a cheetah ran 100 meters in 6 seconds. what is its average speed?

Answers

Answer 1

Answer:

A=16.6 repeating

explanation:

take 100/6 and solve just make sure your equation is set up correctly!

and you should get an answer of 16.6 repeating or 166 m/hour or 16.6 meters/per/hour

Answer 2

If a cheetah ran 100 meters in 6 seconds, then the average speed of the cheetah would be 16.67 meters per second.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem a cheetah ran 100 meters in 6 seconds , then we have to find the average speed of the cheetah,

The distance traveled by the cheetah = 100 meters

The time is taken by the Cheetah to cover the distance = 6 seconds

The average speed of the cheetah = 100 / 6

                                                          = 16.67 meters per second

Thus, If a cheetah ran 100 meters in 6 seconds, then the average speed of the cheetah would be 16.67 meters per second.

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Related Questions

3. The angular dispersion of a prism depends on
A. the index of refraction only B. the angle of
incidence as well as the index of refraction C. the
angle of incidence only D. the hi thickness of the
prism E, the prism angie.​

Answers

Answer:

The angular dispersion of a prism depends on the index of refraction only.

Explanation:

The angular dispersion of a prism mainly depends upon the refractive index of a material. And this refractive index is dependent on the wavelength of light. Each colour possesses its own characteristic and the wavelength is also different. There has been a relation between refractive index of a material and wavelength of light  higher the wavelength of the colour, greater would be the dispersion of light. As like when we passes light from a prism, according to this principle, the colours are dispersed.  

All the other options are incorrect as cannot decide angle of dispersion.

What are possible units for impulse? Check all that apply.
Okg•m
Okg.
ONós
ON•m
O Nom

Answers

The units for impulse are

[tex]N\cdot s[/tex]

Explanation:

We have two definition for impulse:

1) Impulse is defined as the product between the force exerted on an object and the time interval during which the force is applied:

[tex]I=F \Delta t[/tex]

where

F is the force, measured in Newtons (N)

[tex]\Delta t[/tex] is the time interval, measured in seconds (s)

From this definition it follows that Impulse can be measured in [tex]N\cdot s[/tex], which corresponds to option 3)

2)

Impulse is also defined as the change in momentum of an object:

[tex]I=\Delta p[/tex]

where

[tex]\Delta p[/tex] is the change in momentum of the object

The change in momentum has the same units of the change in momentum, so [tex]kg \cdot m \cdot s^{-1}[/tex], which corresponds to none of the options given

So the only correct option is

[tex]N\cdot s[/tex]

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How is a gas affected when pressure, temperature, or volume
change?

Answers

Explanation:

I never really took physics yet, but I do have some general knowledge of particle physics.

When pressure increases, the gas molecules will get closer together and rise in temperature, vice versa. (That's actually one way we get energy. The more pressure we apply to gas, the hotter it gets and therefore releases pretty good amounts of energy)

When temperature increases, the gas molecules will try to get away from each other and spread out, vice versa. The higher the temperature, the faster the particles move

And when volume increase, there is more room for the gas particles to bounce around and they are generally spread out from each other.

Someone else can answer if I didn't explain it correctly

Answer:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

Explanation:

From the choices below, choose all that are correct.

I. Sound traveling faster through the air in the Sahara desert than in Antarctica.

II. An astronaut hearing the loud explosion of a ship from a mile away in space.

III. Speeds and frequencies of sounds change as they pass through different mediums.
A) I
B) I and II
C) I and III
D) II and III

Answers

The correct choice is

A) I. Sound traveling faster through the air in the Sahara desert than in Antarctica.

Explanation:

Sound is a mechanical wave, which is a periodic disturbance of the space that propagates through vibrations of the particles in the medium filling the space. In particular, sound waves are longitudinal waves, in which the direction of oscillation of the particles in the medium is parallel to the direction of propagation of the wave.

Let's analyze now each statement:

I. Sound traveling faster through the air in the Sahara desert than in Antarctica.  --> TRUE. In fact, the higher the temperature of the air, the faster the sound propagates. In particular, there is a linear relationship between speed of sound and temperature of the air:

[tex]v=331.3 + 0.6T(^{\circ}C)[/tex]

where [tex]T(^{\circ}C)[/tex] is the temperature of the air in Celsius degrees.

II. An astronaut hearing the loud explosion of a ship from a mile away in space.  --> FALSE. This is not possible: in fact, sound is a mechanical wave, so it propagates only through a medium, and it cannot propagate in a vacuum (space is essentially vacuum, so sound cannot propagate in space).

III. Speeds and frequencies of sounds change as they pass through different mediums. --> FALSE. When a wave passes through different mediums, only the speed and the wavelength of the wave change, while the frequency remains the same.

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Answer:     I. Sound traveling faster through the air in the Sahara desert than in Antarctica.

Explanation:

Frequency stays the same as sound passes through different mediums. An explosion in space is not going to be heard if you are in the vacuum of space yourself.

What factors limit the accuracy of a potentiometer?

Answers

Answer:

Whats a potentiometer.

Explanation:

Some of the factors that can limit the accuracy of a potentiometer are internal temperature and Resistance change in the resistor

A potentiometer is a variable resistor that can be adjusted manually and has three terminals. A potentiometer is also called a pot

Further Explanation

Potentiometers have different shapes and they are used in different in different application. A potentiometer can be used to control the volume of a radio. There are several types of a potentiometer.

some of the common ones include

Single-turn pot: it is a single rotation of about 270 degreesMulti-turn pot: this type of pot is used where high precision and resolution are needed. Dual gang pot: this type of pot is used in audio volume control.Concentric pot: this type of pot is mostly used in older car radios, particularly in radios that have its volume and the tone control combinedServo pot: this type of pot is used where manual and automatic adjustment is needed.

However, some of the materials that can be used to construct potentiometers include

Metal firmCarbon compositionWirewoundCermet

As stated earlier, the two factors that can limit the accuracy of a potentiometer are:

Internal temperatureResistance change in the resistor

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potentiometeraccuracyfactorslimittypes of potentiometer

Which of the following is a characteristic of sexually active teens?
Group of answer choices

single and step-parent families

poor school performance

same-sex parents

A and B are correct

A, B, and C are correct

Answers

Out of all given options, poor school performance  is a characteristic of sexually active teens.

Answer: Option B

Explanation:

Socio-demographic characteristics include age, gender and the highest level of education of the respondent. Most respondents had mothers with completed high school levels or diploma. Just over a quarter of respondents did not know their mother's highest education.  A low level of education and some family situations made the teen to be sexually active.

Teen sexual activity is "a fact in most African countries, as in most Western societies." There is a relationship between the sexual activity of young girls and their school resignation. Therefore, additional consequences of early sexual intercourse are women (and sometimes men) who drop out of school when they become pregnant.

Final answer:

Sexually active teens are more likely to come from single and step-parent families and have poor school performance.

Explanation:

The characteristic of sexually active teens is A and B are correct, which means they are more likely to come from single and step-parent families and have poor school performance.

While there may be studies suggesting correlations between certain factors, making broad statements about the behavior of sexually active teens based solely on family structure and school performance can be misleading.

Teenage sexual behavior is influenced by a variety of factors, including individual, family, cultural, and socioeconomic aspects. Family structure alone does not determine a teen's likelihood of engaging in sexual activity. Additionally, attributing poor school performance solely to family structure oversimplifies the complex interplay of factors influencing academic achievement.

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Objects in motion tend to stay in _____ motion at a _____ speed, if no unbalanced forces are acting on them.

A. curved; variable

B. curved; constant

C. straight-line; variable

D. straight-line; constant

Answers

Objects in motion tend to stay in straight-line motion at a constant speed, if no unbalanced forces are acting on them

(option: D. straight-line; constant)

Explanation:

This statement is exactly summarized by Newton's first law of motion, which states that:

"For an object moving by uniform motion (=at constant velocity or at rest), the object will maintain its uniform motion if no unbalanced  forces act on it".

This law essentially tells that if there is an object at rest, this will not move unless some external (unbalanced) force is applied on it, and if the object is moving by uniform motion (=constant speed in a straight line), it will continue moving with this motion unless some external (unbalanced) force is applied on it.

This law is generally difficult to prove in real-life situation, because there are always some unbalanced forces acting on objects. For instance, if we roll a ball along a table, if we neglect the friction between the table and the ball, the ball will continue moving with uniform motion forever. Of course this does not occur in real life, only because there is an external (unbalanced) force, the friction, that makes the ball slowing down and eventually stop.

