What does the law of conservation of energy state about energy in a closed system
Explanation:
Law of conservation of energy: The energy of the system can neither be created nor destroyed. It can be transformed from one form to another.
In a closed system, the energy remains conserved. It is isolated from the surrounding.
For example, the ball is rolling from the inclined plane. At the top of the inclined plane, the potential energy is maximum. When the ball starts rolling then the kinetic energy starts increases. Here, the potential energy is converted into kinetic energy. The energy transformation takes place.
What are the properties of elements based on their placement on the periodic table?
Two meteoroids are heading for earth. their speeds as they cross the moon's orbit are 1.0 km/s . part a the first meteoroid is heading straight for earth. what is its speed of impact?
Answer : [tex]v_{2} = 11.2\ km/s[/tex]
Explanation : The total energy of the meteoroids
Total Energy = Kinetic Energy + Potential Energy
[tex]E = \dfrac{1}{2}mv^{2} - \dfrac{GMm}{R}[/tex]
Total energy remain constant.
Now, for both meteoroids
[tex]\dfrac{1}{2}m(v_{2}^{2} - v_{1}^{2}) = GMm\left(\dfrac{1}{R}-\dfrac{1}{r}\right)[/tex]
Where, R = radius of the earth
r = distance of the moon
M = mass of the earth
m = mass of the meteoroid
[tex]v_{2}^{2} = 2GM\left(\dfrac{1}{R}-\dfrac{1}{r}\right)+ v_{1}^{2}.....(I)[/tex]
Now, put the values in equation (I)
[tex]v_{2}^{2} = 1 + 2\times6.67\times10^{-11}\times6\times10^{24}\left(\dfrac{1}{6.37} - \dfrac{1}{384}\right)\times10^{-6}[/tex]
[tex]v_{2}^{2} = 12361\times 10^{4}\ m/s[/tex]
[tex]v_{2} = 11118.003\ m/s[/tex]
[tex]v_{2} = 11.2\ km/s[/tex]
Hence, this is the required solution.
The speed of the meteorite at its impact on Earth will be [tex]\boxed{11.1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{11088.24\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
Further Explanation:
The meteorite in the outer space at a particular distance from the Earth has its energy stored in the form of the kinetic energy as well as the potential energy.
The kinetic energy of the meteorite is given by:
[tex]{E_k} = \frac{1}{2}m{v^2}[/tex]
The potential energy of the meteorite at a particular height from Earth is given by:
[tex]{E_p} = - \frac{{GMm}}{r}[/tex]
Here, [tex]M[/tex] is the mass of the Earth, [tex]m[/tex] is the mass of satellite and [tex]r[/tex] is the distance of the meteorite from the centre of the Earth.
The total energy of the meteorite is given as:
[tex]\begin{aligned}{E_T}&={E_k} + {E_p}\\&=\frac{1}{2}m{v^2}-\frac{{GMm}}{r}\\\end{aligned}[/tex]
As the meteorite moves from the moon’s orbit towards the Earth, the potential energy of the meteorite gets converted into the kinetic energy.
Using conservation of energy for the meteorite from the moon’s orbit to the Earth’s surface:
[tex]\begin{aligned}\frac{1}{2}mv_1^2-\frac{{GMm}}{r}&=\frac{1}{2}mv_2^2-\frac{{GMm}}{R} \hfill\\v_1^2-v_2^2&=2GM\left({\frac{1}{r}-\frac{1}{R}}\right) \hfill\\{v_2}&=\sqrt {v_1^2-2GM\left({\frac{1}{r}-\frac{1}{R}}\right)}\hfill\\\end{aligned}[/tex]
Here, [tex]{v_1}[/tex] is the speed of the meteorite in moon’s orbit, [tex]r[/tex] is the distance of the moon’s orbit from centre of Earth and [tex]R[/tex] is the radius of Earth.
The meteorite passes the moon’s orbit at the speed of [tex]1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .
We know that the distance of the Moon’s orbit from the centre of Earth is [tex]3.84 \times{10^5}\,{\text{km}}[/tex] and the radius of the Earth is [tex]6371\,{\text{km}}[/tex] .
Substitute the values in the equation of Energy.
