A bird flies across your backyard at 4.0 feet per second. How many miles can the bird travel in 2.1 hours (rounded to the nearest tenth)?
A) 2.8 mi
B) 3.2 mi
C) 5.7 mi
D) 9.7 mi

Answers

Answer 1
1 minute = 60 seconds
1 hour = 60 minutes = 60*60 seconds = 3600 seconds
1 hour = 3600 seconds

Multiply both sides by 2.1 to get
1 hour = 3600 seconds
2.1*(1 hour) = 2.1*(3600 seconds)
2.1 hours = 7560 seconds

Now use the formula below
d = r*t
where,
d = distance
r = rate or speed
t = time

In this case,
d = unknown
r = 4 ft per sec
t = 7560 seconds (equivalent to 2.1 hours)

So,
d = r*t
d = 4*7560
d = 30240
The bird can travel 30240 feet. Convert this to miles by dividing the value by 5280 (since 1 mile = 5280 feet)

30240/5280 = 5.727 roughly which rounds to 5.7

Answer: C) 5.7 miles
Answer 2
Final answer:

The bird can travel approximately 5.7 miles in 2.1 hours.

Explanation:

To find the number of miles the bird can travel in 2.1 hours, we need to convert the speed from feet per second to miles per hour. There are 5280 feet in a mile and 3600 seconds in an hour, so the bird's speed is 4.0 * 3600 / 5280 = 2.727 miles per hour. Multiplying this speed by 2.1 hours gives us a total distance of 2.727 * 2.1 = 5.7207 miles, rounded to the nearest tenth, which is 5.7 miles. Therefore, the answer is option C) 5.7 mi.

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Related Questions

Please help me asap!!!

Answers

rewrite (1st) equation
-x -  2y = - 9
multiply the (1st) equation by 3 
-3x - 6y = -27

now you have
-3x - 6y = -27
 3x - 6y = -15
-----------------------add
-12y = -42
     y = 3.5

2(3.5) = -x + 9
7 = - x + 9
x = 2

answer
(2 ,  3.5)


which trig functions have a period of 2pi?

Answers

Tangent and its inverse, cotangent, have a period of pi. The others have a period of 2π.

At 9:00 am two cars started from the same town and traveled north on the same road. one ca traveled at a rate of 35 mph and the other at a rate of 40 mph. after how many hours will the cars be 30 miles apart

Answers

35 x 6 = 210 
40 x 6 = 240 

240 - 210 = 30 

so after 6 hours the cars will be 30 miles apart 

Convert 4 miles to feet.
20,210 feet
21,000 feet
21,120 feet
22,000 feet

Answers

21,120 feet is the right conversion
The answer would be 21,120 feet

Medal will be given to the best answer.


Which of the following is a solution to the equation y = 3x - 1 ?
A. (4,1)
B. (2,5)
C. (4,3)
D. (0, -3)

Answers

B. (2,5)  
For this problem, simply plug in the X values and calculate the Y value and verify that the Y value matches the value given. 
 A. (4,1); X = 4: 3x - 1 = 3*4 - 1 = 12 - 1 = 11. 11 does not match 1.
 B. (2,5); X = 2: 3x - 1 = 3*2 - 1 = 6 - 1 = 5. 5 matches 5.
 C. (4,3); X = 4: 3x - 1 = 3*4 - 1 = 12 - 1 = 11 does not match 3
 D. (0,-3); X = 0: 3x - 1 = 3*0 - 1 = 0 - 1 = -1 does not match -3
 
 And of the above, only option "B. (2,5)" matches.

Molly can either take her lunch or buy it at school. It cost $1.95 to buy lunch. If she wants to spend no more than $30 each month, how many lunches can she buy at most?

Answers

Final answer:

Molly can purchase a maximum of 15 school lunches per month with a budget of $30, considering each lunch costs $1.95.

Explanation:

The question asks how many school lunches Molly can buy if each lunch costs $1.95 and she wants to spend no more than $30 each month. To find out how many lunches Molly can buy, we divide her monthly budget by the cost of one lunch.

So, we perform the calculation: $30 ÷ $1.95 ≈ 15.38. Since Molly cannot buy a fraction of a lunch, we round down to the nearest whole number, which means Molly can buy 15 lunches at most in a month without exceeding her budget.

