A 20.0 μf capacitor initially charged to 30.0 μc is discharged through a 1.80 kω resistor. how long does it take to reduce the capacitor's charge to 15.0 μc

Answers

Answer 1
The charge Q at time t on the capacitor (initially charged) in a RC-circuit is given by
[tex]Q(t)=Q_0 e^{-t/\tau}[/tex] (1)
where [tex]Q_0[/tex] is the initial charge, and [tex]\tau =RC[/tex] is the time constant of the circuit.

Using [tex]C=20 \mu F=20 \cdot 10^{-6}F[/tex] and [tex]R=18 k\Omega = 18 \cdot 10^3 \Omega[/tex] we can calculate the time constant:
[tex]\tau = RC= 0.36 s[/tex]

The problem asks for the time t at which the capacitor's charge is reduced to [tex]Q(t)=15 \mu C[/tex]. Since the initial charge is [tex]Q_0 = 30 \mu C[/tex], we can write
[tex] \frac{Q(t)}{Q_0}= \frac{15 \muC}{30 \muC} = \frac{1}{2} [/tex]
And we can rewrite equation (1) as
[tex] \frac{1}{2} = e^{-t/\tau} [/tex]

By solving this and by using [tex]\tau=0.36 s[/tex], we find
[tex]t=-\tau \ln( \frac{1}{2} )=0.25 s[/tex]
Answer 2
Final answer:

The time it would take for a 20.0 μF capacitor initially charged to 30.0 μC to discharge through a 1.80 kΩ resistor and reduce the capacitor's charge to 15.0 μC can be calculated using the formula for exponential decay and the time constant of the RC circuit.

Explanation:

The time it takes for a capacitor to discharge to half of its original charge can be found using the formula for exponential decay, based on the time constant (t) of the RC circuit, which is given by t = RC, where R is the resistance and C is the capacitance. The time constant represents the time it takes for the charge to decrease to about 36.8% of its initial value. Since we are looking for the time it takes to reduce to half of the initial charge, we must solve the equation 0.5 = e^(-t/RC), where e is the base of natural logarithms.

To solve for t, we can rearrange the equation to get -ln(0.5) = t/RC. Given that R = 1.80KΩ = 1.80x10^3 Ω and C = 20.0 µF = 20.0x10^-6 F, we can substitute these into the equation to find t. Therefore, the time it takes for a 20.0 μF capacitor initially charged to 30.0 µC to discharge through a 1.80 kΩ resistor to reduce the capacitor's charge to 15.0 μC can be calculated using these formulas.

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Related Questions

Which of the following statements is true of taking responsibility?

A. If you correct a mistake quickly, no one else needs to know about it.
B. You can't expect people to respect you if you make too many mistakes.
C. Blaming another for your mistake is sensible when your accusation can be proven.
D. You're unlikely to get control of your life when you blame others for your mistakes.

Answers

I think it is D. You're unlikely to get control of your life when you blame others for your mistakes.
. Blaming others for your own bad deeds gets you nowhere.

A soccer ball is kicked with an initial speed of 23 m/s at an angle of 21° with respect to the horizontal. (a) find the maximum height reached by the ball. m (b) find the speed of the ball when it is at the highest point on its trajectory. m/s (c) where does the ball land

Answers

a. the maximum height reached by the ball is approximately 3.46 meters.

b.   the speed of the ball when it is at the highest point is approximately 21.19 meters per second.

c.   the ball lands  14.83 meters away from the launch point in the same direction as its horizontal component of velocity.

a)

Vertical component = Initial speed * sin(launch angle)

Vertical component = 23 m/s * sin(21°) = 8.23 m/s

The maximum height reached by the ball can be calculated using the equation:

Maximum height = (Vertical component²) / (2 * gravity)

Gravity = 9.81 m/s².

Maximum height = (8.23 m/s)² / (2 * 9.81 m/s²)

=  3.46 m

b)

At the highest point, the vertical component of velocity becomes zero  because the ball stops momentarily before falling back down.

Horizontal component = Initial speed * cos(launch angle)

Horizontal component = 23 m/s * cos(21°) =  21.19 m/s

c)

Time to fall = (2 * Maximum height) / gravity

Time to fall = (2 * 3.46 m) / 9.81 m/s² =  0.70 s

Horizontal distance = Horizontal component * Time to fall

Horizontal distance = 21.19 m/s * 0.70 s =  14.83 m

G davisson and germer performed their experiment with a nickel target for several electron bombarding energies. at what angles would they find diffraction maxima for 48 ev and 60 ev electrons?

Answers

if the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.

Explain what is meant by the term mechanical advantage.


:Levers are tools that allow a small effort to move significantly larger loads. This apparent magnification of the force applied to a lever, and the force resulting from it, is called its mechanical advantage.

Answers

So, in general, we can push something with 10 N of force and it will usually experience a force of 10 N. But if we use levers and other mechanisms, we can magnify the force that is felt. For example, if there is the tendency to rotate, we can have that in the picture I have attached there is balance. That is because the torques have to be equal and this happens if the heavier object is much further from the support than the lighter one. This is the same mechanism as with doors; it is much easier to open a door from the handle than from the rim. At the handle, the torque is greater, even though the force you apply on both cases is the same. In this picture, while the force on the right is bigger, the torques get balanced due to the distance difference. Hence, you can apply 10N on the left side and you will be lifting a box that weighs 100N! That is the magic of levers and in scientific language it is called the mechanical advantage.

The term mechanical advantage is used to described how effectively a simple machine works. Mechanical advantage is defined as the resistance force moved divided by the effort force used. In the lever example above, for example, a person pushing with a force of 30 lb (13.5 kg) was able to move an object that weighed 180 lb (81 kg). So the mechanical advantage of the lever in that example was 180 lb divided by 30 lb, or 6. The mechanical advantage described here is really the theoretical mechanical advantage of a machine. In actual practice, the mechanical advantage is always less than what a person might calculate. The main reason for this difference is resistance. When a person does work with a machine, there is always some resistance to that work. For example, you can calculate the theoretical mechanical advantage of a screw (a kind of simple machine) that is being forced into a piece of wood by a screwdriver. The actual mechanical advantage is much less than what is calculated because friction must be overcome in driving the screw into the wood.

Sometimes the mechanical advantage of a machine is less than one. That is, a person has to put in more force than the machine can move. Class three levers are examples of such machines. A person exerts more force on a class three lever than the lever can move. The purpose of a class three lever, therefore, is not to magnify the amount of force that can be moved, but to magnify the distance the force is being moved. As an example of this kind of lever, imagine a person who is fishing with a long fishing rod. The person will exert a much larger force to take a fish out of the water than the fish itself weighs. The advantage of the fishing pole, however, is that it moves the fish a large distance, from the water to the boat or the shore.

A block with a weight of 3.00 n is at rest on a horizontal surface. a 1.00 n upward force is applied to the block by means of an attached vertical string. collapse question part step 1 how many forces act on the block?

Answers

Initially, when the block is at rest on the horizontal surface, two forces act on the block:
- its weight (3.00 N) acting downward
- the vincular reaction of the surface, acting upward and with same magnitude of the weight (3.00 N)

After the force of the vertical string starts to act on the block, three forces act on the block:
- its weight (3.00 N) acting downward
- The tension of the string, acting upward a force of 1.00 N
- the vincular reaction of the surface, acting upward but with less intensity than before: in fact, it counterbalances the net force acting upward, which is now (1.00N-3.00 N=-2.00 N), so the vincular reaction now is 2.00 N.

A 0.30-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. the well has a depth of 5.1 m. (a) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system before the stone is released? j (b) relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stoneâearth system when it reaches the bottom of the well? j (c) what is the change in gravitational potential energy of the system from release to reaching the bottom of the well? j

Answers

(a) The gravitational potential energy of the stone before it is released is:
[tex]U=mg \Delta h[/tex]
where m=0.30 kg is the mass of the stone, [tex]g=9.81 m/s^2[/tex] and [tex]\Delta h[/tex] is the difference in height relative to the reference level, which is the top edge of the well. Therefore, since the stone in this situation is at h=1.2 m above the top edge of the well, [tex]\Delta h=1.2 m[/tex], and the gravitational potential energy is
[tex]U=(0.30 kg)(9.81 m/s^2)(1.2 m)=3.5 J[/tex]

(b) Similarly, the gravitational potential energy when the stone reaches the bottom of the well is
[tex]U=mg \Delta h[/tex]
but this time the stone is at the bottom of the well, so at 5.1 m below the top edge of the well, therefore [tex]\Delta h=-5.1 m[/tex]. So, the gravitational potential energy in this situation is
[tex]U=(0.30 kg)(9.81 m/s^2)(-5.1 m)=-15.0 J[/tex]

(c) The change in gravitational potential energy from release to the bottom of the well is:
[tex]\Delta U= U_b-U_a=-15.0 J-(3.5 J)=-18.5 J[/tex]

When you jump vertically off the ground, when you reach your highest point your velocity is zero and your acceleration is zero?

Answers

just try your best best friend everyone

two teams are playing tug of war. team a pulls to the right with a force of 450n .team b pulls to the left with a force of 415 n. what is the net force on the rope and what is its direction?

Answers

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, [tex]F_A=450\ N[/tex]

Force applied by Team B, [tex]F_B=415\ N[/tex]

We need to find the net force acting on the rope. It is equal to :

[tex]F_{net}=F_A-F_B[/tex]

[tex]F_{net}=450-415[/tex]

[tex]F_{net}=35\ N[/tex]

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

Answer:

20 N to the left

Explanation:

Two brothers are sitting on a wide bench on a carnival carousel. Aiden sits at a distance R away from the center of the carousel. Daniel sits at a distance 0.75R away from the center after the carousel begins moving in uniform circular motion, what is the ratio of Daniels centripetal acceleration to aidens centripetal acceleration?


A. 3:4
B. 1:1
C. 9:16
D. 4:1

Answers

I think A.3:4 question

Which of these is the best definition of a fuel cell?

Answers

a cell producing an electric current directly from a chemical reaction

The answer is a voltaic cell that uses the oxidation of a fuel to produce electricity.

~Deceptiøn

What are three machines that depend on gravity to work

Answers

Hello!

There are lot's of machines that depend on gravity to work! Here's a few:

• Lever

• Screw

• Wheel

• Pulley

Why is temperature a good criterion for searching for Earthlike exoplanets?

Answers

Answer:

Liquid water is essential for life to exist. Water can occur in a liquid state only within a specific temperature range, so knowing the temperature range on a planet will help astronomers predict whether life exists on that planet.

Explanation:

Final answer:

Temperature is a critical criterion for finding Earthlike exoplanets because it determines the presence of liquid water, a requirement for life. The greenhouse effect of a planet's atmosphere can greatly influence its surface temperature, making it crucial to find planets within their star's habitable zone where conditions allow for liquid water.

Explanation:

Temperature is an excellent criterion for searching for Earthlike exoplanets because it is a fundamental factor that determines a planet's habitability. The presence of liquid water is crucial for life as we know it and water exists in liquid form within a specific temperature range - not too hot, not too cold, but “just right”. Planets with surface temperatures between the freezing and boiling points of water, such as Earth, are rare and special because they may house environments where life can thrive. Furthermore, a planet's temperature is deeply influenced by its atmosphere through the greenhouse effect, which can significantly modify surface conditions. Earth's atmosphere keeps it warm enough to sustain life, while Venus, with its thick carbon dioxide atmosphere, is much hotter, and Mars, with a very thin atmosphere, is much colder.

Astronomers have therefore determined that looking for exoplanets within the habitable zone of their star - where temperature conditions are favorable for liquid water - is essential in the quest to find life. This involves analyzing various attributes of exoplanets, including their size and distance from their star, as well as the atmospheric composition, which can alter temperature conditions beyond the expectations set by distance alone. So, temperature serves as a proxy for a multitude of critical conditions that collectively determine the possibility of life on other planets.

A ____ is a region so dense that nothing, including light, can escape its gravity field.

a. supernova c. black hole b. white dwarf d. supergiant Please select the best answer from the choices provided

Answers

The answer is c. black hole

Answer:

black hole

Explanation:

A black hole is a region which is highly dense and very high gravitational field.

