The molarity of the diluted barium hydroxide solution is approximately 0.5018 M.
The molarity of the diluted solution is calculated by using the formula for molarity (M), which is:
[tex]\[ M = \frac{\text{moles of solute (n)}}{\text{volume of solution (V)}} \][/tex]
When a solution is diluted, the number of moles of solute remains constant. Therefore, we can equate the moles of solute in the concentrated solution to the moles of solute in the diluted solution:
[tex]\[ n_{\text{concentrated}} = n_{\text{diluted}} \][/tex]
Given that the molarity (M) is the number of moles of solute per liter of solution, we can write:
[tex]\[ M_{\text{concentrated}} \times V_{\text{concentrated}} = M_{\text{diluted}} \times V_{\text{diluted}} \][/tex]
We are given:
- [tex]\( M_{\text{concentrated}} = 3.41 \)[/tex] M (molarity of the concentrated barium hydroxide solution)
- [tex]\( V_{\text{concentrated}} = 41.0 \)[/tex] ml (volume of the concentrated solution, which we will convert to liters)
- [tex]\( V_{\text{diluted}} = 279 \)[/tex] ml (volume of the diluted solution, which we will also convert to liters)
First, we convert the volumes from milliliters to liters:
[tex]\( V_{\text{concentrated}} = 41.0 \) ml \( = 41.0 \times 10^{-3} \) L\\ \( V_{\text{diluted}} = 279 \) ml \( = 279 \times 10^{-3} \) L[/tex]
Now we can solve for [tex]\( M_{\text{diluted}} \)[/tex]:
[tex]\[ M_{\text{diluted}} = \frac{M_{\text{concentrated}} \times V_{\text{concentrated}}}{V_{\text{diluted}}} \] \[ M_{\text{diluted}} = \frac{3.41 \times 41.0 \times 10^{-3}}{279 \times 10^{-3}} \] \[ M_{\text{diluted}} = \frac{3.41 \times 41.0}{279} \] \[ M_{\text{diluted}} = \frac{140.01}{279} \] \[ M_{\text{diluted}} \approx 0.5018 \text{ M} \][/tex]
A 75.0-ml volume of 0.200 m nh3 (kb=1.8×10−5) is titrated with 0.500 m hno3. calculate the ph after the addition of 19.0 ml of hno3. express your answer numerically.
From the equation kb = 1.8 x 10^-5
Therefore;
pKb = - log 1.8 x 10^-5 = 4.7
Moles NH3 in 75 ml = (75/1000) L x 0.200 M=0.0150
Moles HNO3 in 19 ml = (19/1000) L x 0.500 M= 0.0095
The net reaction is
NH3 + H+ = NH4+
Moles NH3 in excess = 0.0150 - 0.0095 =0.0055
Moles NH4+ formed = 0.0095
Total volume = 75.0 + 19.0 = 94.0 mL = 0.094 L
[NH3]= 0.0055/ 0.094 L=0.0585 M
[NH4+] = 0.0095/ 0.094 L = 0.1011M
pOH = pKb + log [NH4+]/ [NH3]
= 4.7 + log 0.1011/ 0.0585
= 4.938
pH = 14 - pOH
= 14 – 4.94
=9.06
pH after the addition of 19.0 ml of HNO₃ : 9.018
Further explanationThe pH value of a reaction between strong acid HNO₃ and weak base NH₃ can be estimated from the rest of the reaction product
1. If the remainder of the reaction results obtained the remaining strong acid HNO₃, the pH is sought from the concentration of [H⁺] using the formula
[H⁺] = a. M
a = valence of acid / amount of H⁺ released
M = acid concentration
2. When strong acids and weak bases react, they form salts that are acidic, calculating the pH using the pH hydrolysis formula
[tex]\displaystyle [H +]=\sqrt{\frac{Kw}{Kb}.M }[/tex]
where
M = concentration of salt anion
3. If the remainder of the reaction results are a weak base remaining and the salt, the solution will form a base buffer solution and search for pH using the formula base buffer pH
[tex]\displaystyle [OH-]=Kb\times\frac{weak\:base\:mole}{salt\:mole\times valence}[/tex]
We count the moles of each reactant:
NH₃ mole = 75 ml x 0.2 M = 15 mlmol
mole HNO₃ = 19 ml x 0.5 M = 9.5 mlmol
NH₃ + HNO₃ ---> NH₄NO₃
15 9.5
9.5 9.5 9.5
5.5 0 9.5
so there are remaining weak bases NH₃ = 15 - 9.5 = 5.5 mmol
Then a buffer solution is formed
[OH⁻] = Kb x [weak base mole] / [salt mole x valence]
[tex]\displaystyle [OH-]=1.8.10^{-5}\times\frac{5.5}{9.5\times 1}\\\\pOH=-log\:1.042.10^{-5}\\\\pOH=4.982\\\\pH=14-pOH\\\\pH=9.018[/tex]
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Keywords : pH, acid, base, HNO₃,NH₃
Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon
monoxide gas, CO?
a)the mass
b)the volume
c)the number of molecules
d)the number of oxygen atoms
Answer : The correct option is, (C)the number of molecules
Explanation :
When we are comparing 1 mole of oxygen gas [tex](O_2)[/tex] with 1 mole of carbon monoxide gas [tex](CO)[/tex] then we conclude that,
In 1 mole of oxygen gas [tex](O_2)[/tex], there are two number of molecules of oxygen.
In 1 mole of carbon monoxide gas [tex](CO)[/tex], there are two number of molecules (carbon and oxygen).
Hence, the number of molecules must be the same when comparing 1 mole of oxygen gas, with 1 mole of carbon monoxide gas.
Using a table that lists standard heats of formation, you can calculate the change in enthalpy for a given chemical reaction. the change in enthalpy is equal to _____. ∆hf0 of reactants minus ∆hf0 of products ∆hf0 of products plus ∆hf0 of reactants ∆hf0 of products divided by ∆hf0 of reactants ∆hf0 of products minus ∆hf0 of reactants
Answer:
∆hf0 of products minus ∆hf0 of reactants
Explanation:
23 POINTS PLZ HELP HURRY BEING TIMED FASTS ONE TO ANSWER GET BRAINLY!!
panda population are adopted to live in which kind of habitat/
A. Rain forest
B. Cherry Forest
C. Bamboo forest
D. Ginkgo forest
what is the name of LiNO3?
Lithium nitrate
Lithium (I) nitrogen
Lithium (I) nitrate
Lithium (I) nitride
As the oceans expand the gulf coast loses land area at what rate
Increase along the Gulf Coast and climate change at sea level. Warming ocean waters expand as temperatures rise, while mountain glaciers and inland ice melt.
What is climate ?Climate is a region's averaged long-term weather pattern over a period of time, usually 30 years. More precisely, it is the average and variation of climatic variables over a period of time that can range from a few months to many millions of years.
The average of the weather is the climate. As an illustration, you can anticipate snow in the Northeast in January or hot and muggy weather in the Southeast in July. Climate is this.
Nearly every element of our life is impacted by the climate, including our food supplies, transportation systems, clothing choices, and vacation destinations. It significantly affects our future, our health, and our means of subsistence. The long-term pattern of the weather in any given location is called the climate.
Thus, increase along the Gulf Coast and climate change at sea level.
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The Gulf Coast and similar regions are experiencing land loss due to sea level rise resulting from melting glaciers and ice sheets.
The loss of land area on the Gulf Coast as oceans expand is primarily a result of sea level rise and coastal erosion. As glaciers and ice sheets melt, including those in Greenland and West Antarctica, sea levels rise at an approximate rate of 3 millimeters per year, contributing to land loss along coastlines. The problem is exacerbated along the Atlantic coast by factors such as low elevations and subsiding land. The coastline from Florida to New York, for example, lost more land than it gained between 1996 and 2011, indicating a negative net change in land area.
Moreover, global assessments reveal that roughly 70% of the world's sandy shorelines are retreating, with a significant proportion of beaches eroding at rates that exceed 0.5 meters per year. Specifically, for every 361 gigatonnes per year of ice mass melting into the ocean, sea levels rise by approximately 1 millimeter. Glaciologists project that if current trends continue, we could see more than 1 meter of sea level rise by 2100, considering both melting land ice and thermal expansion of the ocean water.
A compound is 69.9% iron and 30.1% oxygen by mass. how much iron could by obtained from 5.41 grams of the compound?