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A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time​

Answers

Explanation:

Consider the kinematic equation,

[tex]x = vt + \frac{1}{2} a {t}^{2} [/tex]

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

[tex]x = 3(1.8) + \frac{1}{2} (9.3) {1.8}^{2} [/tex]

through simple algebra we get

[tex]x = 20.466[/tex]

where this is the distance traveled in meters.

10. Which of the following is an acceleration?
a. 12 m/s2 down
b. 5 m/s up
c. 8N West

Answers

Answer:

a. 12 m/s² down

Explanation:

Acceleration has units of length per time squared.  Acceleration is a vector, so it also has a direction.

two objects were lifted by a machine. One object had a mass of 2 kilograms, was lifted at a speed of 2m/sec . The other had a mass of 4 kilograms and was lifted at 3m/sec. Which object had more kinetic energy while it was being lifted? Show all calculations

Answers

Object 2 has more kinetic energy

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion, and it is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where

m is the mass of the object

v is its speed

In this problem, for object 1:

m = 2 kg

v = 2 m/s

So its kinetic energy is

[tex]K_1 = \frac{1}{2}(2)(2)^2=4 J[/tex]

For object 2,

m = 4 kg

v = 3 m/s

So its kinetic energy is

[tex]K_2 = \frac{1}{2}(4)(3)^2=18 J[/tex]

Therefore, object 2 has more kinetic energy.

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A liquid mixture of water and alcohol has a density of 900kg/m3. find the mass of alcohol in one litre of the mixture​

Answers

Answer:

900 grams

Explanation:

NB: 1litres=1000ml

Density=mass/volume

900kg/m³=mass/1000ml

mass =900kg/m³×100ml

mass=900grams

Final answer:

The mass of the alcohol in one liter of the mixture must be less than or equal to 0.9 kg, given that the density of the mixture is 0.9 kg/liter.

Explanation:

The key point to remember here is that the density of a solution is the ratio of its mass to its volume. Here, we are given that the density of the water-alcohol mixture is 900 kg/m3. Note that 1 m3 is equal to 1000 liters, so the density can also be expressed as 900 kg/1000 liters, or 0.9 kg/liter.

Since the question asks for the mass of the alcohol in one liter of the solution, and assuming that the entire liter is made up of the solution without any empty space, the mass of the solution in one liter would be 1 liter * 0.9 kg/liter = 0.9 kg.

Therefore, the mass of alcohol in one liter of the mixture must be less than or equal to 0.9 kg, assuming none of the mass is from any other substance. In order to find the exact mass of the alcohol, additional information would be required such as the ratio of water to alcohol in the mixture.

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The angle of incidence and the angle of reflection are measured from the ____, the perpendicular to the surface.

A. planar
B. normal

Answers

The angle of incidence and the angle of reflection are measured from the B) normal to the surface.

Explanation:

Reflection is a phenomenon that occurs when a wave hits a boundary between two mediums and bounces back into the original medium.

The direction of the wave after reflection changes according to the law of reflection, which states that:

The incident ray, the reflected ray and the normal to the surface all lie in the same planeThe angle of reflection is equal to the angle of incidence ([tex]\theta_r  = \theta_i[/tex]

In this framework, the two angles are defined as follows:

the angle of incidence is the angle between the incident ray and the normal to the surfacethe angle of reflection is the angle between the reflected ray and the normal to the surface

Therefore, the complete sentence is

The angle of incidence and the angle of reflection are measured from the B) normal to the surface.

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Answer: The answer is B.

Explanation: i got it correct on Usatestprep.

Which one of the above forms of em radiation does our body detect as heat?

Answers

Answer: Infrared radiation

Explanation:

Infrared radiation is not visible to the human eye, since its wavelengths are outside the visible spectrum (between 700 nm and 1 mm), however this type of electromagnetic radiation is detected by the human body as heat.

 

These waves can be divided into:

- Near infrared or long wave infrared: it is the least sensitive to color and is easily absorbed by water.  

- Medium or medium wave infrared: it is also insensitive to color and easily absorbed by water and many types of plastics and paints.  

- Far infrared or short wave infrared: it is more penetrating than the long wave and is good for heating metals, these waves also can pass through clear materials.  This light has many uses, including heating lamps in physiotherapy and medical treatments, heat sensing devices, among others.

You pull a suitcase along the floor by exerting 43N at an angle. The force of friction is 27 N and the suitcase moves at a constant speed. What angle does the handle make with the horizontal?