As the density of black hole is very high, so the mass of black g=hole is very large thus the force of gravitation is very large. So, even light cannot escape from the gravitational filed from the black hole.

A wave has a wavelength of 8 mm and a frequency of 14 Hertz what is its speed?

Answers

To find the speed you multiply the wavelength and the frequency together.

wavelength = 8mm = [tex]8x10^{-3}[/tex] m = 0.008 m
frequency = 14 Hz

speed = 0.008m * 14 Hz = 0.112 m/s

The diagram below shows rock is affected when water enters cracks in rock,freezes and becomes ice

Answers

Final answer:

The question explores the concept of physical weathering known as frost wedging, which occurs when water freezes in rock cracks, causing the rocks to break apart. This process relates to the property of water expanding upon freezing, which explains ice's lower density and its effects on the environment and human-made structures.

Explanation:

The student's question pertains to the process by which water enters cracks in rocks, freezes, and expands into ice, which is known as frost wedging or frost weathering. This process is a type of physical weathering that occurs in cold climates when temperatures fluctuate above and below 0°C (32°F). As water freezes, it expands by approximately 9%, exerting significant pressure on the surrounding rock, eventually causing it to break apart. The phenomenon of water expanding upon freezing is due to the unique structure of ice.

Understanding ice density is significant for explaining why ice floats and how it affects aquatic ecosystems and human constructions. When water transitions to ice, its molecules form a crystalline structure that is less dense than liquid water, causing ice to float. This property of ice provides crucial insulating effects in natural bodies of water, allowing life to persist beneath the ice layer during winter. Furthermore, the expansion of water when it freezes is why we use antifreeze in engines and why pipes can burst if not properly insulated.

A certain shade of blue has a frequency of 7.15 × 1014 hz. what is the energy of exactly one photon of this light?

Answers

The energy carried by a single photon of frequency f is given by:
[tex]E=hf[/tex]
where [tex]h=6.6 \cdot 10^{-34} m^2 kg s^{-1}[/tex] is the Planck constant. In our problem, the frequency of the photon is [tex]f=7.15 \cdot 10^{14}Hz[/tex], and by using these numbers we can find the energy of the photon:
[tex]E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J[/tex]

Consider a well-insulated horizontal rigid cylinder that is divided into two compartments by a piston that is free to move but does not allow either gas to leak into the other side. initially, one side of the piston contains 1 m3 of n2 gas at 500 kpa and 120°c while the other side contains 1 m3 of he gas at 500 kpa and 40°c. now thermal equilibrium is established in the cylinder as a result of heat transfer through the piston. using constant specific heats at room temperature, determine the final equilibrium temperature in the cylinder. what would your answer be if the piston were not free to move

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begins to move. then the force (in newtons) exerted by the expanding gas on the bullet is 16000 10000x - 26000x2, where x is in meters. (a) determine the work done by the gas on the bullet as the bullet travels the length of the barrel. (enter your answer to at least two decimal places.) 8.73 kj (b) if the barrel is 0.95 m long, how much work is done

Answers

part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
[tex]W= \int\limits^{0.540m}_{0} {F} \, dx = \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx = [/tex]
[tex]=16000x+10000 \frac{x^2}{2} - 26000 \frac{x^3}{3} [/tex]
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
[tex]W=16000(0.540m)+10000 \frac{(0.540m)^2}{2} - 26000 \frac{(0.540m)^3}{3} = [/tex]
[tex]=8733 J=8.73 kJ [/tex]

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
[tex]W=16000(0.95m)+10000 \frac{(0.95m)^2}{2} - 26000 \frac{(0.95m)^3}{3} =[/tex]
[tex]=12280 J=12.28 kJ[/tex]

Which statement explains why the moon's gravity is able to create high and low tides

Answers

the moon is revolving more slowly than the earth is rotating 

Justin, with a mass of 50 kg, is going down an 8.0-m-high water slide. he starts at rest, and his speed at the bottom is 12 m/s. part a how much thermal energy is created by friction during his descent? express your answer with the appropriate units.

Answers

We can use the law of conservation of energy to solve the problem.

