A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 58.5 ∘c. part a what is the mass of the water? express your answer to two significant figures and include the appropriate units.

Answers

Answer 1
When the iron and the water reach thermal equilibrium, they have same temperature, [tex]T=58.5^{\circ}C[/tex].
We can consider this as an isolated system, so the heat released by the water is equal to the heat absorbed by the iron.

The hear released by the water is:
[tex]Q_w =m_w C_{sw} \Delta T_w[/tex]
where [tex]m_w[/tex] is the water mass, [tex]C_{sw}=4.186 J/(g^{\circ}C)[/tex] is the specific heat of the water, and [tex]\Delta T_w = 63.6^{\circ}-58.5^{\circ}=5.1^{\circ}C[/tex] is the variation of temperature of the water.

Similarly, the heat absorbed by the iron is:
[tex]Q_i = m_i C_{si} \Delta T_i[/tex]
where [tex]m_i = 33.0 g[/tex] is the iron mass, [tex]C_{si}=0.444 J/(g^{\circ}C)[/tex] is the iron specific heat, and [tex]\Delta T_i = 58.5^{\circ}-22.7^{\circ}=35.8^{\circ}C[/tex] is the variation of temperature of the iron.

Writing [tex]Q_w=Q_i[/tex] and replacing the numbers, we can solve to find mw, the mass of the water:
[tex]m_w= \frac{m_i C_{si} \Delta T_i}{C_{sw} \Delta T_w} =24.6 g[/tex]

Related Questions

Sound waves require a medium to travel through, such as a solid, liquid or gas because A) waves cannot move through a vacuum. B) sound only works within certain pressures. C) waves only work within certain temperatures. D) sound is molecules bumping into one another. Eliminate

Answers

Sound waves require a medium to travel through, such as a solid,
liquid or gas because sound travels by means of molecules bumping
into one another. (D)

D) sound is molecules bumping into one another.

Explanation:

Sound waves are longitudinal waves generated by the vibrations of the molecules  of a medium. These oscillations occur in a direction parallel to the direction of propagation of the wave (longitudinal wave), so basically the wave is transmitted by the collisions between the molecules of the medium, and therefore D. is the correct answer. Morevoer, these oscillations create regions of higher density of molecules (called compressions) and regions of lower density of molecules (called rarefactions).

A 1.80 m radius playground merry-go-round has a mass of 120 kg and is rotating with an angular velocity of 0.330 rev/s. what is its angular velocity, in rev/s, after a 27.5 kg child gets onto it by grabbing its outer edge? the child is initially at rest.

Answers

Final answer:

To find the final angular velocity of the merry-go-round after the child gets on it, we use the conservation of angular momentum. By setting the initial and final angular momenta equal, we can solve for the final angular velocity. The final angular velocity is found to be approximately 0.301 rev/s.

Explanation:

To find the angular velocity of the merry-go-round after the child gets on it, we need to consider the conservation of angular momentum. The initial angular momentum of the system is equal to the final angular momentum after the child grabs the outer edge. The initial angular momentum of the system is calculated as the product of the moment of inertia of the merry-go-round and its initial angular velocity. The final angular momentum is calculated as the sum of the moment of inertia of the merry-go-round and the child and the final angular velocity.

Let's denote the initial angular velocity of the merry-go-round as ω1, the final angular velocity as ω2, the moment of inertia of the merry-go-round as I1, the moment of inertia of the child as I2, the radius of the merry-go-round as R, the mass of the merry-go-round as M, and the mass of the child as m.

The initial angular momentum is given by:

L1 = I1 * ω1

And the final angular momentum is given by:

L2 = (I1 + I2) * ω2

Setting the initial and final angular momenta equal, we have:

I1 * ω1 = (I1 + I2) * ω2

Rearranging the equation, we can solve for ω2:

ω2 = (I1 * ω1) / (I1 + I2)

Substituting the given values, we have:

ω2 = (120 kg * (1.80 m)^2 * 0.330 rev/s) / ((120 kg * (1.80 m)^2) + (27.5 kg * (1.80 m)^2))

Simplifying the expression, we can calculate the final angular velocity:

ω2 ≈ 0.301 rev/s

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If a car goes along a straight road heading east and speeds up from 45ft/s to 60ft/s in 5s , calculate the acceleration

Answers

acceleration = change in velocity/ time = (final velocity - initial velocity)/time 

accel = (60ft/s - 45ft/s)/5s = 3 ft/s

If the Earth and distant stars were stationary (motionless) in space, what would we observe about the wavelength from these stars?

A.Wavelengths measured would match the actual wavelengths emitted.
B.Wavelengths measured would be shorter than the actual wavelengths emitted.
C.Wavelengths measured would be longer than the actual wavelengths emitted.

If a star is moving toward us in space, what would we observe about the wavelength from these stars?

A.Wavelengths measured would be shorter than the actual wavelengths emitted.

B.Wavelengths measured would match the actual wavelengths emitted.

C.Wavelengths measured would be longer than the actual wavelengths emitted.

Answers

1) In the first case, the correct answer is
A.Wavelengths measured would match the actual wavelengths emitted.
In fact, the stars are not moving relative to Earth, so there is no shift in the measured wavelength.

2) In this second case, the correct answer is
A.Wavelengths measured would be shorter than the actual wavelengths emitted.
in fact, since the stars in this case are moving towards the Earth, then apparent frequency of their emitted light will be larger than the actual frequency, because of the Doppler effect, according to the formula:
[tex]f'= \frac{c}{c+v_s} f_0 [/tex]
where f0 is the actual frequency, f' the apparent frequency, c the speed of light and vs the velocity of the source (the stars) relative to the obsever (Earth). Vs is negative when the source is moving towards the observer, so the apparent frequency f' is larger than the actual frequency f0. But the wavelength is inversely proportional to the frequency, so the apparent wavelength will be shorter than the actual wavelength.

What’s the force of a pitching machine on a baseball? Baseballs pitched by a machine have a horizontal velocity of 30 meters/second. The machine accelerates the baseball from 0 meters/second to 30 meters/second in 0.5 seconds. If a baseball has a mass of 0.15 kilograms, the force the machine exerts is newtons. Use F = ma, where  .

Answers

The acceleration of the baseball is:
[tex]a= \frac{v_f-v_i}{\Delta t} [/tex]
where [tex]v_f[/tex] and [tex]v_i[/tex] are the final and initial speed of the ball, and [tex]\Delta t[/tex] is the time interval in which the force acted.

Replacing the numbers, we get
[tex]a= \frac{30 m/s-0m/s}{0.5 s}=60 m/s^2 [/tex]
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:
[tex]F=ma=(0.15 kg)(60 m/s^2)=9 N[/tex]

Answer:

So F=ma

The acceleration of the baseball is:

where  and  are the final and initial speed of the ball, and  is the time interval in which the force acted.

Replacing the numbers, we get

And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:

Question 1 Unsaved
Most of the mass of the solar system is located in which of the following?

Question 1 options:

Earth


comets


sun


Jupiter

Answers

sun is the biggest mass in the ss

Answer:

The Sun

Explanation:

Did the test, k12

Joan is setting up an experiment in the lab to observe newton's second law of motion. she has a model car that has a mass of 45 kg, and it is accelerating at 7 m/s/s. she then increases the acceleration to 28 m/s/s. what happens to the force of the car?

Answers

The force of the car increases because it is proportional to the acceleration of the object (as stated in the second law). If the object accelerates then the force accelerates, if the acceleration decreases then the force decreases. Same for mass. The force of the car would have changed from 315 newtons of force to 1,260 newtons of force.

Answer:

4 times its original size

Explanation:

study island said so

In the following diagram, the voltage is 1.5 volts and the resistance is 6.0 ohms. Use Ohm's law to determine the current in the circuit.
A)0.25 amps
B)
4.0 amps
C)
6.0 amps
D)
9.0 amps                     
                                HELP ASAP on a test 

Answers

Voltage (v) = current (i) × resistance(r)
Solving for current (i):
[tex]i = \frac{v}{r} = \frac{1.5}{6} \\ i = 0.25 \: amps[/tex]
A) 0.25 amps

The current in the circuit from the voltage 1.5 V and the resistance 6 ohm is 0.25 ampere. Thus, option A is correct.

What is Ohm's law?

Ohm's law is defined as the current flow in the circuit is directly proportional to the applied voltage in the circuit. Ohm's law is applicable at a constant temperature.

V∝I, where V is the potential difference and I is the current. Ohm's law can also be defined as, V = IR, and R is the resistance of the circuit. The unit of current is ampere(A).

Resistance is defined as the obstruction in current flow and the unit of resistance is ohm(Ω). Resistance is inversely proportional to the current flow. Resistance increases with the decrease of current and vice-versa.

From the given,

Voltage(V) = 1.5 V

Resistance (R) = 6 Ω

Ohm's law, V = IR

V / R = I

I = 1.5 / 6

= 0.25 A

I = 0.25 ampere

Thus, the current flow in the circuit is 0.25 A. Hence, the ideal solution is option A.

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Which is a drawback of agricultural technology?

A. Better communication
B. Prevents disease
C. Water pollution
D. Kills bugs

Answers

I would say C. Water pollution because of the pesticides they use

If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 2 options: a) when it is at the top b) when it is getting near the top c) when it leaves your hand d) when it starts to fall back to your hand

Answers

Q1: At the highest point

In order to effectively radiate a radio signal, an antenna must be at least one-half the wavelength of transmission in length, i.e., minimum antenna height = 1/2(λ). WITY operates at a frequency of 980.0 kHz. What is the minimum height (m) of the antenna that WITY (nostalgia radio) must have?,

Answers

The equation that relates Wavelength & frequency of electromagnetic waves is : Velocity (c) = Wavelength (λ) * frequency (f) ------ (1) Electromagnetic wave velocity (c) = Speed of Light = 3 * 10^8 m/s From (1), Wavelength , λ = c / f λ= (3*10^8)/(980*10^3) λ = 306.12 m Minimum height of the antenna for effective transmission = λ * 0.5 = 306.12*0.5 Answer : 153 m (rounded off)

The wavelength of the is the distance of corresponding points between the two consecutive waves.

The minimum height (m) of the antenna that WITY (nostalgia radio) must have is 153.06 meters.

What is the wavelength?

The wavelength of the is the distance of corresponding points between the two consecutive waves.

It can be given as,

[tex]\lambda=\dfrac{c}{f}[/tex]

Here [tex]c[/tex] is the speed of light and [tex]f[/tex] is the frequency of the wave.

Given information-

The minimum height of the antenna is 1/2(λ).

The frequency on which the radio operates is 980.0 kHz.

As the speed of light is [tex]3\times 10^8\rm m/s[/tex]. Thus, find the value of wavelength using the above formula first,

[tex]\lambda=\dfrac{3\times 10^8\rm}{980\times10^3}\\\lambda=306.122\rm m[/tex]

Suppose the minimum height of the antenna is x meters. As the minimum height of the antenna is 1/2(λ). Thus,

[tex]x=\dfrac{1}{2} \times306.122\\x=153.06[/tex]

Hence, the minimum height (m) of the antenna that WITY (nostalgia radio) must have is 153.06 meters.

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Elements can be broken down through ____ processes.

A. Chemical processes, but not nuclear
B. only biological
C. both chemical and nuclear
D. Nuclear processes, but not chemical

Answers

The answer is D. Nuclear processes, but not chemical

Answer: I believe the answer is: Nuclear processes, but not chemical

Explanation:

Derek reads a rate of 25 words per min. How long would it take him to read a 225 work article if he read at a constant rate without stopping

Answers

Hello there! Your answer is (255/25=9) hope it helps and have a wonderful day!

A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The tension in the light horizontal rope connecting the wagons is.

help explain your answer,

Answers

The force will be zero if the wagons are moving at a constant speed (i.e. not accelerating), as there is no frictional force to overcome. If the wagons are accelerating, the force will be proportional to the acceleration, and 20% of the force applied by A.

What is absolute zero? A. Zero on the Celsius scale B. The point at which all motion stops C. Zero on the Fahrenheit scale D. 273 on the Kelvin scale

Answers

Absolute zero is B. the point at which all motion stops. This is equivalent to 0 Kelvin.
Final answer:

Absolute zero is the theoretical lowest temperature at which all molecular motion stops. It's equivalent to -273.15 degrees Celsius or 0 Kelvin.

Explanation:

Absolute zero refers to the lowest possible temperature that can be theoretically achieved. It represents the point at which all molecular motion is presumed to stop, which is choice B in your options. However, this doesn't mean that all forms of energy disappear at this temperature - quantum mechanics tells us that minimal vibrations persist even at this extreme. In practical terms, absolute zero is equivalent to -273.15 degrees Celsius, or 0 on the Kelvin scale (not 273 Kelvin as option D suggests). Neither 0 degrees on the Celsius scale (option A), nor 0 degrees on the Fahrenheit scale (option C), is equivalent to absolute zero.

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Halfway though a cross-country meet,a runner’s speed is 4m/s.In the last stretch,she increases her speed to 7m/s.What is her change in speed?

Answers

v0=4 m/s
v1=7 m/s

Change in speed: v1-v0=7-4=3 m/s

Answer:

The change in speed is 3m/s

Explanation:

The change is speed is defined as the difference between final and initial speed:

ΔV=[tex]V_{2}-V_{1}[/tex]

where V2 and V1 are the final and initial speeds, respectively.

Plugging in the values

ΔV=7m/s-4m/s=3m/s

Jamal does not produce enough insulin to regulate his blood sugar. What part of the endocrine system is most likely being affected??

A. Adrenal gland
B. Pancreas
C. Pituitary gland
D. Testes

Answers

B pancreas, since the pancreas secretes insulin.
B- the pancreas is the answer

A motorboat, whose speed in still water is 15 km/hour, traveled with the current of a river for 35 km, and against the current for 25 km. the boat took the same time traveling with the current as it did traveling against the current. what is the speed of the current in the river?

Answers

Let's call v=15 km/h the speed of the boat in still water, and c the speed of the current.
When the boat travels with the current, its total speed is (v+c), and it travels for a distance of 35 km in a time t. When the boat travels against the current, its total speed is (v-c), and it travels for a distance of 25 km in the same time t. We can write the basic relationship of the uniform linear motion [tex]S=vt[/tex] for both situations:
[tex]35 km = (v+c)t[/tex]
[tex]25 km=(v-c)t[/tex]
If we divide the first equation by the second one, we find
[tex] \frac{35}{25}= \frac{v+c}{v-c} [/tex]
and by rearranging this, we can find the value of c, the speed of the current:
[tex]c= \frac{1}{6}v= \frac{1}{6}(15 km/h)=2.5 km/h [/tex]

What is one way you can destroy a magnet’s magnetism? a. by putting it in water b. by cooling it c. by heating it d. by breaking it into pieces

Answers

By heating it up is the answer


the answer is C LOLOLO

Which of the following does the endocrine system regulate??

A. Hormones
B. Reflexes
C. Respiration
D. Senses

Answers

it's A. hormones that your answer

Answer: Your answer would be A Hormones

Hope this helped XD

What is the average power output of a weight lifter who can lift 260 kg from the floor to a height of 1.60 m in 1.7 seconds?

Answers

The power P is the amount of work W done in a certain amount of time t
[tex]P= \frac{W}{t} [/tex]
For the law of conservation of energy, the amount of work done by the lifter is equal to the difference in gravitational potential energy of the block of mass [tex]m=260 kg[/tex] between its final location (height h=1.60 m) and its initial location (the floor, h=0). This potential energy difference is 
[tex]\Delta U = mgh_f-mgh_0 =(260 kg)(9.81 m/s^2)(1.60 m)-0=4081 J[/tex]

And therefore, the average power output of the lifter, using [tex]t=1.7 s[/tex], is
[tex]P =\frac{W}{t}= \frac{4081 J}{1.7 s}=2400 W [/tex]

Is it accurate to describe the physical universe as composed of only matter and energy?
Plz explain , many thanks!

Answers

The universe is composed of roughly 71% dark energy, 24% dark matter, and 5% atoms. Dark matter is not fully understood, and is thought to be composed of one or more species of sub-atomic particles.

Peter and Paul both had a great influence on the early church. True False

Answers

I think answer should be False! Because Peter and Paul it doesn't had a great influence on their church.

Hope it helped!

Answer:

The answer would be TRUE

Peter and Paul did have a great influence on the early church.

In which situation would an object weigh the LEAST? (assume all the objects have the same mass) A) an object on Earth Eliminate B) an object on the moon C) an object half-way between the Earth and moon D) an object in space closer to the moon than the Earth

Answers


D)an object in space closer to the moon than the Earth

Answer: The correct answer is D.      

Explanation:

The object weigh less on the moon than Earth. The weight of the object on the moon is one sixth the weight of the object on the Earth.

Greater the mass of the object, greater will be the gravitational force. Then more will be the weight of the object. The mass of the moon is less than the mass of the earth. The object weigh less on the moon than Earth.

As you go away from the Earth's surface, the weight of the object will get reduce.

An object in space closer to the moon than the earth.

