Answers
Chemical Formula = COBr₂
Structural Formula = Attached Below
IUPAC Name = Carbonic Dibromide
Common Name = Bromophosgene
As we know Carbon has the tendency to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon is forming two single bonds with two bromine atoms and a double bond with oxygen atom. Therefore, the valencies of all elements in the given compound are satisfied and completed.
Answer:
The chemical formula of the compound will be COBr2.
Further details:
• The chemical formula of the compound is COBr2.
• The IUPAC name is Carbonic Dibromide
• The common name of the compound is Bromophosgene
As we know Carbon has the propensity to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon are making two single bonds with two bromine atoms and a double bond with oxygen atom. So, the valencies of all essentials in the given compound are fulfilled and accomplished.
Formation of Carbon dibromide:
Carbonyl bromide is made when carbon tetrabromide is melted and concentrated sulfuric acid is added.
In compare to phosgene, carbonyl bromide cannot be twisted efficiently from carbon monoxide and bromine. A complete alteration is not possible due to thermodynamic causes. Additionally, the reaction
CO + Br2 ⇌ COBr2
Answer details:
Subject: Chemistry
Level: College
Keywords:
Carbon dibromideFormation of carbon dibromideCarbon Bromine OxygenLearn more to evaluate:
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Related Questions
Consider the following reversible reaction. mc030-1.jpg What is the equilibrium constant expression for the given system?
Answers
1) The chemical equilibrium is a dynamic process. It means that in an equilibrim reaction there are two rectaions, the forward reaction and the reverse reaction whose velocities are the same.
2) The general equation of a a chemical reaction in equlibrium is:
aA + bB ⇄ cC + dD
Where A and B are the reactants, C and D are the products, and a, b, c, d, are the coefficientes in the balanced equation.
3) So, the equilibrium law is:
[tex]Keq= \frac{C]^c[D]^d}{[A]^a[B]^b} [/tex]
Where Keq is the constant of equilibrium
4) To complete the explanation, I am going to deal with an example:
i) Consider the equlibrium reaction between hydrogen and iodine:
H₂ (g) + I₂(g) ⇄ 2HI(g)
ii) The forward reaction is H₂ (g) + I₂(g) → 2HI(g)
iii) The reverse reaction is 2HI (g) → H₂ (g) + I₂(g)
iv) The law of equilibrium is:
[tex]Keq= \frac{[HI]^2}{[H_2][I_2]} [/tex]
Give the percent yield when 28.16 g of co2 are formed from the reaction of 4.000 moles of c8h18 with 4.000 moles of o2. 2 c8h18(l) + 25 o2(g) → 16 co2(g) + 18 h2o(g) molar mass co2 = 44.01 g/mol
Answers
The percent yield of CO2 is calculated by dividing the actual yield (28.16 g of CO2) by the theoretical yield determined from the stoichiometry of the balanced chemical equation and the limiting reactant, and then multiplying by 100 to get the percentage.
Explanation:Percent Yield CalculationThe question asks for the percent yield of CO2 produced from the reaction of C8H18 with O2. First, we need to consider the balanced chemical equation:
Write the balanced chemical equation: 2 C8H18(l) + 25 O2(g)ightarrow 16 CO2(g) + 18 H2O(g).Identify the limiting reactant. Since 4.000 moles of C8H18 and 4.000 moles of O2 are provided, O2 is the limiting reactant because the reaction requires 25 moles of O2 for every 2 moles of C8H18.Calculate the theoretical yield of CO2. Based on the stoichiometry of the reaction, one mole of O2 would produce 16/25 moles of CO2, so 4.000 moles of O2 would produce 4.000 * (16/25) moles of CO2.Convert moles of CO2 to grams. The molar mass of CO2 is 44.01 g/mol, so the theoretical yield in grams is the number of moles times the molar mass.Calculate the percent yield using the formula: (actual yield / theoretical yield) * 100. The actual yield is given as 28.16 g of CO2.