At the top of the slide, Justin is still, so its velocity and its kinetic energy are zero. He only has gravitational potential energy U, so its total mechanical energy is:
[tex]E_i = U = mgh = (50 m)(9.81 m/s^2)(8.0m)=3924 J[/tex]

At the bottom of the slide, the height is now zero, so there is no potential energy left. Instead, Justin acquired a speed v, so its kinetic energy K will be different from zero now, and it will be:
[tex]E_f = K = \frac{1}{2}mv^2= \frac{1}{2}(50kg)(12 m/s)^2=3600 J [/tex]

So, the energy lost by Justin when going from top to bottom is
[tex]\Delta E = E_i-E_f = 3924 J-3600 J=324 J[/tex]
And since energy cannot be destroyed, this energy must have converted into something else, and in fact it corresponds to the thermal energy created by the frictional force during the descent.

The converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

Explanation:

Given information:

Mass of justin [tex]=50 \; \text{kg}[/tex]

Height of water slide [tex]=8\;\text{m}[/tex]

Speed at the bottom [tex]= 12 \;\text{m/s}[/tex]

Now, the total mechanical energy is:

[tex]E_i=U=mgh\\E_i=50\times 9.81\times 8\\E_i=3924\;J[/tex]

And, the kinetic energy :

[tex]E_f=K=(1/2)mv^2\\E_f=0.50\times 50\times 12\\E_f=3600\;\text{J}[/tex]

So, the energy lost by the justin:

[tex]\Delta\;E=E_i-E_f\\\Delta\;E=3924-3600\\\Delta\;E=324J\\[/tex]

Hence, this converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

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Unlike metals, nonmetals exhibit high ______ and fractures easily when subjected to stress.
A) absorbance
B) brittleness
C) ductility
D) malleability

Answers

The asnwere is B) Brittleness

Answer: Option (B) is the correct answer.

Explanation:

Non-metals are the substance which are electron deficient in nature.

Some properties of non-metals are as follows.

Non-metals are dull.They are brittle, that is, they tend to break easily.They have low melting and boiling point.They do not conduct heat and electricity.The are not malleable or ductile.

Thus, we can conclude that unlike metals, nonmetals exhibit high brittleness and fractures easily when subjected to stress.


An ideal gas in a sealed container has an initial volume of 2.30 l. at constant pressure, it is cooled to 24.00 °c where its final volume is 1.75 l. what was the initial temperature?

Answers

Considering the Charles' law, the initial temperature was 390.34 K or 117.34 °C.

Definition of Charles's Law

Charles's Law consists of the relationship that exists between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. For a given amount of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

V÷T=k

Analyzing an initial state 1 and a final state 2, the following is true:

V₁÷T₁=V₂÷T₂

Initial temperature

In this case, you know:

V₁= 2.30 LT₁= ?V₂= 1.75 LT₂= 24 °C= 297 K (being 0°C= 273 K)

Replacing in Charles' law:

2.30 L÷T₁= 1.75 L÷297 K

Solving:

2.30 L= (1.75 L÷297 K)× T₁

2.30 L÷ (1.75 L÷297 K)= T₁

390.34 K= 117.34 °C= T₁

Finally, the initial temperature was 390.34 K or 117.34 °C.

A bag of groceries has a weight of 44 newtons. Find its approximate weight in kilograms.

Answers

You cannot convert newtons to kilograms, or pounds to kilograms,
or kilograms to pounds or newtons.

Newtons and pounds are units of FORCE.  Kilogram is a unit of MASS.


If an object weighs 44 newtons on Mars,
then its mass is about 13.5 kilograms

If an object weighs 44 newtons on the Moon,
then its mass is about 27.2 kilograms.

If an object weighs 44 newtons on Earth,
then its mass is about 4.5 kilograms.

Final answer:

To convert the weight of a bag of groceries from newtons to kilograms, divide the weight in newtons (44 N) by the acceleration due to gravity (9.8 m/s²), which gives an approximate mass of 4.49 kg.

Explanation:

To find the approximate weight of a bag of groceries in kilograms when given a weight of 44 newtons, we need to use the relation between mass, weight, and gravitational acceleration. Weight is the force due to gravity, and it's measured in newtons (N). To convert newtons to kilograms, we divide the weight by the acceleration due to gravity, which is approximately 9.8 m/s². Therefore:

Weight in kilograms = Weight in newtons ÷ gravitational acceleration

Weight in kilograms = 44 N ÷ 9.8 m/s²

Weight in kilograms ≈ 4.49 kg

This is a physics problem involving the conversion of units between the weight (force) and mass, and it requires a basic understanding of the relationship between these concepts. The result, 4.49 kg, represents the mass of the groceries that causes a weight of 44 N.

Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of _______ on blood flow.

Answers

Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of gravity on blood flow.

Veins must counteract the force of gravity on blood flow. Unlike arteries that carry blood away from the heart under high pressure, blood in veins is under much lower pressure after passing through capillaries.

The presence of one-way valves in veins, particularly in the limbs, is crucial to ensure the unidirectional flow of blood back toward the heart. These valves, along with the help of muscle contractions, prevent backflow and assist venous return to the heart, overcoming the effects of gravity and the reduced pressure in the venous system.

By the time blood reaches the venules and veins, the pressure initially exerted by heart contractions has greatly decreased. The veins are equipped with thin walls, large lumens, and valves that work together with muscle contractions to promote the return of blood to the heart.

This system compensates for the low blood pressure and the pull of gravity that would otherwise hinder the upward movement of blood from the extremities.

(b) if we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? explain your reasoning.

Answers

I think I recovered the original question, I'll repost it here:

A typical cell membrane in an animal maintains a potential difference across the membrane of ΔV = 70 mV and the membrane has a thickness of about 8 nm. The capacitance of the membrane is about 1 microFarad per square cm. 

(B) If we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? Explain your reasoning.

Now, notice that:

[tex]Q=C\Delta V\\ \Delta V=E.L[/tex]

Where L is the thickness of the membrane.

We then can get the electric field by just using:

[tex]E=\frac{\Delta V}{L}=\frac{70\times10^{-3}}{8\times10^{-9}}=8.75\times10^{6}N.C^{-1}[/tex]

Now using the charge expression and plugging the the expression for [tex]\Delta V[/tex] into it and then solving for [tex]E[/tex] we get:

[tex]E=\frac{Q}{CL}[/tex]

Now let's multiply both denominator and numerator by [tex]\frac{1}{A}[/tex] this yields:

[tex]E=\frac{\sigma}{C_{\sigma}L}[/tex]

Where 

[tex]\sigma=\frac{Q}{A}\\ C_{\sigma}=\frac{C}{A}[/tex]

Notice that the value in the wording of the problem is no actually the capacitance, but the capacitance per area [tex]C_{\sigma}[/tex], also [tex]\sigma[/tex] is the charge density.

Let's transform [tex]C_{\sigma}[/tex] to [tex]\frac{farad}{m^2}[/tex]:

[tex]\frac{1\mu F}{cm^2}=\frac{1\times10^{-2}F}{m^2}[/tex]


Solving for  [tex]\sigma[/tex] we get:

[tex]sigma=E.C_{\sigma}.L=7\times10^{-4}\frac{Coulomb}{m^2}=7\times10^{-8}\frac{Coulomb}{cm^2}[/tex]




On the decibel scale, a “quiet whisper 1 meter away” is about ____________ decibels,  where a “jackhammer 3 meters away” is _____________ decibels.  a) 20, 100      b) 10, 100      c) 10‐15, 90 

Answers

Looking at decibel scale tables on internet, a "quiet whisper 1 meter away" is generally reported to have a sound intensity of about 20 dB, while a jackhammer 3 meters away produces a sound of about 100 dB of intensity, so option a) could be the correct one.
However, the other options could be considered correct as well, because without knowing the exact sound power produced by the whisper or by the jackhammer it's impossible to calculate the exact sound intensity with precision, and since the values reported in the three options are very similar, all the three of them can be considered as valid.

A circuit consists of a 9.0 v battery connected to three resistors (37 , 17 , and 110 ) in series. (a) find the current that flows through the battery. ma (b) find the potential difference across each resistor. v37 = v v17 = v v110 = v

Answers

(a) The equivalent resistance of three resistors in series is the sum of the three resistances:
[tex]R_{eq}=R_1 + R_2 + R_3 = 37 \Omega + 17 \Omega + 110 \Omega = 164 \Omega[/tex]
And so the current flowing through the circuit (and the battery) can be found by using Ohm's law:
[tex]I= \frac{V}{R_{eq}}= \frac{9.0 V}{164 \Omega}=0.055 A [/tex]

(b) The potential difference across each resistor is given by Ohm's law:
[tex]V_{37} = I R_{37}=(0.055 A)(37 \Omega)=2.04 V[/tex]
[tex]V_{17}=I R_{17}=(0.055 A)(17 \Omega)=0.94 V[/tex]
[tex]V_{110}=I R_{110}=(0.055 A)(110 \Omega)=6.05 V[/tex]

Larry designed an experiment to show how heat can be transferred from one place to another. The steps of the experiment are shown below. Light a candle. Place palm of the hand about 6 inches above the flame. Feel the heat from the burning candle on the palm of the hand. What does Larry's experiment most likely demonstrate?

Answers

What Larry's experiment most likely demonstrate is heat transfer by convection

Heat transfer by convection occurs when particles of heated liquid or gases travel away from the source, carrying thermal energy along. Convection above the flame of the lit candle occurs because the hot air from the candle expands, becomes less dense, and rises towards the palm.

Answer:

heat transfer by convection

Explanation:

yeah the heat just goes to your hand like "hello" now your hand is warm just don't TOUCH the fire because then it will go "HELLO" and it will be painful

Have a fantastic life and just I don't know... live life and go outside it's beautiful.

An agitated llama may spit to assert dominance, or to ward off threats. llamas can spit a considerable distance, and people handling them need to keep this in mind. part a if the spittle from a llama is launched from an initial height of 1.8 m with a speed of 5.5 m/s, and at an angle of 13 ?? above horizontal, how far will it travel horizontally?

Answers

the answer is 4.7 m for the spàthan. this is a very question! I hope this helps my friend! :-)

The horizontal distance traveled by the spittle is 2.62 m.

The given parameters;

height of projection, h = 1.8 minitial velocity, v = 5.5 m/sangle of projection, Ф = 13°

The time of motion is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\1.8 = (5.5\times sin(13))t + (0.5\times 9.8)t^2\\\\1.8 = 1.24t + 4.9t^2\\\\4.9t^2 + 1.24t - 1.8= 0\\\\solve \ the \ quadratic \ equation\ using \ formula \ method;\\\\a = 4.9, \ b = 1.24, \ c = -1.8\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-1.24 \ \ +/- \ \ \sqrt{(1.24)^2 - 4(4.9\times -1.8)} }{2(4.9)} \\\\t = 0.49 \ s[/tex]

The horizontal distance traveled by the spittle is calculated as;

[tex]X = v_0_x \times t\\\\X = 5.5\times cos (13) \times 0.49\\\\X = 2.62 \ m[/tex]

Thus, the horizontal distance traveled by the spittle is 2.62 m.

Learn more here:  https://brainly.com/question/24293822

You apply a potential difference of 5.70 v between the ends of a wire that is 2.90 m in length and 0.654 mm in radius. the resulting current through the wire is 17.6
a. what is the resistivity of the wire?

Answers

1) First of all, let's find the resistance of the wire by using Ohm's law:
[tex]V=IR[/tex]
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
[tex]R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega [/tex]

2) Now that we have the value of the resistance, we can find the resistivity of the wire [tex]\rho[/tex] by using the following relationship:
[tex]\rho = \frac{RA}{L} [/tex]
Where A is the cross-sectional area of the wire and L its length.
We already have its length [tex]L=2.90 m[/tex], while we need to calculate the area A starting from the radius:
[tex]A=\pi r^2 = \pi (0.654\cdot 10^{-3}m)^2=1.34 \cdot 10^{-6}m^2[/tex]

And now we can find the resistivity:
[tex]\rho = \frac{RA}{L}= \frac{(0.32 \Omega)(1.34 \cdot 10^{-6}m^2)}{2.90m}= 1.48 \cdot 10^{-7}\Omega \cdot m[/tex]
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