Let say the basket ball is tossed upwards with initial speed "v"
now when it moves up in the air its speed will decrease due to acceleration of gravity in opposite direction
So here we can say that its final speed at the top position will be zero
here it will take t = 2.5 s to reach the top
now we can use equation of kinematics
[tex]v_f = v_i + at[/tex]
[tex]0 = v + (-9.8)*2.5[/tex]
now we have
[tex]v = 9.8 * 2.5[/tex]
[tex]v = 24.5 m/s[/tex]
so the ball is tossed up initially with speed 24.5 m/s
Use the drop-down menus to match each formula to the satellite motion characteristic it is used to solve.
ANSWERS:
Ac=centripetal accelration
Fc= centripetal force
V= tangential speed
Ac=centripetal accelration
Fc= centripetal force
V= tangential speed
The formulas Ac, Fc, and V represent centripetal acceleration, centripetal force, and tangential speed respectively. These are used in Physics to determine different aspects of a satellite's motion in a circular path.
Explanation:The given formulas in the question correspond to different aspects of satellite motion. Ac, or centripetal accelration, refers to the acceleration of an object moving in a circular path. This tends to be directed towards the center of the circle, hence the term 'centripetal'. The formula for centripetal acceleration is Ac = V^2 / r, where V is the velocity of the object and r is the radius of the circular path.
Fc, or centripetal force, is the force necessitated to keep an object moving in a circular path. This is calculated using the formula Fc = m * Ac, where m is the mass of the object and Ac is the centripetal acceleration.
Lastly, V refers to tangential speed, representing the constant speed of an object moving along a circular path. It can be calculated using the formula V = 2πr / T, where r is the radius of the circular path and T is the period of rotation (or time it takes for one complete rotation).
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A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A
horizontal force displaces the ball by 30o
to the vertical so that the string remains taut. Find:
a) the horizontal force.
b) the tension in the thread.
(a) the horizontal force is 11.3 N
(b) The tension in the thread is 22.6 N
Draw a free body diagram for the suspended metal ball as shown in the figure. The tension T acts along the length of the thread, the force F is the horizontal force and its weight is mg, which acts vertically down wards.
Resolve the tension into two components- T cos 30 along the vertical and T sin30 along the horizontal as shown in the figure.
Apply the condition for equilibrium along the horizontal direction.
[tex]F=Tsin30........(1)[/tex]
Apply the condition for equilibrium along the vertical direction.
[tex]mg=Tcos30.......(2)[/tex]
Divide equation (1) by equation (2) and write an expression for F.
[tex]\frac{F}{mg} = tan30\\ F=mgtan30[/tex]
Substitute 2 kg for m and 9.81 m/s² for g.
[tex]F=mgtan30\\ =(2kg)(9.81m/s^2)(tan30^o)\\ =11.3N[/tex]
The horizontal force required to keep the ball taut is 11.3 N
From equation (2),
[tex]T=\frac{mg}{sin30} \\ =\frac{(2kg)(9.81m/s^2)}{sin30^o} \\ =22.6N[/tex]
Thus, the tension in the thread is 22.6 N
What effects can occur when heat energy is added to a system?
Select all that apply.
increase in temperature
decrease in temperature
change of state
phase change
when heat energy is added to a system, change in system can be:
Increase in temperature: If system doesn't absorb the heat energy, then the effect will be increase in temperature.Change of state: If system absorbs the heat energy. And energy change in system can change the state of system.Phase change: If system absorbs the heat energy then the phase of system can be changed. For example liquid can be converted into vapors by adding heat energy to system.1. California sea lions can swim as fast as 40.0 km/h. Suppose a sea lion begins to chase a fish at this speed when the fish is 60.0 m away. The fish, of course, does not wait, and swims away at a speed of 16.0 km/h. How long would it take the sea lion to catch the fish?
2. A pet-store supply truck moves at 25.0 m/s north along a highway. Inside, a dog moves at 1.75 m/s at an angle of 35.0° east of north. What is the velocity of the dog relative to the road?