Therefore, the percent yield can be calculated by dividing the actual yield of CO2 (28.16 g) by the theoretical yield (calculated in step 4), and then multiplying by 100 to get a percentage.
The half-life of cobalt-60 is 5.20 yr. how many milligrams of a 2.000-mg sample remain after 10.50 years?
Answers
final amount =2.000 mg *(1/2)^(10.5/5.20) = 0.493 mg remain after 10.5 years
The (C4H1 0)3N represents a___ amine.
A. Primary
B. Secondary
C. Tertiary
Answers
Answer :The correct answer for (C₄H₁₀ )₃ N is C) TERTIARY AMINE .
The substitution level of nitrogen in amine or in simple words , description of carbon atoms attached to a given nitrogen in any amine is of 4 types :
1 ) Primary amine :
When the given nitrogen is attached to only one carbon then substitution level is known as PRIMARY amine.
Example : CH₃NH₂ : The nitrogen is attached to only one carbon (CH₃) . Hence it is primary amine
2) Secondary amine :
When the given nitrogen is attached to two carbons .
Example : (CH₃)₂NH : The nitrogen is attached to two carbon ( CH₃)₂ , hence it is secondary amine .
3) Tertiary amine :
When the given nitrogen is attached to three carbon atom .
Example : (CH₃)₃NH : The nitrogen is attached to 3 carbons atoms (CH₃)₃ . Hence it is a tertiary amine
4) Quaternary amine : when the nitrogen attached to 4 carbon atoms and amine posses a positive charge on it , its is known as quaternary amine .
Example : (CH₃)₄N⁺ : The nitrogen is attached to 4 carbons and nitrogen . hence it is quaternary amine .
(Image attached )
The given compound is (C₄H₁₀ )₃ N has 3 groups of C₄H₁₀ attached to N , means 3 carbons attached to N , ( image attached ) . Hence it can be said that (C₄H₁₀ )₃ N is TERTIARY AMINE .
Hence correct option is C) Tertiary amine .
When the concentration of a is doubled,the rate for the reaction:2a+b → 2cquadruples.whentheconcentrationofbisdoubledtherateremainsthesame.whichmechanismbelowisconsistentwiththeexperimentalobservations?
Answers
He rate constant for the forward reaction, k1, is 297 l·mol–1·min–1 and the rate constant for the reverse reaction, k–1, is 393 l·mol–1·min–1 at a given temperature. the activation energy for the forward reaction is 42.1 kj·mol–1, while the activation energy for the reverse reaction is 22.1 kj·mol–1. determine the equilibrium constant, k, of this reaction.
Answers
= [tex] \frac{rate.constant.forward.reaction}{rate.constant.of.backward.reaction} [/tex]
= [tex] \frac{297}{393} [/tex]
=0.7557
The equilibrium constant is a number that shows the extent to which reactants are converted into products. The equilibrium constant of the reaction is 0.76.
What is equilibrium constant?The equilibrium constant is a number that shows the extent to which reactants are converted into products.
We know that to obtain the equilibrium constant; K = k1/k-1 where;
k-1 = rate constant of reverse reaction
k1 = rate constant of forward reaction.
Hence;
K = 297 l·mol–1·min–1/393 l·mol–1·min–1
K = 0.76
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What is the de broglie wavelength of a 0.17-kg hockey puck moving at 37 m/s ?
Answers
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
[tex]x = 6.62 \times 10 ^{ - 34} \div 0.17 \times 37[/tex]
[tex]x =1.05 \times {10}^{ - 34} m[/tex]
The wavelength of a hockey of mass 0.17kg traveling at a speed of37 m/s can be calculated by using De Broglie's equation and it comes out to be 1.05m×10⁻³⁴m.
What is De Broglie's equation?
The De Broglie's equation is an equation which shows that a particle has a wave length and hence particle can show wave nature. Any matter can have two nature one is particle nature and other is wave nature.
