A block has a volume of 0.09m3 and a density of 4000kg/m3. What's the force of gravity acting on the block in water

As per the question there are three physical quantities named as position,distance and displacement.

Before coming into a conclusion first we have to understand a vector and a scalar.

A scalar quantity is a quantity which has only magnitude for it's complete specifications.

A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.

Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.

Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.

Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.

Hence position and displacement are vectors

Answer:

position and displacement

Explanation:

Since the hippocampus' involvement with the brain is to do with memories, I would go with B.) The Hippocampus acts as a "memory index" of sorts, and if you send information to it, it would make connections to, in a sense, help remember it.

Answer:

it is b

Explanation:

The answer is B because the bowling ball is the heaviest.

We have that from the Question, it can be said that

From the Question we are told

If a weight lifter holds a 200 kg barbell in place over his head, he _______

A:does no work because the force he applies does not cause the barbell to move.

B: does work because the barbell is heavy to hold.

Generally the equation for work is mathematically given as

w=f*d

Therefore

For an instance where distance traveled is zero and force exerted is a 1000N  the work done will still be zero because

1000*0 =0

Therefore

does no work because the force he applies does not cause the barbell to move.

Option A

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Answer

The steps in order to explain how a tornado forms are;

1. An extreme difference in wind speed at two elevations causes the wind shear

2. The difference in wind speed causes a column of air to rotate horizontally

3. A strong updraft connects the rotating air with clouds above

4. The column of air stretches to form a tornado

Explanation

The typical steps of tornado formation follow the below steps;

• Occurrence of a large thunderstorm which happens in the cumulonimbus clouds

• There is a change in wind direction and speed at higher attitudes that makes the air to swirl horizontally

• Air rising from the ground pushes up on the swirling air and tips over it

• The swirling air funnel starts to suck up more warm air from the ground

• The funnel enlarges and stretches towards the ground

• The funnel touches the ground level to form a tornado

The formation of a tornado involves wind shear caused by extreme differences in wind speed at various elevations, leading to horizontal air rotation that becomes vertical when connected to an updraft from the clouds. Tornadoes result from severe thunderstorms and can produce destructive winds up to 500 km/h.

To understand how tornadoes form, it is essential to arrange the steps of their formation in the correct sequence:

Tornadoes are associated with severe thunderstorms, particularly supercells, that involve a horizontally rotating column of air. The horizontal rotation shifts to a vertical axis due to the contrasting wind speeds, such as the strong cold winds from the jet stream and warmer winds rising from the Gulf of Mexico. A tornado is a violent rotating column of air that extends from a thunderstorm down to the ground and can reach wind speeds as high as 500 km/h (approximately 300 miles/h), particularly at the bottom where the funnel is narrowest.

Storm reports reveal that atmospheric pressure plays a crucial role in weather determination, and significant pressure differences can lead to strong winds capable of producing tornadoes. The understanding of rotational motion and angular momentum are integral to comprehending why tornadoes spin and increase in velocity; as their radius decreases, similar to an ice skater pulling in her limbs to spin faster.

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initial height of the boy when he jump or dive is 5 meter

[tex]h_1 = 5 m[/tex]

now his final position is 2 yards above the surface

[tex]h_2 = 2 yards[/tex]

as we know that

[tex]1 yard = 0.9144 m[/tex]

[tex]2 yards = 1.83 m[/tex]

now by energy conservation we can say

change in potential energy = gain in kinetic energy

[tex]mg(h_1 - h_2) = \frac{1}{2} mv^2[/tex]

divide both sides by mass "m"

[tex]g*(5 - 1.83) = \frac{1}{2}*v^2[/tex]

[tex]v^2 = 2*9.8*(5 - 1.83)[/tex]

Now kinetic energy will be given as

[tex]KE = \frac{1}{2} mv^2[/tex]

[tex]KE = \frac{1}{2}*70 * 2*9.8*( 5 - 1.83)[/tex]

[tex]KE = 2175 J[/tex]

so his kinetic energy will be 2175 J

If the acceleration applied is constant, then it is the same as the average acceleration throughout the duration of the stop.