Final answer:
To find the amount of iron that could be obtained from 5.41 grams of a compound that is 69.9% iron, multiply the mass of the compound by the percentage of iron (in decimal form) to get 3.78 grams of iron.
Explanation:
To determine how much iron can be obtained from 5.41 grams of the compound, we use the given percentage composition of iron in the compound, which is 69.9%. We can calculate the mass of iron in the given mass of the compound by multiplying the total mass of the compound by the percentage of iron in decimal form.
To find the mass of iron in 5.41 grams of the compound: (percentage of iron / 100) × total mass of compound = (69.9 / 100) × 5.41 grams = 3.78 grams
Therefore, 3.78 grams of iron could be obtained from 5.41 grams of the compound.
Which units represent destiny? Select all that apply.
A. cm3
B. g/m3
C. g/cm3
D. cm3/gm
E. kg/L
F. kg/cm3
G. mL/cm3
The percent composition by mass of nitrogen in NH4OH(gram formula mass= 35 grams/mole) is equal to which of the following? A.4/35×100. B.14/35×100 C.35/14×100 D.35/4×100
The correct option is B: 14/35 × 100.
To determine the percent composition by mass of nitrogen in NH₄OH, we need to use the molar mass of each constituent element and the total formula mass:
Molecular weight of Nitrogen (N): 14 g/molTotal molecular weight of NH₄OH: 35 g/molThe percent composition by mass of nitrogen is calculated as follows:(Mass of Nitrogen / Molar Mass of NH₄OH) × 100
Using the given values:
(14 g/mol / 35 g/mol) × 100 = 40%
Thus, the correct option is B: 14/35 × 100.
How can both a celsius scale thermometer and a kelvin scale thermometer indicate the same temperature change but not the same final temperature reading?
Which liquid has the highest viscosity?
water
acetone
oil
salt water
Explain how an increase in the amount of dissolved co2 in ocean water results in a decrease in the ph of ocean water.
An increase in dissolved CO₂ in ocean water results in an increase in acidity (decrease in pH) of the water. This is due to the formation of carbonic acid that dissociates into hydrogen ions. This process has adverse effects on marine life, particularly animals such as corals and shellfish that rely on calcification to build their shells and skeletons.
Explanation:When carbon dioxide (CO₂) dissolves in the ocean water, it reacts with water to form a weak acid called carbonic acid. This acid then dissociates to form hydrogen ions (H+) and bicarbonate ions (HCO3-). Increased concentration of these hydrogen ions decreases the pH of the water, thus increasing its acidity.
Ocean acidification is detrimental to many marine organisms, especially corals and shellfish. This is because more acidic water interferes with the process of calcification, which they use to build their calcium carbonate shells and skeletons.
The increasing levels of atmospheric CO₂ and rising ocean temperatures are contributing to the acidity of ocean waters, causing harm to marine animals and ecosystems in the process.
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How many resonance structures does NH3 have?
I believe that there are none, but I would like some confirmation...
how many grams of silver chloride (AgCI) can be produced if you start with 4.62 grams of barium chloride (BaCI2)
The chemical equation representing the reaction of silver nitrate with barium chloride:
[tex] 2AgNO_{3}(aq) + BaCl_{2}(aq)--> 2AgCl (s) + Ba(NO_{3})_{2}(aq) [/tex]
Given mass of barium chloride = 4.62 g
Moles of [tex] BaCl_{2} = 4.62 g BaCl_{2}*\frac{1 mol BaCl_{2}}{208.23 g BaCl_{2}} = 0.0222 mol BaCl_{2} [/tex]
Moles of AgCl = [tex] 0.0222 mol BaCl_{2} * \frac{2 mol AgCl}{1 mol BaCl_{2}} [/tex] = 0.0444 mol AgCl
Mass of AgCl = [tex] 0.0444 mol AgCl * \frac{143.32 g AgCl}{1 mol AgCl} = 6.36 g AgCl [/tex]
If you expose a photosynthesizing plant to water that contains both radioactive h and radioactive o, in which of the products of photosynthesis will the radioactive h and o show up? if you expose a photosynthesizing plant to water that contains both radioactive h and radioactive o, in which of the products of photosynthesis will the radioactive h and o show up? h in glucose and water; o in o2 h in glucose; o in water h in water; o in glucose h and o both in glucose
Radioactive hydrogen will be found in glucose, and radioactive oxygen will be found in the oxygen gas produced during photosynthesis.
In photosynthesis, water (H₂O) is split into hydrogen (H) and oxygen (O₂) by the energy from sunlight. When you expose a photosynthesizing plant to water that contains both radioactive hydrogen (³H) and radioactive oxygen (¹⁸O), these elements will be incorporated into the products of photosynthesis in specific ways. The radioactive hydrogen (³H) will be found in glucose (C₆H₁₂O₆) as hydrogen atoms are part of the glucose molecule. The radioactive oxygen (¹⁸O) will be found in the molecular oxygen (O₂) released as a byproduct.
Thus, if you supply a plant with radioactive water, the radioactive H will show up in glucose, while the radioactive O will show up in the oxygen gas produced during photosynthesis.
Which of the following is the most acidic: HBrO3, HFO3, HIO3, and HClO3?
The acidity of the given compounds is determined by how readily they donate H+ ions. By considering their respective positions on the periodic table, it can be inferred that HIO3, iodic acid, is the most acidic as it disperses the resultant negative charge over the largest volume.
Explanation:The acidity of these chemicals is determined by the strength of the acid, which is determined by the degree to which the acid dissociates in water. In this case, we are looking at a series of oxyacids where the central atom is a halogen: HBrO3 (bromic acid), HClO3 (chloric acid), HFO3 (fluoric acid/supposed to be HF which is hydrofluoric acid), and HIO3 (iodic acid).
Bromic acid, HBrO3, can donate a BrO3- ion and 1 H+ ion, which makes it an acid. Similarly, Chloric acid, HClO3, donates a ClO3- ion and 1 H+ ion. Hydrofluoric acid, HF can donate F- and H+ ions, and Iodic acid, HIO3, donates IO3- and H+ ions.
By noting the position of the halogens on the periodic table, we see that iodine is further down the halogen group than the others. As you go down the group in the periodic table, the atomic radius increases. As such, the resulting negative charge on the larger ions is dispersed over a larger volume, and the acidic strength increases. Because of these, HIO3, iodic acid, is the most acidic of the acids provided.
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if you multiply an objects weight times it height, what value do you compute?
This is for a study guide, I can't figure it out!
You draw back on the piston of a pump and the volume of air in the pump doubles. Which of the following happens?
a. The number of collisions per unit area doubles.
b. The temperature of the room doubles.
c. Half of the gas leaks out and the pressure is reduced.
d. The number of collisions per unit area is reduced by one-half.,
Final answer:
Option d is the correct answer. If the volume of air in a pump doubles with temperature remaining constant, according to Boyle's Law, the pressure is halved which means the number of collisions per unit area is reduced by half.
Explanation:
When you draw back on the piston of a pump, causing the volume of air to double, and temperature remains constant, Boyle's Law applies here. Boyle's Law states that the pressure of a gas is inversely proportional to its volume, when temperature and the number of molecules are constant. Hence, when the volume doubles, the pressure is halved. This means that the number of collisions per unit area of the gas molecules against the walls of the piston is reduced by half because there is now twice the space for the gas molecules to move around in.
Considering the given options, the correct answer to what happens when the volume of air in the pump doubles is d. The number of collisions per unit area is reduced by one-half., given that temperature and the number of gas molecules remain constant.
What is element 115, where did it came from, and what is it used for?
please help!!
The concentration of sodium hydroxide is 1.0 M and the concentration of crystal violet is 1.00E-5 M. identify the limiting reagent and calculate how much of the excess reagent remains after the reaction runs to completion.,
In a chemical reaction, the limiting reagent is the chemical being used up while the excess reactant is the chemical left after the reaction process.
Before calculating the limiting and excess reactant, it is important to balance the equation first by stoichiometry.
C25N3H30Cl + NaOH = C25N3H30OH + NaCl
Since the reaction is already balanced, we can now identify which is the limiting and excess reagent.
First, we need to determine the number of moles of each chemical in the equation. This is crucial for determining the limiting and excess reagent.
Assuming that there is the same amount of solution X for each reactant
1.0 M NaOH ( X ) = 1.0 moles NaOH
1.00 x 10-5 M C25N3H30Cl ( X ) = 1.00 x 10-5 moles C25N3H30Cl
The result showed that the crystal violet has lesser amount than NaOH. Thus, the limiting reactant in this chemical reaction is crystal violet and the excess reactant is NaOH.
To identify the limiting reagent between sodium hydroxide and crystal violet, normally one would need the reaction equation and stoichiometry. Assuming a hypothetical 1:1 reaction, crystal violet would be the limiting reagent due to its much lower concentration compared to NaOH.
Explanation:The question asks to identify the limiting reagent in a reaction between sodium hydroxide and crystal violet and calculate the amount of excess reagent remaining after the reaction is complete. Since the concentration of sodium hydroxide (NaOH) is 1.0 M and the concentration of crystal violet is 1.00E-5 M, we do not have the actual reaction equation or the stoichiometry to determine the limiting reagent directly. Normally, the limiting reagent is the one that will be completely consumed first during the reaction, based on the stoichiometry of the reaction. Typically, the number of moles of each reagent would be considered; the one with the fewer moles, per the reaction stoichiometry, would be the limiting reagent.
As an example, if the reaction were 1:1, then clearly crystal violet would be the limiting reagent due to its much lower concentration. To find out how much NaOH remains, we would subtract the moles of NaOH that reacted with crystal violet from the initial moles of NaOH. However, in absence of the reaction equation and assuming a hypothetical 1:1 reaction, all of the crystal violet would react, leaving behind an excess of NaOH. If we had information on the volumes used, we could calculate the actual amount of NaOH remaining using dimensional analysis as demonstrated by various examples provided.
The model below shows an atom of an element.
What is the atomic number of this atom?
6
8
9
16
The atomic number of the atom represent by the model is
8 (answer B)
Explanation.
The atomic number of atom is 8 because the model below has a total number of 8 electrons.
that is; 2 electrons in the inner energy level and 6 electrons in the outermost energy level which make a total of 2+6= 8 electrons
Answer: The the atomic number of this atom is 8.
Explanation: The particles with zero charge represents neutrons, The particles with negative charge represents electrons and the particles with positive charge represents protons.
The number of particles with negative charge are eight in number, thus there are eight electrons. The number of particles with positive charge are eight in number, thus there are eight protons. Thus it is a neutral atom.
The number of electrons represent the atomic number for a neutral atom. Thus the element has atomic number of 8.
The percent composition of methyl butanoate is 58.8% C, 9.8% H, and 31.4 % O and its molar mass is 102 g/mol. What is its empirical formula? What is its molecular formula? @mayankdevnani,
Given:
C= 58.8% ,
H= 9.8% ,
and O=31.4 %
molar mass is = 102 g/mol.
empirical formula=
58.8/C(12.01)= 4.9
9.8/H(1.01)= 9.7
31.4/O(15.99)= 1.96
divide it by the least value so it is 1.96 which shows,
4.9/1.96= 2.5
9.7/1.96= 5
(C2.5H₅O)₂= C₅H₁₀O₂
molecular formula= C₁₀H₂₀O₄
order these units from smallest to largest:cm,um,km,mm,m,nm,dm,pm. then give each a measurement in terms of meters.
A compound containing nitrogen and oxygen is decomposed in the laboratory and produces 1.78 g of nitrogen and 4.05 g of oxygen, calculate empirical formula
The empirical formula for the compound decomposed in the laboratory which resulted in 1.78 g of Nitrogen and 4.05 g of Oxygen can be calculated by finding the moles of each element and comparing ratios. Based on the calculation, the empirical formula for the compound is NO2.
Explanation:First, we determine the number of moles of each element involved in the compound. Recall the atomic weight of Nitrogen (N) is about 14 g/mol and Oxygen (O) is about 16 g/mol.
The given weight of Nitrogen is 1.78 g. So, divide this by the atomic weight to get the number of moles: 1.78 g N / 14 g/mol = 0.127 moles of Nitrogen. Similarly for Oxygen, we have 4.05 g so: 4.05 g O / 16 g/mol = 0.253 moles of Oxygen.
To find the empirical formula, we divide each of these by the smallest number of moles, which is for Nitrogen: 0.127/0.127 = 1 for Nitrogen, and 0.253/0.127 = 2 for Oxygen. Hence, the empirical formula for the compound is N1O2 or simply NO2.
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The empirical formula of the compound is N1O2.
