A 100.0 g sample of aluminum released 1680 calories when cooled from 100.0c to 20.0 c what is the specific heat of the metal

Answer:

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

Explanation:

Step 1 : Write formule of specific heat

Q=mcΔT

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

with ΔT = Change in temperature

For this case :

Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)

m = 100.0g

c= has to be determined

ΔT = 100 - 20 = 80°C

Step 2:  Calculating specific heat

⇒ via the formule Q=mcΔT

7033.824 J = 100g * c * 80

7033.824 = 8000 *c

c = 7033.824 /8000

c = 0,879228 J/g °C

or 0.21 Cal / g°C

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

Final answer:

The specific heat of a metal can be found using the formula Q = mcΔT, which is rearranged to c = Q / (mΔT) to solve for c. For the 100.0 g sample of aluminum that released 1680 calories when cooled from 100.0°C to 20.0°C, the specific heat is calculated to be 0.21 cal/g°C.

Explanation:

To find the specific heat of a metal, you can use the formula Q = mcΔT, where Q is the heat absorbed or released in calories, m is the mass in grams, c is the specific heat capacity in cal/g°C, and ΔT is the change in temperature in degrees Celsius (°C).

In this case, we are given that a 100.0 g sample of aluminum released 1680 calories when cooled from 100.0°C to 20.0°C. The change in temperature (ΔT) is 100.0°C - 20.0°C = 80.0°C.

We can rearrange the formula to solve for c:
c = Q / (mΔT). Plugging in the given values:

c = 1680 cal / (100.0 g × 80.0°C)

After doing the calculation:

c = 1680 cal / 8000 g°C

c = 0.21 cal/g°C

So the specific heat of the metal is 0.21 cal/g°C.