Therefore, an object in space closer to the moon than the Earth would weigh the least.

Which describes the movement of a fluid during convection?
A. Warm and cool fluids rise.
B. Warm and cool fluids sink.
C.Warm fluid rises and cool fluid sinks.
D.Warm fluid sinks and cool fluid rises.

Answers

Hello there!



The hotter molecules would then become expanded and then they would then be warm and cool, and then the fluids would then rise. When the fluids such as gas for example, when they are warm and then cool, they would then rise, and this would be an example of a movement of a fluid during convection.


I hope this helps you! :)



A. Warm and cool fluids rise. 


B. Warm and cool fluids sink. 


C.Warm fluid rises and cool fluid sinks. 


D.Warm fluid sinks and cool fluid rises.



I hope this helps you!

If you're taking the course on Edge, the answer is C.  

When the current is the same through all of the resistors and the batteries of a circuit, you have resistors in __.
A. parallel
B. series
C. both parallel and series
D. series and parallel circuits

Answers

its series cause parallel would be if one would be off and it will still be on. All of them are the same so its a series.

When the current is the same through all the resistors and the batteries of a circuit, you have resistors in series. Option B is correct.

What is series circuit?

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

Components linked in series share a single “electrical route,” and each component receives the same current, which is equal to the network's current.

When the current is the same through all the resistors and the batteries of a circuit, you have resistors in series.

Hence,option B is correct.

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the mass of a proton is 1.6726 * 10^-24 and the mass of a electron is 9.1093 * 10^-28. What is the difference between the mass of a proton and the mass of an electron?

Answers

Answer:

Its C

Explanation:

1.6735 × 10–27

You have been mining for gold and you have found a nugget and are about to be rich. The density of the gold is 19.3 grams/cubic centimeter or g/cc.
Your sample has a mass of 972 grams and is nearly a perfect cube, each side measuring 3 cm.
Find the the density of your sample (HINT: you must find the volume of the cube first).
After you've done this compare the given density of gold to your calculated value. Is your sample pure gold? EXPLAIN.

Answers

volume= 3^3= 27cm3
density= mass/volume
972/27 = 36g/cm3
the Desity of gold is it's property, and it's given as 19.3
but what we got is 36
so there is a change in density
which means that gold is not pure here.

A car with a mass of 1,500 kilograms is moving around a circular curve at a uniform velocity of 16 m/s. The curve has a radius of 100 meters. What's the centripetal force on the car?

Answers

Centripetal force can be computed using this formula.

[tex]f = \frac{mv^{2} }{r} [/tex]

where:
f= centripetal force
m = mass
v = velocity
r = radius

Everything you need is already and all you have to do is input it into your formula:
m = 1,500 kg
v = 16m/s
r = 100  m

[tex]f = \frac{(1,500kg)(16m/s)^{2} }{100m} [/tex]
[tex]f = \frac{1,500kg)(256m^{2}/s^{2}) }{100m} [/tex]
[tex]f = \frac{384,000kg.m^{2}/s^{2} }{100m} [/tex]
[tex]f = 3,840 kg.m/s^{2}[/tex] or [tex]f = 3,840 N[/tex]

The centripetal force in a circular motion is given by:
[tex]F_C = m \frac{v^2}{r} [/tex]
where m is the mass of the object, v its speed and r the radius of the circular path.
Using the data of this problem, m=1500 kg, v=16 m/s and r=100 m, and replacing them inside the formula, we find the value of the centripetal force:
[tex]F_C = (1500 kg) \frac{(16 m/s)^2}{100 m}=3840 N [/tex]

The cliff divers at acapulco, mexico, jump off a cliff 17.2 m above the ocean. ignoring air resistance, how fast are the divers going when they hit the water?

Answers

The divers are in free fall, and they cover a distance of [tex]S=17.2 m[/tex] in a uniformly accelerated motion, with an acceleration equal to [tex]g=9.81 m/s^2[/tex] (gravitational acceleration). We can find their final velocity vf just before hitting the water using the following relationship
[tex]2aS = v_f^2 -v_i^2[/tex]
where [tex]v_i=0[/tex] is their initial velocity, which is zero because the divers start from rest. Therefore, substituting the numbers we can find vf:
[tex]v_f = \sqrt{2aS}= \sqrt{2\cdot 9.81 m/s^2 \cdot 17.2 m}=18.4 m/s [/tex]
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