Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
Answer:
If the football is kicked at a 35.0º angle, it will travel 18.5 m before landing. This is farther than if it were kicked at a 25° angle.
Explanation:
what it says on edge
A neutral copper ball is suspended by a string. a positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. why is this? 1. the ball becomes positively charged by induction. 2. the string is not a perfect conductor. 3. there is a rearrangement of the electrons in the ball. 4. the ball becomes negatively charged by induction. 5. the number of electrons i
The copper ball is attracted to the rod because the electrons in the ball rearrange themselves, making one side of the ball negative and the other positive. This process is known as electrostatic induction. Thus, option 3 is correct.
A neutral copper ball is observed to be attracted to a positively charged insulating rod due to electrostatic induction. Here's a step-by-step explanation:
Rearrangement of Electrons: When the positively charged rod is brought close to the neutral copper ball, the electrons in the copper ball are attracted towards the rod because opposite charges attract each other.Induced Polarization: This movement causes the side of the ball closer to the rod to become slightly negative due to the accumulation of electrons, while the side farther from the rod becomes slightly positive due to the lack of electrons.Attraction: The negatively charged side of the copper ball is attracted to the positively charged rod, causing the ball to move towards the rod.Therefore, the correct reason for the observed attraction is the rearrangement of the electrons in the ball, making option 3 the correct answer.
Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).
The energy produced per gram of reactant for the fusion of H-1 with H-3 to form He-4, can be calculated using the difference of total initial and final masses, which is then used in Einstein's mass-energy equivalence principle (E=mc²). The number of such reactions in 1 gram of reactant is used to convert the energy per reaction to energy per gram of reactant.
Explanation:To calculate the energy produced per gram of reactant in fusion reaction, first let's understand what's happening in the fusion reaction of H-3 with H-1. A helium nucleus is formed with a mass that is 0.7% less than that of four hydrogen nuclei. This mass loss is converted into energy.
The masses of the reactants are 3.016049 u for H-3 and 1.007825 u for H-1, giving us a total initial mass of 4.023874 u. The mass of the helium atom produced, He-4, is 4.002603 u. The mass loss during the reaction equals initial mass minus final mass, which is 0.021271 u.]
Applying Einstein's mass-energy equivalence principle E=mc², where E is energy, m is the lost mass and c is the speed of light, the energy produced in the reaction, can be calculated. To convert amu to kilograms, multiply by 1.66054 x 10⁻²⁷. So, the mass lost is 3.53 x 10⁻²⁹ kg.
As speed of light c = 3 x 10^8 m/s, using the equation we get E = 3.53 x 10⁻²⁹ kg x (3 x 10⁸m/s)² = 3.18 x 10⁻¹²Joules.
Finally, to get the energy per gram, we calculate the number of such reactions in 1 gram of reactants. That would be (1 g)/(4.023874 g/mol) x Avogadro's number (6.02 x 10^23). Multiply this number with the energy produced per reaction to get the energy produced by 1 gram of reactant.
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What is the freezing point of radiator fluid that is 50% antifreeze by mass? k f for water is 1.86 ∘ c/m?
Answer:
-30.02 ºC
Explanation:
Assuming the antifreeze to be ethylene glycol (C₂H₆O₂) which is popular antifreeze.
Molar mass of ethylene glycol (C₂H₆O₂) = 62g/mol
Step 1: calculate the freezing point depression of the solution
ΔT = -Kf*M
where,
ΔT= depression in the freezing point.
M = the molarity of the solution (mol solute / Kg solvent)
Kf = molar freezing point constant of water = 1.86°C/m
To determine depression in the freezing point (ΔT), first we need to calculate;
molarity of solute (ethylene glycol) in mol mass of solvent (water) in kgmolarity of the solution (water +ethylene glycol)Step 2: calculate the molarity of the solute (ethylene glycol)
Molar mass ethylene glycol = 62 g/mol
molarity of ethylene glycol in mol = 50 g / 62g/mol = 0.807 mol
Step 3: calculate mass of solvent in kg
There is 1kg of ethylene glycol which is present in 1kg of water
mass of solvent (water) in kg= 50 g/ 1000 g/ Kg = 0.050 Kg
Step 4: calculate the molarity of the solution (M)
M = 0.807 mol / 0.050 Kg = 16.14 m
Step 5: calculate the freezing point depression of the solution (ΔT)
ΔT = - Kf*M = -1.86 ºC/m x 16.14 m
= -30.02 ºC
Please help 10 points
An automotive research facility is testing a new design on bumpers to determine the force at which it will break. The formula for Force is F = 1 2 m v 2 Where m is the mass (weight) and v is the velocity (speed)What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?
Same
Twice as much
Four times as much
Five times as much
Three 1.2 ohm lamps are connected in series and connected to a 3 volt battery. Calculate the total current in the circuit
How many new elements (fission fragments, or daughter nuclei) are typically presented as a result of fission?
1
3
2
5
True or false: the coefficient of thermal expansion governs the way a substance expands or contracts when it is heated or cooled
Name each type of symbiosis and explain how the two species are affected
For an isolated system, the law of conservation of momentum is valid: A. for inelastic collisions. B. for elastic collisions. C. only when there are no collisions. D. for all types of collisions.
The law of conservation of momentum is valid in isolated systems for all types of collisions, both elastic and inelastic.
The law of conservation of momentum is valid for an isolated system, meaning that no net external force is acting on the system. This principle applies to both types of collisions: elastic collisions and inelastic collisions. In elastic collisions, not only is momentum conserved, but kinetic energy is also conserved. In inelastic collisions, however, while kinetic energy is not conserved, the conservation of momentum still holds true. Therefore, for an isolated system, the law of conservation of momentum is valid for all types of collisions, regardless of whether they are elastic or inelastic.
1. Which of the following statements about mechanical waves is true?
a. mechanical waves require a medium to travel through
b. mechanical waves do not have amplitude and wavelength
c. mechanical waves do not have frequency
d. mechanical waves can travel through blank space
2. Which waves have the shortest wavelength and highest energy on electromagnetic spectrum?
a. microwaves
b. x-rays
c. infrared
c. gamma rays
3. What is true about infrared and X-Rays?
a. X-Rays have greater longer wavelength than infrared
b. Infrared have shorter wavelength than x-rays
c. x-rays have lower energy than infrared
d. Infrared have lower frequency than x-rays
4. In a longitudinal wave (compression wave_ the particles of a matter move ______
a. perpendicular (at right angles)
b. in a circular direction
c. backwards
d. parallel
5. In regard to spend of sound, sound travels slowest in ____
a. solids
b.liquids
c. gases
Mechanical waves require a medium to travel, gamma rays have the highest energy and shortest wavelength on the electromagnetic spectrum, x-rays have higher frequency than infrared, particles in a longitudinal wave move in parallel, and sound travels slowest in gases.
Explanation:1. The correct statement about mechanical waves is 'a. mechanical waves require a medium to travel through'. Unlike electromagnetic waves, mechanical waves, such as sound or seismic waves, need a medium like air, water, or solids to propagate or move.
2. The waves with the shortest wavelength and highest energy on the electromagnetic spectrum are 'c. gamma rays'.
3. The true statement about infrared and X-Rays is 'd. Infrared has lower frequency than x-rays'. X-rays have a higher frequency and shorter wavelength compared to infrared waves, which directly impacts their energy levels, with X-rays having higher energy.
4. In a longitudinal wave (compression wave), the particles of matter move 'd. parallel' to the direction of the wave's propagation. This is different from transverse waves where particles move perpendicular to the wave direction.
5. Sound travels slowest in 'c. gases'. Sound waves travel the fastest through solids, slower through liquids, and slowest through gases.
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PLEASE PLEASE HELP!?!?!!?
What is gravity? Gravity is the force (2 points) Select one: a. of attraction between two objects; it is not related to the object's mass. b. of attraction between two objects; it is related to the object's mass. c. that acts on objects when they are pushed d. that repels objects that have like charges
Many __________ cause poor pupil function more quickly than alcohol does.
