Argon is compressed in a polytropic process with n 5 1.2 from 120 kpa and 108c to 800 kpa in a piston–cylinder device. determine the work produced and heat transferred during this compression process, in kj/kg.
A 2.8 kg block is dropped from rest from a height of 4.5 m above the top of the spring. when the block is momentarily at rest, the spring is compressed by 25.0 cm. what is the speed of the block when the compression of the spring is 15.0 cm?
The peak intensity of radiation from Mars is about 14,000 nm. What is the average surface temperature of Mars rounded to the nearest whole number?
Answer:
T = 206 K
Explanation:
As we know by Wein's law of displacement that if we draw all radiations intensity with all possible wavelengths radiated from the object then the wavelength corresponding to maximum intensity of radiation is inversely dependent to the absolute temperature of the object.
So here we can say
[tex]\lambda = \frac{b}{T}[/tex]
here we know
b = Wein's constant
[tex]b = 2.89 \times 10^{-3}[/tex]
now we have
[tex]\lambda = 14000 nm[/tex]
from above equation
[tex]14000 \times 10^{-9} = \frac{2.89 \times 10^{-3}}{T}[/tex]
[tex]T = 206 K[/tex]
The type of interference that increases the energy of the resulting wave is called interference. The type of interference that results in a loss of energy is called interference.
Answer:
constructive + destructive.
Explanation:
edge 22.
The Doppler effect is a shift in the _______________ of an oscillation caused by the motion of the source of the oscillation, and occurs at speeds below the speed of sound. a) amplitude b) frequency c) speed
A 1500-kg car traveling at 90 km/h toward the east suddenly collides with a 3000-kg car traveling at 60 km/h toward the south. the two cars stick together after the collision. what is the direction of motion of the cars after collision?
The direction of motion of the cars after collision will be south of east. This is determined by the conservation of momentum, with the direction being the sum of the momenta of the two cars, taking into account their initial velocity and mass.
Explanation:This question involves the conservation of momentum, a key concept in physics. Since the two cars stick together after the collision, the direction of their motion is the sum of their momenta, taking into account their mass and initial velocity.
First, convert the speeds from km/h to m/s. The 1500-kg car was travelling at 25 m/s towards the east (90 km/h) and the 3000-kg car was travelling at 16.67 m/s towards the south (60 km/h).
Calculating the Resulting VelocityMomentum (p) is mass (m) times velocity (v), so the momentum of the first car is 1500 kg * 25 m/s = 37500 kg*m/s and the second car's momentum is 3000 kg * 16.67 m/s = 50000 kg*m/s. Since they stick together after the collision, the total momentum must remain the same. However, the momentum now has two components, one towards the east and the other towards the south. The magnitude of the resultant velocity is found using Pythagoras' theorem, sqrt[(37500 kg*m/s)^2 + (50000 kg*m/s)^2], and the direction is given by the arctangent of the ratio of the two components. Therefore, the direction of the cars will be south of east.
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The two cars will move together after the collision with a velocity of approximately 13.89 m/s at an angle of 53.12° south of east. This result is derived by applying the principle of conservation of momentum. We found the momentum components in the eastward and southward directions and used them to determine the direction and magnitude of the combined velocity.
This is a classic example of an inelastic collision where two objects stick together after collision. We use the conservation of momentum to find the direction of motion after the collision.
First, let's convert velocities to meters per second (m/s):
1500-kg car: 90 km/h = 25 m/s
3000-kg car: 60 km/h = 16.67 m/s
Next, we calculate the momentum of each car:
Eastward momentum of the 1500-kg car:
1500 kg * 25 m/s = 37500 kg·m/s
Southward momentum of the 3000-kg car:
3000 kg * 16.67 m/s = 50010 kg·m/s
Since the cars stick together after the collision, their combined mass is 1500 kg + 3000 kg = 4500 kg.
