Answer:
The 'b x h' side of the brick exerts more pressure on the ground, P = 1428.57 N/m²
Explanation:
Given data,
The dimension of the brick, l = 10 cm = 0.1 m
b = 7 cm = 0.07 m
h = 5 cm = 0.05 m
The force exerted by the brick on ground, F = 5 N
The brick has three 2 x 3 sides, b x h, l x h, and l x b
The area of the side, A₁ = b x h
= 0.07 x 0.05
= 0.0035 m²
The area of the side, A₂ = l x h
= 0.1 x 0.05
= 0.005 m²
The area of the side, A₃ = 0.1 x 0.07
= 0.007 m²
The pressure exerted by the surface A₁ on the ground, P₁ = F/A₁
= 5 / 0.0035
= 1428.57 N/m²
The pressure exerted by the surface A₁ on the ground, P₂ = F/A₂
= 5 / 0.005
= 1000 N/m²
The pressure exerted by the surface A₁ on the ground, P₃ = F/A₃
= 5 / 0.007
= 714.29 N/m²
Hence, the 'b x h' side of the brick exerts more pressure on the ground, P = 1428.57 N/m²
A golfer takes two putts to sink his ball in the hole. The first putt displaces the ball 6.50 m east, and the second putt displaces it 5.90 m south. What displacement would put the ball in the hole in one putt?
Explanation:
Let east represent X axis and north represent Y axis.
We need to find what displacement would put the ball in the hole in one putt.
The first putt displaces the ball 6.50 m east
First displacement = 6.50 i m
The second putt displaces it 5.90 m south
Second displacement = -5.90 j m
Total displacement = 6.50 i - 5.90 j
[tex]\texttt{Magnitude = }\sqrt{6.50^2+(-5.90)^2}=8.78m\\\\\texttt{Direction = }tan^{-1}\left ( \frac{-5.9}{6.5}\right )=-42.23^0[/tex]
So displacement to hole from initial position is 8.78 m at direction 42.23° south of east.
An airplane changes its velocity uniformly from 150 m/s to 60 m/s in 15 s. Calculate:
a. Its acceleration
b. The distance traveled in that time
Answer:2.5
Explanation:
Which factors affect heat transfer between a warm and a cool substance?
the time it took to hear the substance, the area of contact and the specific heats of the substances
the amount of time of contact, the area of contact, and the specific heals of the substances
the time it took to heat the substance, the area of the substances, and the specific heats of the substances
the amount of time of contact, the area of the substances, and the specific heats of the substances
The heat transfer depends on the factors such as the amount of time of contact, the area of contact, and the specific heals of the substances.
What is Heat Transfer?The process of flow of energy from a body of higher temperature to a lower temperature is known as heat transfer.
The mathematical expressions governing the concept of heat transfer are given as follows-
Q = m × c × ΔT
here,
m is the mass of the body.
c is the specific heat.
ΔT is the change in temperature.
And,
Q = k × A×ΔT / L
here,
k is the thermal conductivity.
A is the area of contact and L is the length of the body.
So, clearly, heat transfer depends on the factors such as specific heat and the area of contact. Moreover, the time of contact is also a matter of discussion as the longer the contact time, the more amount of energy will get a transfer from one body to another.
Thus, we can conclude that the heat transfer depends on the factors such as the amount of time of contact, the area of contact, and the specific heals of the substances.
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The force on a particle of mass m is given by F=26i-12t2j where F is in N and in s. What
will be the change in the particle’s momentum between 1.0s and 2.0s
Answer:
26i-28j
Explanation:
Mathematically, rate of change of something with respect to another is obtained through the operation called differentiation. Integration is the reverse process of differentiation.
We know that force is the rate of change of momentum.
that is,
F=[tex]\frac{dP}{dt}[/tex]
where,
P=momentum
t=time
dP=small change in momentum
dt=small change in time
dP=Fdt (multiplying both sides with dt)
To get change of momentum within a particular time interval, we have to integrate the above expression giving the necessary limits according to the problem.
Here, we have to calculate the change in momentum between 1.0s and 2.0s. So, the limit of integration is 1.0 to 2.0.
Thus,
[tex]\int\limits^P_p {} \, dP[/tex]=[tex]\int\limits^2_1 {F} \, dt[/tex]
where,
p=momentum at t=1s
P=momentum at t=2s
substituting F in the above equation,
[tex]\int\limits^P_p {} \, dP[/tex]=[tex]\int\limits^2_1 {26i-12jt^{2}} \, dt[/tex]
[tex]\int\limits^P_p {} \, dP[/tex] = P-p = Change in momentum between 1.0s and 2.0s
[tex]\int\limits^2_1 {26i-12jt^{2}} \, dt[/tex] = [tex]\int\limits^2_1 {26i} \, dt - \int\limits^2_1 {12t^{2}j } \, dt[/tex] (Since we can integrate each term of an expression separately)
[tex]\int\limits^2_1 {26i} \, dt - \int\limits^2_1 {12t^{2}j } \, dt[/tex] = [tex]26i(2-1) - 12j(\frac{2^{3} -1^{3} }{3} )[/tex]
=26i-28j
therefore the change in momentum between 1.0s and 2.0s is 26i-28j.
Note: the answer we got is a vector. Because momentum is a vector and therefore change in momentum is also a vector
To find the change in momentum of a particle under the force F=26i-12t2j from 1.0s to 2.0s, we first integrate the force over the given time interval. The change in the particle's momentum is found to be 26i - 20/3j kg*m/s.
The question involves calculating the change in momentum of a particle when a force F=26i-12t2j is applied from 1.0s to 2.0s. To find the change in momentum, we first need to integrate the force over the given time interval, because the change in momentum (Δp) is equal to the integral of the force over time, according to the impulse-momentum theorem, Δp = ∫t1t2 F dt.
For the i-component, the force is constant (26i), so its contribution to the change in momentum from 1.0s to 2.0s is simply 26i N multiplied by the time interval, which is 26i N * (2.0s - 1.0s) = 26i kg*m/s. For the j-component, the force varies with time (-12t2j), so we need to integrate this force from 1.0s to 2.0s. The integral of -12t2 from 1 to 2 gives us -∫12 12t2 dt = -[4t3/3]12 = -8 + 4/3 = -24/3 + 4/3 = -20/3. Thus, the change in momentum in the j-direction is -20/3 j kg*m/s.
Combining the i and j components, the total change in the particle's momentum between 1.0s and 2.0s is 26i - 20/3j kg*m/s.
why is "Galloping Gertie" an appropriate nickname for the bridge
Answer:
"Galloping Gertie" is an appropriate nickname for the bridge Tacoma Narrows.
Explanation:
The Tacoma Narrows Bridge is slender, elegent and graceful bridge is stretched like a steel ribbon across Puget Sound in 1940.
When Galloping Gertie splashed into Puget Sound, it created ripple effects across the nation and around the world. The event changed forever how engineers design suspension bridges.
Tacoma Narrows Bridge The original bridge received its nickname "Galloping Gertie" because of the vertical movement of the deck observed by construction workers during windy conditions.
Final answer:
The nickname 'Galloping Gertie' is appropriate for the bridge because it refers to the Tacoma Narrows Bridge, which famously collapsed due to strong winds.
Explanation:
The nickname 'Galloping Gertie' is appropriate for the bridge because it refers to the Tacoma Narrows Bridge, which famously collapsed due to strong winds. When the bridge experienced wind-induced vibrations, it appeared to be galloping like a horse, hence the nickname. The collapse of Galloping Gertie serves as an important lesson in engineering and the need for understanding the effects of forces on structures.
Why do physicists say mass is more fundamental than weight??
Answer:
because mass of a matter never changes
on the other hand the weight of a matter changes due to gravity
for example the
on the moon the pull of gravity is less than it is on earth so the Weight of an object will be less on the moon but the mass of it will stay the same
Explanation:
I
Mass is more fundamental than weight because mass is a consistent measure of the quantity of matter, whereas weight is the gravity-dependent force acting on an object and can vary. The confusion between these terms occurs often in everyday language, especially since they are used interchangeably.
Physicists say that mass is more fundamental than weight because mass is an intrinsic property of an object that represents the quantity of matter, which does not vary in classical physics. Conversely, weight is the gravitational force acting on an object, which can vary depending on the location and gravity. Therefore, mass is a more consistent and universal characteristic of matter than weight, which can differ even on Earth depending on elevation or geographic location.
The confusion between mass and weight arises as the terms are used interchangeably in everyday language. For instance, our medical records may show our weight in kilograms, which is actually a unit of mass, instead of the correct unit of newtons, which is used to measure gravitational force. This interchangeability of terms has led to a common misunderstanding of these distinct physical quantities.
The relationship between mass and weight becomes particularly evident in space.
What is the definition of a neutron?
Answer:
neutron is a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.
Answer:
According to Oxford dictionary neutron is a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.
Suggest possible explanations why reaction times are different for different people?
Everyone has a different reaction time because not everyone reacts the same to situations. Some people may be faster or slower than others. It could be a result of age, health, and how they take care of themselves physically.
Gender, age, physical fitness, level of exhaustion, distraction, alcohol usage, personality type, the limb utilized for the test, biological rhythm, health, and whether the stimulus is auditory or visual have all been found to have an impact on reaction time. Social and cultural factors on reaction time are irrelevant.
What is reaction time?A reaction is a deliberate, free response to an outside stimulus. The reaction time is the amount of time between the administration of an external stimulus and the appropriate motor response.
The period between the introduction of the stimulus and the emergence of the subject's proper voluntary response is referred to as the reaction time.