A. Pain relievers
B. Antihistamines
C. Tranquilizers
D. Benzodiazepines
Answer:
B. Antihistamines
Explanation:
Whenever you have an allergy, your body creates a chemical called histamines. For a short term treatment against there allergies, you can take antihistamines. However, among the side effects of this treatment is poor pupil function.
So the correct answer is:
B. Antihistamines
A 0.50-kg block attached to an ideal spring with a spring constant of 80 n/m oscillates on a horizontal frictionless surface. the total mechanical energy is 0.12 j. the greatest extension of the spring from its equilibrium length is:
The greatest extension of the spring from its equilibrium length is calculated through the formula for total energy in harmonic motion, given as 0.5 * k * x^2. When rearranged for displacement(x), and values substituted, the extension is found to be 0.155 meters or 15.5 cm.
Explanation:In this problem, we are dealing with a block attached to an ideal spring and on a frictionless surface. The total mechanical energy, E, is given as 0.12 joules. We can use this information to find the peak displacement or the greatest extension, x, of the spring (amplitude) from its equilibrium length, using the formula E = 0.5*k*x^2.
The total energy of the system is the potential energy at the position of the greatest extension or amplitude, which means the block is momentarily at rest and has zero kinetic energy. Therefore, E = 0.5 * k * x^2, where E is the total energy, k is the spring constant, and x is the displacement.
Here, rearranging the formula to solve for the extension (x) we get x = sqrt((2*E)/k).
Substitute E = 0.12 joules and k = 80 N/m, into the equation. Therefore the greatest extension of the spring from its equilibrium length is x = sqrt((2*0.12 J)/80 N/m) = 0.155 meters or 15.5 cm.
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The greatest extension of the spring from its equilibrium length, which correlates to the amplitude A, is calculated from the given mechanical energy and spring constant. This can be determined by solving the equation for total mechanical energy, ETotal = (1/2)kA² for A. The calculation gives a maximum extension of approximately 15.5 cm.
Explanation:The total mechanical energy of a block and spring system is equal to the potential energy stored in the spring at the maximum extension/compression because at these points all of the energy is potential and none is kinetic. The total mechanical energy is given by ETotal = (1/2)kA², where k is the spring constant and A is the amplitude, which is the maximum extension or compression of the spring from its equilibrium length.
In this circumstance, the total mechanical energy is 0.12 Joules, and the spring constant 'k' is 80 N/m. So we can solve the above equation for A, the maximum extension:
A = sqrt( (2 * ETotal) / k ) = sqrt( (2 * 0.12 J) / 80 N/m ) = 0.15494 meters,
which is about 15.5 cm (since 1 m = 100 cm).
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A howler monkey is the loudest land animal and under some circumstances, can be heard up to a distance of 5.0 km. Assume the acoustic output of a howler to be uniform in all directions and that the threshold of hearing is 1.0*10^-12 W/m^2. The acoustic power emitted by the howler is closest to
a) 3.2 mW b) 0.11 mW c) 11 mW d) 1.1 mW e) .31 mW
A feather of mass 0.001 kg falls from a height of 2 m under realistic conditions it experiences air resistance based on what you know about friction what can you say about the kinetic energy of the feather as it reaches the ground
Answer:
KE < 0.0196 J
In the circuit diagram, what does the line segment with two circles at the ends represent?
an electrical conductor
a source of electrical energy
an electrical resistor
a closed switch
That is a symbol for a closed switch meaning that current flows through the wire. If the line between the two circles wasn't connected to one of the circles, then it would be an open circuit in which current doesn't flow through the wire.
Answer: closed switch
Explanation:
Closed switch is when current is allowed to flow freely without hindrance.
What is the resistance of a resistor if the potential differences across the resistor is 4v when a cirrent of 10 a flow through the resistor?
Which of these is a cultural service—a non material benefit people get from the environment
Answer: providing national parks
Explanation:
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a wire that is 10.9 m long, has a mass of 55.8 g, and is stretched under a tension of 253 n?
What is the pressure of the gas in this mercury manometer if h = 63 mm and atmospheric pressure is 773 mmhg?
Ryan is experimenting with core materials for an electromagnet. he slides different for materials to a quail of current caring wire. sort the court materials based on whether they will or will not increase the strength of Ryan's electromagnet.
which form of energy is involved in weighting fruit on a spring scale ?
Which of these is most likely to produce wastewater containing benzene and other hydrocarbons
An Oil Refinery (APEX)
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.
freezing
vaporizing
condensing
melting
Answer:
Melting
Explanation:
If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as:
freezing. NO. Freezing is the process in which a liquid turns into a solid.vaporizing. NO. Vaporizing is the process in which a liquid turns into a gas.condensing. NO. Condensing is the process in which a gas turns into a liquid.melting. YES. Melting is the process in which a solid turns into a liquid.Place the notebook on a table, and push it a few inches with your finger. When it moves, it has kinetic energy. Which kind of force opposed the motion of the notebook?
Answer:
The force of friction opposed the motion of the notebook.
Explanation:
Plato answer
The fundamental frequency of a pipe that is open at both ends is 564 hz . part a how long is this pipe?
The length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
What is the frequency?Frequency is defined as the no of waves that are passing from the point in respect to a given time. Frequency can be measured in Hertz. Humans, whose capacity to hear is normal, can hear between the frequency of 20 Hertz to 20000 Hertz.
Given:
The frequency, f = 564 Hz,
Calculate the length by the formula given below,
[tex]l= k / 2[/tex]
2l = k
Calculate the length of the pipe by the formula given below,
[tex]f = v k[/tex]
f = v (2l) [Substitute the value of k]
l = f / 2v
l = 564 / (2 × 344)
l= 564 / 688
l = 0.82 m or 82 cm
Therefore, the length of the pipe, if The fundamental frequency of a pipe that is open at both ends is 564 Hz, is 82 cm.
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Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the magnitude of the magnetic field midway between the two wires?
The magnitude of the magnetic field midway between two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m is 4.5 x 10⁻⁵ T.
Explanation:To find the magnitude of the magnetic field midway between the two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m, we can use the formula for the magnetic field due to a long straight wire. The magnitude of the magnetic field at a distance r from the wire is given by: B = (μ₀ * I) / (2π * r). Since we are looking for the magnetic field midway between the wires, the distance from each wire to the point is half of the total separation, which is 0.10 m. Plugging in the values, we get: B = (4π * 10⁻⁷ T·m/A * (20 A + 5.0 A)) / (2π * 0.10 m) = 4.5 x 10⁻⁵ T.
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The magnitude of the magnetic field midway between two parallel wires carrying currents of 20 A and 5 A in opposite directions and separated by 0.20 m is 3 * 10^-6 T.
Explanation:To find the magnitude of the magnetic field midway between the two wires, we can use the formula for the magnetic field produced by a long straight wire:
B = (μ0 * I) / (2πr)
where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In this case, we have two wires with currents of 20 A and 5 A, and they are separated by 0.20 m. Since we are interested in the magnetic field midway between the wires, the distance r will be half of the separation between the wires, which is 0.20 m / 2 = 0.10 m.
Plugging in the values, we get:
B = (4π * 10-7 T·m/A * (20 A - 5 A)) / (2π * 0.10 m) = (4 * 10-7 T·m/A * 15 A) / (0.20 m) = 3 * 10-6 T
So, the magnitude of the magnetic field midway between the two wires is 3 * 10-6 T.
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Recall that the differential equation for the instantaneous charge q(t) on the capacitor in an lrc-series circuit is l d 2q dt 2 + r dq dt + 1 c q = e(t). see this excerpt about lrc-series circuits. use the laplace transform to find q(t) when l = 1 h, r = 20 ω, c = 0.005 f, e(t) = 160 v, t > 0, q(0) = 0, and i(0) = 0. q(t) =
The Laplace transform can be used to solve the differential equation for the charge on the capacitor in an LRC-series circuit.
Explanation:The Laplace transform can be used to solve the differential equation for the charge on the capacitor in an LRC-series circuit.
The Laplace transform transforms the differential equation into an algebraic equation, which can be solved to find q(t). First, we substitute the given values of L, R, C, and e(t) into the differential equation.
Then, we take the Laplace transform of both sides of the equation. Finally, we solve for Q(s) and take the inverse Laplace transform to find q(t).
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