Please explain your work and give the formulas you used. Tysm <3!
Answer:
1) time t = 9 s
2) velocity v = 26.4 m/s 2.17° east of north
Explanation:
1
Given
velocity of sea lion [tex]v_s = 40.0 kmph[/tex]
velocity of the fish [tex]v-f = 16 kmph[/tex]
Distance between the fish and sea lion d = 60 m
Solution
Relative velocity of the sea lion with respect to the fish
[tex]v = v_s - v_f\\\\v = 40 - 16\\\\v = 24.kmph\\\\v = 24 \times \frac{1000}{60 \times 60} m/s\\\\v = 6.67 m/s[/tex]
Time
[tex]t = \frac{d}{v} \\\\t = \frac{60}{6.67} \\\\t = 9 s[/tex]
2
Given
velocity of the truck [tex]v_t = 25 m/s[/tex]
velocity of the dog [tex]v_d = 1.75 m/s[/tex]
Angle [tex]\theta = 35.0^o[/tex]
Solution
Dog moves in north east so
Component of velocity in East
[tex]v_{d,E} = v_dsin\theta\\\\v_{d,E} = 1.75 \times sin35\\\\v_{d,E} = 1.004 m/s[/tex]
Component of velocity in North
[tex]v_{d,N} = v_dcos\theta\\\\v_{d,N} = 1.75 \times cos35\\\\v_{d,N} = 1.434 m/s[/tex]
The velocity of Dog relative to the road = velocity of the dog relative to truck + velocity of the truck relative to the road
Y component
[tex]v_y = v_t + v_{d,N}\\\\v_y = 25 + 1.434\\\\v_y = 26.434 m/s[/tex]
X component
[tex]v_x = v_{d,E}\\\\V_x = 1.004 m/s[/tex]
Velocity
[tex]v = \sqrt{v_x^{2} +v_y^{2} } \\\\v = \sqrt{1.004^2 + 26.434^2} \\\\v = 26.4 m/s[/tex]
Direction
[tex]\phi = tan^{-1}\frac{v_x}{v_y} \\\\\phi = tan^{-1}\frac{1.004}{26.434} \\\\\phi = 2.17^o east of north[/tex]
For the time and velocity:
The sea lion will catch the fish in 0.42 seconds.
The velocity of the dog relative to the road is 26.41 m/s north.
How to find time and velocity?Question 1: Formula:
Relative velocity = vA - vB
The sea lion is moving at a relative velocity of 40.0 - 16.0 = 24.0 km/h faster than the fish.
The distance between the sea lion and the fish is 60.0 m, which is 0.160 km.
The time it takes the sea lion to catch the fish is:
time = distance / relative velocity
= 0.160 km / 24.0 km/h
= 0.007 h
= 0.42 seconds
Therefore, it would take the sea lion 0.42 seconds to catch the fish.
Question 2: Formula:
Relative velocity = vA + vB
The velocity of the dog relative to the road can be found by adding the velocity of the truck and the velocity of the dog.
The velocity of the truck is 25.0 m/s north.
The velocity of the dog can be broken down into two components: a northward component of 1.75 × cos(35.0°) = 1.41 m/s and an eastward component of 1.75 × sin(35.0°) = 1.18 m/s.
Therefore, the velocity of the dog relative to the road is 25.0 + 1.41 = 26.41 m/s north.
The direction of the velocity of the dog relative to the road is north.
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How much is the force of gravity on Mr.Arbo if his mass is 74.8kg?
Answer:
Force due to gravity in earth = 74.8*9.8 = 733.04 N
Explanation:
We have mass of Mr. Arbo = 74.8 kg
Force of gravity = Weight = Mass * Acceleration due to gravity value of planet.
In earth acceleration due to gravity value = 9.8[tex]m/s^2[/tex]
So force due to gravity in earth = 74.8*9.8 = 733.04 N
During a crash test, an air bag inflates to stop a dummy’s forward motion. The dummy’s mass is 75kg. If the net force on the dummy is 825 N toward the rear of the car, what is the dummy’s acceleration?
Mass of the dummy m = 75 kg
Net Force on the dummy [tex]F_{net} = -825 N[/tex] since it is given that the force is towards the backside of the car.
Acceleration of the dummy a = ?
Using Newton's 2nd law of motion, we have
[tex]F_{net} = ma[/tex]
-825 = (75)a
Hence, [tex]a = \frac{-825}{75}[/tex]
Acceleration of the dummy is -11 [tex]m/s^{2}[/tex]
The negative sign indicates that the dummy is slowing at a rate of 11 [tex]m/s^{2}[/tex]
Answer:
Acceleration towards rear = 11 [tex]m/s^2[/tex]
Acceleration towards direction of movement of dummy = -11 [tex]m/s^2[/tex]
Explanation:
Mass of dummy = 75 kg
Force acted towards rear of the car = 825 N
We have Force acting on a body = Mass of body * Acceleration of body
Substituting the given values in the above equation we will get
825 = 75 * a
a = 11 [tex]m/s^2[/tex]
So acceleration towards rear = 11 [tex]m/s^2[/tex]
Acceleration towards direction of movement of dummy = -11 [tex]m/s^2[/tex]
The planets stay in orbit due to
A.kinetics
B.friction
C.gravity
D.mass
The planet stay in orbit due to gravity. because the gravity of the sun keeps the planets in their orbits,
if a spring stores 5 j of energy when its compressed by 0.5 m. what is the spring constant
The elastic potential energy stored in a spring is given by:
[tex]E=\frac{1}{2}kx^2[/tex]
where k is the spring constant, and x=0.5 is the compression of the spring. Re-arranging the formula and using E=5 J, we find the spring constant:
[tex]k=\frac{2E}{x^2}=\frac{2(5 J)}{(0.5 m)^2}=40 N/m[/tex]
Spring constant = k = 10 N/m
Explanation:According to Hooke's law:
F = kx.
F = The force applied to the spring in newtons (N). k = The spring constant measured in newtons per meter (N/m).x = The distance the spring is stretched from its equilibrium position in meters (m).k = F/x
Putting values in above formula:
k = 5/0.5
k = 10 N/m
What are the 3 base units of measurement ?
In the SI (International, metric) system of measurement, they are the Kilogram of mass, the Meter of length, and the Second of time.
With mass, length, and time, you can combine them in enough ways to measure ALMOST everything that can be measured in the physical world, like speed, velocity, acceleration, momentum, area, volume, force, energy, pressure, etc.
'Almost'. You still need a few more to wrap things up. The other quantities (and their SI units) are: Electric charge (the Coulomb), temperature (the Kelvin), amount of a substance (the Mol), and luminous intensity (the Candela). You can't build these with only mass, length, and time.
The three base units of measurement in the International System of Units (SI) are the meter for length, the kilogram for mass, and the second for time.
Explanation:The three base units of measurement in the International System of Units (SI) are the meter (m) for length, the kilogram (kg) for mass, and the second (s) for time.
The meter is defined as the length of the path travelled by light in a vacuum during a time interval of 1/299,792,458 of a second.
The kilogram is defined by the Planck constant as exactly 6.62607015×10−34 kilogram square meter per second.
The second is defined by the cesium-133 atom in ground state, where one second is the duration of 9,192,631,770 periods of radiation corresponding to the transition between two energy levels.
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If two objects of unequal mass collide, both objects will continue to move in the direction ofL A. the smaller object's momentum B. the larger object's momentum C. the smaller object's resistance D. the larger object's resistance
Final answer:
Momentum determines the movement of two objects after a collision. The total momentum of a two-object system remains constant, generally resulting in motion towards the direction of the larger momentum. Option b
Explanation:
When two objects of unequal mass collide, the direction they will continue to move in after the collision is determined by the momentum they have. According to the principle of conservation of momentum, the total momentum of a system remains constant if no external forces are acting on it.