[tex]a=\dfrac{\Delta v}{\Delta t}\implies-6.4\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{0-28\,\frac{\mathrm m}{\mathrm s}}{\Delta t}\implies\Delta t=4.4\,\mathrm s[/tex]

T= The time it takes for the flower pot to pass the top of my window.  

V= The velocity of the flower pot at the moment it is passing the top of my window.  

X= The height above the top of my window that the flower pot was dropped.  

h = Lw + X  

Lw = (1/2)*g*t^2 + V*t  

V*t = Lw - (1/2)*g*t^2  

V= Lw/t - (1/2)*g*t , On the other hand we know : V=gT.  

Therefore we will have: Tg= Lw/t - (1/2)*g*t  

T= Lw/(tg) - t/2  

Now substitute for T in the following equation: X = (1/2)*g*T^2  

X= (1/2)*g*(Lw/(tg) - t/2)^2  

Now substitute for X in the very first equation I mentioned: h = Lw + X  

h = Lw + (1/2)*g*(Lw/(tg) - t/2)^2  

In case you wanted the answer to be simplified, then:  

h= (Lw^2)/(2*g*t^2) + (g*t^2)/8 + Lw/2

Answer:

3.26m

Explanation:

Using one of the equation of motion to get the distance of the pot from the window and the ground;

v² = u²+2as where

v is the final velocity = 8m/s

u is the initial velocity = 0m/s

a =+g = acceleration due to gravity (this acceleration is positive since the body is falling downwards)

g = 9.81m/s

s is the distance between the object and the window from which it dropped.

Substituting this values to get the distance s we have;

8² = 0²+2(9.81)s

64 = 19.62s

s = 64/19.62

S = 3.26m

Potential Kinetic Kinetic Potential Potential

60 mph

hope this helps

the equation is total distance/total time

180/3

60

Solution with explanation is given below in attachment.

This is possible due to inertia of motion. which is nothing but newton's first law.

according to this law , an object tries to retain its state of motion or rest unless acted upon by an external force.  

consider an object placed on a paper, initially both the object and paper are at rest. to pull the paper , we apply force on the paper and paper gains velocity. but the object keeps its motion of rest and hence the paper can be removed without moving the object.

The dependent variable in an experiment is also called the responding variable, as it responds to changes in the independent variable.

In the context of an experiment, the dependent variable is also known as the responding variable. This is because it is the variable that responds to the changes made to the independent variable, which is referred to as the manipulated variable due to it being purposefully altered by the researcher. Other variables in the experiment, known as control variables, are kept constant so they do not affect the outcome of the dependent variable.

When car is at rest the steaks makes makes vertical lines

which means the rain is falling in vertically downward direction

Now when car is moving with some speed v

Now the steaks makes and an angle 45 degree

So here we can say that relative velocity of rain with car is 45 degree

Now this is the resultant speed of rain in car frame

[tex]V_{rc} = V_r - V_c[/tex]

now if relative velocity makes 45 degree angle so this vector must have same components in vertical and horizontal direction

Since we know that relative velocity is resultant of rain velocity and car velocity so we can say here its two components are rain velocity and car velocity

So these two components must be of same magnitude

as it makes 45 degree

because when two vector are of same magnitude then the resultant vector always makes 45 degree with them if these two vectors are perpendicular to each other

car is moving at same speed as the speed of rain

Final answer:

When the rain makes a 45-degree angle streak on a moving car's window, the speed of the car is equal to the speed of the falling rain.

Explanation:

The student's question involves understanding relative velocities and their relationship to observed angles. Specifically, if rain makes 45-degree streaks on a moving vehicle's window, we want to know how fast the car is moving compared with the speed of the falling rain.

