction and utilization in cells.

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A glass flask whose volume is 1000 cm3 at a temperature of 1.00 ∘C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0 ∘C , a volume of 8.25 cm3 of mercury overflows the flask.If the coefficient of volume expansion of mercury is 18.0×10−5K−118.0×10 compute the coefficient of volume expansion of the glass.

Answers

Answer:

[tex]1.8\times 10^{-5}/K[/tex]

Explanation:

Volume of glass flask,[tex]V_0=1000 cm^3[/tex]

[tex]T_1=1.00^{\circ} C[/tex]

[tex]T_2=52.0^{\circ} C[/tex]

Over flow[tex]\Delta V=8.25 cm^3[/tex]

Coefficient of mercury=[tex]\beta_{Hg}=18.0\times 10^{-5}/K[/tex]

[tex]\Delta V_{Hg}=\beta_{Hg}V_0(T_2-T_1)=18\times 10^{-5}\times 1000\times (52-1)[/tex]

[tex]\Delta V_{Hg}=9.18 cm^3[/tex]

[tex]\Delta_{gass}=\Delta V-\Delta_{Hg}=9.18-8.25=0.93 cm^3[/tex]

[tex]\beta_{gass}=\frac{\Delta V_{gass}}{V_0(T_2-T_1)}[/tex]

[tex]\beta_{gass}=\frac{0.93}{1000\times (52-1)}[/tex]

[tex]\beta_{gass}=1.8\times 10^{-5}/K[/tex]

Hence, the coefficient of volume expansion of the glass=[tex]1.8\times 10^{-5}/^{\circ} C[/tex]

The coefficient of volume expansion of the glass [tex]\bold { 1.8 x 10^-^5\ K^-^ 1}[/tex]

Given here,

Volume of the glass flask = 1000[tex]\bold {cm^3}[/tex]

Initial temperature = 1[tex]\bold{^oC}[/tex]

Final temperature = 52 [tex]\bold{^oC}[/tex]

[tex]\bold{ \Delta V = V_0 \beta \Delta T}[/tex]

Where,

[tex]\bold {\Delta V}[/tex] - Change in volume

[tex]\bold{V_0}[/tex] - initial volume = 1000cm

[tex]\bold {\beta }[/tex] -  coefficient of volume expansion

[tex]\bold{\Delta T }[/tex] - temperature [tex]\bold { = T_2- T_1}[/tex]

Put the values in the formula

[tex]\bold {\Delta V_H_g = 18\times 10^-^5 \times 1000\times 51}\\\\\bold {\Delta V_H_g = 9.18 cm^3}[/tex]

[tex]\bold {\Delta Vglass = \Delta V_H_g - \Delta _H_g}\\\\\bold {\Delta Vglass = 9.18 -8.25 }\\\\\bold {\Delta Vglass = 0.93 cm^3}[/tex]

So,  coefficient of volume expansion for gas,

[tex]\bold {\beta glass = \dfrac {0.93 }{1000 \times 51}}\\\\\bold {\beta glass = 1.8 x 10^-^5\ K^-^ 1}[/tex]

The coefficient of volume expansion of the glass [tex]\bold { 1.8 x 10^-^5\ K^-^ 1}[/tex]

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A sound wave (a periodic longitudinal wave) from a loudspeaker travels from air into water. The frequency of the wave does not change, because the loudspeaker producing the sound determines the frequency. The speed of sound in air is 343 m/s, whereas the speed in fresh water is 1482 m/s. When the sound wave enters the water, does its wavelength increase, decrease, or remain the same

Answers

Answer:

When the sound wave enters the water its wavelength increase.

Explanation:

Given:

Speed of sound in air [tex]v = 343 \frac{m}{s}[/tex]

Speed of sound in fresh water [tex]v' = 1482 \frac{m}{s}[/tex]

We know that when wave travel into one medium to another medium frequency doesn't change.

Velocity is given by,

  [tex]v = f \lambda[/tex]

In above equation frequency is constant,

So when sound wave enters the water wavelength increase because speed sound is increase in water as compare to air.

Therefore, when the sound wave enters the water its wavelength increase.

Convection

A) is energy similar to radiant heat from the sun.
B) is the result of conductive heat loss to the air that overlies the surface of the body.
C) is the direct transfer of energy through physical contact.
D) changes a liquid to a vapor.

Answers

Answer:

A) energy similar to radiant heat from the sun

The incoming infrared radiation from the Sun as it travels towards Earth is _____. mostly reflected back out into space mostly absorbed and transmitted toward Earth's surface equally absorbed and reflected completely blocked and reflected by the upper atmosphere

Answers

Answer:

Mostly absorbed and transmitted toward Earth's surface

Explanation:

Infrared radiation from the sun reaches the Earth's surface and warms the Earth's surface. It emits some infrared radiation, some absorbed by gases such as carbon dioxide in the atmosphere. This is known as the greenhouse effect. and If it don't, radiation from the earth is powerful enough to burn the skin.

so correct answer is Mostly absorbed and transmitted toward Earth's surface

Answer:

mostly absorbed and transmitted toward Earth's surface

Explanation:

Kinect energy is expressed using the unit

Answers

joule
The standard unit for kinetic energy is the joule (J). The joule is the standard unit for energy in general. Other units for energy include the newton-meter (Nm) and the kilogram meter squared over seconds squared (kg m2/s2).

Answer:

joule

Explanation:

every unit for Energy is joule J

On a merry-go-round, animals at the edge are located 4 times farther from the axis of rotation than the animals near the center. The animals near the center has a rotational speed of 3 RPM and a tangential speed of 2 m/sec.

What is the rotational speed of the animals near the edge?

a 3 RPM
b 12 RPM
c 2 RPM
d 6 RPM

Answers

Answer:

12 RPM

Explanation:

I would calculate the distance from the edge to the center, and then multiple that by 3RPM with 2 m/sec

Write down the (real) electric and magnetic fields for a monochromatic plane wave of amplitude E0 , frequency w, and phase angle zero that is (a) traveling in the negative x direction and polarized in the z direction; (b) traveling in the direction from the origin to the point (1, 1, 1), with polarization parallel to the xz plane. In each case, sketch the wave, and give the explicit Cartesian components ofk and ii.

Answers

Answer:

a) the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis

b) the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)

Explanation:

a) the polarization the determined wave oscillates the electric field, which is the z axis

 As the wave travels on the negative x-axis and the magnetic field is perpendicular, this field goes on the positive y-axis

the oscillation of this field is in phase, when the magnetic field goes in the negative direction of y, the elective field goes in the positive direction of the z axis

be) in the case of a polarization in the xi plane the magnetic field must go in the direction of the magnetic field perpendicular to this electric field and the speed in the negative x the magnetic field goes in the x direction and in the direction (1, - 1.1)

In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following pressure p, in atm, as a function of volume V, in liters: p = p0 V-6/5. Here p0 is a constant of units atm⋅L6/5. show answer Incorrect Answer 50% Part (a) Write an expression for the work W done on the gas when the gas is compressed from a volume Vi to a volume Vf.

Answers

Final answer:

The work done on the gas during an adiabatic compression process is calculated by integrating the pressure as a function of volume from the initial volume to the final volume. In this case, the integral ∫from V(i) to V(f) p₀ V^(-6/5) dV provides the value for the work done.

Explanation:

In an adiabatic process, the work done W on the gas when it's compressed from a volume V(i) to a volume V(f) can be calculated by integrating the pressure-volume equation over the given volume range.

Given the pressure equation p = p₀ V^(-6/5), the work done on the gas (W) can be computed by the integral formula for work: W = ∫p dV = ∫from Vi to Vf p₀ V^(-6/5) dV. Evaluating this integral gives the work done on the gas during the compression process in the adiabatic process.

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veronicas velocity was measured as 4.3 m/s. She displaced 20 meters in 4.7 seconds. Which piece of information is missing for the correct calculation of velocity?

Answers

In this question, it was not stated that Veronica’s velocity is constant at 4.3m/s. Velocity can be categorised both by Instantaneous velocity and constant velocity.

If the question is finding veronica’s constant velocity, no information is missing.

If the question is finding Veronica’s instantaneous velocity, information regarding acceleration is missing.

