A car tire has a radius of 15 inches. Suppose the car is traveling at 60 miles per hour (1 mile = 5,280 feet). What is the approximate rate of spin, in revolutions per minute, of the tire? Round the answer to the nearest whole number.

Answer:

The length of the radius of this circle is 14 inches.

Step-by-step explanation:

Circumference of the circle = [tex]28\pi[/tex]

Let's take the length of the radius of the circle as [tex]a[/tex]

Circumference of a circle = [tex]2\pi r[/tex]

Where,

r is the radius of the circle.

Therefore,

[tex]2\pi a=28\pi[/tex]

[tex]2a=28[/tex]

[tex]a=14[/tex]

Therefore, the length of the radius of this circle is 14 inches.

The Last one is your answer

Answer:

The last one i did this before

Step-by-step explanation:

To determine the function which has the largest value at x=3,

We will calculate the value of each function by substituting the value of x=3 in each of the given function.

Let us consider the first function,

[tex] c(x)=3x^{2}+5x+22 [/tex]

[tex] c(3)=3\times 3^{2}+5 \times 3+22 [/tex]

[tex] c(3)=27+15+22 [/tex]

[tex] c(3)=64 [/tex]

Let us consider the second function,

[tex] j(x)=12x [/tex]

[tex] j(x)=12 \times 3 =36 [/tex]

Let us consider the third function,

[tex] a(x)=9x [/tex]

[tex] a(x)=9 \times 3=27 [/tex]

Therefore, the function c(x) has the largest value at x=3.

The answer is 3

To determine which function has the largest value when x = 3, we need to substitute x with 3 into each function and calculate their values.

c(x) = 3x2 + 5x + 22 => c(3) = 3(3)2 + 5(3) + 22 = 27 + 15 + 22 = 64

j(x) = 12x => j(3) = 12(3) = 36

a(x) = 9x => a(3) = 9(3) = 27

The function c(x) has the largest value of 64 when x = 3.

The variables as length are L and width is W and the system of equations is L = 2W - 3 and 42 = 2(L + W) and the length and width are 13 feet and 8 feet respectively.

A rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

As per the given total fencing = 42 feet

Let's say the length is L and the width is W.

As per the given,

L = 2W - 3

Perimeter = 2(length + width)

42 = 2(L + W)

21 = 2W - 3 + W

21 + 3 = 3W

W = 8 feet

And, L = 2(8) - 3 = 13 feet

Hence "The variables as lengths are L and width is W and the system of equations is L = 2W - 3 and 42 = 2(L + W) and the length and width are 13 feet and 8 feet respectively".

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Answer:

Option B is correct, i.e. -2 x^8 y^18.

Step-by-step explanation:

To find the equivalent expression to (10)(x^6)(y^12) / (-5)(x^-2)(y^-6)

Step 1: simplify numerical terms

(10) / (-5) = -2

Step 2: simplify exponents of x-terms

(x^6) / (x^-2) = (x^6) * (x^2) = x^(6+2) = x^8

Step 3: simplify exponents of y-terms

(y^12) / (y^-6) = (y^12) * (y^6) = y^(12+6) = y^18

It means (10)(x^6)(y^12) / (-5)(x^-2)(y^-6) = -2 x^8 y^18

Hence, option B is correct, i.e. -2 x^8 y^18.

Adam bought 26.14 ounces of orange juice.

To solve the problem, we need to determine how many ounces of orange juice Adam bought with $3.42, given that the cost per ounce is $0.12. We can set up a simple proportion to find the answer.

First, we convert the cost of orange juice per ounce from a fraction to a decimal. The cost is $0.12 per ounce, which can also be written as [tex]$\frac{12}{100}$[/tex] dollars per ounce. Simplifying this fraction gives us [tex]$\frac{3}{25}$[/tex] dollars per ounce.

Next, we convert the total amount spent by Adam, $3.42, into a fraction. This is equivalent to [tex]$\frac{342}{100}$[/tex] dollars.

Now, we set up the equation to find the number of ounces (let's call it [tex]$x$[/tex]) that Adam bought:

[tex]\[ \frac{3}{25} \times x = \frac{342}{100} \][/tex]

To solve for [tex]$x$[/tex], we multiply both sides of the equation by the reciprocal of [tex]$\frac{3}{25}$[/tex], which is [tex]$\frac{25}{3}$[/tex]:

[tex]\[ x = \frac{342}{100} \times \frac{25}{3} \][/tex]

Multiplying the numerators and denominators separately, we get:

[tex]\[ x = \frac{342 \times 25}{100 \times 3} \][/tex]

Simplifying the right side of the equation by canceling out common factors (25 cancels with 100 to become 4, and 3 cancels with 342 to become 114), we have:

[tex]\[ x = \frac{114 \times 4}{4} \][/tex]

This simplifies to:

[tex]\[ x = 114 \][/tex]

However, we must remember that the original amount spent was $3.42, not $342. Therefore, we must divide our result by 100 to account for the cent conversion:

[tex]\[ x = \frac{114}{100} \][/tex]

[tex]\[ x = 1.14 \][/tex]

This result represents the number of ounces Adam bought in addition to the whole number of ounces he could buy with whole dollars. Since $3.00 would buy [tex]$\frac{3}{0.12}$[/tex] ounces, we need to add this to our 1.14 ounces to get the total:

[tex]\[ x_{total} = 1.14 + \frac{3}{\frac{12}{100}} \][/tex]

[tex]\[ x_{total} = 1.14 + \frac{3 \times 100}{12} \][/tex]

[tex]\[ x_{total} = 1.14 + \frac{300}{12} \][/tex]

[tex]\[ x_{total} = 1.14 + 25 \][/tex]

[tex]\[ x_{total} = 26.14 \][/tex]

The total surface area of a cone can be found using the formula A = πr(r + l), where A is the total surface area, r is the radius of the base, and l is the slant height. In this case, the correct answer is 115π cm².

The total surface area of a cone can be found using the formula A = πr(r + l), where A is the total surface area, r is the radius of the base, and l is the slant height.

In this case, the correct answer is 115π cm². Let's calculate it:

Therefore, the correct answer is 115π cm².

To solve the equation 3x = 42, divide both sides by 3, which results in x = 14. This means you would pay $14. The process is similar to isolating a variable in quadratic equations, where different methods may be employed.

Given the equation 3x = 42, we need to isolate the variable x to find its value. This is accomplished by dividing both sides of the equation by 3, which is the coefficient of x. Therefore, the equation becomes x = 42 / 3.

By performing this simple division, we find that x equals 14. So, if x represents the amount you must pay, then you would pay $14.

The process of isolating the variable is essential for solving not only simple equations but also more complex ones, such as quadratic equations which take the form ax² + bx + c = 0.

When dealing with quadratic equations, you can employ the quadratic formula or other methods like factoring or completing the square, depending on the nature of the coefficients and the terms present in the equation.

The amount of salt that is in the tank after 20 minutes is;

A(20) = 267.56 Oz

Initial amount of salt in tank; A(0) = 40 Ounces

A solution containing 4 oz salt per gallon is pumped into the tank at a rate of 5 gal/min.

This means rate in oz/min = 4/1 × 5/1 = 20 oz/min

A'(t) = 20 - [(A(t)/(100)) × 5/1]

A'(t) = 20 - A(t)/20

Rearranging gives;

A'(t) + A(t)/20 = 20

Multiplying through by the integrating factor gives;

A'(t) [tex]e^{t/20}[/tex] + (A(t)/20) [tex]e^{t/20}[/tex] = 20[tex]e^{t/20}[/tex]

A(t) [tex]e^{t/20}[/tex] = 400[tex]e^{t/20}[/tex]  + C

Divide through by [tex]e^{t/20}[/tex] to get;

A(t) = 400 + C [tex]e^{-t/20}[/tex]

At initial condition of A(0) = 40, we have;

40 = 400 + C

C = -360

Thus; at time (t), the amount of salt left is given by;

A(t) = 400 - 360 [tex]e^{-t/20}[/tex]

A(20) = 400 - 360 [tex]e^{-20/20}[/tex]

A(20) = 400 - 132.44

A(20) = 267.56 Oz

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Answer:

the answer on edge is D. 66^2

Step-by-step explanation: