A bicycle wheel is rotating at 49 rpm when the cyclist begins to pedal harder, giving the wheel a constant angular acceleration of 0.45 rad/s2 . what is the wheel's angular velocity, in rpm, 9.0 s later?

V=wavelength*frequency

3 m/s=wavelength*10 Hz

3m/s=10 Hz

wavelength= .3

Answer:

Wavelength of the wave, λ = 0.3 m

Explanation:

It is given that,

The speed of the wave, v = 3 m/s

The frequency of the wave, f = 10 Hz

We know the relationship between the frequency, wavelength and the speed of the wave. Mathematically, it can be written as :

[tex]speed=frequency\times lambda[/tex]

or

[tex]v=f\times \lambda[/tex]

[tex]\lambda=\dfrac{v}{f}[/tex]

[tex]\lambda=\dfrac{3\ m/s}{10\ Hz}[/tex]

[tex]\lambda=0.3\ m[/tex]

Hence, the wavelength of the wave is 0.3 m

The maximum acceleration would be 1.0 m/s² when this truck was towing a bus of twice its own mass

[tex]\texttt{ }[/tex]

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial acceleration = a₁ = 3.0 m/s²

mass of tow-truck = m₁ = m

mass of bus = m₂ = 2m

Asked:

final acceleration = a₂ = ?

Solution:

[tex]\texttt{Initial Force of Tow-Truck = Final Force of Tow-Truck }[/tex]

[tex]F_1 = F_2[/tex]

[tex]m_1 a_1 = m_2 a_2[/tex]

[tex]m (3.0) = (m + 2m) a_2[/tex]

[tex]3m = 3m (a_2)[/tex]

[tex]a_2 = 3m \div 3m[/tex]

[tex]\boxed{a_2 = 1.0 ~ \mathtt{ m/s^2}}[/tex]

[tex]\texttt{ }[/tex]

The maximum acceleration would be 1.0 m/s²

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

Answer: its C on edge 2023. =0.7

Explanation: He's right just putting it in a quicker format.

To calculate the time the supplies should be dropped before the plane is directly overhead, use the equation for free-fall motion and plug in the values given. The supplies should be dropped approximately 5.06 seconds before the plane is directly overhead.

To determine how many seconds before the plane is directly overhead the supplies should be dropped, we need to calculate the time it takes for the supplies to fall 160 m. We can use the equation for free-fall motion:

Time = sqrt((2 * distance) / g)

where distance is the height the supplies need to fall and g is the acceleration due to gravity. Plugging in the values, we get:

Time = sqrt((2 * 160 m) / 9.8 m/s²) ≈ 5.06 seconds

Therefore, the supplies should be dropped approximately 5.06 seconds before the plane is directly overhead.

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The box that Manuel is holding would exert a force of 49 N, directed downwards due to gravity. This calculation is done using the mass of the box and the acceleration due to gravity. According to Newton's third law, the force exerted by the box on Manuel would be in the opposite direction to which he lifts it.

The box that Manuel is holding exerts a force equal to its weight due to gravity. The weight can be calculated using the formula F = mg, where F is the force, m is the mass of the object, and g is the acceleration due to gravity. In this case, the mass of the box is 5 kg and assuming the acceleration due to gravity to be approximately 9.8 m/s², we can calculate the force as F = (5 kg) * (9.8 m/s²) = 49 N.

As for the direction, the direction of the force is always directed downwards or towards the center of the Earth because gravity is the force involved in this situation. To be more specific, the force that the box exerts on Manuel is in the opposite direction to which he lifts it, according to Newton's third law of motion which states that for every action, there is an equal and opposite reaction. Therefore, the box exerts a downward force of 49 Newtons on Manuel.

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The warmest field on a temperature map is indicated by warmer colors such as red or orange. On maps like those from the WMAP spacecraft, red represents higher temperatures. In thermographic maps of buildings, warmer areas show where heat transfer is most severe.

The warmest field on a map showing temperature variations can typically be found in regions marked with a warmer color, such as red or orange, indicating higher temperatures. In the context of the map used by the WMAP spacecraft to show fluctuations in the cosmic microwave background, red represents areas of higher temperature and higher density. Similarly, thermographic maps of buildings, like Figure 1.32, use color to indicate variations in temperature, with warmer areas potentially signifying regions where heat transfer is most severe, such as through windows.

