8j -k+148j−k+148, j, minus, k, plus, 14 when j=0.25j=0.25j, equals, 0, point, 25 and k=1k=1

Answers

Answer 1
It looks like you want to evaluate
.. 8j -k +14
for (j, k) = (0.25, 1).

Put the numbers where the letters are. If you cannot do the math, let your calculator do it.
.. 8*0.25 -1 +14
.. = 2 -1 +14
.. = 1 +14
.. = 15

The value of the expression is 15 at (j, k) = (0.25, 1).
Answer 2

Answer:

15. It was right for me, not sure for anyone else

Step-by-step explanation:


Related Questions

If f(x) = –x3, g(x) = 3x2 – 1, and h(x) = 2x + 5, what is the degree of [f o g o h](x)?

a-2
b-3
c-5
d-6

Answers

I'm not sure but I'm thinking it's letter d

Answer:

Option d:  6

Step-by-step explanation:

Find f(g(h(x))).

h(x)=2x+5

g(h(x)) = 3(2x+5)^2 -1     (substitute h(x) in)

f(g(h(x)))= -[3(2x+5)^2 -1]^3    (substitute g(h(x)) in)

Since it asks for the degree of the function, that means we must look for the variable with the highest degree. In this case, after distributing and simplifying out the last equation, we will find that the variable x has the highest degree of x^6, or 6.

Can one angle of a parallelogram be equal to 40° and another one 50°? Justify your reasoning.

Answers

Short answer: No! <<=====
If the two are one after another, then they are not supplementary, which a parallelogram requires.

If they are in opposite corners, they must be equal. That's another property of parallelograms.

(-7/8)(-3/4)

A:6/7

B:-21/32

C:21/32

Answers

the answer is C
I pretty sure
c is the correct answer

What are the asymptotes of the graph of f(x) ?

Answers

when you graph the equation the horizontal line is on Y=0 & 20

 answer y=0 & Y=20

Your Turn: In the diagram, AB = 12, DX = 2.5, and BX = 5. Find CD. Show all work.

Answers

answer is 6.5 as the two triangles are similar

Your Turn: In the diagram, AB = 12, DX = 2.5, and BX = 5. Find CD. Show all work.

Solution:

In ΔABX and ΔCDX,

∠CDX=∠ABX=90°

Also,∠CXD=∠AXB (as shown in figure)

∠DCX=∠BAX, as two angles of the triangle are equal. The third angle is also equal.

So ΔCDX≈ΔABX

Hence, the ratio of sides must be equal.

[tex] \frac{CD}{AB} =\frac{DX}{BX} =\frac{CX}{AX} [/tex]

Now, using,

[tex] \frac{CD}{AB} =\frac{DX}{BX} [/tex]

[tex] \frac{CD}{AB=12} =\frac{DX=2.5}{BX=5} [/tex]

[tex] \frac{CD}{12} =\frac{2.5}{5} [/tex]

Now, To solve for CD, Let us multiply by 12 on both sides

[tex] \frac{12*CD}{12} =\frac{12*2.5}{5} [/tex]

[tex] \frac{1*CD}{1} =\frac{30}{5} [/tex]

[tex] CD =\frac{6}{1} [/tex]

CD=6 Answer

Write an equation of the line with a slope of 2 that passes through the point (2,0)

Answers

You can use the slope-intercept form of the equation of a line.

[tex] y = mx + b [/tex]

m is the slope. We are told m = 2.

Now we have

[tex] y = 2x + b [/tex]

We need to find b, the y-intercept. We are given a point, (2, 0). We replace x with 2 and y with 0. Then we solve for b.

[tex] 0 = 2(2) + b [/tex]

[tex] -4 = b [/tex]

Now that we know that b = -4, we replace b with -4.

[tex] y = 2x - 4 [/tex]

Hence, the line with a slope [tex]2[/tex] that passes through the point [tex](2,0)[/tex] is

[tex]y=2x-4[/tex]

What is the line of equation?

The equation of a line is an algebraic form of representing the set of points, which together form a line in a coordinate system.

The numerous points which together form a line in the coordinate axis are represented as a set of variables [tex]x, y[/tex] to form an algebraic equation, which is referred to as an equation of a line.

As we know the line of the slope is

[tex]y=mx+b[/tex]

where [tex]m[/tex] is the slope we have [tex]m = 2.[/tex]

So it would be

[tex]y=2x+b[/tex]

Given the point,   [tex](2, 0)[/tex]

Now, we replace [tex]x[/tex] with [tex]2[/tex] and [tex]y[/tex] with [tex]0[/tex].

Now, we solve for [tex]b[/tex].

So,

[tex]0=2(2)+b\\b+4=0\\b=-4[/tex]

Since we get [tex]b = -4[/tex], we replace [tex]b = -4[/tex]

i.e., [tex]2x-4[/tex]

Hence, the line with a slope [tex]2[/tex] that passes through the point [tex](2,0)[/tex] is

[tex]y=2x-4[/tex]

To know more about the line of equation

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Keith had 1 1/2 cups of flour.he used 5 2/3 cups to make bread.How many cups of flour does Keith have left

Answers

If Keith had 1 1/2 cups, he can't use 5 2/3 cups. He cant use more than what he had. There is error in this question.

What is the area of the triangle whose vertices are (0,0), (3,0) and (0,4)?

Answers

Answer: 6

Since one of the points is at the origin, then you can take the number point on the x axis and multiply it by the point on the y axis, and you get 12. To find the area of a triangle, you must use base x height divided by 2. Divide 12 by 2 to get 6. 

Hope this helped!
9 6is very wrong it is 9nine

based on the given information ,which statement best explains whether the quadrilateral is a parallelogram

Answers

It would be A. It cannot be determined from the information given

Answer:

the answer is (it cannot be determined from the information given)

Given the functions f(x)= [tex] \frac{1}{x-2} + 1 [/tex] and g(x) = [tex] \frac{1}{x+5} + 9[/tex]
Which statement describes the transformation of the graph of function f onto the graph of function g?
The graph shifts 8 units right and 7 units down.

The graph shifts 8 units left and 7 units up.

The graph shifts 7 units right and 8 units down.

The graph shifts 7 units left and 8 units up.

Answers

f (x) = (1 / (x-2)) + 1g (x) = (1 / (x + 5)) + 9
 Transformation of functions: 
 Suppose that k> 0
 To graph y = f (x) + k, move the graph of k units up.
 To graph y = f (x) -k, move the graph of k units down.
 Suppose that h> 0
 To graph y = f (x-h), move the graph of h units to the right.
 To graph y = f (x + h), move the graph of h units to the left.

 f (x) = (1 / (x-2)) + 1
 To graph y = f (x) + k, move the graph of k units up.
 h (x) = (1 / (x-2)) + 1 + 8
 To graph y = f (x + h), move the graph of h units to the left.
 g (x) = (1 / (x-2 + 7)) + 1 + 8
 g (x) = (1 / (x + 5)) + 9

 Answer: 
 The graph shifts 7 units left and 8 units up.

In right triangle PQR, P and Q are complementary angles. The value of sin Q is 9/41. What is the value of cos P?

Answers

Final answer:

In right triangle PQR, sin Q = 9/41. To find cos P, we need to determine the length of the hypotenuse PR. Once we have PR, we can use the cosine function to find cos P.

Explanation:

In a right triangle, the sine of an angle is the length of the side opposite the angle divided by the length of the hypotenuse. So, in triangle PQR, sin Q = opposite/hypotenuse = PQ/PR = 9/41.

Since angles P and Q are complementary, their sum is 90 degrees. Therefore, angle P = 90 - angle Q.

Now, using the Pythagorean theorem for triangle PQR (PQ^2 + QR^2 = PR^2), we can find PR. Since PQ = 9 and QR = 41, we have: 9^2 + 41^2 = PR^2. Solving for PR gives us PR ≈ 41.297.

Now that we have PR, we can find cos P using the cosine function: cos P = adjacent/hypotenuse = QR/PR = 41/41.297 ≈ 0.993.

Final answer:

In a right triangle, sin Q = 9/41. To find cos P, we can use the identity cos(90 - x) = sin(x). So cos P = sin(Q) = 9/41.

Explanation:

In a right triangle, the sine of an angle is equal to the length of the side opposite the angle divided by the hypotenuse. In this case, sin Q = 9/41, which means that the length of the side opposite Q is 9 and the length of the hypotenuse is 41. Since P and Q are complementary angles, P = 90 - Q. Therefore, cos P = cos(90 - Q).

Using the identity cos(90 - x) = sin(x), we can substitute the value of Q to find cos P. cos P = sin(Q) = 9/41.

Can you solve an angle measures 36° more than the measure of a complementary angle. what is the measure of each angle

Answers

 I'm reading this as ..... 36o more then the measure of its complementary angle.
x = 90 - x + 36 add 90 and 36 together.
x = 126 - x Add x to both sides.
2x = 126
x = 126 /2
x = 63

The complementary angle is 90 - 63 = 27
The question is is 63 36 bigger than 27

27 + 36 = 63 and the angles are
Answer 27o and 63o

the area of the green square is 9ft squared. the area of the red square is 16ft squared. what is the area of the yellow square

Answers

Answer:

25ft^2

Step-by-step explanation:

9 + 16 = 25

Answer: The answer to this given basic math question about finding the area of the yellow square is 25 feet squared.

Step-by-step explanation: Mmmm, that was easy, so anyway, here is a basic step in order to find the area of the yellow square:

Add green and a red square with the given feet squared that looks in the equation form like this: [tex]9+16=25ft^{2}.[/tex]

I hope that my given short answer with my given short step-by-step explanation is very helpful to your own basic math question about finding the area of the yellow square, please mark me as Brainliest, take care, always be safe, and have a great rest of the weekend! :D

Sincerely,

Jason Ta,

The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.

Which conversion requires multiplication?

A. Deciliter to liter
B. Liter to kiloliter
C. Kiloliter to liter
D. Milliliter to centiliter

Answers

With metric measurements, the prefixes in order from smallest to largest are:
milli-, centi-, deci-, unit, deca-, hecto-, kilo-.
Converting from the left to right (from smallest to largest) means you divide to get your answer.
Converting from the right to the left (from largest to smallest) means you multiply to get your answer.  Deciliter to liter goes from left to right, so that would be division.  Liter to kiloliter goes from left to right, so it is division.  Kiloliter to liter goes from right to left, so it is multiplication.  Milliliter to centiliter goes from left to right, so it is division.

Answer:

I believe it is B

Step-by-step explanation:

NEED HELP ASAP!

simplify the radical expression State any restrictions (n^4 -11n^2 +30) / (n^4 -7n^2 +10)

Please show steps!

Answers

-Factor the expressions


-reduce

-then simplify the product 
(n-squareof 6) x (n+sqaureof 6) / (n-sqaureof2) x (n+squareof 2) 

and your answer will be 
n^2-6 / n^2-2


Answer:

screenshot shows the answer but: n^2-6/n^2-2

Step-by-step explanation:

n^4-11n^2+30/n^4-7n^2+10
simplify the numerator
rewrite n^4 as (n^2)^2
and let u substititue for all occurences of n^2
u^2-11y+30/n^4-7n^2+10
factor u^2 - 11u+30 using the AC method.
(u-6)(u-5)/n^4-7n^2+10

(n^2-6)(n^2-5)/(n^2-5(n^2-2)

Cancel the common factor, and n^2-6/n^2-2 is your answer.

Excluded values/restrictions are n= -sqrt5 n= -sqrt2, also n= sqrt5 n= sqrt2

Jayce’s insurance company pays for 90% of the cost of an ambulance ride, after he pays a $250 deductible. The ambulance ride costs $1400. How much would Jayce pay for an ambulance ride?

Answers

To answer this question you would subtract the $250 deductible from $1400. The answer would be $1150 remaining After the deductible. You would then pay 10% of this $1150 for your cost. 0.10 times $1150 =$115. Add the $115 to the $250 deductible and your total cost would be $365.

The amount which would Jayce pay for an ambulance ride for the claim to the Jayce’s insurance company is $365.

What is deductible amount?

The deductible amount is the amount which has to be paid by the customer against an insurance lost.

This amount is subtracted from the insurance amount, which one is claimed against the claim.

Jayce’s insurance company pays for 90% of the cost of an ambulance ride, after he pays a $250 deductible.

As the ambulance ride costs $1400. Thus the ambulance cost after the deductible is,

[tex]C=1400-250\\C=1150[/tex]

Here, the Jayce’s insurance company pays for 90% of the cost of an ambulance ride. Thus, the 10 percent amount should be pay by the Jayce's.

Now, the amount which is left after the insurance company paid to Jayce's is,

[tex]A=\dfrac{10}{100}\times1150\\A=115[/tex]

Hence, the total amount paid by Jayce is,

[tex]A=115+250\\A=365[/tex]

Hence, the amount which would Jayce pay for an ambulance ride for the claim to the Jayce’s insurance company is $365.

Learn more about the deductible here;

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Richard records the weight of his two pets in a table, as shown. After how many weeks were the pets the same weight? What was their weight at that time? Pet 1 Week Weight (grams) 0 400 2 800 Pet 2 Week Weight (grams) 0 500 2 700 At 1 week, they both weighed 600 grams. At 2 weeks, they both weighed 500 grams. At 3 weeks, they both weighed 650 grams. At 4 weeks, they both weighed 1,000 grams.

Answers

  Pet 1                                                  Pet 2
0 - 400                                               0 - 500
1 - 600                                               1 - 600
2 - 800                                               2 - 700   
3 - 1000                                             3 - 800

Option A - At 1 week, they both weighed 600 grams. 

Answer:

After week 1 both the pets were having same weights of 600 gms.

Step-by-step explanation:

As given in the question weights of two pets are

Week   weight of pet 1(in gm)     weight of pet 2(in gm)

  0                       400                              500

  1                        600                              600

  2                       800                              700

  3                       1000                             700

In this table weights of the pets at 0 wk and 2 wk has been given only and we have calculated the weights by averaging their weights at 1 and 3 wk.

1). weight at 1 week = (weight at 0 wk + weight at 2 wk)/2

weight of pet 1 = (400+800)/2 = 600 gm

weight of pet 2 = (500 + 700)/2 = 600 gm

2).weight at 2 week = (weight at 1 wk + weight at 3 wk)/2

Therefore weight after 3 week = 2×weight after 2 week - weight after 1 week.

weight of pet 1 = 2×800 - 600 = 1600-600 =1000 gm

weight of pet 2 = 2×700 - 700 = 700 gm.

Now we have got the answer from the table formed that after 1 week both the pets were of same weight 600 gm.

What values of c and d make the equation true? mc011-1.jpg c = 2, d = 2 c = 2, d = 4 c = 6, d = 2 c = 6, d = 4

Answers

If the equation is ∛(162x^cy^5) = 3x²y(∛(6y^d)
We can simplify the equation by first cubing both sides
            = 162x^cy^5 = (27x^6y^3)6y^d
            = 162x^cy^5 = 162 x^6y^3y^d
dividing both sides by 162
           = x^cy^5 =x^6y^3y^d
      equating the values with similar bases
   x^c = x^6, therefore c=6
and y^5=y^3y^d
        y ^5 = y^(3+d)
hence, 5 = 3+d
thus, d= 2
Therefore, the values of d and c that will satisfy the equation are, c =6 and d=2 

The answer is C.

c=6  d=2

Find the sum of the first thirty consecutive whole numbers.

