A box of mass 3.0 kg is accelerated from rest across a floor at a rate of 3.0 m/s2 for 4.0 s . what is the net work

Answers

Answer 1
Work done is given by multiplying force and distance.
Therefore; W = Force × distance
  but from the second newton's law of motion F=ma
Therefore; W = (ma) × d
Using; V= U + at
 V = 0 + (3×4)
 V = 12 m/s
 But d = (V+U)/2 (t)
        d = 12/2 (4)
           = 24 M
Hence;  W = ( 3 ×3 )× 24
                  = 216 J

Related Questions

A diver with a mass of 70.0 kg stands motionless at the top of a diving platform 3.0 m high. The diver’s initial vertical speed is zero. What is the diver’s potential energy relative to the water surface?

Answers

The answer is 2,058J. 

You can solve for the potential energy using the formula:

[tex]PE=mgh[/tex]

Where:
PE= potential energy
m= mass
g= 9.8m/s² (This is constant. This is acceleration due to gravity because the diver is positioned above the surface of the Earth.)
h= height

The given in your problem are the following:
m = 70kg
h = 3.0 m
g = 9.8m/s² (Again this is constant)

Just plug in your given in the formula and solve:
[tex]PE=mgh[/tex]
           [tex]=(70kg)(9.8m/s^{2})(3.0m)[/tex]
           [tex]=2,058kg.m^{2}/s^{2} or 2,058J[/tex]

Final answer:

The diver's potential energy relative to the water surface, calculated using the formula PE = mgh with given values, is 2058 Joules.

Explanation:

To calculate the diver's potential energy relative to the water surface, we use the formula for gravitational potential energy, which is PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height above the reference point (in this case, the water surface).

Given a diver with a mass of 70.0 kg standing 3.0 m high above the water, the calculation would be as follows:

PE = (70.0 kg) * (9.8 m/s2) * (3.0 m) = 2058 Joules.

Therefore, the diver's potential energy relative to the water surface is 2058 Joules.

Jessie draws a ray diagram to show how an image of a candle is produced by a concave mirror when the candle is placed in front of the center of curvature. Jessie thinks the image should be virtual and behind the mirror.
Which best describes Jessie’s error?

The object should be placed anywhere on the principal axis.
The object should be at the center of the curvature.
The object should be between the center and vertex.
The object should be between the focal point and vertex.

Answers

There are two rules of reflection for the concave mirror:
1)Any incident ray traveling parallel to the principal axis on the way to the mirror will pass through the focal point upon reflection.
2)Any incident ray passing through the focal point on the way to the mirror will travel parallel to the principal axis upon reflection.
Also, keep in that for concave mirror center of curvature is 2f.
Using these two rules we can construct the image. 
You should always use these two "special" rays, I will mark then 1 and 2 on the picture.
From the picture, we can see that if you place the object between the focus and vertex you get the virtual image.
The answer is: object should be between the focal point and the vertex

On Edge, the answer is D.

which of the following best describes the noble gases?

have an outer electron shell that needs only 1 electron

are highly reactive

have a full outer electron shell

combine easily with other elements

Answers

Answer: third option: have a full outer electron shell.

Explanation:

Noble gases is the family name given to the elements of group 18 of the periodic table.

The electron valence shell of all these elements is full:

He has two electrons wich is the maximum an atom of the first row can have.

Ne, Ar, Kr, Xe, and Rn (well you can include Og which is the last noble gas discovered; it is the element number 118), have 8 electrons on their valence electron shell, which is the maximum any element can have.

Precisely, that feature (valence shell full) accounts for the low reactivity of these elements, which conferred them the title of nobles (they hardly combine with other elements to form compounds).

If an object has a volume of 2 milliliters and a mass of 10 grams, calculate the density of the object.







If a neutral atom has a mass of 15 amu and an atomic number of 7, determine the number of protons, neutrons, and electrons in the atom.,

Answers

Density = mass/volume 10g/2mL=5g/mL Atomic mass= protons + neutrons Atomic number=protons In a neutral atom, electrons = protons 15 amu-7 atomic number = 8 neutrons, 7 protons and 7 electrons

Which statement accurately compares the weight of an object on these two planets

Answers

"An object weighs about two times as much on Jupiter as on Neptune." Hope this helps :)

If an element has 10 electrons, how many of them will be in the 2nd energy level?