It's important to carefully analyze the colors and legends provided on the map to determine the precise locations of the warmest fields. When maps show global temperature changes, such as Figure 24.9.5, the land areas and the Arctic are noted for having experienced the greatest increases in temperature relative to mid-20th-century baseline values.

The number of photons of blue light required is 42 photons of blue light

The number of photons of green light required is 53 photons of green light

The number of photons of red light required is 56 photons of red light

The energy of one photon of light is calculated using the formula:

E = h * c / λ

where h, Planck's constant  = 6.63 * 10⁻³⁴ Js

speed of light c = 3 * 10⁸ m/s

λ = wavelength of light

wavelength of blue light = 419 nm = 4.19 * 10⁻⁷ m

wavelength of green light = 531 nm = 5.31 * 10⁻⁷ m

wavelength of red light = 558 nm = 5.58 * 10⁻⁷ m

Number of photons of light = Energy of light / Energy of one photon of light

Energy of light required by optic nerve = 2.0 * 10⁻¹⁷ J

Energy of one photon of blue light,

E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 4.19 * 10⁻⁷ m = 4.74 * 10⁻¹⁹ J

Number of photons of blue light = 2.0 * 10⁻¹⁷ J / 4.74 * 10⁻¹⁹ J

Number of photons of blue light = 42 photons of blue light

Energy of one photon of green light,

E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 5.31 * 10⁻⁷ m = 3.74 * 10⁻¹⁹ J

Number of photons of green light = 2.0 * 10⁻¹⁷ J / 3.74 * 10⁻¹⁹ J

Number of photons of green light = 53 photons of green light

Energy of one photon of red light,

E = (6.63 * 10⁻³⁴ Js * 3 * 10⁸ m/s) / 5.58 * 10⁻⁷ m = 3.56 * 10⁻¹⁹ J

Number of photons of red light = 2.0 * 10⁻¹⁷ J / 3.56 * 10⁻¹⁹ J

Number of photons of red light = 56 photons of red light

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Here Ben checked the quality of three sanitizer

He took all three and checked how much effective each soap is to kill the bacteria

He analyzed and find out that both brands of soap were more effective in killing bacteria than the advertised hand sanitizer

He took his decision on the basis of quality so this is qualitative analysis

option C is correct

Answer:

It is C

Explanation:

Final answer:

The downward force on the parachute from the 66.0 kg person experiencing a downward acceleration of 2.60 m/s2 is 171.6 newtons, calculated using Newton's second law of motion (F = ma).

Explanation:

The question asks for the downward force on the parachute from a person with a mass of 66.0 kg experiencing a downward acceleration of 2.60 m/s2. To find this force, we use Newton's second law of motion, which states that force (F) equals mass (m) times acceleration (a), or F = ma.

To calculate the force, we multiply the person's mass (66.0 kg) by the given acceleration (2.60 m/s2):

F = 66.0 kg × 2.60 m/s2
 = 171.6 N

The downward force exerted on the parachute by the person is therefore 171.6 newtons, expressed to three significant figures.

The force act on the body tries to attract the body inward towards the circle when the body is executing circular motion. The maximum value of speed will be 13.3 m/sec.

The force operating on an object in curvilinear motion directed toward the axis of rotation or center of curvature is known as centripetal force.

Newton is the unit of centripetal force.

The centripetal force is always perpendicular to the direction of displacement of the item. The centripetal force of an item traveling on a circular route always works towards the center of the circle.

Due to rotation, the tension is act in the chord which is equal to the centripetal force act the ball.

[tex]\rm T = F_c= \frac{mv^2}{r}[/tex]

Tension in the cord  = T= 75 N

Centripetal force = [tex]F_c[/tex]

Mass of the ball= m= 0.55 Kg

Linear  speed =v= ?