Typically, it is measured in milliseconds. It depicts the rate at which stimuli operate on a person's sensory system to produce neurophysiological, cognitive, and informational processes.
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What are some sir issac newtons greatest accomplishments?
Answer:#1 NEWTON’S THREE LAWS OF MOTION LAID THE FOUNDATION OF CLASSICAL MECHANICS #2 HE WAS THE FIRST TO FORMULATE THE NOTION OF GRAVITY AS A UNIVERSAL FORCE
#3 NEWTON’S PRINCIPIA IS ONE OF THE MOST IMPORTANT WORKS IN THE HISTORY OF SCIENCE
#4 HE DISCOVERED THE GENERALISED BINOMIAL THEOREM IN 1665
#5 ISAAC NEWTON INVENTED CALCULUS
#6 HE INVENTED THE FIRST REFLECTING TELESCOPE
#7 HE DID GROUND BREAKING WORK IN OPTICS
#8 HE IDENTIFIED LIGHT AS THE SOURCE OF COLOUR SENSATION
#9 HE INFERRED CORRECTLY THE OBLATENESS OF EARTH’S SPHEROIDAL FIGURE
#10 SIR ISAAC NEWTON WAS THE SECOND SCIENTIST TO BE KNIGHTED
Answer:
Invented the reflecting telescope.
Proposed new theory of light and color.
Discovered calculus.
Developed three laws of motion.
Devised law of universal gravitation.
Advanced early modern chemistry.
Explanation:
Sir Isaac Newton had many great accomplishments. Here are some of his most notable achievements:
1. Newton's Three Laws of Motion: Newton formulated three fundamental laws that laid the foundation of classical mechanics. These laws describe how objects move and interact with each other. They are still widely used today to understand and predict the motion of objects.
2. Formulation of Gravity: Newton was the first to formulate the notion of gravity as a universal force. He explained that every object with mass attracts other objects towards it. His understanding of gravity helped explain why objects fall to the ground and why planets orbit the Sun.
3. Principia: Newton's book called "Mathematical Principles of Natural Philosophy" (commonly known as "Principia") is one of the most important works in the history of science. In this book, Newton presented his laws of motion and the law of universal gravitation. It revolutionized the field of physics and became the foundation for classical mechanics.
4. Generalized Binomial Theorem: In 1665, Newton discovered the generalized binomial theorem, which is a mathematical formula used to expand powers of binomials (expressions with two terms). This theorem is still studied and applied in various branches of mathematics.
5. Invention of Calculus: Newton independently developed calculus, a branch of mathematics that deals with rates of change and the accumulation of quantities. Calculus is widely used in many fields, including physics and engineering, and it provides a powerful tool for solving problems involving change and motion.
6. Invention of the Reflecting Telescope: Newton constructed the first reflecting telescope, which used mirrors instead of lenses to gather and focus light. This invention greatly improved the quality and clarity of images observed through telescopes and had a significant impact on the field of astronomy.
7. Groundbreaking Work in Optics: Newton conducted groundbreaking experiments and made important discoveries in the field of optics. He demonstrated that white light is composed of different colors, which led to the understanding of the color spectrum. His work on optics laid the foundation for future developments in this field.
8. Identification of Light as the Source of Color Sensation: Newton proposed that light is the source of color sensation. He demonstrated that the colors we perceive are a result of how light interacts with objects and our eyes. This understanding of light and color perception has had lasting effects in fields like art and design.
9. Inference of Earth's Oblateness: Newton correctly inferred that the Earth is not a perfect sphere but rather oblate, meaning it is slightly flattened at the poles and bulges at the equator. His understanding of the Earth's shape was based on his knowledge of gravity and the forces acting on the planet.
10. Knighthood: Newton was knighted by Queen Anne in 1705, becoming the second scientist to receive this honor. His contributions to science and mathematics were recognized and celebrated during his lifetime.
a 50 kg pole vaulter drops vertically from a height of 4 meters coming to rest just .4s after his feet touch the ground, what is his momentum just before his feet touch the ground? what net force acts on him during his acceleration?
1) His momentum before touching the ground is 442.5 kg m/s
2) The net force on the pole vaulter is 490 N
Explanation:
1)
The motion of the pole vaulter is a motion of free fall, so it is subjected only to the force of gravity. Therefore, he falls to the ground at constant acceleration ([tex]g=9.8 m/s^2[/tex], acceleration of gravity), so we can use the following suvat equation to find his final velocity:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u = 0 is the initial velocity
[tex]a=g[/tex] is the acceleration
s = 4 m is the distance covered during the fall
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(4)}=8.85 m/s[/tex]
And therefore, his final momentum before touching the ground is
[tex]p=mv[/tex]
where m = 50 kg is his mass. Substituting,
[tex]p=(50)(8.85)=442.5 kg m/s[/tex]
2)
As we said previously, the only force acting on the pole vaulter during his fall is the force of gravity, which is
[tex]F=mg[/tex]
where
m = 50 kg is the mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Substituting, we find the force of gravity, and therefore the net force acting on the pole vaulter:
[tex]F=(50)(9.8)=490 N[/tex]
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Think Critically Predict what would happen to the volume of a gas
if the pressure on that gas were doubled and then the absolute
temperature of the gas were doubled.
The volume of the gas does not change
Explanation:
To solve this problem, we can apply the ideal gas equation, which states that:
[tex]\frac{pV}{T}=const.[/tex]
where
p is the pressure of the gas
V is its volume
T is its absolute temperature
The equation can also be written as
[tex]\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}[/tex]
where in this problem we have:
[tex]p_1[/tex] is the initial pressure of the gas
[tex]V_1[/tex] is the initial volume
[tex]T_1[/tex] is the initial temperature
[tex]p_2 = 2 p_1[/tex] is the final pressure (twice the initial pressure)
[tex]V_2[/tex] is the final volume
[tex]T_2 = 2T_1[/tex] is the final temperature (twice the initial temperature)
Solving for V2, we find what happens to the volume of the gas:
[tex]V_2 = \frac{p_1 V_1 T_2}{p_2 T_1}=\frac{p_1 V_1 (2T_1)}{(2p_1) T_1}=V_1[/tex]
Therefore, the volume of the gas does not change.
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During study group Mary and Ben were arguing about a question on the practice test. The question said "True or False: The amount of mass of an object determines the amount of force that is needed to accelerate it." Mary said the answer was false, but Ben thinks it is true. Who is right? Justify your answer.
a.Mary is correct because according to Newton's first law it is unbalanced forces that cause an object to accelerate.
b. Ben is correct. According to Newton's 3rd law force is determined by mass.
c. Ben is correct. According to Newton's 2nd law of motion objects with more mass require more force to accelerate.
d. Mary is correct because it is the type of force that determines the acceleration, not the mass.
c. Ben is correct. According to Newton's 2nd law of motion objects with more mass require more force to accelerate.
Explanation:
We can answer this question by using Newton's second law of motion, which states that the net force applied on an object is equal to the product between the mass of the object and its acceleration. Mathematically:
[tex]F=ma[/tex]
where
F is the net force
m is the mass of the object
a is its acceleration
From the equation, we notice that:
- The force is directly proportional to the mass of the object --> so if the mass increases, the force needed to accelerate the object will increase too
Therefore, the correct answer is
c. Ben is correct. According to Newton's 2nd law of motion objects with more mass require more force to accelerate.
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A group of researchers is studying the effects of stress on decision making. They provide a group of candidates with questionnaire to fill
out and place them in mildly stressful situations. The following table shows the time taken to complete the questionnaire what is the
mean and median of the sample data?
subject 1 120 seconds
subject 2 139 seconds
subject 3 103 seconds
subject 4 100 seconds
subject 5 112 seconds
The median of the samples
The mean of the sample set is. ____________. The median of the sample set is ____________.
Answer:
Mean: 114.8
Median: 112
Explanation:
The mean is the average of the numbers so you add them all together and divide by the number of terms. The median is the middle value when the terms are in order from least to greatest.
Answer:
Mean of the sample set = 114.8
Median of the sample set = 112
Explanation:
To calculate mean, add value of all samples and then divide with number of samples.
Mean of the sample set = (100+103+112+120+139)/5 = 114.8
To calculated median, arrange the values in ascending order then take the value which is at middle.
100, 103, 112, 120, 139
“112” is at the middle so,
Median of the sample set = 112
what is the mass of a cannonball whose velocity is 100 m/s if it were shot from a 2500 kg cannon that recoiled at a speed of 3 m/s
The mass of the cannonball is 75 kg
Explanation:
We can solve this problem by using the law of conservation of momentum: in fact, the total momentum of the ball-cannon system before and after the shot must be equal.
Before the shot, the total momentum is zero, since both objects are at rest:
[tex]p=0[/tex] (1)
After the shot, the total momentum is: given by:
[tex]p=mv+MV[/tex] (2)
where :
m kg is the mass of the cannonball
v = 100 m/s is the velocity of the ball
M = 2500 kg is the mass of the cannon
V = -3 m/s is the recoil velocity of the rifle (in the opposite direction to the ball
Since the toal momentum is conserved, (1) = (2), therefore we can solve for m, the mass of the cannonball:
[tex]0=mv+MV\\m=-\frac{MV}{v}=-\frac{(2500)(-3)}{100}=75 kg[/tex]
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3-) A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of
road. A boy riding on the back of the truck throws a can of soda upward (Fig. P4.54) and catches the
projectile at the same location on the truck bed, but 16.0 m farther down the road.
(a) in the frame of reference of the truck, at what angle does the boy throw the can? .
(b) What is the initial speed of the can relative to the truck?
given,
constant velocity = 9.50 m/s
acceleration = 0
distance = 16 m
the time of flight
s = so + ut + 1/2at²
16 = 9.50 × t
t = 1.68 s
a) to catch the can the truck he must throw it straight up, at 0° to the vertical.
b) now,
yf = Yi + UyT + 1/2at²
0 = 0 + Uy * 1.68 - 1/2 * 9.8 * 1.68²
Uy = 8.23 m/s
Which choice can be defined as the space around any charged particle that is directed away from a positive charge and towards a negative charge?
gravitational field
magnetic field
proton field
electric field
Answer:electric field
Explanation:Because in an electric field, positive charge is directed away and negative charge is directed towards the electric field.
Answer:
an electric field
Explanation:
this field is what is direted to a negative charge
Pus is a mixture of dead neutrophils, dead tissue, bacteria, and living white blood cells.
A.
True
B.
False
Final answer:
The statement is true, as pus is composed of dead neutrophils, dead tissue, bacteria, and living white blood cells. It reflects the immune system's response to infection, with pus indicating an accumulation of these elements at the site of infection.
Explanation:
The statement "Pus is a mixture of dead neutrophils, dead tissue, bacteria, and living white blood cells" is true. Pus is indeed an accumulation of these components. When neutrophils, which are a type of leukocyte, respond to an infection, they engulf pathogens in a process called phagocytosis. The dead neutrophils, along with any other cellular debris, dead pathogens, and living immune cells, such as macrophages still fighting the infection, aggregate to form pus at the infection site.
This purulent or suppurative discharge is a typical sign of the body's defensive responses engaging with the invading microorganisms. While small amounts of pus can indicate a healthy immune response, in history, there were attempts to produce pus artificially under the misguided notion that it could aid in healing. We now know that inducing pus does not promote recovery and that a natural immune response is best in fighting infections.
how much electrical energy is used by a 400 W toaster that is operating for 5 minutes?
The electrical energy consumed by a toaster is 0.033 Kwh.
Explanation:
The power utilized by the toaster is 400 W.
[tex]\text { The power utilized by the toaster is } 400 \mathrm{W} \text { in kilo-watts is } \frac{400}{1000}=0.4 \mathrm{Kw}[/tex]
The toaster is operated for 5 Minutes.
[tex]\text { The toaster is operated for } 5 \text { Minutes in hours is } \frac{5}{60}=0.083 \text { hours. (One minute is } 60 \text { seconds) }[/tex]
We know that,
[tex]\text {power}=\frac{\text {energy}}{\text {time}}[/tex]
Substitute the values in the above formula to obtain electrical energy,
[tex]0.4=\frac{\text { energy }}{0.083}[/tex]
Electrical energy = 0.4 × 0.083
Electrical energy is 0.033 Kwh.
Answer:
The answer is 120,000 Joules
Explanation:
A 2.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 27.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2.
If the coefficient of kinetic friction between
the block and the wall is 0.40, find
a) the work done by the force on the block.
Answer in units of J.
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.
1) Work done by the force: 8.3 J
2) Work done by gravity: -19.6 J
3) Normal force: 16.3 N
Explanation:
1)
The work done by a force pushing an object is given by
[tex]W=Fd cos \alpha[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\alpha[/tex] is the angle between the direction of the force and of the displacement
First of all, we need to find the magnitude of the force F. Since the block is moving vertically at constant velocity (= zero acceleration), the equation of motion of the block along the vertical direction is:
[tex]F sin \theta - \mu N - mg = 0[/tex] (1)
Where
[tex]\theta=27.0^{\circ}[/tex]
[tex]\mu N[/tex] is the force of friction, where
[tex]\mu=0.40[/tex] is the coefficient of friction
N is the normal reaction of the wall
(mg) is the weight of the block, where
m =2.0 kg is the mass of the block
[tex]g=9.81 m/s^2[/tex] is the acceleration of gravity
Along the horizontal direction, the equation of motion is:
[tex]F cos \theta = N[/tex] (2)
Substituting (2) into (1),
[tex]F sin \theta - \mu F cos \theta - mg =0[/tex]
And solving for F,
[tex]F(sin \theta - \mu cos \theta) = mg\\F=\frac{mg}{sin \theta - \mu cos \theta}=\frac{(2.0)(9.81)}{sin 27^{\circ} - 0.40 cos 27^{\circ}}=18.3 N[/tex]
Now we can calculate the work done by the force. Here we have
d = 1.0 m is the displacement
[tex]\alpha = 90^{\circ} - 27^{\circ} = 63^{\circ}[/tex] is the angle between the direction of the force and the displacement
Substituting,
[tex]W=(18.3)(1.0)(cos 63^{\circ})=8.3 J[/tex]
2)
The work done by gravity is equal to:
[tex]W_g = mg d cos \alpha[/tex]
where
m = 2.0 kg is the mass of the block
[tex]g=9.81 m/s^2[/tex]
d = 1.0 m is the displacement
[tex]\alpha=180^{\circ}[/tex], since the direction of gravity is downward while the displacement of the block is upward
Substituting,
[tex]W=(2.0)(9.81)(1.0)(cos 180^{\circ})=-19.6 J[/tex]
3)
Equation (2) found in part 1) tells that
[tex]N=F cos \theta[/tex]
which means that the normal force between the wall and the block is equal to the horizontal component of the pushing force on the block.
