A 1.5 mol sample of radon gas has a volume of 21.0L at 33°C.
What is the pressure of the gas?
A) 37.7 atm B) 1.8°C C) 1.8K D) 1.8 atm

Answer:

97.561 g/mol

Explanation:

The molar mass of Cu(OH)₂ is 97.57 g/mol. This is calculated by adding the atomic masses of copper, oxygen, and hydrogen in the compound. Each element's atomic mass is multiplied by the number of its atoms in the formula.

To find the molar mass of Cu(OH)₂, you need to add up the atomic masses of all the atoms in the compound:

Copper (Cu): 1 atom × 63.55 g/mol = 63.55 g/mol  

Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol

Hydrogen (H): 2 atoms × 1.01 g/mol = 2.02 g/mol

Adding these together gives the total molar mass of Cu(OH)₂:

Cu(OH)₂ molar mass = 63.55 g/mol + 32.00 g/mol + 2.02 g/mol

= 97.57 g/mol

Thus, the molar mass of Cu(OH)₂ is 97.57 g/mol.

Answer:

35.0 kPa

Explanation:

As pressure decreases, the volume of a gas increases at a given temperature., so since the balloon got bigger, the new pressure must be less than 103kPa

Assuming the temperature does not change, use Boyles Law

P1V1 = P2V2

(103kPa) (1750L) = P2 (5150L)

P2 = (103)(1750) / 5150

The pressure of the gas is inversely proportional to the volume of the gas. The pressure of the balloon at 5150 L is 35.0 kPa.

Boyle's Law states the relationship between the initial pressure and volume to the final pressure and the volume. It is given as,

[tex]\rm P_{1}V_{1} = \rm P_{2}V_{2}[/tex]

Given,

The initial pressure of the weather balloon = 10.3 kPa

The initial volume of the weather balloon = 1750 L

The final pressure of the weather balloon =?

The final volume of the weather balloon = 5150 L

Substituting values in the above equation:

[tex]\begin{aligned} \rm P_{2} &= \rm \dfrac{P_{1}V_{1}}{V_{2}}\\\\&= \dfrac{103 \times 1750}{5150}\\\\&= 35 \;\rm kPa\end{aligned}[/tex]

Therefore, the final pressure decreases with an increase in volume.

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Answer:

Heat

Explanation:

Friction can help convert heat into kinetic energy and kinetic energy into heat. Friction can be thought of as particles from different objects hitting each other. Collisions transfer energy converting large scale movement (kinetic energy) into small scale movement (heat).

Answer:

the answer is written in the picture.

Explanation:

Answer:

2H2 + O2 = 2H2O

Explanation:

To balance the equation, you must place coefficients behind the element and have equal amounts of atoms on both sides. In this case, to balance the equation, it would read:

2H2 + O2 = 2H2O

Answer:0.0014458

That’s the right one

Answer:

0.0014458

Explanation:

edg

Answer:

cartilage

Explanation:

The flexible connective tissue shown in blue in the shoulder joint is cartilage, which provides support and cushioning between bones.

The flexible connective tissue in the shoulder joint is primarily cartilage. Cartilage is a tough and resilient tissue that covers the ends of bones where they meet in a joint, providing a smooth surface for low-friction movement. In the shoulder, it is found in the glenoid cavity of the scapula (shoulder blade) and the head of the humerus (upper arm bone).

This articular cartilage naturally reduces friction and cushions the joint during various movements like arm rotation and lifting. While cartilage plays a crucial role in the shoulder joint's flexibility and function, it can be susceptible to wear and tear, leading to conditions like osteoarthritis.

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A process that involve rearrangement of the molecules or ionic structure of substance as distinct from change in the physical form or a nuclear reactions

I hope you are satisfied with this answer

Final answer:

A chemical reaction is a transformation where reactants are turned into products, involving changes at the atomic level including breaking and forming of bonds. Chemical equations represent these reactions, which must be balanced to reflect the conservation of matter.

Explanation:

A chemical reaction is a process that fundamentally changes one or more substances, known as reactants, into one or more different substances, known as products. These transformations involve a combination, separation, or rearrangement of atoms. During chemical reactions, bonds between atoms in the reactants are broken and new bonds are formed to create the products.

Chemical reactions are depicted using chemical equations, which have the reactants on the left side, an arrow representing “yields”, and the products on the right side. For a chemical equation to be useful or valid, it must be balanced, meaning it respects the law of conservation of mass with the same number and types of atoms on both sides. Examples of chemical reactions include the rusting of iron, the combustion of gasoline in a car's engine, and the metabolic processes within a living cell. In each case, the initial substances or reactants are transformed into different substances with new properties.

Answer : The specific heat of copper is, [tex]0.384J/g^oC[/tex]

Explanation :

Formula used :

[tex]q=m\times c\times \Delta T[/tex]

where,

q = heat absorb = 15200 J

m = mass of sample = 105 g

c = specific heat capacity of copper = ?

[tex]\Delta T[/tex] = change in temperature = [tex]377^oC[/tex]

Now put all the given values in the above formula, we get:

[tex]15200J=105g\times c\times 377^oC[/tex]

[tex]c=0.384J/g^oC[/tex]

Therefore, the specific heat of copper is, [tex]0.384J/g^oC[/tex]

Answer:

First one is : London dispersion

Second one is: London dispersion

Third One is : dipole-dipole

Fourth one is : induced dipole

Explanation:

Answer:

taste buds

Explanation:

Answer:

8.11g

Explanation:

Given parameters:

Molarity of aqueous solution = 0.3M

total volume  = 0.15L

Molecular weight of glucose  = 180.6g/mol

Unknown:

Mass of glucose needed in the solution = ?

Solution:

To solve this problem, we need to understand molarity.

Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.

      Molarity  = [tex]\frac{number of moles of solute}{volume of solution}[/tex]

A solution is made up of solute and solvent.

   now, let us solve for the number of moles of the solute which is glucose;

   Number of moles of glucose  = molarity x volume of solution;

                                                      = 0.3 x 0.15

                                                      = 0.045mole

Now to find the mass of glucose;

        mass of glucose  = number of moles x molar mass

             input the parameters;

         Mass of glucose  = 0.045  x 180.16 = 8.11g

To determine the amount of glucose needed for the solution, we calculate the number of moles of glucose in the solution and then use the molecular weight of glucose to convert this to grams. Thus, 8.107 g of glucose is necessary for the solution.

To figure out how much glucose we need, we'll have to use molarity, which measures the concentration of a solution. The molarity is defined as the number of moles of solute (in this case, glucose) per liter of solution.

Therefore, we first find the number of moles in the 0.150 L solution by multiplying 0.300 M by 0.150 L, which gives us 0.045 moles of glucose. Then, we multiply this by the molecular weight of glucose, which is 180.16 g/mol. Therefore, to create the solution, we'd need 8.107 g of glucose.

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Answer:

Molecular Weight of gas = 44.418 grams/mole

Explanation:

PV = nRT = (mass/f.wt.)RT => f.wt. = mass·R·T/P·V

mass = 0.435g

R = 0.08206·L·atm/mol·K

T = 100°C = 372K

P = (765/760)Atm = 1.01Atm

V = 297ml = 0.297L

f.wt. = (0.435g)(0.08206L·Atm/mol·K)(372K)/(1.01Atm)(0.297L) = 44.418 grams/mole

Answer:

vector

Explanation:

a vector is an organism that transmits a pathogen from organism to organism.

Answer:

b. is always a weak electrolyte.

Explanation:

Such compounds of low solubility dissociates partly and hence cannot be strong electrolytes

2. a. Approximately 0.0208 L of the 1.20 M AgNO3 solution is needed to precipitate all the chloride ions.

b. Approximately 2.70 g of AgCl should precipitate.

To find out how much AgNO3 solution is needed to precipitate all the chloride ions, we need to determine the amount of chloride ions present in the HCl solution and then use stoichiometry to find the amount of AgNO3 required.

Part a: Volume of AgNO3 solution needed

1. Calculate moles of Cl⁻ ions in the HCl solution:

Given:

- Volume of HCl solution = 250.0 mL = 0.250 L

- Concentration of HCl solution = 0.100 M

[tex]\[ \text{Moles of } \text{Cl⁻} = \text{Concentration} \times \text{Volume} \][/tex]

[tex]\[ \text{Moles of } \text{Cl⁻} = 0.100 \, \text{mol/L} \times 0.250 \, \text{L} = 0.025 \, \text{mol} \][/tex]

2. Use stoichiometry to find the moles of AgNO3 required:

From the balanced chemical equation:

[tex]\[ \text{AgNO3(aq)} + \text{HCl(aq)} \rightarrow \text{AgCl(s)} + \text{HNO3(aq)} \][/tex]

It's a 1:1 molar ratio between AgCl and Cl⁻ ions. So, moles of AgNO3 required = moles of Cl⁻ ions.

[tex]\[ \text{Moles of AgNO3} = 0.025 \, \text{mol} \][/tex]

3. Calculate the volume of 1.20 M AgNO3 solution:

Given:

- Concentration of AgNO3 solution = 1.20 M

[tex]\[ \text{Moles of AgNO3} = \text{Concentration} \times \text{Volume} \][/tex]

[tex]\[ 0.025 \, \text{mol} = 1.20 \, \text{mol/L} \times \text{Volume} \][/tex]

[tex]\[ \text{Volume} = \frac{0.025 \, \text{mol}}{1.20 \, \text{mol/L}} \][/tex]

[tex]\[ \text{Volume} ≈ 0.0208 \, \text{L} \][/tex]

Part b: Mass of AgCl precipitated

1. Calculate moles of AgCl precipitated:

From the stoichiometry, the moles of AgCl precipitated will be equal to the moles of Cl⁻ ions, which is 0.025 mol.

2. Calculate the mass of AgCl precipitated:

Given:

- Molar mass of AgCl = [tex]\( 107.87 \, \text{g/mol} \) (atomic masses: Ag = \( 107.87 \, \text{g/mol} \), Cl = \( 35.45 \, \text{g/mol} \))[/tex]

[tex]\[ \text{Mass of AgCl} = \text{Moles of AgCl} \times \text{Molar mass of AgCl} \][/tex]

[tex]\[ \text{Mass of AgCl} = 0.025 \, \text{mol} \times 107.87 \, \text{g/mol} \][/tex]

[tex]\[ \text{Mass of AgCl} \approx 2.70 \, \text{g} \][/tex]

Answer:

Sodium Sulfate: Dissociate

Ammonium Phosphate: Dissociate

Sulfuric Acid: Ionize

Potassium Iodide: Dissociate

Perchloric Acid: Ionize

Cesium Chloride: Dissociate

Nitric Acid: Ionize

Sodium Sulfate: Dissociate

Ammonium Phosphate: Dissociate

Sulfuric Acid: Ionize

Potassium Iodide: Dissociate

Perchloric Acid: Ionize

Cesium Chloride: Dissociate

Nitric Acid: Ionize

Ionization is described because of the method wherein new charged debris is produced. Dissociation is described as the technique wherein a charged particle is separated from the prevailing compound. that is an irreversible system. this is a reversible process.

Dissolution is any procedure that consequences in stages (whether it's liquid-liquid for acetic acid or stable-liquid for sodium chloride) creating an unmarried segment. Ionic compounds dissociate to try this, however many compounds (glucose, acetone, and many others.) can have interaction sufficient with water enough to dissolve without ionizing.

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Answer:

600.6L

Explanation:

Step 1:

The balanced equation for the reaction.

3CO + Fe2O3 --> 2Fe + 3CO2

Step 2:

Determination of the number of moles in 1001g of Fe.

This is illustrated below:

Mass of Fe = 1001g

Molar Mass of Fe = 56g/mol

Number of mole =?

Number of mole = Mass/Molar Mass

Number of mole of Fe = 1001/56

Number of mole of Fe = 17.875 mole

Step 3:

Determination of the number of mole of CO that reacted during the process.

This is illustrated below:

3CO + Fe2O3 --> 2Fe + 3CO2

From the balanced equation above,

3 moles of CO produced 2 moles of Fe.

Therefore, Xmol of CO will produce 17.875 moles of Fe i.e

Xmol of CO = (3 x 17.875)/2

Xmol of CO = 26.8125 moles

Step 4

Determination of the volume occupied by 26.8125 moles of CO at stp.

1 mole of a gas occupy 22.4L at stp.

Therefore 26.8125 moles of CO will occupy = 26.8125 x 22.4 = 600.6L

Therefore, 600.6L of CO is needed to produce 1001g of Fe

Answer:

[tex]V=602L[/tex]

Explanation:

Hello,

In this case, for the given chemical reaction:

[tex]3 CO + Fe_2O_3 \rightarrow 2 Fe + 3 CO_2[/tex]

In such a way, for the 1,001 g of iron, we compute the required moles of carbon monoxide by using the 2:3 mole ratio:

[tex]n_{CO}=1,001gFe*\frac{1molFe}{55.845gFe}*\frac{3molCO}{2molFe} \\\\n_{CO}=26.89molCO[/tex]

Finally, we use the ideal gas equation to compute the volute at STP conditions (1atm and 273K):

[tex]V=\frac{nRT}{P}=\frac{26.89mol*0.082\frac{atm*L}{mol*K}*273K}{1atm} \\\\V=602L[/tex]

Best regards.

Answer:

bite where there is less sauce.

Explanation:

i just ate a pizza and it worked

Answer:

take a bite near crust

Explanation:

because the sauce is still hot so u will get burned

Answer:

5.7

Explanation:

The amplitude of a sound wave determines its loudness. A higher amplitude results in a louder sound, and a lower amplitude results in a softer sound.

In Physics, the amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, while a smaller amplitude means a softer sound.

This spread of energy follows the inverse square law, meaning that doubling the distance from the sound source reduces its amplitude to one-quarter of its original value. This causes the sound to become softer the further it travels.

Answer:

Option A.12.8 atm

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 8 L

Initial pressure (P1) = 0.8 atm

Final volume (V2) = 0.5 L

Final pressure (P2) =?

Step 2:

Determination of the new pressure. The new pressure of the balloon can simply be obtained by applying the Boyle's law equation as follow:

P1V1 = P2V2

0.8 x 8 = P2 x 0.5

Divide both side by 0.5

P2 = (0.8 x 8) / 0.5

P2 = 12.8 atm

Therefore, the new pressure of the balloon is 12.8 atm

To find the amount of CO₂ produced from 12.0 g of CH₄ and 133 g of O₂, we write the balanced chemical equation for the combustion of methane, find the limiting reactant, which is CH₄, and then use stoichiometry to calculate that 32.95 grams of CO₂ will be produced.

The question involves a stoichiometry calculation in Chemistry where we need to determine how many grams of CO₂ will be produced from a given amount of CH₄ and O₂ based on a chemical reaction.

The first step is to write the balanced chemical equation for the combustion of methane:
CH₄(g) + 2 O₂(g) ⇒ CO₂(g) + 2 H₂O(l)

Next, we calculate the moles of CH4 using its molar mass:
(12.0 g CH₄) / (16.04 g/mol) = 0.7484 mol CH₄

Then, we need to check if oxygen is in excess by calculating the moles of O₂:
(133 g O₂) / (32.00 g/mol) = 4.156 mol O₂

Now, since the reaction requires 2 moles of O₂ for every mole of CH₄, we have more than enough O₂ to react with CH₄, which means CH₄ is the limiting reactant.

According to the balanced equation, 1 mole of CH₄ produces 1 mole of CO₂. Therefore, 0.7484 mol of CH₄ will produce 0.7484 mol of CO₂.

Finally, we calculate the mass of CO₂ produced:
(0.7484 mol CO₂) x (44.01 g/mol) = 32.95 g CO₂

Thus, 32.95 grams of CO₂ will be produced from the reaction between 12.0 g of CH₄ and 133 g of O₂.

Answer:

When energy is transformed from one from to another, energy is transferred form one form to another.

Explanation:

While the transformation of energy occur, total energy remains constant.

This is the LAW OF CONSERVATION OF ENERGY.

Answer : The number of moles of oxygen formed are, 0.255 moles.

Explanation :

The given chemical reaction is:

[tex]H_2O_2\rightarrow H_2O+O_2[/tex]

This reaction is an unbalanced chemical reaction because in this reaction number of oxygen atoms are not balanced.

In order to balance the chemical equation, the coefficient '2' put before the [tex]H_2O_2[/tex] and [tex]H_2O[/tex] then we get the balanced chemical equation.

The balanced chemical reaction will be:

[tex]2H_2O_2\rightarrow 2H_2O+O_2[/tex]

Now we have to calculate the number of moles of oxygen formed.

From the balanced chemical reaction we conclude that,

As, 2 moles of hydrogen peroxide react to give 1 mole of oxygen

So, 0.51 moles of hydrogen peroxide react to give [tex]\frac{0.51}{2}=0.255[/tex] mole of oxygen

Therefore, the number of moles of oxygen formed are, 0.255 moles.

Answer:

LIthium vegetable oil

Answer:

A and B

Explanation:

Answer: A and B.

Explanation:

I took the enginuidy