Physics Middle School

A ball of mass 0.16 kg is moving forwards at a speed of 0.50 m/s. A second ball of mass 0.10kg is stationary. The first ball strikes the second ball. The second ball moves forwards at a speed of
0.50 m/s.
What is the speed of the first ball after the collision?​

Answers

Answer 1

Answer:

0.19 m/s

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(0.16 kg) (0.50 m/s) + (0.10 kg) (0 m/s) = (0.16 kg) v₁ + (0.10 kg) (0.50 m/s)

0.08 kg m/s = (0.16 kg) v₁ + 0.05 kg m/s

0.03 kg m/s = (0.16 kg) v₁

v₁ ≈ 0.19 m/s

Answer 2

Final answer:

After applying the conservation of momentum principle to the collision, the final velocity of the first ball after the collision with the second stationary ball is calculated to be 0.1875 m/s.

Explanation:

The subject of this question is Physics, specifically the conservation of momentum during collisions. When analyzing collisions, we use the principle of conservation of momentum, which states that the total momentum of a closed system before the collision is equal to the total momentum after the collision, provided no external forces act on the system. In the scenario given, a 0.16 kg ball moving at 0.50 m/s hits a stationary 0.10 kg ball which afterwards moves forward at 0.50 m/s. To find the speed of the first ball after the collision, we can set the total initial momentum equal to the total final momentum:

Initial momentum = (0.16 kg * 0.50 m/s) + (0.10 kg * 0 m/s)

Final momentum = (0.16 kg * v) + (0.10 kg * 0.50 m/s)

By solving the equation, we can find the final speed v of the first ball. The solution involves isolating v on one side of the equation.

Calculation:

0.08 kg·m/s = (0.16 kg * v) + 0.05 kg·m/s

0.08 kg·m/s - 0.05 kg·m/s = 0.16 kg * v

0.03 kg·m/s = 0.16 kg * v

v = 0.03 kg·m/s / 0.16 kg

v = 0.1875 m/s

The final velocity of the first ball after the collision is therefore 0.1875 m/s.

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