Answers

At the second electron there will be 15 electron and if it has 10 proton it will have 20 electron. Hope u enjoy your grade!

Answer:

If an element has 10 electrons, 8 of them will be in the second energy level.

Explanation:

There are 7 energy levels, numbered from 1 to 7, and in which electrons are distributed, logically in order according to their energy level.

Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4, which are called: s, p, d, f. In the sub-level s there can only be a maximum of 2 electrons, in p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In level 1 there is only one sub-level, which will be the s. In level 2 there are 2 sub-levels, the s and the p. At level 3 there are 3 sub-levels s, p and d. And at level 4 there are 4 sub-levels, the s, the p, the d and the f.

Then, in level 1 there is only a maximum two electrons. In level 2 there are a maximum of 8 electrons. At level 3 there are a maximum of 18 electrons. And at level 4 there are a maximum of 32 electrons.

The filling of the orbitals occurs in increasing order of energy, that is, from the orbitals of lower energy to those of higher energy.

So, considering that at level 1 there can only be two electrons and that it is the lowest energy level, 2 of the 10 electrons that the element has will be located at that level. So 8 electrons remain to be located.

The next level to fill with electrons is 2. As this level can enter a maximum of 8 electrons, the electrons that remained to be located in level 1 will be located in level 2.

If an element has 10 electrons, 8 of them will be in the second energy level.

How does the usable form of nitrogen enter our bodies?

A.)by breathing in air
B.)by consuming plants
C.)by consuming water
D.)by burning fuel

Answers

Answer: B.)by consuming plants

Explanation:

There is about 78% nitrogen is available in the atmosphere. But living beings such as plants does not absorb it directly from the air. Instead they absorb the compounds of nitrogen from the soil. The soil bacteria convert the nitrogen oxides into ammonia, nitrates and nitrites in the soil in this way these bacteria fix atmospheric nitrogen into the soil. The plants absorb these forms of nitrogen, which are essentially required for the synthesis of proteins and nucleic acids. Nitrogen as an element becomes essential ingredients in all biomolecules. We humans and animals eat plants and through them the usable form of nitrogen in the form of biomolecules enters the body.

Answer:

the correct answer is B. by consuming plants

Explanation:

Suppose a star the size of our Sun, but of mass 8.0 times as great, were rotating at a speed of 1.0 revolution every 12 days. If it were to undergo gravitational collapse to a neutron star of radius 12 km, losing 3/4 of its mass in the process, what would its rotation speed be? Assume the star is a uniform sphere at all times.

(a) Assume that the thrown-off mass carries off no angular momentum, in rev/s

(b) Assume that the thrown-off mass carries off its proportional share (3/4) of the initial angular momentum, in rev/s

Answers

You have two different phases of the star: 1 the Sun-like phase and 2 the neutron star phase. The given quantities are:
r₁ = r(Sun) = 695700km
m₁ = 8 Msun
f₁ = 1 rev / 12 days
m₂ = [tex] \frac{1}{4} [/tex]·m₁

First thing, you need to transform the frequency in units of revolution/seconds
f₁ = 1 rev / (12·24·60·60) = 1 rev / 1036800 s

and then into angular velocity through the formula
ω₁ = 2πf = 6.06E-6 rad/s

a) If the angular momentum stays the same: L₁ = L₂
where L = I·ω    
and the momentum of inertia I is given by I = m·r²

Therefore, substituting we have:
m₁·r₁²·ω₁ = m₂·r₂²·ω₂

And we can find:

ω₂ = [tex] \frac{r1²w1}{0.25r2²} [/tex]

(remember m₂=[tex] \frac{1}{4} [/tex]·m₁ so we can cancel out the two m₁)

We obtain:
ω₂ = (695700²·6.06E-6)/(0.25·12²) = 81473.1 rad/s

we can transform it back into frequency:
f₂ = ω₂/2π = 1 rev / 12967 s = 7.7e-5 rev/s

b) If L₂ = [tex] \frac{1}{4} [/tex]·L₁
we do expect an angular velocity 4 times smaller.
Using the same formulas as above:

[tex] \frac{1}{4} [/tex]·m₁·r₁²·ω₁ = [tex] \frac{1}{4} [/tex]·m₁·r₂²·ω₂

ω₂ = [tex] \frac{r1²w1}{r2²} [/tex] =
     = [(695700²·6.06E-6)(12²) = 20368 rad/s

and 

f₂ = 1 rev / 3242 s = 3.08e-4 rev/s



(a) The final angular velocity [tex](\(\omega_2\))[/tex] of the neutron star is approximately [tex]\(1.42 \times 10^{-5}\)[/tex] rad/s.

(b) The final angular velocity [tex](\(\omega_2'\))[/tex] of the neutron star is approximately [tex]\(3.54 \times 10^{-6}\)[/tex] rad/s.

**(a) Assume that the thrown-off mass carries off no angular momentum:**

1. Calculate the initial moment of inertia [tex](\(I_1\)):[/tex]

[tex]\[I_1 = \frac{2}{5} \cdot (8 \cdot \text{mass of the Sun}) \cdot (\text{radius of the Sun})^2\][/tex]

  The mass of the Sun is approximately [tex]\(2 \times 10^{30}\)[/tex] kg, and the radius of the Sun is approximately 6.96 x [tex]10^8[/tex] meters. Calculate [tex]\(I_1\): \[I_1 = \frac{2}{5} \cdot (8 \times 2 \times 10^{30} \text{ kg}) \cdot (6.96 \times 10^8 \text{ m})^2\][/tex]

  This gives [tex]\(I_1 \approx 3.06 \times 10^{40}\) kg m^2.[/tex]

2. Calculate the initial angular velocity [tex](\(\omega_1\)):[/tex]

  The rotation period is 12 days, which is equivalent to [tex]\(12 \times 24 \times 60 \times 60\)[/tex] seconds. Calculate

[tex]\(\omega_1\): \[\omega_1 = \frac{2\pi}{12 \times 24 \times 60 \times 60} \text{ rad/s}\][/tex]

  This gives [tex]\(\omega_1 \approx 1.99 \times 10^{-7}\) rad/s.[/tex]

3. Calculate the initial angular momentum [tex](\(L_1\)): \[L_1 = I_1 \cdot \omega_1 = (3.06 \times 10^{40}\, \text{kg·m²}) \cdot (1.99 \times 10^{-7}\, \text{rad/s})\][/tex]

  This gives [tex]\(L_1 \approx 6.11 \times 10^{33}\) kg m^2/s.[/tex]

4. Calculate the final moment of inertia [tex](\(I_2\)):[/tex]

  The final radius of the neutron star is 12 km, which is equivalent to 12,000 meters. Calculate [tex]\(I_2\):[/tex]

[tex]\[I_2 = \frac{2}{5} \cdot (3/4 \cdot \text{mass of the Sun}) \cdot (12,000 \text{ m})^2\] \[I_2 = \frac{2}{5} \cdot (3/4 \cdot 2 \times 10^{30}\, \text{kg}) \cdot (12,000\, \text{m})^2\][/tex]

  This gives [tex]\(I_2 \approx 4.32 \times 10^{38}\)[/tex] kg·m².

5. Use the conservation of angular momentum [tex](\(L_1 = L_2\))[/tex] to find the final angular momentum [tex](\(L_2\)): \[L_2 = L_1 = 6.11 \times 10^{33}\, \text{kg·m²/s}\][/tex]

6. Calculate the final angular velocity [tex](\(\omega_2\))[/tex] of the neutron star:

[tex]\[\omega_2 = \frac{L_2}{I_2} = \frac{6.11 \times 10^{33}\, \text{kg·m²/s}}{4.32 \times 10^{38}\, \text{kg·m²}}\][/tex]

  This gives [tex]\(\omega_2 \approx 1.42 \times 10^{-5}\)[/tex] rad/s.

