If a particular utility burned 2.90 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide was emitted?
How is the strength of a weak acid related to the strength of its conjugate base?
Final answer:
The strength of a weak acid is related to the strength of its conjugate base through an inverse relationship.
Explanation:
The strength of a weak acid is related to the strength of its conjugate base through an inverse relationship. According to the general rule, the stronger the acid, the weaker the conjugate base, and vice versa. This can be understood by considering the concept of acid-base equilibrium.
For example, if we have a strong acid and a weak base, the acid-base equilibrium will favor the side with the weaker acid and base. Conversely, if we have a weak acid and a strong base, the equilibrium will favor the side with the weaker acid and base.
Therefore, the strength of a weak acid and its conjugate base are inversely related, with the weaker acid having a stronger conjugate base.
The solubility of a salt in a given volume of water depends primarily on the
How many electrons are needed in the outer energy levels of most atoms to be chemically stable?
Which is not a characteristic of chemical equilibrium?
The reactions go to completion.
The reactions are reversible.
The reaction occurs in a closed container.
The forward and reverse processes occur at the same rate.
C. The reactions go to completion
The ksp of zinc carbonate (znco3 is 1.0 × 10–10. what is the solubility concentration of carbonate ions in a saturated solution at 25°c? 1.4 × 10–5m 7.1 × 10–6m 1.7 × 10–5m 1.0 × 10–5m
A student made this model of a carbon dioxide molecule. its has one carbon atom and two oxygen atoms what is the correct way to write the chemical name of carbon dioxide
Answer:
The chemical name of carbon dioxide is [tex]CO_2[/tex].
Explanation:
[tex]C+2O\rightarrow CO_2[/tex]
In a model of carbon dioxide made by the student there are one carbon atom and two oxygen atoms which means that total atoms in the molecule of carbon-dioxide is three.
While writing the chemical name of the carbon dioxide we will first write the symbol of the electropositive atom and then electronegative atom:[tex]CO_2[/tex]
What does a positive standard reduction potential mean about a given element?
The element is more readily oxidized than hydrogen.
The element is more readily oxidized than most other elements.
The element is more readily reduced than hydrogen.
The element is more readily reduced than most other elements.
The correct statement is " The element is more readily reduced than hydrogen." A hydrogen electrode is always attached to the rod of the element being investigated to obtain the electrode potential. It is called a standard hydrogen electrode, because the conditions are standard with pressure at 1 atm and the concentration of [tex]H^+[/tex] ions at 1M. A positive standard reduction potential means the element's electrode forms its metal ions less readily than hydrogen, which leads to the electrode being reduced by gaining electrons and the potential difference giving a positive value.
A student must find the total mass of several bouncing balls but none of the balls or remain on a triple beam balance propose a method for measuring the mass of the bouncing balls using the balance
A method for the student to find the total mass of the balls, without the problems of the balls not remaining in the balance, to synchronize a type of container or box that could house all the balls. With the container still empty, the student should weigh the container and note the weight. After that, the student should place the balls into the container and weigh the container along with the balls and note the weight.
In the second weighing the student will have the weight of the container along with the weight of the balls, but in the first weighing the student weighed the container alone. Thus, we can conclude that if the student subtracts the weight of the balls with the container by the hair of the soxinho regipiente, the student will result in the total mass of the balls.
You are asked to bring the pH of 0.500L of 0.550 M NH4Cl to 7.00. Which of the following solutions would you use: 12.0 M HCl or 12.0 M NH3? How many drops (1 drop 0.05 mL ) of this solution would you use?
The answer to part one is 12.0 M NH3 but how do you answer the second part?
Thank you
Sodium ions are used by your body every time you move a muscle. The difference between the Na+ ions and atomic Na is that A) ionic sodium has one more electron. B) atomic sodium has one more electron. C) atomic sodium has one fewer electron. D) ionic sodium is only found in the body.
B) atomic sodium has one more electron.
This can be easily seen if you compare the charges - ionic sodium carries one more positive charge than atomic sodium, so ionic sodium must have one fewer electron.
Calculate the number of moles in 3.025 X 10^28 atoms of NaCl.
1.0 mol NaCl
5.02 X 10^4 mol NaCl
5.02 X 10^50 mol NaCl
1.78 X 10^39 mol NaCl
What effect would poor circulation of the melting point bath liquid have on the observed melting point?
SOMEONE PLEASE HELP ME! MEDAL, FAN, AND TESTIMONIAL
K3PO4 + Al(NO3)3 → 3KNO3 + AlPO4
How many moles of potassium nitrate are produced when 2.5 moles of potassium phosphate react?
Round final answers to the tenth position, one place after the decimal. Please remember your units.,
The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.
N2O4(g) ⇌ 2 NO2(g) Kc = 1.46
5 N2O4(g) ⇌ 10 NO2(g) Kc = ?
A) 1.46
B) 0.292
C) 6.63
D) 1.08
E) 7.30
Answer: C,
Answer:
The answer is C) 6.63
Explanation:
When the coefficients in a balanced equation are multiplied by a factor, the resulting equilibrium constant is raised to this factor.
In this case, you have the following equilibrium:
N₂O₄(g) ⇌ 2 NO₂(g) Kc = 1.46
In which the coefficients are 1 (for N₂O₄) and 2 (for NO₂)
In the second equation, notice that you have the coefficients of the first equation multiplied by 5 (1 x 5= 5 for N₂O₄; 2 x 5= 10 for NO₂) :
5 N₂O₄(g) ⇌ 10 NO₂(g)
Thus, to obtain the equilibrium constant of the second equation (Kc'), you have to raise the first equilibrium constant (Kc) to 5:
K'c= (Kc)⁵= (1.46)⁵= 6.63
Please help ill medal and fan!
After 15 minutes, 30 g of a sample of polonium-218 remain uncharged. If the original sample had a mass of 960 g, what is the half-life of polonium-218?
And
Suppose you want to separate the leaves, acorns, and twigs from a pile of soil. Filtration and distillation are two processes of separating mixtures. Explain which process you would use and why.
"when a hydrogen atom is covalently bonded to either oxygen"
what do we need to survive and how long for
A theory which repeatedly fails to confirm the expected predictions:
probably needs to be developed into a law
probably should be discarded
requires more research time
should be maintained indefinitely,
Answer:
Probably should be discarded.
Explanation:
This reaction was monitored as a function of time:
AB --> A + B
A plot of 1/[AB] versus time yields a straight line with slope of -0.055/M*s.
a) What is the value of the rate constant (k) for this reaction t this temperature?
b) Write the rate law for the reaction.
c) What is the half-life when the initial concentration is 0.55M?
d) If the initial concentration of AB is 0.250M, and the reaction mixture initially contains no products, what are the concentrations of A and B after 75s?
a. The value of the rate constant (k) for this reaction at this temperature is 18.18 [tex]M^-1*s^-1.[/tex]
b. The rate law can be written as: ate = k[AB]
c. The half-life of the reaction when the initial concentration is 0.55 M is 0.038 seconds.
d. The concentrations of A and B after 75 seconds would be approximately 0.004 M each.
How to Write the rate law for the reaction.To answer the given questions, analyze the reaction kinetics based on the provided information:
a) The rate constant (k) can be determined from the slope of the plot 1/[AB] versus time. The slope is given as -0.055/M*s. The rate constant (k) can be calculated by taking the reciprocal of the slope:
k = -1/slope
k = -1/(-0.055/Ms)
k = 18.18 [tex]M^-1s^-1[/tex]
Therefore, the value of the rate constant (k) for this reaction at this temperature is 18.18 [tex]M^-1*s^-1[/tex].
b) The rate law can be determined using the given reaction:
AB --> A + B
Since the reaction is a first-order reaction, the rate law can be written as:
Rate = k[AB]
c) The half-life (t₁/₂) can be calculated using the first-order integrated rate law:
t₁/₂ = (0.693) / k
Given the initial concentration ([AB]₀) as 0.55 M and the rate constant (k) as 18.18 [tex]M^-1*s^-1[/tex], calculate the half-life:
t₁/₂ = (0.693) / (18.18 [tex]M^-1*s^-1[/tex])
t₁/₂ ≈ 0.038 s
Therefore, the half-life of the reaction when the initial concentration is 0.55 M is approximately 0.038 seconds.
d) To determine the concentrations of A and B after 75 seconds, use the first-order integrated rate law:
[AB] = [AB]₀ * exp(-kt)
Given:
[AB]₀ = 0.250 M (initial concentration of AB)
t = 75 s (time)
Using the rate constant (k) calculated earlier (18.18 [tex]M^-1*s^-1[/tex]), calculate the concentrations of A and B:
[AB] = 0.250 * exp(-18.18 [tex]M^-1*s^-1[/tex] * 75 s)
[AB] ≈ 0.004 M
Since the reaction is stoichiometrically 1:1, the concentrations of A and B after 75 seconds would be:
[A] ≈ 0.004 M
[B] ≈ 0.004 M
Therefore, the concentrations of A and B after 75 seconds would be approximately 0.004 M each.
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The rate constant is 0.055/M*s. The rate law is rate = k[AB]. The half-life is 10.5 seconds and the concentrations of A and B after 75 seconds can be calculated using the integrated rate equation.
Explanation:a) The slope of the line in the plot represents the rate constant (k) for this reaction. In this case, the slope is -0.055/M*s. So, the value of the rate constant is 0.055/M*s.
b) The rate law for the reaction can be determined by examining the stoichiometry of the reaction. The reaction is AB → A + B. Since the rate is expressed as 1/[AB], the rate law is rate = k[AB].
c) To find the half-life, we need to use the integrated rate equation ln([AB]₀/[AB]) = kt. Substituting the given values, we get ln(0.55/0.25) = (0.055/M*s)t. Solving for t, we find t = 10.5 seconds.
d) To find the concentrations of A and B after 75 seconds, we can use the integrated rate equation again. [A] = [AB]₀ - [AB]₀e^{-kt}. Plugging in the values, we get [A] = 0.250M - 0.250Me^{(-0.055/M*s)(75s)}. Similarly, we can find [B] = 0.250M - [A].