The radius of the circle.= r = 1.3 m

T is the maximum tension before the cord breaks. So according to the condition the obtained velocity will be ;

[tex]\rm v = \sqrt{\frac{Tr}{m} } \\\\ \rm v = \sqrt{\frac{75\times1.3}{0.55} }\\\\ \rm v = 13.3 \;m/sec[/tex]

Hence the maximum value of speed will be 13.3 m/sec.

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Answer:

Flubber is a combination of two words Fluid+ Rubber. It means flubber has physical properties of both fluid and rubber(solid).

Physical properties of Flubber are as follows

1. It has elasticity like rubber

2. It can take the shape of the container in which it is filled. It does not have any particular shape like fluid.

3.It has viscoplastic nature

4. It is gelatinous

5. It flows under low pressure and can break when high pressure is applied on it.

The magnitude of the electric field at the surface of the wire in the Geiger counter can be found using the charge per unit length and the formula E = (1/(2πε0)) * (λ/r). Substituting the given values into the formula will yield the electric field at the wire's surface.

The student asked about calculating the magnitude of the electric field at the surface of the wire in a Geiger counter. To solve this, we will employ the formula for the electric field (E) generated by an infinitely long charged wire, which is given by E = (1/(2πε0)) * (λ/r), where λ is the charge per unit length and r is the radial distance from the wire. In this case, the charge per unit length λ is the total charge divided by the length of the wire, and r is the radius of the wire.

Given: Charge (Q) = 8.0 x 10-10 C, Length (L) = 10.0 cm = 0.1 m, and Wire radius (a) = 0.002 cm = 0.00002 m.

First, calculate the charge per unit length: λ = Q/L = (8.0 x 10-10 C) / (0.1 m) = 8.0 x 10-9 C/m.

Next, calculate the electric field using the radius of the wire (a) as radial distance (r): E = (1/(2πε0)) * (λ/a).

Using the value for the vacuum permittivity ε0 (approximately 8.854 x 10-12 C2/N·m2), the electric field on the surface of the wire is computed to be:

E = (1/(2π(8.854 x 10-12))) * (8.0 x 10-9 / 0.00002) N/C.

Simplifying this expression gives us the electric field at the surface of the wire.

Using the given values, the magnitude of the electric field at the surface of the wire (r = 0.002 cm or 0.00002 m) and L = 10 cm or 0.1 m is calculated as follows:

Convert the radius to meters: r = 0.002 cm = 0.00002 m.

Plugging in the values: E = (8.0 x 10-10 C) / (2π * 8.854 x 10-12 C2/Nm2 * 0.00002 m * 0.1 m).

Calculate the electric field: E = 2.87 x 106 N/C.

The magnitude of the electric field at the surface of the wire in the Geiger counter is therefore 2.87 x 106 Newtons per Coulomb (N/C).

The magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].

The magnitude of the electric field at the surface of the wire is given by the formula:

[tex]\[ E = \frac{\sigma}{\varepsilon_0} \][/tex]

where [tex]\( \sigma \)[/tex] is the surface charge density of the wire, and [tex]\( \varepsilon_0 \)[/tex]is the vacuum permittivity [tex](\( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \)).[/tex]

The surface charge density [tex]\( \sigma \)[/tex] can be calculated by dividing the total charge [tex]\( Q \)[/tex] by the surface area [tex]\( A \)[/tex] of the wire. The surface area of a cylinder is given by [tex]\( A = 2\pi r h \)[/tex], where [tex]\( r \)[/tex] is the radius and [tex]\( h \)[/tex] is the height (or length in this case) of the cylinder.

Given:

- Radius of the wire, [tex]\( r = 0.002 \, \text{cm} = 2 \times 10^{-5} \, \text{m} \) (since 1 cm = 0.01 m)[/tex]

- Length of the wire, [tex]\( h = 10.0 \, \text{cm} = 0.1 \, \text{m} \)[/tex]

- Total charge on the wire, [tex]\( Q = 8.0 \times 10^{-10} \, \text{C} \)[/tex]

First, we convert the radius from centimeters to meters for consistency in units:

[tex]\[ r = 0.002 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} = 2 \times 10^{-5} \, \text{m} \][/tex]

Now, we calculate the surface area of the wire:

[tex]\[ A = 2\pi r h = 2\pi (2 \times 10^{-5} \, \text{m})(0.1 \, \text{m}) \][/tex]

[tex]\[ A = 4\pi \times 10^{-6} \, \text{m}^2 \][/tex]

Next, we calculate the surface charge density [tex]\( \sigma \)[/tex]:

[tex]\[ \sigma = \frac{Q}{A} = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \][/tex]

[tex]\[ \sigma = \frac{8.0 \times 10^{-10} \, \text{C}}{4\pi \times 10^{-6} \, \text{m}^2} \approx \frac{8.0 \times 10^{-10}}{12.56637 \times 10^{-6} \, \text{m}^2} \][/tex]

[tex]\[ \sigma \approx 6.3662 \times 10^{-5} \, \text{C/m}^2 \][/tex]

Finally, we calculate the magnitude of the electric field at the surface of the wire:

[tex]\[ E = \frac{\sigma}{\varepsilon_0} = \frac{6.3662 \times 10^{-5} \, \text{C/m}^2}{8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2} \][/tex]

[tex]\[ E \approx 7.19 \times 10^{6} \, \text{N/C} \][/tex]

Therefore, the magnitude of the electric field at the surface of the wire is approximately [tex]\( 7.19 \times 10^{6} \, \text{N/C} \)[/tex].

Answer:

C. When there is an angle between the two directions, the cosine of the angle must be considered.

Explanation:

I can confirm answer is C.

Answer:

Explanation:

The amount of energy required to change the state of matter at constant temperature is called latent heat.

There are two types of latent heat.

1. Latent heat of fusion: The amount of heat required to convert 1 kg of ice at 0 degree Celsius into 1 kg water at 0 degree Celsius is called latent heat of fusion.

2. Latent heat of vaporization: The amount of heat required to convert 1 kg of water at 100 degree Celsius into 1 kg steam at 100 degree Celsius is called latent heat of vaporization.

The ability of small insects to walk on water is due to surface tension, which results from cohesive forces among water molecules. This tension creates a thin 'skin' at the water's surface that can support the weight of light objects, such as insects.

The ability of small insects to walk on the surface of still water can be best explained by the phenomenon of surface tension. Surface tension is created due to the cohesive forces between water molecules at the liquid-air interface. This cohesion results in a thin 'skin' forming at the surface, which can support the weight of small insects like water striders. These insects distribute their weight over their long legs, ensuring that the force they exert is less than the surface tension holding the water molecules together, allowing them to effectively 'walk' on water.

An example of this can be seen when a paper clip or a thin razor blade is carefully placed on the surface of water without sinking, demonstrating the strength of surface tension.

The weight of the bag of sports equipment is 98N

From the question,

We are to determine the weight of a bag of sports equipment that has a mass of 10.0 kg

The weight of an object with a given mass can be determined by using the formula

W = mg

Where

W is the weight

m is the mass

and g is the acceleration due to gravity (g = 9.8 m/s²)

From the given information,

m = 10.0 kg

∴ Weight of the bag of sports equipment,

W = 10.0 × 9.8

W = 98 N

Hence, the weight of the bag of sports equipment is 98N

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Final answer:

To find the speed of an electron with a given kinetic energy of 4.1e-18 J, use the non-relativistic kinetic energy formula. The calculation reveals the speed is approximately 2.7 x 10⁶ m/s, validating the use of the classical formula.

Explanation:

If the kinetic energy of an electron is 4.1e-18 J, calculating the speed of the electron involves using the non-relativistic kinetic energy formula, KE = ½mv², where KE is the kinetic energy, m is the mass of the electron (9.11 x [tex]10^-^3^1[/tex] kg), and v is the speed of the electron.

First, rearrange the formula to solve for v, resulting in v = √(2KE/m). Substituting the given kinetic energy and the mass of an electron, we get v = √([tex]2*4.1e^-^1^8[/tex] J / (9.11 x [tex]10^-^3^1[/tex] kg)). Calculating this provides a numerical value for the electron's speed.

After calculating, you'll find that the electron's speed is approximately 2.7 x 10⁶ m/s, which is fast but still less than the speed of light, indicating that using the non-relativistic formula is justified in this scenario.