**(b) Assume that the thrown-off mass carries off its proportional share (3/4) of the initial angular momentum:**

1. Calculate the final angular momentum [tex](\(L_2'\))[/tex] considering that 3/4 of the initial angular momentum is carried away by the mass that is thrown off during the collapse:

[tex]\[L_2' = (1 - \frac{3}{4}) \cdot L_1 = (1 - 0.75) \cdot 6.11 \times 10^{33}\, \text{kg·m²/s}\][/tex]

  This gives [tex]\(L_2' \approx 1.53 \times 10^{33}\, \text{kg·m²/s}\).[/tex]

2. Calculate the final angular velocity [tex](\(\omega_2'\))[/tex] of the neutron star:

[tex]\[\omega_2' = \frac{L_2'}{I_2} = \frac{1.53 \times 10^{33}\, \text{kg·m²/s}}{4.32 \times 10^{38}\, \text{kg·m²}}\][/tex]

  This gives [tex]\(\omega_2' \approx 3.54 \times 10^{-6}\)[/tex] rad/s.

To know more about angular velocity:

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What will happen if you rub two different materials together?

Answers

it will cause heat from friction
Sometimes, electrons can also be tranferred

The surface pressures at the bases of warm and cold columns of air are equal. air pressure in the warm column of air will ______ with increasing height __________ than in the cold column.

Answers

In atmospheric science, surface pressure is the atmospheric pressure at a location on Earth's surface. It is directly proportional to the mass of air over that location. For numerical reasons, atmospheric models such as general circulation models (GCMs) usually predict the nondimensional logarithm of surface pressure.

The answer is decrease more slowly


What voltage would be measured across the 45 ohm resistor?

Answers

You would find the potential difference aka voltage, but more specifically it would be just the voltage that the resistor uses and not the whole circuit.

But if you want the voltage value it’s V=IR so whatever the current is multiply it by the 45 ohm resistor value

Answer:

C) 9.0 volts

Explanation:

Wave A has an amplitude of 2, and wave B has an amplitude of 2. What will happen when the crest of wave A meets the trough of wave B?

They will interfere to create a crest with an amplitude of 0.
They will interfere to create a crest with an amplitude of 2.
They will interfere to create a crest with an amplitude of 4.
They will bounce off each another.

Answers

They will interfere to create a crest with an amplitude of 0 as it’s basically addition so 2 + (-2) would equal 0 as they cancel out

Answer:

They will interfere to create a crest with an amplitude of 0.

Explanation:

It is given that,

Wave A has an amplitude of 2, and wave B has an amplitude of 2. The superposition of two waves is called interference of wave. When the resultant wave have maximum amplitude is called constructive interference while when the amplitude of resultant completely destructs, the destructive interference happens.    

When the crest of wave A meets the trough of wave B, then destructive interference occurs. the phase difference will be 180°. There resultant is given by :

[tex]R=\sqrt{A^2+B^2+2ABcos(180)}[/tex]

R = A - B

Here A = 2 and B = 2

⇒ R = 0

Hence, the correct option is (a) "They will interfere to create a crest with an amplitude of 0".

Four wires meet at a junction. it is assumed that two currents, i1 and i4, enter the node. an ammeter records a value of +4a for i1. currents i2 and i3 are travelling out of the node. i2 has 3a running through it, and i3 has 0.5 a running through it. what is the current in i4?

Answers

Kirchhoff’s Current Law states that sum of entering currents is equal to sum of exiting currents.
[tex] I_{IN} = I_{OUT} [/tex]

We are given information:
[tex] I_{1} = 4A \\ I_{2} = 3A \\ I_{3} =0.5A \\ I_{4} = ?[/tex]

Kirchhoff’s Current Law for our example is:
[tex] I_{1} + I_{4} = I_{2} + I_{3} [/tex]
[tex] 4 + x = 3 + 0.5 [/tex]
[tex] 4 + x = 3.5 [/tex]
[tex] x = -0.5A [/tex]

We got negative value for current. This means that current I₄ is not entering but it is leaving from the junction.

The pH of acid rain would be _____. greater than 7 less than 7 exactly 7 exactly 14

Answers

Less than 7, Ph of 7 is neutral Acid Rain would be between 4 and 0. 