A jar made of 3/16-inch-thick glass has an inside radius of 3.00 inches and a total height of 6.00 inches (including the bottom thickness of glass). The glass has a density of 165 lb/ft3. The jar is placed in water with a density of 62.5 lb/ft3.
Assume the jar sits upright in the water without tipping over. How far will the empty jar sink into the water?

What is the volume of the glass shell of the jar? Precision 0.00

What is the weight of the jar? Precision 0.00

What is the weight of water the empty jar will displace? Precision 0.00

What is the volume of water the empty jar will displace? Precision 0.00

How far will the empty jar sink?

Answers

We can calculate the volume of a glass shell of the jar by calculating the total volume of a jar and then subtract the volume of air that fits in the jar (the space bounded by the shell).
The total volume of the jar is:
[tex]V_t=Bh=\pi h(r+a)^2[/tex]
Where h is the height of the jar, a is the thickness and r is the inner radius.
The volume of empty space, bounded by the jar, is:
[tex]V_e=B(h-a)=\pi r^2(h-a)[/tex]
The volume of a jar shell is the difference between these two:
[tex]V_s=V_t-V_e=\pi h(r+a)^2-\pi r^2(h-a)[/tex]
When we plug in all the number we get:
[tex]V_s=27.17 {$in}^3[/tex]
The weight of the jar is simply its volume times its density. We have to convert density of the glass:
[tex]165 \frac{lb}{ft^3}=\frac{165}{1728}\frac{lb}{in^3}=0.0949\frac{lb}{in^3}[/tex]
Now we can find the mass:
[tex]m_j=V_s\rho_j=27.17\cdot 0.0949=2.58 $lb[/tex]
The volume of water jar would displace depends how far the jar would sink.
There two forces acting on the jar when you put in the water. The first one is gravity and it's pulling the jar down. The second force is the buoyancy the and this force pushes the jar upward. In order for that jar to be stable, these two forces must be the same.
The buoyancy is given with this formula:
[tex]B=\rho gV_{disp}[/tex]
The volume of water that would be displaced by the jar can be expressed by this formula:
[tex]V_{disp}=\pi h'(r+a)^2[/tex]
Where h' is the height of the jar that is submerged in the water.
So the buoyancy force is:
[tex]B=\rho_w g\pi h'(r+a)^2[/tex]
This force must be equal to the force of gravity acting on the jar: 
[tex]F_g=B\\ m_jg=\rho_w g\pi h'(r+a)^2\\ m_j=\rho_w \pi h'(r+a)^2\\[/tex]
We solve for h':
[tex] h'=\frac{m_j}{\rho_w \pi(r+a)^2}[/tex]
If we plug in the number we get:
[tex]h'=2.24 $in[/tex]
Now we can calcuate the amount of water discplaced and its mas(keep in mind that we also converted density of water into lb/in^3):
[tex]V_{disp}=\pi h'(r+a)^2=71.50${in}^3\\ m_v=\rho_w\cdot V_{disp}=2.58$lb[/tex]
We get the same mass as the mass of the jar, which makes perfect sense:
[tex]m_jg=\rho_w V_{disp}g\\ m_j=m_{wdisp}[/tex]



Final answer:

The volume of the glass shell of the jar is 0.0136 ft³ and its weight is 2.24 lbs. The weight and volume of the water it will displace amounts to 2.24 lbs and 0.036 ft³ respectively. Consequently, the jar will sink approximately 2.2 inches into the water.

Explanation:

To begin, the volume of the glass shell of the jar will first need to be established. Given that the thickness of the glass is 3/16 inches, the outer radius of the jar is 3 inches + 3/16 inches = 3.1875 inches. To get the volume, utilise the formula for the volume of a cylinder, which is πr²h. Thus, with measurements converted to feet for the calculations (1 inch = 0.08333 foot), we have an external volume of π(0.265625 ft)² * 0.5 ft = 0.1118 ft³ and an internal volume of π(0.25 ft)² * 0.5 ft = 0.0982 ft³. Hence, the volume of glass is 0.1118 ft³ - 0.0982 ft³ = 0.0136 ft³

Next, the weight of the jar is determined by the formula mass = volume * density, so mass = 0.0136 ft³ * 165 lb/ft³ = 2.24 lbs.

To ascertain the weight of water the jar will displace, we consider the principle of buoyancy, which suggests that an object will displace a volume of fluid with a weight equal to its own weight. Thus, the weight of the water displaced is 2.24 lbs.

