A body is accelerated continuously. What is the form of the graph?
A. Cubic
B. Inverse
C. Linear
D. Quadratic

Note :the graph shows distance and time

Answers

1)  3,840 N

2) 80 m

Explanations

Centripetal force is the force that maintenance objects that are moving in a circular motion.

F = mv²/r

  = (1500 × 16²)/100

   = (1500×256)/100

     = 384000/100

     = 3,840 N

2) F = (mv²)/r

       6000 N = (1200 × 20²)/r

r = (1200 × 400)/6000

   = 480,000/6000

     = 80 m

Discovered by Sir Isaac Newton, this law states that every object in the universe that has mass attracts every other object in the universe that has mass. The force is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers. When applying this to a situation with two objects, the object with the smaller mass will do most of the moving because the other object has too much inertia to move any noticeable amount.

4. Without advanced technology like we have today, Ptolemy and Copernicus tried to best explain the model of the universe through observation. Ptolemy’s model came first and placed a stationary earth at the center of the model. Everything else moved in respect to earth. This was widely accepted since it seemed like earth was not moving. Ptolemy stated that the planetary bodies moved around the earth in circular paths. However, this wasn’t always witnessed through observation. He adjusted his model to state that some planets must be moving in secondary orbits.

Copernicus put a rotating earth in a sun-centered model. The rotation of earth was able to account for the rising and setting of stars. The orbital motion of the earth and moon also accounted for the motion of the sun and moon with respect to the stars. This was easier to understand but encountered scrutiny due to its differences from religious teachings.

One big difference between the approaches in the two is that Copernicus didn’t try to adjust his model to match what was going on; he used observations to develop the model. In addition, one common trend in science is that the simplest explanation is usually most accurate or closer to accurate. Copernicus’ model was more straightforward; Ptolemy’s was more complex.

Horizontal distance that a person can jump on the ground is known as horizontal range.

Horizontal range can be calculated by the formula of projectile motion which is given as

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

here for the maximum possible range of jump we can say that he must have to jump at 45 degree

so that the value of the range will be maximum in above equation

[tex]R = \frac{v^2}{g}[/tex]

now if we compare the jump of a person on two planets then as per the capability of the person then velocity of jump will remain same on two planets so we can say

[tex]\frac{R_1}{R_2} = \frac{g_2}{g_1}[/tex]

[tex]\frac{1.57}{R_2} = \frac{0.153g}{g}[/tex]

here it is given that on Earth the acceleration is g = 8.21 m/s^2[/tex]

and on moon it is g' = 0.153g

now we have

[tex]\frac{1.57}{R_2} = \frac{0.153}[/tex]

[tex]R_2 = \frac{1.57}{0.153}[/tex]

[tex]R_2 = 10.3 m[/tex]

So the person can jump a distance of 10.3 m on the Moon

The person could jump about 6.43 times higher on the Moon than on Earth if the takeoff speed is the same in both locations.

To find out how much farther a person could jump on the Moon compared to Earth, we need to use the concept of gravitational acceleration. The gravitational acceleration on the Moon is about 1/6 that of Earth. Since the takeoff speed of the astronaut is the same in both locations, we can use the equation: distance = (takeoff speed)^2 / (2 * gravitational acceleration).

Let's say the person can jump a distance of 1.57 m on Earth, with a gravitational acceleration of 8.21 m/s^2. On the Moon, the gravitational acceleration is 0.153 * 8.21 m/s^2. Plugging these values into the equation, the person could jump a distance of approximately 10.09 m on the Moon. This means the person could jump about 6.43 times higher on the Moon than on Earth.

It is a physical change. One is physically change the wheat from one form to the other.

Answer:

B on edge

Explanation:

Budgets help consumers control their expenses and reach financial goals by providing a system to track and manage incoming and outgoing funds, allowing for informed financial decisions.(Option B)

The question relates to how budgeting assists consumers in reaching their financial goals. Among the given options, B) Budgets allow consumers to control how much money they have going out for expenses is the best explanation. A budget is an invaluable tool that enables individuals to track incoming and outgoing funds, ensuring that expenses do not exceed income. It helps in identifying non-essential expenditures and allows for adjustments to meet financial goals.

While budgeting isn't always easy—often because it requires making trade-offs and giving up certain pleasures—it is essential in a world of economic scarcity where desires outstrip realities. By creating and adhering to a budget constraint, individuals can navigate their financial resources effectively and make informed decisions about their consumption.

In the question there are three values of densities.

We are asked to arrange these values in descending order.

In order to solve this problem first we have to convert each values into same unit.Let the unit chosen to be gram per cubic centimeter.