To find the velocity components of the combined mass after the collision:
Eastward velocity component:
(37500 kg·m/s) / 4500 kg = 8.33 m/s
Southward velocity component:
(50010 kg·m/s) / 4500 kg = 11.11 m/s
We combine these components to find the magnitude and direction of the final velocity:
Magnitude = √((8.33 m/s)² + (11.11 m/s)²)
or, Magnitude = √(69.39 + 123.4)
Magnitude ≈ 13.89 m/s
Direction: arctan(11.11 / 8.33)
Direction ≈ 53.12° south of east
So, the cars will move at a velocity of approximately 13.89 m/s in a direction that is 53.12 degrees south of east after the collision.
Which electrical device makes it possible to transmit electrical energy efficiently from a power plant to users?
Transformers, specifically step-up transformers, are crucial for efficiently transmitting electrical energy from power plants to users by increasing the voltage, resulting in reduced current and minimization of Joule losses. High voltage transmission leads to greater efficiency and lower energy losses, making the process both economical and environmentally friendly.
The electrical device that makes it possible to transmit electrical energy efficiently from a power plant to users is the transformer. Transformers play a critical role in adjusting the voltage levels during the transmission of electric power over long distances. When power is generated, a step-up transformer increases the voltage from the power plant, which results in a proportional decrease in current and thus minimizes resistive power losses known as Joule losses. These minimized losses are crucial for maintaining efficiency since identical currents flow through both the load and transmission lines, where power is dissipated usefully in the load but wasted in the resistance of the transmission lines.
Scientists want to place a 3700 kg satellite in orbit around mars. they plan to have the satellite orbit a distance equal to 1.9 times the radius of mars above the surface of the planet. here is some information that will help solve this problem: mmars = 6.4191 x 1023 kg rmars = 3.397 x 106 m g = 6.67428 x 10-11 n-m2/kg2 1) what is the force of attraction between mars and the satellite?
Answer:
3805.59 N
Explanation:
Parameters given:
Mass of satellite, m = 3700 kg
Mass of Mars, M = [tex]6.4191 * 10^{23} kg[/tex]
Radius of Mars, r = [tex]3.397 * 10^6[/tex] m
Distance between the satellite and the surface of Mars, D = 1.9 times r
D = [tex]1.9 * 3.397 * 10^6[/tex] = [tex]6.454 * 10^6 m[/tex]
The gravitational force of attraction is given as:
[tex]F = \frac{GMm}{D^2}[/tex]
where G = gravitational constant = [tex]6.67428 * 10^{-11}Nm^2/kg^2[/tex]
[tex]F = \frac{6.67428 * 10^{-11} * 6.4191 * 10^{23} *3700}{(6.454 * 10^6)^2}[/tex]
[tex]F = 3805.59 N[/tex]
The gravitational force of attraction is 3805.59 N
A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never include units in the answer to a numerical question.)
Given the force acting on the object, the change in its momentum is 4kg.m/s.
Force; [tex]F = 8.0N = 8 kg.m/s^2[/tex]Mass; [tex]m = 0.7kg[/tex]Time, [tex]t = 0.50s[/tex]To determine the object's change in momentum, we use the Impulse Momentum Theorem:
The impulse applied to a body or matter is equal to the change in its momentum
Impulse = Change in Momentum
[tex]Impulse = F * dt[/tex]
Where F is the force applied and [tex]dt[/tex] is the elapsed time
Hence
[tex]Change \ in \ Momentum = F * dt[/tex]
We substitute our given values into the equation
[tex]Change \ in \ Momentum = 8 kg.m/s^2 * 0.50s\\\\Change \ in \ Momentum =4kg.m/s[/tex]
Therefore, given the force acting on the object, the change in its momentum is 4kg.m/s.
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After harvesting their main crops, such as corn and wheat, many farmers plant a second crop called a cover crop. This cover crop grows during the fall and winter and is then plowed over in the spring. What is the main purpose of a cover crop?
A.
to get rid of excess seed rather than storing during the winter
B.
to provide food and shelter for birds and animals during the winter
C.
to prevent water runoff into other parts of the farmers' field
D.
to prevent erosion of the topsoil by wind and water
Answer:
Option (D)
Explanation:
A cover crop is usually defined as a special type of crop that is cultivated in order to increase the productivity of the soil, rather than focusing on the productivity of the crop. These are very commonly used and it helps in the decreasing amount of weeds, controlling pests and diseases, increasing the fertility of the soil, reduction of soil erosion. It also enhances the biodiversity.
