A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.5 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 4.9 m/s velocity to the east, what is the mass of the ball (in grams)? (NEVER include units in the answer to a numerical question.)

To achieve an interference pattern, we must have two coherent wave sources. For coherence, the waves must have the same frequency and either have no phase difference or a constant phase difference.

For two waves traveling in the same medium, having the same frequency implies having the same wavelength by v = fλ where v = velocity, f = frequency, and λ = wavelength.

An interference pattern requires all of the above conditions except for having the same amplitude.

Choice C

Answer:

e.) They all travel through space at the same speed.

All electromagnetic waves travel through space at the same speed. therefore the correct answer is option E

The oscillation of an electric field and a magnetic field produces electromagnetic waves, which are waves. In other words, electromagnetic waves (EM waves) are made up of vibrating magnetic and electric fields that are orthogonal to one another. Transverse waves are another name for electromagnetic waves since they move in a transverse direction.

These waves are used to transfer light & heat as a form of electromagnetic radiation, these electromagnetic waves are of various kinds such as radio waves, visible light, ultraviolet waves, x-rays, infrared waves, microwaves, gamma rays, etc.

All different kinds of electromagnetic waves have different wavelengths and frequencies but they all travel through space at the same speed of light.

Thus, All electromagnetic waves travel through space at the same speed. therefore the correct answer is option E

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Answer:

Neutrophils

Explanation:

Answer:

a) [tex]v_0=640[/tex] ft/s

b) [tex]y=H+1600[/tex] ft where[tex]H[/tex]  represents the height as the projectile was launched.

c)[tex]x=11085.13[/tex] ft

Explanation:

First, recognize the values that are given in the problem:

[tex]\alpha =30 ^o[/tex]

[tex]t_f=20[/tex]

[tex]y_f=H[/tex]

a) With those three use this formula: [tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2[/tex]

to find the initial velocity [tex]v_0[/tex].

[tex]\\y_f= H+v_0sin(\alpha)t_f-\frac{1}{2}gt_f^2 \\H= H+v_0sin(30)(20)-\frac{1}{2}(32)(20)^2 \\ -v_0sin(30)(20)=-\frac{1}{2}(32)(20)^2\\ v_0=\frac{\frac{1}{2}(32)(20)^2}{sin(30)(20)} \\ v_0=\frac{6400}{10} =640[/tex]

b) In order to find the maximum altitude, the time is needed to apply the formula. The maximum altitude is when the velocity in the y-axis is equal to zero, so use the formula for the velocity in the y-axis is to find the time, the formula is:

[tex]v_y=v_{0y}-gt\\v_y=v_0sin(\alpha)-gt\\0=(640)sin(30)-32t\\32t=(640)sin(30)\\t=\frac{(640)sin(30)}{32}=\frac{320}{32}=10[/tex]

With [tex]s=10[/tex]s use this formula for the altitude: [tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2[/tex]

[tex]y=H+v_0sin(\alpha)t-\frac{1}{2}gt^2\\y=H+(640)sin(30)(10)-\frac{1}{2}(32)(10)^2\\y=H+3200-1600\\y=H+1600[/tex]

Finally, the range is the maximum displacement in the x-axis, the formula of the  displacement is:

[tex]x=v_{0x}t=v_0cos(\alpha )t[/tex]

And the maximum occurs when[tex]t=20[/tex]s

[tex]x=v_0cos(\alpha)t\\x=640cos(30)(20)\\x=11085.13[/tex]

Answer:

kinetic energy is the energy an object contains due to motion while potential energy is stored energy that an object contains due to its position or shape.

hope this helps! (:

Answer:

Kinetic energy- is energy of an object which contains becuase of motion. Potential energy- is stored energy that an object contains because of its position or shape.

Answer: This law allows us to know how the illuminance  of the star varies with the square of the distance.

Explanation:

The Law of the Inverse of the Square for light, allows us to determine, in the case of a star, and considering it as a point source, how its illuminance  

[tex]E[/tex]  (power per unit area) varies with the square of the distance   [tex]r[/tex] that separates us from it when measuring its apparent brightness.

This law is expressed as follows:

[tex]E=\frac{I}{r^{2}}[/tex]

Where [tex]I[/tex] is the pointance (The flux power per unit solid angle, which is somehow analog with the intensity).

As we can see, as the distance from the light source increases, the illuminance decreases.

The inverse square law of light enables us to calculate the distance to a star by using its apparent brightness and known intrinsic brightness, especially through the use of standard candles in astronomy.

Assuming we can measure the apparent brightness of a star, the inverse square law of light allows us to calculate the distance to the star when we know its intrinsic brightness. This law states that the observed flux of an object decreases as the inverse of the square of its distance from the observer. When utilizing this principle in astronomy, the standardized luminosity of certain astronomical objects, commonly known as standard candles, is needed to determine their distance. For example, if we identify a main sequence star with a known spectral type, we can assume it has a similar luminosity to other stars with the same spectral type and thus calculate its distance by observing its flux and applying the inverse square law.

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, [tex]A \rightarrow B + C + Heat[/tex]

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction [tex]A \rightarrow B + C + heat[/tex], the potential energy of the products is less than that of the reactant.

The correct answer is: the potential energy of the products is less than that of the reactant.

Here's why:

The reaction notation A B + C + heat indicates an exothermic reaction. This means the reaction releases heat to the surroundings.

In exothermic reactions, the total potential energy of the products is less than the total potential energy of the reactants. The released heat signifies a decrease in the overall potential energy of the system.

Let's analyze the other options:

Net input of energy: This is the opposite of what's happening in an exothermic reaction. The reaction releases energy, not absorbs it.

Potential energy of products is the same: In some reactions, the potential energy might remain the same. However, the "heat" term in the notation signifies a release of energy, making this unlikely.

Entropy has decreased: Entropy, a measure of randomness, usually increases in most natural processes, including chemical reactions.

Answer:

Assume that [tex]\rm g= 9.81\; N\cdot kg^{-1}[/tex]; [tex]\rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}[/tex].

Density of the disk: approximately [tex]\rm 2.19\times 10^{3}\; kg\cdot m^{-3}[/tex].

Weight of the disk: approximately [tex]\rm 245\;N[/tex].

Buoyant force on the disk if it is submerged under water: approximately [tex]\rm 112\; N[/tex].

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

The radius of a circle is 1/2 its diameter:

[tex]\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m[/tex].

Volume of this disk:

[tex]V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}[/tex].

Density of this disk:

[tex]\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}[/tex].

[tex]\rho(\text{disk}) >\rho(\text{water})[/tex] indicates that the disk will sink when placed in water.

Weight of the object:

[tex]W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N[/tex].

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately [tex]\rm 0.0114009\; m^{3}[/tex] of water. The buoyant force on the disk will be:

[tex]\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}[/tex].

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

Explanation:

To start a fire it is more optimal to use a concave mirror than a plane mirror. This is because the concave mirror allows concentrating sunlight at a point (the focal point) on an object that acts as fuel and ignite the fire there.

For this it is necessary the object to be  positioned between the center of curvature of the mirror and the mirror (its focus). Thus the rays of the Sun, when converging on the focus, will heat the object and make it burn.

Hence, the correct option is B.

A concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature, is optimal for starting a fire using sunlight. This is due to the mirror's ability to concentrate parallel sunlight at a specific point.

The most accurate statement for starting a fire using sunlight and a mirror would be B) It would be best to use a concave mirror, with the object to be ignited positioned halfway between the mirror and its center of curvature. This is due to the properties of concave mirrors in focusing parallel beams of light, such as sunlight, to a single point. These mirrors can concentrate light at a specific point, effectively increasing the light's intensity and, hence, its heat. This is similar to how a magnifying glass can focus sunlight enough to ignite paper.

The statement C) is incorrect because positioning an object at the center of curvature would spread the light across the object, rather than concentrating it at a point. Convex mirrors (D), on the other hand, would focus light away from the object, making them unsuitable. The statement E) is untrue, as mirrors certainly can form real images and concentrate light to the point of starting a fire. The primary consideration here is the shape of the mirror and the positioning of the object to be ignited relative to the mirror's focal point.

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Answer:

Explanation:

I think the questionable statement is that Synthesizers have always been a well established presence in standard ensembles. The very earliest ones that were in common use came out in the 60s and 70s. A great many pieces of music had no use for them before that time. The Classical period lacked the electronics (completely) to make use of such modern equipment.

