Answer : The correct option is, (c) use of a mobile and a stationary phase.
Explanation :
Chromatography : It is a separation process or technique of a mixture in which a mixture is distributed between the two phases at different rates, one of which is stationary phase and another is mobile phase.
Mobile phase : The mixture is dissolved in a solution is known as mobile phase.
Stationary phase : It is an adsorbent medium and It is a solid, liquid or gel that remains immovable when a liquid or a gas moves over the surface of adsorbent. It remains stationary.
Hence, a characteristic feature of any form of chromatography is the use of a mobile and a stationary phase.
Warm-Up
A 206-gram bar of iron has sunlight shining on it. Initially, its temperature is 24.7°C. As it gains 1,070.79 joules of energy, its
temperature rises to 36.2°C. Calculate the specific heat capacity of the iron bar using the formula Q = mCAT.
Answer:
0.425
Explanation:
Answer:
0.452
Explanation:
Is bleach an acid or base?
Answer:
Chlorine bleach is strongly basic. We actually make it by dissolving chlorine gas in a concentrated solution of sodium hydroxide, which forms sodium hypochlorite and sodium chloride, in the following equilibrium.
Explanation:
A helium gas balloon is expanded to 78.0 L, while the pressure is held constant at 0.37 atm. If the work done on the gas mixture was 28.2 J, what was the initial volume (in liters) of the helium gas balloon. (1 L. atm?
Answer:
77.248 L
Explanation:
From the question,
Work done on the gas mixture is given as,
W = PΔV.................. Equation 1
Where W = work done, P = pressure of the the gas, ΔV = Change in volume of the gas.
make ΔV the subject of the equation
ΔV = W/P..................... Equation 2
Given: W = 28.2 J, P = 0.37 atm = (0.37×101325) N/m² = 37490.25 N/m²
Substitute into equation 2
ΔV = 28.2/37490.25
ΔV = 0.000752 m³
ΔV = 0.752 L
But,
ΔV = V₂-V₁................. Equation 3
Where V₂ = Final volume of the helium gas, V₁ = Initial volume of the helium gas
make V₁ the subject of the equation
V₁ = V₂-ΔV................ Equation 4
Given: V₂ = 78 L.
Substitute into equation 4
V₁ = 78-0.752
V₁ = 77.248 L
Answer:
The initial volume of the helium gas balloon was 1.78 L
Explanation:
Step 1: Data given
Volume of the balloon is expanded to 78.0 L
The pressure is held constant at 0.37 atm
If the work done on the gas mixture was 28.2 J
Step 2: Calculate the initial volume
W = pΔV
⇒W = the work done on the gas = 28.2 J
⇒p = the pressure = 0.37 atm
⇒ΔV = the change in volume = V2 - V1 = 78.0 L - V1
W = 0.37 * ( 78.0 - V1)
28.2 J = 0.37 * ( 78.0 - V1)
28.2 J = 28.86 - 0.37V1
-0.66 = -0.37V1
V1 = 1.78 L
The initial volume of the helium gas balloon was 1.78 L
"" What is the pH of a solution that is prepared by dissolving 8.52 grams of lactic acid (formula weight = 90.08 grams/mol) and 7.93 grams of sodium lactate (formula weight = 112.06 grams/mole) in water and diluting to 500.00 mL? The Ka for lactic acid is 0.000137.
Answer: The pH of given solution is 3.74.
Explanation:
The given data is as follows.
Mass of lactic acid = 8.52 g, Formula weight of lactic acid = 90.08 g/mol
So, number of moles of lactic acid will be calculated as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{8.52 g}{90.08 g/mol}[/tex]
= 0.094 moles
Mass of sodium lactate = 7.93 g, Formula weight of sodium lactate = 112.06 g/mol
Hence, number of moles of sodium lactate is as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{7.93 g}{112.06 g/mol}[/tex]
= 0.071 moles
As we know that relation between [tex]K_{a}[/tex] and [tex]pK_{a}[/tex] is as follows.
[tex]pK_{a} = -log K_{a}[/tex]
= -log(0.000137)
= 3.86
Using Henderson equation, we will calculate the pH as follows.
pH = [tex]pK_{a} + log (\frac{\text{Conjugate base}}{\text{Acid}})[/tex]
pH = [tex]3.86 + log (\frac{\text{sodium lactate}}{\text{lactic acid}})[/tex]
= [tex]3.86 + log (\frac{0.071}{0.094})[/tex]
= 3.86 + log (0.755)
= 3.86 - 0.121
= 3.74
Therefore, we can conclude that pH of given solution is 3.74.