Answers

The sum of the first thirty consecutive whole numbers can be represented by the following series

[tex] 0+1+2+3+4+....+29\\ \\Sum \; of\; first \; 30\; whole \; numbers\; =\; Sum\; of\; first \; 29\; Natural\; Numbers\\ \\1+2+3+4+...+29 \\ \\ Formula\\ 1+2+3+....+n=\frac{n(n+1)}{2} \\ \\ Substituting\; 29\; for\; n,\; we\; get...\\ \\ 1+2+3+4+...+29=\frac{29(30)}{2}=29 \times 15=435 [/tex]

Conclusion:

The sum of the first thirty consecutive whole numbers is 435.

Answer:

435

Step-by-step explanation:

The gouse method or something.

(29*30)/2=435

Larissa wants to inscribe a regular hexagon in a circle using only a compass and straightedge. She will construct a circle and finds its center. She will then perform the following steps.

Step 1: Plot a point on the circle to represent a vertex of the hexagon. Place the compass on this point and draw an arc to cut the circle. This represents the next vertex of the hexagon.
Step 2: Without adjusting the width of the compass, place the compass on this vertex and draw an arc to create the next vertex.
Step 3: Repeat the process to get a total of 6 vertices.
Step 4: Draw a line between successive pairs of vertices to form the regular hexagon.

What is the error in Larissa's construction?

A. She did not change the width of the compass when constructing the different vertices.
B. She did not set the width of the compass to the radius of the circle.
C. She did not set the width of the compass to the diameter of the circle.
D. She did not construct two perpendicular bisectors to construct two diameters of the circle.

Answers

Answer: option B. She did not set the width of the compass to the radius of the circle.

Explanation:

1) If she sets the compass to an arbitrary width to draw the arc to cut the circle, the point obtained will not be to the right distance from the first vertex.

2) All the adjacent vertices on a regular polygon have the same distance one from each other.

3) In the hexagon that distance is the same radius, which you can see becasue you can form six equilateral triangles inside the circle, whose side lengths are the radius.

4) So, she should set the width of the compass to the radius of the circle.

What is the approximate volume of the cone? Use 3.14 for π . 1206 cm³ 2170 cm³ 3260 cm³ 6510 cm³ Outline of cone with a dotted line rising from middle of base to the point. Line is labeled 8 cm. A second dotted line extends horizontally from middle of base to its edge. Line is labeled 12 cm.

Answers

The volume of a cone is given by the formula [tex]V=\frac{1}{3} \pi r^2 h[/tex], where r is the radius and h is the height. The horizontal dotted line from the center of the base circle to the outside edge would be the radius, so that would be 12 cm.  The vertical dotted line from the center of the base to the point of the cone would be the height, so that would be 8 cm.  We substitute these values into our formula:
[tex]V=\frac{1}{3} \pi (12^2)(8)[/tex]
Substituting 3.14 for pi we have:
[tex]V=\frac{1}{3}(3.14)(12^2)(8) = 1205.76 \text{cm}^3[/tex]

The required approximate value volume of the cone is v =  1206 `cm³.

Given that the Height of the cone = 8 m

The Radius of the cone =  12 m

We have to find,The approximate volume of the cone .

What is the  volume of a cone?

The volume of a cone is equal to one-third of the volume of a cylinder having the same base radius and height.

Where V is the volume, r is the radius and h is the height.

The volume of the cone

[tex]V = \dfrac{1}{3} \pi r^3 h \: \rm unit^3[/tex]

Where, π = 3.14

[tex]V = \dfrac{1}{3} \pi r^3 h \: \rm unit^3\\\\ V = \dfrac{1}{3} \pi (8)^3 (12) \: \rm unit^3[/tex]

V = 1206 cm³

Hence, The required approximate value volume of the cone is v =  1206 `cm³

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Please help What is the value of d?

Answers

Rule: with any inscribed quadrilateral, the opposite angles are supplementary (they add to 180 degrees)

Based on that rule, we can say
d+100 = 180
d+100-100 = 180-100
d = 80

Answer: 80

What is the answer for A?

What is the answer I need help now!!!!

Answers

When flipping a coin, you will either land on heads or tails. That being said, the probability of landing on either side is 50% as only 1 of 2 outcomes are possible.
The probability of heads is 0.50, or 50%.