[tex]\begin{aligned}v_{f}&=\sqrt{(1)^{2}-2(6.67\times10^{-11})(5.97\times10^{24})\left(\dfrac{1}{384}-\dfrac{1}{6.37}\right)10^{-6}}\\&=\sqrt{1.229\times10^{8}}\text{ m/s}\\&=11088.24\text{ m/s}\\&\approx11.1\text{ km/s}\end{aligned}[/tex]
Thus, the speed of the meteorite striking the Earth is [tex]\boxed{11.1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{11088.24\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
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Answer Details:
Grade: College
Subject: Physics
Chapter: Gravitation
Keywords:
Meteorite, moon’s orbit, 1km/s, two meteorite, heading for, speed of impact, 11.1 km/s, 384000 km, total energy, heading straight.
The _____ point is the point at which a liquid boils when at a pressure of 14.7 pounds per square inch absolute (psia). A. Boiling B. Combustion C. Flash
5. Describe how a battery works. (4 points)
Which structures allow for the removal of wastes from the developing fetus?
The fetus relies upon its mother as it develops. These are some of the things it needs:
protection against knock and bumps, and temperature changes oxygen for respiration nutrients (food and water)The developing fetus also needs its waste substances removing.
The fetus is protected by the uterus and the amniotic fluid, a liquid contained in a bag called the amnion.
how does my potential energy increase and decrease?
A soccer ball is traveling at a velocity of 50 m/s the kinetic energy of the ball is 500 j what is the mass of the soccer ball?
Answer:
Its 0.4kg
Explanation:
in the free-body diagram shown above, which of the following is the gravitational force acting on the car?
a.5800 N
b.755 N
c.14700 N
d.13 690 N
Answer:
c. 14700 N
Explanation:
The gravitational force acting on the car in a free-body diagram depends on the car's mass and gravitational constant. Without the mass or the context provided by the diagram, it is impossible to definitively answer the question.
Explanation:In order to determine the gravitational force acting on the car in this free-body diagram, you first need to understand the underlining principles of force. The force of gravity on an object is determined by the object's mass and the gravitational constant, typically represented by the formula F=mg. However, without further information such as the mass of the car or the free-body diagram referenced in the question, it's not possible to definitively answer this question. The options a) 5800N, b) 755N, c) 14700N, or d) 13690N could be potential answers depending on the mass of the car, the scale of the diagram, and the context of the problem.
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David’s doctor suspects that he has diabetes. Which of these should be performed by the doctor to confirm the suspicion?
Answer: D.
Explanation: Glucose levels are only option that relates to realistic diagnosis
Rest of the answers-
a DNA analysis to identify genetic abnormalities
a physical exam to look for tumors
a study to observe David’s social behaviors
a test to check David’s glucose levels
Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the entire structure would sink by a certain amount for every additional floor that is added. If the maximum permissible limit for depression of the structure is 20 centimeters, how many floors can be safely added to the building?
14
15
18
23
Identify which best describes the energy used to pluck guitar strings to make sound.
A concrete bridge is built of 315-cm-long concrete slabs with an expansion joint between them. the slabs just touch on a 115∘f day, the hottest day for which the bridge is designed.
The expansion joints in a concrete bridge allow for thermal expansion, preventing buckling by accommodating changes in size due to temperature variation. This allows the bridge to withstand frequent temperature changes without significant structural damage.
Explanation:The subject of this question involves a phenomenon known as thermal expansion, which is a concept in physics. When the temperature of a material changes, the material can expand or contract. Concrete, like many other materials, expands when heated and contracts when cooled.
On a sunny day, especially a very hot one like 115 degrees Fahrenheit, the heat from the sun causes the concrete slabs in the bridge to expand. Thanks to the expansion joints between the slabs, the bridge can change length without buckling under this thermal stress. The expansion joints are designed to accommodate this precise thermal expansion, allowing the slabs to expand and contract freely with changes in temperature.
In the case of the Auckland Harbour Bridge in New Zealand, the bridge is equipped with thermal expansion joints that prevent it from buckling due to thermal expansion. Similarly, the change in length of the bridge due to temperature changes is usually small and distributed across multiple expansion joints, making the process almost unnoticeable in daily use.
