-7y to the third (4y + y - 3)

Answers

Answer 1
Hello,

So if we have the equation: -7y^3(4y + y - 3), we're essentially distributing "-7y^3" to everything of what's in the parenthesis. When you distribute -7y^3, know that you add exponents but you multiply the numbers. After simplifying you get:

-28y^4 - 7y^4 + 21y^3

**We can still simplify this expression because there are still like terms:

-35y^4 +21y^3

Hope this helps!

May

Related Questions

To win at lotto in a certain state, one must correctly select 6 numbers from a collection of 50 numbers (one through 50). the order in which the selections is made does not matter. how many different selections are possible?

Answers

Number of different selection = 50C6
Number of different selection = 50 x 49 x 48 x 47 x 46 x 45
Number of different selection = 15 890 700

Answer: 15 890 700
The number of possible selections is
  C(50, 6) = 50!/(6!*44!) = 15,890,700

helppppp picture included

Answers

They dont represent proportional relationship!
but what are the drop down answers?

PLEASE HELP!!! REWRITE THE FOLLOWING LINEAR EQUATION IN SLOPE INTERCEPT FORM??

Answers

y=-2x-2 That is the answer
y=-2x-2 you want to use the distributive property on the right side before subtracting four from both sides
y+4=-2(x-1)
y+4=-2x+2
y(-4)=-2x+2(-4)
y=-2x-2

REALY NEED HELP Find an equation of the line passing through the pair of points. Write the equation in the form Ax+By=C. (4,8) and (3,5)

Answers

let
A (4,8) and B (3,5)

step 1
find the slope m
m=(y2-y1)/(x2-x1)---------> m=(5-8)/(3-4)----> m=-3/-1----> m=3

step 2
with m=3 and point B (3,5) find the equation of the line
y-y1=m*(x-x1)-----> y-5=3*(x-3)----> y-5=3x-9----> 3x-y=4

the answer is
the equation in the form Ax+By=C is
 3x-y=4

see the attached figure

if 7 out of 8 people use crust toothpaste, how many use this product in a city with a population of 40,000?

Answers

Since 7 out of 8 people use crust toothpaste, in a city with the population of 40,000, 87.5% of the people use crust. so 40,000*87.5%= 35,000. 

What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point (15, –5)?

Answers

The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
  -1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
  y = (-5/3)(x -15) -5
  y = (-5/3)x +20

The y-intercept of the perpendicular line is y=20.

What is the probability of flipping a coin and it coming up heads four times in a row

Answers

In a single toss, the probability that the result of the toss is head is 1/2:
[tex]P_1 (head) = \frac{1}{2} [/tex]

For 2 tosses in a row, the probability that the result is head in both tosses is
[tex]P_2 = P_1 \cdot P_1 = ( \frac{1}{2} )( \frac{1}{2} )= \frac{1}{4} [/tex]

If we continue, we find that the probability to have 4 heads in 4 consecutive tosses is given by
[tex]P_4 = ( P_1 (head) )^4 = ( \frac{1}{2} )^4 = \frac{1}{16} [/tex]

Esther pays $467 per month for 5 years for a car. she made a down payment of $3,700. if the loan costs 7.1% per year compounded monthly, what was the cash price of the car?

Answers

The present value of the string of payments added to the down payment is $27,228.33. This is the cash price of the car.

The correct cash price is d) $27,228.33.

To determine the cash price of the car, we need to calculate the present value of all payments made by Esther, including her down payment.

Calculate the total number of monthly payments:
Total number of payments: 5 * 12 = 60

Determine the monthly interest rate:
Monthly interest rate: 0.071 / 12 = 0.0059167 (approximately)

Calculate the present value of the monthly payments using the formula for the present value of an annuity:

P = PMT × [tex]\frac{[1 - (1 + r)^{-n]} }{ r}[/tex]

P = 467 × [tex]\frac{ [1 - (1 + 0.0059167)^{-60}]}{ 0.0059167}[/tex] = $23,528.33

Add the down payment to the present value of the monthly payments to get the total cash price of the car:

Total cash price = $23,528.33 + $3,700 = $27,228.33

Therefore, the correct answer is (d) $27,228.33.

The complete question is

Esther pays $467 per month for 5 years for a car. she made a down payment of $3,700. if the loan costs 7.1% per year compounded monthly, what was the cash price of the car?

a) $23,528.33

b) $19,828.33

c) $29,820.57

d) $27,228.33

e) $37,220.57

select true statements. (-10x^(2)+5x+3)/(2x^(2)+4)

Answers are
The numerator has 3 terms
The denominator includes a coefficient of 4
The denominator includes a coefficient of 2
The numerator has 2 terms
The numerator includes a coefficient of 3

Answers

The correct answers for the exercise shown above, are:

 - The numerator has 3 terms:

 the first term is:-10x^2
 the second term is: 5x
 the third term is: 3

 - The denominator includes a coefficient of 4:

 2x^2+4

 - The denominator includes a coefficient of 2:

  2x^2+4

 - The numerator includes a coefficient of 3:

 -10x^2+5x+3

Answer: True statements::    The numerator has 3 terms; The denominator includes a coefficient of 2.


Step-by-step explanation:


Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.
PLEASE HELP ASAP!! NEED NOW! THANKS!

Answers

y=-4/3x+300  i  hope this helps you

y=-4/3x+300  i  hope this helps you


Q # 4 find the slope of the line through the pair of points A(2, -3), P(2, 9)

Answers

The answer is 12/0, which is undefined
The given points are (2, -3) and (2, 9)

The x-component of the two points is the same. Which means the line passing through the given two points is a vertical line and slope of a vertical line is undefined.

You can also validate it using the formula of finding slope.

Slope = (-3-9)/(2-2) = -12/0 = undefined

So, first option is the correct answer.

Lisa drove 40 3/5 miles in one hour. At the same speed in how many hours could she drive in 121 4/5

Answers

She would drive c 3 hours
Hello!

[tex]\bf Answer:[/tex]

Lisa can drive 121 4/5 miles in [tex]\boxed{ \rm C.~3~hours}[/tex].

40 3/5 = 40.6

121 4/5 = 121.8

121.8 ÷ 40.6 = 3

Eve is replacing the soil in her plant containers. How many cubic inches of soil will Eve need for the two rectangular containers? 
A.45 
B.216
C.648
D.864

Answers

The answer is B, 216in 3.

Q # 18,Graph the inequality on a coordinate plane, - y < 3 x - 5

Answers

For this case we have the following inequality:
 - y <3 x - 5
 Rewriting we have:
 y > -3x + 5
 The solution is given in this case by the set of points that belong to the shaded region shown in the graph.
 Answer:
 
see attached image.

describe the steps you would use to factor 2x ^ 3 + 5x ^ 2 - 8x - 20 completely then State the factored form. this isn't multiple choice btw

Answers

Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0

You see that the term will be 0 for x = 2

(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0

You can use the abc-formula to solve the quadratic equation.

x = -2.5 ∨ x = -2

So the factored form will be

2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


Answer:

2·x^3 + 5·x^2 - 8·x - 20 = 0


You see that the term will be 0 for x = 2


(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0


You can use the abc-formula to solve the quadratic equation.


x = -2.5 ∨ x = -2


So the factored form will be


2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)


Solve each system of equation algebraically
y=x+2
y=-3x

Answers

Try this solution:
[tex] \left \{ {{y=x+2} \atop {y=-3x}} \right. \ =\ \textgreater \ \ \left \{ {{-3x=x+2} \atop {y=x+2}} \right. \ =\ \textgreater \ \ \left \{ {{y=2- \frac{1}{2}} \atop {x=- \frac{1}{2}}} \right. \ =\ \textgreater \ \ \left \{ {{y= \frac{3}{2}} \atop {x=- \frac{1}{2}}} \right. [/tex]

The easiest method to use to solve this equation is substitution. This is because we already have our second equation set equal to the variable y, so we can substitute the x values in for the variable y in the first equation, as follows:


y = x + 2

y = -3x


-3x = x + 2


To simplify, we should subtract x from both sides of the equation so that we can have all of the x terms isolated on the left side of the equation.


