A 500.0 g sample of Al2(SO4)3 is reacted with 450.0 g of Ca(OH)2. A total of 596 g of CaSO4 is produced. What is the limiting reagent in this reaction, and how many moles of excess reagent are unreacted? Al2(SO4)3(aq) + 3Ca(OH)2(aq) -> 2Al(OH)3(s) + 3CaSO4(s)

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

Answer:

0.011437L

Explanation:

In the question, we are told that under a pressure of 680mmHg, chlorine gas occupies a volume of 20.352mL and then the pressure is changed to 1210mmHg at constant temperature.

Boyle's law states that the volume of a fixed mass of gas is directly proportional to the pressure of the gas at constant temperature.

Mathematically;

P1V1=P2V2

P1= initial pressure

V1= initial volume

P2= final pressure

V2= final volume

We will apply Boyle's law to get the new volume.

From, the relationship P1V1=P2V2

We make V2 subject of formula

V2= (P1V1)/P2

Given;

P1=680mmHg

V1=20.352mL= 20.352/1000L= 0.020352L

P2=1210mmHg

V2=(680×0.020352)/1210

V2=0.011437L

Answer:

Solute is Lithium nitrate, and solvent is water.

Explanation:

Lithium nitrate is trigonal crystal which is soluble in water.

Answer:

N₂ = 0.7515atm

O₂ = 0.1715atm

NO = 0.0770atm

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g)

Where Kp is defined as:

[tex]Kp = \frac{P_{NO}^2}{P_{N_2}P_{O_2}}}[/tex]

Pressures in equilibrium are:

N₂ = 0.790atm - X

O₂ = 0.210atm - X

NO = 2X

Replacing in Kp:

0.0460 = [2X]² / [0.790atm - X] [0.210atm - X]

0.0460 = 4X² / 0.1659 - X + X²

0.0460X² - 0.0460X + 7.6314x10⁻³ = 4X²

-3.954X² - 0.0460X + 7.6314x10⁻³ = 0

Solving for X:

X = - 0.050 → False answer. There is no negative concentrations.

X = 0.0385 atm → Right answer.

Replacing for pressures in equilibrium:

N₂ = 0.790atm - X = 0.7515atm

O₂ = 0.210atm - X = 0.1715atm

NO = 2X = 0.0770atm

Answer:

partial pressure N2 =  0.7515 atm

partial pressure O2 =  0.1715 atm

partial pressure NO =  0.077 atm

Explanation:

Step 1: Data given

Temperature = 2200 °C

Pressure of N2 = 0.790 atm

Pressure of O2 = 0.210 atm

Kp = 0.0460

Step 2: The balanced equation

N2(g) + O2(g) ⇆ 2NO(g)

Step 3: The pressure at equilibrium

pN2 = 0.790 - X atm

pO2 = 0.210 - X atm

pNO = 2X

Step 4: Define Kp and the partial pressures

Kp = (pNO)² / (pO2 * pN2)

0.0460 = 4X² / (0.210 - X)(0.790 - X)

X = 0.0385

pN2 = 0.790 - 0.0385 =  0.7515 atm

pO2 = 0.210 - 0.0385 = 0.1715 atm

pNO = 2*0.0385 = 0.077 atm

Answer:

D All of these

Explanation:

hope this helped

The equilibrium constant for the decomposition of water is approximately 1.01 × 10^-13.

The equilibrium constant (Kc) for the decomposition of water can be calculated using the equation: Kc = [H2]2[O2]/[H2O]2.

Given that ΔG°f(H2O(l)) = -237.2 kJ/mol, we can use the equation ΔG° = -RTlnK to find the equilibrium constant. R is the ideal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin (25 °C + 273.15 = 298.15 K). Plugging in the values, we can solve for K.

ΔG° = -RTlnK

-237.2 kJ/mol = -(8.314 J/(mol·K) × 298.15 K) × lnK

lnK = -237.2 kJ/mol ÷ (8.314 J/(mol·K) × 298.15 K)

lnK ≈ -29.155

K ≈ e-29.155

K ≈ 1.01 × 10-13

Therefore, the equilibrium constant for the decomposition of water at 25 °C is approximately 1.01 × 10-13.

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Final answer:

When the volume of a chamber containing CH₄ increased from 7.00L to 8.20L, 0.260 moles of CH₄ were added, assuming constant temperature and pressure.

Explanation:

To determine how many moles of CH₄ (methane) were added when the volume of the chamber increased from 7.00L to 8.20L, we can use the molar volume concept under the assumption that temperature and pressure remain constant, therefore following Avogadro's Law. According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of moles. You can calculate the number of moles in the new volume by setting up a proportion based on the known conditions (3.00 L contains 0.650 moles) and then solving for the number of moles in the new volume of 8.20 L.

