A basketball game was scheduled to last 606060 minutes, including the breaks between quarters. Several timeouts were used throughout the game, resulting in the game lasting a total of 727272 minutes, including breaks. If each timeout was 909090 seconds, how many total timeouts were used during the game?

Answers

Answer 1

Answer:

8

Explanation:

Total length of timeouts = no. of timeouts × length of each timeout

                                    T = n × l

Data:

Scheduled length of game = 60 min

      Actual length of game = 72 min

                                          l = 90 s

Calculations:

T = 72 - 60 = 12 min = 720 s

720 s = n × 90 s

      n = 720/90 = 8

There were eight timeouts during the game.


Related Questions

An animal shelter uses 21 cups of food to feed 12 dogs and 15 cats one meal each. How many cups of food are needed to feed one meal to 16 dogs and 20 cats?

Answers

Answer:

36 cup will be needed to feed one meal to 16 dogs and 20 cats.

Which expression is a sum of cubes?

Answers

Answer:

-27a³b⁶ + 8a⁹b¹²

Explanation:

Every term in the expression above every term is a perfect cube.

In the first term (-27a³b⁶), -27 is a perfect cube of -3 while the exponents of a and b are both divisible by three.

In the second term  (8a⁹b¹²),8 is a perfect cube of 2  while the exponents of a and b are divisible by three.

If the index of a number is divisible by three to give a whole number, the result of finding the cube root is a whole number hence a perfect cube root.

Answer:

A) [tex]-27a^{3}b^{6} + 8a^{9}b^{12}[/tex]

Explanation:

-27 can be divided by -3 and the cube root of 8a^9 b^12 is 2a^3 b^4

A town's chamber of commerce printed a map of the buisiness district. The map is 12 inches square, and 1 inch on the map represents an actual distance of 300 feet. On the map, a parking lot for one business is represented by a square with side length 0.25 inches. What is the actual area. In square feet, if the parking lot?

Answers

Answer:

[tex]\boxed{\text{5625 ft}^{2}}}[/tex]

Explanation:

On the map, 300 ft = 1 in

So, for the parking lot

[tex]\text{0.25 in} = \text{0.25 in} \times \dfrac{\text{300 ft}}{\text{1 in}} = \text{75 ft}[/tex]

The formula for the area of a square is

A = l², where l is the length of a side.

A = (75 ft)² = 5625 ft²

[tex]\text{The area of the parking lot is }\boxed{\textbf{5625 ft}^{2}}}[/tex]

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