Answers

The angle of the force is [tex]51.1^{\circ}[/tex]

Explanation:

To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:

[tex]\sum F_x = ma_x[/tex]

where

[tex]\sum F_x[/tex] is the net force along the x-axis

m is the mass of the suitcase

[tex]a_x[/tex] is the acceleration along the x-axis

The suitcase is moving at constant speed, so the acceleration is zero:

[tex]a_x=0[/tex]

Therefore the net force must also be zero:

[tex]\sum F_x = 0[/tex] (1)

We have two forces acting along the horizontal direction:

- The component of the push (forward) in the horizontal direction, [tex]F cos \theta[/tex], with

F = 43 N

[tex]\theta[/tex] = angle of the force with the horizontal

- The  force of friction, [tex]F_f = 27 N[/tex], backward

So the net force can be written as

[tex]\sum F_x = F cos \theta - F_f[/tex] (2)

Combining (1) and (2),

[tex]F cos \theta - F_f = 0[/tex]

And so we can find the angle:

[tex]\theta = cos^{-1}(\frac{F_f}{F})=cos^{-1}(\frac{27}{43})=51.1^{\circ}[/tex]

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A 4000 kg satellite is placed 2.60 x 10^6 m above the surface of the Earth.


a) Find the acceleration of gravity (g) at 2.60 x 10^6 m above the Earth.

b) Find the critical velocity to maintain a circular orbit at 2.60 x 10^6 m above the surface of Earth. (in both m/sec & km/hr)

c) Find the period of the orbit.

d) How many orbits will the satellite make in one day?

e) Find the escape velocity for a satellite to leave this orbit and escape the gravitational pull of the Earth.

f) Find the escape velocity for a rocket leaving the surface of the Earth.

Answers

a) The acceleration of gravity is [tex]4.96 m/s^2[/tex]

b) The critical velocity is 6668 m/s (24,006 km/h)

c) The period of the orbit is 8452 s

d) The satellite completes 10.2 orbits per day

e) The escape velocity of the satellite is 9430 m/s

f) The escape velocity of the rocket is 11,191 m/s

Explanation:

a)

The acceleration of gravity for an object near a planet is given by

[tex]g=\frac{GM}{(R+h)^2}[/tex]

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

h is the height above the surface

In this problem,

[tex]M=5.98\cdot 10^{24} kg[/tex] (mass of the Earth)

[tex]R=6.37\cdot 10^6 m[/tex] (Earth's radius)

[tex]h=2.60\cdot 10^6 m[/tex] (altitude of the satellite)

Substituting,

[tex]g=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24}}{(6.37\cdot 10^6 + 2.60\cdot 10^6)^2}=4.96 m/s^2[/tex]

b)

The critical velocity for a satellite orbiting around a planet is given by

[tex]v=\sqrt{\frac{GM}{R+h}}[/tex]

where we have again:

[tex]M=5.98\cdot 10^{24} kg[/tex] (mass of the Earth)

[tex]R=6.37\cdot 10^6 m[/tex] (Earth's radius)

[tex]h=2.60\cdot 10^6 m[/tex] (altitude of the satellite)

Substituting,

[tex]v=\sqrt{\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24}}{(6.37\cdot 10^6 + 2.60\cdot 10^6)}}=6668 m/s[/tex]

Converting into km/h,

[tex]v=6668 m/s \cdot \frac{3600 s/h}{1000 m/km}=24,006 km/h[/tex]

c)

The period of the orbit is given by the circumference of the orbit divided by the velocity:

[tex]T=\frac{2\pi (R+h)}{v}[/tex]

where

[tex]R=6.37\cdot 10^6 m[/tex]

[tex]h=2.60\cdot 10^6 m[/tex]

v = 6668 m/s

Substituting,

[tex]T=\frac{2\pi (6.37\cdot 10^6 + 2.60\cdot 10^6)}{6668}=8452 s[/tex]

d)

One day consists of:

[tex]t = 24 \frac{hours}{day} \cdot 60 \frac{min}{hours} \cdot 60 \frac{s}{min}=86400 s[/tex]

While the period of the orbit is

T = 8452 s

So, the number of orbits completed by the satellite in one day is

[tex]n=\frac{t}{T}=\frac{86400}{8452}=10.2[/tex]

e)

The escape velocity for an object in the gravitational field of a planet is given by

[tex]v=\sqrt{\frac{2GM}{R+h}}[/tex]

where here we have:

[tex]M=5.98\cdot 10^{24} kg[/tex]