Then, the volume of this water is found with the formula volume = weight/density -> volume = 2.24 lbs / 62.5 lb/ft³ = 0.036 ft³.

Lastly, considering the jar will sink until the weight of the water being moved equals the weight of the jar. The volume of the water displaced equates to the submerged volume of the jar. Its depth in feet is then the volume divided by the cross-sectional area of the jar (internal radius), so the distance the jar sinks is roughly 0.036 ft³ / π(0.25 ft)²  = 0.18 ft -> convert to inches = 2.2 inches.

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The sum of two numbers is 240. the larger number is 6 less than twice the smaller. find the numbers. the smaller number is , and the larger number is

Answers

The sum of two numbers is 240. The larger number is 6 less than twice the smaller. Find the numbers.
----------
Let the smaller be "x" ; Larger is "2x-6"
EQUATION:

x + 2x-6 = 240

3x= 246

x = 82 (smaller)

2x-6 = 158 (larger)

The smaller number is 82 and the larger number is 158.

Given that, the sum of two numbers is 240.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the smaller number be x.

The larger number is 6 less than twice the smaller.

Larger number = 2x - 6

Now, the sum of two numbers is 240.

So, x+2x-6 = 240

⇒ 3x - 6 =240

⇒ 3x = 246

⇒ x = 82

Larger number = 240 - 82

= 158

Therefore, the smaller number is 82 and the larger number is 158.

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Choose the polynomial that is written in standard form. (1 point)


−3x5y2 + 4x3y + 10x2

−8xy2 + 4x4y2 + 3x3

x4y2 + 4x3y5 + 10x4

x6y2 + 4x3y8 + 10x7

Answers

Standard form is where the degree of each monomial decreases from left to right. Degree can be found by adding the exponents on each variable.

The only one where this is true is the first one.
The degree goes from 7 to 4 to 2

Answer:

[tex]-3x^5y^2+4x^3y+10x^2[/tex]

Step-by-step explanation:

A polynomial in two variables is in standard form if its monomial from left to right are arrangerd in descending order. We say that a monomial [tex]x^ay^b[/tex] is greater than a monomial [tex]x^{a^{\prime}}y^{b^{\prime}}[/tex] if [tex]a+b > a^{\prime} + b^{\prime}[/tex] or [tex]a+b=a^{\prime}+b^{\prime} \quad \text{and} \quad (a,b)>(a^{\prime},b^{\prime}})[/tex] in the alphabetical order.

For example

[tex]x^2y>xy \quad \text{since} \quad 2+1>1+1 \\\\x^2y>xy^2 \quad \text{since} \quad 2+1=1+2 \quad \text{and} \quad 2>1[/tex]

The polynomial [tex]-3x^5y^2+4x^3y+10x^2[/tex] is in standard form, since [tex]x^5y^2 > x^3y >x^2[/tex]. On the other hand, the polynomial [tex]-8xy^2+4x^4y^2+3x^3[/tex] is not in standard form since [tex]x^4y^2>xy^2.[/tex]

Hi need this done fast, please
Andrea is planting a rectangular garden with a length of 6 feet and a width of 5 feet. Her mother is planting another garden that is 60% of the length of Andrea's garden and 150% of the width of Andrea's garden.

The length of her mother's garden is--- feet, and the width is---- feet.

Answers

Length:
60% of 6 is 3.6

3.6 x 6 = 21.6


Width:
150% of 5 is 7.5

7.5 x 5 = 37.5

So her mothers garden should be 21.6 feet in length, and 37.5 feet in width.

The answer is 3.6 and 7.5

In your math class there are 15 boys and 21 girls. 12 of the boys and 15 of the girls are freshmen. if you randomly choose a student in your class, what is the probability that you'll choose a girl or a freshman?

Answers

Final answer:

The probability of randomly choosing a girl or a freshman from the class is 0.916 or 91.6%. This is calculated by considering the total number of girls and freshmen in the class, while avoiding double-counting freshman girls in the calculation.

Explanation:

To calculate the probability that a randomly chosen student from the class is either a girl or a freshman, we need to consider the total number of students in the class, as well as the number of girls and the number of freshmen. The class consists of 15 boys and 21 girls, totaling 36 students. Out of these, 12 boys are freshmen and 15 girls are freshmen, but we must avoid double-counting the girls who are also freshmen.

First, we calculate the total number of freshmen: 12 boys + 15 girls = 27 freshmen. Next, we calculate the probability of picking a girl: 21 girls / 36 total students = 0.583 (to three decimal places). We then calculate the probability of picking a freshman: 27 freshmen / 36 total students = 0.750. However, since the freshmen include both boys and girls, we must subtract the probability of picking a freshman girl to avoid double-counting: 15 girls who are freshmen / 36 total students = 0.417.

Finally, we add the probability of picking a girl and the probability of picking a freshman, and subtract the probability of picking a freshman girl to obtain the inclusive probability: 0.583 (girl) + 0.750 (freshman) - 0.417 (freshman girl) = 0.916.

Therefore, the probability that a randomly chosen student is either a girl or a freshman is 0.916, or 91.6%.

Can someone explain the Pythagorean theorem to me, please?

Answers

Pythagorean theorem is applied to the right triangles. 

Pythagorean theorem is a²+b²=c².

a is the length is the leg, b is also a leg and c is the hypotenuse

On a rombus AB=27, m

Answers

Angle ADC = 180- 74 = 106 degrees

Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.

Answers

sum of the angles of any quad =360
then y+(x+2)+(x-2)+(x-10) = y +3x -10 =360 (by adding both sides by 10)
y + 3x =370 ;.... eq 1
the sum of each two opposite sides in a quad inscribed in a circle =180
then (x+2)+(x-2)=180 
therefore 2x =180
therefore x=90  (sub in eq 1)
y+3*90 =y +270 = 370 (subtracting both sides by 270)
therefore y=100
then measure angle B=100 degrees
A=92 degrees
C=88 degrees
D=80 degrees

The following is an idealized equation representing the world population of Leatherback turtles, where t represents time in years since 1970.

f(t) = 50,000(.92)^t

How would you determine the population in the year 2000?

Is this a growth or a decay function?

How can you tell a growth or decay function just by looking at it?

Answers

In this case t = 2000 - 1970 = 30 
so population in 2000 = 50,000 * (0.92)^30  =  4098 Asawer
This is a function of decay.

The function is decay because the number in the parentheses is < 1. 

Taylor is competing in a 30 km race. She has already run 12.35 km through a park and swam 3.75 km. She will bike the rest of the way. Round each distance to the nearest km. About how far does Taylor need to bike to finish the race? A. about 12 km B. about 13 km C. about 14 km D. about 23 km

Answers

C. about 14 km
12km + 4km = 16km
30km - 16km = 14km

Suppose that x=6 and y=8. If y is inversely related to x, what it y when x=3?

4
5
16
18

Answers

X equals 6 and y equals 8 and y is complete buddies with x, Y would definitely be 4 when x is 3 because they are halved. Half of 6 is 3 and half of 8 is four. If we half them both we get our answer. 5, 16, and 18 would all be classified as incorrect answers.

Credit to: Jdoe0001.

C. 16

If it takes bottling machine to fill 150 bottles per minute, how many minutes will it take the machine to bottle 4500 bottles

Answers

It takes bottling machine to fill 4500 bottles in 30 minutes.

I would like help with the question. It's part of my assigment, but I have trouble with this type of math. If someone understands, can you explain it to me as well? For future reference?

In Panama City in January, high tide was at midnight. The water level at high tide was 9 feet and 1 foot at low tide. Assuming the next high tide is exactly 12 hours later and that the height of the water can be modeled by a cosine curve, find an equation for water level in January for Panama City as a function of time (t).,

Answers

The cosine function cos(x), as you know, has a peak at x=0, a minimum at x=π, and another peak at x=2π. That is, its period is 2π. Its amplitude is 1, meaning the peak is +1 and the minimum is -1.

Problems where sine or cosine functions are used to model periodic behavior are problems in scaling. You need to match the period and amplitude of your scaled cosine function to the period and amplitude of the phenomenon you are modeling.

Here, high tides are 12 hours apart, so we need to scale x by a factor that turns 12 hours into 2π. That might be x ⇒ 2πx/12 or (π/6)x.

The high tide is 9 ft, and the low tide is 1 ft, so we need to do vertical offset and scaling to make the peak of our transformed cosine function be 9 and its minimum be 1. That difference is 8, so has an amplitude of ±4 around a midline of (9+1)/2 = 5.

Then our tide model is
.. water level = 5 +4*cos((π/6)t)

The dollar value v(t) of a certain car model that is t years old is given by the following exponential function.

V(t)=24,500(0.95^t)

Find the initial value of the car and the value after 13 years.
Round answers to the nearest dollar as necessary.

Answers

The value after 13 years will be 12576.9 dollars if the dollar value v(t) of a certain car model that is t years old is represented by the exponential function.

What is an exponential function?

It is defined as the function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent y = a^x

where a is a constant and a>1

It is given that:

The dollar value v(t) of a certain car model that is t years old is given by the exponential function.

[tex]\rm V(t)=24,500(0.95^t)[/tex]

The initial value plug t = 0 in the above function:

V(0) = $24500

Plug t = 13 years in the above exponential function

[tex]\rm V(13)=24,500(0.95^1^3)[/tex]

After calculating, we get:

V(13) = 12576.88

V(13) = 12576.9 dollars

Thus, the value after 13 years will be 12576.9 dollars if the dollar value v(t) of a certain car model that is t years old is represented by the exponential function.

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What equation results from completing the square and then factoring x^2-12x=58

Answers

The correct answer is (x - 6)2 = 94


Answer:

A for me

Step-by-step explanation:

what is the answer too......5(x+9)

Answers

Hi there!

To solve for x in this problem, we need to distribute the 5 using the distributive property and then simplify.

5 * x + 5 * 9
= 5x + 45

So, the most simplified form of this expression would be 5x + 45.

Hope this helps!
5(x+9) distribute the 5 to the x and 9.
5*x + 5*9 =
5x + 45
You have to get the x alone so divide both of them by 5
5x/5 + 45/5 = 
x + 9 
To get the x alone subtract it. 
x - x + 9 = 
9 = -x  can't leave x a negative so dived both sides by -1
9/-1 = -x/-1 =
-9 = x or x = -9
Hope this Helps!

How do I solve this?

Answers

This problem can be worked with units of feet in the vertical direction and units of inches in the horizontal direction, as long as you maintain that relationship.

I find it convenient to draw a graph of a line that represents the ladder. I choose to have the y-intercept be where the ladder touches Catie's head (5.5 feet above the ground), and the x-intercept to be where the ladder touches the ground, 16 inches away from Catie.

Then the wall is 4.5 feet (54 inches) from the ladder's base, or 38 inches in the other direction from Catie. The graph shows the ladder hits the wall at a height of about 18.6 feet.

The graph shows the calculations for the position of the wall and for the equation of the line. (The line is written in "intercept form.") The graphing calculator shows the intercept points, so no "work" is required except to highlight them.

Matt is saving to buy a new motorcycle. If he deposits $60 at the end of each month in an account that pays an annual interest rate of 3.5%, how much will he have in 15 months? Assume that the compounding is being done monthly.,

Answers

This is a problem of compound interest because the interest received one month is added to the money deposited on which you calculate the interest the next month.

You need to apply the following formula:
C = P[ [tex] (1+r)^{t} [/tex] - 1]
where:
C = compound interest you need
P = original amount of money deposited
r = is the rate, written as a rational number
t = number of months

Pluggin in numbers:
C = 60[ [tex] (1+0.035)^{15} [/tex] - 1] = 40.52$

Now, you need to add this amunt to the original amunt:
(60+40.52) = 100.52$

Therefore, Matt will have 100.52$ after 15 months.

PLEASE SOMEONE HELP ME WITH THIS
Hurryyy!!!!
ASAP~ BRAiNLiEST AVAILABLE TO CORRECT ANSWER

1st Blank options : +6, +1, +7, +13
2nd blank options: 7,13, 6, 1
3rd blank options: +6 , -1 , +7 , +1
4th blank options: 71 ,59, 69, 61

Answers

Look at the beginning of the recursive formula:

[tex]\sf f(1)=7,f(n)=f(n-1)[/tex]

It gives us the first value, which is 7. The second part means that for whatever term we want to find, we plug that in for 'n'. Say we want to find the second term, let's plug in 2 for 'n':

[tex]\sf f(2)=f(2-1)=f(1)[/tex]

We are left with f(1), which is given as 7. So the second term is 7 and then we have the leftover blank. We already know that the second term is 13. 13 - 7 = 6. Therefore, what must be missing from this recursive formula is + 6.