First, determine the number of moles in the 7.00 L chamber:

moles in 3.00 L / 3.00 L = moles in 7.00 L / 7.00 L

0.650 moles / 3.00 L = x moles / 7.00 L

x = (0.650 moles / 3.00 L) × 7.00 L

x = 1.517 moles in 7.00 L

Now, calculate the number of moles in the increased volume of 8.20 L:

moles in 3.00 L / 3.00 L = moles in 8.20 L / 8.20 L

0.650 moles / 3.00 L = y moles / 8.20 L

y = (0.650 moles / 3.00 L) × 8.20 L

y = 1.777 moles in 8.20 L

The number of moles added is the difference between the moles in 8.20 L and the moles in 7.00 L:

moles added = 1.777 moles - 1.517 moles

moles added = 0.260 moles

Therefore, when the volume of the CH₄ chamber increased from 7.00L to 8.20L, 0.260 moles of CH₄ were added.

Answer:

The pressure of the solution is 144 torr

Explanation:

Step 1: Data given

Number of moles of a nonvolatile solute = 0.5 moles

Mass of ethanol = 300 grams

Molar mass of ethanol = 46.07 g/mol

Temperature = 40°C

The vapor pressure of ethanol = 134 torr

Step 2: Calculate moles ethanol

Moles ethanol = mass ethanol / molar mass ethanol

Moles ethanol = 300 grams / 46.07 g/mol

Moles ethanol = 6.51 moles

Step 3: Calculate the total moles

Total moles = 0.5 moles + 6.51 moles

Total moles = 7.01 moles

Step 4: Calculate mol fraction

Mol fraction = moles / total moles

Mol fraction ethanol = 6.51 / 7.01 moles

Mol fraction ethanol = 0.93

Mol fraction nonvolatile solute

0.5 moles / 7.01 moles = 0.07

Step 5: Calculate Total pressure of the solution

Vapor pressure ethanol = mol fraction * total pressure solution

134 torr = 0.93 * total pressure solution

Total pressure solution = 134 torr/ 0.93

Total pressure solution = 144 torr

The pressure of the solution is 144 torr

Final answer:

Nuclear fusion is a reaction in which two nuclei combine to form a larger nucleus, releasing energy. It is the process that powers the sun and stars.

Explanation:

Nuclear fusion is a reaction in which two nuclei are combined to form a larger nucleus, releasing energy. It is the process that powers the sun and other stars. In the sun, hydrogen nuclei combine to form helium, releasing a significant amount of energy.

Answer:

11.4 moles of H₂SO₄ are needed to completely react the 7.6 moles of Al

Explanation:

The equation indicates that 2 moles of aluminum react to 3 moles of sulfuric acid in order to produce 1 mol of aluminum sulfate and 3 moles of hydrogen gas.

The reaction is:  2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

This question can be solved with an easy rule of three. Ratio in the reaciton is 2:3, so we propose:

2 moles of Al react with 3 moles of sulfuric acid

Then, 7.6 moles of Al will react with 11.4 moles of H₂SO₄

Option B is correct. The statement that describes all solids is that they have a definite shape and volume

States of matter are one of the ways in which matter exists. Matter can exist as a solid, liquid, gas, and plasma.

The states of matter have different characteristics. Some of the properties of solids are:

The liquid contains loosely packed atoms eliminating the first option. Based on the explanations above, we can conclude that solids have a definite shape and volume.

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To determine the Ksp of Ag2CrO4 at 25 °C, you would first need to determine the standard reduction potentials and use the free energy equation ∆G° = -nFE°. Next, use the relationship between the equilibrium constant and ∆G° given by ∆G° = -RT ln Ksp to find the Ksp. However, without the necessary information, a precise value cannot be given.

To find the solubility product constant (Ksp) of Ag2CrO4 at 25 °C given the provided standard reduction potentials, we would need to look at the relationship between the equilibrium constant, K, and ∆G° (standard free energy). The equation ∆G° = -RT ln K is used in these cases, where R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant that we're interested in. Note that in order to use this equation, we first need to calculate ∆G° using the given reduction potentials and the equation ∆G° = -nFE°, where n is the number of electrons transferred, F is Faraday's constant, and E° is the standard reduction potential.

For example, if the ∆G° for the reaction came out to be around 167.9 kJ as per the details provided, and we can use ∆G° = -RT ln Ksp to find the Ksp. However, without the complete standard reduction potentials, a precise Ksp value for Ag2CrO4 at 25 °C cannot be provided here.