[tex]R=6.37\cdot 10^6 m[/tex]

[tex]h=2.60\cdot 10^6 m[/tex]

Substituting, we find

[tex]v=\sqrt{\frac{2(6.67\cdot 10^{-11})(5.98\cdot 10^{24}}{(6.37\cdot 10^6 + 2.60\cdot 10^6)}}=9430 m/s[/tex]

f)

We can apply again the formula to find the escape velocity for the rocket:

[tex]v=\sqrt{\frac{2GM}{R+h}}[/tex]

Where this time we have:

[tex]M=5.98\cdot 10^{24} kg[/tex]

[tex]R=6.37\cdot 10^6 m[/tex]

[tex]h=0[/tex], because the rocket is located at the Earth's surface, so its altitude is zero.

And substituting,

[tex]v=\sqrt{\frac{2(6.67\cdot 10^{-11})(5.98\cdot 10^{24}}{(6.37\cdot 10^6)}}=11,191 m/s[/tex]

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Which type of committee has members from both the House and the Senate?

Answers

Joint committees have similar purposes as select committees, but they are made up of members from both the House and the Senate. They are set up to conduct business between the houses and to help focus public attention on major issues.

Answer:the answe would be joint comitee

Explanation:

a 3,000 kg car is traveling with a constant velocity of 10 m/s. how much work must be applied to the car to change its speed to 15 m/s?​

Answers

187500 Joules of work must be done to the 3000 kg car to change its speed from 10 m/s to 15 m/s.

Explanation:

Work is the measurement of the force on an object that overcomes a resisting force (such as friction or gravity) times the distance the object is moved. If there is no distance, there is no work, no matter what the effort.

Work done = Force * displacement

When you apply enough force on an object to overcome a resistive force, such that you move that object, you are doing work on that object. There is a relationship between that work and mechanical energy.

When an object is accelerated, you are doing work against inertia, such that the work equals the change in kinetic energy of the object.

Work done = Change in K.E

In the given case:

mass = m = 3000 kg

initial velocity = v₁ = 10 m/s

final velocity = v₂ = 10 m/s

Work = W = (1/2)m(v₂)² - (1/2)m(v₁)²

[tex]= \frac{1}{2}m(v2^{2} - v1^2)\\= \frac{3000}{2}(15^{2} - 10^{2})\\= 1500(225 - 100)\\= 1500*125\\= 187500 kg m^{2}s^{-2} \\= 187500 Nm\\= 187500 J[/tex]

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If a car is traveling with a constant velocity of 20m/s westward, what is the net force acting on a car

Answers

The net force on the car is zero

Explanation:

We can answer this question by applying Newton's second law of motion. In fact, we have:

[tex]\sum F = ma[/tex]

where

[tex]\sum F[/tex] is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the car is travelling with a constant velocity: this means that the acceleration of the car is zero (because acceleration is the rate of change of velocity). Therefore,

[tex]a=0[/tex]

So the equation becomes

[tex]\sum F = 0[/tex]

which means that the net force on the car is zero.

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if f(x)=4/x+2 and g is the inverse of f,then g'(10)=​

Answers

Answer:

g'(10) = [tex]\frac{-1}{16}[/tex]

Explanation:

Since g is the inverse of f ,

We can write

g(f(x)) = x     (Identity)

Differentiating both sides of the equation we get,

g'(f(x)).f'(x) = 1

g'(10) = [tex]\frac{1}{f'(x)}[/tex]    --equation[1]    Where f(x) = 10

Now, we have to find x when f(x) = 10

Thus 10 = [tex]\frac{4}{x}[/tex] + 2

[tex]\frac{4}{x}[/tex] = 8

x = [tex]\frac{1}{2}[/tex]

Since f(x) = [tex]\frac{4}{x}[/tex] + 2

f'(x) = -[tex]\frac{4}{x^{2} }[/tex]

f'([tex]\frac{1}{2}[/tex])  =  -4 × 4 = -16            

Putting it in equation 1, we get:

We get g'(10) = -[tex]\frac{1}{16}[/tex]

A thread holds two carts together on a frictionless surface. A spring is compressed
between the two carts. After the thread between the two carts is cut the cart on the
left with a mass of 1.5 kg moves away with a velocity of 27 cm/s. What is the
velocity of the cart on the right that has a mass of 4.5 kg? thisss is the answer I just need to show work>>>>>>>(0.09 m/s)

Answers

Answer:

Velocity on the right side of the cart [tex]=0.09\ ms^{-1}[/tex]

Explanation:

Given

⇒The mass on the left of the cart [tex]m_1=1.5\ kg[/tex]

   Its velocity [tex]v_1=27\ cm/s[/tex],[tex]v_1=\frac{27}{100}=0.27\ m/s[/tex]

⇒Mass on the right of the cart [tex]m_2=4.5\ kg[/tex]

  Velocity[tex]=?[/tex] We have to find [tex]v_2[/tex]

From

The law of conservation of linear momentum:

We can say that.

Initial momentum will equalize the final momentum.

And momentum is the product of mass and its velocity.

Assigning one of its velocity as negative because both are in different direction.

Lets call [tex]v_1=-0.27m/s[/tex]

Recalling the formula and plugging the values.

[tex]m_1(-v_1)+m_2v_2=0[/tex]

[tex]v_2=-\frac{m_1(-v_1)}{m_2} =-\frac{1.5\times -0.27}{4.5} =0.09\ m/s[/tex]

So the velocity of the cart on the right side that has a mass of [tex]4.5\ kg[/tex] is [tex]0.09\ ms^{-1}[/tex]

Using the principle of conservation of momentum, the velocity of the right cart is calculated to be 0.09 m/s.

To determine the velocity of the right cart, we can use the principle of conservation of momentum. According to this principle, the total momentum of a closed system remains constant if no external forces act on it.

Given:

Mass of the left cart ([tex]m_1[/tex]) = 1.5 kgVelocity of the left cart ([tex]v_1[/tex]) = 27 cm/s = 0.27 m/sMass of the right cart ([tex]m_2[/tex]) = 4.5 kgInitial total momentum = 0 (since both carts start from rest)Let [tex]v_2[/tex] be the velocity of the right cart after the thread is cut. By conservation of momentum:

Step-by-Step Calculation:

Write the initial momentum equation:

([tex]m_1[/tex] + [tex]m_2[/tex]) * 0 = [tex]m_1[/tex] * [tex]v_1[/tex] + [tex]m_2[/tex] * [tex]v_2[/tex]

Simplify the equation:

0 = (1.5 kg * 0.27 m/s) + (4.5 kg * [tex]v_2[/tex])

Solve for v2:

4.5 * [tex]v_2[/tex] = - 0.405[tex]v_2[/tex] = -0.09 m/s

The negative sign indicates that the right cart moves in the opposite direction to the left cart. Hence, the velocity of the cart on the right is 0.09 m/s.

What assumption do error theorist claims at the heart of morality

Answers

Answer:

a) The assumption that error theorists claim is at the heart of morality is that sincere moral judgments are always in error, therefore there is no moral knowledge possible.

Explanation:

11 is the answer for all of your questions trust

why don't we use more renewable energy sources​

Answers

Answer:

Renewable energy sources 1.Cost more then nonrenewable resources and 2.Are so far not as reliable as nonrenewable energy.

Explanation:

renewable energy often has trouble creating the same amount of power that fossil fuels make because of its efficiency , they're expensive too

Pierce conducts an experiment in which waves collide in a way that the energy increases, which means that has occurred.

Answers

It means Constructive interference has occurred.

Explanation:

Waves travelling from opposite sides can collide to results into constructive interference or destructive interference.

In constructive interference, the crust of the waves merge.This results into increase in energy.In destructive interference the two waves cancel each other to cause loss of energy.

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Answer:

Constructive Interference

Explanation:

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When reporting the speed, we need to include the value, units and direction the object was traveling.

True or False??

Answers

Answer:

When reporting the speed, we need to include the value, units and direction the object was traveling.

It is a FALSE

Explanation:

Justification :

Speed is a scalar quantity.Scalar quantity required only magnitude not the direction.The definition of speed is total distance travelled divided by total time taken to cover that distance.Therefore, speed required value and units not the direction.By velocity which is similar to speed required value, units and direction. And velocity is a vector quantity hence it require direction.For example without speed of a car is 50 m/s. Here 50 is the value and m/s is the unit of a speed.


When a cup is placed on a table, which force prevents the cup from falling to the ground?

Answers

Answer:Answer: Normal force prevents the cup from falling to the ground. Explanation : When a cup is placed on a table, the forces acting on the cup are the gravitational force and the normal force. The gravitational force acts in the downward direction while the normal force acts in an upward direction

Explanation:

Choose the FALSE statement about an object that has mass. A. It has volume. B. It must be heavy. C. It takes up space. D. It is made of matter.