The wave nature in a particle was given by De Broglie Particle nature of a matter can be described by the phenomenon of black body radiation. Photoelectric effect two shows particle nature nature of light.
Mathematically,
[tex]{\lambda}=\frac{h}{mv}[/tex]
where,
[tex]{\lambda}[/tex]=wavelength=?
m=mass of hockey=0.17kg
h=Plank's constant
v=velocity of hockey=37 m/s
Substituting all given values in the equation
[tex]\lambda[/tex]= (6.626×10⁻³⁴)÷(0.17kg ×37 m/s )=1.05m×10⁻³⁴m
Thus the wavelength of motorcycle is 1.05m×10⁻³⁴m.
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What is the molarity of 500 ml of a solution containing 85.0g AgNO3?
Answers
Formula mass of AgNO3 is 107.9 + 14 + (3 X 16) = 169.9 g.
85.0 g 0.5 mole
------- = ------------ = 1.0 M
169.9 (g/mole) 0.5 liter
Answer: 1 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{85.0g}{170g/mol}=0.5moles[/tex]
[tex]V_s[/tex] = Volume of solution in ml
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.5moles\times 1000}{500ml}=1mole/L[/tex]
Therefore, the molarity of solution will be 1 M.
Please help kind of confused here.
In the early 1900s, Henry Gwyn-Jeffreys Moseley added to the development of the modern periodic table. Which answer best explains how Moseley started his investigations?
1. by reviewing the work of those who contributed to the previous versions of the table
2. by making an entirely new organizational scheme for the previous versions of the table
3. by analyzing the work of a select group of contributors to the previous versions of the table
4. by rejecting the work of all those who had previously developed the earlier versions of the table
Answers
Moseley took Mendeleevs periodic table which was organized by weight and organized the elements instead by at atomic number
Answer:
The correct answer is 1. Moseley started his investigations by reviewing the work of those who contributed to the previous versions of the table.
Explanation:
Henry Gwyn Jeffreys Moseley was a British physicist. His most important scientific contribution was the proof of the correctness of the concept of atomic numbers in chemistry.
In 1913, using X-ray spectroscopy, he found a systematic relationship between the wavelength and the atomic number. Previously, it was assumed that the atomic number was an arbitrary number based on the order of the atomic masses, but had to be changed to bring an element into the right place in the periodic table. Moseley's discovery showed that atomic numbers had an experimentally measurable basis. In addition, he showed that there were gaps in numbers 43, 61 and 75 (known today as the radioactive elements technetium and promethium, as well as the stable but rare rhenium). His work was further proof of the then controversial atomic theory.
Consider the electrolysis of molten barium chloride (bacl2). (a) write the half-reactions. include the states of each species..
Answers
Molten barium
chloride is separetes:
BaCl₂(l) →
Ba(l) + Cl₂(g),
but first ionic bonds in this salt are separeted
because of heat:
BaCl₂(l) →
Ba²⁺(l) + 2Cl⁻(l).
Reaction of reduction at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).
Reaction of oxidation at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.
The anode is positive and the cathode is negative.
The electrolysis of molten barium chloride involves reduction of barium ions and oxidation of chloride ions, requiring two electrons to move through the circuit for one unit of the reaction.
Explanation:During the electrolysis of molten barium chloride (BaCl2), barium ions (Ba2+) are reduced at the cathode, and chloride ions (Cl-) are oxidized at the anode. The half-reactions, showing the movement of electrons through the circuit, are as follows:
Cathode (reduction): Ba2+(l) + 2e- → Ba(l)Anode (oxidation): 2Cl-(l) → Cl2(g) + 2e-The overall cell reaction is obtained by combining the half-reactions and balancing the electrons:
Ba2+(l) + 2Cl-(l) → Ba(l) + Cl2(g)
For each mole of barium ions reduced, two electrons are involved in the transfer. Similarly, for each mole of chlorine gas produced, two electrons are given up by chloride ions. As such, there would be two electrons that moved through the circuit for one unit of the reaction to occur.
. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?