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What are five characteristics of a group on the periodic table?
Which diagram(s) represents the bonding pattern of metals?
A and B
C and D
A
C
The answer is the third option which is A.
Please vote Brainliest if I am right. (:
Answer is: A.
1. Metallic bond is a type of chemical bond.
2. Metallic bond is formed between electrons and positively charged metal ions.
3. Metallic radius is defined as one-half of the distance between the two adjacent metal ions.
4. Metallic bond increace electrical and thermal conductivity.
5. Metals conduct heat, because when free moving electrons gain energy (heat) they vibrate more quickly and can move around.
When the ancient Greeks looked at the night sky they noticed that some points of light seem to "wander" in the sky. Which term do we use for these wanderers today? A. stars B. nebulae C. planets D. moons
Answer:
I think planets....?
Explanation:
I'm not actually sure but my brother told me it's nebulae and I think he's lying... stars don't move and the moon wouldn't actually be a "point" even if it was it wouldn't be plural....
The volume of a gas is 4.00 liters at 293 k and constant pressure. for the volume of the gas to become 3.00 liters, the kelvin temperature must be equal to
Under standard condition and 298 K, the free energy difference, ∆Gº between the two chair conformations of a substituted cyclohexane molecule is 5.95 kJ/mol. What percent of the sample at equilibrium represents the most stable conformer?
Using the given free energy difference at 298 K and the equation ∆Gº = -RTlnK, we calculate the equilibrium constant (K) and determine that the most stable conformer of a substituted cyclohexane molecule comprises approximately 91.7% of the sample at equilibrium.
To determine what percent of the sample at equilibrium represents the most stable conformer of a substituted cyclohexane molecule, we use the free energy difference (
∆Gº) between the two chair conformations. Given that
∆Gº is 5.95 kJ/mol at 298 K, we first calculate the equilibrium constant (K) using the equation ∆Gº = -RTlnK, where R is the universal gas constant (8.314 J/mol•K) and T is the temperature in Kelvin. Substituting the known values, we have:
5.95 kJ/mol = - (8.314 J/mol•K)(298 K)lnK
Converting 5.95 kJ/mol to J/mol, we get 5950 J/mol. We then solve for K:
5950 J/mol = - (8.314 J/mol•K)(298 K)lnK
lnK = -5950 J/mol / (- (8.314 J/mol•K)(298 K))
lnK = 2.397
K = e^(2.397)
K ≈ 11.0
The ratio of the amounts of each conformer at equilibrium can be expressed as K = [Most Stable]/[Least Stable]. Hence, if the least stable conformer is taken as 1 part, the most stable will be 11 parts out of a total of 12 parts. The percent representation of the most stable conformer at equilibrium is then (11/12) * 100%, which approximates to 91.7%.
Therefore, the most stable conformer comprises approximately 91.7% of the sample at equilibrium.
Calculate the percent ionization of 0.0075 m butanoic acid (ka = 1.5 x 10-5) in a solution containing 0.085 m sodium butanoate.
The percent ionization of the solution is 0.017%.
The steps involved are;
Write the reaction equationSetup the ICE tablemake the necessary calculationThe equation of the reaction is;
CH3CH2CH2COOH(aq) ⇄ H^+(aq) + CH3CH2CH2COO^-(aq)
I 0.0075 0 0.085
C -x +x + x
E 0.0075 - x x 0.085 + x
The Ka of the acid = 1.5 x 10^-5
Hence;
1.5 x 10^-5 = x(0.085 + x)/0.0075 - x
1.5 x 10^-5 (0.0075 - x ) = x(0.085 + x)
1.1 x 10^-7 - 1.5 x 10^-5x = 0.085x + x^2
x^2 + 0.085x - 1.1 x 10^-7 = 0
x = 0.0000013 M
Percent ionization= 0.0000013 M/0.0075 × 100/1
= 0.017%
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If horizontal layers of sedimentary rock have a vertical fault running through them, how might a geologist use relative dating to determine when the fault occurred ? Could scientists use absolute dating as well ? Why or why not ?
Answer:
Scientists will be able to use relative dating and absolute dating to determine when the failure occurred.
Explanation:
Scientists will be able to use relative dating, because it is the method capable of determining an order of events that occurred in the past by relating the rock with that failure to a rock without failure or with different failures, without the need to determine an absolute age of when the failure happened, however revealing a relative, approximate date.
It will also be possible to use absolute dating, which will give a more precise age on the fault present in the rock, using a chronological age that will be determined by observing the physical and chemical properties of the rock. This technique shows the age of the event in numbers, as opposed to relative dating.
Temperature at which a substance goes from a solid to liquid
In the reactions of glycolysis, acetyl-coa formation and the citric acid cycle, chemical energy is transferred to the bonds in:
Sugar cubes are placed in water. how will the mixture be affected by stirring the water, by breaking apart the sugar cubes, or by raising the temperature? each action will increase the speed that the sugar dissolves in the water. each action will increase the solubility of sugar in water. each action will increase the concentration of sugar that eventually is reached in the solution.