Two sound waves are emitted from identical sources at the same time. They each travel a distance of 10 m, but one wave reaches the destination faster than the other. What can you conclude about the two waves?
Answer:
Varying frequency between both waves accounts for difference in speed.
Explanation:
The speed of a wave is dependent on four major factors:
wavelengthfrequencymedium, and temperatureAssuming equal temperature and medium of travel of these sound waves, and given that the wavelength (that is distance of travel) is equal, the only varying factor would be their frequency.
Wave speed is calculated by multiplying the wavelength times the frequency
⇒ Speed = λ * f
Answer:
Faster one has a lower frequency and higher wavelength.
Explanation:
The waves have properties such as frequency and wavelength. If the distance they travel is the same but one wave is faster than the other one, the faster wave must have a lower frequency and higher wavelength as it can be seen in this graph from Encyclopedia Britannica.
I hope this answer helps.
For each of the following aqueous reactions, identify the acid, the base, the conjugate base, and the conjugate acid. (Type your answer using the format [NH4] for NH4 and [Ni(CN)4]2- for Ni(CN)42-.) (a) Al(H2O)63 H2O equilibrium reaction arrow H3O Al(H2O)5(OH)2
Answer:
Acid: [Al(H₂O)₆]³⁺
Base: H₂O
Conjugate base: [Al(H₂O)₅(OH)]²⁻
Explanation:
(a) For the reaction:
[Al(H₂O)₆]³⁺ + H₂O ⇄ H₃O⁺ + [Al(H₂O)₅(OH)]²⁻
The acid: [Al(H₂O)₆]³⁺
The base: H₂O
The conjugate base: [Al(H₂O)₅(OH)]²⁻
According to the Bronsted-Lowry acid-base theory, the reaction of an acid and base occurs by the exchange of a proton. The acid forms its conjugate base, and the base forms its conjugate acid in the reaction.
Hence, by the above definition, the [Al(H₂O)₆]³⁺ is the acid that forms its conjugate base [Al(H₂O)₅(OH)]²⁻ and the H₂O is the base that forms its acid conjugate H₃O⁺ when they react and the [Al(H₂O)₆]³⁺ lose a proton to the H₂O.
I hope it helps you!
What is the most likely reason that there are so many volcanoes in Iceland?
Explain why aluminum is a substance
Answer:
.
Explanation:
Aluminium is a silvery-white, lightweight metal. It is soft and malleable. Aluminium is used in a huge variety of products including cans, foils, kitchen utensils, window frames, beer kegs and aeroplane parts. This is because of its particular properties.
a gas has a pressure of 1.21 atm and a volume of 1.04 L. What is the new volume at 0.671 atm
Answer:
1.88 L
Explanation:
We can solve this problem by using Boyle's law, which states that:
"For a fixed mass of an ideal gas at constant temperature, the pressure of the gas is inversely proportional to its volume"
In formula:
[tex]pV=const.[/tex]
where
p is the gas pressure
V is the gas volume
We can write the formula as
[tex]p_1 V_1=p_2 V_2[/tex]
For the gas in this problem we have:
[tex]p_1=1.21 atm[/tex] is the initial pressure
[tex]V_1=1.04 L[/tex] is the initial volume
[tex]p_2=0.671 atm[/tex] is the final pressure
Therefore, the new volume is
[tex]V_2=\frac{p_1 V_1}{p_2}=\frac{(1.21)(1.04)}{0.671}=1.88 L[/tex]
How many protons does the carbon-12 atom have?
Answer:
So Carbon-14 has eight neutrons and Carbon-12 has six neutrons. Hope it helps!
Answer:
A carbon-12 atom has 6 protons, 6 neutrons, and 6 electrons.
Calculate the bond energy per mole for breaking all the bonds in methane
Answer : The required bond energy per mole for breaking all the bonds in methane is, 1656 kJ/mol
Explanation :
The given compound is, [tex]CH_4[/tex].
Methane compound breakdown into 4 C-H bonds.
Given:
[tex]B.E_{C-H}[/tex] = 414 kJ/mol
The expression will be:
[tex]\Delta H_{CH_4}=4\times (B.E_{C-H})[/tex]
[tex]\Delta H_{CH_4}=4\times (414kJ/mol)[/tex]
[tex]\Delta H_{CH_4}=1656kJ/mol[/tex]
Therefore, the required bond energy per mole for breaking all the bonds in methane is, 1656 kJ/mol
Help please I don't get this question
Answer:
Explanation:
combustion
When 15.3 g of sodium nitrate, NaNO₃, was dissolved in water in a constant-pressure calorimeter, the temperature fell from 25.00 °Celsius to 21.56 °Celsius. If the heat capacity of the solution and the calorimeter is 1071 J/oC, what is the enthalpy change when 1 mol of sodium nitrate dissolves in water?
The solution process is NaNO₃(s) _______.
Answer:
20468J / mol
Explanation:
The dissolution in water of NaNO₃(s) is:
NaNO₃(s) → Na⁺(aq) + NO₃⁻(aq)
Now, the equation of a calorimeter is:
Q = -C × ΔT
Where Q is heat, C is heat capacity (1071 J/°C) and ΔT is change in temperature (21.56°C - 25.00°C = -3.44°C)
Replacing:
Q = -1071 J/°C × -3.44°C
Q = 3684.24 J is change in enthalpy per 15.3g of sodium nitrate.
Moles of sodium nitrate are:
15.3g × (1mol / 85g) = 0.18 moles
Thus, enthalpy change per mole of sodium nitrate is:
3684.24J / 0.18mol = 20468J / mol
Answer:
ΔH = 20468 J/mol = 20.5 kJ/mol
Explanation:
Step 1 : Data given
Mass of sodium nitrate NaNO3 = 15.3 grams
The temperature fell from 25.00 °Celsius to 21.56 °Celsius
The heat capacity of the solution and the calorimeter is 1071 J/°C
Step 2: Calculate Q
Q = Cp * ΔT
⇒with Q = the heat transfer = TO BE DETERMINED
⇒with Cp = The heat capacity of the solution and the calorimeter is 1071 J/°C
⇒with ΔT = the change of temperature = 25.00 - 21.56 = 3.44 °C
Q= 1071 J/°C * 3.44 °C
Q = 3684.24 J
Step 3: Calculate moles NaNO3
Moles NaNO3 = mass / molar mass NaNO3
Moles NaNO3 = 15.3 grams / 84.99 g/mol
Moles NaNO3 = 0.180 moles
Step 4: Calculate the enthalpy change when 1 mol of sodium nitrate dissolves in water.
ΔH = Q / moles
ΔH = 3684.24 J/ 0.180 moles
ΔH = 20468 J/mol = 20.5 kJ/mol
Since the temperature decreases, this is an endothermic process.
For an endothermic process, the enthalpy change is positive.
15.0 moles of gas are in a 8.00 LL tank at 24.5 ∘C∘C . Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2a=2.300L2⋅atm/mol2 and b=0.0430 L/molb=0.0430 L/mol .
Answer: The difference in pressure between methane and an ideal gas is 4 atm
Explanation: Please see the attachments below
Final answer:
The question involves comparing pressure differences between methane and an ideal gas, utilizing the van der Waals equation for methane and the ideal gas law, emphasizing real versus ideal gas behavior.
Explanation:
The question asks for the calculation of the difference in pressure between methane and an ideal gas under the given conditions, considering van der Waals deviations for methane. While the question doesn't directly provide all necessary parameters (like the use of temperature in Kelvin) or the specific method to calculate the pressures (ideal gas law for the ideal gas and van der Waals equation for methane), the comparison aims to show how real gas behavior (represented by methane with specific van der Waals constants) deviates from the ideal gas law predictions due to the interactions between gas molecules and the volume they occupy.
The ideal gas law is given by PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. For a real gas like methane, the pressure is calculated using the van der Waals equation: [P+a(n/V)²](V-nb)=nRT, where a and b are the van der Waals constants for methane.
Given the complexity and the specificity of the calculations, including transformations of units and potential adjustments for temperatures, this question illustrates the important distinction between ideal and real gases. It emphasizes the practical considerations when predicting the behavior of gases under different conditions, especially for those like methane which have significant applications in various industries.