[tex]\sf f(n)=f(n-1)+6[/tex]

For the explicit function, we want to know what will give us these same values if we plugged in which term we want for 'n'. So if we plugged in 1 for 'n', we want to get 7, and if we plugged in 2 for 'n' we want to get 13, and so on. I can spot the similarity that all of these are additions of 1 to the multiples of 6. 6 * 1 = 6 + 1 = 7, 6 * 2 = 12 + 1 = 13, and so on. We could just write this as:

[tex]\sf 6n+1[/tex]

If you tried plugging in 1, you'd get 7, if you plugged 2 in, you'd get 13, and so on. So this is our explicit formula, the 2nd blank should be 6, and the 3rd blank should be + 1.

For the fourth blank, f(10) would just be plugging in 10 for 'n' into our formula, let's do this:

[tex]\sf 6n+1[/tex]

[tex]\sf 6(10)+1[/tex]

Multiply:

[tex]\sf 60+1[/tex]

Add:

[tex]\sf 61[/tex]

So the 4th blank should be 61.
1st blank: each term is 6 more than the previous one, so the appropriate choice is "+6"

2nd blank: The way we write the generic term of an arithmetic sequence is
  a[n] = a[1] +d*(n -1)
You have a[1] = 7 and d = 6, so this is
  a[n] = 7 +6*(n -1) = 6 +6n -6 = 6n +1
The appropriate choice for the 2nd blank is "6"

3rd blank: see the discussion for the 2nd blank. The appropriate choice is "+1"

4th blank: a[10] = 6*10 +1 = 61. The appropriate choice is "61"

am i correct?

Which of the following describes how to translate the graph of y = |x| to obtain the graph of y = |x + 1| - 2?


shift right 1 and down 2
shift left 1 and down 2 <<<
shift right 1 and up 2,

Answers

You are actually incorrect, as setting x=0 shows that the shifted graph needs to hit the y-axis at -2 (a downshift of 2). Similarly setting y=0, we find that x then becomes -1, since the absolute value of x +1 =0 implies that x=-1. So the correct answer is actually a shift down of 2 and left of 1.

Answer: both of u are wrong its one unit shift up one unit shift down


10 POINTS + BRAINLIEST ANSWER!!

Let the function f be defined by f(x) = (x - 1)(x + 7). Which of the following is an equivalent form of f in which the minimum value of f appears as either a coefficient or a constant?

A. f(x) = x^2 - 7

B. f(x) = x^2 + 6x - 7

C. f(x) = (x + 3)^2 - 16

D. f(x) = (x - 3)^2 - 20

Answers

B. f(x) = x^2 + 6x - 7

All you have to do is foil 

Please help asap!!! 16 points ):

Answers

This is a line on the x axis because it does not intersect with the y axis at all. The line is at x=3 and is a vertical line. If the line was x=-3, it would be to the left of (0,0), but it is positive to the right of the x and y intersection.

ANSWER: D) x=3

Hope this helps! :)

How do I solve this? Please explain.

Answers

Volume is the product of base area and height.

The first candle will have a volume of
.. V = Bh = (21 cm^2)*(8 cm) = 168 cm^3

The second candle will have a volume of
.. V = Bh = (7 cm^2)*(14 cm) = 98 cm^3

The total volume of the two candles is
.. 168 cm^3 +98 cm^3 = 266 cm^3

Josie is 6 cm^3 short of the amount required for the two candles she has in mind.

No, the base area of the second candle cannot be 7 cm^2. There is not enough wax to make a candle with that area 14 cm tall.

PLEASE HELP ME ASAP
PLEASE

Answers

Answer
Choice D
Company 2 is greater in avg rate of change by $750

=======================================

Explanation:

Average rate of change is the same as slope through two points. The two points are the endpoints of the interval. 

The x values we'll use is x = 0 and x = 12 since it constitutes the first 12 years (12-0 = 12)

For company 1, if x = 0 and x = 12, then y = 12000 and y = 30000 respectively. The two points (0,12000) and (12,30000) are on the graph for company 1
The slope of the line through these two points is
m = (y2-y1)/(x2-x1)
m = (30000-12000)/(12-0)
m = 18000/12
m = 1500
Over the first twelve years, the average rate of change for company 1 is 1500

For company 2, the points (0,15000) and (12,42000) are on the graph
The slope of the line through these two points is
m = (y2-y1)/(x2-x1)
m = (42000-15000)/(12-0)
m = (27000)/(12)
m = 2250
Over the first twelve years, the average rate of change for company 2 is 2250

Now find the difference in the slopes
2250-1500 = 750

Company 2's rate of change is larger by $750
So that's why the answer is choice D. Over this timespan, company 2 is growing faster on average compared to company 1

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