Answer: B

Explanation:

Sound waves are converted into mechanical movements by the

Answers

Answer:

a.auditory ossicles

b.oval window

c.Round window

d.tympanic membrane

Answer is tympanic membrane

Explanation:

The tympanic membrane otherwise called the ear drum is a membrane shaped like a cone,it connects the outside to the inner ear,it serves to convert vibration from air into fluid membrane vibration a good example of mechanical waves for onwatd transmission into the cochlea of the inner ear through the oval window

Final answer:

Sound waves are converted into mechanical movements by the ear, specifically through structures in the middle and inner ear. The eardrum, ossicles, and cochlea play significant roles in this process, with the final conversion to electrical signals occurring in the cochlea.

Explanation:

Sound waves are converted into mechanical movements by the ear, specifically the structures within the middle and inner ear.

When sound waves enter the ear, they strike the eardrum or tympanic membrane in the middle ear, causing it to vibrate. These vibrations are then transferred to three tiny bones in the middle ear called the ossicles, consisting of the malleus, incus, and stapes. The vibrations move these bones, with the stapes pushing into the oval window of the cochlea in the inner ear.

The cochlea is filled with fluid and lined with tiny hair-like structures called stereocilia. The mechanical movement from the ossicles creates waves in this fluid, which cause the stereocilia to move. This movement is converted into electrical signals that the brain interprets as sound.

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The top and bottom surfaces of a metal block each have an area of A = 0.030 m 2, and the height of the block is d = 0.11 m. At the top surface of the block, a force F1 is applied to the right, while at the bottom surface of the block, a force F2 is applied to the left, causing a shear in the metal block. If F1 = F2 = 30 ⨯ 106 N and the displacement between the two edges due to the shear is 1.12 10-3 m, what is the shear modulus of the metal

Answers

Answer:

Shear modulus is equal to [tex]9.82\times 10^{10}N/m^2[/tex]

Explanation:

We have given area [tex]A=0.030m^2[/tex]

Force is given [tex]F_1=F_2=30\times 10^6N[/tex]

Height of the block d = 0.11 m

Change in height of the block [tex]\Delta d=1.12\times 10^{-3}m[/tex]

Stress is given by

[tex]stress=\frac{force}{area}[/tex]

[tex]stress=\frac{30\times 10^6}{0.030}=10^9N/m^2[/tex]

Strain is equal to

[tex]strain=\frac{\Delta d}{d}[/tex]

[tex]strain=\frac{1.12\times 10^{-3}}{0.11}=10.18\times 10^{-3}[/tex]

Shear modulus is equal to

Shear modulus [tex]=\frac{stress}{strain}[/tex]

[tex]=\frac{10^9}{10.18\times 10^{-3}}=9.82\times 10^{10}N/m^2[/tex]

Will water flow more easily through a wide pipe or a narrow pipe? Will current flow more easily through a thick wire or a thin wire?

Answers

Answer:

Explained below.

Explanation:

The water will flow more easily through a wide pipe, because as we know that if the diameter of the pipe is wider than the flow of water will be more.

And same case will be applied with the electric current, if the is wire thicker then the flow of the current will be more easy and the charge will also flow easily.

Suppose you are 3.3km away from a rifle range where someone is practicing shooting. How long would it take you to hear the sound of a shot fired by him?

Can you guys answer quickly, its urgent.

Answers

Answer:9.5 seconds(approx.)

Explanation:time=distance/speed

here,

distance=3.3 km= 3300 m

standard speed of sound=344 m/s

so, time=3300/344

time=9.5(approx.)

Final answer:

It would take approximately 9.71 seconds for the sound of a shot to travel 3.3 km and reach you, using the speed of sound of 340 m/s.

Explanation:

To calculate how long it would take for you to hear the sound of a shot fired from 3.3 km away, we need to use the speed of sound. In general, the speed of sound is approximately 340 meters per second (m/s) at sea level under normal conditions. Therefore, we can use the formula:

Time = Distance / Speed of Sound.

Now we simply plugin the values to get:

Time = 3300 meters / 340 m/s = 9.71 seconds

Therefore, it would take approximately 9.71 seconds for the sound of the shot to travel 3.3 km and reach you.

Degeneracy pressure stops the crush of gravity in all the following except

Answers

Answer:

A very massive main- sequence star

Explanation:

Degeneracy pressure refers to pressure expend by dense material , which is composed of fermions, which is an example of electrons in a white dwarf star. According to Pauli exclusion principle, which states that no two fermions can exist in the same quantum state, actually give details about the pressure.