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20. A 0.145 kg mass of tungsten at 130.0 °C is placed in a 0.502 kg of water at 22.0 °C. The mixture reaches equilibrium at 28.6 °C. Calculate the specific heat of tungsten. (specific heat of water = 4180 J/kg C)
Givens:
Unknown:
Equation: macaΔTa = - mbcbΔTb
Substitute:
Solve:
Fluorine is more electronegative than oxygen because 1. the outer orbitals of fluorine are located further from the nucleus than the outer orbitals of oxygen. 2. the effective nuclear charge of fluorine is greater than that of oxygen. 3. the effective nuclear charge of oxygen is greater than that of fluorine. 4. the outer orbitals of oxygen are located closer to the nucleus than the outer orbitals of fluorine. 5. false; oxygen is more electronegative than fluorine.
Fluorine is more electronegative than oxygen because the effective nuclear charge of fluorine is greater than that of oxygen.
Electronegativity is the tendency of an atom to attract electrons. The effective nuclear charge is the net positive charge experienced by an electron in an atom. Fluorine has a smaller atomic radius than oxygen. This means that the electrons in the outer orbitals of fluorine are closer to the nucleus than the electrons in the outer orbitals of oxygen.
The closer the electrons are to the nucleus, the stronger the attractive force between the electrons and the nucleus. This means that the effective nuclear charge of fluorine is greater than that of oxygen. Therefore, fluorine is more electronegative than oxygen.
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Kara built a model of how molecules behave when they are in solid form. She filled a clear plastic box with marbles to the very top and put the lid on the box. When she shakes the box, the marbles can barely move. Which of the following is a limitation of Kara's model?
Answer:
The marbles must be held in a box, but solids hold together without a container.
Explanation:
study island!!!
Answer:
The marbles must be held in a box, but solids hold together without a container.
A bicycle wheel is rotating at 49 rpm when the cyclist begins to pedal harder, giving the wheel a constant angular acceleration of 0.45 rad/s2 . what is the wheel's angular velocity, in rpm, 9.0 s later?
Answer:
Angular velocity, [tex]\omega_f=9.180\ rad/s[/tex]
Explanation:
It is given that
Initial angular velocity of the wheel, [tex]\omega_o=49\ rpm[/tex]
Since, 1 revolutions per minute = 0.10471 radians per second
[tex]\omega_o=49\ rpm=5.1307\ rad/s[/tex]
Angular acceleration of the wheel, [tex]\alpha =0.45\ rad/s^2[/tex]
Time taken, t = 9 s
Let [tex]\omega_f[/tex] is the final velocity of the wheel 9 seconds later. Using the equation of kinematics to find it :
[tex]\omega_f=\omega_o+\alpha t[/tex]
[tex]\omega_f=5.1307+0.45\times 9[/tex]
[tex]\omega_f=9.180\ rad/s[/tex]
So, the final angular velocity of the wheel is 9.180 rad/s. Hence, this is the required solution.
The bicycle wheel's angular velocity, in rpm is 87.68 rpm.
Given the following data:
Time = 9.0 secondsAngular acceleration = 0.45 [tex]rad/s^2[/tex]Initial angular velocity of the bicycle wheel = 49 rpm.Conversion:
1 rpm = 0.1047 rad/s
49 rpm = X rad/s
Cross-multiplying, we have:
[tex]X = 49[/tex] × [tex]0.1047[/tex]
X = 5.1303 rad/s
To find the bicycle wheel's angular velocity, in rpm, we would use the first equation of kinematics:
[tex]w_f = w_o + at[/tex]
Where:
[tex]w_f[/tex] is the final angular velocity.[tex]w_o[/tex] is the initial angular velocity.a is the angular acceleration.t is the time.Substituting the given parameters into the formula, we have;
[tex]w_f = 5.1303 + 0.45(9)\\\\w_f = 5.1303 + 4.05[/tex]
Final angular velocity = 9.1803 rad/s
Next, we would convert the value in rad/s to rpm:
Conversion:
1 rpm = 0.1047 rad/s
X rpm = 9.1803 rad/s
Cross-multiplying, we have:
[tex]9.1803 = 0.1047X\\\\X = \frac{9.1803}{0.1047}[/tex]
X = 87.68 rpm.
Final angular velocity = 87.68 rpm.
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This theory lost its appeal when astronomers discovered quasars and cosmic background radiation.