The False statement is ; Synthesizers have always had a well-established presence in standard ensembles ( C )

Synthesizers are used for the composition of musical sounds by  generating sounds from waveforms sent into it from musical instruments like keyboards. these waveforms produced are altered to produce the exact timbre, and volume as required by the composer. synthesizers are used for live performances

Synthesizers are made up of different parts with each part performing a specific function in the synthesizer and they are ;

Hence we can conclude that The False statement is Synthesizers have always had a well-established presence in standard ensembles

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Explanation:  

The expression for an Ideal Gas is:  

[tex]P.V=n.R.T[/tex]  

Where:  

[tex]P[/tex] is the pressure of the gas  

[tex]V[/tex] is the volume of the gas  

[tex]n[/tex] the number of moles of gas  

[tex]R[/tex] is the gas constant  

[tex]T[/tex] is the absolute temperature of the gas  

As we can see, there is a direct proportional relation between the temperature and the pressure, which means that if the temperature increases the pressure of the gas increases as well.

However, it is important to note this is fulfilled if and only if the volume of the container where the ideal gas is, remains constant.

Answer:

The sled slides 0.68m before rest.

Explanation:

Vi= 2 m/s

m= 60kg

μ= 0.3

N= m * g = 60kg * 9.8 m/s²= 588 N

Fr= μ * N

Fr= 176.4 N

a= Fr/m

a= -2.94m/s²

t= Vi/a

t= 0.68 seg

d= Vi*t - a*t²/2

d= 0.68m

Answer:

A) Magma emplacement

Explanation:

Sedimentary structures forms during deposition of sediments. It can also form after sediments have been deposited. Sedimentary structures can only be found in sedimentary rocks. Some examples include mud cracks, ripple marks, cross stratification, potholes, etc

Magma emplacement is an igneous process which describes the different mechanisms by which magma can be emplaced. It is only typical of igneous rocks.

Answer:

Velocity of the car decreases.

Explanation:

We can understand the situation if we apply the conservation of energy principle to the situation

Let the initial mass of the freight be [tex]m_{f}[/tex]

Initial velocity of the freight be [tex]v_{fi}[/tex]

Thus the initial Kinetic energy of the freight will be [tex]K.E=\frac{1}{2}m_{f}v_{if}^{2}[/tex]

When a Coal Block of mass M falls into the freight it's energy will become

[tex]K.E=\frac{1}{2}(m_{f}+M)v_{ff}^{2}[/tex]

Equating both the energies we get final velocity as[tex]v_{ff}[/tex]

[tex]\frac{1}{2}m_{f}v_{if}^{2}=\frac{1}{2}(M+m_{f})v_{ff}^{2}\\\\v_{ff}=\sqrt{\frac{m_f}{(M+m_{ff})}}\cdot v_{if}[/tex]

As we see that [tex]\sqrt{\frac{m_f}{(M+m_{ff})}}[/tex] is less than 1 we can infer that velocity decreases.

Final answer:

When coal is dumped into a moving freight car on a frictionless track, its velocity decreases due to the conservation of linear momentum, and the kinetic energy of the car decreases as a result.

Explanation:

If a large load of coal is suddenly dumped into an open freight car moving at a constant speed, the car's velocity will decrease due to the conservation of momentum. Since we are ignoring air resistance and assuming the track is frictionless, this scenario can be analyzed with the principle of conservation of linear momentum, which asserts that the total momentum of a closed system is constant if external forces are absent. In this case, the load of coal suddenly added to the freight car significantly increases the mass of the system without adding any horizontal momentum, as the coal is initially at rest relative to the horizontal motion of the car.

Considering the professional example provided, the initial momentum of the 30,000-kg freight car at a velocity of 0.850 m/s is m₁v₁. The final momentum, after 110,000 kg of scrap metal is added, must be the same as the initial momentum due to conservation of momentum. Thus, the final velocity v₂ can be found using the equation m₁v₁ = (m₁ + m₂)v₂, where m₂ is the mass of the scrap metal.

For the kinetic energy, initially, the car has a certain amount of kinetic energy due to its motion. After the additional scrap metal is dumped, the total mass of the car increases, and its velocity decreases, which corresponds to a decrease in kinetic energy. This lost kinetic energy can be computed by subtracting the final kinetic energy from the initial kinetic energy of the car before the coal was added.