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Answer:hope we can be friends

can i please get brainliest

Although phlorizin inhibition of Na+-glucose cotransport occurs within a few seconds, 3H-phlorizin binding to the sodium-coupled glucose transport protein(s) requires several minutes to reach equilibrium (the fast-acting slow-binding paradigm). Using kinetic models of arbitrary dimension that can be reduced to a two-state diagram according to Cha’s formalism, we show that three basic mechanisms of inhibitor binding can be identified whereby the inhibitor binding step either (A) represents, (B) precedes, or (C) follows the rate-limiting step in a binding reaction. We demonstrate that each of mechanisms A–C is associated with a set of unique kinetic properties, and that the time scale over which one may expect to observe mechanism C is conditioned by the turnover number of the catalytic cycle. In contrast, mechanisms A and B may be relevant to either fast-acting or slow-binding inhibitors.

Explanation:

Answer:

2

Explanation:

well since the question has given you the concentration of the solution 0.2mol/L and the wanted amount (moles) of naoh(0.4mol) you are able put this into the formula n=cV; where n is the moles of naoh the solution, c is the concentraton of the solution and V is the volume of the solution in litres.

therefore the for the solution to have 0.4 moles of naoh you put it into the formula, giving you:

0.4 = 0.2V

V = 2

V = 2 litres

Final answer:

To obtain 0.4 moles of NaOH from a 0.2 M NaOH solution, you would need to measure out 2 liters of the solution.

Explanation:

To calculate the volume of a 0.2 M NaOH solution needed to have 0.4 moles of NaOH, we can use the molarity equation, which is:

Molarity (M) = Moles of solute / Volume of solution in liters (L)

We can rearrange this equation to solve for the volume:

Volume of solution (L) = Moles of solute / Molarity (M)

Substituting the given values:

Volume of solution (L) = 0.4 moles NaOH / 0.2 M NaOH

Volume of solution (L) = 2 liters

Therefore, you would need 2 liters of a 0.2 M NaOH solution to have 0.4 moles of NaOH.

Answer: Mrs. Salge can make 6 ice cream cones

Explanation:

Mrs. Salge's recipe:

1 cone

1 scoop blue ice cream

2 scoops red ice cream

1 cherry

Now we will find what the limiting ingredient is:

We know she has:

10 cones.    →    10 ice cream cones

12 scoops blue ice cream.    →    12 ice cream cones

12 scoops red ice cream.    →    6 ice cream cones

10 cherries.    →    10 ice cream cones

The red ice cream is the limiting factor. Mrs. Salge can make 6 ice cream cones.

Mrs. Salge can make a total of 6 ice cream cones with her available ingredients, as the red ice cream scoops are the limiting factor.

To determine how many ice cream cones Mrs. Salge can make given her resources, we must find out which ingredient limits the number of cones she can make. Her recipe requires one cone, one scoop of blue ice cream, two scoops of red ice cream, and one cherry for each ice cream cone. Therefore, we will check each ingredient to see which will run out first if she keeps making the ice cream cones as per the recipe.

Since each cone requires 2 scoops of red ice cream, the number of cones she can make will be limited by the red ice cream. With 12 scoops of red ice cream, she can make 6 cones because each cone requires 2 scoops. This is the limiting factor because even though she has 10 cones and 10 cherries, after making 6 cones, she will run out of red ice cream.

Therefore, Mrs. Salge can make a total of 6 ice cream cones with the ingredients available to her before one of the ingredients runs out and prevents her from making more.

Answer:

D

Explanation:

well, just need to remember

Answer:

Catalyst decreases activation energy

Explanation:

Consider the attached diagram and note the annotation => top of transition diagram for catalyzed reaction is lower than uncatalyzed reaction.

Answer:

False

Explanation:

Genes are found inside chromosomes and chromosomes are in cells. So technically genes are in cells

Answer:

12 moles Pb(NO₄)₂ needed.

Explanation:

                3Pb(NO₃)₂ +2AlCl₃     => 3PbCl₂ + 2Al(NO₃)₃

Given =>   ? moles      8 moles

from reaction stoichiometry, 2 moles AlCl₃ requires 3 moles Pb(NO₄)₂ then 8 moles AlCl₃ requires 3/2(8) moles of the Pb(NO₄)₂ => 12 moles Pb(NO₄)₂ needed.

Answer:

17.08 moles of manganese dioxide

Explanation:

From the balanced reaction equation;

Zn + 2 MnO2 + 1 H2O → Zn(OH)2 + Mn2O3 (notice that I did not put 1 as a stoichiometric coefficient. It is expected that any specie written without a coefficient should have a coefficient of 1)

It is clear from the reaction equation that 2 moles of manganese dioxide produced 1 mole of zinc II hydroxide

Hence x moles of manganese dioxide will produce 8.54 moles of zinc II hydroxide

x= 2× 8.54/1

x= 17.08 moles of manganese dioxide

Answer:

IPM is also known as Integrated Pest management.

IPM is an ecosystem-based strategy that deals with long-term prevention of pests or their damage through a combination of techniques such as biological control, habitat manipulation, modification of cultural practices, and use of resistant varieties.

These factors are very important in protecting the environment and it prevents some crops and animals from going into extinction.

The process of IPM involves prevention, monitoring and intervening as an environmental solution.

IPM stands for 'Integrated Pest management', it is an  ecosystem-based strategy.

IPM works on three main aspects and that are:

Hence, the process of IPM raised out as an environmental solution.

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Final answer:

From 5.0 grams of silver nitrate reacting with barium chloride, 4.21 grams of silver chloride are produced. The exact amount of barium chloride is not calculated because it is in excess.

Explanation:

To determine how many grams of silver chloride are produced from the reaction of 5.0g of silver nitrate (AgNO3) with an excess of barium chloride (BaCl2), we use the stoichiometry of the balanced chemical equation. The balanced equation is:

AgNO3 (aq) + BaCl2 (aq) → AgCl (s) + Ba(NO3)2 (aq)

To calculate the mol product, we follow the equation:

(mol product) = (mol reactant) × (stoichiometric mole ratio)

For AgNO3 with a molar mass of 169.88 g/mol, we calculate the moles of reactant:

moles of AgNO3 = mass of AgNO3 / molar mass of AgNO3

= 5.0 g / 169.88 g/mol

= 0.0294 moles of AgNO3

For silver chloride (AgCl) with a molar mass of 143.32 g/mol, we calculate the mass of AgCl produced:

mass of AgCl = moles of AgCl x molar mass of AgCl

= 0.0294 moles × 143.32 g/mol

= 4.2094 grams of AgCl (rounded to 4.21 grams)

Regarding the amount of barium chloride needed, since it is in excess and not limiting the reaction, the exact amount needed is not calculated. However, if one wanted to calculate it, we would use the stoichiometry of the reaction based on the amount of silver nitrate, ensuring that barium chloride is in excess.

Answer:

D is the answer

Explanation:

I'm pretty sure a molecular compound doesn't form between 2 non metals

...I think, but I can't remember

The incorrect statement is that in an ionic compound, a metal and a polyatomic ion form a compound, and electrons are shared. In ionic compounds, electrons are transferred, not shared, resulting in the formation of cations and anions.

The statement that is NOT correct is: b) In an ionic compound, a metal and a polyatomic ion form a compound, and electrons are shared. This statement is incorrect because in an ionic compound, electrons are not shared but are transferred from the metal to the non-metal or to the polyatomic ion, forming cations and anions.

In ionic compounds, metals lose valence electrons to form positively charged ions, while nonmetals gain those electrons to form negatively charged ions, both achieving a full outer shell as per the octet rule. Covalent compounds, on the other hand, form when non-metals share electrons, producing molecular compounds.

Therefore, the correct statements are:

a) In an ionic compound, a metal and a non-metal form a compound, and electrons are transferred from one to the other.

c) In both ionic and molecular compounds, valence electrons take part in bonding.

d) In a molecular compound, a non-metal and a non-metal form a compound, and electrons are shared.

Answer:

A white light is apparently colourless light, for example ordinary daylight. It contains all the wavelengths of the visible spectrum at equal intensity.

Answer:

White Light is a light having a mixture of frequencies, being perceived as having no specific colour; such as sunlight.

Explanation:

The compound MnCL2 called

Manganese cloride

Answer:

Explanation:

Cloruro de manganeso

Answer:

There are 40 electrons in one atom of Zirconium.

Explanation:

Note: The word is not zicronium, it is Zirconium.

Answer:

Name Zirconium

Atomic Mass 91.224 atomic mass units

Number of Protons 40

Number of Neutrons 51

Number of Electrons 40

Explanation:

Answer:

Limiting reactant is H2.

Excess reactant is O2.

Maximum 5.6 mol of H2O can be produced.

Explanation:

                               2H2 + O2 ----> 2 H2O

from reaction         2 mol   1 mol    

given                    5.6mol   4.7mol

calculated            5.6mol   2.8 mol

We can see that  for 5.6 mol H2 only 2.8 mol O2 needed, but we have 4.7 mol O2 given, so we have excess of O2.