Answer:

Less than 7.

Explanation:

pH scale in chemistry is used to measure the concentration of hydrogen ion. In other words, it is used to measure the extent of acidity or alkalinity of any solution. The pH scale having numbers that range from 0 to 14. The acidic solution has a lower pH value while the basic solution has a higher pH. The pH value of pure water is 7.

As the name implies acid rain, it is formed by the combination of sulfur and nitrogen oxides. The pH of acid rain is less than 7. Typically its value is 4.  

This is a large, rocky body found in space. It often orbits the sun in a belt between Mars and Jupiter.

Answers

Final answer:

Asteroids are rocky bodies in space that mostly orbit the Sun within the asteroid belt, located between Mars and Jupiter. They vary in size and are classified by composition as C-type, S-type, or M-type. The largest asteroid and dwarf planet in this belt is Ceres.

Explanation:

The large, rocky bodies that are often found orbiting the sun in a belt between Mars and Jupiter are known as asteroids. The region where most asteroids are found is called the asteroid belt, and this area extends from 2.2 to 3.3 AU from the Sun. Asteroids are mainly remnants of the initial solar system that existed before the planets formed, ranging from a few centimeters to hundreds of kilometers in size. While most asteroids reside within the asteroid belt, they are spread out with significant empty space between them, making navigation for spacecraft like Galileo and Cassini feasible.

Asteroids are classified into different types: C-type (carbonaceous), S-type (stony), and M-type (metallic). The largest known asteroid is Ceres, which is also classified as a dwarf planet. Understanding asteroids is important for planetary defense as well as for exploring the solar system's past.

A __________ sign on a truck means that the load on the truck is potentially dangerous.

Answers

The answer is:
diamond-shaped

A hazardous sign on a truck means that the load on the truck is potentially dangerous.

A hazardous sign on a truck means that the load on the truck is potentially dangerous. These signs are part of a system of hazard communication that includes symbols, labels, and placards to quickly and effectively convey information about the hazards of the materials being transported. The use of such signs is essential for the safety of everyone on the road, including the truck driver, other motorists, emergency responders, and the general public. It helps to ensure that appropriate precautions are taken when handling, transporting, and in the event of an accident involving, these materials.

Degausser creates a magnetic field that erases data from magnetic storage media.
a. True
b. False

Answers

The Answer is A. It's true.

Which of the following is true of energy? A. Energy can be created. B. Energy can be destroyed. C. Energy is constantly increasing. D. Energy is conserved.

Answers

Hello,

The answer is option D "Energy is conserved".

Reason:

The answer to this question is option D because it seems to be the best fit. Its not option A or B because energy cannot be created nor destroyed it only can be transformed into another type of energy. It shouldn't be C because energy is not always increasing because potential energy is the amount a energy that is in a object THATS NOT MOVING....therefore your answer is option D.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonpotrit

A solid uniform-density sphere is tied to a rope and moves (without spinning) in a circle with speed 7 m/s. The distance from the center of the circle to the center of the sphere is 1.8 m, the mass of the sphere is 6 kg, and the radius of the sphere is 0.89 m. The angular speed, w=5.62. What is the rotational kinetic energy of the sphere?,

Answers

Final answer:

The rotational kinetic energy of the sphere in a circular path (without spinning) is calculated using given parameters such as mass, radius, and angular speed, and the resultant rotational kinetic energy is approximately 227.03 Joules.

Explanation:

Answer

For the sphere, when it moves in a circular path without spinning, its rotational kinetic energy (K) is zero, because there's no internal rotation where the points in the body are moving through some angle due to spinning. However, if you are considering the entire motion of the system, then you could argue that there's rotational kinetic energy due to the rotation of the center of the circle. This is really a translational motion but in a circular path. The rotational kinetic energy can then be calculated using the equation, K = 1/2 (mr^2)w^2, where m is the mass of the sphere, r is the distance from the center of the circle to the center of the sphere, and w is the angular speed (not the angular velocity of the sphere itself if it was spinning). Lastly, substituting the known values: m=6 kg, r=1.8 m, and w=5.62 rad/s, we find that K = 1/2 * (6kg) * (1.8m)^2 * (5.62 rad/s)^2 = 227.0268 Joules.

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The rotational kinetic energy of the sphere is 30.03 Joules. This is calculated using the formula [tex]KE_{rot} = 0.5 \times I \times w^2[/tex], where I is the moment of inertia of the sphere and w is its angular speed.

To find the rotational kinetic energy of the sphere, we use the formula for rotational kinetic energy: [tex]KE_{rot} = 0.5 \times I \times w^2[/tex].

Where:

I - moment of inertia of the spherew - angular speed

For a solid sphere, the moment of inertia is given by:

[tex]I = (2/5) \times m \times R^2[/tex]

Substituting the given values:

[tex]I = (2/5) \times 6 kg \times (0.89 m)^2\\I = (2/5) \times 6 kg \times 0.7921 m^2\\I = 1.901 kg\cdot m^2[/tex]

Now, using the angular speed w = 5.62 rad/s:

[tex]KE_{rot} = 0.5 \times 1.901 kg\cdot m^2 \times (5.62 rad/s)^2\\KE_{rot} = 0.5 \times 1.901 kg\cdot m^2 \times 31.5844 rad^2/s^2\\KE_{rot} = 30.03 J[/tex]

Therefore, the rotational kinetic energy of the sphere is 30.03 Joules.

How are ocean ridges formed

Answers

The answer is divergent boundaries.
I hope this helps you!
Hello,

The answer is option B "divergent boundaries".

Reason:

Ocean ridges are formed by divergent boundaries which are boundaries the pull away from each other which allows the magma ti rise therefore making a ocean ridge which is why your answer is option B!

If you need anymore help feel free to ask me!

Hope this helps!

~Noportrit

2. Lower latitudes tend to have __________. (Points : 1)
lower average temperatures than higher latitudes
the same temperatures as higher latitudes
higher average temperatures than higher latitudes
you can't compare temperatures without including pressure data

Answers

Option c. higher average temperatures than higher latitudes
 Explanation:
 Lower latitudes are also called tropics which is the area of the globe which lies in 0 to 30 degrees of the equator. The region nearer to the equator is hotter as it is direct to the rays of the sun and higher latitudes (60 to 90 degrees) is the polar region which are the regions away from the equator and this the sun's rays falls slantly on those regions and they experience cold temperature whereas tropical region is warmer.

Answer:

Higher average temperatures then higher latitudes. I TOOK THE TEST!

Explanation:

A gas has a volume of 300 ml at 300 kpa. what will its volume be if the pressure is changed to 600 kpa?

Answers

I believe that it is 140 mL.

When you hold a warm bowl, the temperature of your palms of your hands increases this is example of

Answers

heat transfer is the answer

How can an electron in an atom lose energy to go from a higher energy level to a lower energy level? select one:
a. it exchanges gravitational potential energy for kinetic energy.
b. it loses gravitational potential energy.
c. it releases a photon equal in energy to its own energy drop.
d. it absorbs a photon equal in energy to its own energy drop.
e. it loses kinetic energy?

Answers

i belive that the answer is b. 

How many neutrons does element X have if its atomic number is 36 and its mass number is 74?

Answers

The atomic number Z of an element is the number of protons it contains (and in an atom it is equal to the number of electrons). The mass number M is close to the mass of one mol of the substance but it is defined as the number of protons and neutrons in the nucleus of the atom; there, the main mass of the atom is contained. Hence, N=M-Z=74-36=38(since M counts both protons and neutrons while Z only protons). Thus, it has 38 neutrons.

There are a truly enormous number of neutrons in any sample of Element X.

Why, EVERY ATOM of Element X has 38 of them in its nucleus !

The force due to gravity between two objects can be described using the equation fg = g m1 m2 / d2. according to this equation, if the distance between two objects increases, what happens to the gravitational force between them?

Answers

If the distance between the two object increases, then the force between them decreases.
In fact, the formula is
[tex]F=G \frac{m_1 m_2}{d^2} [/tex]
we can see that the distance d is at the denominator, therefore when d increases, the value of the fraction decreases, and so the gravitational force F decreases as well.

Increasing the distance between two objects decreases the gravitational force between them because the force is inversely proportional to the square of the distance.

According to the equation fg = G m1 m2 / d2, when examining the gravitational force (fg) between two objects, we look at two key factors: the product of their masses (m1 and m2) and the square of the distance between them (d2). The gravitational force is directly proportional to the product of their masses, meaning if the masses increase, the force increases. However, it is inversely proportional to the square of the distance between them, meaning if the distance (d) increases, the gravitational force decreases.

To illustrate this principle, if the distance between two objects is increased, the gravitational force between them decreases. This is because the force diminishes with the square of the distance increase, which is demonstrated by the 1/d2 factor in the equation. For example, if you increase the distance by a factor of 3, the gravitational force would decrease by a factor of 32 (or 9).

Therefore, as the distance between two objects increases, the gravitational force between them will indeed decrease, highlighting the importance of distance when considering gravitational interactions.

When an object is moving with uniform circular motion, the centropetal acceleration of the object?

Answers

Yes this is possible if the speed is changing. An object moves in a circular path at a constant speed. I hope this helps my friend.

Answer:

The correct answer is "is directed toward the center of motion".

Explanation:

When an object moves in a uniform circular motion, the centrifugal acceleration of the object is directed toward the center of the motion. This acceleration is the only acceleration of the object experiences when it has constant velocity on a circular path. This causes the body to be attracted to the center of the trajectory by a centripetal force that prevents the body from entering a rectilinear trajectory.

Have a nice day!

What is the magnitude of the electric force on an electron in a uniform electric field of strength 2050 n/c that points due east?

Answers

given E=2050 N/C

charge of an electron = 1.6×10^-19 C

USING E = F/Q , electric field = force ÷ charge

2050 = F ÷ (1.6×10^-19)....

make F subject of formula and get the answer 

A current of 12 amps is measured in a circuit with a total resistance of 9.0 ohms. What is the size of the voltage source that supplies this circuit?

a. 108 volts
b. 21 volts
c. 1.3 volts
d. 0.75 volts

Answers

a. 108 volts is the answer.
A 108 volts is the answer! I had to check to be sure :) Brainest?

An earth satellite in an elliptical orbit travels slowest when it is

Answers

The satellite travels slowest when it is at the maximum distance from the Earth.

We can verify this in two ways:

1) By using Kepler's second law: "A line segment joining a a satellite with the Earth covers equal areas during equal intervals of time". This means that the larger is the distance of the satellite from Earth, the slower it goes.

2) by looking at the forces acting on the satellite. There is only one force acting on it: the gravitational attraction exerted by Earth, and this force is the centripetal force that keeps the satellite in circular (elliptical, actually) motion. So we can write:
[tex]G \frac{Mm}{r^2}=m \frac{v^2}{r} [/tex]
where on the left we wrote the formula of the gravitational force, while on the right the centripetal force. G is the gravitational constant, M the Earth's mass, m the satellite's mass, v its velocity and r the distance of the satellite from the center of Earth.
Simplifying, we get
[tex]v= \sqrt{ \frac{GM}{r} } [/tex]
which is the speed of the satellite when it is at a distance r from Earth: the larger r, the smaller the speed v.
Final answer:

A satellite in an elliptical orbit around Earth moves slowest at its apogee, which is the point farthest from the Earth, due to the weaker gravitational force and conservation of angular momentum.

Explanation:

An earth satellite in an elliptical orbit travels slowest when it is at the point farthest from the Earth, known as the apogee.

In an elliptical orbit, satellites experience varying speeds. The speed is greatest at the point closest to Earth, called perigee, and lowest at the apogee. This is due to the conservation of angular momentum and energy: while the gravitational pull is strongest at the perigee resulting in higher velocity, it is weakest at the apogee, hence causing the satellite to move slower.

Orbital dynamics, such as the one described, are dictated by Kepler's laws of planetary motion where among others, it states that a planet or satellite will sweep out equal areas in equal times, leading to a change in speed depending on its position along the orbit. Thus, as a satellite moves away from the Earth, to the apogee of its orbit, its orbital speed decreases due to the weaker gravitational force at that point.

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