When there is stellar masses that is less than about 1.44 of that of solar masses, there will be gravitational fall in the energy , and the energy will not be sufficient to produce the neutrons of a neutron star, therefore, the fall is abstruptly stopped through the electron degeneracy to form white dwarfs.this result to the creation of an effective pressure that further prevents gravitational fall.

If an electronin an electron beam experiences a downward force of 2.0x10^-14N while traveling in a magnetic field of 8.3x10^-2T west, what is the direction and the magnitude of the velocity?

Answers

Answer:

Explanation:

Given that,

Force is downward I.e negative y-axis

F = -2 × 10^-14 •j N

Magnetic field is westward, +x direction

B = 8.3 × 10^-2 •i T

Charge of an electron

q = 1.6 × 10^-19C

Velocity and it direction?

Force in a magnetic field is given as

F = q(V×B)

Angle between V and B is 270, check attachment

The cross product of velocity and magnetic field

F =qVB•Sin270

2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2

Then,

v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)

v = 1.51 × 10^6 m/s

Direction of the force

Let x be the direction of v

-F•j = v•x × B•i

From cross product

We know that

i×j = k, j×i = -k

j×k =i, k×j = -i

k×i = j, i×k = -j OR -k×i = -j

Comparing -k×i = -j to given problem

We notice that

-F•j = q ( -V•k × B×i)

So, the direction of V is negative z- direction

V = -1.51 × 10^6 •k m/s

A block of mass = 4.00 kg is supported by a spring scale with unit of measure of Newtons. This spring scale is attached to top of an elevator. The elevator accelerates upward with a = 3.00 m/sec2. What is the reading on the spring scale to 3 significant figures?

Answers

Answer:

118 N

Explanation:

Given mass of the block, m = 4.00kg.

The acceleration of the elevator, a = 3.0 m/s^2.

As elevotar attaced with spring scale and accelerating upward

(block and elevator), so total force

[tex]F_N-mg=ma[/tex]

Here, mg is the weight of the block downward direction.

or

[tex]F_N=ma+mg=m(g+a)[/tex]

substitute the given value, we get

[tex]F_N=4kg(9.8m/s^2+3m/s^2)[/tex]

     = 117.6 N = 118 N.

Thus, the reading on the spring scale to 3 significant figures is 118 N.

A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds?

Answers

Answer:

43 m/s

Explanation:

Mass, m = 5 kg

Force, F(t) = 6t² - 4t + 3

To find the speed, we first need to get the acceleration, a.

Force is the product of mass and acceleration. It is given as:

F = ma

Therefore, acceleration is:

a(t) = F(t)/m

a(t) = (6t² - 4t + 3) / 5

a(t) = 1.2t² - 0.8t + 0.6

Acceleration is the differentiation of velocity with respect to time, t. Therefore, to get velocity, v, we integrate a(t):

a(t) = dv(t) / dt

=> v(t) = (1.2/3)t³ - (0.8/2)t² + 0.6t

v(t) = 0.4t³ - 0.4t² + 0.6t

Therefore, at time t = 5secs, velocity is:

v(5) = 0.4 * (5³) - 0.4 * (5²) + 0.6 * 5

v(5) = 50 - 10 + 3

v(5) = 43 m/s

The velocity at time, t = 5 secs is 43 m/s

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.814 rad/s2.What is the mass of the wheel?

Answers

Answer:

The mass of the wheel is 2159.045 kg

Explanation:

Given:

Radius [tex]r = 0.330[/tex]

m

Force [tex]F = 290[/tex] N

Angular acceleration [tex]\alpha = 0.814 \frac{rad}{s^{2} }[/tex]

From the formula of torque,

 Γ [tex]= I\alpha[/tex]                                        (1)

 Γ [tex]= rF[/tex]                                       (2)

[tex]rF = I \alpha[/tex]

Find momentum of inertia [tex]I[/tex] from above equation,

[tex]I = \frac{rF}{\alpha }[/tex]

[tex]I = \frac{0.330 \times 290}{0.814}[/tex]

[tex]I = 117.56[/tex] [tex]Kg. m^{2}[/tex]

Find the momentum inertia of disk,

 [tex]I = \frac{1}{2} Mr^{2}[/tex]

[tex]M = \frac{2I}{r^{2} }[/tex]

[tex]M = \frac{2 \times 117.56}{(0.330)^{2} }[/tex]

[tex]M = 2159.045[/tex] Kg

Therefore, the mass of the wheel is 2159.045 kg

The electric power consumed by a circuit with one light bulb is 24 W. The voltage of the battery is 3 V. What is the current in the circuit?

Answers

Answer:

8 ampere

Explanation:

P= V x I

so

I = P/V

I= 24 /3

I = 8 A

Compute the quantity of heat released by 25.0 g of steam initially at 100.0oC, when it is cooled to 34.0°C and by 25.0 g of water initially at 100.0 oC, when it is cooled to 34.0°C.

Answers

Answer:

For steam, heat released E = 15.26KJ

For water, heat released E2 = 6.91KJ

Explanation:

Given;

Mass(steam) ms = 25g

Mass (water) mw = 25g

Change in temperature of both steam and water ∆T = 100-34= 66°C

Specific heat of water C = 4.186 J/g.°C

Specific Latent heat L = 334J/g

For steam;

Heat released E = msL + msC∆T

E = (25×334) + (25×4.186×66)

E = 15256.9J

E = 15.26KJ

For water;

Heat released E2 = mwC∆T

E2 = 25×4.186×66

E2 = 6906.9J

E2 = 6.91KJ

Why do you think the combined wave is more powerful than either the transverse or longitudinal wave with the same amplitude

Answers

Answer:

Explanation:

The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,

In the picture, what can you say about the indices of refraction n1 and n2? (1 point)


n1 < n2

n1 > n2

n1 = n2

Not enough information to tell

Answers

Answer:

  (c)  n1 = n2

Explanation:

You want to know what can be said about the indices of refraction when a light ray continues on a straight path from one medium to another.

Refraction

When a wave passes through media where the index of refraction changes, its path will be bent in accordance with Snell's law. When the index of refraction does not change, the path will remain unbent.

The figure shows the path of the ray is a straight line, so we can conclude ...

  n1 = n2 . . . . . choice C

__

Additional comment

Even if the indices are different, the path will remain straight if the angle of incidence is 0—the path is normal to the interface between media. Here, the path is not shown as normal to the interface.

Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 1515 grams and velocity of 77 centimeters per second has a kinetic energy of 147147 ergs. Find the kinetic energy for a mass of 1010 grams and velocity of 99 centimeters per second?

Answers

Answer:

The second kinetic energy is 162 J.

Explanation:

Given that,

Mass, [tex]m_1=15\ g[/tex]

Velocity, [tex]v_1=7\ cm/s[/tex]

Kinetic energy, [tex]K_1=147\ ergs[/tex]

Mass, [tex]m_2=10\ g[/tex]

Velocity, [tex]v_2=9\ cm/s[/tex]

We need to find kinetic energy [tex]K_2[/tex]. Kinetic energy is given by :

[tex]K=\dfrac{1}{2}mv^2[/tex]

So,

[tex]\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J[/tex]

So, the second kinetic energy is 162 J.

Light refracts when traveling from air into glass because light

Answers

Answer:

Speed of light changes

Explanation:

Since glass is denser than air so the speed of light in glass is less than in air so light rays bend i.e. refract.

Final answer:

Light refracts when traveling from air into glass due to a change in speed caused by differences in optical density. The process, governed by Snell's Law, results in the bending of light towards the normal line as it enters the denser medium.

Explanation:

Light refracts when traveling from air into glass because light waves undergo a change in speed when they pass from one medium to another. This process is known as refraction. Refraction occurs because there is a change in light's propagation speed due to the difference in optical density between air and glass. When light rays propagate from air (less optically dense) into glass (more optically dense), they bend towards the normal line—a line perpendicular to the boundary between the two media. This bending happens according to Snell's Law, which relates the angle of incidence to the angle of refraction, taking into account the refractive indices of the two media.

A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second law and express the acceleration of the cart. Express your answer in terms of the variables F, f, and m.

Answers

Final answer:

The acceleration of the cart can be calculated using the equation a = (F - f) / m, where F is the applied force, f is the friction force, and m is the mass of the cart.

Explanation:

The acceleration of the cart can be expressed using Newton's second law, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

Therefore, the acceleration (a) of the cart can be calculated using the equation:

a = (F - f) / m

Learn more about Newton's second law here:

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