The first value is 1000 kg per cubic metre.

we know that 1 kg=1000 kg and and 1 m=100 cm

Hence the value in CGS system will be-

                                                  [tex]1 kg/m^3 =\frac{10^3 gram}{[10^2cm]^3}[/tex]

                                                                  [tex]=10^-3\ g/cm^3[/tex]

 The second value is 1 gram per cubic centimetre.

Third value is 1 kg per cubic millimeter.

we know that

                      [tex]1 mm =10^-1 cm[/tex]

Hence 1 kg per cubic millimeter i.e

                                                     [tex]1 kg/mm^3[/tex]

                                                       [tex]=\frac{10^3 gram}{[10^-1cm]^3}[/tex]

                                                       [tex]=10^6 g/cm^3[/tex]

Hence the perfect order will be-

                      [tex]10^6 g/cm^3[/tex] >[tex]1 g/cm^3[/tex]  > [tex]10^-3\ g/cm^3[/tex]  

                      [tex]i.e\ 1 kg/mm^3>1\ g/cm^3>1 kg/m^3[/tex]

Answer:

1 kg/mm³, 1 kg/m³, 1 g/m³

Explanation:

We have 3 objects of different densities, 1 kg/m³, 1 g/m³, and 1 kg/mm³.

In order to compare their densities, we will express all of them in the same units, for instance, kg/m³.

First object

It has a density of 1 kg/m³.

Second object

We know that 1 kg = 10³ g. Then,

1 g/m³ × (1 kg/10³ g) = 10⁻³ kg/m³

Third object

We know that 1 m = 10³ mm. Then,

1 kg/mm³ × (10³ mm/1 m)³ = 10⁹ kg/mm³

The densities, from most to least dense are:

1 kg/mm³, 1 kg/m³, 1 g/m³

We can assume here that left and right directions are -X and + X directions respectively

Similarly its perpendicular directions are +Y and -Y i.e. upwards and downwards respectively

So here it is given that

[tex]F_1 = 83.6 N[/tex] +X direction

[tex]F_2 = 121.7 N[/tex] - X direction

[tex]F_3 = 633.6 N[/tex] + Y direction

[tex]F_4 = 241.7 N[/tex] - Y direction

Now net force in X direction is required here in this question

So here in X direction there are two forces opposite to each other

so in order to find net force we need to add them vector addition rule

so here

[tex]F_{net} = F_1 - F_2[/tex]

[tex]F_{net} = 83.6 - 121.7[/tex]

[tex]F_{net} = -38.1 N[/tex]

so it requires 38.1 N force towards left

Answer:

1. Rovers- These are vehicles which are designed to move on the surface on any celestial body and collect samples, data and images. Sometimes, these can be used to transport mission crew members.

2. Orbiters- These are spacecrafts designed to orbit any celestial body and collect data in form of images.

3. satellites- artificial satellites are placed in the orbit of celestial bodies for various purposes. There are various types of satellites like communication satellite, weather satellites, space telescopes. These collect images and data inform of signals.

4. space stations: It is a satellite where research and experiments take place. Images are also collected for research purpose.

Space shuttle is a wrong option because it is just a vehicle to transport these satellites and probes into the space and place in the orbit or surface of celestial body.

Answer:

rovers

satellites

space stations

Explanation:

i just took the test

The medical equipment used for ultrasound imaging is based on Doppler's effect.

The ultrasound imaging process uses high frequency radio waves to view inside images like tendons,muscles,joints,blood vessels etc.

In this process the transmitted pulse produces a Doppler's shift when it interacts with the moving reflector. Here we have to consider the moving reflector as the moving source.The moving reflector will produce an echo which will be received by the transducer.The transducer acts as stationary observer.

The whole process can be explained as below-

1-The ultrasound machine transmits the high frequency signal to the body through a prove.The sound will be reflected by the boundary of tissue and received by the probe.Some sound waves penetrate more into inside part of the body.

2-The received reflected sound will be allowed to enter into the machine which calculates the distance between various tissue and forms an image based on Doppler's shift.

Hence the correct answer is Doppler's effect.

Answer:

the Doppler effect

Explanation:

The frequency of the sound waves used in Doppler ultrasound are high frequency sound waves. These are used to observe and  measure the amount of blood that is flowing through the arteries and veins . The veins that supply the blood to arms and legs are studied using the Doppler ultrasound technology.

The ultrasound waves can accurately measure the movement of the red blood cells, since their movement can produce a change in the frequency of the sound waves that are reflected.

Answer:

Probe, Space Observatory

Explanation:

A probe can be sent off to far away planets and galaxies. A space observatory is an outer space observatory with an advanced telescope used to study the universe.

To study a star in the Andromeda galaxy, astronomers use satellites and space observatories equipped with advanced telescopes and detectors. Rovers, probes, and space stations are not used for studying distant galaxies.

Astronomers who wish to study a star in the Andromeda galaxy, the closest galaxy to our Milky Way, would require highly advanced technology due to the vast distance involved—about 2.5 million light-years from Earth. The instruments capable of such observations include satellites and space observatories. These are equipped with large telescopes and sensitive detectors that can capture images and spectra of distant galaxies, despite their faint appearance due to the immense distance. Observatories like the Hubble Space Telescope have been instrumental in exploring objects in distant galaxies. Rovers and probes are primarily designed for in-situ exploration of objects within our solar system, such as planets, moons, and asteroids, and would not be used to study distant stars. Similarly, space stations like the ISS serve as research labs for experiments in microgravity and would not be used for distant astronomical observations.

Because this allows us to describe the direction of the motion.

In fact, when studying a motion, we need to specify the velocity of the object, which consists of a magnitude (the speed) and also a direction. Without a coordinate system, it would be impossible to describe in which direction is the object moving.

a) Let's call x the direction parallel to the river and y the direction perpendicular to the river.

Dave's velocity of 4.0 m/s corresponds to the velocity along y (across the river), while 6.0 m/s corresponds to the velocity of the boat along x. Therefore, the drection of Dave's boat is given by:

[tex]\theta= arctan(\frac{v_y}{v_x})=arctan(\frac{4.0 m/s}{6.0 m/s})=arctan(0.67)=33.7^{\circ}[/tex]

relative to the direction of the river.

b) The distance Dave has to travel it S=360 m, along the y direction. Since the velocity along y is constant (4.0 m/s), this is a uniform motion, so the time taken to cross the river is given by

[tex]t=\frac{S_y}{v_y}=\frac{360 m}{4.0 m/s}=90 s[/tex]

c) The boat takes 90 s in total to cross the river. The displacement along the y-direction, during this time, is 360 m. The displacement along the x-direction is

[tex]S_x = v_x t =(6.0 m/s)(90 s)=540 m[/tex]

so, Dave's landing point is 540 m downstream.

d) If there were no current, Dave would still take 90 seconds to cross the river, because its velocity on the y-axis (4.0 m/s) does not change, so the problem would be solved exactly as done at point b).

Answer:

C. 250g mass on the left

Explanation:

As the given figure there are two forces on the box placed on the table

1) due to 250 gram there will be a force which will pull it towards right

2) due to 100 g mass which will pull it downwards

now if we wish to move the block only in downward direction then we have to add a force on the block that will counterbalance the force towards right direction

so here it must have a force towards left which will balance the force of 250 g mass towards right

so it would be

C. 250g mass on the left

Given:

u(initial velocity): 0

a(acceleration): 0.13 m/s∧2

distance = 458 m

Now  s= ut +1/2 (at∧2)

Substituting from the given values we get

458= 0+ 1/2(0.13 x t∧2)

t = 83.94 secs

Now v (velocity)= u+ at

Substituting for t as 83.94 secs and for a and u from the given values we get:

v= 0+0.13 x t

v= 0.13 × 83.94

v=10.91 m/s

Therefore the final velocity of the boat is 10.91 m/s and the time taken for the boat to travel 458 m is 83.94 secs

B: the ice cubes gain heat energy from the water.

Answer:

 Height of ramp = 17.49 m

Explanation:

  We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Considering horizontal motion of skier

      Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.

    [tex]63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds[/tex]

The vertical distance traveled in 1.909 seconds is the height of  ramp

      Initial velocity = 0 m/s, acceleration = acceleration due to gravity =  9.8 [tex]m/s^2[/tex], time = 1.909 s and we need to find displacement.

      [tex]s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m[/tex]

    So height of ramp = 17.49 m

No it is not balanced. It has more CI on the product side that the reactant side.

Hope I helped

IT's cell membrane because it maintains homeostasis by controlling what enters the cell and what exits it.

You draw 3 circles around the stations with the size of the circle equal to the distance from the earthquake. Then you simply find where the edge circles all overlap.

C) 9 kilogram meters/second

Explanation:

The impulse is defined as the integral of the force over the time:

[tex]J=\int F dt[/tex]

in a force-time graph, the impulse corresponds to the area under the curve. Therefore, in this case we can calculate the impulse by finding the area of the triangle.

The base is 3 s, while the height is 6 N, therefore the area (and the impulse) is

[tex]J=\frac{(3 s)(6 N)}{2}=9 kg m/s[/tex]

Answer:

C) 9 kilogram meters/second

Explanation:

Correct answer on plato/edmentum

Final answer:

The presence of heat, steam, and condensation, as well as feeling or hearing the engine cooling down, can indicate if a parked car had been running recently.

Explanation:

When walking close to a parked car, you can tell if it has been recently running by paying attention to energy flows. If the engine was running recently, you may be able to feel the heat radiating from the hood or hear the engine cooling down. Another clue is the presence of steam or condensation from the exhaust pipe, indicating that the engine has been producing heat and burning fuel. These signs indicate that the car was using stored chemical energy in the form of gasoline, converting it into mechanical energy to power the engine and produce heat.