If we consider two cars with different masses in an inelastic collision, car 1 will slow down, losing some momentum, and car 2 will speed up, gaining momentum.
However, the momentum of the system (both cars) before and after the collision remains the same. The total momentum after the collision will move in the direction of the combined momentum of the two objects prior to the collision.
Generally, this would be in the direction of the object with the larger pre-collision momentum, but the exact direction and speed will depend on the masses and velocities of both objects. Option b
Why is it important to balance a chemical equation?
A. It is not important to balance a chemical equal
B. To make sure you have the correct products
C. To make sure you have the correct reactants
D. To obey the law of conservation of mass
The chemical equation of a chemical must be balanced to obey the law of conservation of mass. Therefore, option (D) is correct.
What is the balanced chemical equation?The equation in which the number of atoms of each element of reactants is equal to the number of atoms of each element of products is called a balanced chemical equation.
The law of conservation of mass obeys by a balancing of a chemical equation for a chemical reaction. According to this law, the mass of matter can neither be created nor be destroyed in a chemical reaction.
By following this law, the total mass of the elements on the reactant side should be equal to the total mass of elements on the product side in a balanced chemical equation.
An example of the balanced chemical equation is the formation of water:
2H₂ + O₂ → 2H₂O
On both sides of the arrow in the equation, the number of hydrogen and oxygen atoms is equal and so are their masses. Therefore this chemical equation obeys the law of conservation of mass.
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A stone falls freely from rest for 18 s. The acceleration due to gravity is 9.8 m/s 2. What was the stone’s displacement after that time? ans in m
-- At the end of 18sec, the stone's velocity is (9.8m/s² x 18s) = 176.4m/s downward.
-- Starting at 0 m/s and ending at 176.4m/s, its average velocity is 88.2m/s downward.
-- Falling for 18s at an average speed of 88.2m/s, it falls (88.2m/s x 18s) = 1,587.6 m .
-- Its displacement is 1,587.6 meters downward.
The stone's displacement after falling freely for 18 s under the acceleration due to gravity (9.8 m/s²) is 1587.2 meters.
Explanation:The displacement of an object in free fall can be determined using the equation of motion: S = ut + 0.5gt². In this case, the stone is dropped freely from rest, so the initial velocity (u) is 0 m/s. The acceleration due to gravity (g) is 9.8 m/s² and the time (t) is 18 s. Substituting these values into the equation, we get: S = 0 * 18 + 0.5 * 9.8 * (18)² = 0 + 0.5 * 9.8 * 324 = 1587.2 meters.
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If a spacecraft that seems to be motionless in deep space is given some type of quick push, what will happen?
A. The spacecraft will not move because it only works on earth.
B. The spacecraft will move and will not stop until it is stopped by an equal or opposite force.
C. The spacecraft will not move due to air resistance.
D. The spacecraft will move and then slowly come to a stop on its own.
the answer i believe is B
Answer:
B. The spacecraft will move and will not stop until it is stopped by an equal or opposite force.
Explanation:
From the first law of motion (given by Newton), a body continues to be in state of rest or motion, unless and until an unbalanced external force acts on it. This is also known as law of inertia.
So, according to this law, the spacecraft which is motionless would move when a push is given to it. It will now keep on moving until an equal and opposite force acts on it and stops it.
Thus, option B is correct.
how much work is done when you push a crate horizontally with 130 N across a 5.0-m
Complete solution is given below in attachment
Jim wants to learn more about the feeding habits of ants. What steps should he take in order to best study the patterns of ants?
The largest number of neurons within the brain and spinal cord are responsible for the central nervous system’s complex internal communication and intervene between jnputs and output these are the
Interneurons.
Their role is to receive signals from from the Sensory Neurons, process them, and communicate the decision to the Motor Neurons. They play a good role in Reflex Arcs.
dayshawn is traveling at 12 m/s away from the school. dayshaun's mom is looking for him because he is late coming home so she left the house and is driving toward the school at 5 m/s. The school is 6492 m from dayshauns house. at what position will dayshawn meet his mom and how long after she left the house did she find dayshaun? draw a motion map and solve. show your work
Speed of Dayshawn travelling towards his home is 12 m/s
Speed of her mom towards his school is 5 m/s
They both starts at same time so whenever they will meet on their path the sum of the distance covered by Dayshawn and distance covered by his mom must be equal to the total distance of school and home
Now let say they both meet after "t" time when they starts motion
so we can write the total distance between school and home as
[tex]d = v_1*t + v_2*t[/tex]
here d = 6492 m
[tex]v_1 = 12 m/s[/tex] = speed of dayshawn
[tex]v_2 = 5 m/s[/tex] = speed of his mom
now by solving the above equation
[tex]6492 = 12t + 5 t[/tex]
[tex]t = \frac{6492}{17}[/tex]
[tex]t = 381.9 s[/tex]
so they will meet after 381.9 s from start which will be 3.36 minutes from there start
Also at this time the distance covered by her mom will be
[tex]d_2 = v_2*t[/tex]
[tex]d_2 = 5* 381.9 = 1909.4 m[/tex]
so they will meet at distance 1909.4 m from their home
What can the arrow in a chemical reaction be translated to mean? Check all that apply
A. yields
B. accompanied by
C. react to form
D. added to
E. except
The arrow in a chemical reaction can be translated as the following:
A. yields
C. react to form
The arrrow in a chemical reaction is translated to mean a reactant combines to yield or react to form a product: Option A and C are correct.
Arrows in a chemical reaction are very important to differentiate between the reactants and the product.
They are used in chemical reactions to show that the reaction yields a particular product.
For instance, hydrogen reacts with oxygen to yield water as shown;
[tex]2H_2 + O_2 \rightarrow 2H_2O[/tex]
We can see that the arrow in the reaction shows that the reaction of hydrogen and oxygen element yields or react to form water.
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why do you choose MCB in place of a fuse？
It protects the electrical appliance and the person from electrical shocks/faults.
Hope it Helped!
Two carts (m= 0.4 kg each) are placed on an aluminum track. The first cart pushed with the initial velocity of 1.5 m/s towards the second cart, which remains at rest until the collision. Determine the velocities if both carts after the collision.
here two cars are placed on an aluminium track
so there is no friction on two carts during their motion and hence there is no external force on them
now if there is no external force so momentum is conserved
[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f][/tex]
here
[tex]m_1 = m_2 = 0.4 kg[/tex]
[tex]v_{1i} = 1.5 m/s[/tex]
[tex]v_{2i} = 0[/tex]
now plug in all values in it
[tex]0.4 * 1.5 + 0 = 0.4* v_{1f} + 0.4*v_{2f}[/tex]
divide whole equation by mass 0.4
[tex]v_{1f} + v_{2f} = 1.5[/tex]
also be the equation of coefficient of restitution
[tex]e = 1 = \frac{v_{2f} - v_{1f}}{v_{1i} - v_{2i}}[/tex]
now we have
[tex]v_{2f} - v_{1f} = 1.5[/tex]
now by solving above equations we will have
[tex]v_{2f} = 1.5 m/s[/tex]
[tex]v_{1f} = 0[/tex]
so after collision speed of two carts is 0 m/s and 1.5 m/s after collision
what did bohr contribute to modern atomic theory
Bohr’s model showed that electron orbits had distinct radii.
Answer:
bohr developed a model of the atom that predicts how it will behave
Explanation:
a p e x :)
In which situation is work not being done?
AS
work done =W = F.d = F d cosФ (Ф is angle between force F and displacement d) If a body/object is moving on a smooth surface (friction-less surface ) .There is no force acting on that body. F=0 so W=FdcosФ= (0)dcosФ ⇒ W=0
Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0
example: A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.
The third term upon which work done dependent is angle between force and displacement i.e Ф. If Ф=90° then W= FdcosФ= Fdcos90⇒ W=0 ( as cos 90°=0)
Answer: need more info
Explanation:
In an attempt to reduce our dependence on non–renewable resources, and cut down on the harm to the environment, we could burn ______ to produce electricity.