1. During her soccer game, Erica accidentally kicks the ball (3.6L) into a trash can! The temperature on
the field is 10°C, but in the trash can it is 25°C. Cindy, standing nearby, wonders "hmmm hat is new
volume of the soccer ball if atmospheric pressure did not change?"
The new volume of the soccer ball is 9 litres when temperature inside the can was 25°C and pressure remained constant.
Explanation:
Data given:
initial volume of the ball, V1 = 3.6 litres
temperature of the field, initial temperature, T1 = 10°C
temperature in the trash can, final temperature, T2 = 25 °C
pressure =constant throughout
volume of the ball when in trash can, final volume V2 =?
From the data given:
Charles' Law will be applied to know the volume of the ball in the can:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
putting the values in the equation after rearranging it:
V2 = [tex]\frac{V1T2}{T1}[/tex]
V2 = [tex]\frac{3.6 X 25}{10}[/tex]
V2 = 9 litres
The volume will be increased to 9 litres when ball will go inside the trash can.
What is true about a system in chemical equilibrium?No reactants remain in the system.The amount of product equals the amount of reactant.The amount of reactant changes, but over time remains about the same.There are no products in the system.
A chemical system in equilibrium has its reactants and products present in constant concentrations, as the forward and reverse reactions occur at equal rates in a closed system.
In a chemical system at equilibrium, the following is true:
Reactants and products coexist in the system.The amounts of reactants and products do not have to be equal, but, after equilibrium is attained, the amounts or concentrations remain constant.The system is closed, meaning substances can neither enter nor leave the system.This state is a dynamic process where the forward and reverse reactions occur at equal rates.Thus, the correct statement about a chemical system in equilibrium is that the amount of reactant changes but over time remains about the same, indicating that the reaction is dynamic with continuous forward and reverse processes.
Please consider the following gas phase reaction and its experimentally determined rate law expression. If the concentration of A is tripled and the concentration of B is doubled, the reaction rate would be increased by a factor of:_________.
A + B → C rate = k[A]^2 [B]
A) 6
B) 9
C) 12
D) 18
E) 36
Answer:
D) 18
Explanation:
Hello,
In this case, by considering the given rate law:
[tex]r=k[A]^2[B][/tex]
We also take into account that the concentration of A is tripled and the concentration of B is doubled, therefore, we have:
[tex]r=k[3*A]^2[2*B][/tex]
Which results in an increasing factor of:
[tex]3^2*2=9*2=18[/tex]
By considering only the tripling and the doubling, thus, the answer is D) 18.
Regards.
At a different temperature (this means that Keq will be different than part a)), 6.0 mol of IF5 and 8.0 mol of I4F2 are placed in a 10.0 L container. At equilibrium, 6.0mol of I4F2 are left. Calculate the Keq for the new temperature.
Answer:
Keq for the new temperature is 26.8
Explanation:
Let's propose the equilibrium:
2IF₅ + I₄F₂ ⇄ 3I₂ + 6F₂
Now we propose the situations:
2IF₅ + I₄F₂ ⇄ 3I₂ + 6F₂
Initial 6 mol 8 mol - -
Initially we added 6 mol and 8 mol of our reactants
React. x x/2 3/2x 3x
By stoichiometry x amount has reacted, so a half of x react to the I₄F₂ and we finally produced 3/2x and 3x in the product side
Eq. (6 - x) (8 - x/2) 3/2x 3x
Notice we have the concentration left for the I₄F₂, so we can find the x value, the amount that has reacted:
8 - x/2 = 6
x = 4, so the concentrations in the equilibrium are:
2 moles of IF₅, 6 moles I₄F₂, 6 moles of I₂ and 12 moles of F₂
As we need molar concentration to determine Keq, we must divide the moles by the volume of the container:
2/10 = [IF₅] → 0.2 M
6/10 = [I₄F₂] → 0.6 M
6/10 = [I₂] → 0.6 M
12/10 = [F₂] → 1.2 M
Let's make, expression for Keq:
Keq = ([I₂]³ . [F₂]⁶) / [IF₅]² . [I₄F₂]
Keq = 0.6³ . 1.2⁶ / 0.2² . 0.6 → 26.8
The election configuration has of an element is 1s^2 2s^2 2p^1. How many valence electrons does the element have?
Answer:
it has 3 valence electrons
Explanation:
2+2+1 is 5, boron is 5 and its in the 3rd group
A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of what ?
A geographically distant species is a green gopher snake that dwells in the grass and a brown rat snake that dwells in the desert.
The environments of the green and brown rat snakes demonstrate that they are geographically distinct species.Because of their differing habitats and morphologies, the two rat snakes are separate species.When two species are separated by environment, their breeding technique morphology or reproductive pattern changes.These species don't have any viable progeny.
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The green and brown rat snakes demonstrate camouflage, a biological adaptation for survival. Camouflage helps them blend into their respective environments, thus evading predators. Anyone considering a snake as a pet must provide an appropriate diet, remembering the potential ecological impact snakes can have when introduced into non-native environments.
Explanation:A green rat snake that lives in the grass and a brown rat snake that lives in the desert is an example of camouflage, which is a form of adaptation where an organism has evolved to blend in with its environment to increase its chances of survival and reproduction. This can be a result of natural selection, where those that can avoid being seen by predators are more likely to survive and pass on their genes. The brown rat snake in the desert is camouflaged against the sandy environment, while the green rat snake blends with the greenery in the grasslands.
Knowing that snakes are carnivorous and some species such as the rat snake are beneficial to humans for controlling pest populations, it's important for anyone considering a snake as a pet to be prepared to feed it a diet consisting of appropriate live or raw prey. It is also noteworthy that in some instances, snakes like the brown tree snake have caused ecological issues when introduced to new environments without natural predators, such as on the island of Guam.
0.450 moles of NaCl are dissolved in 95.0 mL of water. Calculate the molarity of the NaCl solution.
0.0047 M is the molarity of the NaCl solution.
What are moles?A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
0.450 moles of NaCl are dissolved in 95.0 mL of water
[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]
[tex]Molality = \frac{0.450}{95.0 mL}[/tex]
Molality = 0.004736842105 M = 0.0047 M
Hence, 0.0047 M is the molarity of the NaCl solution.
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To find the molarity of a NaCl solution with 0.450 moles of NaCl in 95.0 mL of water, divide the moles by the liters of solution to get a molarity of 4.74 M.
The question asks to calculate the molarity of a NaCl solution when 0.450 moles of NaCl are dissolved in 95.0 mL (0.0950 L) of water. To calculate the molarity (M), which is defined as the number of moles of solute per liter of solution, we use the formula:
M = moles of solute / liters of solution
Substituting the given values: M = 0.450 moles / 0.0950 L = 4.74 M
This means the molarity of the NaCl solution is 4.74 M.
Which statement is true about the most common naturally occurring fatty acids?A) They have 50-100 carbon atoms and an even number of carbon atoms.B) They have 50-100 carbon atoms and an odd number of carbon atoms.C) They have 12-20 carbon atoms and an even number of carbon atoms.D) They have 12-20 carbon atoms and an odd number of carbon atoms.
Answer:
C) They have 12-20 carbon atoms and an even number of carbon atoms.
Explanation:
Fatty acid is described as Carboxylic acid that contains the structural component of lipids
fats and oils. Fatty acids are unbranched and usually have 12-20 carbon atoms evenly. They are known by their number of carbon-to-carbon double bonds present.
For saturated fatty acids, they don't have any carbon-to-carbon double bonds. Fatty acid can be classified based on the number of carbon-to-carbon, such as; monounsaturated fatty acids which have one carbon-to-carbon double bond and also polyunsaturated fatty acids which have contain more than carbon-to-carbon double bonds
Some natural fatty acid
1.)Lauric acid (C11H23COOH)
2.)Palmitic acid (C15H31COOH)
3.)Myristic acid (C13H27COOH)
4.) Linoleic acid (C17H31COOH)
5.) Arachidonic acid(C19H31COOH)
Convert 540mmHg to atm (760mmHg = 1 atm)
Answer:
.71atm
Explanation:
Divide 540 by 760
Answer:
.7105263158 atm
Explanation:
540/760 = 27/38 atm = answer above
Divide the given amount by the conversion to get the converted number.
what is the variable for this number 22.4L?
Answer:
'L' is the variable for this number.
Enzymes use several types of catalytic mechanisms. Differentiate between acid-base catalysis
Answer:
Explanation:
Covalent catalysis is when a transient covalent bond is formed between substrate and residues such that so the enzyme nucleophilic group on an electrophilic moiety of the substrate is bound at the active site. Metal ion catalysis involves activating bound water through forming nucleophilic hydroxide ion.
Protonation or proton abstraction may be accomplished through the use of amino acids such as aspartate or Lysine in acid-base catalysis.
What is catalysis ?The term Catalysis is defined as the process of adding a catalyst to facilitate a reaction. During a chemical reaction, the bonds between the atoms in molecules are broken, rearranged, and rebuilt, recombining the atoms into new molecules.
Catalysis by covalent bonds the two-part catalytic process forms a covalent bond between enzyme and substrate (for example, chymotrypsin mechanism uses a nucleophilic functional group).
By changing the oxidation state, metal ion catalysis catalysts can participate in oxidation-reduction reactions.
Through ionic interactions, a Zn2+ cofactor may properly orient the substrate in the active site. May be involved in Fe2+ interactions.
All lowers activation energy or stabilizes the transition state or intermediate catalyst after the reaction occurs.
Thus, a proton is transferred between enzyme and substrate may use amino acids such as aspartate or Lysine for protonation or proton abstraction is called as acid-base catalysis.
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Your question is incomplete, most probably your question was
Enzymes use several types of catalytic mechanisms. Differentiate between acid-base catalysis, covalent catalysis, and metal ion catalysis.
How do balanced chemical equations show the conservation of mass
Answer: Matter cannot be created or destroyed
Explanation: Balanced equations are set equations we cannot change one element or compound in the equation without changing the entire equation. So balanced equation show the conservation of mass because while other substances may be formed from the synthesis or decomposition of compounds new elements are never introduced and are not created out of thin air :)
Answer:
Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.
Please fill out correctly
15POINTS
Answer:
The answer to your question is below
Explanation:
I will write the answers assigning numbers to each column
Isotope Nuclear form 1 2 3 4 5
Boron-10 ¹⁰B 5 10 5 5 5
Potassium-37 ³⁷K 19 37 19 18 19
Boron-11 ¹¹B 5 11 5 6 5
Silver-107 ¹⁰⁷Ag 47 107 47 60 47
Uranium-238 ²³⁸U 92 238 92 146 92
Oxygen-17 ¹⁷O 8 17 8 9 8
Silver-108 ¹⁰⁸Ag 47 108 47 61 47
The equation represents the combustion of sucrose. C12H22O11 + 12O2 Right arrow. 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? 0.029 mol 0.250 mol 0.351 mol 3.00 mol
Answer: 0.029 mol
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
The balanced chemical equation is:
[tex]C_{12}H_{22}O_{11}+12O_2\rightarrow 12CO_2+11H_2O[/tex]
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=\frac{10.0g}{342g/mol}}=0.029moles[/tex]
Thus there are 0.029 moles of sucrose
Answer:
A
Explanation:
How many moles of potassium chloride (KCI) are in 252 mL of 0.33 mil/L KCI
Answer:
0.083 moles KCl
Explanation:
We have 252 mL of 0.33 M KCl. "M" is molarity, and it's measured in mol/L. Since we know the molarity is 0.33 mol/L, in order to find how many moles 252 mL is, we need to multiply our given volume by the molarity.
However, our given volume is in mL, so let's convert to L first by dividing 252 by 1000 (because there are 1000 mL in 1 L):
252/1000 = 0.252 L
Now, we can multiply 0.252 L by 0.33 mol/L to get moles since the L units will cancel out:
0.252 L * 0.33 mol/L = 0.08316
We have two significant figures here, so round 0.08316 to 0.083.
The answer is 0.083 moles.
Hope this helps!
the complex ion NidppeCl2 can either have a tetrahedral geometry or a square planar geometry around the interior Ni2 ion. When tested, NidppeCl2 proved to be diamagnetic. Based on crystal field theory, what is the geometry around the central Ni ion
Answer:
Square planar
Explanation:
Ni^2+ is a d8 ion. It could exist in either a square planar or a tetrahedral geometry depending on the identity of the ligand. However, strong field ligands often lead to a square planar geometry owing to a greater crystal field splitting.
From the splitting diagrams of nickel II ion in tetrahedral and square planar geometries, it can easily be seen that a diamagnetic complex only arises from the square planar geometry.
Note that both tetrahedral and square planar geometries involve a coordination number of four.