Here we have:
F = 18.3 N is the magnitude of the pushing force
[tex]\theta=27.0^{\circ}[/tex] is the angle of the force with the horizontal
Substituting, we find the normal force:
[tex]N=(18.3)(cos 27^{\circ})=16.3 N[/tex]
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The work done by the force on the block is 22.3 J. The work done by gravity is 19.6 J and the normal force between the block and the wall is 18.1 N.
Explanation:Firstly, we need to calculate the force that is applied (Force Applied) by taking the cosine of the angle (27.0◦) which is the force applied horizontally. Using the formula F_applied = m*g/cos(θ), where m=2.0 kg and g=9.81 m/s^2, we find that Force Applied = 22.3 N.
Next, the work done by the force on the block (Work Done) can be calculated by multiplying the Force Applied by the distance it moved (Force Applied x distance). Here, Work Done = 22.3 N x 1.0 m = 22.3 J.
The work done by gravity is obtained by multiplying the weight of the block by the distance it moves vertically (Work Done by Gravity). Here, Work done by Gravity = m*g*d = 2.0 kg * 9.81 m/s^2 * 1.0m = 19.6 J.
Finally, we calculate the magnitude of the normal force by multiplying the weight of the block by the cosine of the angle (m*g*cos(θ)) which equals to Normal Force = 2.0 kg * 9.81 m/s^2 * cos(27.0◦) = 18.1 N.
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8. Using a ramp 6 meters long, workers apply an effort force of 1250 N to move a
2000 N (F.) crate onto a platform 2 meters high. What is the efficiency of the
ramp? (Hint: calculate Win & Wout, then efficiency
The efficiency of the machine is 0.53 (53%).
Explanation:
The efficiency of a machine is given by:
[tex]\eta = \frac{W_{out}}{W_{in}}[/tex]
where
[tex]W_{out}[/tex] is the output work
[tex]W_{in}[/tex] is the work in input
The output work is:
[tex]W_{out}=F_L d_L = (2000)(2)=4000 J[/tex]
where
[tex]F_L = 2000 N[/tex] is the load
[tex]d_L = 2 m[/tex] is the distance covered by the load
The input work is:
[tex]W_{in}=F_E d_E = (1250)(6)=7500 J[/tex]
where
[tex]F_E = 1250 N[/tex] is the effort force
[tex]d_E = 6 m[/tex] is the distance from the effort to the pivot
Solving for the efficiency,
[tex]\eta=\frac{4000}{7500}=0.53[/tex]
So, the efficiency of the machine is 0.53 (53%).
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If you could only see the lights in the circuit and the wires were covered from view, how could you determine the type of circuit the lights are arranged in?
To determine the type of circuit by only viewing the lights, one can observe the behavior when a light is manipulated; all lights going out suggests a series circuit, while others staying lit indicates a parallel circuit. Brightness changes with the addition or removal of lights also help identify the circuit type.
If you could only see the lights in a circuit and the wires were concealed, determining if the lights are arranged in a series or parallel circuit could be inferred by observing the behavior of the lights when one is manipulated. For example, if one light goes out and the others remain lit, it suggests a parallel circuit, as each light has its own path to the power source. However, if one light goes out and the rest do as well, this indicates a series circuit, where all lights are in a single path and the current must flow through each light consecutively.
Another method to determine the circuit type is by observing brightness changes when more lights are added or removed. In a series circuit, adding more lights would generally cause all lights to dim since the same current flows through each component and the total resistance increases. In contrast, in a parallel circuit, adding or removing lights would not change the brightness of the other lights, as each has an independent connection to the power source and their voltages remain constant.
Someone throws their laptop with a horizontal component of velocity of 25 m/s. It takes the laptop 3.00 seconds to come back to the original height. Calculate the horizontal range and the initial vertical component of velocity
1) The horizontal range of the laptop is 75.0 m
2) The initial vertical component of the velocity is 14.7 m/s
Explanation:
1)
The motion of the laptopin this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
To find the horizontal range of the laptop, we just need to analyze its horizontal motion.
We know that:
- The laptop moves horizontally with a constant velocity of [tex]v_x = 25 m/s[/tex]
- The time of flight of the laptop is [tex]t=3.00 s[/tex]
So, the horizontal range of the laptop is given by
[tex]d=v_x t = (25)(3.00)=75.0 m[/tex]
2)
The total time of flight of a projectile is given by
[tex]t=\frac{2u_y}{g}[/tex]
where
[tex]u_y[/tex] is the initial vertical component of hte velocity
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Here we know that the time of flight is
[tex]t=3.00 s[/tex]
Therefore, we can solve the formula for [tex]u_y[/tex], to find the initial vertical velocity:
[tex]u_y = \frac{tg}{2}=\frac{(3.00)(9.8)}{2}=14.7 m/s[/tex]
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Un cuerpo se mueve a la derecha sobre una superficie horizontal áspera a una velocidad constante bajo la acción de una fuerza horizontal de 15 N. Determine:
a) Modulo y dirección de la fuerza de roce
Answer:
Fuerza de roce = 15 N
Hacia la izquierda
Explanation:
Las leyes de Newton explican el comportamiento de cuerpos bajo efectos de fuerzas externas. La primera ley especifica que un cuerpo no cambiará su estado de movimiento mientras una fuerza desequilibrante no lo acelere. Es decir, un cuerpo que se mueve a velocidad constante, tiene cero fuerza desequilibrante.
Como el cuerpo se está moviendo a velocidad constante, no hay aceleración y por lo tanto la fuerza total es cero.
Dado que estamos aplicando una fuerza horizontal de 15N y aún así el cuerpo se mueve a velocidad constante, significa que esa fuerza está siendo contrarrestada por la fuerza de roce hasta producir un equilibro de fuerzas y por lo tanto, cero fuerza desequilibrante.
La fuerza de roce es entonces, en módulo igual a la fuerza aplicada, es decir, 15 N
Su dirección siempre es opuesta al movimiento, así que la fuerza de roce se dirige hacia la izquierda
This graph describes the motion of a sky diver that jumped from an airplane. The skydiver is MOST LIKELY ?
A) being influenced by equal amounts of gravity and air resistance.
B) slowing down because of an unbalanced force of air resistance.
C) accelerating because of an unbalanced force of gravity.
Eliminate
D) on the ground and is not falling anymore.
Answer:
A) being influenced by equal amounts of gravity and air resistance.
Explanation:
B) slowing down because of an unbalanced force of air resistance.
False - if it was slowing down, then the velocity would go down.
D) on the ground and is not falling anymore.
False - This would be mistaken as the answer but it is not because if the person is not falling anymore the horizontal line should be at the x-axis, meaning that there is no more velocity.
C) accelerating because of an unbalanced force of gravity.
False - The line would otherwise be going up or down.
The shape of the graph of the magnitude of the acceleration versus time for a falling skydiver initially increases and then decreases towards zero as the skydiver reaches terminal velocity. The graph of the magnitude of the velocity versus time initially increases and then reaches a plateau at terminal velocity. The graph of the magnitude of the displacement versus time initially increases and then levels off as the skydiver experiences constant displacement.
Explanation:In the case of a skydiver, the shape of the graph of the magnitude of the acceleration versus time will initially be positive and then decrease towards zero as the skydiver reaches terminal velocity. This is because the skydiver is initially accelerating due to the unbalanced force of gravity, but as they approach terminal velocity, the force of air resistance opposes the force of gravity and causes the acceleration to decrease.
Similarly, the shape of the graph of the magnitude of the velocity versus time for a falling skydiver will initially be positive and then reach a plateau at terminal velocity.
Lastly, the shape of the graph of the magnitude of the displacement versus time for a falling skydiver will initially be positive and then level off as the skydiver reaches terminal velocity and experiences constant displacement.
Mr.G I running down the street trying to catch the bus. He is one city block away (200m) and this bus is leaving in 10s.
a) How fast does Mr.G need to run to catch the bus on time? (Hint: what do you know about the problem)
b) If the fastest human can run 12 m/s, will Mr.G be able to catch the bus? Explain your answer
Answer:
a) 20 m/s
b) No
Explanation:
a)
Mr. G needs to run x= 200 m in t = 10 seconds to catch the bus.
Knowing the speed is computed as
[tex]\displaystyle v=\frac{x}{t}[/tex]
We have
[tex]\displaystyle v=\frac{200m}{10s}=20m/s[/tex]
b)
The fastest human can run 12 m/s, so Mr. G won't be able to catch the bus because he needs to run faster than that
Final answer:
Mr.G needs to run at 20 meters per second to catch the bus, but since the fastest human can run only at 12 meters per second, it is impossible for Mr.G to catch the bus on time.
Explanation:
To solve for how fast Mr.G needs to run to catch the bus on time, we need to find his required speed. Speed is calculated by dividing the distance by the time. Since Mr.G is 200 meters away from the bus and he has 10 seconds to reach it, his required speed is 20 meters per second (200m / 10s = 20m/s).
Regarding whether Mr.G can catch the bus, considering the fastest human can run at a speed of 12 meters per second, it is unfortunately impossible for Mr.G to catch the bus. The required speed to catch the bus is 20m/s, which exceeds the maximum human running speed.