To solve this problem, we make use of trigonometry, particularly the tangent function which relates opposite and adjacent sides in a right-angled triangle. If the streaks are at a 45-degree angle, the vertical and horizontal speeds (i.e., speed of the rain and speed of the car) are equal. Therefore, in this scenario, the car is moving at the same speed as the rain is falling. Using the formula tan(θ) = vhorizontal / vvertical, where θ is the angle of the rain relative to the vertical, we find that at 45 degrees, tan(45) = 1 which implies the car's speed (vhorizontal) is equal to the rain's speed (vvertical).

Answer:

Objects in free-fall do not experience air resistance.

Explanation:

This comes from the definition of free-fall: an object in free fall is an object which is falling and the only force acting on it is gravity. Therefore, air resistance is not present for an object in free-fall. As a result, the acceleration of any object in free-fall is always equal to g (gravitational acceleration), and so all the objects fall with the same velocity and same time, regardless of their mass.

If the object is massive then the acceleration of gravity is faster, such objects will free fall more quickly than lighter objects. The objects in free fall do not experience air resistance are all true statements because the force of gravity which depends upon weight.

It is directly proportional to the weight. Yet the mass and weight are not same because mass is only value in kilograms but the weight is the value in which mass and gravitational acceleration are included. However, its unit is kilograms - 2 which is equal to Newton law of formula which is also unit of force.

Focal distance of an ellipse is given by the formula

[tex]f = ae[/tex]

here a = length of semi major axis

e = eccentricity of the path

now here we know that

length of major axis for the path of planet is given as 32 units

so here we can say

[tex]2a = 32 units[/tex]

[tex]a = 16 units[/tex]

so length of semi major axis is 16 units

focal distance for the planet path is given as 8 units

now from the above formula we can write

[tex]f = a*e[/tex]

[tex]8 = 16*e[/tex]

[tex]e = \frac{8}{16}[/tex]

[tex]e = \frac{1}{2} = 0.5[/tex]

so eccentricity for the path of planet will be 0.5

Normal reaction force on the block while it is at rest on the inclined plane is given as

[tex]F_n = mgcos\theta[/tex]

here we know that

m = 46 kg

[tex]\theta = 29^o[/tex]

now we will have

[tex]F_n = 46*9.8*cos29 = 394.3 N[/tex]

now the limiting friction or maximum value of static friction on the block will be given as

[tex]F_s = \mu_s * F_n[/tex]

[tex]F_s = 0.6 * 394.3 = 236.56 N[/tex]

Above value is the maximum value of force at which block will not slide

Now the weight of the block which is parallel to inclined plane is given as

[tex]F_{||} = mg sin\theta[/tex]

here we know that

[tex]F_{||} = 46*9.8 sin29 = 218.55 N[/tex]

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.

So here friction force on the given block will be same as its component on weight which is 218.55 N

The frictional force acting on the 46 kg mass is approximately 202.70 N.

The frictional force acting on the 46 kg mass can be found using the formula ƒk = µkN, where µk is the coefficient of kinetic friction and N is the normal force. The normal force can be found using N = mg cos(theta), where m is the mass of the block and g is the acceleration due to gravity. Plugging in the values, we get N = (46 kg)(9.8 m/s^2) cos(29°) = 397.67 N.

Now, we can calculate the frictional force using ƒk = µkN = (0.51)(397.67 N) = 202.70 N.

Therefore, the frictional force acting on the 46 kg mass is approximately 202.70 N.

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The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

v=u+gt

v=0+9.81×2.8

v=27.468 m/s

now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

As E= mc²

E = (4.36 × 10^ -5) ×( 3 × 108 m/s.)²

E= 3.924×10^12J

E= (3.924×10^12)KJ/ 1000

E =3.92 × 109 kJ

Answer:

Released energy, [tex]E=3.92\times 10^6\ kJ[/tex]

Explanation:

It is given that,

Loss in mass in a nuclear reaction, [tex]m=4.36\times 10^{-5}\ g=4.36\times 10^{-8}\ g[/tex]

The relation between the mass and energy is given by Einstein mass energy equivalence equation :