Explanation:To determine the empirical formula of the compound, we need to find the ratio of nitrogen to oxygen. The given data states that 1.78 g of nitrogen and 4.05 g of oxygen were produced. First, convert the mass of each element to moles using their molar masses. The molar mass of nitrogen is 14 g/mol, so 1.78 g of nitrogen is equal to 0.127 moles. The molar mass of oxygen is 16 g/mol, so 4.05 g of oxygen is equal to 0.253 moles. Next, divide each mole value by the smallest mole value to get the mole ratio. In this case, the ratio is approximately 1:2. Therefore, the empirical formula of the compound is N1O2.
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Given the data in the table below, δh°rxn for the reaction ag2o (s) + h2s (g) → ag2s (s) + h2o (l) is ________ kj. substance δh∘f(kj/mol) ag2o (s) -31.0 ag2s (s) -32.6 h2s (g) -20.6 h2o (l) -286
The half-life of tritium, or hydrogen-3, is 12.32 years. After about 37 years, how much of a sample of tritium will remain unchanged?
A)1/8 B)1/4 C)1/3 D)1/2
The correct option is A) 1/8
half-life of tritium, or hydrogen-3, is 12.32 years.
After about 37 years,
= 37/12.32
= 3
means 3 half lives.
sample of tritium that will remain unchanged will be:
= 1/2^no.of half lives
= 1/2³
= 1/2 x 1/2 x 1/2 = 1/8
1/8 remains back
If you can smell your grandmother’s perfume from across the room, you are experiencing the result of which liquid property?
viscosity
surface tension
cleavage planes
volatility
How does chromium oxide improve the properties of stainless steel?
Final answer:
Chromium oxide enhances stainless steel by forming a protective passivating layer that inhibits corrosion and increases the alloy's durability. Chromium contributes its corrosion resistance to stainless steel, ensuring long-lasting quality and protection against environmental elements.
Explanation:
Chromium oxide plays a crucial role in improving the properties of stainless steel. By alloying the iron with chromium, stainless steel gains significant resistance to corrosion. This is largely due to the chromium tending to migrate towards the surface, where it reacts with oxygen to form a passivating chromium oxide layer.
This oxide layer protects the iron from further corrosion, enhancing the durability and longevity of the stainless steel.
While pure chromium does not readily corrode, it bestows its resistive properties upon steel when used as an alloy. The created oxide layer is thin but very protective, acting as a barrier that blocks moisture, air, and other corrosive agents from reaching the iron.
In different environmental conditions, chromium can exist in several oxidation states, such as Cr(III) and Cr(VI). Cr(III) is relatively insoluble in water and low in toxicity, while Cr(VI) is considerably more toxic and soluble in water.
However, in stainless steel, chromium's positive contributions in the form of its corrosion resistance make it a valuable element for maintaining the material's quality and safety.
How do I balance this equation:
__HNO3+ __Mg(OH)2 —> __Mg(NO3)2 + __H2O
#1: When you squeeze an air-filled balloon, what happens inside?
A. There are more collisions of air molecules against the wall of the balloon.
B. There are fewer collisions of air molecules against the wall of the balloon.
C. There is no change in the number of collisions of air molecules against the wall of the balloon.
D. The temperature inside the balloon decreases.
**my answer: A
is that right? not too sure haha @aaronq :)
When you squeeze an air-filled balloon, there are fewer collisions of air molecules against the wall of the balloon.
Explanation:When you squeeze an air-filled balloon, there are fewer collisions of air molecules against the wall of the balloon.
When pressure is applied to the balloon by squeezing it, the volume of the balloon decreases. As a result, the air molecules inside become more crowded, reducing the number of collisions with the balloon wall.
So, the correct answer is B. There are fewer collisions of air molecules against the wall of the balloon.
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When you squeeze an air-filled balloon, you reduce the volume for the air molecules which results in more frequent collisions against the interior of the balloon.
Explanation:Yes, your answer is correct. When you squeeze an air-filled balloon, you are effectively reducing the volume available for the air molecules inside it. As a result, there will be a noticeable increase in the number of collisions the air molecules have against the wall of the balloon (option A). This is concisely explained by the kinetic theory of gases, which states that gases consist of a large number of molecules that are in constant, random motion. So, under compression, the space for these random movements is limited, and therefore, they collide more frequently with the balloon's interior.
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