A uniforn half metre rule is pivated at its 30cm mark. A mass of 50g hung at the 45cm mark keeps the rule horizontal. determine the mass of the half metre rule
150 g
Explanation:From the question;
Half meter rule (50 cm) is pivoted at 30 cm Mass of 50 g Pivoted at 45 cmIt means the mass is 15 cm from the pivot
Mass of the meter rule is always at the center of the rule ( 25 cm mark)Therefore, the mass of the half meter rule is experienced 5 cm from the pivot.But, According to law of moments, clockwise moments is equal to anticlockwise moments when a system is at a state of balance.Therefore;
Assuming the mass of half meter rule is m
Then;
m × 5 cm = 50 g × 15 cm
m = 150 g
Therefore;
Mass of the half meter rule is 150 g
The mass of the half meter ruler is 150g
how do i work out these?
Answer:
2. 0.27 N/kg
3a. 210 N
3b. 23.3 N
Explanation:
The acceleration due to gravity is:
g = GM / r²
where G is the gravitational constant, M is the mass of the planet, and r is the distance from the planet's center.
2. At the surface of the Earth (r = R), the acceleration due to gravity is 9.8 N/kg.
9.8 = GM / R²
At r = 6R, the acceleration due to gravity is:
g = GM / (6R)²
g = (GM / R²) / 36
g = 9.8 / 36
g = 0.27 N/kg
3a. Weight is mass times acceleration due to gravity:
W = mg
W = (20 kg) (10.5 N/kg)
W = 210 N
3b. Find the new value of g:
g = GM / (3R)²
g = (GM / R²) / 9
g = 10.5 / 9
g = 1.17 N/kg
Now find the weight:
W = mg
W = (20 kg) (1.17 N/kg)
W = 23.3 N
Two plane mirrors are facing each other. They are parallel, 5.00 cm apart, and 30.0 cm in length, as the drawing indicates. A laser beam is directed at the top mirror from the left edge of the bottom mirror. What is the smallest angle of incidence with respect to the top mirror, such that the laser beam hits each mirror only twice.
Answer:
The minimum angle of incidence is, ∅ = 56° 18' 35'' to the normal
Explanation:
Given data,
The distance between the two plane mirror, d = 5 cm
The length of the plane mirror, L = 30 cm
According to the laws of reflection, the angle of incidence is equal to the angle of reflection.
If the laser beam touches each mirror only twice, then the base of the triangle formed is not less than L/2.
Let ∅ be the angle of incidence to the normal. The normal divides the triangle into two equal halves where base becomes L/4.
Therefore,
tan ∅ = opp / adj
= (L/4) / d
= (30/4) / 5
tan ∅ = 1.5
∅ = tan ⁻¹ (1.5)
= 56° 18' 35''
Hence, the minimum angle of incidence is, ∅ = 56° 18' 35'' to the normal.
What height (displacement) will a ball reach if thrown upward with an initial velocity of 15 m/s
Answer:
11.48 m
Explanation:
initial velocity (u) = 15 m/s
acceleration due to gravity (g) = 9.8 m/s
final velocity (v) = 0 ( the ball's speed reduces gradually when thrown until
becomes 0 at maximum height)
find the height reached.
height (s) = ut + 0.5 at^{2}we cannot apply this formula directly because we do no know the time
(t), so we first need to find the time
v = u + at0 = 15 + (-9.8 x t) (the negative sign is because the ball is decelerating
upwards)
15 = 9.8t
t = 1.53 s
now that we have the time we can put it into the initial equationheight (s) = ut + 0.5 at^{2}height (s) = (15 x 1.53) + (0.5 x (-9.8) x 1.53^{2})
height = 22.95 - 11.47 = 11.48 m
what is resistance? Difference between resistance and resistivity.
Answer:
Resistance is the opposition that a substance offers to the flow of electric current
Explanation:
resistance is the opposition and Resistivity is a measure of the resistance of a given size of a specific material to electrical conduction.
Final answer:
Resistance is the opposition to electric current flow in materials, measured in ohms, while resistivity is a fundamental property of the material itself, indicating how much it resists electric current flow.
Explanation:
Understanding Resistance and Resistivity in Physics
Resistance is a measure of the difficulty in passing an electric current through a wire or component. It has units of ohms and is calculated by the formula V = IR, where V is voltage, I is current, and R is resistance. Resistivity, represented by the symbol p, is a material property that quantifies how strongly a material opposes the flow of electric current. The resistance R of a cylindrical object like a wire can be calculated using the formula R = pL/A, where L is the length and A is the cross-sectional area.
The key difference between resistance and resistivity is that resistivity is an intrinsic property of a material, which means it does not change regardless of the shape or size of the material. In contrast, resistance is an extrinsic property that depends on both the material's resistivity and the physical dimensions of the object. Materials can generally be categorized into conductors, semiconductors, and insulators, based on their resistivity values.