As per the graph there is a motion map which denotes the motion of two dots C and D respectively.

As per the graph the motion of dot C is non uniform .It is so because it is covering unequal distance in equal interval of time.Its speed is increasing at every instant .Hence it is speeding up.

The motion of dot D is uniform .It covers equal distance in equal interval of time.Hence the dot D is moving at a constant velocity.

Hence out of four options given in the question,the third option i.e C is the correct answer .

Motion is detected when an object changes its position with respect to a reference point. Coordinate system is basically used to represent motion. A coordinate system uses numbers or coordinates which represent position of the reference points on a two-dimensional or three-dimensional space. The trajectory of a point or line can be studied on a coordinate system which describes various aspects of motion like velocity, acceleration, distance, displacement etc. Coordinate system is important because it helps to choose a starting point and the direction (which will be positive).

Answer: At the top of its flight.

At the top of the flight,the height from the ground is maximum. Owing to this position the potential energy attained here is the maximum.

Also potential energy = mgh

Where m is the mass of the object.

g is the acceleration due to gravity

h is the height of object.

From this equation we can conclude that at the top,the maximum height would be attained and hence it would possess maximum potential energy.

Also at the top the object will possess zero velocity.

Kinetic energy = 1/2 (mv^2).

Where m is the mass of the object

v is the velocity of the object.

Hence at the top, since the velocity of the object is zero,the kinetic energy would be zero as explained in the below equation.

Kinetic energy= 1/2(m x 0)

Kinetic energy = 0.

Thus at the top of the flight,the ball possess only potential energy and minimum (0) kinetic energy.

With the air bag deployed, the driver has 5 times longer to decelerate and lessen her/his impact and risk of injury.

a) The change in momentum of the ball is given by:

[tex]\Delta p = m \Delta v[/tex]

where m=140 g=0.14 kg is the mass of the ball, and [tex]\Delta v =30 m/s[/tex] is the change in velocity. Substituting, we find

[tex]\Delta p=(0.14 kg)(30 m/s)=4.2 kg m/s[/tex]

The ball stops in t=1.5 ms=0.0015 s; the magnitude of the force that stops the baseball is given by the ratio between the change in momentum and the time taken:

[tex]F=\frac{\Delta p}{t}=\frac{4.2 kg m/s}{0.0015 s}=2800 N=2.8 kN[/tex]

b) The force we found at point a) is the force that the head exerts on the ball to stop it. However, Newton's third law states that when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. If we apply this law to this case, we understand that the force exerted by the baseball on the head is equal to the force exerted by the head on the ball: therefore, the answer is still 2.8 kN.

c) The forehead is not in danger of a fracture, since it can withstand a maximum force of 6.0 kN, while the ball exerts a force of 2.8 kN. Instead, the cheek is in danger of fracture, because it can withstand only a maximum force of 1.3 kN.

Potential energy is given as

[tex]U = 4y^3[/tex]

now as we know that force is related by potential energy by the formula

[tex]F = - \frac{dU}{dy}[/tex]

So it is gradient of energy with position in Y

[tex]F = - \fracd(4y^3}{dy}[/tex]

[tex]F = -12y^2 \hat j[/tex]

Now at y = 0

[tex]F = 0 N[/tex]

at y = 1

[tex]F = - 12*1^2 [/tex]

[tex]F = - 12 N[/tex]

at y = 2

[tex]F = - 12*2^2[/tex]

[tex]F = - 48 N[/tex]

so above is the forces at given positions

The force on the particle at

[tex]y=0\;\text{is} \;0\;\text{N}\\\\y=1\;\text{is} \;12\;\text{N}\\\\y=2\;\text{is} \;48\;\text{N}\\[/tex]

Explanation:

Given information:

The potential energy: [tex]U=4y^3[/tex]

Now, as we know that force:

[tex]F=-\frac{dU}{dy}[/tex]

So, the gradient of energy with position y

[tex]F=-4y^3dy\\F=-12y^2j[/tex]

At, y=0

[tex]F=0\;N[/tex].

At, y=1

[tex]F=-12+1\\F=-12 \;N[/tex]

At, y=2

[tex]F=-12\times 4\\F=-48\;\text{N}[/tex]

Hence , The force on the particle at

[tex]y=0\;\text{is} \;0\;\text{N}\\\\y=1\;\text{is} \;12\;\text{N}\\\\y=2\;\text{is} \;48\;\text{N}\\[/tex]

For more information visit:

https://brainly.com/question/20982168?referrer=searchResults

Base isolation is a technique developed to prevent or minimise damage to buildings during an earthquake. It has been used in New Zealand, as well as in India, Japan, Italy and the USA.

Taipei 101