Answers
Four
Explanation:
Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,
Ca → Ca²⁺ + 2 e⁻
These two electrons are accepte by Sulfur as,
S + 2 e⁻ → S²⁻
So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,
The three beakers shown below contain solutions of [cof6]3–, [co(nh3)6]3+, and [co(cn)6]3–. based on the colors of the three solutions, which compound is present in each of the beakers?
Answers
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.
- Ligands strength order: CN⁻ > NH₃ > F⁻
- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻
- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.
- So CN complex will absorb at lower wavelength (yellow color)
The colors of the compounds in the beakers could potentially be: [CoF6]3– (green), [Co(NH3)6]3+ (yellow-orange), and [Co(CN)6]3– (red), although colors can vary based on different conditions.
Explanation:The question asks us to identify the compounds present in three beakers based on the color of the solution. While this is generally impossible to answer with absolute certainty without more information or additional tests, we can make a fair guess based on some known color-characteristics of these compounds.
[CoF6]3– is generally green due to the color of the Cobalt(III) ion.
[Co(NH3)6]3+ is usually yellow to orange in color.
FInally, [Co(CN)6]3– commonly has a strong red color.
Note that in reality, actual colors can vary depending on concentration, temperature, and other factors.
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James is looking at a parallel circuit plan for lighting. There is a battery providing the power. There are switches labeled A,B,C,D that can be turned on to close the circuit. Which switch does not have to be on for light 3 to function?
Answers
For light 3 to function, switch D does not have to be on. This diagram shows a parallel circuit that provides more than one way for the current to return to the power source.
Acetyl-coa and succinyl-coa are both high-energy thioesters, but their chemical energy is put to different uses. explain how the chemical energy is used in the two cases.
Answers
The energy released by hydrolysis of acetyl-CoA is needed for the condensation reaction that links acetyl moiety to oxaloacetate, yielding citrate. The energy released by hydrolysis of succinyl-CoA drives the phosphorylation of GDP, yielding GTP
Some reactions of the citric acid cycle are endergonic. Explain how the overall cycle is exergonic.
The sum of the energies of the individual reactions is -44.3kJ for each mole of acetyl-CoA that enters the cycle
Which enzymes of the citric acid cycle are missing from the glyoxylate cycle?
isocitrate dehydrogenase, alpha-ketoglutarate dehydrogenase, and succinyl-CoA synthetase
Which element has the electron configuration shown above
Answers
The 2p shell is the elements on period 2 from Boron to Neon on the periodic table. The 6 means it has 6 electrons and is sixth in line so it must be Neon.
Which change in oxidation number represents reduction?
A) –1 to +1
B) –1 to –2
C) –1 to +2
D) –1 to 0
Answers
If 152 grams of ethane (c2h6) are reacted with 231 grams of oxygen gas, what is the mass of the excess reactant leftover after the reaction has reached completion? 2c2h6(g) + 7o2(g) → 4co2(g) + 6h2o(g)
Answers
Chemical reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(g).
m(C₂H₆) = 152 g.
n(C₂H₆) = m(C₂H₆) ÷ M(C₂H₆).
n(C₂H₆) = 152 g ÷ 30 g/mol.
n(C₂H₆) = 5.067 mol.
m(O₂) = 231 g.
n(O₂) = 231 g ÷ 32 g/mol.
n(O₂) = 7.218 mol; limiting reactant.
From chemical reaction: n(O₂) : n(C₂H₆) = 7 : 2.
n(C₂H₆) = 2 · 7.218 mol ÷ 7.
n(C₂H₆) = 2.0625mol.
Δn(C₂H₆) = 5.067 mol - 2.0625 mol.
Δn(C₂H₆) = 3.0045 mol.
Δm(C₂H₆) = 3.0045 mol · 30 g/mol = 90.135 g.
The answer is:
the mass of the excess reactant leftover after the reaction has reached completion is 90.135 grams
The explanation:
According to the reaction equation:
2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(g)
when m is the mass of C₂H₆ m(C₂H₆) = 152 g
So we need to get the number of moles of C₂H₆
n(C₂H₆) = mass C₂H₆ / molar mass of C₂H₆(M)
and when the molar mass of C₂H₆ = 30 g/mol
so, by substitution:
n(C₂H₆) = m(C₂H₆) / M(C₂H₆).
n(C₂H₆) = 152 g / 30 g/mol.
n(C₂H₆) = 5.067 mol.
Then
when the mass of O₂ m(O₂) = 231 g
so we need to get the number of moles of O₂
when nO₂ = mass O₂/ molar mass of O₂
when molar mass of O₂ = 32 g /mol
So, by substitution:
n(O₂) = 231 g / 32 g/mol.
n(O₂) = 7.218 mol
So O₂ is the limiting reactant
according to the chemical reaction we can get the molar ratio between the O₂and C₂H₆:
n O₂ : n C₂H₆ → 7.218 : n C₂H₆
7 : 2 7 : 2
∴ n(C₂H₆) = 2 * 7.218 mol / 7
∴ n(C₂H₆) = 2.0625 mol
The number of moles remaining n(C₂H₆) = 5.067 mol - 2.0625 mol
∴ n (C₂H₆) = 3.0045 mol
So the mass remains = moles remains * molar mass of C₂H₆
∴ m (C₂H₆) = 3.0045 mol * 30 g/mol = 90.135 g
help again pleaseee!!
Answers
from the energy need to fuse the atoms together
Fusion is the process which powers the sun and the stars. It is energy that makes all life on earth possible. It is called 'fusion' because the energy is produced by fusing together light atoms, such as hydrogen, at the extremely high pressures and temperatures which exist at the centre of the sun (15 million ºC). At the high temperatures experienced in the sun any gas becomes plasma, the fourth state of matter (solid, liquid and gas being the other three).
The fusion reaction that is easiest to accomplish is the reaction between two hydrogen isotopes: deuterium, extracted from water and tritium, produced during the fusion reaction through contact with lithium. When deuterium and tritium nuclei fuse, they form a helium nucleus, a neutron and a lot of energy.
Glacier and erosion in a sentence
Answers
Complete the following table.
Acid Molarity Moles of H⁺ released per liter
HCl 1 ____
H2SO4 1 ____
H3PO4 1 ____
H2SO4 0.5 ____
H3PO4 3 ____
HNO3 2 ____
Answers
Explanation:
1) Arrange the data to understand the question:
Acid Molarity Moles of H⁺ released per liter
HCl 1 ____
H2SO4 1 ____
H3PO4 1 ____
H2SO4 0.5 ____
H3PO4 3 ____
HNO3 2 ____
2) All the given acids are strong acids, so you can consider they dissociate completely and release all the hydrogens present in the chemical formula.
3) The molarity formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters
From that, n = M×V
Go one by one with that formula.
Acid Molarity Moles of solute number of H in Moles H⁺ per liter the chemical formula per liter
HCl 1 1M×1L = 1 1 1×1 = 1
H₂SO4₄ 1 1M×1L = 1 2 2×1 = 2
H₃PO₄ 1 1M×1L = 1 3 3×1 = 3
H₂SO₄ 0.5 0.5M×1L = 0.5 2 2×0.5 = 1
H₃PO₄ 3 3M×1L = 3 3 3×3 = 9
HNO₃ 2 2M×1L = 2 2 2×2 = 4
Complete the following table.
Acid Molarity Moles of H⁺ released per liter
HCl 1
H2SO4 1
H3PO4 1
H2SO4 0.5
H3PO4 3
HNO3 2
[Answer]
1
2
3
1
9
2
Answer how many moles of sodium will react with 2.6l of cl2 gas at 1.15 atm
Answers
2 Na + Cl₂ → 2 NaCl
Before applying stoichiometry, first you will have to find the moles of Cl₂ at given conditions using Ideal gas equation.
n = P V / R T
As, temperature is not given, so put standard Temperature i.e. 273 K, or if you are provided with it simply put its value So,
n = (1.15 atm × 2.6 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K)
n = 0.133 mol of Cl₂
Now,
According to Balance equation,
1 mole Cl₂ required = 2 moles of Na
So,
0.133 mol Cl₂ will require = X moles of Na
Solving for X,
X = (0.133 mol × 2 mol) ÷ 1 mol
X = 0.266 moles of Na
ASAP HELP GIVING TO CORRECT PERSON A BRAINLIEST REWARD
Cellulose is a polymer that makes up plant cell walls. Cellulose is made from a chain of C6H10O5 molecules.
Which monomers are most likely used to produce cellulose?
a)nucleotides and amino acids
b)glucose molecules
c)nucleotides
d)amino acids
Answers
Answer:
Answer is B
Explanation:
What is the molar concentration of a phosphoric acid (h3po4) solution if 55.5 ml of the solution requires 35.5 ml of .150 m naoh to completely react with the phosphoric acid?
Answers
find the moles of NaOH reacted =molarity x volume
= 35.5 x0.150 = 5.325 moles
write a balanced reacting equation
=NaOH +3 H3PO4 = Na3PO4 + 3H2O
by use of reacting ratio between NaOH to H3PO4 which is 1:3 the moles of H3Po4 is therefore
= 5.325moles/3= 1.775 moles
molar concentration is therefore of H3PO4= moles /volume
=1.775/55.3 = 0.0320 M of H3PO4
Name the salt k4[pt(co3)2f2] given that the carbonate ion acts as a monodentate ligand in the complex. the oxidation number of platinum is +2. enter the name.
Answers
*Note, since carbonate ion is acting as monodentate ligand, prefix of 'di' is used. In case, if it had been a bidentate ligand prefix 'bis' would have been used.
Answer:
Potassium dicarbonatedifluoroplatinate (II)
Explanation:
Hello,
Based on the IUPAC rules, the given compound is a complex called potassium dicarbonatodifluoroplatinate (II) as long as the carbonate ion is present twice as a monodentate ligand therefore it is preceded by a "di" prefix. In addition, two fluorines are also present with the "di" prefix as well as a platinum which complete the anionic section including +2 as the platinum oxidation state.
Best regards.
How many milliliters of 0.564 m hcl are required to react with 6.03 grams of caco3 ?
Answers
CaCO3 + 2 HCl = CO2 + CaCl2 + H2O
Find how many moles of CaCO3 you are dealing with
6.03 g x 1 mol / 100 g = .0603 moles
However, you need twice as much HCl
.0603 x 2 moles / .564 M = .21 L
Determine the overall charge on each complex.a) tetrachlorocuprate(i)b) pentaamminechlorocobalt(iii)c) diaquadichloroethylenediaminecobalt(iii)
Answers
In present complex chlorine is negatively charged ligand (-1) and oxidation state of copper is +1. Therefore, total charge on complex = 4(-1) + 1 = -3
Complex b: pentaamminechlorocobalt(iii)
In present complex, ammine is a neutral ligand (charge = 0), chlorine is negatively charged ligand (charge = -1) and oxidation state of Co is +3. Therefore, total charge on complex is 5(0) + (-1) + (+3) = +2
Complex c: diaquadichloroethylenediaminecobalt(iii)
In present complex, aqua is a neutral ligand (charge = 0), chlorine is a negatively charged ligand (charge = -1), ethylenediamine is a neutral ligand (charge = 0) and oxidation state of cobalt is +3. Therefore, total charge on complex is 2(0) + 2(-1) + 2(0) + 3 = +1.
What is the mass of 2.30 moles of magnesium chloride, mgcl2?
Answers
Mass (grams) ⇄ Moles ⇄ Particles (atoms, molecules, etc.)
× ÷
↓ ↓
Molar Mass 6.02 × 10^23 (Avogadro's number)
Molar Mass of Magnesium Chloride: 1 Mg: 24.3
+ 2 Cl: 2(35.5)
95.3 g/mol MgCl2
2.30 mol × 95.3 g/mol MgCl2 ≈ 219. grams MgCl2 (according to significant figures)
Ksp [caso4] = 2.4 × 10-5. determine the molar solubility of caso4 in a solution containing 0.100 m na2so4.
Answers
The molar solubility of CaSO4 in a solution containing 0.100 M Na2SO4 is 2.4 x 10−4 M, calculated using the Ksp value and the concentration of sulfate ions due to the common ion effect.
Explanation:The molar solubility of CaSO4 in a solution containing 0.100 M Na2SO4 can be calculated using the solubility product constant (Ksp) and the concept of common ion effect. The solubility product expression for CaSO4 can be written as Ksp = [Ca²+ ][SO4²−]. Since the sodium sulfate solution already contains sulfate ions, we will consider the concentration of [SO4²−] as 0.100 M given in the question. The equation simplifies to Ksp = [Ca²+]*0.100. Therefore, the molar solubility is [Ca²+]= Ksp/0.100 which is 2.4 x 10−5/0.100 = 2.4 x 10−4 M. This suggests that in a 0.100 M Na2SO4 solution, additional CaSO4 would start precipitating when the [Ca²+] reaches 2.4 x 10−4 M.
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The molar solubility of CaSO₄ in a solution containing 0.100 M Na₂SO₄, with a Ksp of 2.4 × 10⁻⁵ is 2.4 × 10⁻⁴ M, which is lower than in pure water due to the common ion effect.
Calculating the molar solubility of calcium sulfate (CaSO₄) in a solution containing 0.100 M sodium sulfate Na₂SO₄ given the solubility product constant (Ksp) for CaSO₄ is 2.4 × 10⁻⁵.
Because Na₂SO₄ dissociates into 2 Na⁺ and 1 SO₄²⁻ in solution, the concentration of SO₄²⁻ due to Na₂SO₄ is 0.100 M. Since the solution is already saturated with sulfate ions, the molar solubility of CaSO₄ will be different from its solubility in pure water. The common ion effect will reduce the solubility of CaSO₄ in the solution.
To find the molar solubility of CaSO₄, let's set up the equation based on the Ksp expression:
Ksp = [Ca²⁺] [SO₄²⁻]
Since the concentration of SO₄²⁻ from Na₂SO₄ is already 0.100 M, and the Ksp for CaSO₄ is 2.4 × 10⁻⁵, the molar solubility of CaSO₄ in this solution is calculated as:
Ksp = (s) × (0.100 M)
2.4 × 10⁻⁵ = (s) × (0.100 M)
s = 2.4 × 10⁻⁴ M
Therefore, the molar solubility of CaSO₄ in a 0.100 M Na₂SO₄ solution is 2.4 × 10⁻⁴M.
If I cut the height of an object in half, what will happen to its GPE?
A. Not enough info
B. Double
C. Disappear
D. Halve
Answers
If you cut the height of an object in half, its gravitational potential energy (GPE) will also halve.
Explanation:If you cut the height of an object in half, its gravitational potential energy (GPE) will also halve.
GPE is determined by the height of the object and its mass. When you cut the height in half, the GPE is reduced by half because the potential energy is directly proportional to the height.
For example, if a book has a certain GPE at a certain height, cutting the height in half will result in the book having half the GPE it had before.
Learn more about Gravitational potential energy here:https://brainly.com/question/23134321
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Choose all the answers that apply. Muscles in the small intestine are _____. striated voluntary involuntary smooth cardiac
Answers
The muscles can be seen in the muscularis externa layer of the small intestine. Those muscles are arranged in two ways as outer is longitudinal and inner is circular way. Those muscles help to do movements of small intestine.
Answer:
The answer is smooth and Involuntary.
Explanation:
Smooth muscles are involuntary which means they automatically do a function without the brain telling it to.