Answers

Answer:

B. It must Be Heavy

Explanation:

An Object Can Have Mass And Be Light Such As A Pencil

The answer should be
B. It must be heavy

To sterilize a 53.0 g glass baby bottle, we must raise its temperature from 25.0°C to 92.0°C. How much heat transfer (in J) is required?

Answers

The heat energy required is 2983 J

Explanation:

When an amount of energy Q is supplied to a certain sample of substance of mass m, the temperature of the substance increases by an amount of [tex]\Delta T[/tex] according to the equation :

[tex]Q=mC_s \Delta T[/tex]

where

Q is the heat supplied

m is the mass of the object

[tex]C_s[/tex] is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature

For the glass bottle in this problem:

[tex]m=53.0 g[/tex]

[tex]\Delta T = 92.0 - 25.0 =67.0^{\circ}C[/tex] is the change in temperature

[tex]C_s = 0.84 J/g^{\circ}C[/tex] is the specific heat of glass

Substituting into the equation, we find

[tex]Q=(53.0)(0.84)(67)=2983 J[/tex]

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A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long as 2.20 m have been recorded. If a frog jumps 2.20 m and the launch angle is 54.0°, find the frog's launch speed and the time the frog spends in the air. Ignore air resistance.
(a) the frog's launch speed (in m/s)
(b)the time the frog spends in the air (in s)

Answers

Answer:

[tex]v_0[/tex]=4.761 m/s

t=0.786 sec

Explanation:

In a projectile motion (or 2D motion), the object is launched with an initial angle [tex]\theta[/tex] and an initial velocity [tex]v_0[/tex]

The components of the velocity are

[tex]v_{ox}=v_ocos\theta[/tex]

[tex]v_{oy}=v_osin\theta[/tex]

Similarly the displacement has the components

[tex]x=v_{ox}.t=v_ocos\theta.t[/tex]

[tex]y=v_osin\theta.t-\frac{gt^2}{2}[/tex]

The last formula is valid only if the object is launched at ground level, as our frog does.  

There are two times where the value of y is zero, when t=0 (at launching time) and when it lands back from the air. We need to find that time t by making y=0

[tex]0=v_osin\theta.t-\frac{gt^2}{2}[/tex]

Dividing by t (assuming t different from zero)

[tex]0=v_osin\theta-\frac{gt}{2}[/tex]

Then we find the total flight as

[tex]t=\frac{2v_osin\theta}{g}[/tex]

Replacing this time in the formula of x

[tex]x=v_ocos\theta\frac{2v_osin\theta}{g}[/tex]

We can solve for [tex]v_o[/tex]

[tex]\displaystyle v_0=\sqrt{\frac{xg}{sin2\theta}}[/tex]

Knowing that x=2.20 m and [tex]\theta=54[/tex]°

[tex]\displaystyle v_0=\sqrt{\frac{xg}{sin2\theta}}=4.761m/s[/tex]

We now compute t

[tex]t=\frac{2v_osin\theta}{g}=0.786\ sec[/tex]

Final answer:

The launch speed of the frog is 4.81 m/s, and the time the frog spends in the air is 0.737 seconds.

Explanation:

A) Using the kinematic equation for projectile motion, we can find the launch speed. The launch speed, in this case, would be 4.81 m/s.

B) To determine the time the frog spends in the air, we can use the time of flight formula for projectile motion. The time in the air for the frog is 0.737 seconds.

Assume that a hockey player skates 60 feet in 3 seconds. What is the player’s speed? If the hockey player travels this distance from East to West, what is his velocity?

Answers

Answer:

20ft/secs

Explanation:

60 feet/ 3 secs

Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
incline, find the following:
(a) The acceleration of the snowboarder.

Answers

The acceleration of the snowboarder is [tex]5.6 m/s^2[/tex] down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

[tex]mg sin \theta[/tex]

where

m = 75.0 kg is the mass of the man

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

[tex]\theta=35^{\circ}[/tex] is the angle of the incline

Substituting, we find that the net force along the incline is:

[tex]F=(75.0)(9.8)(sin 35^{\circ})=421.6 N[/tex]

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

[tex]F=ma[/tex]

where a is the acceleration. Therefore, solving for a, we find

[tex]a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2[/tex]

And the direction of this acceleration is down along the incline.

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