-3x - x = x - x + 2

-4x = 2


Finally, we must divide both sides of the equation by -4 to get the variable x alone.


x = -2/4


Because both the numerator and denominator of this fraction are divisible by 2, we can use this knowledge to simplify the fraction by dividing by the GCF of 2.


x = -1/2


Now that we know the value of x, we can substitute this value into either of our original equations to find out the value of y.


y = -3x

y = -3(-1/2)

y = 3/2


Therefore, your answer is x = -1/2 and y = 3/2, or written as an ordered pair (-1/2, 3/2).


Hope this helps!

This is a function whose domain is a set of consecutive integers. They are finite and infinite.

Answers

The set of consecutive integers are:

[tex]z = \{...,-3, -2, -1, 0, +1, +2, +3,...\}[/tex]

If the function is finite, then there are two values [tex]a[/tex] and [tex]b[/tex], being [tex]a\ \textless \ b[/tex], in which this function is valid, then:

[tex]f(x) = x[/tex]
being [tex]x [/tex] the set of integers in the interval defined by [tex](a,b)[/tex]

If the function is infinite, the function is valid in the set of all integers then:

[tex]f(x) = x[/tex]
And -∞[tex]<x<[/tex]+∞ 

Answer:

the answer is sequence (usa test prep)

Step-by-step explanation:

Find f. f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

Answers

It has been a while since I have done differnetial equations but I think here you only need to integrate twice. 
4 + 6x + 36x^2=  2*(2+3x+18x^2) 

Integrate 2+3x+18x^2 to get 2x+3/2x^2+18/3x^3 +C = 2x +3/2x^2+6x^3 + C
Integrate again now this: 2x +3/2x^2+6x^3 + C to get x^2 + 1/2x^3+3/2x^4 +Cx +D 
Now multiply by two (as I have taken out 2 earlier) 
2x^2+x^3+3x^4+2Cx+D

Now use the initial conditions. 
f(0)=2 
D=2 
f(1)=10
2+1+3+2C+2=10
C=1

So the solution is: (ordered by power, as neat mathematicans would do) 
f(x)= 3x^4 + x^3 + 2x^2 + 2x +2

The function [tex]\( f(x) \)[/tex] is: [tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

Given:

[tex]\[ f''(x) = 4 + 6x + 36x^2 \][/tex]

[tex]\[ f(0) = 2 \][/tex]

[tex]\[ f(1) = 10 \][/tex]

1. Integrate [tex]\( f''(x) \)[/tex] to find [tex]\( f'(x) \)[/tex]:

[tex]\[ f'(x) = \int (4 + 6x + 36x^2) \, dx = 4x + 3x^2 + 12x^3 + C_1 \][/tex]

2. Integrate [tex]\( f'(x) \)[/tex] to find [tex]\( f(x) \)[/tex]:

[tex]\[ f(x) = \int (4x + 3x^2 + 12x^3 + C_1) \, dx = 2x^2 + x^3 + 3x^4 + C_1x + C_2 \][/tex]

3. Use the initial condition [tex]\( f(0) = 2 \)[/tex] to find [tex]\( C_2 \)[/tex]:

[tex]\[ 2x^2 + x^3 + 3x^4 + C_1x + C_2 \text{ at } x=0 \][/tex]

[tex]\[ 2 = C_2 \][/tex]

[tex]\[ C_2 = 2 \][/tex]

4. Use the initial condition [tex]\( f(1) = 10 \)[/tex] to find [tex]\( C_1 \)[/tex]:

[tex]\[ f(1) = 2(1)^2 + (1)^3 + 3(1)^4 + C_1(1) + 2 = 10 \][/tex]

[tex]\[ 2 + 1 + 3 + C_1 + 2 = 10 \][/tex]

[tex]\[ 8 + C_1 = 10 \][/tex]

[tex]\[ C_1 = 2 \][/tex]

Thus, the function [tex]\( f(x) \)[/tex] is:

[tex]\[ f(x) = 2x^2 + x^3 + 3x^4 + 5x + 4 \][/tex]

The complete question is:

Find f(x). f ''(x) = 4 + 6x + 36x2, f(0) = 2, f (1) = 10

Mike is looking for a loan. He is willing to pay no more than an effective rate of 8.000% annually. Which, if any, of the following loans meet Mike’s criteria? Loan X: 7.815% nominal rate, compounded semiannually Loan Y: 7.724% nominal rate, compounded monthly Loan Z: 7.698% nominal rate, compounded weekly a. Y only b. X and Z c. Y and Z d. None of these meet Mike’s criteria.

Answers

If Mike is willing to pay no more than an effective rate of 8.000% annually, the loans that meet his criteria are loan X and loan Z. Of those two, the lowest would be loan X.  I hope the answer will help you :)

Answer:

b. X and Z

Step-by-step explanation:

Since, the effective rate is,

[tex]r=(1+\frac{i}{n})^i-1[/tex]

Where, i is the nominal rate,

n is the number of compounding periods,

For loan X,

i = 7.815 % = 0.07815,

n = 2, ( 1 year = 2 semiannual )

Thus, the effective rate would be,

[tex]r=(1+\frac{0.07815}{2})^2-1[/tex]

[tex]=0.079676855625[/tex]

[tex]=7.9676855625\%\approx 7.968\%[/tex]

Since, 7.968 % < 8.000 %,

Loan X meets Mike's criteria,

For loan Y,

i = 7.724 % = 0.07724,

n = 12 ( 1 year = 12 months ),

Thus, the effective rate would be,

[tex]r = ( 1+\frac{0.07724}{12})^{12}-1[/tex]

[tex]=0.0800339518197[/tex]

[tex]=8.00339518197\% \approx 8.003\%[/tex]

Since, 8.003 % > 8.000 %,

Loan Y does not meet his criteria,

For loan Z,

i = 7.698 % = 0.07698,

n = 52 ( 1 year = 52 weeks ),

Thus, the effective rate would be,

[tex]r = (1+\frac{0.07698}{52})^{52}-1[/tex]

[tex]=0.0799589986135[/tex]

[tex]=7.99589986135\%[/tex]

[tex]\approx 7.996\%[/tex]

Since, 7.996 % < 8.000 %,

Loan Z meets his criteria.

Therefore, Option 'b' is correct.

A bag contains 7 blue, 12 red, and 6 orange marbles. Find each probability if you draw one marble at random from the bag. Write as a fraction. a) P (purple)
b) P (red or orange) Please
c)P(not blue) Help

Answers

Total = 7 + 12 + 6 = 25

Purple = 0
Red = 12/25
Orange = 6/25
Blue = 7/25

a. Since there is 0 purple, the answer is 0.
b. 18/25 ( 12/25 + 6/25)
c. 18/25 (Not blue = 25 - 7 = 18)

Hope this helped☺☺

the radius of a glass is 1.25 inches. What circumference? use 3.14 for pi

Answers

C=2×3.14×1.25

Answer= 7.85
I think this is the answer.

5.6 times what equals 19.04

Answers

You would have to multiply 5.6 by 3.4 to get 19.04

What is the sum of the roots of the polynomial shown below f(x)=x^3-4x^2-11x+30

Answers

The sum of the roots of a cubic is the opposite of the coefficient of the squared term (provided that the leading coefficient is 1).

The sum of the roots is -(-4) = 4.

_____
The graph shows the roots to be -3, 2, 5, whose sum is 4.

priority question

The dot plots below show the test scores of sixth- and seventh-grade students: Dot plot for Grade 6 shows 6 dots on score 70, 4 dots on score 80, 6 dots on score 90, and 4 dots on score 100. Dot plot for Grade 7 shows 5 dots on score 50, 7 dots on score 60, 4 dots on score 70, and 4 dots on score 80. Based on visual inspection of the dot plots, which grade, if any, appears to have the higher mean score? Grade 6 Grade 7 Both groups show about the same mean score. No conclusion about mean score can be made from the data.

Answers

Sixth grade:
7 | x x x x x x
8 | x x x x
9 |x x x x x x
A | x x x x . . . . . . . . where "A" is used to represent 10 tens (100)

7th grade:
5 | x x x x x
6 | x x x x x x x
7 | x x x x
8 | x x x x

The range (low, high) and median of the 6th grade scores are all higher than those of the 7th grade scores.

Based on visual inspection, Grade 6 appears to have the higher mean score.

Answer:

Grade 6 i think

What is the slant height x of this square pyramid? The figure shows a square pyramid. The slant height is shown as a dashed line perpendicular to the base edge and is labeled as x. The length of the lateral edge is 4 meters. The lateral edge makes a 60 degree angle with the base edge. Enter your answer in the box. Express your answer in radical form.

Answers

The side adjacent to the 60° angle in the right triangle consisting of x, the lateral edge, and half the base edge is half the base edge, 2 m. The side opposite that angle is x. Thus you have
  tan(60°) = x/(2 m)
  (2 m)*tan(60°) = x = 2√3 m

The slant height is 2√3 meters.

Based on the information given, it should be noted that the slant height will be 2✓3 meters.

From the information given, the slant height is shown as a dashed line perpendicular to the base edge and is labeled as x as the length of the lateral edge is 4 meters and the lateral edge makes a 60 degree angle with the base edge.

Therefore, the calculation of the slant height goes thus:

Tan 60° = x/2

x = 2 × tan 60°

x = 2 × ✓3

x = 2✓3

Learn more about triangles on:

https://brainly.com/question/17335144

use similar triangles to solve. a person who is 5 feet tall is standing 140 ft from the base of a tree and the tree cast a 154 foot shadow. the person's Shadow is 14 ft in length what is the height of the tree

Answers

For this case we have the following relationship using similarity of triangles:
 (x / 154) = (5/14)
 Clearing the value of x we have:
 x = (5/14) * (154)
 Rewriting we have:
 x = 55 feet
 Answer:
 
the height of the tree is:
 
x = 55 feet
To find the height of the tree, you can create a proportion with the information that is given and solve for the height.

Heights:                x              5 feet
Base Lengths:    154 feet      14 feet

14x = 770
14       14
x = 55 feet

The height of the tree is 55 feet.

Find the first term, a1, of an arithmetic sequence if a12 = 38 and a45 = 170.
–6

132/33

–5

6

Answers

Standard formula for arithmetic sequence:
an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d 
170 - 38 = 33d
132 = 33d

132/33 = d
This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0

The starting term is -6

The solution is: The starting term is -6

What is Arithmetic progression?

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Standard formula for arithmetic sequence:

an = a0 + d(n-1)

if we use the two terms given, setting a12 as starting term and a45 as the end term an.

170 = 38 + 33d 

170 - 38 = 33d

132 = 33d

132/33 = d

This is the common difference, use it to find the first term.

38 = a0 + (132/33)(12-1)

38 = a0 + (132/33)(11)

38 = a0 + 132/3

38 - 132/3 = a0

38 - 44 = a0

-6 = a0

The starting term is -6

To lean more on Arithmetic progression click:

brainly.com/question/28898589

#SPJ2

The home of Russell Slater is assessed at $140,000. The tax rate is 11.8 mills. The actual amount of tax on Russell's home is:


$1,652


$1,462


$1,362


None of these


$1,562

Answers

number 3 is right i think

Consider the differential equation dy/dx = 1/3x(y-2)^2.

(a) A slope field for the given differential equation is shown below. Sketch the solution curve that passes through the point (0, 2), and sketch the solution curve that passes through the point (1, 0).

(b) Let y = f(x) be the particular solution to the given differential equation with initial condition f(1) = 0. Write an equation for the line tangent to the graph of y = f(x) at x = 1. Use your equation to approximate f(0.7).

(c) Find the particular solution y = f(x) to the given differential equation with initial condition f(1) = 0.

(This was on the no-calculator section of the recently-released AP Calculus AB 2018 exam so I appreciate it if you tried to limit calculator usage)

Answers

a) Judging by the slope field, it would appear the solution passing through (0, 2) would just be the line [tex]y=2[/tex]. This holds up for the given ODE, since if [tex]y(x)=2[/tex], then both sides of the ODE reduce to 0.

Since we can surmise that [tex]y=2[/tex] is an equilibrium for this ODE (that is, the derivative along this line is 0 everywhere), and the slope at (1, 0) is positive, we know that as [tex]x\to+\infty[/tex], the function [tex]y(x)[/tex] will converge to 2. In other words, as [tex]x[/tex] gets larger, the slope field suggests that the solution curve through (1, 0) will start to plateau and steadily approach [tex]y=2[/tex]. On the other hand, as [tex]x\to-\infty[/tex], the slope field tells us that the curve would rapidly diverge off to [tex]-\infty[/tex]. (When you actually draw the solution, you would end up with something resembling the plot of [tex]-e^{-x}[/tex].)

b) The tangent line to [tex]y=f(x)[/tex] at [tex]x=1[/tex], given that [tex]f(1)=0[/tex], takes the form

[tex]\ell(x)=f(1)+f'(1)(x-1)[/tex]
[tex]\ell(x)=f'(1)(x-1)[/tex]

When [tex]x=1[/tex], we have [tex]y=0[/tex], so

[tex]f'(1)=\dfrac13\cdot1\cdot(0-2)^2=\dfrac43[/tex]

and so the tangent line to [tex]f(x)[/tex] at [tex]x=1[/tex] is

[tex]\ell(x)=\dfrac43(x-1)[/tex]

Using the tangent line as an approximation, we would find

[tex]f(0.7)\approx\ell(0.7)=\dfrac43\left(\dfrac7{10}-1\right)=-\dfrac4{10}=-0.4[/tex]

c) The ODE is separable, so we can write

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac13x(y-2)^2\iff\dfrac{\mathrm dy}{(y-2)^2}=\dfrac x3\,\mathrm dx[/tex]

Integrating both sides gives us

[tex]-\dfrac1{y-2}=\dfrac{x^2}6+C[/tex]

Given that [tex]y(1)=0[/tex], we get

[tex]-\dfrac1{0-2}=\dfrac{1^2}6+C\implies C=\dfrac13[/tex]

so the particular solution is

[tex]-\dfrac1{y-2}=\dfrac{x^2}6+\dfrac13[/tex]

You're asked to find the solution in the form [tex]y=f(x)[/tex], so you should solve for [tex]y[/tex]. You would end up with

[tex]y=-\dfrac6{x^2+2}+2=\dfrac{2(x^2-1)}{x^2+2}[/tex]
Final answer:

To sketch the solution curves passing through (0, 2) and (1, 0), we can use the slope field provided. The tangent line to y = f(x) at x = 1 can be found by taking the derivative of f(x) and substituting x = 1. We can find the particular solution to the differential equation by integrating it with the given initial condition f(1) = 0.

Explanation:(a) Solution curves through (0, 2) and (1, 0)

To sketch the solution curves, we can use the slope field provided. For the point (0, 2), the slope is 1/3(0)(2-2)^2 = 0. Thus, at (0, 2) the solution curve is horizontal. For the point (1, 0), the slope is 1/3(1)(0-2)^2 = 8/3. Thus, at (1, 0) the solution curve is directed upwards with a slope of 8/3.

(b) Tangent line at (1, 0) and f(0.7)

Since f(1) = 0, we already know that the point (1, 0) lies on the graph of y = f(x). The equation of the tangent line to y = f(x) at x = 1 can be found by finding the derivative of f(x) and substituting x = 1. In this case, the derivative is dy/dx = 1/3x(y-2)^2, so at x = 1, we have dy/dx = 1/3(1)(0-2)^2 = -8/3. Therefore, the equation of the tangent line is y - 0 = (-8/3)(x - 1), which simplifies to y = -8/3(x-1). To approximate f(0.7), we can substitute x = 0.7 into the equation of the tangent line to get y = -8/3(0.7 - 1) = -8/3(0.3) = -8/10 = -0.8.

(c) Find the particular solution with f(1) = 0

To find the particular solution, we can integrate the differential equation with the given initial condition. Starting with dy/dx = 1/3x(y-2)^2, we can rewrite it as (y-2)^(-2)dy = 1/3xdx. Integrating both sides will give us the equation of the particular solution.

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you have a part-time job that pays $4.75 an hour with tips allergy $4 and fifty an hour your deductions are fic a 7.65% federal tax withholding 12.5% in state tax withholding 6.85 % you work 20 hours per week you want to save $40 a week how much left in your discretionary income per week soon that all the income from your part time job is discretionary and the next one is

You decide to save 15% of your realized income how much do you save per month?

Answers

I do believe that the answer is 27.75 if I have the correct definition of what the realized income is.
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