A car is moving with a speed of 22 m/s. The driver then brakes, and the car comes to a halt after 6.5 s. What is the distance covered by the car after the driver brakes, until it comes to a stop?

Answers

Answer 1

The distance covered by the car until it comes to a stop is 71.6 m.

What is speed?

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given parameters:

Initial speed of the car; v = 22 m/s.

The car stops after time t = 6.5 s.

The distance covered by the car after the driver brakes, until it comes to a stop; s = ?

So, deceleration of the car = ( initial speed - final speed)/time

= ( 22 m/s - 0 m/s )/6.5 s

= 3.38 m/s².

So, by using v² = u² - 2as in this decelerated motion; we get:

⇒ 0² = 22² - 2×3.38×s

⇒ s = 22²/(2×3.38) = 71.6 m.

Hence, the distance covered by the car after the driver brakes, until it comes to a stop is 71.6 m.

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Related Questions

Determine the Kinetic energy of a 1000 kg roller coaster car that is moving with speed of 20.0 m/s

Answers

Final answer:

The kinetic energy of a 1000 kg roller coaster car moving at a speed of 20.0 m/s is calculated using the formula KE = ½ mv², resulting in KE = 200,000 J or 2.00 × 10⁵ J.

Explanation:

The question requires us to calculate the kinetic energy of a 1000 kg roller coaster car that is moving with a speed of 20.0 m/s. The kinetic energy (KE) of an object can be found using the formula KE = ½ mv², where m is the mass of the object and v is its velocity. Inserting the given values into the formula, we get:

KE = ½ (1000 kg) (20.0 m/s)

KE = ½ (1000 kg) (400 m²/s²)

KE = (500 kg) (400 m²/s²)

KE = 200,000 J or 2.00 × 10⁵ J

The roller coaster car possesses 200,000 joules of kinetic energy at the given speed.

As the wave interacts with a wall, which kind of wave interaction is shown?

absorption

diffraction

refraction

reflection

Answers

reflection thats the answer bois

Compare rhyolite to basalt (answer in one word only):

a. which has a lower density?

b. which has a lighter color?

c. which has a more mafic composition?

d. which has a greater percentage of biotite in it?

e. which contains quartz? 13. name a felsic, intrusive rock. 14. name a light-colored, plutonic igneous rock.

Answers

Rhyolite is a fine-grained igneous rock which is rich in silica while basalt is a common extrusive igneous rock formed by the rapid cooling of basaltic lava exposed at or very near the surface of Earth.
The density of Basalt is higher than that of Rhyolite. Rhyolite has a density that ranges between 2.4-2.6 g/cm^3, while that of Basalt ranges from 2.9-3.1 g/cm^3.

b) Rhyolite is a Grey, white, light black rock, while Basalt is Black, Brown, Light to Dark Grey. Rhyolite appears to be banded while the apperance of Basalt is Dull and soft.

c) Basalt is more mafic; most mafic minerals are dark in color, and common rock-forming mafic minerals include olivine, Pyroxene, amphibole, and biotite. Common mafic rocks include basalt, diabase and gabbro. Mafic rocks often also contain calcium-rich varieties of plagioclase feldspar.

d) Rhyolite has a higher percentage of biotite. Rholite contains a higher percentange of sodium and potassium oxides which can reach up to 5%. Quartz, feldspar and biotite are the most common minerals found in rhyolite. In some cases , thick rhyolitic lavas will cool as glassy obsidian flows.

e) Rhyolite contains quartz. The chemical composition of rhyolite is similar to that of granite. The phenocrysts or rhyolite may include quartz, alkali feldspar, oligoclase feldspar, biotite, amphibole, or pyroxene.

13. I think it is plutonic rocks. Intrusive rocks that were formed deep in the earth's crust are called plutonic rocks and are generally coarse gained (minerals grains greater than 1 millimeter in diameter), large, and often associated with mountain building. Mafic felsic, and intermediate intrusive rocks.

14. Anorthosite. It is the light-colored plutonic rock composed mostly of feldspar, labradorite, with very little pyroxene. The felsic plutonic rocks usually have quartz, large proportions of potassium feldspar, and lesser amounts of plagioclase and mafic minerals. On the other hand, intermediate and mafic rocks have increasingly larger proportions of dark iron-rich minerals.

Answer A:

Rhyolite has a lower density

Average density of Rhyolite is 2.5 g/cm³ whereas the average density of basalt is 3 g/cm³ So we can say that Rhyolite is less denser.

Answer B:

Rhoylite is more lighter

Rhyolite is either pink or grey whereas basalt is usually grey or black so we can say that Rhyolite has lighter color

Answer C:

Basalt is more melfic

Rhyolite is usually considered as felsic, while basalt is mafic. Generally felsic rocks make the bulk of the continental plates, while mafic basalt forms the seafloor.

Answer D:

Basalt has more amount of biotite

Basalt has 5% biotite in it whereas Thyloite has very rare amount of biotite in it so we can say that greater amount of biotite is present in Basalt

Answer E:

Quartz in Rhyolite may be present in amounts of 25% to 30%. whereas basalt has 20% - 60% quartz amount in it.

Answer 13:

Granodiorite is an example of felsic intrusive rock.

Answer 14:

Name of a very hard plutonic, igneous rock is Granite.

An antique carousel that’s powered by a large electric motor undergoes constant angular acceleration from rest to full rotational speed in 5.00 seconds. When the ride ends, a brake causes it to decelerate steadily from full rotational speed to rest in 11.0 seconds. Compare the torque that starts the carousel to the torque that stops it. τstart/τstop = the tolerance is +/-2%

Answers

1) For a rotating object, we can write the analogous of Newton's second law as
[tex]\tau = I \alpha[/tex]
where [tex]\tau[/tex] is the torque applied to the object, I is the moment of inertia and [tex]\alpha [/tex] is the angular acceleration.

2) We can write the ratio between the starting torque and the stopping torque as:
[tex] \frac{\tau _{start}}{\tau _{stop}} = \frac{I \alpha _{start}}{I \alpha _{stop}} = \frac{ \alpha _{start}}{\alpha _{stop}} [/tex]

3) Then, we can rewrite the two angular accelerations. The general formula is
[tex]\alpha = \frac{\omega _f - \omega _i}{t} [/tex]
where [tex]\omega _f [/tex] and [tex]\omega _i[/tex] are the final and initial angular velocities, while t is the time.

4) Let's start by calculating the starting acceleration. In this case, the initial velocity is zero, while the final velocity is the full rotational speed (let's call it [tex]\omega _{max}[/tex], and the time is t=5.0 s:
[tex]\alpha _{start} = \frac{\omega_{max}-0}{5 s}= \frac{\omega_{max}}{5 s}=[/tex]
When the carousel stops, instead, the initial velocity is [tex]\omega _{max}[/tex] while the final velocity is 0, and the time is t=11.0 s:
[tex]\alpha _{stop} = \frac{0-\omega _{max}}{11 s}= \frac{-\omega _{max}}{11 s} [/tex]
Therefore, if we replace the two angular accelerations that we found into the formula of the torque ration written at step 2), we find:
[tex] \frac{\tau _{start}}{\tau _{stop}} = - \frac{11}{5} [/tex]
where the negative sign simply means that the two torques have opposite direction. Therefore, the ratio between starting and stopping torque is 11:5.

The tangential speed at the outer rim of a Ferris wheel is 10 m/s. What is the tangential speed of a position halfway from the center to the outer rim?

Answers

Final answer:

In rotational motion, tangential speed is proportional to the radius. Thus, if you're halfway between the center and the rim of a Ferris wheel, your speed would be half that of the rim's speed. So, the tangential speed halfway to the center from the rim would be 5 m/s assuming the outer rim speed is 10 m/s.

Explanation:

The concept you're asking about is related to tangential speed and its relationship to the radius in rotational motion. In the case of a Ferris wheel, or any rotating body, the tangential speed is defined as the angular velocity times the radius. Therefore, if the radius is halved (a point halfway from the center to the outer rim), the tangential speed at the new point will also be halved assuming a constant angular velocity. Thus, in your example, if the tangential speed at the outer rim is 10 m/s, the speed halfway to the center will be 5 m/s.

This is because the properties of a rotating body dictate that the tangential speed increases linearly with the radius from the axis of rotation, in the case of a constant angular velocity. Hence, the farther away from the center of rotation, the faster the tangential speed, and vice versa.

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The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel with an outer rim speed of 10 m/s would be 5 m/s.

The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel is half of the tangential speed at the outer rim. In this case, the initial tangential speed at the outer rim is given as 10 m/s, so the tangential speed at halfway to the rim would be 5 m/s. This is because tangential speed is directly proportional to the radius in uniform circular motion, and if the radius is halved, so is the tangential speed.

A shot hitting the birdie high and deep to the backcourt is called what

Answers

I think it would be "Clear"

Final answer:

In badminton, a shot that sends the birdie high and deep to the backcourt is called a clear. It's a defensive move to create more playing space and opportunities.

Explanation:

A shot in badminton that is hit high and deep into the opponent’s backcourt is known as a clear. This type of shot is a defensive move, intended to give the player hitting the clear more time to return to a ready position and to push the opponent to the rear of their court, potentially creating opportunities for future aggressive plays. The clear can be performed as either a forehand or backhand stroke depending on the player's position and the shuttlecock's trajectory.

can someone help me with the physics problem?:

if you do 144 J of work to elevate a bucket of water, what is it’s final gravitational potential energy relative to its starting position?

Answers

The work you put into something is the energy it has afterward (neglecting friction and other so-called non-conservative forces). This is called the work-energy theorem. Think of objects in a gravitational field as "energy piggy banks". If you put X joules of energy into it, that energy will be there as potential energy, stored for later. So if you do 144J of work to elevate the bucket from an initial position, what ever it is initially, the final gravitational energy is 144J greater than before.

What is the electric force between a glass ball with 3.5 µc of charge and a rubber ball with -4.5 µc of charge when they are separated by 5 cm?

Answers

they attract each other with force
F=q1*q2/(4πεr^2), where
q1=2.4 µC, q2=4.2 µC,
r=4.9·10-2 m, ε=8.854·10^(-12) SI units.
♦ F=2.4·10-6 * 4.2·10-6 /(4*pi* 8.854·10^(-12) *0.049^2)=
=37.73 N;

To find the electric force between the charged glass and rubber balls, we use Coulomb's Law with Coulomb's constant, the charges in Coulombs, and the distance in meters to calculate the force.

The student has asked to find the electric force between a glass ball with a charge of 3.5 µC and a rubber ball with a charge of -4.5 µC when they are 5 cm apart. To calculate this, we can use Coulomb's Law, which states that the electric force (F) between two point charges is directly proportional to the product of the magnitudes of the charges (q1 and q2), and inversely proportional to the square of the distance (r) between them. The formula is represented as:

F = k * |q1 * q2| / r₂

Here, k is Coulomb's constant (8.988 x 10^9 N·m^2/C²), q1 and q2 are the charges in Coulombs, and r is the distance in meters. For the glass and rubber ball, q1 is 3.5 µC (or 3.5 x 10^-6 C) and q2 is -4.5 µC (or -4.5 x 10⁻⁶ C), and the distance r is 5 cm (or 0.05 m). Plugging in these values, we get:

F = (8.988 x 10⁹ N·m²/C₂) * |(3.5 x 10⁻⁶ C) * (-4.5 x 10⁻⁶ C)| / (0.05 m)²

After calculation, the result is the magnitude of the electric force exerted between the two charges.

An instrument that can detect the presence of an electric charge is a
a.
magnet.
b.
electroscope.
c.
generator.
d.
conductor.

Answers

The answer to this question is B

Answer:

b. electroscope.

Explanation:

-A magnet is an object that creates a magnetic field around it and has two poles.

-An electroscope is an instrument that helps to find out if there is a charge in an object.

-A generator is an object that produces electrical energy.

-A conductor is an object that allows to transmit energy.

According to this, the answer is that an instrument that can detect the presence of an electric charge is an electroscope.

if a cannon is fired from the front of a boat, the boat will drift backward. which on of Newton's laws best describes this motion?

Newton's second law of motion: force is equal to mass time acceleration

Newton's third law of motion: for every action, there is a equal and opposite reaction

Newton's first law of motion: an object in motion stays in motion unless acted on by another force

Answers

Newton's Third Law: For every action, there is an equal and opposite reaction.

The cannon jumps back which pushes the boat backwards.

Calculate the water pressure in the pipes at the bottom of a high-rise building that is fed by reservoir 60 m above the roof top. Please help and explain

Answers

In order to solve the problem, we can use Stevin's law. The pressure at the bottom of a column of fluid with density [tex]\rho[/tex] and height h is:
[tex]p=\rho g h[/tex]
In our problem, the fluid is water, so its density is [tex]\rho = 1000 Kg/m^3[/tex]. The height of the column of water is h=60 m, and [tex]g=9.81 m/s^2[/tex], therefore
[tex]p=(1000 Kg/m^3)(9.81 m/s^2)(60 m)=5.89 \cdot 10^5 Pa[/tex]

19. Water that flows downhill along Earth's surface is called A. beach hydraulics. B. cycles. C. runoff. D. rain.

Answers

the answer is most likely C

Water that flows downhill along Earth's surface is called "Runoff". When water is left to 'run' 'off' the side of roads and other surfaces. So the answer is C.

A certain wave has a wavelength of 35 meters and a frequency of 4.0 Hz. What is the speed of the wave? 8.8 m/s 31 m/s 39 m/s 140 m/s

Answers

35
4.0 Hz
*______
1.40 Hz
+ 8.8m/s
_______
=10.2 Hz m/s(31)m/s(39)m/s(140)m/s

Answer:

Speed, v = 140 m/s

Explanation:

It is given that,

Wavelength, λ = 35 meters

Frequency of the wave, υ = 4 Hz

The speed of the wave is the product of the frequency and the wavelength of the wave.

Mathematically, it can be written as :

v = υ λ

v = 35 m × 4 Hz

v = 140 m/s

So, the speed of the wave is 140 m/s

Hence, this is the required solution.

What is the net force in the x-direction? 30 N 34 N 55 N 65 N

Answers

Answer

34 N

Explanation.

I think the question is not complete.. It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"

We should find the horizontal component of the force 65 N.

Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.

cosФ = adjacent/hypotenuse

let x be the net required (the component of 65N)

cos 58 = x/65

x = 65 × cos 58

= 34.44 N

Answer:

The answer is 34 N

Explanation:

Hope this helped!!!

A dry cleaner throws a 20 kg bag of laundry onto a stationary 8.3 kg cart. the cart and laundry bag begin moving at 2.6 m/s to the right. find the velocity of the laundry bag before the collision. answer in units of m/s. answer

Answers

The total momentum before and after the collision must be conserved.

- Let's start from the end: at this point, both cart and laundry bag are moving together, with a total mass of (m1+m2) and velocity 2.6 m/s. Therefore, the total momentum is
[tex]p_f = (m_1+m_2) v_f =(20 kg+8.3 kg)(2.6 m/s)=73.6 kg \cdot m/s[/tex]

- The momentum must be conserved, so the initial momentum must be equal to this value:
[tex]p_i = p_f = 73.6 kg \cdot m/s[/tex]

- At the beginning, the cart is stationary, so its momentum is zero. There is only one momentum, the one of the bag, which has a mass of 20 kg and unknwon velocity vi:
[tex]p_i = m_1 v_i[/tex]

- So, using the conservation of momentum we find
[tex]m_1 v_i = 73.6 kg \cdot m/s[/tex]
and from this, the initial velocity of the laundry bag:
[tex]v_i = \frac{p_f}{m_1}= \frac{73.6 kg \cdot m/s}{20 kg}=3.7 m/s [/tex]

Final answer:

Using the conservation of momentum, the velocity of the 20 kg laundry bag before the collision is calculated to be approximately 3.689 m/s to the right.

Explanation:

To find the velocity of the laundry bag before the collision, we can use the conservation of momentum, which states that the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system. Since the cart is initially stationary, its initial momentum is 0. After the bag is thrown onto the cart, both move together with a certain velocity, so the final momentum is the combined mass times the final velocity. We can set up the equation as follows:

Momentum before collision (p₁) = Momentum after collision (p₂)

Since the cart is stationary before the collision, this simplifies to:

Velocity of the bag before collision (v) × Mass of the bag [tex](m_{bag)[/tex] = (Mass of the bag [tex](m_{bag)[/tex] + Mass of the cart [tex](m_{cart)[/tex]) × Final velocity [tex](v_f)[/tex]

Inserting the given values, we get:

v × 20 kg = (20 kg + 8.3 kg) × 2.6 m/s

Now we solve for the velocity (v):

v = (28.3 kg × 2.6 m/s) / 20 kg

v = 3.689 m/s

Therefore, the velocity of the laundry bag before the collision was approximately 3.689 m/s to the right.

How many days are between the first quarter and full moon phases

Answers

there are approximately 3.75 days between each lunar cycle so between the first quarter and full moon there are 2 cycles so 2 multiplied by 3.75 is 7.5

Using a simple machine, a student is able to lift a 500N weight by applying only 100N.

What is the mechanical advantage of the simple machine?

A) 0.2

B) 1

C) 5

D) 50000

Answers

Hey there!

[tex] a \ student \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\ \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer![/tex]

Hope this helps you!

Apply Newton's three laws of motion to everyday situations.

Answers

Hey there!

We'll start with the first law, the law of inertia, which states:

"an object in motion will stay in motion moving at the same speed in the same direction unless acted on by an outside force".

Let's imagine you're playing soccer with your friends. You kick the ball at them really hard, and they're the goalie. It goes in the same direction in a straight line, and then they catch it - the unbalanced force. There's a change in motion there, and that change in motion depends on the inertia of an object- it's tendency to resist change in motion. Inertia even applies to planets. Wonder why out Earth's orbit is an ellipse? By natural standards of physics, the Earth goes straight when it's not pulled into orbit when here it is. It still has that tendency to go straight, but the Sun pulls it towards itself, creating a motion in which the Earth is trying to go straight, but the Sun's more powerful.

The second law is pretty much summarized by the famous equation f = ma. The law, summed up, states,

"The net force of an object is equal to the mass of the object times its acceleration."

If you tried to give a push to a small box with efficient wheels, it'd go pretty far. This is because it has not a lot of mass, and the force required isn't a lot. However, if we had a large box on the ground, the force required to move it would be larger, as it's more massive and doesn't have any acceleration. Imagine a shopping cart filled to the ceiling with cereal. It would require a lot of force, wouldn't it? Be sure to think about that.

Last one. Newton's third law is perhaps the most famous. It states,

"For every action, there is an equal and opposite reaction".

This is probably the hardest one to understand. Let's try an example. Have you ever accidentally not tightened your balloon, and it started to fly up? That's an application of Newton's third law. The air comes out from the bottom, and the balloon flies up - that's an opposite reaction; up and down. It's the same thing with a rocket. The same force to propel it up is exerted on the ground - an equal reaction.

Hope this helps! Be sure to let me know if you have any questions :)

The more particles that are hitting each other in a fluid, the less pressure is created. true of false

Answers

This statement is false: More hitting among particles creates more energy which means a higher temperature, which in turn means higher pressure. Thus, this is a false statement.

Hope this helps!

two or more velocities add by

Answers

Two or more velocities add by vector sum.
In fact, velocity is a vector, with its own intensity, direction and verse. Therefore, we cannot simply add two velocities by algebraic sum, but we need to decompose them on two axes (if we are in a 2D-plane) and calculate the resultant on each axis, and then calculate the total resultant of the two vectors, which will have its intensity, direction and verse.

Read the scenario and solve these two problems. When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed isJ. Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of? The train can climb a hill that ism high.

Answers

first answer 5400000
second answer 46

1. The kinetic energy of the train is 5400000 J

2. The tallest hill the train can climb is 45.92 m

1. Determination of kinetic energy of the train

Mass (m) = 12000 Kg

Velocity (v) = 30 m/s

Kinetic energy (KE) =?

The kinetic energy of the train can be obtained as follow:

KE = ½mv²

KE = ½ × 12000 × 30²

KE = 6000 × 900

KE = 5400000 J

2. Determination of the height of the hill the train can climb

Energy (E) = 5400000 J

Mass (m) = 12000 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

E = mgh

5400000 = 12000 × 9.8 × h

5400000 = 117600 × h

Divide both side by 117600

h = 5400000 / 117600

h = 45.92 m

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Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F

Answers

That's true. There's plenty of gravity in Earth orbit, and things have plenty of weight there.

Answer:

true

Explanation:

true

Challenge: a sound wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with a speed of 340 m/s. Approximately how many times larger is the wavelength in water than in air?

Answers

Final answer:

The wavelength in water is approximately 4.41 times larger than the wavelength in air.

Explanation:

In order to calculate the ratio of the wavelengths in water and in air, we need to use the formula:

ratio = speed of sound in water / speed of sound in air

Given that the speed of sound in water is 1500 m/s and the speed of sound in air is 340 m/s, we can substitute these values into the formula: ratio = 1500 m/s / 340 m/s = 4.41

Therefore, the wavelength in water is approximately 4.41 times larger than the wavelength in air.

The wavelength in water is approximately 4.4 times larger than in air.

To find the wavelength of a sound wave in a given medium, one can use the formula:

[tex]\[ \lambda = \frac{v}{f} \][/tex]

where [tex]$ \lambda $[/tex] is the wavelength, [tex]$ v $[/tex] is the speed of sound in the medium, and [tex]$ f $[/tex] is the frequency of the sound wave.

Given that the frequency [tex]$ f $[/tex] of the sound wave is 100.0 Hz, we can calculate the wavelength in water and in air using their respective speeds.

First, calculate the wavelength in water:

[tex]\[ \lambda_{\text{water}} = \frac{v_{\text{water}}}{f} = \frac{1,500 \text{ m/s}}{100.0 \text{ Hz}} = 15 \text{ m} \][/tex]

Next, calculate the wavelength in air:

[tex]\[ \lambda_{\text{air}} = \frac{v_{\text{air}}}{f} = \frac{340 \text{ m/s}}{100.0 \text{ Hz}} = 3.4 \text{ m} \][/tex]

To find out how many times larger the wavelength in water is compared to the wavelength in air, we divide the wavelength in water by the wavelength in air:

[tex]\[ \text{Ratio} = \frac{\lambda_{\text{water}}}{\lambda_{\text{air}}} = \frac{15 \text{ m}}{3.4 \text{ m}} \approx 4.4 \][/tex]

An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus?

A.9.4 N
B.14 N
C.27 N
D.66 N

Answers

the centripetal force would be mv^2/r
which is then equal to 2*5*5/0.75
that's 66 N

Answer:

I am pretty sure the answer is "66N"

Explanation:

I've seen a lot of results on the internet saying the same thing

If this is not the answer, I am truly sorry and you can message me so that I can delete the question.

Have a good day!

When the IMA is compared to AMA in the real world, _____.
(A)the value of the IMA is always larger than the AMA
(B)the value of the AMA is always larger than the IMA
(C)the value of the AMA is larger than the IMA when there is no resistance
(D)the value of the IMA is larger than the AMA when there is no resistance

Answers

AMA is actual mechanical advantage in where it would compare the force in as well as out in using actual measurements in the real life or with friction while in IMA which is the ideal mechanical advantage no friction then is needed. The answer then is a. the value of IMA is larger than AMA.

I believe the answer is A.) the value of the IMA is always larger than the AMA
(Not 100% on this, not my strongest topic, so I would double check)

Periodic Motion Problem, how to tackle this beast?

Answers

You can see the periodic motion as the projection over the diameter of a point moving with a circular motion.

The Amplitude will be the radius of the circumference and ω is the angular frequency (or speed) for both motions.

In the periodic motion, you will have maximum velocity at the center and it will be zero at the extremities, where the projection changes direction, while the acceleration will be maximum at the extremities and zero at the center.

The displacement will then be:
x(t) = A · cos(ωt)
And from this (using a little bit of calculus):
v(t) = A · ω · sin(ωt)
a(t) = A · ω² · cos(ωt)

(this question is just for fun)(at least try to answer it) If I was driving 272mph in a koenigsegg one:1 And I was traveling 50 miles across the country how long will it take me to arrive without no obstacles

Answers

The speed of the koenigsegg one is 272 mph , the distance that the car must travel is 50 miles

Speed = distance/time

Time = distance/speed = 50miles/272miles per hour = 0.1838 hours

Time = 0.1838 hours = 11.028 minutes = 661.68 seconds

USE THE AGERA RS, also it would run out of gas:) Im a car enthusiast

Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what could Lana do to get more out of her hhomework

Answers

I added a screenshot with the complete question

Answer:
D. Ask her instructor questions about it the next day

Explanation:
We are given that Lana doesn't understand everything she's supposed to learn from the homework.

Let's check the options:
1- start working on it eve earlier
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts

2- put it off until she's ready to work on it
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible

3- Only work on it directly before going to class.
this is the same as option 2. She might not even be able to finish it before the class

4- Ask her instructor questions about it the next day
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits

Hope this helps :)

Explanation:

Since Lana is unable to understand everything while doing her homework it means that she has doubts about some of the topics given in her homework.

Therefore, in that case she should take the help of her teacher or instructor the very next day because her doubts are new and she should consult about then as soon as possible.

Thus, by doing so she can clear her doubts on time.

Which of the following is an accurate description of relationship demonstrated in ohms law

Answers

There is no accurate description in the list of choices that you provided.

Answer:

The electric potential (volts) divided by the current (amperes) equals the resistance (ohms).

Explanation: That is the formula to find the resistance based on the Ohm's laws.

How can the creation of ice result in physical weathering? view available hint(s) how can the creation of ice result in physical weathering? ice dissolves the surrounding container. ice scrapes the sides of the container, making it bigger. ice contracts as it forms, allowing a container to collapse. water expands in volume when freezing, exerting pressure on a container. liquid water carries talus into a fracture, which wedges the container open?

Answers

Ice plays a very important role in mechanical weathering. The fourth option is the correct answer. WATER EXPANDS IN VOLUME WHEN FREEZING, EXERTING PRESSURE ON A CONTAINER.

The appropriate name for this type of weathering is frost action/frost shattering/freeze and thaw weathering. This type of weathering occurs in the mountainous regions of the temperate climate were water freezes at night and thaws in the day or summertime. When water freezes it expands by 10% and exerts pressure within the cracks in rocks. Over time this continuous freezing and thawing will cause rocks to break off into angular fragments.

Final answer:

The creation of ice can result in physical weathering by expanding and exerting pressure on its surroundings, causing rocks to break apart or structures to crack or collapse.

Explanation:

When water freezes, it expands in volume and exerts pressure on its surroundings. This expansion can cause physical weathering by breaking down rocks or damaging structures such as containers or pipes. For example, when water seeps into the cracks of a rock and freezes, the expanding ice can widen the cracks and eventually break apart the rock. Similarly, water that freezes in a container can exert enough pressure to cause it to crack or even collapse.

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