Using the formula for velocity (v = u + at) with the given values, we find that the velocity of the ball 3 seconds after it's thrown upwards on a planet with a gravitational acceleration of 4.0 m/s2 is 12 m/s in the upward direction.

The question asks about the velocity of a ball 3 seconds after it's thrown upwards on a planet with a gravitational acceleration of 4.0 m/s2. We can use the formula for velocity which is the initial velocity plus acceleration times time (v = u + at). In this case, the initial velocity (u) is 24 m/s, the acceleration (a) is -4.0 m/s2 (negative because it's working against the upwards motion of the ball), and the time (t) is 3 seconds.

Substituting these values into the formula gives us v = 24 m/s + (-4.0 m/s2 * 3 s) = 24 m/s - 12 m/s = 12 m/s. So the velocity of the ball 3 seconds after it's thrown is 12 m/s in the upwards direction.

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Answer:

750 mm

Explanation:

Given:

d = 1.8 mm

R = 4.8 m

m = 5

y = 1

Using the equation

y = (mLR)/d ,

where,  

m gives a distance 'y' to that particular slit image.  

R = distance from the double slits to the screen

d = double slit separation distance.  

L = wavelength of the light.

substituting the values in the given equation

we get

L = [tex]\frac{1\times 1.8\times 10^{-3}}{5\times 4.8}[/tex]

or

L = 750 mm

Answer:

The wavelength of the monochromatic light is [tex]7.5\times10^{-7}\ m[/tex]

Explanation:

Given that,

Distance between the slits d = 1.8 mm

Distance of fringe from the slits D =4.8 m

Number of fringe m =1

Distance between the fringes = 1 cm

We need to calculate the wavelength of monochromatic light

Using formula of young's double slits

[tex]\lambda=\dfrac{Yd}{mD}[/tex]

Where, d = Distance between the slits

D = Distance of fringe from the slits

m = Number of fringe

y = Distance between the fringes

Put the value in to the formula

[tex]\lambda=\dfrac{1\times10^{-2}\times1.8\times10^{-3}}{5\times4.8}[/tex]

[tex]\lambda =7.5\times10^{-7}\ m[/tex]

Hence, The wavelength of the monochromatic light is [tex]7.5\times10^{-7}\ m[/tex]

Answer:

A and C are different elements, while D is an isotope of C

Explanation:

To identify an atom, we simply use the atomic number. The atomic number is the number of protons in an atom.

For a neutral atom, the number of protons is the same as the number of electrons in such an atom.

Isotopes of an element have the same atomic number (protons) but different mass number(proton + neutron) as a result of their different number of neutrons.

From the given information about the atoms, only the second option is correct:

A and C are different elements because their atomic number differs:

          A : 3 electrons, 3 protons and 3 neutrons

          C : 4 electrons, 4 protons and 3 neutrons

D is an isotope of C:

          C : 4 electrons, 4 protons and 3 neutrons

          D : 4 electrons, 4 protons and 4 neutrons

They have the same atomic number but the mass number differs due to their different number of neutrons.

Answer:

What is the fastest time trial for the first quarter checkpoint? 2.02 seconds

What is the slowest time trial for the first quarter checkpoint? 2.15 seconds

What is the range of times measured for this checkpoint? 0.13 seconds

Answer:

2.02

2.15

0.13

Explanation:

i did it on edge

Yes.  That's a true statement.  Ultrasound is indeed the name given to sounds with frequencies above the human range of hearing.  

Ultrasound is not different from "normal" (audible) sound in its physical properties, except that humans can't hear it.

Faraday's Law states that the magnitude of the emf induced in a coil is directly proportional to the rate of change of magnetic flux through it. Hence, a large magnetic flux change would induce a greater emf compared to a small flux change. This process of induction is foundational to many operational principles of electrical and electronic devices.

The concept asked in the question revolves around Faraday’s Law in Physics. According to Faraday’s Law, an electromotive force (emf) is induced in a coil when there is a change in magnetic flux through the coil. The magnitude of the induced emf is directly proportional to the rate of change of magnetic flux. Therefore, a large change in magnetic flux through a coil would induce a greater emf as compared to a small flux change.

So, if you were to suddenly increase the magnetic field strength (B) passing through a coil, this would represent a large change in magnetic flux (Ø), which as per Faraday's law, would induce a greater emf. Conversely, a slower or smaller change in magnetic field strength would lead to a smaller emf.

The process whereby a change in magnetic flux induces an emf is called electromagnetic induction. Remember, not only the magnitude of the magnetic field but also the orientation of the magnetic field (angle θ referenced in BA cos θ) with respect to the coil can affect the emf. Magnetic flux, Ø is given by BA cos θ, where B is the magnetic field strength, A is the area through which field passes and θ is the angle between B and A.

In application, a tangible example of this is the working of electric generators where a coil is rotated in a static magnetic field. The rotation changes the magnetic flux through the coil, hence inducing an emf according to Faraday’s Law. Induced emf is the fundamental principle behind the workings of many electrical and electronic devices we use in daily life.

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Answer:

266.5 newton

Explanation:

Weight of first object = 51 kg * 9.81

                                   =  500 N

Weight of second object = 81 kg *9.81

                                         = 794.61 N

As length of ladder is 15 m, the center of mass will be at 7.5 m.

Level arm is always perpendicular to the force. So the level of arm is at

7.5 sin θ.

τ ( wall) = τ (first object ) + τ ( second object)

N cos 30 ×15 = 794.61 sin 30 × 4  + ( 500 sin 30 ×7.5 )

13 N =  1589.22 + 1875

13 N = 3464.22

   N= 266.5 newton  

Answer:

Explanation:

Given that, .

Mass of ladder is 51kg

Then, it weight is

WL = mg = 51 × 9.81 = 500.31N

This weight will act at the midpoint of the ladder

Length of ladder is 15m

The ladder makes an angle 55°C with the horizontal

An object whose mass is 81kg is at 4m from the bottom of the ladder

Then, weight of object

Wo = mg = 81 × 9.81 = 794.61 N

Using newton second law

Check attachment

Ng is normal force on the ground

Ff is the horizontal frictional force

Nw Is the normal force on the wall

ΣFy = 0

Ng = Wo + WL

Ng = 794.61 + 500.31

Ng = 1294.92 N

Also

ΣFx = 0

Ff — Nw = 0

Then,

Ff = Nw

Now taking moment about point A.

Check attachment

using the principle of equilibrium

Sum of clockwise moment equals to sum of anti-clockwise moment

Also note that the Normal force on the wall is not perpendicular to the ladder, so we will resolve that and also the weights of ladder and weight of object

Clockwise = Anticlockwise

Wo•Cos60 × 4 + WL•Cos60 × 7.5 = Nw•Sin60 × 15

794.61Cos60 × 4 + 500.31Cos60 × 7.5 = Nw × Sin60 × 15

1589.22 + 1876.163 = 12.99•Nw

3465.383 = 12.99•Nw

Nw = 3465.383 / 12.99

Nw = 266.77 N

Since, Nw = Ff

Then, Ff = 266.77N

the horizontal force exerted by the ground on the ladder is 266.77 N

Answer:

Infinite Distance

Explanation:

The electric potential due to a point charge can be expressed by the following equation:

[tex]V=\frac{kQ}{r}[/tex]

Here,

V is the electric potential due to the point charge

k is the proportionality constant

Q is the magnitude of the point charge

r is the distance from the charge

As the value of r increases, the value of V decreases since there is an inverse relation between the two. The value of V can be absolutely 0 when the distance from the charge is infinite i.e. r is infinite. Mathematically, dividing a number by infinity results in zero. Also theoretically speaking, at infinite distance the electric field lines won't approach and hence the electric potential would be zero.

The electric potential due to a point charge is 0 V at a distance r from the charge when the charge is infinite.

The electric potential due to a point charge is 0 V at a distance r from the charge when the charge is infinite. In other words, if the point charge is far away from the observation point, the electric potential becomes zero. This is because the electric potential decreases with distance.

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Avogadro's number [tex]N_ {A}[/tex] is determined by the number of particles (or atoms) in a mole:

[tex]N_{A}=6.0221(10)^{23}/mol[/tex]

It should be noted that the mole is one of the seven fundamental units of the International System of Units and defines the amount of substance.

Therefore:

Avogadro’s number was calculated by determining the number of atoms in a mole.

(a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

(a)

The total resistance of the circuit is found as;

R=R₁+R₂

R=8 -ohm +6-ohm

R=14.0-ohm

(b)

The current in the 6.0-ohm resistor is;

The potential difference across the 6.0-ohm resistor= 12-V.

From Ohm's law;

V=IR

I=V/R

I=12-V/8-ohm

I=1.5-A

c)The potential difference across the battery is;

[tex]\rm I=I_1 \\\\ \frac{V}{R} =\frac{V_1}{R_1} \\\\\frac{V}{14} =\frac{12}{6} \\\\ V=28 \ volt[/tex]

Hence, a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

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The total resistance of the circuit is 14.0 ohms. The current in the 6.0-ohm resistor is 2 A. The potential difference across the battery is 28 V.

Let's analyze the series circuit step by step:

Answer: 1) 24.76 kJ/g

2)  597.4 kJ/mol

Explanation:

Let the heat released during reaction be q.

[tex]q=m\times c\times \Delta T[/tex]

q = Heat gained by water

m = Mass of water= 300 g

c = Heat capacity of water = 4.184 J/g°C

Change in temperature = ΔT = 1.126 °C

[tex]q=300\times 4.184\times 1.126=1413.3J[/tex]

Heat gained by bomb calorimeter = [tex]q_{cal}[/tex]

Heat capacity of bomb calorimeter , C = 1769J/g°C

Change in temperature = ΔT'= 1.126 °C

[tex]q_{cal}=m_{cal}\times c_{cal}\times \Delta T=C_{bomb}\times \Delta T=1769\times 1.126=1991.9J[/tex]

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

[tex]q_{combustion}=-(q_{water}+q_{cal}[/tex]

[tex]q_{combustion}=-(1413.3+1991.9)J[/tex]

[tex]q=3405J=-3.405kJ[/tex]

Thus 0.1375 g of magnesium releases 3.405 kJ of heat

1 g of magnesium releases =[tex]\frac{3.405}{0.1375}\times 1=24.76kJ[/tex] of heat

Thus heat given off by the burning magnesium, in kJ/g is 24.76.

Moles of magnesium =[tex]\frac{0.1375g}{24g/mol}=5.7\times 10^{-3}mol[/tex]

[tex]5.7\times 10^{-3}[/tex]  moles of magnesium releases 3.405 kJ of heat

1 mole of magnesium releases =[tex]\frac{3.405}{5.7\times 10^{-3}}\times 1=597.4 kJ[/tex] of heat

Thus heat given off by the burning magnesium, in kJ/mol is 597.4.

The heat given off by the burning magnesium is 0.27297 kJ. The heat given off per gram of magnesium is 1.984 kJ/g. The heat given off per mole of magnesium is 48.15 kJ/mol.

To calculate the heat given off by the burning magnesium, we need to use the equation q = mCΔT, where q is the heat, m is the mass, C is the heat capacity, and ΔT is the temperature change. In this case, the mass is 0.1375 g, the heat capacity is 1769 J/°C, and the temperature change is 1.126 °C.

Plugging in these values, we get q = (0.1375 g)(1769 J/°C)(1.126 °C) = 272.97 J.

To convert this to kJ, use the conversion factor 1 kJ = 1000 J. Therefore, the heat given off by the burning magnesium is 0.27297 kJ.

To find the heat given off per gram of magnesium, divide the heat by the mass of the magnesium: 0.27297 kJ / 0.1375 g = 1.984 kJ/g.

To find the heat given off per mole of magnesium, we need to convert the mass of the magnesium to moles using the molar mass of magnesium. The molar mass of magnesium is 24.31 g/mol.

Therefore, moles of magnesium = (0.1375 g) / (24.31 g/mol) = 0.00566 mol.

Divide the heat by the moles of magnesium to get the heat given off per mole: 0.27297 kJ / 0.00566 mol = 48.15 kJ/mol.

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Answer: The car if it weighs more than the horse

Explanation: Kinetic energy is proportional to the object's mass and velocity, so higher the mass and velocity the more kinetic energy it will have. In this case as all the objects have the same velocity we have to consider their masses and thus, the car assumingly has the greatest kinetic energy

Answer:

A car traveling at 35 miles per hour

Explanation:

Kinetic energy is the energy possessed by an object having motion. The kinetic energy depends on the mass and speed of the object:

K.E. = 0.5 mv²

In the given options, all the things have same speed. So, the kinetic energy can be compared on the basis of the mass. The car is the heaviest among the given four options. Thus, the car traveling at the 35 miles per hour has the maximum kinetic energy.

Answer:

[tex]v_{avg} = 0[/tex]

Explanation:

As we know that average velocity is defined as the ratio of total displacement of the object and its time interval.

so here we can say

[tex]v_{avg} = \frac{displacement}{time}[/tex]

now we know that in one complete revolution the total displacement of the tip of the seconds hand is zero

because it will have same position after one complete revolution from where it starts

so here we can say that the average velocity will be zero

[tex]v_{avg} = 0[/tex]

Final answer:

The average velocity of the second hand is 0 cm/s because it returns to its starting point after one minute, despite having an average speed of about 0.33 cm/s.

Explanation:

The tip of the second hand of a clock moving in a circle with a 20 cm circumference completes one revolution in one minute. Velocity is a vector quantity, which means it has both magnitude and direction. However, because the second hand returns to its starting point after one minute, its displacement is zero, and therefore its average velocity over one minute is 0 cm/s. If we were to consider average speed instead, which is a scalar quantity and only takes into account magnitude, the average speed can be found by dividing the total distance traveled by the time taken. Thus, the average speed would be 20 cm / 60 s, which is approximately 0.33 cm/s.

Answer:

Farther

Explanation:

In acceleration, if you were taking distance measurements of a free falling object at 1 second intervals, you see the object moving farther at each measurement interval.

Answer:

Option (a) is the correct answer

Explanation:

Option (a) smaller than P is the correct answer for the given question. This is because the pressure (P) at any depth 'd' from the top surface of the water with density (ρ)  is given as:

P = ρ × g × d

where,

g is the acceleration due to the gravity

thus from the above equation it can be concluded that the pressure at any depth 'd' is directly proportional to the density of the water.

thus,

in the given case the density of the water is lower than that in the first case.

Hence, the option (a) is the correct answer

Pressure at the bottom of a container filled with liquid depends on the density of the liquid, among other factors. When water is replaced with ethyl alcohol, which has a lower density, the resulting pressure at the bottom decreases. Therefore, the correct answer is (a) smaller than P.

The pressure at the bottom of a container filled with liquid is determined by the formula P = hρg, where P is the pressure, h is the height of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity. When the water (density 1000 kg/m³) is replaced with ethyl alcohol (density 806 kg/m³), the height of the liquid and gravity remain constant while the density decreases.

Since ρ in the term hρg has decreased, the overall product, i.e, the pressure at the bottom (P), also decreases. Therefore, when the glass is filled with ethyl alcohol, the pressure at the bottom of the glass is smaller than before. So, the correct answer is (a) smaller than P.

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Answer:

[tex]7.6\cdot 10^9 N/C[/tex]

Explanation:

The relationship between force exerted on a charge and strength of the electric field is given by

[tex]F=qE[/tex]

where

F is the strength of the electric force

q is the charge of the particle

E is the magnitude of the electric field

For the particle in the problem, we have

[tex]q=3.3\cdot 10^{-18} C[/tex]

[tex]F=2.5\cdot 10^{-8} N[/tex]

So the magnitude of the electric field at the location of the particle is

[tex]E=\frac{F}{q}=\frac{2.5\cdot 10^{-8}}{3.3\cdot 10^{-18}}=7.6\cdot 10^9 N/C[/tex]

Final answer:

The magnitude of the electric field at the given location is [tex]7.6 × 10^9 N/C.[/tex]

To calculate the magnitude of the electric field at a location, we can use the formula E = F/q, where E represents the electric field, F represents the force, and q represents the charge. In this case, we are given the charge of one particle as  [tex]+3.3 × 10^-18 C[/tex] between the particles as  [tex]2.5 × 10^-8 N[/tex]hese values into the formula, we get:

[tex]E = (2.5 × 10^-8 N) / (3.3 × 10^-18 C)[/tex]

Evaluating this expression, we find that the magnitude of the electric field at this location is approximately  [tex]7.6 × 10^9 N/C.[/tex]