Thus, the main purpose of the cover crop is to prevent the erosion of the topsoil by the agents such as water and wind.
Hence, the correct answer is option (D).
You drive a 6,000 kg boat due north, while the wind exerts a force of 600 N due south and the water exerts a resistive force of 1,200 N due south. The generated force by the boat’s engines is 4,200 N. Find the magnitude and direction of the boat’s acceleration.
"explain why the orbital radius and the speed of a satellite in circular orbit are not independent"
An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 200 n. (a) what is the equivalent spring constant of the bow
The period of a wave is found to be 50 seconds. What is the frequency of the wave? 50 Hz 0.8 Hz 0.02 Hz not enough information given
The period of a wave is found to be 50 seconds. What is the frequency of the wave?
0.02 Hz
A force of 230 N applied on a hydraulic lift raises an automobile weighing 6500 N. If the applied force is exerted on a 7.0 m^2 piston, what is the area of the piston beneath the automobile?
a.
2.0 x 10^2 m^2
b.
4.0 m^2
c.
0.25 m^2
d.
0.0050 m^2
Answer:
197.83 m^2
Explanation:
F = 6500 N, A = ?
f = 230 N, a = 7 m^2
Let the area of piston beneath the automobile is A.
By use of Pascal's law
F / A = f / a
6500 / A = 230 / 7 A = 197.83 m^2
A 0.32 μc particle moves with a speed of 18 m/s through a region where the magnetic field has a strength of 0.95 t . you may want to review (pages 773 - 777) . part a at what angle to the field is the particle moving if the force exerted on it is 4.8×10−6n? express your answer using two significant figures. θ = ∘ request answer part b at what angle to the field is the particle moving if the force exerted on it is 3.0×10−6n? express your answer using two significant figures.
The force on a particle in a magnetic field can be determined using F = qvBsin(\theta). By rearranging the equation to solve for \theta, we can find the angle the particle's velocity makes with the magnetic field for any given force, charge, velocity, and field strength.
Explanation:The situation described is a classic example of Lorenz force experienced by a charged particle moving through a magnetic field. The force exerted on a charged particle when it moves through a magnetic field can be calculated with the following equation:
F = qvBsin(\theta)
where:
F is the magnetic force,q is the charge of the particle,v is the velocity of the particle,B is the magnetic field strength, and\theta is the angle between the velocity vector and the magnetic field.To find the angle \(\theta\), we can rearrange the equation:
\theta = arcsin(\frac{F}{q v B})
For part A:
Using the information given, where F = 4.8 \times 10^{-6} N, q = 0.32 \times 10^{-6} C, v = 18 m/s, and B = 0.95 T, we can calculate the angle.
\(\theta = arcsin(\frac{4.8 \times 10^{-6}}{0.32 \times 10^{-6} \times 18 \times 0.95}) = arcsin(\frac{4.8}{0.32 \times 18 \times 0.95})\)
This returns an angle \(\theta\), which will be in degrees once evaluated using a calculator.
For part B, you would apply the same approach but with F = 3.0 \times 10^{-6} N, to find the different angle.
What is the energy of the spring-mass system when the mass first passes through the equilibrium position? (you may wish to include a logical test to help you find when this occurs)?
two ends of an inextensible string of length 12m are attached to points Aand B 1.2m apart,in the same horizontal plane.a mass 20kg is suspended from the middle point C of the string and the system is in equilibrium. calculate the tension on either arm of string
What are the three longest wavelengths for standing waves on a 280-cm-long string that is fixed at both ends? enter your answers numerically separated by commas?
A child goes down a playground slide with an acceleration of 1.12 m/s2 .find the coefficient of kinetic friction between the child and the slide if the slide is inclined at an angle of 27.0 ∘ below the horizontal.