I hope this helps!

Find the circumstances of the circle

Answers

The meaning of circumference is to find the distance around a circle or in other words perimeter by using the formula C=2πr or C=πd.

On this case it is asked you to find the circumference of a circle with a diameter of 3 meters, so you will use the formula C=2πr.

C=2πr
C=2(3.14)(3)
C=18.84 meters

The circumference of the given circle is 18.84 meters.

A family size container of macaroni holds sixteen 3/4 cup servings. A chef prepares meals using 1-cup bowls. How many bowls can the chef prepare from one family sized container?

Answers

Determine total # of cups in the container.

= 16 servings * 3/4 cups
= (16*3)/4
= 48/4
= 12 cups

Since the container holds 12 1-cup servings, the chef can prepare 12 1-cup servings.

Hope this helps! :)

Answer:

The answer is 12 cups.

Step-by-step explanation:

A family size container of macaroni holds 16 [tex]\frac{3}{4}[/tex] cup servings.

A chef prepares meals using 1-cup bowls.

So, the number of bowls, the chef can prepare from one family sized container is = [tex]16\times\frac{3}{4}[/tex]

= [tex]4\times3=12[/tex] bowls

Therefore, the answer is 12 cups.

what is the solution to the proportion? 3y-8/12 = y/5

Answers

Answer: 40 / 3

Justification:

A proportion is the equality of two ratios.

Your equality is:

3y - 8         y
--------- =   ---
   12           5

That equality is an equation. Now you must solve for y.

These are the steps:

1) Multilpy both sides by 12 * 5

=> 5 (3y - 8) = 12y

2) Expand the parentesis (distributive property)

15y - 40 = 12y

3) Transpose 12 and - 40

15y - 12y = 40

4) Combine the like terms

3y = 40

5) Divide both sides by 3

y = 40 / 3

Answer: y = 40 / 3

You survey 67 employees, and 30 respond that their job satisfaction is high. What percentage of your employees have high job satisfaction?

Answers

30/67 x 100 = 44.78%

Answer:

Percentage of employees have high satifaction of tthe job = 44.78%

Explanation:

In a company there are 67 employees

after survey only 30 employees give the high satisfaction feedback.

So, percentage of employess have high job satisfaction = [tex] \frac{Survey result}{Total employees} *100
[/tex]

= [tex] \frac{30}{67}*100 [/tex]

= 0.44776*100

= 44.78% Final answer

Help me I don’t get this!!!

Answers

101 yeo don't venture know

Classify the model as exponential growth or exponential decay. Identify the growth or decay factor AND the percent of increase or decrease per time period.

y=100(1.05)^t

Plz help!

Answers

See also https://brainly.com/question/8975313

The growth factor is 1.05.

The increase is (1.05 -1)*100% = 5% per period.

Rectangle FGHJ is transformed according to the rule T(–3, –2)ry = x. What is the y-coordinate of J”?

Answers

we have that
 the point J (10,-6)
the rule is-----------(x,y)-------------------> (x-3, y-2)
therefore
J (10,-6)----------------- > (10-3,-6-2)--------> (7,-8)

the answer is 
the y-coordinate of J” is -8

Answer:

The y-coordinate of J'' is 8.

Step-by-step explanation:

The given rule of transformation is

[tex]T(-3,-2)r_{y=x}[/tex]

It means, first the figure is reflected across the line y=x and then translated by the rule T(-3,-2).

From the given figure it is clear that the coordinates of point J are (10,-6).

If a figure is reflected across the line y=x, then

[tex](x,y)\rightarrow (y,x)[/tex]

The coordinate of point J'.

[tex]J(10,-6)\rightarrow J'(-6,10)[/tex]

If a figure is translate by the rule T(-3,-2), then

[tex](x,y)\rightarrow (x-3,x-2)[/tex]

The coordinate of point J''.

[tex]J'(-6,10)\rightarrow J''(-6-3,10-2)=J''(-9,8)[/tex]

Therefore the y-coordinate of J'' is 8.

Other Questions
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