[tex]E=mc^2[/tex]

c is the speed of light

So, [tex]E=4.36\times 10^{-8}\times (3\times 10^8)^2[/tex]

[tex]E=3.92\times 10^9\ J[/tex]

[tex]E=3.92\times 10^6\ kJ[/tex]

The energy released in a nuclear reaction is [tex]3.92\times 10^6\ kJ[/tex]. Hence, the correct option is (B)

Answer: slow revolution and fast rotation

Solar system has 8 planets. 4 inner rocky planets - Mercury, Venus, Earth and Mars and 4 outer gaseous planets - Jupiter, Saturn, Uranus and Neptune.  The outer planets have few common features.

They are gaseous. There  period of revolution is larger than the inner planets which means that they have slow revolution about the Sun. One day on the outer planets is smaller than the inner planets which means they have fast rotation.

For example, Jupiter has revolves around sun in 11.86 Earth years and rotates about axis in 9.8 Earth hours. Uranus revolves around sun in 84 Earth years and rotates on its axis 17.9 Earth hours.

fast rotation

slow revolution

Force of gravitation between two balls is given by the formula

[tex]F = \frac{Gm_1 m_2}{r^2}[/tex]

here we know that

[tex]m_1[/tex] = mass of ball 1

[tex]m_2[/tex] = mass of ball 2

[tex]r[/tex] = distance between two balls

So here the two factors that will affect the force of gravitation is

1. Distance between two balls

2. mass of two balls

Here balls do not move due to gravitation attraction force because here the force of gravitation is very small as it is compared with other forces like frictional force between balls and ground.

So this weak gravitational force is balanced by frictional force on balls

SO all balls remains at rest

Gravitational force is directly affected by the masses of the objects involved and the distance between them. Despite this, objects do not simply move towards each other due to gravity because other forces such as friction and air resistance often counteract this attraction.

The question essentially asks about two factors that affect gravity and why the balls do not move towards each other unless acted upon by an external force. Here's what we know from Newton's Law of Universal Gravitation: the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. In simple terms, this means that the larger the masses of the objects, and the closer they are to each other, the stronger the gravitational pull between them.

Now, onto the second part of your question. In a perfect vacuum where no other forces exist, the balls would indeed move towards each other. However, in the real world, there are other forces at play, such as friction and air resistance, that counteract the gravitational pull. Therefore, unless these balls are acted upon by a stronger force (like a push or a pull), they will not move towards each other.

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answer: you stand in a lab experiment because if you sit during the lab, you have much reach of the materials on the table. and also, you might have a risk on some chemical spill on your clothes. the chemical might be flammable and it might set your clothes on fire.

so that's why you have to stand during lab experiments.

hope this helps! ❤ from peachimin

Standing during a lab experiment is important for safety and accuracy. It allows better control over equipment and materials and minimizes the risk of hazards.

When conducting a lab experiment, it is important to stand to ensure safety and accuracy of the experiment. Standing allows you to have better control and stability over the equipment and materials you are working with. Additionally, it helps minimize the risk of accidental spills, breakage, or other hazards.

For example, if you are working with chemicals or glassware, standing can prevent the equipment from tipping over and causing injury. It also allows you to observe the reaction or process more closely, making it easier to record accurate data and observations.

Overall, standing during a lab experiment promotes safety, precision, and optimal results.

As it is given that 2 kg mass is suspended by 12 cm long thread and then a horizontal force is applied on it so that it remains in equilibrium at 30 degree angle

So here we can use force balance in X and Y directions

now for X direction or horizontal direction we can use

[tex]F = Tsin30[/tex]

for vertical direction similarly we can say

[tex]mg = T cos30[/tex]

so here we first divide the two equations

[tex]\frac{F}{mg} = \frac{sin 30}{cos 30}[/tex]

[tex]\frac{F}{mg} = tan 30[/tex]

[tex]F = mg tan30[/tex]

now plug in all values in the above equation

[tex]F = 2 * 9.8 * tan30[/tex]

[tex]F = 11.3 N[/tex]

Part b)

now in order to find the tension in the thread we can use any above equation

[tex]F = T sin30[/tex]

[tex]11.3 = T sin30[/tex]

[tex]T = \frac{11.3}{sin30}[/tex]

[tex]T = 22.6 N[/tex]

so tension in the thread will be 22.6 N

Final answer:

To find the horizontal force and tension in a string supporting a displaced metal ball, one must use equilibrium principles along with trigonometric relations from Newton's second law, focusing on the components of tension.

Explanation:

The question involves finding a) the horizontal force and b) the tension in the thread that supports a metal ball displaced by 30 degrees to the vertical. This situation can be analyzed using principles of equilibrium and Newton's second law. When the ball is displaced, it creates an angle with the vertical, leading to a horizontal component of the tension acting as the horizontal force, and a vertical component of the tension balancing the weight of the ball.

To calculate these forces, we can use trigonometric relations and Newton's second law. The tension in the string can be resolved into two components: the horizontal component (Thorizontal) and the vertical component (Tvertical). The vertical component balances the weight of the ball (mg), and the horizontal component is the force needed to keep the ball in equilibrium.

For a ball of mass 2 kg displaced at a 30-degree angle, assuming g = 9.8 m/s2, the calculations would involve using the equations Tvertical = mg and Thorizontal = Tvertical * tan(θ) where θ is the angle of displacement. However, specific calculations are not provided here without the complete equations and values.

So because trajectories including both universes are more or less inclined, Mars' orbit is not far from this same ecliptic.

Learn more about orbit here:

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let the tension force in the rope attached to the sledge be "T"

θ  = angle of rope with the horizontal = 40 deg

X = horizontal component of tension force "T" = 100 N

horizontal component of tension force "T" is given as

X = T Cosθ

100 = T Cos40

T = 130.54 N

Y = vertical component of the tension force = ?

vertical component of the tension force is given as

Y = T Sinθ

inserting the values

Y = (130.54) Sin40

Y = 83.91 N

You've managed somehow to post the mirror image of the circuit diagram, including the numbers and values of the resistors.  I'm curious to know how you did that.

The three resistors at the left end of the diagram are  3Ω ,  2Ω , and  1Ω  all in series.  They behave like a single resistor of  (3+2+1) = 6Ω .

That  6Ω  resistor is in parallel with the  2Ω  drawn vertically in the middle of the diagram.  That combination acts like a single resistor of  1.5Ω  in that position.

Finally, we have that  1.5Ω  resistor in series with  1Ω  and  4Ω  .  That series combination behaves like a single resistor of  6.5Ω  across the battery V.  

let the magnitude of force applied by each worker be "F"

consider east-west direction along X-axis and north-south direction along Y-axis

In unit vector form, force vector by worker pushing in east direction is given as

[tex]\underset{A}{\rightarrow}[/tex] = F [tex]\hat{i}[/tex] + 0  [tex]\hat{j}[/tex]

In unit vector form, force vector by worker pushing in north direction is given as

[tex]\underset{B}{\rightarrow}[/tex] = 0 [tex]\hat{i}[/tex] + F  [tex]\hat{j}[/tex]

resultant force is given as the vector sum of two vector forces as

[tex]\underset{R}{\rightarrow}[/tex] = [tex]\underset{A}{\rightarrow}[/tex] + [tex]\underset{B}{\rightarrow}[/tex]

[tex]\underset{R}{\rightarrow}[/tex] = (F [tex]\hat{i}[/tex] + 0  [tex]\hat{j}[/tex] ) + (0 [tex]\hat{i}[/tex] + F  [tex]\hat{j}[/tex] )

[tex]\underset{R}{\rightarrow}[/tex] = F [tex]\hat{i}[/tex] +  F  [tex]\hat{j}[/tex]

direction of the force is hence given as

θ = tan⁻¹(F/F)

θ =  tan⁻¹(1)

θ = 45 degree north of east

hence the direction is north-east