The coefficient of kinetic friction is obtained by considering the forces acting on the child as they slide. These are the force of gravity (mg sin θ) and the force of kinetic friction (μk mg cos θ). Setting these forces equal gives us an equation that can be solved to find the coefficient of kinetic friction, μk.
Explanation:To figure out the coefficient of kinetic friction, we need to consider the forces acting on the child as they slide down the playground. There are two key forces to consider, the force caused by gravity which is pulling the child down the slide, and the force of kinetic friction which is trying to slow the child down.
The force of gravity working to pull the child down the slide, or the component of the weight down the slope is given as mg sin θ. Here m is the mass of the child, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the slide. The force of kinetic friction, which opposes the motion, is expressed as μk mg cos θ, where μk is the coefficient of kinetic friction we're trying to find.
Since the child is sliding down the slide with an acceleration of 1.12 m/s², the force due to gravity exceeds the force of friction. Setting up the equation μk mg cos θ = mg sin θ - ma, where a is the acceleration of 1.12 m/s², and solving for μk gives us the coefficient of kinetic friction between the child and the slide.
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Loni makes a diagram to help organize what she has learned about the gas laws.
Which label belongs in the region marked X?
involves changes in temperature
has a constant volume
shows an inversely proportional relationship
does not describe pressure changes
This question is based on Boyle's law and Charles' law.
As per Boyle's law the volume of a given mass of a gas is inversely proportional to the applied pressure at constant temperature. Mathematically it can be written as
[tex]P\ \alpha \frac{1}{V}[/tex] [at constant T and n]
Charles'law: It states that at constant pressure the volume of a given mass of a gas increases or decreases by 1/273 th of its volume at zero degree celsius for every 1 degree centigrade rise or fall of temperature.One may say that volume is directly proportional to temperature. Mathematically it can be written as
V∝T [at constant P and n]
Here P,V,T and n stand for pressure,volume,temperature and number of moles respectively.
In the diagram given in the question the point X is present in the region where Boyle's law is obeyed.Hence the correct option will be the third one which depicts the presence inverse relationship which is true for pressure and volume at constant temperature.
A 42-cm-long solenoid, 1.8 cm in diameter, is to produce a 0.030-t magnetic field at its center. part a if the maximum current is 4.3 a , how many turns must the solenoid have?
The solenoid must have about 2332 turns
[tex]\texttt{ }[/tex]
Further explanationLet's recall magnetic field strength from current carrying wire and from center of the solenoid as follows:
[tex]\boxed {B = \mu_o \frac{I}{2 \pi d} } [/tex]
B = magnetic field strength from current carrying wire (T)
μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)
I = current (A)
d = distance (m)
[tex]\texttt{ }[/tex]
[tex]\boxed {B = \mu_o \frac{I N}{L} } [/tex]
B = magnetic field strength at the center of the solenoid (T)
μo = permeability of free space = 4π × 10⁻⁷ (Tm/A)
I = current (A)
N = number of turns
L = length of solenoid (m)
Let's tackle the problem now !
[tex]\texttt{ }[/tex]
Given:
Current = I = 4.3 A
Length = L = 42 cm = 0.42 m
Magnetic field strength = B = 0.030 T
Permeability of free space = μo = 4π × 10⁻⁷ T.m/A
Asked:
Number of turns = N = ?
Solution:
[tex]B = \mu_o \frac{I N}{L}}[/tex]
[tex]\frac{I N}{L} = B \div \mu_o[/tex]
[tex]IN = BL \div \mu_o[/tex]
[tex]N = BL \div (\mu_o I)[/tex]
[tex]N = ( 0.030 \times 0.42 ) \div ( 4 \pi \times 10^{-7} \times 4.3 )[/tex]
[tex]\boxed {N \approx 2332}[/tex]
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Physics
Chapter: Magnetic Field
A horizontal line above the time axis of a speed vs. time graph means an object is ___.
a zero
b constant
c decreasing
A horizontal line on a speed vs. time graph signifies that the object is maintaining a constant velocity because there is no change in speed over time.
A horizontal line above the time axis of a speed vs. time graph indicates that an object is travelling at a constant velocity. This is because the speed does not change over time, and thus the graph shows a straight line parallel to the time axis, with no slope. When examining an acceleration vs. time graph, a horizontal line at zero would mean the acceleration is zero, which aligns with the object maintaining a constant speed, as acceleration is the rate of change of velocity.
What is the electric potential of a 4.5 × 10-5 C charge that has an electric potential energy of 0.027 J?
Answer : Electric potential is 600 V
Explanation :
It is given that,
Electric charge, [tex]q=4.5\times 10^{-5}\ C[/tex]
Electric potential energy, [tex]U=0.027\ J[/tex]
The relation between the electric potential and the electric potential energy is given by :
[tex]U=qV[/tex]
[tex]V=\dfrac{U}{q}[/tex]
[tex]V=\dfrac{0.027\ J}{4.5\times 10^{-5}\ C}[/tex]
[tex]V=600\ V[/tex]
Hence, the electric potential is 600 V.
What is the correct displacement for the following vectors: 4km south, 2 km north, 5 km south, and 5 km north ?
Answer:
2 km south
Explanation:
In order to calculate this you just have to have in mind that your starting point will be 0, and as south and north are contrary, one of the will benegative, in this case we will take south as negative, so lets begin:
-4 km south
+2 km north
-5 km south
+5 km north
This equals -2 km, since it is negative we know that it´s south, so the displacement after all will be 2 kilometers south from the starting point.
There is a 12 v potential difference between the positive and negative ends of the jumper cables, which are a short distance apart. an electron at the negative end ready to jump to the positive end has a certain amount of potential energy. on what quantities does this electrical potential energy depend? view available hint(s)
A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 revolutions before coming to rest. find the constant angular acceleration (in rad/s2) of the centrifuge.
A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².
We can apply the following formula to determine the centrifuge's constant angular acceleration:
Δθ = ω₀t + (1/2)αt²
Δθ = ω₀t + (1/2)αt²
Since the final angular speed is 0, the formula becomes:
Δθ = ω₀t
48 rev * (2π rad/rev) = 381.92 rad/s * t
Simplifying:
96π rad = 381.92 rad/s * t
Dividing both sides by 381.92 rad/s:
t ≈ 0.251 s
Now, we can calculate the angular acceleration (α) using the rearranged formula:
α = (0 - ω₀) / t
α = (0 - 381.92 rad/s) / 0.251 s
α = -1522.71 rad/s²
Thus, the constant angular acceleration of the centrifuge is approximately -1522.71 rad/s².
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An experimenter finds that no photoelectrons are emitted from a particular metal unless the wavelength of light is less than 295 nm. her experiment will require photoelectrons of maximum kinetic energy 2.4 ev. what frequency light should be used to illuminate the metal?
The frequency of light is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.
To determine the frequency of light that should be used to illuminate the metal in order to produce photoelectrons with a maximum kinetic energy of 2.4 eV, we can use the relationship between energy, frequency, and wavelength in the context of the photoelectric effect.
The energy of a photon (light particle) is given by Planck's equation:
[tex]\[ E = h \cdot f \][/tex]
Where:
- [tex]\( E \)[/tex] is the energy of the photon in joules (J)
-[tex]\( h \)[/tex] is Planck's constant, approximately [tex]\( 6.626 \times 10^{-34} \)[/tex] J·s
- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)
We are given the maximum kinetic energy of the photoelectrons as 2.4 eV. To convert this to joules, we use the conversion factor [tex]\( 1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J} \)[/tex]
[tex]\[ E_{\text{max}} = 2.4 \, \text{eV} \times (1.602 \times 10^{-19} \, \text{J/eV}) \]\\\[ E_{\text{max}} = 3.845 \times 10^{-19} \, \text{J} \][/tex]
Now, since the photoelectrons are emitted only when the wavelength of light is less than 295 nm (nanometers), we can use the speed of light equation to relate frequency and wavelength:
[tex]\[ c = f \cdot \lambda \][/tex]
Where:
- [tex]\( c \)[/tex] is the speed of light, approximately [tex]\( 3.00 \times 10^8 \)[/tex] m/s
- [tex]\( f \)[/tex] is the frequency of the light in hertz (Hz)
- [tex]\( \lambda \)[/tex] is the wavelength of the light in meters (m)
First, we convert the wavelength limit of 295 nm to meters:
[tex]\[ \lambda_{\text{max}} = 295 \, \text{nm} \times (1 \, \text{m} / 10^9 \, \text{nm}) \][/tex]
[tex]\[ \lambda_{\text{max}} = 2.95 \times 10^{-7} \, \text{m} \][/tex]
Now, we can rearrange the speed of light equation to solve for frequency:
[tex]\[ f = \frac{c}{\lambda_{\text{max}}} \][/tex]
[tex]\[ f = \frac{3.00 \times 10^8 \, \text{m/s}}{2.95 \times 10^{-7} \, \text{m}} \][/tex]
[tex]\[ f = 1.016 \times 10^{15} Hz[/tex]
Therefore, the frequency of light that should be used to illuminate the metal and produce photoelectrons with a maximum kinetic energy of 2.4 eV is approximately [tex]\( 1.016 \times 10^{15} \)[/tex] Hz.
Which labels correctly identify the layers most closely associated with gamma rays and visible light? Z: Gamma rays X: Visible light X: Gamma rays Z: Visible light Z: Gamma rays Y: Visible light Y: Gamma rays Z: Visible light
Answer:
A on edge
Explanation:
A car with a mass of 525kg is being pushed west (left) by a force of 375n from its engine. the coefficient of friction felt by the car is .0420.
a.calculate the force weight of the car.
b.calculate the force friction acting on the car.
c.what is the net force acting on this car?
d.calculate the acceleration of the car.
Explanation:
It is given that,
Mass of the car, m = 525 kg
Applied force, F = 375 N
The coefficient of friction felt by the car is 0.42, [tex]\mu=0.42[/tex]
(a) The weight of the car is given by :
[tex]W=mg[/tex]
[tex]W=525\times 9.8[/tex]
W = 5145 N
(b) The force of friction acts in the opposite direction of motion. It can be calculated as :
[tex]f=\mu mg[/tex]
[tex]f=0.42\times 5145[/tex]
f = 2160.9 N
(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.
(d) As the net force acting on the car is 0. There will be no acceleration in the car.
Final answer:
a. The force weight of the car is 5145 N. b. The force friction acting on the car is 216.09 N. c. The net force acting on the car is 158.91 N. d. The acceleration of the car is 0.714 m/s².
Explanation:
a. To calculate the force weight of the car, we can use the formula:
Force weight = mass * acceleration due to gravity
Given that the mass of the car (m) is 525 kg and the acceleration due to gravity (g) is 9.8 m/s², we can substitute these values into the formula:
Force weight = 525 kg * 9.8 m/s² = 5145 N
So, the force weight of the car is 5145 N.
b. To calculate the force friction acting on the car, we can use the formula:
Force friction = coefficient of friction * force weight
Given that the coefficient of friction (µ) is 0.0420 and the force weight is 5145 N, we can substitute these values intothe formula:
Force friction = 0.0420 * 5145 N = 216.09 N
So, the force friction acting on the car is 216.09 N.
c. The net force acting on the car can be calculated by subtracting the force friction from the force applied by the engine:
Net force = force applied - force friction
Given that the force applied by the engine is 375 N and the force friction is 216.09 N, we can substitute these values into the formula:
Net force = 375 N - 216.09 N = 158.91 N
So, the net force acting on the car is 158.91 N.
d. To calculate the acceleration of the car, we can use Newton's second law of motion:
Force = mass * acceleration
Given that the force applied by the engine is 375 N and the mass of the car is 525 kg, we can substitute these values into the formula:
375 N = 525 kg * acceleration
Solving for acceleration:
acceleration = 375 N / 525 kg = 0.714 m/s²
So, the acceleration of the car is 0.714 m/s².