A bag of walnuts sells for$1.95 Estimate the cost of 8 bags of walnut

Answer:

The value of t test statistics is 4.518.

Step-by-step explanation:

We are given that director of a radio broadcasting company wants to determine whether the mean length of commercials on his station is equal to 24 seconds.

He samples 200 commercials, and finds that the average length of these commercials is 26.3 seconds, with a standard deviation of 7.2 seconds.

Let [tex]\mu[/tex] = mean length of commercials on his station.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 24 seconds     {means that the mean length of commercials on his station is equal to 24 seconds}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 24 seconds     {means that the mean length of commercials on his station is different from 24 seconds}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

                        T.S. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample average length of these commercials = 26.3 seconds

            s = sample standard deviation = 7.2 seconds

            n = sample of commercials = 200

So, test statistics  =  [tex]\frac{26.3-24}{\frac{7.2}{\sqrt{200} } }[/tex]  ~ [tex]t_1_9_9[/tex]  

                               =  4.518

The value of t test statistics is 4.518.

Answer:

  $2400

Step-by-step explanation:

Let x represent the amount invested at 9%. (3600-x) will be the amount invested at 8%. The total interest earned is then ...

  312 = 0.09x +0.08(3600 -x)

  24 = .01x . . . . subtract 288, simplify

  2400 = x . . . . divide by .01

$2400 was invested in the 9% account.

Using the median concept, it is found that the second quartile is of 86.

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile. The median is also called the second quartile, as [tex]\frac{2}{4} \times 100 = 50[/tex].

In this problem, there are 22 scores, which is an even number, hence the median is the mean of the 11th and the 12th scores.

From the stem-and-leaf plot, we have that:

Then:

(85 + 87)/2 = 86

The second quartile is of 86.

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To find the quartiles of a dataset, arrange the data in ascending order, determine the median (Q2), split the data into a lower half and an upper half (excluding the median if the number of data points is odd), and find Q1 and Q3 as the medians of these subgroups.

To find the quartiles for a set of test scores, first arrange the data from lowest to highest and then divide the dataset into four equal parts. The second quartile (Q2), also known as the median, separates the data into two halves. In this case, because we have 22 data points, the median will be the average of the 11th and 12th data points.

To calculate the first quartile (Q1), we find the median of the lower half of the data, which consists of the 10 scores below the overall median. Since we have an even number of data points in the lower half, Q1 will be the average of the 5th and 6th smallest scores.

Similarly, the third quartile (Q3) is the median of the upper half, consisting of the 10 scores above the overall median. Q3 will be the average of the 5th and 6th highest scores within this upper half.

The lower limit of the 95% confidence interval for the difference in mean credit card debt between female and male students can be calculated by formula using sample means, standard deviations, sample sizes, and accounting for the t-value associated with 95% confidence.

To calculate the 95% confidence interval for the difference between the mean credit card debt of female and male StatCrunchU students, we use the given information: µ1 (mean credit card debt of females) = 2577.75, µ2 (mean credit card debt of males) = 3809.42, std. dev. of females = 1916.29, std. dev. of males = 2379.47, number of females = 67, number of males = 33.

To calculate the confidence interval, we will use the t-model formula for confidence intervals for difference in means, which is:

(µ1-µ2) ± t*(sqrt([std. dev.1/sqrt(n1)] + [std. dev.2/sqrt(n2)]))

After plugging in the objective values, we would get the confidence range. The lower limit will be (µ1-µ2) - t*(sqrt([std. dev.1/sqrt(n1)] + [std. dev.2/sqrt(n2)])).

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Answer: 4 litres of air is held in Braydon’s tank.

Step-by-step explanation:

The law relating pressure to volume is the Boyle's law. It states that the volume of a given mass of gas is inversely proportional to its pressure as long as temperature remains constant. It is expressed as

P1V1 = P2V2

Where

P1 and P2 are the initial and final pressures of the gas.

V1 and V2 are the initial and final volumes of the gas.

From the information given,

V1 = 6 litres

P = 220 psi

P2 = 330 psi

Therefore,

6 × 220 = 330V2

V2 = 1320/330 = 4 litres

Answer:

V=1320/p

the tank holds 4 liters

Step-by-step explanation:

Answer: The owner reaches at Rs. 56438.28 after 30 years.