In an attempt to reduce our dependence on non-renewable resources, and cut down on the harm to the environment, we could burn biomass to produce electricity.
A sailor in a small sailboat encounters shifting winds. She sails 2.00 km east, then 3.50 km southeast, and then an additional distance in an unknown direction. Her final position is 5.80 km directly east of the starting point (Fig. P1.72). Find the magnitude and direction of the third leg of the journey. Draw the vectoraddition diagram and show that it is in qualitative agreement with Your numerical solution.
Answer:
Third displacement = 2.81 m which is 61.70° north of east.
Explanation:
Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
She sails 2 km east, displacement = 2 i
Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis
Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j
Let third displacement be x i + y j
We have final displacement = 5.80 km east = 5.80 i
From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j
= (4.47+x) i + (y - 2.47) j
Comparing both , we have 4.47+x = 5.80
x = 1.33
y-2.47=0
y = 2.47 j
So third displacement = 1.33 i + 2.47 j
Magnitude of third displacement = [tex]\sqrt{1.33^2+2.47^2} =2.81m[/tex]
θ = tan⁻¹(2.47/1.33) = 61.70°
So third displacement = 2.81 m which is 61.70° north of east.
How are force, mass and acceleration related?
Newton's 2nd law of motion:
F = ma
F is force, m is mass, and a is acceleration.
In the absence of air resistance, objects fall at constant
In the absence of air resistance , object fall with same acceleration .
In the absence of air resistance, objects fall at constant acceleration.
Object falling in absence of air resistance is tantamount to object falling in a vacuum. The experiment was performed in Italy by a Physicist known as Galilio Galilian. He dropped two different objects of different masses in the absence of air and discovered that they both landed at the same time.
The objects falling in the absence of air resistance will experience a free fall. And the formula for free fall are :
h = 1/2g[tex]t^{2}[/tex][tex]v^{2}[/tex] = 2ghV = gtNon of the above formula depends on the mass of the object but the acceleration due to gravity and the height at which they are falling.
And since the acceleration due to gravity is constant, therefore, In the absence of air resistance, objects fall at constant acceleration due to gravity.
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Which is a chemical property that can be used to identify calcium carbonate?
A. white color
B. powered solid
C. melting point of 825 °C (1517 °F)
D. reacts with acids by producing gas bubbles
Answer:
could someone at least give one answer instead of a choice between two cause that is a 50/50 chance to get it correct on a test!!
Explanation:
How can the rate of a reaction be decreased?
A. Lowering the temperature.
B. Increasing the amount of reactants.
C. Having more surface area.
D. Adding a Catalyst.
A. Lowering the temperature.
The anser is going to be A.Lowering the temperature.
I HOPE THIS HELPS YOU OUT ALLOT
How to get displacement
Suppose you have 100kg of fresh strawberries. What would be the approximate mass of the strawberries after freeze-drying
The mass of strawberries after freeze-drying would be significantly less than their original mass, given that most of the water content is removed during the process. For 100 kg of fresh strawberries, the approximate mass after freeze-drying would be about 8.4 kg, assuming 91.6% water content.
The approximate mass of strawberries after freeze-drying can be calculated by considering the water content in the fresh strawberries. Fresh strawberries consist of about 91.6% water. During the freeze-drying process, most of this water is removed, hence reducing the mass significantly.
To estimate this change in mass, we can subtract the mass of water (91.6% of the original mass) from the total mass of the fresh strawberries (100 kg). Thus, the dried strawberries would approximately be 8.4% of their original mass, since the mass of fructose and other non-water components remain. This is an estimation and the actual number can be slightly higher or lower depending on the exact freeze-drying process and the specifics of the strawberries.
Therefore, after freeze-drying 100 kg of fresh strawberries, which originally consist of 91.6% water, the approximate mass of the strawberries would be about 8.4 kg.