Answer:
1.24 atm is the new pressure
Explanation:
We may solve this question with the Ideal Gases Law that must be used, twice. → P . V = n . R . T
Total pressure = Partial pressure of gas A + Partial pressure of gas B
Total pressure = 0.298 atm + 0.589 atm → 0.887 atm
We convert the T° to Absolute value → 55°C + 273 = 328K
0.887 atm . 9.80L = n . 0.082 . 328K
(0.887 atm . 9.80L) /(0.082 . 328K) = 0.323 moles
These are the moles from the initial mixture, but we add 0.130 moles
Total new moles are 0.323 + 0.130 = 0.453 moles
P = (0.453 mol . 0.082 . 328K) / 9.80L
P = 1.24 atm
Notice, that the pressure was increased. As we add a third gas, the pressure is correctly increased because the molecules from all of the gases collide more with the walls of the vessel.
NaOH and bleach have several characteristics in common. They include all BUT one of the characteristics listed.
Answer:
Their pH is less than 7
Explanation:
Both of these compounds pHs are greater than 7.
Answer:
A) Their pH is less than 7
Explanation:
Their pH is less than 7 is not correct. Their pH is greater than seven, but not equal to seven.
O3(g)+NO(g)<—>O2(g)+NO2(g) Write the equalibrium expression
Answer: [NO2][O2]/[NO] [O3]
Explanation: Kc = [NO2][O2]/[NO] [O3]
How many liters of o2 at 298 k and 1.00 bar are produced in 1.25 hr in an electrolytic cell operating at a current of 0.0500 a?
Answer:
0.0144 L
Explanation:
Step 1:
Data obtained from the question. This includes:
Temperature (T) = 298k
Pressure (P) = 1 bar
Time (t) = 1.25 hr
Current (I) = 0.0500 A
Step 2:
Determination of the quantity of electricity (Q) used. This is illustrated below:
Q = it
Time (t) = 1.25 hr = 1.25 x 3600 = 4500 secs
Current (I) = 0.0500 A
Quantity of electricity (Q) =?
Q = it
Q = 0.05 x 4500
Q = 225C
Step 3:
Determination of the number of mole of O2 liberated in the process.
In the electrolytic process, O2 will be liberated according to the equation:
2O^2- + 4e- —> O2
From the above illustration, 4 faraday are needed to liberate 1 mole of O2.
1 faraday = 96500C
Therefore of 4 faraday = 4x96500C = 386000C
From the above equation,
386000C of electricity liberated 1 mole of O2.
Therefore, 225C will liberate = 225/386000 = 5.83x10^-4 mole of O2.
Step 4:
Determination of the volume of the O2 liberated.
Number of mole (n) = 5.83x10^-4 mole
Temperature (T) = 298k
Pressure (P) = 1 bar = 0.987 atm
Gas constant (R) = 0.082atm.L/Kmol
Volume (V) =?
Applying the ideal gas equation:
PV = nRT
The volume of O2 can be obtained as follow:
PV = nRT
0.987 x V = 5.83x10^-4 x298x0.082
Divide both side by 0.987
V = (5.83x10^-4 x298x0.082)/0.987
V = 0.0144 L
The volume of [tex]\(O_2\)[/tex] produced is approximately [tex]0.0145 \ liters[/tex] at [tex]298 \ K[/tex] and [tex]1.00[/tex] bar.
To determine the volume of [tex]\(O_2\)[/tex] gas produced in an electrolytic cell, we can follow these steps:
Calculate the total charge
The total charge [tex]\(Q\)[/tex] passed through the cell is given by the product of current [tex]\(I\)[/tex] and time [tex]\(t\)[/tex]:
[tex]\[ Q = I \cdot t \][/tex]
Given:
[tex]Current, \(I = 0.0500 \, \text{A}\)[/tex]
[tex]Time, \(t = 1.25 \, \text{hr} = 1.25 \times 3600 \, \text{s} = 4500 \, \text{s}\)[/tex]
[tex]\[ Q = 0.0500 \, \text{A} \times 4500 \, \text{s} = 225 \, \text{C} \][/tex]
Determine the amount of [tex]\(O_2\)[/tex] produced
The half-reaction for the production of [tex]\(O_2\)[/tex] in water electrolysis is:
[tex]\[ 2 \, \text{H}_2\text{O} \rightarrow \text{O}_2 + 4 \, \text{H}^+ + 4 \, \text{e}^- \][/tex]
From this reaction, we see that [tex]4[/tex] moles of electrons produce [tex]1[/tex] mole of [tex]\(O_2\)[/tex]
The Faraday constant [tex](\(F\))[/tex] is [tex]\(96485 \, \text{C/mol}\)[/tex].
The moles of electrons [tex](\(n_{\text{e}^-}\))[/tex] can be calculated as:
[tex]\[ n_{\text{e}^-} = \frac{Q}{F} = \frac{225 \, \text{C}}{96485 \, \text{C/mol}} = 0.00233 \, \text{mol} \][/tex]
From the stoichiometry of the half-reaction, [tex]4[/tex] moles of electrons produce [tex]1[/tex] mole of [tex]\(O_2\)[/tex]:
[tex]\[ n_{\text{O}_2} = \frac{n_{\text{e}^-}}{4} = \frac{0.00233 \, \text{mol}}{4} = 0.000583 \, \text{mol} \][/tex]
Calculate the volume of [tex]\(O_2\)[/tex] gas
Use the ideal gas law to find the volume of [tex]\(O_2\)[/tex] gas at [tex]298\ K[/tex] and [tex]1.00[/tex] bar:
[tex]\[ PV = nRT \][/tex]
Given:
Pressure, \[tex](P = 1.00 \, \text{bar} = 1.00 \times 10^5 \, \text{Pa}\)[/tex]
Temperature, [tex]\(T = 298 \, \text{K}\)[/tex]
Gas constant, [tex]\(R = 8.314 \, \text{J/(mol K)}\)[/tex]
Moles of [tex]\(O_2\), \(n = 0.000583 \, \text{mol}\)[/tex]
[tex]\[ V = \frac{nRT}{P} = \frac{0.000583 \, \text{mol} \times 8.314 \, \text{J/(mol K)} \times 298 \, \text{K}}{1.00 \times 10^5 \, \text{Pa}} \][/tex]
[tex]\[ V = \frac{1.447 \, \text{J}}{1.00 \times 10^5 \, \text{Pa}} = 1.447 \times 10^{-5} \, \text{m}^3 \][/tex]
[tex]\[ V = 0.01447 \, \text{L} \][/tex]
A solution is made containing 22.8 g of magnesium nitrate per 325 g of water. What is the weight/ weight % or percent by mass of the solute?
Answer:
6.56%
Explanation:
mass of solute = 22.8 g
mass of solution = mass (solute) + mass (water) = 22.8 + 325 = 347.8 g
% by mass = [mass(solute)/ mass(solution)]*100% =(22.8/347.8)*100% = 6.56%
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the percent yield of oxygen in this chemical reaction?Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100..
Answer:
73.4% is the percent yield
Explanation:
2KClO₃ → 2KCl + 3O₂
This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.
We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃
In the theoretical yield of the reaction we say:
2 moles of potassium chlorate can produce 3 moles of oxygen
Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂
The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g
But, we have produced 115 g. Let's determine the percent yield of reaction
Percent yield = (Produced yield/Theoretical yield) . 100
(115g / 156.6g) . 100 = 73.4 %
Which part of an atom is most directlly involved in chemical bonding?
What conditions are required for heat transfer between states of matter to occur? In what
direction will heat transfer occur?
Why does phosphate act as an environmental contaminant?
Answer:
Too much phosphorus in the water causes algae to grow faster than ecosystems can handle. Large growths of algae are called algal blooms and they can severely reduce or eliminate oxygen in the water, leading to illnesses in fish and the death of large numbers of fish.
Explanation
Futhermore, with a loss of fish the whole ecosystem will be upset and will be in need of serious recovery.
Final answer:
Phosphate acts as an environmental contaminant by promoting eutrophication, excessive growth of algae in water. It is introduced through human activities and contributes to the overgrowth of algae, leading to negative effects on the aquatic ecosystem.
Explanation:
Phosphate acts as an environmental contaminant due to its role in promoting eutrophication. Eutrophication is the excessive growth of algae in a body of water, which leads to a decrease in dissolved oxygen levels that can harm aquatic organisms. Phosphates are introduced into the environment through human activities, such as the use of phosphate-containing detergents and the leaching of phosphate from rock by weathering. These phosphates contribute to the overgrowth of algae and the subsequent negative effects on the aquatic ecosystem.a
A gas is sealed in a rigid canister at a temperature of –5.0°C and a pressure of 713 mmHg. Which of the following actions would most likely bring the gas to STP?
heating the canister
removing some of the gas from the canister
transfer some of the gas to a larger canister
Answer: heating the canister
Answer:
heating the canister
Explanation:
How many moles are in 65 g of carbon dioxide (CO2)?
Answer:
1.477mole
Explanation:
First, we'll begin by calculating the molar mass of CO2. This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Mass of CO2 from the question = 65g
Mole of CO2 =?
Number of mole = Mass/Molar Mass
Mole of CO2 = 65/44
Mole of CO2 = 1.477mole
Therefore, 65g of carbon dioxide (CO2) contains 1.477mole
When an irregular shaped object was put in a graduated cylinder with an initial volume of 25 mL of water, the water level rose to 54.0 mL of water after the object was submerged. If the mass of the object is 7.0 grams, what is the density of the object
Answer:
0.24 g/mL
Explanation:
The density of an object is given by the ratio between its mass and its volume:
[tex]\rho=\frac{m}{V}[/tex]
where
m is the mass of the object
V is its density
In this problem, we have:
m = 7.0 g is the mass of the object
The volume of an irregular shaped object can be measured by putting it into water, and by measuring the difference in water volume.
In this case,
[tex]V_1=25 mL[/tex] is the initial volume of water
[tex]V_2=54 mL[/tex] is the final volume of water
So the volume of the object is
[tex]V=V_2-V_1=54-25=29 mL[/tex]
Therefore, the density of the object is:
[tex]\rho = \frac{7.0 g}{29 mL}=0.24 g/mL[/tex]
Final answer:
To find the density of an irregular shaped object submerged in water, the volume displaced by the object is calculated first, and then the density is found by dividing the mass of the object by the displaced volume. In this case, the density is 0.241 g/mL.
Explanation:
When an irregular shaped object is placed in a graduated cylinder with a starting volume of 25 mL of water and causes the water level to rise to 54.0 mL upon submersion, the object displaces a volume of water equal to the difference in these measurements. To calculate the density of the object, you have to use the formula for density, which is mass divided by volume. Given that the mass of the object is 7.0 grams and the volume displacement is 54.0 mL - 25 mL = 29.0 mL, the density of the object can be found using these values.
The calculation would be as follows: Density = Mass / Volume = 7.0 grams / 29.0 mL = 0.241 g/mL.
Therefore, the density of the object is 0.241 g/mL, indicating how compact the object's mass is within its volume.
what happens when you mix MORE vinegar than baking soda?
Answer:
Excess Vinegar
Explanation:
You will have excess vinegar
Calculate the mass, in grams, of the solvent present in a 32.2% solution that contains 14.7 g of NaBr.
Answer:
32g
Explanation:
We have to remember that for percent (w/w) concentration we usually write;
Percent concentration= mass of solute/mass of solution ×100
Since mass of solute= 14.7 g and percent concentration = 32.2%
Then
Mass of solution= mass of solute × 100/ percent concentration
Mass of solution= 14.7 ×100/32.2
Mass of solution= 46.7 g
Since mass of solution = mass of solute + mass of solvent
Mass of solute= 14.7 g
Mass of solution = 46.7g
Mass of solvent = 46.7g -14.7g = 32g
What is the hydrogen ion concentration of a substance with a hydroxide ion concentration of 1.07x10-10M?
(Be sure to give your answer in 3 sig figs and the unit. Also type the letter "e" for "X10" just like on webassign
with no spaces)
Answer:
Explanation:
[OH⁻] = 1.07 x 10⁻¹⁰
[H⁺] x [ OH⁻ ] = 10⁻¹⁴
[H⁺] x 1.07 x 10⁻¹⁰ = 10⁻¹⁴
[H⁺] = 10⁻¹⁴ / 1.07 x 10⁻¹⁰
= .93458 x 10⁻⁴
= 9.3458 x 10⁻⁵
= 9.35 x 10⁻⁵
= 9.35e-5. M.
What is meant by enthalpy change?
Enthalpy change is a measurement of heat energy absorbed or released during a chemical reaction at constant pressure. It reflects the net energy required to break the chemical bonds of reactants versus the energy released when new bonds form in products, determining if the reaction is endothermic or exothermic.
It represents the difference between the enthalpy (heat content) of the reactants and the products. When chemical bonds are broken in reactants, energy is absorbed, and when new bonds form in products, energy is released. If the energy required to break bonds is greater than the energy released when new bonds are formed, the reaction is endothermic and the enthalpy change is positive; conversely, if more energy is released during bond formation than is absorbed during bond breaking, the reaction is exothermic and exhibits a negative enthalpy change.
The enthalpy change can be calculated using the formula ΔH = Σ (bond dissociation energies of reactants) minus Σ (bond dissociation energies of products), which simplifies the overall energy balance of bond breaking and bond formation processes. This understanding allows scientists to predict whether a reaction will absorb or release energy and is crucial in fields such as thermodynamics and chemical engineering.
What do the COEFFICIENTS in a chemical reaction represent?
Answer:First: the coefficients give the number of molecules (or atoms) involved in the reaction. In the example reaction, two molecules of hydrogen react with one molecule of oxygen and produce two molecules of water. Second: the coefficients give the number of moles of each substance involved in the reaction.
Explanation: PLESE GIVE BRAINLIEST
The coefficients tells us about the number of atoms, molecules or compound present in a reaction. They are actually the numbers or terms which are used in a balanced chemical equation.
What is a balanced chemical equation?A chemical equation in which amount of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation. The number of atoms of reactants and products on both sides will be equal.
The coefficients are the numbers which are added in front of the chemical formulae or symbol in order to balance the chemical equation. Only by adding the coefficients a balanced equation obeys the law of conservation of mass.
An equation is balanced with the help of coefficients.
For example, in the given reaction:
2H₂ + O₂ → 2H₂O
The coefficients of H₂,O₂ and H₂O are 2, 1 and 2.
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A solution of potassium cyanide, KCN, is made by dissolving 3.2 g of KCN in water. When this solution reacts with excess hydrochloric acid, HCl, it produces 0.30 g of poisonous hydrogen cyanide gas, HCN.
KCN + HCl --> KCl + HCN
(a) Calculate the theoretical yield of HCN.
(b) Calculate the percent yield of HCN.
Answer:
22.7%
Explanation:
We must first put down the equation of reaction to guide our work while solving the problem.
KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)
The questions specifically state that HCl is in excess so KCN is the limiting reactant.
Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN
Mass of KCN reacted= 3.2 g
Molar mass of KCN= 65.12 g/mol
Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles
Theoretical yield of HCN is obtained thus;
From the reaction equation;
1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.
Mass of HCN = number of moles ×molar mass
Molar mass of HCN= 27.0253 g/mol
Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN
Actual yield of HCN= 0.30g
% yield= actual yield/ theoretical yield ×100
% yield= 0.30/1.32 ×100
%yield= 22.7%
Answer:
The theoretical yield HCN is 1.33 grams
The percent yield HCN is 22.56 %
Explanation:
Step 1: Data given
Mass of KCN = 3.2 grams
Molar mass KCN = 65.12 g/mol
Mass of HCN produced = 0.30 grams
Step 2: The balanced equation
KCN + HCl --> KCl + HCN
Step 3: Calculate moles KCN
Moles KCN = mass KCN / moalr mass KCN
Moles KCN = 3.2 grams / 65.12 g/mol
Moles KCN = 0.0491 moles
Step 4: Calculate moles HCN
For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN
For 0.0491 moles HCN we'll have 0.0491 moles HCN
Step 5: Calculate mass HCN
Mass HCN = moles HCN * molar mass HCN
Mass HCN = 0.0491 moles * 27.03 g/mol
Mass HCN = 1.33 grams = the theoretical yield
Step 6: Calculate the percent yield HCN
Percent yield = (actual yiel / theoretical yield) * 100 %
Percent yield = (0.30 grams / 1.33 grams)
Percent yield = 22.56 %
Consider the conversion of succinate to fumarate in the Citric Acid Cycle (reaction below). This reaction is endergonic under standard conditions (ΔGo’≈ 6 kJ/mol). How might this reaction be made favorable under equilibrium conditions? Your answer should include the relationship of this reaction to a canonical electron transport chain (i.e. an electron transport chain that uses oxygen as a terminal electron acceptor).
Answer:
Succinate oxidation to fumarate The following reactions transform succinate to regenerate oxalacetate. The first of these reactions is carried out by an oxidation catalyzed by succinate dehydrogenase. The hydrogen acceptor is FAD, since the free energy change is insufficient to allow NAD to interact. The final product is fumarate.
Explanation:
The condensation reaction of GDP + Pi and the hydrolysis of Succinyl-CoA involve the H2O necessary to balance the equation.
Which situation will most likely cause the sustainability of an ecosystem to weaken?
A zebra is killed and eaten by a lion.
A disease wipes out several plant species.
A frog lays hundreds of eggs that hatch into tadpoles.
A dry season causes a few small trees to die.
Answer:
B. A disease wipes out several plant species.
Explanation:
This will be the most detrimental to the environment as it will decrease oxygen levels and many animals will lose their shelter.
- everything else happens every year and is common and normal.
A disease wiping out several plant species will most likely cause the sustainability of an ecosystem to weaken.
What is an ecosystem?Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.
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You started with only 6.750 g of sodium carbonate, but you ended up with more mass than that at the end of the reaction. According to the Law of Conservation of Mass, matter cannot be created or destroyed, so how is it possible for the product to weigh more than the starting material? (State your answer in 1-2 complete sentences.)
Answer:
It is not possible, since the total weight of all the reagents involved in the reaction is equal to the total weight of the product, since it is not possible to create or destroy atoms, thus, it is not possible to change the weight of the product. It is equal to the weight of the reagent.
Explanation:
Given the half‑reactions and their respective standard reduction potentials 1. Cr 3 + + e − ⟶ Cr 2 + E ∘ 1 = − 0.407 V 2. Cr 2 + + 2 e − ⟶ Cr ( s ) E ∘ 2 = − 0.913 V calculate the standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s).
Answer:
The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is -0.744 V
Explanation:
Here we have
1. Cr³⁺ + e − ⟶ Cr²⁺ E⁰₁ = − 0.407 V
2. Cr²⁺ + 2 e − ⟶ Cr ( s ) E⁰₂ = − 0.913 V
To solve the question, we convert, the E⁰ values to ΔG as follows
ΔG₁ = n·F·E⁰₁ and ΔG₂ = n·F·E⁰₂
Where:
F = Faraday's constant in calories
n = Number of e⁻
ΔG₁ = Gibbs free energy for the first reaction
ΔG₂ = Gibbs free energy for the second half reaction
E⁰₁ = Reduction potential for the first half reaction
E⁰₂ = Reduction potential for the second half reaction
∴ ΔG₁ = 1 × F × − 0.407 V
ΔG₂ = 2 × F × − 0.913 V
ΔG₁ + ΔG₂ = F × -2.233 V which gives
ΔG = n × F × ΔE⁰ = F × -2.233 V
Where n = total number of electrons ⇒ 1·e⁻ + 2·e⁻ = 3·e⁻ = 3 electrons
We have, 3 × F × ΔE⁰ = F × -2.233 V
Which gives ΔE⁰ = -2.233 V /3 = -0.744 V.
The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is found by the summation of the standard reduction potentials of the half-reactions involved, giving -1.32V.
Explanation:To calculate the standard reduction potential for the reduction half-reaction of Cr(III) to Cr(s), we first need to understand that a redox reaction is a sum of an oxidation half-reaction and a reduction half-reaction. In the given half-reactions, the first is for Cr3+ being reduced to Cr2+ and the second one is for Cr2+ being reduced to Cr(s).
From the given standard reduction potentials, the 1st reaction has E°1 = -0.407 V and the 2nd reaction has E°2 = -0.913 V. Therefore, to get from Cr3+ to Cr(s), we add both these half-reactions together, which also means we add their potentials together. The sum gives us the potential for the entire reaction, which is E°total = E°1 + E°2 = (-0.407V) + (-0.913V) = -1.32V.
Thus, the standard reduction potential for the reduction half-reaction of Cr(III) to Cr(s) is -1.32V.
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What is the representative particle for copper metal, Cu
The representative particle for copper metal, Cu, refers to the smallest unit which retains the properties of copper – in this case, a single copper atom.
Explanation:In chemistry, a representative particle refers to the smallest unit of a substance that still retains the properties of that substance. For a pure metal like copper (Cu), the representative particle is an atom. Therefore, the representative particle for copper metal, Cu, is a copper atom. Copper atoms join together in a crystal lattice structure forming the bulk material we see and use in everyday life like wires, coins etc. But the smallest unit of this structure, the unit which represents its basic physical and chemical properties, is a single copper atom.
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Calculate the mass of KOH in a 35% solution that contains 58.5 g of water.
Answer:
Approximately [tex]\rm 31.5\; g[/tex].
Explanation:
The mass of a solution can be divided into two parts:
the solute (the material that was dissolved,) and the solvent.In this particular [tex]\rm KOH[/tex] solution in water,
[tex]\rm KOH[/tex] is the solute, whilewater is the solvent.The number [tex]35\%[/tex] here likely refers to the concentration of [tex]\rm KOH[/tex] in this solution. That's ratio between the mass of the solute ([tex]\rm KOH[/tex]) and the mass of the whole solution (mass of solute plus mass of solvent.) That is:
[tex]\displaystyle \frac{m(\text{KOH})}{m(\text{solution})} = 35\% = 0.35[/tex].
Hence, [tex]m(\mathrm{KOH}) = 0.35\, m(\text{solution})[/tex].
However, since the solution contains only the solute and the solvent, [tex]m(\text{solution}) = m(\text{solute}) + m(\text{solvent})[/tex].
For this solution in particular,
[tex]\begin{aligned}&m(\text{solution})\\&= m(\text{solute}) + m(\text{solvent}) \\ &= m(\text{KOH}) + m(\text{water})\end{aligned}[/tex].
As a result,
[tex]\begin{aligned}&m(\mathrm{KOH})\\ &= 0.35\, m(\text{solution}) \\&= 0.35\, (m(\mathrm{KOH}) + m(\text{water}))\\&= 0.35\, m(\mathrm{KOH}) + 0.35 \, m(\text{water})\end{aligned}[/tex].
Subtract [tex]0.35\, m(\mathrm{KOH})[/tex] from both sides of the equation:
[tex](1 - 0.35)\, m(\mathrm{KOH}) = 0.35\, m(\text{water})[/tex].
[tex]\begin{aligned} &m(\mathrm{KOH}) \\ &= \left(\frac{0.35}{1 - 0.35}\right)\cdot m(\text{water}) \\ &= \frac{0.35}{0.65} \times 58.5\; \text{g} = 31.5 \; \text{g}\end{aligned}[/tex].
Note, that for this calculation, there's nothing special about this [tex]35\%[/tex] solution of [tex]\mathrm{KOH}[/tex] in water. In general,
[tex]\displaystyle m(\text{solute}) = \left(\frac{\%\text{concentration}}{100\% - \%\text{concentration}}\right)\cdot m(\text{solvent})[/tex].
86.1 g of nitrogen reacts with lithium, how many grams of lithium will react?
Answer:
128g of Li, will react in this reaction
Explanation:
Before to start working, we need the reaction:
N₂ and Li react, in order to produce Li₃N (lithium nitride)
N₂ + 6Li → 2Li₃N
1 mol of nitrogen reacts with 6 moles of lithium
We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles
1 mol of N₂ reacts with 6 mol of Li
Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li
We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g
Consider the reaction between 15.0 mL of a 1.00 M aqueous solution of AgNO3 and 10.0 mL of a 1.00 M aqueous solution of K2CrO4. When these react, a precipitate is observed. What is present in solution after the reaction is complete
The two solutions AgNO3 and K2CrO4 react to give a precipitate along with an aqueous solution of KNO3. Hence, after the reaction is complete, KNO3 remains in the solution.
Explanation:When the two aqueous solutions AgNO3 and K2CrO4 react, they produce solid silver chromate Ag2CrO4 as a precipitate and leave potassium nitrate KNO3 in the solution. The reaction is balanced as 2AgNO3 (aqueous) + K2CrO4 (aqueous) -> Ag2CrO4 (s) + 2KNO3 (aqueous). As the reaction proceeds, silver ions (Ag+) and chromate ions (CrO42-) combine to form the precipitate, leaving potassium ions (K+) and nitrate ions (NO3-) in the solution. Hence, after the reaction, the solution consists of KNO3 because it remains aqueous, with 1.00 M K+ and 1.00 M NO3-.
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A 1.00 L flask was filled with 2.00 mol gaseous SO2 and 2.00 mol gaseous NO2 and heated. After equilibrium was reached, it was found that 1.30 mol gaseous NO was present. Assume that the reaction occurs under these conditions. Calculate the value of the equilibrium constant, K, for the following reaction. SO2(g) NO2(g) equilibrium reaction arrow SO3(g) NO(g)
Answer:
Explanation:
SO3 (g) + NO (g) U SO2 (g) + NO2 (g)
occurs under these conditions. Calculate the value of the equilibrium constant, Kc, for the above reaction.
SO3 (g) + NO (g) U SO2 (g) + NO2 (g)
Initial (M) 2.00 2.00 0 0
Change (M) −x −x +x +x
Equil (M) 2.00 − x 2.00 − x x x
2 2 c 3
2
c 2
[SO ][NO ]
[SO ][NO]
(2.00 )
=
= −
K
x K
x
Since the problem asks you to solve for Kc, it must indicate in the problem what the value of x is. The concentration of
NO at equilibrium is given to be 1.30 M. In the table above, we have the concentration of NO set equal to 2.00 − x.
2.00 − x = 1.30
x = 0.70
Substituting back into the equilibrium constant expression:
2c 2 2c 2
(2.00 )
(0.70)
(2.00 0.70)
= − = −
x KxK
Kc = 0.290
The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
is 225 kPa. What is the temperature of the air in the tire? Assume that the
volume is constant. Make sure your answer is rounded to nearest whole
number and your final answer has the units of K.*
Answer : The temperature of the air in the tire is, 341 K
Explanation :
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure = 198 kPa
[tex]P_2[/tex] = final pressure = 225 kPa
[tex]T_1[/tex] = initial temperature = [tex]27^oC=273+27=300K[/tex]
[tex]T_2[/tex] = final temperature = ?
Now put all the given values in the above equation, we get:
[tex]\frac{198kPa}{300K}=\frac{225kPa}{T_2}[/tex]
[tex]T_2=340.9K\approx 341K[/tex]
Therefore, the temperature of the air in the tire is, 341 K
Describe the sources of marine debris and explain why it is a problem with global origins.
Answer:
Explanation:
Marine debris consists of most anything used and discarded by humans. Winds, rivers and storms can carry this debris to the ocean from far inland, so it is not solely a case of pollution along shorelines. It is also true that oceangoing ships directly contribute to marine debris while they are at sea and not associated with any particular nation.
Which is the formula mass of Na₂SO₄? *
1. 119 amu
2. 125 amu
3. 142 amu
4. 174 amu
Answer:
the answer is option 3.
A bullet of mass 10 g is fired from a gun of mass 490 g. The bullet leaves the gun with a speed of 120 ms-1. Find the speed of recoil of the gun.
A. 2.4 ms-1 B. 4.8 ms-1
C. 6.4 ms-1 D. 7.4 ms-1
Final answer:
The recoil speed of the gun is found using the conservation of momentum. The calculation shows that the gun's recoil speed is approximately 2.4 ms-1. So the correct option is A.
Explanation:
The question posed is related to the concept of conservation of momentum in physics. When a bullet is fired from a gun, the bullet moves forward and the gun is pushed back due to recoil, both objects conserving the system's total momentum. To find the speed of recoil of the gun, you can use the formula:
[tex]m_{bullet}v_{bullet} = m_{gun}v_{gun}[/tex]
Where:
[tex]m_{bullet}[/tex] mass of the bullet (10 g or 0.01 kg)[tex]v_{bullet}[/tex] speed of the bullet (120 m/s)[tex]m_{gun}[/tex]e mass of the gun (490 g or 0.49 kg)[tex]v_{gun}[/tex]the recoil speed of the gunThus, solving for [tex]v_{gun}[/tex] :
[tex]v_{gun} = m_{bullet}v_{bullet} / m_{gun}[/tex]
[tex]v_{gun}[/tex]= (0.01 kg * 120 m/s) / 0.49 kg = 2.45 m/s
The speed of the recoil of the gun is therefore approximately 2.4 ms-1, which matches answer choice A.