Then limiting reactant is H2.

Excess reactant is O2.

                               2H2 + O2 ----> 2 H2O

from reaction         2 mol                2 mol

given                      5.6 mol             x mol = 5.6 mol

Final answer:

The maximum number of moles of H₂O that can be produced from 5.6 mol H₂ and 4.7 mol O₂ is 5.6 mol H₂O, with hydrogen (H₂) as the limiting reactant and oxygen (O₂) as the excess reactant.

Explanation:

To answer the question of the maximum number of moles of H₂O that can be produced from the reaction of 5.6 mol H₂ and 4.7 mol O₂, we must first look at the balanced chemical equation for the reaction which is 2H₂ + O₂ ightarrow 2H₂O. From this equation, we can see that every 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

Now, let's see if we have enough of each reactant:

Hydrogen: 5.6 moles H₂ is available

Oxygen: 4.7 moles O₂ is available

According to the stoichiometry of the equation, oxygen will run out first since 4.7 moles of oxygen can react completely with (4.7 times 2) = 9.4 moles of hydrogen. But only 5.6 moles of hydrogen are available, which is less than 9.4 moles, so actually, hydrogen will limit the reaction.

Thus, the limiting reactant is hydrogen (H₂) and the excess reactant is oxygen (O₂). The maximum number o2f moles of water that can be produced is therefore equal to the moles of hydrogen available, which is 5.6 moles of H₂, resulting in 5.6 moles of H₂O being produced.

Answer:

9.03*10^23 atoms  of C

Explanation:

1 mol of any substance contains 6.02*10^23 particle of this substance.

1 mol C ---    6.02*10^23 atoms of C

1.50 mol C ---  x atoms of C

x = 1.50*6.02*10^23 = 9.03*10^23 atoms of C

Answer:

Base

Explanation:

acid + base = salt + water

The compound reacts with an acid to form a salt and water is base.

A base is a substances that is slippery to touch,corrosive and sour taste which react with acid to give salt and water. It turns red lithmus paper to blue. It is the degree of hydroxide ion in a solution.

The compound reacts with an acid to form a salt and water is base.

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Answer : The molarity of a solution is, 0.0337 M

Explanation : Given,

Mass of [tex]MgI_2[/tex] = 468 mg  = 0.468 g   (1 mg = 0.001 g)

Volume of solution = 50.0 mL

Molar mass of [tex]MgI_2[/tex] = 278 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

[tex]\text{Molarity}=\frac{\text{Mass of }MgI_2\times 1000}{\text{Molar mass of }MgI_2\times \text{Volume of solution (in mL)}}[/tex]

Now put all the given values in this formula, we get:

[tex]\text{Molarity}=\frac{0.468g\times 1000}{278g/mole\times 50.0mL}=0.0337mole/L=0.0337M[/tex]

Therefore, the molarity of a solution is, 0.0337 M

The molarity of the solution formed is 0.0337 M

From the question,

We are to determine the molarity of the solution formed.

First, we will determine the number of moles MgI₂ dissolved

Mass of MgI₂ dissolved = 468 mg = 0.468 g

From the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of MgI₂ = 278.1139 g/mol

∴ Number of moles of MgI₂ present = [tex]\frac{0.468}{278.1139}[/tex]

Number of moles of MgI₂ present = 0.001682764 mole

Now,

For the molarity of the solution formed,

Using the formula

[tex]Molarity = \frac{Number\ of\ moles}{Volume}[/tex]

Volume of the solution = 50.0 mL = 0.050 L

∴ Molarity of the solution = [tex]\frac{0.001682764}{0.050}[/tex]

Molarity of the solution = 0.033655

Molarity of the solution ≅ 0.0337 M

Hence, the molarity of the solution formed is 0.0337 M

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The critical concentration is key in determining whether actin monomers will form filaments or disassemble. Above this concentration, polymerization of actin occurs, while below it, monomers dissociate. A steady state is reached at the critical concentration, essential for cell motility and structure.

The critical concentration is the threshold at which actin filaments will either form or dissociate. In the presence of actin monomers above this concentration, the actin will polymerize into filaments; below it, the filaments will disassemble into monomers. At the critical concentration, there is a dynamic state where the rates of polymerization and depolymerization are equal, leading to a steady state in the reaction containing F-actin (filamentous actin).

Actin dynamics are essential for various cellular functions, including muscle contraction and cell motility. The polymerization and depolymerization processes are regulated by ATP-binding and hydrolysis, with critical concentration playing a crucial role in achieving a steady state of F-actin within cells. This balance affects the cell's ability to exert forces on itself and its environment, a key aspect of cellular motility and structure.