Answer:
The steady state theory
Explanation:
According to the steady state model of the universe, the universe is continuously expanding while maintaining average density as constant. According to the theory, matter is continuously being formed and creating new stars and galaxies while the old ones are becoming un-observable. There is no beginning or end of time.
On the other hand, the big bang theory describes that the entire matter of the universe was confined in a point and with the big bang, this point started expanding. This happened about 13.8 billion years ago. Of course the density and temperature of the universe was very high at the beginning. In the initial few minutes of the big bang, the universe expanded rapidly which resulted in the decrease in its density and temperature. After million years, the universe transparent for radiation to freely travel through space. Cosmic Microwave background is the remnant of this early universe and is a strong evidence of the Big Bang Theory. The number of quasars were greater in past than present which shows that universe is evolving with time.
A solid has a _____ volume and a ____ shape.
fixed, variable, fixed, variable
HELP
An electrical drill has 100 J of chemical energy. Of the 100 J, 45 J are transformed into kinetic energy and 20 J are transformed into sound. The remaining energy is given off as thermal energy.
What is the thermal energy of the drill?
According to law of conservation of energy, the thermal energy of the drill is 35J.
What is law of conservation of energy?The law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.
Total energy = Kinetic energy + Sound energy+ Thermal energy
100 = 45+20+ Thermal energy
Thermal energy = 35J
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A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0 N. What is the speed of the wave?
Warhol's early paintings of these objects made him famous.
Campbell's soup cans
Coke bottles
comic strips
urinals
What is the voltage of a battery that will charge a 4.0 μf capacitor to ± 36 μc ?
Lexy used the formula shown to calculate the force of gravity on a space shuttle. Fg = G What does 3 × 105 kg represent? the difference between Earth’s mass and the space shuttle’s mass the sum of Earth’s mass and the space shuttle’s mass the mass of Earth the mass of the space shuttle
This term shows the mass of the space shuttle
Explanation:We know that the mass of the Earth is 5.972 × 10^24 kg. Similarly the sum of mass of earth and the mass of shuttle must be a greater number as compared to the number given. It simply means that the mass of earth is itself 5.972 × 10^24 kg and the value given is 3 × 105 kg so it is obvious that if was the sum then it must be greater than the mass of earth. Therefore we can say that this not the mass of earth, neither the sum of mass of earth and shuttle, but this is only the mass of space shuttle which is the last multiple choice.
Answer:
The answer is D
Explanation:
1200 meters is less than 1 kilometer
TRUE OR FALSE
if you weigh 110 pounds , in kilograms the number will be greater than 110
TRUE OR FALSE
A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from the wall is at a frequency 408 hz. at what is the speed is the boy riding his bicycle toward the wall? assume the speed of sound in air is 340 m/s.
The boy on the bicycle is approaching the brick wall at a speed of 5.88 m/s. This is calculated using the formula for the Doppler effect which describes a frequency shift due to relative motion of the source and the observer.
Explanation:This problem deals with the Doppler effect, which is a shift in frequency perceived by an observer due to relative motion between the source of a wave (here, the bicycle horn) and the observer (the bicyclist hearing the reflected sound from the wall). In this case, we can use the formula for the Doppler effect when both the source and observer are moving towards each other:
f' = f (v + vo) / (v - vs)
where f' is the observed frequency (408 Hz), f is the source frequency (400 Hz), v is the speed of sound (340 m/s), vo is the observer's speed (the boy's speed) and vs is the source's speed (in this case, zero, since the wall is stationary).
Setting up the equation gives us:
[tex]408 = 400 (340 + vo) / (340 - 0).[/tex]boy, gives us vo = 5.88 m/s. Thus, the boy is riding his bicycle towards the wall at a speed of 5.88 m/s.
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Using the Doppler effect principle, the speed of the boy on the bicycle relative to the air is approximately 6.8 m/s.
Explanation:The scenario given in the problem is a classic example of the Doppler Effect: the change in frequency or wavelength of a wave in relation to an observer moving relative to the wave source. In this case, we have the frequency of the sound wave as observed in the stationary frame (400 Hz) and in the moving frame (the boy on the bicycle, 408 Hz). The speed of sound in air is given as 340 m/s.
The observed frequency f is related to the source frequency f0 and the speed of the observer v with respect to the medium (air in this case) by the formula: f = f0*(v + v0) / v, where v0 is the speed of the source of the wave.