Step-by-step explanation:

Since we have given that

Sum = Rs. 17000

Rate of compounded daily = 4%

Number of years = 30 years

So, Using "compound interest formula" we get that :

[tex]A=P(1+\dfrac{r}{n})^{nt}\\\\A=17000(1+\dfrac{0.04}{365})^{365\times 30}\\\\A=17000(1.000109589)^{10950}\\\\A=56438.28[/tex]

Hence, The owner reaches at Rs. 56438.28 after 30 years.

Final answer:

The probability that a randomly selected golf ball from the bag is not a type A ball is 11/16, as we calculate this by dividing the number of non-type A balls (11) by the total number of balls (16).

Explanation:

The probability that the golf ball selected at random is not a type A ball can be found by first determining the total number of balls in the golf bag and then subtracting the number of type A balls to obtain the number of non-type A balls. The total number of balls is 5 type A balls + 8 type B balls + 3 type C balls = 16 balls. The number of non-type A balls is 8 type B balls + 3 type C balls = 11 balls.

To find the probability that the selected ball is not a type A ball, we divide the number of non-type A balls by the total number of balls, which gives us a probability of 11/16.

Final answer:

The probability that a randomly selected golf ball from the bag is not a type A ball is 0.6875 or 68.75%.

Explanation:

To find the probability that the golf ball selected at random is not a type A ball, we need to determine the total number of non-type A balls in the golf bag and divide it by the total number of balls in the bag. The golf bag contains 5 type A balls, 8 type B balls, and 3 type C balls, so the total number of balls in the bag is 5 + 8 + 3 = 16. There are 8 + 3 = 11 non-type A balls (type B and type C).

The probability of selecting a non-type A ball is then given by the number of non-type A balls divided by the total number of balls:

Probability = Number of non-type A balls / Total number of balls

We calculate it as:

Probability = 11 / 16 = 0.6875

Thus, the probability that the selected golf ball is not a type A ball is 0.6875 or 68.75%.

The question is a college-level mathematics problem focusing on statistics related to normal distribution, particularly the calculation of probabilities, defining a random variable, and understanding hypothesis testing and p-values.

The student's question pertains to the concept of normal distribution and statistics as applied to biological data. Specifically, it involves analysis using the mean and standard deviation of a dataset, and proper understanding of hypothesis testing and p-values in scientific research.

Understanding the Random Variable X

The random variable X, in this context, represents the duration of criminal trials. The question requires defining X and calculating related probabilities using the normal distribution properties. A probability statement and sketching of the graph would aid in visual understanding of the probabilities in question.

In statistical hypothesis testing, a p-value less than the level of significance (e.g., 0.01) typically leads to rejection of the null hypothesis, indicating evidence supporting the alternative hypothesis. The data on fruit flies' fecundity and genetic traits provided is an example of such an analysis.

Answer:

3

Step-by-step explanation:

the frequency of success is 244.

part b's answer is 240.

A relative frequency distribution shows the proportion of the total number of observations associated with each value or class of values and is related to a probability distribution, which is extensively used in statistics.

Relative frequency can be defined as the number of times an event occurs divided by the total number of events occurring in a given scenario. The relative frequency formula is given as:

Relative Frequency = Subgroup frequency/ Total frequency.

1. Frequency of success

=400 - 96 - 60

=244

relative frequency of fail

=60/400= 0.15

Relative Frequency of success

=1-0.15 - 0.24

=0.61

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Answer:

Step-by-step explanation:

given that Suppose that $2n$ tennis players compete in a round-robin tournament. Every player has exactly one match with every other player during $2n-1$ consecutive days.

this is going to be proved by contradiction

Answer: b. finding all studies published on a topic, calculating the effect size for each of those studies, and averaging the effect sizes together to find the average size of the effect across all studies.

Step-by-step explanation:

Answer:

Part (A)

Part (B)

Part (C)

Explanation:

0. Write the monthly cost and​ price-demand equations correctly:

Cost:

      [tex]C(x)=72,000+70x[/tex]

Price-demand:

      [tex]p(x)=300-\dfrac{x}{20}[/tex]

Domain:

        [tex]0\leq x\leq 6000[/tex]

1. Part (A) Find the maximum revenue

Revenue = price × quantity

Revenue = R(x)

           [tex]R(x)=\bigg(300-\dfrac{x}{20}\bigg)\cdot x[/tex]

Simplify

      [tex]R(x)=300x-\dfrac{x^2}{20}[/tex]

A local maximum (or minimum) is reached when the first derivative, R'(x), equals 0.

         [tex]R'(x)=300-\dfrac{x}{10}[/tex]

Solve for R'(x)=0

      [tex]300-\dfrac{x}{10}=0[/tex]

       [tex]3000-x=0\\\\x=3000[/tex]

Is this a maximum or a minimum? Since the coefficient of the quadratic term of R(x) is negative, it is a parabola that opens downward, meaning that its vertex is a maximum.

Hence, the maximum revenue is obtained when the production level is 3,000 units.

And it is calculated by subsituting x = 3,000 in the equation for R(x):

Hence, the maximum revenue is $450,000

2. Part ​(B) Find the maximum​ profit, the production level that will realize the maximum​ profit, and the price the company should charge for each television set.

i) Profit(x) = Revenue(x) - Cost(x)

       [tex]Profit(x)=300x-\dfrac{x^2}{20}-\big(72,000+70x\big)[/tex]

       [tex]Profit(x)=230x-\dfrac{x^2}{20}-72,000\\\\\\Profit(x)=-\dfrac{x^2}{20}+230x-72,000[/tex]

ii) Find the first derivative and equal to 0 (it will be a maximum because the quadratic function is a parabola that opens downward)

Thus, the production level that will realize the maximum profit is 2,300 units.

iii) Find the maximum profit.

You must substitute x = 2,300 into the equation for the profit:

Hence, the maximum profit is $192,500

iv) Find the price the company should charge for each television set:

Use the price-demand equation:

Therefore, the company should charge a price os $185 for every television set.

3. ​Part (C) If the government decides to tax the company ​$4 for each set it​ produces, how many sets should the company manufacture each month to maximize its​ profit? What is the maximum​ profit? What should the company charge for each​ set?

i) Now you must subtract the $4  tax for each television set, this is 4x from the profit equation.

The new profit equation will be:

ii) Find the first derivative and make it equal to 0:

Then, the new maximum profit is reached when the production level is 2,260 units.

iii) Find the maximum profit by substituting x = 2,260 into the profit equation:

Hence, the maximum profit, if the government decides to tax the company $4 for each set it produces would be $183,800

iv) Find the price the company should charge for each set.

Substitute the number of units, 2,260, into the equation for the price:

That is, the company should charge $187 per television set.

Final answer:

The question involves Mathematics and requires understanding of statistics and normal distribution to find z-scores for designing helmets to fit a specific range of male head breadths, accommodating all except the smallest and largest 4.3%.

Explanation:

The subject of this question is Mathematics, specifically focusing on statistics and the concept of normal distribution. Engineers designing helmets need to consider the breadths of male heads, which are normally distributed with a given mean and standard deviation. The design requirements stipulate that the helmets should fit all men except for those in the extremities of the distribution (smallest 4.3% and largest 4.3%).

To address such a problem, one would typically use the z-score to identify the cutoff points on a standard normal distribution that correspond to these percentages. The z-score represents the number of standard deviations a data point is from the mean. Therefore, the engineers must calculate the z-scores that correspond to the smallest and largest 4.3% of the distribution to determine the range of head breadths the helmets must accommodate.

Answer:

The correct option is;

Callie multiplied incorrectly

Step-by-step explanation:

Here we have 0.42 × 4.73 = 1.9866 then

1.9866 + 29.4 + 168 = 199.3866

Therefore, from the question, we had 0.42 × 4.73 = 1.26 which is incorrect, meaning that Callie multiplied incorrectly

Apparently, Callie multiplied as follows;

0.42 × 3 = 1.26 but what was in the question was

0.42 × 4.73 which is equal to 1.9866.

Answer:

Callie multiplied incorrectly

Step-by-step explanation:

all the credit goes to guy above me

Answer:

235 people

Step-by-step explanation:

Given:

P' = 15% = 0.15

1 - P' = 1 - 0.15 = 0.85

At 99% confidence leve, Z will be:

[tex] \alpha [/tex] = 1 - 99%

= 1 - 0.99 = 0.01

[tex] \alpha /2 = \frac{0.01}{2} = 0.005 [/tex]

[tex] Z\alpha/2 = 0.005 [/tex]

Z0.005 = 2.576

For the minimum number of 25-50 year old people who must be surveyed in order to estimate the proportion of non-grads to within 6%, we have:

Margin of error, E = 6% = 0.06

sample size = n = [tex] (\frac{Z\alpha /2}{E})^2 * P* (1 - P) [/tex]

[tex] = (\frac{2.576}{0.06}) ^2 * 0.15 * 0.85 [/tex]

= 235.02 ≈ 235

A number of 235 people between 25-30 years should be surveyed .

Answer:

n = 236

Step-by-step explanation:

Solution:-

- The proportion of people over the age of 50 who didn't graduate from high school are, p = 0.15 - ( 15 % )

- We are to evaluate the minimum sample size " n " from the age group of 25-50 year in order to estimate the proportion of non-grads within a standard error E = 6% of the true proportion p within 99% confidence.

-  The minimum required sample size " n " for the standard error " E " for the original proportion p relation is given below:

                             [tex]n = \frac{(Z_\alpha_/_2)^2 * p* ( 1 - p )}{E^2}[/tex]

- The critical value of standard normal is a function of significance level ( α ), evaluated as follows:

                            significance level ( α ) = ( 1 - CI/100 )

                                                                 = ( 1 - 99/100 )

                                                                 = 0.01

- The Z-critical value is defined as such:

                           P ( Z < Z-critical ) = α / 2

                           P ( Z < Z-critical ) = 0.01 / 2 = 0.005

                          Z-critical = Z_α/2 = 2.58

- Therefore the required sample size " n " is computed as follows:

                           [tex]n = \frac{(2.58)^2 * 0.15* ( 1 - 0.15 )}{0.06^2}\\\\n = \frac{6.6564 * 0.1275}{0.0036}\\\\n = \frac{0.848691}{0.0036}\\\\n = 235.7475\\[/tex]

Answer: The minimum sample size would be next whole number integer, n = 236.

Answer:

Step-by-step explanation:

It’s 1 3,and 4

Answer:

1,3,4

Step-by-step explanation:

Final answer:

None of the provided expressions have a greatest common factor of 3xy² with 42xy⁴ because they do not contain the necessary factors of 3, x, and y².

Explanation:

The student is asking for expressions that have a greatest common factor (GCF) of 3xy² with 42xy⁴. To find expressions with a GCF of 3xy², we need to look for expressions that include multiples of 3xy² in their factorization.

Looking at the provided expressions:

Therefore, none of the provided expressions have a GCF of 3xy² with 42xy⁴.

Answer:

a) [tex]P(E) = \frac{6}{8}[/tex]

b) [tex]P(F|E) = \frac{5}{7}[/tex]

c) [tex]P(E \cap F) = \frac{15}{28}[/tex]

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

We have that:

8 vehicles, of which 6 are vans.

a.) Let E denote the event that the first vehicle assigned is a van. What is P(E) ?

8 vehicles, of which 6 are vans.

So

[tex]P(E) = \frac{6}{8}[/tex]

b.) Let F denote the probability that the second vehicle assigned is a van. What is P(F|E)?

P(F|E) is the probability that the second vehicle assigned is a van, given that the first one was.

In this case, there are 7 vehicles, of which 5 are vans. So

[tex]P(F|E) = \frac{5}{7}[/tex]

c.) Use the results of parts(a) and (b) to calculate P(E and F)

[tex]P(F|E) = \frac{P(E \cap F)}{P(E)}[/tex]

[tex]P(E \cap F) = P(F|E)P(E)[/tex]

[tex]P(E \cap F) = \frac{6}{8}\frac{5}{7}[/tex]

[tex]P(E \cap F) = \frac{15}{28}[/tex]

The probability of the first vehicle assigned being a van is 3/4, and the conditional probability of the second vehicle being a van given the first was a van is 5/7. The probability that both vehicles assigned are vans is 15/28.

The subject of this question is probability, a topic in Mathematics. We are asked to find the probability of a certain event occurring under certain conditions.

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Answer:

54689

Step-by-step explanation:

Answer:

the interval would get bigger.

Step-by-step explanation:

if you wanted to be more confident in the interval you're giving, you would make more of the answers fit under the umbrella you're hypothetically creating.

Answer:

24 324

Step-by-step explanation:

21334 fda  adf

Answer: 24, 324

Step-by-step explanation:

Find the perimiter of both sides

Answer:-18-9=-17

Step-by-step explanation:

Answer:

-27

Step-by-step explanation:

Nine less than negative eighteen

[tex] - 18 - 9 = - 27[/tex]

Answer:

The test statistic t = 1.126 <  1.703 of '27' degrees of freedom at 0.05 level of significance.

null hypothesis(H₀ ) is accepted

There is evidence that the average breaking strength is  7.000.

Step-by-step explanation:

Step 1:-

Given random sample size (n) =28 <30

small sample size n= 28

The sample mean (x⁻) = 7.142

sample standard deviation (S) =0.672

Step 2:-

Null hypothesis :- there is evidence that the average breaking strength is  7.000.

H₀ : μ =7

Alternative hypothesis:-there is evidence that the average breaking strength is  7.000.

H₁ : μ ≠7

The test statistic [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]

Substitute all values and simplification ,

[tex]t = \frac{7.142 -7}{\frac{0.672}{\sqrt{28} } } = \frac{0.142 }{0.1269}[/tex]

t = 1.126

Calculated value is t = 1.126

The degrees of freedom γ = n-1 = 28-1 =27

The tabulated value t= 1.703 at degrees of freedom at 0.05 level of significance.

since  calculated t < tabulated value 't' value of 27 degrees of freedom at 0.05 level of significance.

null hypothesis(H₀ ) is accepted

There is evidence that the average breaking strength is  7.000.

Answer:

-3/2

Step-by-step explanation:

Answer:  x = -2/3 = -0.667

Answer:

14 sq cm

Step-by-step explanation:

7 × 4 = 28

28 ÷ 2 = 14

brainliest?

Answer:

it equals 1

Step-by-step explanation:

(5)(2)+2x−7=5

Step 1: Simplify both sides of the equation.

(5)(2)+2x−7=5

10+2x+−7=5

(2x)+(10+−7)=5(Combine Like Terms)

2x+3=5

2x+3=5

Step 2: Subtract 3 from both sides.

2x+3−3=5−3

2x=2

Step 3: Divide both sides by 2.

2x

2

=

2

2

x=1

Answer:

The standard error (SE) is 0.1847.

The t-statistic for this test is 2.490.

Step-by-step explanation:

We are given that the sample has a mean of [tex]\bar X[/tex] = 101.09 and a standard deviation of s = 0.4887 .

Also, the 7 sample values are also given.

Let [tex]\mu[/tex] = population mean.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 100.63  

Alternate Hypothesis, [tex]H_1[/tex] : [tex]\mu[/tex] > 100.63  

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

                         T.S. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = 101.09

            s = sample standard deviation = 0.4887

            n = sample values = 7

The Standard Error (SE) is given by =  [tex]\frac{s}{\sqrt{n} }[/tex]  =  [tex]\frac{0.4887}{\sqrt{7} }[/tex] = 0.1847

So, test statistics  =  [tex]\frac{101.09-100.63}{\frac{0.4887}{\sqrt{7} } }[/tex]  ~ [tex]t_6[/tex]

                                =  2.490

The value of t test statistics is 2.490.

Answer:

[tex] ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635[/tex]

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean [tex]\mu[/tex] is given by this formula:

[tex] \bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}} [/tex]

The confidence level on this case is 0.9 and the significance [tex]\alpha=1-0.9=0.1[/tex]

The confidence interval calculated on this case is [tex]60.128 \leq \mu \leq 69.397[/tex]

The margin of error for this confidence interval is given by:

[tex]ME =t_{\alpha/2} \frac{s}{\sqrt{n}} [/tex]

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

[tex] ME = \frac{Upper -Lower}{2}[/tex]

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

[tex] ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635[/tex]

And the best answer on this case would be:

b) m = 4.635

cones

cylinders

spheres

Step-by-step explanation:

The question was worded incorrectly and instead of giving the options it gave you the answers