A, B, C, and D have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. Which sentence about the points is true?

A, B, C, and D lie on the same line.
AB and CD are perpendicular lines.
AB and CD are parallel lines.
AB and CD are intersecting lines but are not perpendicular.
AC and BD are parallel lines.

Slope-intercept form is y = mx +b, where the variable m represents the slope of the line and the variable b represents the y-intercept of the line. Since we weren't given the y-intercept, one way to solve this problem is substitute the slope for the variable m and then the x and y values from the ordered pair to solve for b.

y = mx + b

y = 3x + b

-4 = 3(9) + b

Now, we can simplify by computing the multiplication on the right side of the equation.

-4 = 27 + b

Finally, we can find the value for b by subtracting 27 from both sides of the equation to get:

-31 = b

Now, we should substitute this value for b back into our equation with the slope.

y = 3x - 31

Therefore, your answer is y = 3x - 31.

Hope this helps!

Answer:

The correct answer would be y = 3x - 31

Step-by-step explanation:

In order to find the answer to this question, we must use point-slope from, which is listed below.

y - y1 = m(x - x1)

Now we input the ordered pair in for x1 and y1 and the slope in for m.

y - -4 = 3(x - 9)

Then we solve for y.

y + 4 = 3x - 27

y = 3x - 31

The slope of the tangent will be "[tex]10a-6a^2[/tex]". The equation at point (1, 8) is "[tex]y = 4x+4[/tex]" and at point (2,9) is "[tex]y = -4x+17[/tex]".

Given equation is:

(a)

The slope of the tangent to the curve point where [tex]x = a[/tex] is:

→ [tex]\frac{dy}{dx} = m = 10x-6x^2[/tex]

→              [tex]= 10a-6a^2[/tex]

(b)

The equation of tangent at point (1,8) will be:

→ Slope, [tex]m = 10-6[/tex]

                  [tex]= 4[/tex]

→ [tex]y-8=4(x-1)[/tex]

         [tex]y = 4x-4+8[/tex]

         [tex]y = 4x+4[/tex]

and,

The equation of tangent at point (2,9) will be:

→ Slope, [tex]m = 10\times 2-6\times 2^2[/tex]

                  [tex]= 20-24[/tex]

                  [tex]= -4[/tex]

→ [tex]y-9=-4(x-2)[/tex]

   [tex]y-9=-4x+8[/tex]

         [tex]y = -4x+17[/tex]

Thus the above answer is right.

Learn more about tangent here:

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Answer:

B. Time

Step-by-step explanation:

In general, x-axis is the variable (cause) and the y-axis is the response (effect)

So, according to the given information, TIME would be represented by the x-axis.

Answer:

Stan would need 960 sprinkles to make 60 cookies.

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

Since we are given 3 values, which are the amount of sprinkles to make 24 cookies, 60 cookies, and give us one variable. We can use the Rule of Three technique to find the amount of sprinkles needed for 60 cookies. This technique is shown in the picture that is attached below.

24 cookies   ⇒   384 sprinkles

60 cookies   ⇒   x

[tex]\frac{60*384}{24} = x[/tex]

[tex]960 sprinkles = x[/tex]

Therefore, we can see that Stan would need 960 sprinkles to make 60 cookies.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:

Step-by-step explanation:

You take the amount of 2-digit numbers there are (90) and subtract it from the  amount of two digit numbers that are multiples of 5 and 7 (29). You should get 61.

Answer:  The number 2-digit numbers are multiples of neither 5 nor 7 is 61.

Step-by-step explanation:  We are given to find the number of 2-digit numbers that are multiples of neither 5 nor 7.

Let A denote the set of 2-digit numbers that are multiples of 5 and B denote the set of 2-digit numbers that are multiples of 7.

Then,

A = {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95}

and

B = {14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98}

That is, n(A) = 18  and  n(B) = 13.

Now, the set of 2-digit numbers that are multiples of both 5 and 7 is given by

[tex]A\cap B=\{35, 70\}~~~~~~\Rightarrow n(A\cap B)=2.[/tex]

Therefore, the number of 2-digit numbers that are multiples of either 5 or 7 is given by

[tex]n(A\cup B)=n(A)+n(B)-n(A\cup B)=18+13-2=29.[/tex]

Now, there are 90 2 -digit numbers.

Thus, the number 2-digit numbers are multiples of neither 5 nor 7 is

90 - 29 = 61.

Hence, the total number of numbers is 61.

Answer:

D

Step-by-step explanation:

Answer:

Graph B

Step-by-step explanation:

The pink line going downward to the right.

Answer:

Graph B

Step-by-step explanation:

The pink line going downward to the right.

Answer(s):

[tex]\displaystyle y = 4cos\:(4\theta \pm \pi) \\ y = -4cos\:4\theta[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Acos(B\theta - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pm\frac{\pi}{4}} \hookrightarrow \frac{\pm\pi}{4} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle y = -Acos(B\theta - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 4[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that this cosine graph will have TWO equations because the curvature begins upward from [tex]\displaystyle [0, -4][/tex] instead of downward from [tex]\displaystyle [0, 4],[/tex] telling you that one equation will have a “negative” symbol inserted in the beginning of the equation. Before we go any further though, we must figure the period of the graph out. So, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, -4],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{2}, -4],[/tex] they are obviously [tex]\displaystyle \frac{\pi}{2}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{2}.[/tex] Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 4cos\:4\theta.[/tex] Now, if you look hard enough, you will see that both graphs are “mirror reflections” of one another, meaning you can figure the rest of the terms out one of two ways. The first way is to figure the appropriate C-term out that will make the graph horisontally shift and map onto the original cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also, keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the rightward graph is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] on both sides of the y-axis, which means that in order to match the original graph, we need to shift the graph back, which means the C-term will be both negative and positive; and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pm\frac{\pi}{4}} = \frac{\pm\pi}{4}.[/tex]So, one equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4cos\:(4\theta \pm \pi).[/tex] Now that we got this out the way, we can focuss on finding the second equation. Another way is to write an equation with a “negative” symbol inserted in the beginning [like I mentioned earlier]. Now, sinse we are writing an equation with the negative, the graph will not have a horisontal shift; so, C will be zero. With this said, the second equation is [tex]\displaystyle y = -4cos\:4\theta.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended four units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

You can calculate the scale factor by dividing the coordinates of the image by the corresponding coordinates of the pre-image.

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

Assume that the initial coordinates are (x, y) and that the dilated coordinates are (x', y').

The dilation is therefore:

(x, y) → (x', y')

Now, let's assume that the dilation factor is k.

Therefore:

x' = kx

y' = ky

To get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k, which is the scale factor,

For example =

Assume an original point at (2,4) is dilated to coordinates (4,8) we need to find the dilation factor.

Assume the dilation coefficient is k.

(x, y) are (2,4) and (x', y') are (4,8)

Therefore:

x' = kx → 4 = k×2 → k = 2

or:

y' = ky → 8 = k×4  → k = 2

Based on the above, the dilation coefficient would be 2.

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