Substituting the given values into the equation gives 408 Hz = 400 Hz * (340 m/s + v) / 340 m/s. Solving the equation yields the speed of the boy on the bicycle relative to the air, which comes out to be approximately 6.8 m/s.
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A merry-go-round is spinning at a rate of 4.0 revolutions per minute. cora is sitting 1.0 m from the center of the merry-go-round and cameron is sitting right on the edge, 2.0 m from the center. what is the relationship between the rotational speeds of the two children?
Answer:
Same.
Explanation:
The rotational speed of an object is given by :
[tex]\omega=\dfrac{\theta}{t}[/tex]
[tex]\theta[/tex] is the angular displacement
t is the time taken
The angular speed of a merry- go- round is 4 revolutions per minute. There are two persons Cora and Cameron. Cora is sitting 1.0 m from the center of the merry-go-round and Cameron is sitting right on the edge, 2.0 m from the center.
The rotational speeds of both of the children remains the same because it is independent of the distance from the center.
A light bulb does 100 joules of work in 2.5 seconds. How much power does it have.
Final answer:
To calculate power, divide energy in joules by time in seconds. The light bulb with 100 joules of work done in 2.5 seconds has a power of 40 watts.
Explanation:
The student is asking how to determine the power of a light bulb based on the work done over time. The formula to calculate power is:
P = W / t
where P is power in watts (W), W is energy in joules (J), and t is time in seconds (s). In this case, the light bulb does 100 joules of work in 2.5 seconds. So, applying the formula:
P = 100 J / 2.5 s = 40 W
Hence, the power of the light bulb is 40 watts.
An isotope of the element fluorine has 9 protons and 10 neutrons. What is the name of this isotope? fluorine-
Answer:
19
Explanation:
Fluorine-19.
The isotope of fluorine with 9 protons and 10 neutrons is named Fluorine-19. This is because the mass number of an isotope equals the sum of its protons and neutrons, and in this case, 9 (protons) + 10 (neutrons) = 19. The atomic number of fluorine is 9, which means any atom of fluorine will always have 9 protons. A normal (most commonly occurring) atom of fluorine also has a mass number of 19, deriving from 9 protons and 10 neutrons. This makes Fluorine-19 the only stable and naturally-occurring isotope of fluorine.
A +1.0 c charged object and a +2.0 c charged object are separated by 100 m. where should a -1.0x10-3 c charged object be placed on a line between the positively charged objects so that the net electrical force exerted on the negatively charged object is zero?
The negative charge should be placed 41 m from +1.0 C charged object
Further explanationElectric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
Given:
Q₁ = +1.0 C
Q₂ = +2.0 C
R₁ = x
R₂ = 100 - x
q = -1.0 × 10⁻³ C
Unknown:
x = ?
Solution:
In order to produce a total force = 0, the electric forces acting on this negative charge must be in the opposite direction and equal in magnitude.
We assume the distance of this negative charge to the positive charge +1.0 C is x, then:
[tex]F_1 = F_2[/tex]
[tex]k\frac{Q_1q}{R_1^2} = k\frac{Q_2q}{R_2^2}[/tex]
[tex]\frac{Q_1}{R_1^2} = \frac{Q_2}{R_2^2}[/tex]
[tex]\frac{1}{x^2} = \frac{2}{(100 - x)^2}[/tex]
[tex]\sqrt{\frac{1}{x^2}} = \sqrt{\frac{2}{(100 - x)^2}}[/tex]
[tex]\frac{1}{x} = \frac{\sqrt{2}}{100 - x}[/tex]
[tex]100 - x = \sqrt{2}x[/tex]
[tex]x + \sqrt{2}x = 100[/tex]
[tex]x ( 1 + \sqrt{2} ) = 100[/tex]
[tex]x = \frac{100}{1 + \sqrt{2}}[/tex]
[tex]x = 100(\sqrt{2} - 1) ~ m[/tex]
[tex]x \approx 41 ~ m[/tex]
Learn moreThe three resistors : https://brainly.com/question/9503202A series circuit : https://brainly.com/question/1518810Compare and contrast a series and parallel circuit : https://brainly.com/question/539204Answer detailsGrade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces